What is the coefficient of the third term in the binomial expansion of (a b)6? 1 15 20 90

The answer for the following part is

Surface area is the amount of space covering the outside of a three-dimensional shape.

Surface Area of Cone,

= πrl + πr²

=3.14*8*15.77 + 3.14* 8*8

= 597.61804 mm²

Surface Area of triangular pyramid,

= apothem * slant height * length

= 73.6 m²

Surface Area pentagonal pyramid

= B + LA

= 247.75 + 5 ( 1/2*12*19.5)

= 247.75 + 5 ( 117)

= 832.75 in²

Surface area of square pyramid

= P*l /2

= 2400 ft²

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Answer:

23 min 30 sec

Step-by-step explanation:

First, you add 35 + 14 + 18 + 27 which is 94.
Next, you divide 94 by the number of deliveries there were. Which is 4.
94/4 = 23.5.
So your answer would be 23 minutes and 30 seconds.

I Hope This Helped :D

Answer:

23.5 minutes or 23 minutes and 30 seconds

Step-by-step explanation:

1. add all the minutes

35 minutes + 14 minutes + 18 minutes+ 27 minutes = 94 minutes

2. Divide the total amount of minutes by the number of deliveries

94 minutes =  23.5 minutes or 23 minutes and 30 seconds

4 deliveries

Answer:

25:28 is the simplest form

Step-by-step explanation:

This is a ratio, think of it like a fraction. You can simplfy it by dividing by common factor.

25 and 28 have no common factors except for 1.

25: 1,5,25

28: 1,2,4,7,14,28

It will stay as 25:28

Answer:

it stays the exact same or 0.893

Step-by-step explanation:

Answer:

y = 2x - 1

Step-by-step explanation:

Given equation: 2x - y = 1

We're being asked to solve for y. This is also known as the Slope-Intercept Form. It is represented by the following formula:

y = mx + b

where:

Steps:

1. Subtract 2x from both sides:

[tex]\sf 2x-2x - y = 1-2x\\\\\implies-y=-2x+1[/tex]

2. Divide both sides by -1:

[tex]\sf \dfrac{-y}{-1}=\dfrac{-2x+1}{-1}\\\\\implies y=2x-1[/tex]

This equation has a slope of 2, and a y-intercept of -1.

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Answer:

pounds (£)

Step-by-step explanation:

pounds are used in countries such as the UK and South Georgia

An equation that models the height of the ball as a function of time t is; h(t) = -16t² + 40t + 3. The maximum height that the ball will reach is 28 ft

We are given the equation for the vertical velocity model as;

h = -16t² + vt + s

Where;

v = velocity

s = starting height

h = ending height

t = time

A) From the question, we have;

v = 40 ft/s

s = 3 ft

Thus, the equation is;

h = -16t² + 40t + 3

B) To find the time that the ball reaches its maximum height, we will equate the height equation to zero and find the roots. Thus;

-16t² + 40t + 3 = 0

Using an online quadratic equation calculator gives;

t = 2.573 s

C) The maximum height that the ball will reach is;

h'(t) = -32t + 40

At h'(t) = 0;

-32t + 40 = 0

32t = 40

Thus;

t = 1.25 s

Max height = -16(1.25)² + 40(1.25) + 3

Max height = 28 ft

D) The height of the ball after 2 seconds is;

h(2) = -16(2)² + 40(2) + 3

h(2) = 19 ft

E) Time for the ball to hit the ground is;

T = 2 * 2.573

T = 5.146 s

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Answer:

The answer for this question is c

The value of x from the quadratic term equation is x = ( -11/2 ) ± ( 5√5 ) / 2

A quadratic equation is a second-order polynomial equation in a single variable x , ax² + bx + c=0. with a ≠ 0. Because it is a second-order polynomial equation, the fundamental theorem of algebra guarantees that it has at least one solution. The solution may be real or complex.

The roots of the quadratic equations are

x = [ -b ± √ ( b² - 4ac ) ] / ( 2a )

where ( b² - 4ac ) is the discriminant

when ( b² - 4ac ) is positive, we get two real solutions

when discriminant is zero we get just one real solution (both answers are the same)

when discriminant is negative we get a pair of complex solutions

Given data ,

Let the quadratic equation be represented as A

Now , the value of A is

x² + 11x + 121/4 = 125/4

Subtracting ( 125/4 ) on both sides , we get

x² + 11x + ( 121 - 125 ) / 4 = 0

x² + 11x - 1 = 0   be equation (1)

On simplifying , we get

The roots of the quadratic equations are

x = [ -b ± √ ( b² - 4ac ) ] / ( 2a )

So , x = [ -11 ± √ ( 11 )² - 4 ( 1 ) ( -1 ) ] / 2

On further simplification , we get

x = -11 ± √ ( 121 + 4 ) / 2

x = [ -11 ± √125 ] / 2

x = ( -11/2 ) ± ( 5√5 ) / 2

Therefore , the roots of the equation are x = ( -11/2 ) ± ( 5√5 ) / 2

Hence , the quadratic equations are solved

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Answer:

x = (√10  -3)/2  and (-√10  -3)/2

Step-by-step explanation:

(2x+3)^2 = 10

To solve the equation, take the square root of each side

sqrt((2x+3)^2) = ±√10

2x+3 = ±√10

Subtract 3 from each side

2x+3-3 = ±√10  -3

2x = ±√10  -3

Divide each side by 2

2x/2 = (±√10  -3)/2

x = (±√10  -3)/2

There are two solutions

x = (√10  -3)/2

and (-√10  -3)/2

Answer:

[tex]\large {\textsf{A and D}}\ \implies \sf \sf \bold{x_1}=\dfrac{-\sqrt{10}-3}{2},\ \bold{x_2}=\dfrac{\sqrt{10}-3}{2}[/tex]

Step-by-step explanation:

Given: (2x + 3)² = 10

In order to find the solutions to the given equation, we can take the (square) roots of the equation to find the zeros, which are also known as the x-intercepts. This is where the zeros intersect the x-axis.

Note: when taking the square roots of a quadratic equation, remember to use both the positive and negative roots.

Step 1: Square both sides of the equation.

[tex]\sf \sqrt{(2x + 3)^2} = \sqrt{10}\\\\\Rightarrow 2x+3=\pm\sqrt{10}[/tex]

Step 2: Separate into possible cases.

[tex]\sf x_1 \implies 2x+3=-\sqrt{10}\\\\x_2 \implies 2x+3=\sqrt{10}[/tex]

Step 3: Solve for x in both cases.

[tex]\sf \bold{x_1} \implies 2x+3=-\sqrt{10}\ \ \textsf{[ Subtract 3 from both sides. ]}\\\\\Rightarrow 2x+3-3=-\sqrt{10}-3\\\\\Rightarrow 2x=-\sqrt{10}-3\ \ \textsf{[ Divide both sides by 2. ]}\\\\\Rightarrow \dfrac{2x}{2}=\dfrac{-\sqrt{10}-3}{2}\\\\\Rightarrow x_1=\dfrac{-\sqrt{10}-3}{2}\\\\[/tex]

[tex]\sf \bold{x_2}\implies 2x+3=\sqrt{10}\ \ \textsf{[ Subtract 3 from both sides. ]}\\\\\Rightarrow 2x+3-3=\sqrt{10}-3\\\\\Rightarrow 2x=\sqrt{10}-3\ \ \textsf{[ Divide both sides by 2. ]}\\\\\Rightarrow \dfrac{2x}{2}=\dfrac{\sqrt{10}-3}{2}\\\\\Rightarrow x_2=\dfrac{\sqrt{10}-3}{2}[/tex]

Therefore, the solutions to this quadratic equation are: [tex]\sf \bold{x_1}=\dfrac{-\sqrt{10}-3}{2},\ \bold{x_2}=\dfrac{\sqrt{10}-3}{2}[/tex]

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Answer:

Step-by-step explanation:

What are the 6 types of journals?

There are various types of journals including:

academic/scholarly journals.

trade journals.

current affairs/opinion magazines.

popular magazines.

newspapers.

Answer:

The area is 16 inches squared and the perimeter is also 16 inches

Step-by-step explanation:

To find the area, you must multiply the length by the width. Since this is a square, you have to multiply one adjacent side by the other. For perimeter, you can either multiply one side by 4 or add all 4 sides.

Answer:

x=9

y=?

36= 1/2(x*y)

36 *2 = 2* 1/2 (9*y)

72 = 9*y

72/9= 9*y/9

8=y

The other number is 8.

Answer:

x=20

Step-by-step explanation:

The angles are 'Co-interior Angles', they make a C shape and add up to 180 degrees

so 4x +5x =9x

9x=180

x=20

4x=80

5x=100

Answer:

5y + 3= 14

subtract 3 from each side

5y=11

divide each side by 5

5y/5=11/5

y=11/5 or 2.2 or 2 1/5

Hope This Helps!!!

Answer:

2.2

Step-by-step explanation:

Properties needed:

First we need to subtract 3 from both sides because of subtraction property of equality to make both sides equal.

5y + 3 = 14

      -3    -3

5y = 11

Then we need to divide 5 from both sides (division property of equality) to get y.

[tex]\frac{5y}{5} = \frac{11}{5}[/tex]

And we get 2.2

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I hope this helps!

Have a great day!

Answer:

Using the concept of equation of line, we find that the relationship will be

C = $6.5p.

Step-by-step explanation:

If the cost per head is $6.5 and there are p persons entering the car, then the total amount would be $6.5p.

The final equation would resemble the equation of line y = mx + c.

The expression for the total cost C, would be

C = 6.5p.

Here y = C, x = p, m = 6.5 and c = 0.

So, the expression for the total cost will be the equation of line C = 6.5p.

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Answer:

given - a rectangle ABCD

AB = 40

AC. = 90

BC = ?

in triangle ABC

using Pythagoras theorem

(AB) ² + (BC) ² = (AC) ²

(40)² + (BC) ² = (90)²

(BC) ² = (90)²- (40)²

(BC) ² = 8100 - 1600

(BC) ² = 6500

BC =

[tex]20 \sqrt{10} [/tex]

Answer:

A. g(x)=x^2+5x+2

Step-by-step explanation:

f(x) = x^2 + 5x - 1 Shift 3 units to the left. k=3

g(x)=x^2+5x-1+3=x^2+5x+2

g(x)=x^2+5x+2

Hope this helps!

If not, I am sorry.

Answer:

16.6

Step-by-step explanation:

Add the numbers together.

13.2+20=33.2

Now divide the number by 2.

33.2/2=16.6

Hope this helps!

If not, I am sorry.

By using the given graph, we will see that:

Here we have a graph of function G(x), and we want to evaluate it in different values of x.

To do that, we need to look at the interval where the lines are defined. An open dot means that the endpoint does not belong to the interval, while the closed dot means that the endpoint belongs.

First, G(0).

If you look at the graph, when x = 0 we have a closed dot on the bottom line. That is the line that we need to look to do this evaluation, there we can see that when x = 0, we have G(0) = -5.

Then we have x = 2.999.

Notice that x < 3.

And the second line (the one at y = -3) is on the interval (0, 3].

Then x = 2.999 is included on that interval, it means that:

G(2.999) = -3.

Now we have x = 0.0001

Again, notice that the second line is on the interval (0, 3]

Because 3 > 0.0001 > 0, then:

0.0001 ∈ (0, 3]

From that, we conclude that:

G(0.0001) = -3

Finally:

G(3).

Again, 3 belongs to the interval (0, 3]

Then we use the second line again.

G(3) = -3

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Answer:

G(0) = -5

G(0.0001) = -3

G(2.999) = -3

G(3) = -3

Step-by-step explanation:

Step-by-step explanation:

yo thara bhai joginder tu he ek bndr

Answer:

(0.5,2) and (-3,3)

Step-by-step explanation:

Answer:

Y = 4x -2 is (0.5,2)

y = x +3 is (-3,3)

1) [tex]OA=OB[/tex] (all radii of a circle are equal)

2) [tex]\angle OBA=52^{\circ}[/tex] (angles opposite equal sides in a triangle are equal)

3) [tex]\angle OAB+\angle OBA+\angle AOB=180^{\circ}[/tex] (angles in a triangle add to 180 degrees)

4) [tex]52^{\circ}+52^{\circ}+\angle AOB=180^{\circ}[/tex] (substitution)

5) [tex]\angle AOB=76^{\circ}[/tex] (subtraction)

6) [tex]\angle AOB+\angle BOD=180^{\circ}[/tex] (angles on a line add to 180 degrees)

7) [tex]76^{\circ}+\angle BOD=180^{\circ}[/tex] (substitution)

8) [tex]\angle BOD=104^{\circ}[/tex] (subtraction)

9) [tex]\angle ODE=\angle OBC=90^{\circ}[/tex] (tangents are perpendicular to the radius of a circle at the point of tangency)

10) [tex]\angle ODC=117^{\circ}[/tex] (angle addition postulate)

11) [tex]\angle BOD+\angle OBC+\angle ODC+\angle DCB=360^{\circ}[/tex] (angles in a quadrilateral add to 360 degrees)

12) [tex]104^{\circ}+90^{\circ}+117^{\circ}+\theta=360^{\circ}[/tex] (substitution)

13) [tex]\theta=49^{\circ}[/tex] (subtraction)

The velocity of the wind will be 50 km per hour.

The quantity which has magnitude, direction and follows the law of vector addition is called a vector.

A motorcyclist riding North along a straight road at 50 km per hour observes that the wind appeared to have a velocity of 50 km per hour from the direction North 60 degrees West.

Then the velocity of the wind will be

Let x be the speed of the wind. Then we have

x² = 50² + 50² - 2 x 50 x 50 x cos 60°

x² = 2500 + 2500 - 2500

x² = 2500

x = 50 km per hour

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The number of adults are 2 . the number of youths are 8

Given charge $7 for adults , $2 for youth and $0.50 for children

Let the number of adults , youths and children be x , y and z

Now it is given that there is total pay of 100

Therefore the equation formed is

7x + 2y +0.50 = 100

Now it is also given that 150 people enter

Therefore

x+y+z=150

x+y+z =150

14x+4y+z=200

Using argument matrix

[tex]\left[\begin{array}{ccc}1&1&1\\14&4&1\end{array}\right] \left[\begin{array}{ccc}150\\200\end{array}\right][/tex]

Corresponding system equation is

x+y+z=150

y+(13/10)z=190

Take z = m (arbitary)

y = 190 - 1.3 m

x = 150 - y

m = 140 x = 2 and y = 8

Hence The number of adults are 2 . the number of youths are 8

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The differential equation

[tex]M(x,y) \, dx + N(x,y) \, dy = 0[/tex]

is considered exact if [tex]M_y = N_x[/tex] (where subscripts denote partial derivatives). If it is exact, then its general solution is an implicit function [tex]f(x,y)=C[/tex] such that [tex]f_x=M[/tex] and [tex]f_y=N[/tex].

We have

[tex]M = \tan(x) - \sin(x) \sin(y) \implies M_y = -\sin(x) \cos(y)[/tex]

[tex]N = \cos(x) \cos(y) \implies N_x = -\sin(x) \cos(y)[/tex]

and [tex]M_y=N_x[/tex], so the equation is indeed exact.

Now, the solution [tex]f[/tex] satisfies

[tex]f_x = \tan(x) - \sin(x) \sin(y)[/tex]

Integrating with respect to [tex]x[/tex], we get

[tex]\displaystyle \int f_x \, dx = \int (\tan(x) - \sin(x) \sin(y)) \, dx[/tex]

[tex]\implies f(x,y) = -\ln|\cos(x)| + \cos(x) \sin(y) + g(y)[/tex]

and differentiating with respect to [tex]y[/tex], we get

[tex]f_y = \cos(x) \cos(y) = \cos(x) \cos(y) + \dfrac{dg}{dy}[/tex]

[tex]\implies \dfrac{dg}{dy} = 0 \implies g(y) = C[/tex]

Then the general solution to the exact equation is

[tex]f(x,y) = \boxed{-\ln|\cos(x)| + \cos(x) \sin(y) = C}[/tex]

Answer: 280

Step-by-step explanation:

50 cents for each banana so: 4* 50= 200

200+80

Answer is 280

Divya should not check her answers for extraneous solution as it's not required in this case.

It should be noted that an extraneous solution simply means is the transformed equation that's isn't the root of the original equation.

Based on the information given, Divya had already solved the equation and it's not necessary to check the answers for extraneous solution.

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Answer:

No, she shouldn't.