What is the balanced chemical equation for this reaction? H3PO4 + HCl → PCl5 + H2O Question 7 options: H3PO4 + 5HCl → PCl5 + H2O 2H3PO4 + 10HCl → 2PCl5 + 4H2O 2H3PO4 + 5HCl → 2PCl5 + 3H2O H3PO4 + 5HCl → PCl5 + 4H2O

Answer:

Can A will make a louder and stronger fizz than can B.

Explanation:

Temperature has a direct effect on gas solubility. We know that carbonated water contains carbon dioxide dissolved in water. The extent of dissolution or solubility of this gas is dependent on the temperature of the system.

As the temperature of the system rises, the solubility of gas in solution decreases. It follows that can A, having been stored in a garage is definitely at a higher temperature than can B stored in the refrigerator.

Since solubility of gases decreases with increasing temperature, the carbon dioxide in can A will be less soluble than in can B. This will cause can A to make a louder and stronger fizz when opened than can B.

Answer:

First list

A. CH3OH----hydrogen bonds

CH4----dispersion forces

CaCO3---ionic bonds

C6H14----dispersion forces

Second list

H2O------ liquid----hydrogen bonds

C2H2----gas---dispersion forces

CCl4---liquid---dispersion forces

KCl----solid---ionic bonds

Explanation:

For every compound, the intermolecular forces decide whether the substance will be solid liquid or gas. Molecules are known to associate with each other in any particular state of matter. These molecules are held together by different intermolecular interactions with varying degrees of strength. The strength of the intermolecular interaction between the molecules of a substance will decide if the substance will be a solid, liquid or gas.

When the intermolecular forces are very strong such as in ionic solids and covalent network solids, the substance exists as a solid. When the intermolecular forces are not so strong such as dispersion forces and hydrogen bonds, the substance exists as a liquid. However, very weak intermolecular dispersion forces are found in gases hence the molecules are relatively free when compared to molecules of liquids and solids.

Answer:

NH4NO3 = N2O + 2(H2O)

Explanation:

there are 2 N, 4 H, 3 O

Answer:

NH4NO3=N2O+2H2O

Explanation:

N-2,O-3,H-4

Answer:

Numbers 4,3

Explanation:

Ionic bond is between nonmental and metals

Answer:

The correct answer is 32.2 grams.

Explanation:

Based on the given information, the enthalpy of formation for aluminum oxide is 1676 kJ/mol. It signifies towards the energy that is required to generate aluminum and oxygen, and both of these exhibit zero enthalpy of formation. Therefore, the ΔHreaction is the required energy to generate 2 moles of aluminum. Thus, the energy needed for the formation of single mole of aluminum is,  

ΔHrxn = 1676/2 = 838 kJ/mol

Q or the energy input mentioned in the given case is 1000 kJ. Therefore, the number of moles of Al generated is,  

(1000 kJ) / (838 kJ/Al mole) = 1.19 moles of Aluminum

The grams of aluminum produced can be obtained by using the formula,  

mass = moles * molecular mass

= 1.19 * 26.98

= 32.2 grams.  

In the thermal decomposition of aluminum oxide, the transference of 1.000 × 10³ kJ of heat can produce 32.19 g of Al.

A thermochemical equation is a balanced stoichiometric chemical equation that includes the enthalpy change.

Al₂O₃(s) ⇒ 2 Al(s) + 3/2 O₂(g)     ΔH rxn = 1676 kJ

According to the thermochemical equation, 2 moles of Al are formed when 1676 kJ of heat is transferred.

1.000 × 10³ kJ × (2 mol Al/1676 kJ) = 1.193 mol Al

The molar mass of Al is 26.98 g/mol.

1.193 mol × 26.98 g/mol = 32.19 g

In the thermal decomposition of aluminum oxide, the transference of 1.000 × 10³ kJ of heat can produce 32.19 g of Al.

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Answer:

A. The pH value of rainwater is acidic about 4.4

B. The molar concentrations of the Hydronium ions are more than that of the hydroxide ions. That is why the rainwater is acidic with a pH of less than 7

Explanation:

A. Methyl orange is an acid indicator that is used to detect acidic solutions which have pH values that fall within the range of about 4.4 to 7.  The distinct yellow colour change that was shown by the methyl orange as it was added to the water shows that the pH value is acidic, with a value above 4.4. (it has to be like this before methyl orange changes to  yellow colour)

B. The Hydronium ( H30+) ion concentrations and the hydroxide (OH-) ion concentrations are used to measure the pH values of substances.

We can tell that the Hydronium ( H30+) ion concentrations are more than the hydroxide (OH-) ion concentrations in the sample of rainwater tested. This can be detected from the colour change that both the methyl orange and the litmus paper gave. The indicators showed that the rainwater solution was indeed acidic. Hence, the pH value will be less than 7, but greater than 4.4.

Answer:

[CH₂Cl₂] = 7.07x10⁻² M

[CH₄] = 0.319 M

[CCl₄] = 0.164 M  

Explanation:

The equilibrium reaction is the following:

2CH₂Cl₂(g) ⇄ CH₄(g) + CCl₄(g)  

The equilibrium constant of the above reaction is:

[tex] K = \frac{[CH_{4}][CCl_{4}]}{[CH_{2}Cl_{2}]^{2}} = \frac{0.173 M*0.173 M}{(5.35 \cdot 10^{-2} M)^{2}} = 10.5 [/tex]

When 0.155 mol of CH₄(g) is added to the flask we have the following concentration of CH₄:

[tex] C = \frac{\eta}{V} = \frac{0.155 mol}{1.00 L} = 0.155 M [/tex]

[tex]C_{CH_{4}} = 0.328 M[/tex]      

Now, the concentrations at the equilibrium are:

2CH₂Cl₂(g)   ⇄   CH₄(g)  +  CCl₄(g)

5.35x10⁻² - 2x   0.328 + x   0.173 + x    

[tex]K = \frac{[CH_{4}][CCl_{4}]}{[CH_{2}Cl_{2}]^{2}} = \frac{(0.328 + x)(0.173 + x)}{(5.35 \cdot 10^{-2} - 2x)^{2}}[/tex]

[tex]10.5*(5.35 \cdot 10^{-2} - 2x)^{2} - (0.328 + x)*(0.173 + x) = 0[/tex]

Solving the above equation for x:  

x₁ = 0.076 and x₂ = -0.0086

Hence, the concentration of the three gases once equilibrium has been reestablished is:

[CH₂Cl₂] = 5.35x10⁻² - 2(-0.0086) = 7.07x10⁻² M

[CH₄] = 0.328 + (-0.0086) = 0.319 M

[CCl₄] = 0.173 + (-0.0086) = 0.164 M  

We took x₂ value because the x₁ value gives a negative CH₂Cl₂ concentration.

I hope it helps you!

Cathode ray experiments of the following provides evidence to support Thomson's hypothesis about electrons.

Rutherford's gold leaf experiment demonstrated that the atom is essentially empty space with such a tiny, compact, positively-charged nucleus. Thomson had proposed the plum pie model of the atom, which featured negatively-charged electrons buried within a favorably "soup." Since most of the alpha particles flow through an atom directly without being deflected, contrary to what Thomson's model predicted, the majority of a space inside of an atom is empty. As a result, the Thomson model of a molecule was disproved.

According to Thomson's model, every atom is made up of negative charges "plums" surrounded in positively charged "pudding," or electrons with a soup of positive ion to balance their negative charges. Hans Geiger and Arthur Marsden's 1909 gold foil test refuted the 1904 Thomson model.

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Answer:

0.287 mole of PCl5.

Explanation:

We'll begin by calculating the number of mole in 51g of Cl2. This is illustrated below:

Molar mass of Cl2 = 2 x 35.5 = 71g/mol

Mass of Cl2 = 51g

Number of mole of Cl2 =..?

Mole = Mass /Molar Mass

Number of mole of Cl2 = 51/71 = 0.718 mole

Next, we shall write the balanced equation for the reaction. This is given below:

P4 + 10Cl2 → 4PCl5

Finally, we determine the number of mole of PCl5 produced from the reaction as follow:

From the balanced equation above,

10 moles of Cl2 reacted to produce 4 moles of PCl5.

Therefore, 0.718 mole of Cl2 will react to produce = (0.718 x 4)/10 = 0.287 mole of PCl5.

Therefore, 0.287 mole of PCl5 is produced from the reaction.

Answer:

It is neutral (NR)

Explanation:

Salts are formed when the ionizable hydrogens in an acid is replaced by metallic or ammonium ions from bases. The reaction is known as a neutralization reaction.

The nature of a salt formed from this reaction depends on the nature of the reacting acid and base.

If the reaction is between a strong acid and strong base, the salt produced is a neutral salt.

If the reaction occurs between a strong acid and a weak base, the salt produced is acidic.

If the reaction occurs between a strong base and a weak acid, the salt produced is a basic salt.

Considering the salt above, LiNO3.

On hydrolysis, addition of water, the following products are obtained:

LiNO3 + H2O ----> LiOH + HNO3

The products obtained, LiOH and HNO3 are a strong base and a strong acid respectively. Therefore, the salt, LiNO3, is a neutral salt.

The salt, LiNO₃ is a neutral, NR salt as it's a salt formed from the reaction of a strong acid and a strong base.

In neutralisation reactions, acids and bases react to form salt and water.

However, the salt formed may be acidic, basic or neutral. This is dependent on the type of acid and base which form the salt.

A strong acid and a strong base react to yield a neutral salt like, LiNO₃.

The equilibrium equation when LiNO₃ is dissolved in aqeous solution is;

Evidently, LiOH and HNO₃ are an example strong base and acid respectively.

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Answer: Ethanol is the odd one out.

Explanation:

A polar compound is defined as the compound which is formed when there is a difference of electronegativities between the atoms. It is also defined as the bond which is formed due to the unequal sharing of electrons between the atoms.

Non-polar compound is defined as the compound which is formed when there is no difference of electronegativities between the atoms or the polarities cancel out.

Hexane [tex](C_6H_{14}), Oil (mixture of hydrocarbons) and carbon tetrachloride [tex](CCl_4)[/tex] all are non polar whereas ethanol is polar due to electronegative difference between hydrogen and oxygen.

Answer:

C

Explanation:

It looks pretty reasonable to me

Answer:

That its small pointed. Pink(Himalayan salt)or white(normal salt)

Explanation:

Summa dees questions are so stupid, deys makin me salty.

Answer: D

Explanation: The elements in two compunds switch places

Answer:

The percentage of the void space out of the total volume occupied is 93.11%

Explanation:

A mole of water contains 2 atoms of hydrogen and 1 atom of oxygen.

To calculate the volume of a mole of water, we calculate 2 times the volume of the hydrogen atom and 1 times the volume of the oxygen atom

Let's calculate this one after the other.

For the hydrogen, formula for the volume will be

[tex]V_{hydrogen[/tex] = 2 × 4/3 × π × [tex]r_{H}^{3}[/tex]

where [tex]r_{H}^{3}[/tex] = 37 pm which is read as 37 picometer (1 picometer = 10^-12 m) = 37 × [tex]10^{-12}[/tex] meters

Volume of the hydrogen = 8/3 × (37 × 10^-12)^3 = 4.05 * 10^-31

we multiply this by the avogadro's number = 6.02 * 10^23

= 4.05 * 10^-31 * 6.02 * 10^23 = 2.6 * 10^-8 m^3

We do same for thr oxygen, but this time we do not multiply the volume of the oxygen by 2 as we have only one atom of oxygen

Volume of oxygen = 4/3 * π * (73 * 10^-12) ^3 * avogadro's number = 9.81 * 10^-7 m^3

adding both volumes together, we have 1.24 * 10^-6 m^3 or simply 1.24 ml ( 0.01 m = 1 ml)

Dividing the molar mass of one mole of water by its density, we can get the volume of 1 mole of water

= (18g/mol)/(1 g/ml) = 18 ml/mol

Now we proceed to calculate the volume of void = Total volume - volume of molecule = 18 - 1.24 = 16.76 ml

Now, the percentage of void = volume of void/total volume * 100%

= 16.76/18 * 100% = 93.11%

Answer:

Explanation:

The specific rotation of the sample is -2 degrees/0.2 g/mL of mixture

This equals -10 degrees/g/mL of sample.

let the proportion of the R (+) enantiomer be x. The proportion of the S (-) enantiomer in the mixture will be given by (1-x).

specific rotation of the mixture = proportion of R enantiomer* its specific rotation + proportion of S enantiome * its specific rotation

i.e.

-10 = x *(+20) + (1-x)*(-20)

-10 = 20x-20 + 20x

-10+20 = 40x

+10 = 40 x

x=10/40 = 25%

Since the proportion of the other enantiomer is 1-x, it is 0.75 or 75%

So the mixture contains 25% R, 75% S, giving you an excess of 50%.

Answer:

10%

Explanation:

Enantiomeric excess is a way of describing how optically pure a mixture is by calculating the purity of the major enantiomer. It can range from 0%-100%. Enantiomeric excess ( ee ) can also be defined as the absolute difference between the mole fractions of two enantiomers.

Enantiomeric excess is also called optical purity. This is because chiral molecules cause the rotation of plane-polarized light and are said to be optically active. An enantiomerically pure sample has an enantiomeric excess of 100 percent

Enantiomeric excess = observed specific rotation/specific rotation of the pure enantiomer x 100

From the data given in the question;

observed specific rotation= -2°

specific rotation of the pure enantiomer = +20°

Therefore;

ee= 2/20 ×100

ee= 10%

Answer:

Answer is letter B

Explanation:

The first one is wrong because acids release H+, not bases.

The third one is wrong because the pH is exactly 7, not greater.

The last one is wrong because it is vague and does not fit a neutralization reaction.

Answer:

The correct answer to the following question will be Option A (DNA sequencing and profiling).

Explanation:

The other three situations aren't connected to the situation in question. That option 1 seems to be the right answer.

Answer:

For our assumed experiment; the expected  volume of Hcl acid needed to neutralize the bicarbonate is 0.13 mL

Explanation:

We are going attempt this question experimentally.

We know that benzoic acid originate from the relationship between  benzene and a carboxylic group. So basically , the functional group of a carboxylic acid (-COOH) joins with a benzene ring(C₆H₆) to form a simple aromatic carboxylic acid known as Benzoic acid. (C₇H₆O₂)

However, it is possible to isolate benzoic acid from  a bicarbonate solution in the presence of an acidified concentrated hydrochloric acid.

Let assume that ;

0.20 g of benzoic acid was reacted with 2 mL of a 20% solution of NaHCO₃, the amount of the  excess NaHCO₃ can be determined by subtracting the amount of benzoic acid from the amount of NaHCO₃.

Let first calculate the number of moles in 0.20 g of benzoic acid

we know that the standard  molar mass of benzoic acid is 122.12 g/mol

number of moles of benzoic acid = mass of benzoic acid/molar mass of benzoic acid =

number of moles of benzoic acid = 0.20/ 122.12

number of moles of benzoic acid = 0.0016 mol

number of moles of bicarbonate  solution = mass of bicarbonate solution/ molar mass of bicarbonate solution

number of moles of bicarbonate  solution =  0.2/84.00654 g/mol

number of moles of bicarbonate  solution =  0.00238 mol

∴

(0.00238 - 0.0016) mol

= 7.8 × 10⁻⁴ mol

Let assume that the concentrated HCl is 12  M

Also. HCl and NaHCO₃ react together at the ratio of 1:1; thus the  volume of Hcl acid needed to neutralize the bicarbonate is:

[tex]= ( 7.8 * 10^{-4} \ \ mol )* ( \dfrac{2\ L}{ 12 \ M})*( \dfrac{10^3 \mL}{1 \ L})[/tex]

= 0.13 mL

Thus; for our assumed experiment; the expected  volume of Hcl acid needed to neutralize the bicarbonate is 0.13 mL

Answer:

[tex]Q=-3.11x10^5kJ[/tex]

Explanation:

Hello,

In this case, for the given reaction, we are given the standard enthalpy of reaction per mole of ammonia that is -92.6 kJ, it means, that forming one mole of ammonia will release 92.6 kJ of energy. In such a way, for the formation of 5.71x10⁴ g of ammonia, the following amount of heat will be released:

[tex]Q=5.71x10^4gNH_3*\frac{1molNH_3}{17gNH_3}*-92.6\frac{kJ}{molNH_3}\\ \\Q=-3.11x10^5kJ[/tex]

Best regards.

The amount of the heat associated with the production of 5.71×10⁴ g of ammonia, NH₃ is –311026.732 KJ

We'll begin by calculating the number of mole in 5.71×10⁴ g of NH₃

Mass of NH₃ = 5.71×10⁴ g

Molar mass of NH₃ = 14 + (3×1) = 17 g/mol

Mole = mass / molar mass

Mole of NH₃ = 5.71×10⁴ / 17

N₂(g) + 3H₂(g) —> 2NH₃(g) ΔH°rxn = −92.6 kJ

Since reaction took place at standard conditions, it means:

1 moles of NH₃ required −92.6 kJ

Therefore,

3358.82 moles of NH₃ will require = 3358.82 × –92.6 = –311026.732 KJ

Thus, the amount of the heat associated with the production of 5.71×10⁴ g of ammonia, NH₃ is –311026.732 KJ

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Answer:

The fugacity coefficient is  [tex][\frac{f}{p} ] = 1.45[/tex]

Explanation:

From the question we are told that

  The gas obeys the equation [tex]p(v-b) = RT[/tex]

   The value  of b is  [tex]b = b = 0.0391 \ L /mol[/tex]

   The pressure is  [tex]p = 1000 \ atm[/tex]

    The temperature is [tex]T= 1000^oC = 1273 K[/tex]

generally

        [tex]RT ln[\frac{f}{p} ] = \int\limits^{p}_{o} [ {v_{r} -v_{i}} ]\, dp[/tex]

Where  [tex]\frac{f}{p}[/tex] is the fugacity coefficient

          [tex]v_r[/tex] is the real volume which is mathematically evaluated from above equation  as

           [tex]v_r = \frac{RT}{p} + b[/tex]

           [tex]v_r = \frac{RT}{p} + 0.0391[/tex]

and     [tex]v_{i}[/tex] is the ideal volume which is evaluated from the ideal gas equation (pv = nRT , at  n= 1) as

         [tex]v_{i} = \frac{RT}{p}[/tex]

So

     [tex]RT ln[\frac{f}{p} ] = \int\limits^{1000}_{o} [[ \frac{RT}{p} + 0.0391] - [\frac{RT}{p} ]} ]\, dp[/tex]

=>      [tex]RT ln[\frac{f}{p} ] = \int\limits^{1000}_{o} [0.391 ]\, dp[/tex]

=>    [tex]RT ln[\frac{f}{p} ] = [0.391p]\left | 1000} \atop {0}} \right.[/tex]

=>   [tex]RT ln[\frac{f}{p} ] = 38.1[/tex]

   So

         [tex]ln[\frac{f}{p} ] = \frac{39.1}{RT}[/tex]

Where R is the gas constant with value [tex]R = 0.082057\ L \cdot atm \cdot mol^{-1}\cdot K^{-1}[/tex]

         [tex][\frac{f}{p} ] = \frac{39.1}{ 2.303 *0.082057 * 1273}[/tex]

        [tex][\frac{f}{p} ] = 1.45[/tex]

Answer:

polyethylenes

Explanation:

the plastic bottles used to hold potable water and other drinks are made from polyethylene because, the material is both strong and light.

hope this helped!

Answer: Polyethylenes

Explanation: I got 100% on the test :)

Answer:

93.15 %

Explanation:

We have to start with the chemical reaction:

[tex]CaCl_2~+~Na_2CO_3~->~CaCO_3~+~NaCl[/tex]

Now, we can balance the reaction:

[tex]CaCl_2~+~Na_2CO_3~->~CaCO_3~+~2NaCl[/tex]

Our initial data are the 15.71 g of [tex]CaCl_2[/tex], so we have to do the following steps:

1) Convert from grams to moles of [tex]CaCl_2[/tex] using the molar mass (110.98 g/mol).

2) Convert from moles of [tex]CaCl_2[/tex] to moles of [tex]CaCO_3[/tex] using the molar ratio. ( 1 mol [tex]CaCl_2[/tex]= 1 mol of [tex]CaCO_3[/tex]).

3) Convert from moles of [tex]CaCO_3[/tex] to grams of [tex]CaCO_3[/tex] using the molar mass. (100 g/mol).

[tex]15.71~g~CaCl_2\frac{1~mol~CaCl_2}{110.98~g~CaCl_2}\frac{1~mol~CaCO_3}{1~mol~CaCl_2}\frac{100~g~CaCO_3}{1~mol~CaCO_3}=14.16~g~CaCO_3[/tex]

Finally, we can calculate the yield percent:

[tex]%~=~\frac{13.19~g~CaCO_3}{14.16~g~CaCO_3}*100=93.15~%[/tex]

I hope it helps!

The percentage yield obtained when excess sodium carbonate, Na₂CO₃, is added to a solution containing 15.71 g CaCl₂ is 93.2%

Molar mass of CaCl₂ = 40 + (35.5×2) = 111 g/mol

Mass of CaCl₂ from the balanced equation = 1 × 111 = 111 g

Molar mass of CaCO₃ = 40 + 12 + (16×3) = 100 g/mol

Mass of CaCO₃ from the balanced equation = 1 × 100 = 100 g

SUMMARY

From the balanced equation above,

111 g of CaCl₂ reacted to produce 100 g of CaCO₃

From the balanced equation above,

111 g of CaCl₂ reacted to produce 100 g of CaCO₃.

Therefore,

15.71 g of CaCl₂ will react to produce = [tex]\frac{15.71 * 100}{111} \\\\[/tex] = 14.15 g of CaCO₃.

Thus, the theoretical yield of of CaCO₃ is 14.15 g

Actual yield of CaCO₃ = 13.19 g

Theoretical yield of CaCO₃ = 14.15 g

[tex]Percentage yield = \frac{Actual}{Theoretical} * 100\\\\= \frac{13.19}{14.15} * 100\\\\[/tex]

Therefore, the percentage yield of the reaction is 93.2%

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Answer:

Amide

Explanation:

O=NH2 is the Amide group versus NH2, which is the amine group.

Answer:

Butamide

Explanation:

C3H7-C(=O)-NH2 IUPAC NAME

C4H9NO

     H   H   H

H - C - C - C - C = O

     H   H   H   N - H

                      H

But amide

Amide because R-CO-NH2 ie C(=O)-NH2

But because 4 Cabon

Answer:  [tex]H_2PO_4[/tex] and [tex]H_3PO_4[/tex]

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given reaction:

[tex]H_2PO_4^-+H_2O\rightleftharpoons H_3PO_4+OH^-[/tex]

Here, [tex]H_2O[/tex] is loosing a proton, thus it is considered as an acid and after losing a proton, it forms [tex]OH^-[/tex] which is a conjugate base.

Similarly , [tex]H_2PO_4^-[/tex] is gaining a proton, thus it is considered as an base and after gaining a proton, it forms [tex]H_3PO_4[/tex] which is a conjugate acid.

Thus [tex]H_2PO_4[/tex] and [tex]H_3PO_4[/tex] is a conjugate acid-base pair in the reaction represented by the equation below

The Bronsted-Lowry conjugate acid-base hypothesis defines an acid as a substance that loses protons and donates them to another chemical to produce conjugate base, and a base as a substance that takes protons to generate conjugate acid.

Thus, a proton is being lost, making it an acid, and once a proton is lost, a conjugate base is formed. Similar to that, is gaining a proton, making it a base, and then it produces a conjugate acid after gaining a proton.

The Brnsted-Lowry hypothesis, often known as the proton theory of acids and bases, is an independent theory of acid-base reactions that was put forth in 1923 by Johannes Nicolaus Brnsted and Thomas Martin Lowry.

This theory's central idea is that when an acid and a base interact, the acid creates its conjugate base and the base creates its conjugate acid by exchanging a proton (the hydrogen cation, or H+).

Thus, The Bronsted-Lowry conjugate acid-base hypothesis defines an acid as a substance that loses protons and donates them to another chemical to produce conjugate base, and a base as a substance that takes protons to generate conjugate acid.

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Answer:

Explanation:

use gas law eqation

P1 * V1  / T1 = P2 * V2 /T2

600*V1/227 = 300*800/23

V1 = 300*800*227 / 23*600 = ............ can you solve this and get the answer?

Answer:

Final temperature of the solution = 26.43°C

Explanation:

Concentration of HCl = 0.662 M, Volume = 200 mL= 0.200 L

Concentration of Ba(OH)₂ = 0.331 M, Volume = 200 mL = 0.200 L

Initial temperature of solution = 22.00°C

Specific Heat capacity of water = 4.184 J/g°C

Heat of neutralization = -56.3 KJ/mol of H₂O produced.

The full calculations is found in the attachment below

Answer:

The correct answer is 4.502 g per ml.

Explanation:

Based on the given question, the sum of the mass of mesitylene and barium together is 148.792 grams. The mass of barium given is 77.240 grams. Therefore, the mass of mesitylene will be,  

Mass of mesitylene = Total mass - Mass of barium

= 148.792 - 77.240

= 71.552 grams

The density of mesitylene is 0.86370 g per ml. To calculate the volume of mesitylene, the formula to be used is,  

Volume = mass / density. Now, putting the values we get,  

Volume = 71.552 / 0.86370 = 82.8436 ml.  

As the total volume is 100 ml, therefore, the volume of Ba will be,  

Volume of Ba = 100-82.8436 = 17.1564 ml

The density of Ba at 20 degree C can be calculated by using the formula,  

Density = mass / volume. Now putting the values we get,  

Density = 77.240 g / 17.1564 ml  

= 4.502 g per ml