what is the average speed of the object during the first 4.0 seconds?
0 m/s^2
2 m/s^2
4 m/s^2
8 m/s^2​

What Is The Average Speed Of The Object During The First 4.0 Seconds?0 M/s^22 M/s^24 M/s^28 M/s^2

Answers

Answer 1

Answer:

The average speed of the given object.. is 2m/^s


Related Questions

i am giving brainly to however answers first
A student made the table to showing how different objects transform electrical energy. Which statement best explains why the table is incorrect?

Item Transformed Energy

Radio Electrical → Sound

Lamp Electrical → Light

Doorbell Electrical → Motion

Iron Electrical → Heat

The doorbell transforms electrical energy into sound.

The iron transforms electrical energy into light.

The lamp transforms electrical energy into sound.

The radio transforms electrical energy into heat.

Answers

Answer:

The doorbell transforms electrical energy into sound.

Explanation:

The doorbell MAY turn electrical energy into motion of a striker which then impacts a resonator creating sound. However all door bells do not have solenoids. Some are electronic playing recordings when activated.

All doorbells do produce sound, though.

Q1. How much gravitational potential energy do you gain when you walk up the CN Tower stairs (346 m)? What type of energy/energies transformed into GPE in this scenario?​

Answers

The characteristics of the gravitational potential energy allows to find the results for the energy change when climbing the stairs are:

The energy change is:  ΔU = 3390.8m. If the mass is m = 1kg the energy is ΔU = 3390.8 J This energy is a system configuration energy type.

Potential energy is a configuration energy of the system, the system has the ability to perform work. The gravitational potential energy is:

           U = mg y - U₀

Where U is the gravitational potential energy and m the mass of the body, g the acceleration of gravity and y the height, Uo is the zero of the energy that must be defined for each case.

Indicates that the body rises a height of y = 346 m, the energy increases.

         ΔU = U-U₀ = m g y

         ΔU = m 9.8 346

         ΔU = 3390.8 m

Where m is the mass of the body. If we assume that the mass is m = 1kg.

         ΔU = 3390.8 J

This energy is due to the height therefore it is due to the configuration of the system, consequently it is a configuration energy.

In conclusion, using the characteristics of gravitational potential energy we can find the results for the energy change when climbing the stairs are:

The energy  change is ΔU = 3390.8m.  If the mass is m = 1kg the energy is ΔU = 3390.8 J Potential energy  is a system configuration wnwegy type.

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An arrow is shot straight up in the air from the ground with an initial velocity of 54.0 m/s. If on striking the ground it
embeds itself 15.0 cm into the ground, what is the acceleration required to stop the arrow when it hits the ground?

Answers

hindi ko po alam yan sorry po

A 1500-kg car accelerates from 0 to 25 m/s in 7.0 s. What is the average power delivered by the engine (1 hp

Answers

Answer:

The average power delivered by the engine is 90 hp.

Make a rule: If you know the width, length, and mass of a boat, how can you calculate how deep it will sink in water

Answers

Answer:

U would need to know the depth of the water

Explanation:

A strechy material with a spring constant of 42 N/m is stretched 3.6 cm from its equilibrium length. What is the magnitude of the resulting spring force

Answers

k : spring constant
X : distance from equilibrium position
F = 1/2 x k x X^2
F = 1/2 x 42 x 0.036^2
F = 0.027 N

The force acting on a stretchy  material is the product of of the spring constant and the displacement by stretching of the material. Thus, resultant force  of the material with a spring constant o 42 N/m with a displacement of 3.6 cm is 1.51 N downwards.

What is force?

Force is an external agent acting on a body to change it form the state of rest or motion. There are various kinds of forces such as gravitational force, nuclear force, magnetic force, frictional force etc.

A stretching material such as a string will experience an elastic nature. The force F acting on the spring is directly proportional to the its displacement X. The proportionality constant is called spring constant.

Hence we can write it as ,

F = -kx

Here, the spring constant is given 42 N/m and displacement is 3.6 cm or 0.036 m. Now the force is calculated as follows:

Force =  -0.036 m ×  42 N/m

          =- 1.51 N

The negative sign indicates the direction is downwards.

Thus, the force acting on the material is 1.51 N.

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Suppose that an object of mass 11.4 g is hung from a vertical spring that is stretched 10 cm as a result. What is the spring constant of this spring, in N/m

Answers

Neglect the mass of spring
Mg = Fspring
11.4 x 10^-3 x 9.8 = 1/2 x k 10^-2
k = 22.344 N/m

If a radio is connected between the open wire and the circuit is closed, what happens?

Answers

You need a closed path, or closed circuit, to get electric current to flow.

Please list the following for the Element, HYDROGEN
Number of protons, number of electrons, and number of neutrons
Period number
Group number
Name of group to which it belongs (i.e., alkali metals, alkaline earth metals, halogens,
noble gases, and so on)

PLEASE INCLUDE ALL INFORMATION THANK YOU! WILL MARK BRAINLIEST IF ANSWERED CORRECTLY

Answers

Answer:

1 Proton, 1 Electron, No Neutrons

Group 1, Period 1

Gases

One factor that could account for a drop in the water table is:
A. more wind.
B. less porous soil.
C. more clouds.
D. less rain and snow.

Answers

Answer:

D. Less rain and snow.  

Explanation:

A factor that can be a account for a drop in the water table is, less rain and snow. to topography, water tables is influenced by lot of factors, including the geology, weather, ground cover.

A plane traveling 3.1 m/s east encounters wind traveling 4.7 m/s north. The wind current is 18 m wide. Determine the time to cross the wind current.

Answers

T = 18 / 3.1
T = 5.80 second
T = 6 second.

d. If they are dropped from their original heights at the same time, will the melon or
the pomegranate hit the ground first? Explain. (1 point)

Answers

Answer:

Melon

Explanation:

The melon will hit the ground first because it has a greater mass and therefore greater gravitational pull than the pomegranate, which weighs less.

Both  melon and the pomegranate will reach the ground at the same time

What is gravitational force ?

The force between all masses in the universe, especially the force of the earth's mass for bodies near its surface is called gravitational force

Both  melon and the pomegranate will reach the ground at the same time ,because melon is heavier hence it will have greater gravitational force on it but it will also has lower acceleration but pomegranate have lighter mass hence will have  lower gravitational force but have higher acceleration , so these two effects will cancel each other and allow both melon and pomegranate to reach the ground at  same time .

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What is the mass of a person who
weighs 343 N?
m
[?] kg

Answers

Answer:

the answer is 343/9.8=35

Explanation:

the answer is 35 because mass=weight/gravity

The mass of a person who weighs 343 N is 35.0 kg.

What are mass and weight?

The most fundamental characteristic of matter is mass, which is one of the fundamental quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilograms is the SI unit of mass (kg).

Weight is a measurement of how much gravity is pulling on a body.

The weight formula is as follows: w = mg

Since weight is a force, it has the same SI unit as a force, which is the Newton (N). It depends on both mass and the acceleration caused by gravity.

The weighs of the person is = 343 N

The mass of the person is = weighs of the person ÷ acceleration due to gravity

= 343 N ÷ 9.80 m/s²

= 35.0 kg.

Hence, the mass of the person is 35.0 kg.

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The gravitational force between two objects is represented by the variable F.

If the masses are both doubled and the distance is halved, what is the new gravitational force?

Answers

Explanation:

Fgravity = G*(mass1*mass2)/D²

G is the gravitational constant, which has the same value throughout our universe.

D is the distance between both objects.

now, we change these numbers

Fgravitynew = G*(2*mass1*2*mass2)/(1/2 * D)² =

= G*(4*mass1*mass2)/(D²/4) =

= 4* (G*(mass1*mass2)/D²) *4 =

= 16* (G*(mass1*mass2)/D²) = 16*Fgravity

so, the new gravitational force will be 16×F.

Identify if the verbs signal past, future, or present tense, and drag them to the appropriate box. I walked home. She will walk home. It will open next week. She studied. He made a list. She walks home. They leave the door open. W Past Present Future​

Answers

Answer:

Past  

I walked home.

She studied.

He made a list.

 

Present

She walks home.

They leave the door open.

 

Future

She will walk home.

It will open next week.

Explanation:

Question 1 (2 points)
What is gravitation?
Question 1 options:

the tendency of objects to move downward

the attraction of any two objects because of their mass

the attraction or repulsion of objects because of their electric charge

the effect of air pressure in pushing objects to the ground
Question 2 (2 points)
Which of these was discovered by Newton?
Question 2 options:

The acceleration caused by gravity is�9.8�m/s/s.

Gravity keeps the planets in their orbits.

The planets move in elliptical orbits around the sun.

The earth orbits the sun, rather than the reverse.
Question 3 (2 points)
How was the gravitational constant�G�first determined?
Question 3 options:

by measuring the force of gravity between two planets

by observing the moon's orbit

by measuring the force of gravity between two objects on the earth

by knowing that the acceleration caused by gravity is�9.8�m/s/s
Question 4 (2 points)
The force of gravity between any two ordinary objects on the earth is __________.
Question 4 options:

always downward

stronger when closer to the earth

stronger if the objects are more massive

stronger than the force of gravity from the earth
Question 5 (2 points)
Which of these statements is true about the International Space Station in orbit around the earth?
Question 5 options:

The space station exerts a force on the earth toward the space station.

The earth's gravity acts on the space station, but not the reverse.

There is no gravity acting at the height of the space station.

The force of gravity produces the same acceleration for the earth and the space station.
Question 6 (2 points)
Suppose a planet has twice the mass of the Earth and twice the earth's radius. What is the acceleration of an object in free fall on this planet?
Question 6 options:

twice as much as on Earth.

four times as much on Earth.

one half as much as Earth.

one fourth as much as Earth.
Question 7 (2 points)
Which of these does Newton's law of universal gravitation imply?
Question 7 options:

Force is mass times acceleration squared.

There is no gravity inside a space station in orbit.

The earth attracts the moon more strongly than the moon attracts the earth.

The force of the earth's gravity on an object at sea level is stronger than at the top of a mountain.
Question 8 (2 points)
What is a gravitational field?
Question 8 options:

a region of space-time with constant gravity

the region of space-time where the force is equal to�6.67�10?11�N

a region of space-time with a property at each point determined as the gravitational force on any object divided by its mass�m

the force of gravity between any two objects
Question 9 (2 points)
A gravitational field can be represented by
Question 9 options:

field vector arrows pointing in the direction of the gravitational force.

field vector arrows pointing in the direction of the electrical force.

a photo of a large, green field filled with heavy grass.

field vector arrows pointing in random directions based on their mass.
Question 10 (2 points)
What is the magnitude of a gravitational field at a location where an 80 kg astronaut weighs 25 percent what he would weigh on the earth?
Question 10 options:

10 N/kg

2.5 N/kg

20 N/kg

200 N/kg
Question 11 (2 points)
What causes gravitational force in Einstein's theory of general relativity?
Question 11 options:

the way an object with mass placed on a surface bends the surface

the way mass bends space and time

the existence of black holes

reference frames moving at a constant relative velocity
Question 12 (2 points)
A mass of 10.0 kg is in a gravitational field of�3.50�N/kg�. What force acts on the mass?
Question 12 options:

0.35 N

9.8 N

35.0 N

21.6 N

Answers

We have several questions about gravity, the answers are:

The first question is, what is gravitation?

We define gravitational force as the attraction force between two objects with mass. From this, we can see that the correct option is:

"the attraction of any two objects because of their mass"

The second question is, which of the following was discovered by Newton?.

Newton concluded that the forces between objects with masses were what defined the orbits in the solar system, so the correct option here is:

"Gravity keeps the planets in their orbits."

The third question is: How the gravitational constant was first determined?

It was originally measured by Cavendish in 1978, he actually measured Earths density, and by knowing that the acceleration was roughly 9.8m/s^2, he could estimate the constant, so here the correct option is:

"by knowing that the acceleration caused by gravity is 9.8 m/s/s"

The fourth question is: The force of gravity between any two ordinary objects on the earth is?

Remember, gravity is an attractive force that depends on the mass of the objects. Here the only option that is always correct is:

"stronger if the objects are more massive"Question 5:Here the correct option is:"

For question 5 we have that the correct one is:

"The space station exerts a force on the earth toward the space station" Gravity acts on both objects, the earth and space station, just that the planet has a lot more mass than the space station, thus the force that it causes in the planet is negligible.

Question 6:

Gravity increases linearly with mass and decreases quadratically with distance, so if we double the mass and the radius, we can expect that the gravity at the surface to be near half of that one we have on Earth, then the correct option is:

"one half as much as Earth."

Question 7:

Again, force decreases with distance squared, then if you are closer to the planet, let's say, at sea level, the force will be greater than if you are on top of a mountain. The correct option is:

"The force of the earth's gravity on an object at sea level is stronger than at the top of a mountain."

Question 8.

By definition of gravitational field, the correct option is the last one:

"a region of space-time with a property at each point determined as the gravitational force on any object divided by its mass"

Question 9:

The field defines the force, thus the arrows should point in the same direction that the force acts, the correct option is:

"field vector arrows pointing in the direction of the gravitational force."

Question 10:

The correct option is 2.5 N/kg

Notice that N/kg = m/s^2

To get this, you just need to compute the 25% of Earth's gravitational acceleration.

Question 11:

The correct option is:

"the way an object with mass placed on a surface bends the surface"

Gravity is thought as a deformation in the space plane.

Question 12:

We just multiply the mass by the field:

10kg*3.5 N/kg = 35N

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how long in seconds would it take a rock to fall 450 feet and what would be the final velocity of the rock in miles per hour when it hit the ground

Answers

Answer:

S = Vy t + 1/2 g t^2 = 1/2 g t^2    vertical speed with zero initial speed

t = (2 S / g)^1/2      with g = 32 ft/sec^2

t = (900 / 32)^1/2 = 5.30 sec    time to reach ground

V = a t = 32 ft/s^2 * 5.30 s = 170 ft/sec

170 ft/sec / (88 ft/sec / 60 mph) = 116 mph           since 88 ft/sec = 60 mph

help this is urgent ;-;

Answers

Answer:Intensive properties are more useful.This is because these characteristics—colour,odour,melting points,boiling points etc—do not depend on the amount of sample, nor do they change according to conditions.

Ps:I hope this was clear


A jet needs to reach a "lift-off' speed of 120 m/s before it can leave the ground. How quickly must
the jet accelerate if the run way has a length of 322 m?

Answers

The jet must accelerate in 5.37 s if it must reach the lift-off speed

From the question given above, the following data were:

Initial velocity (u) = 0 m/s

Final velocity (v) = 120 m/s

Distance (s) = 322 m

Time (t) =?

The time needed for the jet to accerate can be obtained as follow:

[tex]s = \frac{(v + u)t}{2} \\ \\ 322 = \frac{(120 + 0)t}{2} \\ \\ 322 = \frac{120t}{2} \\ \\ cross \: multiply \\ \\ 120t = 322 \times 2 \\ \\ 120t = 644 \\ \\ divide \: both \: side \: by \: 120 \\ \\ t = \frac{644}{120} \\ \\ [/tex]

t = 5.37

Thus, the jet must accelerate in 5.37 s in order to reach the lift-off speed

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As the jet leaves the ground, it accelerates at a rate of 22.4 ms-2.

We have the following information from the question;

Final velocity = 120 m/s

Initial velocity = 0 m/s

Distance covered = 322 m

Acceleration = ?

Using the equation;

v^2 = u^2 + 2as

v = final velocity

u = initial velocity

a = acceleration

s = distance

(120)^2 = 0^2 + (2 × a × 322)

14400 = 644a

a = 14400/644

a = 22.4 ms-2

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A solid sphere with a radius of 5cm initially at rest rolls 270cm down a slope 37° above the horizontal. What is its velocity (rad/s) at that point? [PS: it has not reached the foot of the slope]​

Answers

This question involves the concepts of the law of conservation of energy, kinetic energy, potential energy, and moment of inertia.

The angular velocity of the solid sphere at this point is "95.44 rad/s".

According to the law of conservation of energy:

Loss in Potential Energy = Gain in Rotational Kinetic Energy + Gain in Translational Kinetic Energy

[tex]mgh = \frac{1}{2}I\omega^2+\frac{1}{2}mv^2[/tex]

where,

m = mass of sphere

g = acceleration due to gravity = 9.81 m/s²

h = loss in height = (270 cm) Sin 37° = 162.5 cm = 1.625 m

r = radius of sphere = 5 cm = 0.05 m

ω = angular speed of sphere = ?

v = linear speed of sphere = rω

I = moment of inertia of sphere = [tex]\frac{2}{5}mr^2[/tex]

Therefore,

[tex]mgh=\frac{1}{2}\frac{2}{5}mr^2\omega+\frac{1}{2}m(r\omega)^2\\\\gh=\frac{1}{5}r^2\omega^2+\frac{1}{2}r^2\omega^2\\\\(9.81\ m/s^2)(1.625\ m)=(\frac{1}{5}+\frac{1}{2})(0.05\ m)^2\omega^2\\\\\omega=\sqrt{\frac{15.941\ m^2/s^2}{0.00175\ m^2}}[/tex]

ω = 95.44 rad/s

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The attached picture explains the law of conservation of energy.

please HELP IM SOO STUCKKK

A 3.75 kg bucket of water attached
to a rope is swung in a 0.555 m
circle. At the bottom, the tension
in the rope is 172 N. What is the
speed of the bucket at that point?

Answers

Answer:

look at the photo........................

Answer:

4.46 is the correct answer

Explanation:

What force acting on an object would cause it’s weight to change

Answers

Answer:

The Force Of Gravity

Sarah and Tom are riding on a merry-go-round revolving at a constant rate. Sarah is sitting on the edge and Tom is half-way in from the edge. What is the relationship between their centripetal accelerations

Answers

The centripetal acceleration of Tom sitting half-way from the edge of the merry-go-round is double of the centripetal acceleration of Sarah sitting at the edge of the merry-go-round.

Let the constant rate of their motion, = v

Let the radius of the merry-go-round = R

The centripetal acceleration of Sarah sitting at the edge of the merry-go-round is calculated as;

[tex]a_c_1 = \frac{V^2}{R}[/tex]

The centripetal acceleration of Tom sitting half-way from the edge of the merry-go-round is calculated as;

[tex]a_c_2 = \frac{V^2}{\frac{1}{2} \times R } \\\\a_c_2 = \frac{2V^2}{R} \\\\a_c_2 = 2(\frac{V^2}{R} )\\\\a_c_2 = a_c_1[/tex]

Thus, the centripetal acceleration of Tom sitting half-way from the edge of the merry-go-round is double of the centripetal acceleration of Sarah sitting at the edge of the merry-go-round.

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A ball is Thrown straight up with a speed of 30 M/S, and air resistance is negligible what is its velocity after 4.2s

Answers

Answer:

11.2 m/s

Explanation:

We need to first figure out how long it took to reach the ball's max height:

Vf = 0

Vi = 30 m/s

a = -9.81 m/s^2

t = ?

---------------

Vf = Vi + at

0 = 30 + (-9.81)t  --->  -30 = -9.81t  ---> 3.058 = t

t = 3.058 s

---------------

We can now solve the problem by subtracting the given time (4.2s) by the max height time (3.058s) and plugging that into a kinematic equation for Vf:

Vi = 0

a = 9.81 m/s^2

t = (4.2s - 3.058s) = 1.142 s

Vf = ?

---------------

Vf = Vi + at

Vf = 0 + (9.81)*(1.142)  ---> Vf = 11.203

---------------

The velocity of the ball after 4.2s is 11.2 m/s

What power (in horsepower) is developed by a grinding machine whose wheel has a radius of 8.89 in and runs at 7.42 rev/s, when the tool to be sharpened is held against the wheel with a force of 47.3 lb

Answers

Answer:

P = W / t     definition of power

P = F s / t = F v t / t = F v     power expended

v = 2 pi R f         f = frequency = rev / sec     (S = 2 pi R n = 2 pi R f t)

                                                                        and v = S / t

P = F 2 pi R f = 47.3 lb * 6.28 * .741 ft * 7.42 / sec = 1630 ft-lb/sec

(1630 ft-lb/sec) / (550 ft-lb/sec / HP) = 2.96 HP  

Hello, I want to ask. . anyone knows the answer.

Answers

Answer:

1 tablet

Explanation:

The closest rounding of 1.04 that is in the answers is 1.

A 2kg pumpkin is thrown with a velocity of 15m/s towards a brick wall. The pumpkin comes to a crashing rest (0m/s) in 0.05 seconds. What is the force exerted on the pumpkin by the wall?

Answers

The force exerted on the pumpkin by the wall is 600 N

From the question given above, the following data were obtained:

Mass (m) = 2 Kg

Initial velocity (u) = 15 m/s

Final velocity (v) = 0 m/s

Time (t) = 0.05 s

Force (F) =?

The force exerted on the pumpkin by the wall can be obtained as follow:

[tex]f = \frac{m(v + u)}{t} \\ \\ f = \frac{2(0 + 15)}{0.05} \\ \\ f = \frac{2 \times 15}{0.05} \\ \\ f = \frac{30}{0.05} \\ \\ [/tex]

F = 600 N

Therefore, the force exerted on the pumpkin by the wall is 600 N

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A raindrop of mass 3.35 * 10-kg falls vertically at constant speed under the influence of gravity and air resistance. Model the drop as a particle. As it falls 100m, what is the work done on the raindrop (a) by the gravitational force and (b) by air resistance?​

Answers

Answer:

a) Wnet = 0

b) W, = 32.9mJ

c) Wresistance = -32.9mJ

Explanation:

in pic

________________________

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Plane-polarized light is incident on a single polarizing disk with the direction of E0 parallel to the direction of the transmission axis. Through what angle should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of 1.22

Answers

Malus's law allows us to find the result for which is the angle of the polarizer for a reduction of the intensity is:

          θ = 34.9º

Malus's law establishes a mathematical relationship for the light transmitted by a polarizer is:

          I = I₀ cos² θ

where I and I₀ are the transmitted and incident intensities, respectively, θ is the angle between the two polarizers.

They indicate that the incident light is polarized, so we do not need the first polarized to create the polarized light, ask what the polarized angle should be for the intensity to be reduced by a factor.

           [tex]\frac{I_o}{I } = 1.22 \\\frac{I}{Io} = 0.81967[/tex]

           

Let's use Malus's law

          i / Io = cos² θ

           

          cos θ = [tex]\sqrt{\frac{I}{I_o} }[/tex]  

          θ = cos⁻¹1 0.81967

          θ = 34.9º

In conclusion, using Malus's law we can find the angle of the polarized for a reduction of the intensity is:

          θ = 34.9º

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What factors affect how an object moves in an environment with air?

Answers

Answer:

The factors that affect how an object moves through the air are force, friction, interia, and momentum.

Explanation:

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