Answer:
organic chemistry is chemistry focused on structure and composition, extending to recations and properties of compounds.
often centered around compounds with carbon.
alcohols, amines, and aldehydes are some groups that are studied on organic chemistry
SHORT ANSWER:
a) chemistry focused on the structure qnd composition of compounds
b) alcohols, amines, aldehydes
Explanation:
Organic compounds, which are the compounds associated with life processes, are the subject matter of organic chemistry. Among the numerous types of organic compounds, four major categories are found in all living things: carbohydrates, lipids, proteins, and nucleic acids.
What is the empirical formula for a compound composed of 0.0683 mol of carbon ( C ), 0.0341 mol of hydrogen ( H ), and 0.1024 mol of nitrogen ( N )?
The empirical formula for a compound composed of 0.0683 mol of carbon ( C ), 0.0341 mol of hydrogen ( H ), and 0.1024 mol of nitrogen ( N ) is [tex]C_2HN_3[/tex].
What is the empirical formula?An empirical formula tells us the relative ratios of different atoms in a compound.
Given data:
Moles of carbon = 0.0683 mol
Moles of hydrogen = 0.0341 mol
Moles of nitrogen = 0.1024 mol
Dividing each mole using the smallest number that is divided by 0.0341 moles.
We get:
Carbon= 2
Hydrogen=1
Nitrogen=3
The empirical formula for a compound is[tex]C_2HN_3[/tex].
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a specialist that study substance obtained by attained mining is called a what
Answer:
Explanation:
Mining:
Mining is when certain substances are removed from the Earth, usually in large quantities. Mining can occur below the surface of the Earth via tunnels and caves. It can also occur at surface level through methods such as strip mining, which removes huge amounts of soil in the process
If aluminum has a density of 2.7 g/cm³, what is the volume of 2.7 grams of aluminum?
Answer:
Solution Density of aluminium = 2.7 g/Cm 3 In kg/ m 3 = 27 × 1000 10 =2700 kg/ m 3
Explanation:
Not much of one
Diffrentiate the reactivity of metals and Non-metals with air / oxygen.
Answer:
Both metals and non-metals when burnt in oxygen form their oxides. Oxides of metals are basic in nature and oxides of non-metals are acidic in nature.
Aqueous Copper (II) nitrate reacts with aqueous potassium iodide to form Copper (II) iodide solid and potassium nitrate
Answer:
Cu(NO₃)₂ (aq) + 2 KI (aq) ---> CuI₂ (s) + 2 KNO₃
Explanation:
When writing the reaction with the symbols, you need to take into account the charges of the ions. If he charges on the ions do not balance out in a molecule, they need to be made up for in the form of subscripts. For example, copper (+2) and iodine (-1) have charges which do not balance. Thus, to make the molecule neutral, you need to have two iodine atoms (CuI₂).
The unbalanced equation:
Cu(NO₃)₂ (aq) + KI (aq) ---> CuI₂ (s) + KNO₃
Reactants: 1 copper, 2 nitrate, 1 potassium, 1 iodine
Products: 1 copper, 1 nitrate, 1 potassium, 2 iodine
The balanced equation:
1 Cu(NO₃)₂ (aq) + 2 KI (aq) ---> 1 CuI₂ (s) + 2 KNO₃
Reactants: 1 copper, 2 nitrate, 2 potassium, 2 iodine
Products: 1 copper, 2 nitrate, 2 potassium, 2 iodine
The energy released per gram of material is __________.
A much larger in nuclear fusion reactions than in chemical reactions
B much smaller in nuclear fusion reactions than in chemical reactions
C the same amount in nuclear fusion reactions as it is in chemical reactions
D insignificantly larger in nuclear fusion reactions than in chemical reactions
Answer:
I'm pretty sure the answer is C.
Which of the following is a covalent compound?
NF3
KBr
CuO
FeCI3
Which of the following is an insoluble compound that is likely to be produced by the reaction below?
CaSO4 + PbI _______
The following is an insoluble compound that is likely to be produced by the reaction below CaSO4 + PbI- CaI + PbSO4. The PbSO4 will be insoluble as The sulfates are insoluble in water besides for the sulfates of calcium, barium, mercury, and lead.
Why lead sulfate is insoluble in water?Lead sulphate ($PbS$) is insoluble in water due to the fact water's dipole electricity is simply too vulnerable to shy away the ions (each anion and cations) from the sturdy crystals of lead sulphate.Lead sulfate seems as a white crystalline solid. Insoluble in water and sinks in water. Contact might also additionally aggravate skin, eyes, and mucous membrane.
Thus, PbSO4 is insoluble. In PbSO4 , the electricity of the dipole is vulnerable to interrupting the anionic and cationic bond. So, PbSO4 stays insoluble in solution.
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Is CaO a molecular compound?
Answer:
It's a Ionic compound
Explanation:
To tell if CaO (Calcium oxide) is ionic or covalent (also called molecular) we look at the Periodic Table that and see that Ca is a metal and O is a non-metal. When we have a metal and a non-metal the compound is usually considered ionic.
Because we have a metal and non-metal in CaO there will be a difference in electronegativity between the metal and non-metal. This difference results in an electron(s) being transferred from the metal (lower electronegativity) to the non-metal (higher electronegativity). The results in the metal becoming a postitive ion and the non-metal a negative ion. The two opposite charges are attracted and form the ionic bond between atoms in Calcium oxide.
Pb + 02 - Pb304 help
Answer:
6PbO +O2 --> 2Pb3O4
Explanation:
The question is incomplete I assume it is
PbO + 02 - Pb304
Engineers are starting on a new project to develop technology. Which of these
statements does not describe something they might do at the very beginning
of the process?
OA. Look at the problems society is facing.
OB. Make a decision about how to best apply the technology.
C. Look at the benefits and challenges of using specific materials.
OD. Decide whether they have designed the best possible product.
Answer: Decide whether they have designed the best possible product.
why is it important to record all accidents and breakages that occur in the laboratory
It is important to record all accidents and breakages that occur in the laboratory to prevent them from happening again.
What is laboratory accident?Laboratory accident is defined as the type of accident that occurs in the laboratory leading to harm.
Example of laboratory accidents include the following:
chemical burns, cuts from broken glass, inhalation of toxic fumes, absorption of chemicals through the skin, and ingestion of toxic chemicals.A record of these type of laboratory accidents would hel prevent it's reoccurrence.
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Determine the mass of SO₂ that contains 6.075 × 10^26 S atoms.
Answer:
= 64584.7176 g
or
= 64.5847 kg
Explanation:
From our question, we have been asked to find the mass of SO₂ containing 6.075 × 10^26 S atoms.
We know that from Avogadro's constant,
1 mole of a substance contains 6.02 x 10²³ ions/atoms/units
Thus,
1 mole => 6.02 x 10²³ atoms
x moles=> 6.075 × 10²⁶ atoms
We cross multiply;
x moles = (6.075 × 10²⁶ x 1)/(6.02 x 10²³)
= 1009.1362 moles
1 mole of SO2 = 64 g
1009.1362 moles = ?
=>
[tex] \frac{1009.1362 \times 64}{1} [/tex]
= 64584.7176 g
= 64.5847 kg
What hazard symbol does alcohol have? Why?
Answer:
Alcohol has considerable toxic effects on the digestive- and cardiovascular systems. Alcoholic beverages are classified as carcinogenic by the International Agency for Research on Cancer and increase the risk of several cancer types.
Explanation:
please mark me brainlist
Alcohol has a fire hazard symbol because it is extremely flammable and can create fires. Too be specific, ethanol alcohol is the flammable substance.
What mass in grams of iron metal can be formed by the reaction of 2.14 gAI metal with excess Fe₂O₃, according to the thermite reaction: 2Al(s) + Fe₂O₃ → 2Fe(s) + Al₂O₃(s)
Answer:
4.43 g Fe
Explanation:
To find the mass of iron, you need to (1) convert grams Al to moles Al (via molar mass), then (2) convert moles Al to moles Fe (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe to grams Fe (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs because the given value (2.14) has 3 sig figs.
Molar Mass (Al): 26.982 g/mol
2 Al(s) + Fe₂O₃ ---> 2 Fe(s) + Al₂O₃(s)
Molar Mass (Fe): 55.845 g/mol
2.14 g Al 1 mole 2 moles Fe 55.845 g
---------------- x ----------------- x -------------------- x ------------------ = 4.43 g Fe
26.982 g 2 moles Al 1 mole
Aluminum reacts with ferric oxide to produce iron by the thermite reaction. The mass of the iron metal that will be formed by the chemical reaction is 4.43 g Fe.
What is a limiting reagent?Limiting reagent has been described as reactions that are present in lesser amounts than the other reactant in the reaction that determines the amount of formation of the products and are never left in a reaction.
The balanced thermite reaction is given as:
2 Al(s) + Fe₂O₃ → 2 Fe(s) + Al₂O₃(s)
Molar mass of aluminium = 26.982 g/mol
Molar Mass of iron= 55.845 g/mol
Mass of aluminium (Al) = 2.14 grams
Here, according to the reaction 2 moles of Aluminum are needed to produce 2 moles of iron (Fe).
Moles of aluminum is calculated as:
Moles = mass ÷ molar mass
n = 2.14 ÷ 26.982
= 0.079 mol
As aluminum is the limiting reagent, it determines the formation of iron as:
2 mol Al = 2 mol Fe
0.079 mol Al = 0.079 mol Fe
Mass of iron is calculated as:
Mass = moles × molar mass
mass = 0.079 × 55.845 g/mol
= 4.411 grams
Therefore, 4.43 g Fe will be produced from 2.14 gm Al.
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How many grams of KCl 03 are needed to produce 6.75 Liters of O2 gas measured at 1.3 atm pressure and 298 K?
11.48-gram of [tex]KCl0_3[/tex] are needed to produce 6.75 Liters of [tex]O_2[/tex] gas measured at 1.3 atm pressure and 298 K
What is an ideal gas equation?The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
P= 1.3 atm
V= 6.75 Liters
n=?
R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]
T=298 K
Putting value in the given equation:
[tex]\frac{PV}{RT}=n[/tex]
[tex]n= \frac{1.3 \;atm\; X \;6.75 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]
Moles = 0.3588 moles
Now,
[tex]Moles = \frac{mass}{molar \;mass}[/tex]
[tex]0.3588 moles = \frac{mass}{32}[/tex]
Mass= 11.48 gram
Hence, 11.48-gram of [tex]KCl0_3[/tex] are needed to produce 6.75 Liters of [tex]O_2[/tex] gas measured at 1.3 atm pressure and 298 K
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Look at the question marks between zinc (Zn) and arsenic (As) . At the time no elements were known with atomic weights between 65.2 and 75
Mendeleev positioned elements in the periodic table in increasing order of their atomic numbers, such that elements having identical chemical properties and characteristics plunge into the same group.
What is Mendeleev's periodic table?Mendeleev's periodic table may be defined as a collection of elements in an increasing atomic mass hierarchy in a table arrangement, such that it reminisces resemblances and manias according to their chemical properties and characteristics.
Mendeleev found that two elements existed between atomic weights 65.2 and 75 because he comprehended especially pleasingly that the possessions of the elements were more comparable and closer to this degree.
He also anticipated having other elements that would have their possessions comparable to these other elements.
Therefore, he departed a void for these two elements in the periodic table until they were ultimately found in their real existence.
The complete question is as follows:
Look at the two question marks between zinc (Zn) and arsenic (As). At the time, no elements were known with atomic weights between 65.2 and 75. But Mendeleev predicted that two elements must exist with atomic weights in this range. What led Mendeleev to predict that two undiscovered elements existed in that range?
Therefore, it is well described above.
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How many mol of C7H16 would you have if you have 76.36 grams? Give your answer to 2 decimal spaces.
0.761 mol of [tex]C_7H_{16}[/tex] would you have if you have 76.36 grams.
What is a mole?A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Given data:
Mass=76.36 grams
[tex]Moles = \frac{mass}{molar \;mass}[/tex]
[tex]Moles = \frac{76.36 grams}{100.21 g/mol}[/tex]
Moles = 0.761
Hence, 0.761 mol of [tex]C_7H_{16}[/tex] would you have if you have 76.36 grams.
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Which of these is a reason an engineer may choose to use a prefabricated
building component?
A. She wants to make the building more original and unique.
B. She wants to use standard materials to minimize negative
environmental impacts.
C. She wants to make the building safer.
OD. She is not on a strict timeline.
Answer:
B.
Explanation:
customization requires more material, more machine time which can creates a greater impact on the environment in the sense of pollution (travel by the extra employees, creation of custom materials, increased machine running time). Good luck in your studies. Hope this answers your question in full.
Is any of the following an acid?
a. Ba(OH)2
b. H3PO4
c. FeCl3
d. NaC2H3O2
e. No acids are listed.
Answer:
b
Explanation:
calculate the molecular weight of carbon dioxide
Answer:
44.01 g/mol
Explanation:
Carbon dioxide is produced when carbon and oxygen are burned.
To totally burn carbon into carbon dioxide, or CO2, we require one mole of oxygen for every gram of carbon by weight.
or alternatively:
You produce 12+216=44 g of carbon dioxide for every 12 g of carbon.
The weight of CO2 in kg may be calculated if the amount of CO2 in litres is known by converting it to moles and multiplying it by 44.
What is the volume occupied by 14.3 g of argon gas at a pressure of 1.35 atm and a temperature of 436 K?
Answer:
9.487 L
Explanation:
argon mole wt = 39.948 gm/mole
14.3 gm / 39.948 gm/mole = .357965 moles of argon
Use Ideal Gas Law:
PV = n RT where R = .082057 L-atm / K-mol
V = .357965 * .082057 * 436 / 1.35 = 9.487 L
Please help me make analysis scheme flow chart for the detection of cation present in my unknown salt mixture of Ag+, Pb2+, or Ca2+ cations based on their solubility in the given reagents.
I can only use these reagents: Na2CO3, NaCl, & Na2SO4
The suspected cations in the unknown cation mixture are: Ag+, Pb2+, or Ca2+.
I used 0.5 M solution of all these reagents.
My test results are:
Na2CO3: 20 drops of sodium carbonate were used and silver blue precipitate was produced.
NaCl: 20 drops of sodium chloride were used and no precipitate was formed.
Na2SO4: 20 drops of sodium sulfate were used yellow precipitate was produced.
Please please help me make analysis flow chart based on this information and also tell me in what sequence these reagents will be added to unknown salt mixture.
I suspect that the cation may be Ca2+ based on solubility rules. But I'm not sure.
The possible action your solution might contain is amongst [tex]Ag^+[/tex], [tex]Pb^{2+}[/tex], or [tex]Ca^{2+}[/tex].
What are the solutions?A solution is a homogeneous mixture of one or more solutes dissolved in a solvent.
NaCl: 20 drops of NaCl were used and no precipitate was formed.
No precipitation formed means the [tex]Cl^-[/tex] cation is soluble in water. From your chart, you might see the halide of [tex]Ag^+[/tex] and [tex]Pb^{2+}[/tex] is insoluble in water, which means they should have formed precipitation but you didn't. This means there's less possibility it contains [tex]Ag^+[/tex] or [tex]Pb^{2+}[/tex], so we are left with only [tex]Ca^{2+}[/tex]. Let's confirm it with the rest.
[tex]Na_2SO_4[/tex] : 20 drops of [tex]Na_2SO_4[/tex] were used yellow precipitate was produced.
Even though all other sulfates form precipitation ( Insoluble in water)
[tex]Na_2CO_3[/tex] : 20 drops of sodium carbonate were used and the silver-blue precipitate was produced.
It seems all of their Carbonate is insoluble in nature. ( which is our case too ).
From the above result, only the reaction with NaCl was deemed to be decisive and it indeed contains [tex]Ca^{2+}[/tex] ions. Means you are correct.
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A sample of zinc is heated to a temperature of 77.4ºC, then placed in a calorimeter containing 65.0 g of water. Temperature of water increases from 20.00ºC. The specific heat of zinc is 0.390 j/g°C. What was the mass of the zinc sample?
180.189 g was the mass of the zinc sample with a specific heat of zinc is 0.390 j/g°C.
What is specific heat capacity?The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).
Using specific heat capacity formula here:
[tex]C_{Zn}[/tex] × [tex]m_{Zn}[/tex]× Δ[tex]T_{Zn}[/tex] = [tex]C_{H_2O}[/tex]× [tex]m_{H_2O}[/tex] × Δ[tex]T_{H_2O}[/tex]
0.390J/g°C × [tex]m_{Zn}[/tex] ×77.4ºC = 4.184J/g°C× 65.0g × 20.00ºC.
[tex]m_{Zn}[/tex] = 180.189 g
Hence, 180.189 g was the mass of the zinc sample.
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A laser emits light at a wavelength of 678 nm. How many photons are required to emit 1 joule of energy?
0.342 x [tex]10^(^1^6^)[/tex]) photons are required to emit 1 joule of energy.
What is a photon?A photon is a particle of light defined as a discrete bundle (or quantum) of electromagnetic (or light) energy.
We need to find the number of photons emitted per second.
So we have E = hc ÷ λ
= (6.6 x [tex]10^-(^3^4^)[/tex]x 3 x [tex]10^8[/tex] m/s) ÷ 6.78 x [tex]10^(^-^7^)[/tex]nm
= 2.92 x [tex]10^(^-^1^9^)[/tex]Joules
Now number of photons per second = I / E (I = intensity)
= 1 x [tex]10^(^-^3^)[/tex] joule / sec ÷ 2.92 x [tex]10^(^-^1^9^)[/tex]joule
= 0.342 x[tex]10^(^1^6^)[/tex]
Hence, 0.342 x [tex]10^(^1^6^)[/tex]) photons are required to emit 1 joule of energy.
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2. A solution is made by dissolving 3.88 g of NaCl in enough water to make 67.8 mL of solution. What is the concentration of sodium chloride in units of weight/volume percent?
The concentration of sodium chloride in the solution is 5.72% (weight/volume percent).
How to calculate the weight/volume percent concentration?Weight/volume percent concentration (w/v) expresses the amount of solute (in grams) dissolved in a given volume of solution (in milliliters). Specifically, it is defined as the weight of the solute divided by the volume of the solution, multiplied by 100.
To calculate the weight/volume percent concentration, we need to determine the mass of NaCl per volume of the solution.
First, we need to convert the volume of the solution from milliliters (mL) to liters (L):
67.8 mL = 0.0678 L
Next, we calculate the concentration of NaCl in grams per liter (g/L):
Concentration = Mass of solute ÷ Volume of solution
Concentration = 3.88 g ÷ 0.0678 L
Concentration = 57.2 g/L
Finally, we convert the concentration to weight/volume percent by multiplying by 100:
Weight/volume percent = Concentration x 100
Weight/volume percent = 57.2 g/L x 100
Weight/volume percent = 5.72%
Therefore, the concentration of NaCl in the solution is 5.72% (weight/volume percent).
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5. A group decided to use 250.0 mL of vinegar and 24.0 grams of baking soda. What is the limiting
reactant?
Hence, If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.
What is a limiting reactant?The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.
To solve this problem, it is necessary to know the exact concentration of acetic acid in vinegar, because manufacturers produce many types of vinegar the with different concentrations. Most often, concentration of acetic acid in vinegar ranges from 4% to 8%. In this case, it is possible
to calculate the concentration of vinegar making the assumption that 250 ml of vinegar reacts completely with 24 grams of baking soda.
Acetic acid [tex]CH_3CO_2H[/tex] reacts with baking soda [tex]NaHCO_3[/tex] according to the equation:
[tex]CH_3CO_2H + NaHCO_3[/tex] → [tex]CH_3CO_2Na + CO_2 + H_2O[/tex]
1. Molar mass of [tex]NaHCO_3[/tex] is 23+1+12+16×3 = 84 g/mol
= [tex]\frac{1 mol \;NaHCO_3}{84 g \;NaHCO_3}[/tex]
= [tex]\frac{24 g \;NaHCO_3 X 1 mol \;NaHCO_3}{84 g \;NaHCO_3}[/tex]
=0.29 mol [tex]NaHCO_3[/tex]
2. From the balanced equation we see that 1 mole of [tex]NaHCO_3[/tex] reacts with 1 mole of [tex]CH_3CO_2H[/tex] , then 0.29 moles of [tex]NaHCO_3[/tex] react with 0.29 moles of [tex]CH_3CO_2H[/tex].
3. Mass of 1 mole of [tex]CH_3CO_2H[/tex] is 12+ 1×3+12+16×2=60 g/mol
= [tex]\frac{0.29 mol \;CH_3CO_2H X \;60 g \;CH_3CO_2H }{1 mol \;CH_3CO_2H}[/tex]
[tex]=17.4 g CH_3CO_2H[/tex]
4. In this step density of vinegar is needed.
Making the assumption that concentration of acetic acid is 7%, we can calculate the mass of acetic acid in 250 ml of vinegar:
Mass of vinegar=Volume × density
= 250 ml ×1.0084 g/ml
=252 g
Mass of acetic acid = mass of vinegar × concentration ÷ 100%
= 252 g × 7% ÷ 100%
= 17.6 g.
17.6 g [tex]CH_3CO_2H[/tex] is very close to 17.4 g [tex]CH_3CO_2H[/tex]. It means, that 250 ml of vinegar with a concentration of acetic acid equal to 7% reacts completely with 24 g of baking soda.
Hence, If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.
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Which of the following is the best definition of a physical change?
A. A change in a substance where a new substance is formed
B. A change in a substance in which mass is conserved
C. A change in a substance inwhich bonds are broken
D. A change in a substance with no new substances being formed
D. A change in a substance with no new substances being formed
Explanation:There are 2 ways a substance can change, physical changes and chemical changes. In all changes, physical or chemical, mass is always conserved.
Physical vs. Chemical
The main difference between a physical and chemical change is the substance at the end.
Physical changes do not form new substancesChemical changes do form new substancesNew substances are only created by chemical changes. Additionally, only chemical changes break apart bonds. Physical changes maintain the same compounds and elements, so bonds are not broken.
Examples of Physical Changes
Physical changes do not change the actual substance, but they can change the form of the substance.
MeltingBoilingFreezingCrumblingCuttingBreakingAll of these change the state of matter or shape of the substance, but not the chemical makeup.
Convert the scientific notation to a decimal number.
To convert Scientific Notation to a decimal number, Prescribed steps are to be taken given below.
What is Scientific Notation ?Scientific notation is a way of writing very large or very small numbers.
A number is written in scientific notation when a number between 1 and 10 is multiplied by a power of 10.
Steps to Calculate Scientific Notation ;Determine the exponent, n , on the factor 10 .Move the decimal n places, adding zeros if needed. If the exponent is positive, move the decimal point n places to the right. If the exponent is negative, move the decimal point |n places to the left.Check.Learn more about Scientific Notation here ;
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what is the new concentration of A if 7.7 ml of a .10 M solution of A is mixed with 18.3 mL of .20 M solution B and an additional 11.7 ml water?
Answer:
0.12 M
Explanation:
To find the new concentration, you need to (1) find the moles of Solution A (via the molarity equation), then (2) find the moles of Solution B, then (3) combine all of the moles and volumes, and then (4) calculate the new molarity. The final answer should have 2 sig figs to reflect the lowest amount of sig figs in the given values.
Solution A:
7.7 mL / 1,000 = 0.0077 L
Molarity = moles / volume
0.10 M = moles / 0.0077 L
0.00077 = moles
Solution B:
18.3 mL / 1,000 = 0.0183 L
Molarity = moles / volume
0.20 M = moles / 0.0183 L
0.00366 = moles
New Solution:
11.7 mL / 1,000 = 0.0117 L
New Volume = 0.0077 L + 0.0183 L + 0.0117 L
New Volume = 0.0377 L
New Moles = 0.00077 moles + 0.00366 moles
New Moles = 0.00443 moles
Molarity = moles / volume
Molarity = 0.0043 moles / 0.0377 L
Molarity = 0.1175 M = 0.12 M
