34. Which information MUST a HACCP plan for sous vide soup contain?
O Approval records for all suppliers
O Nutritional value for all ingredients
The names of the cooks and the manager
The materials, ingredients, and equipment used
The materials, ingredients, and equipment used must be included in a
HACCP plan.
Hazard analysis and critical control points(HACCP) is a safety plan used in
preparing food in order to ensure risks such as biological and chemical are
reduced to the barest minimum.
This plan contains the materials, ingredients and equipment which are the
vital components used in preparing food(sous vide soup). The components
are analyzed to identify and control the ones which may cause any form of
hazard.
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An incompressible fluid is flowing through a horizontal pipe with a constriction. The velocity of the fluid in the wide section of the pipe is 5.00 m/s and the velocity of the fluid in the narrow section of pipe is 8.00 m/s. The pressure of the fluid in the wide section is 200 kPa. What is the pressure in the narrow section of the pipe
The Bermoulli's equation allows us to find the pressure in the narrow part of the pipe through which water circulates is:
P = 500 Pa
Bernoulli's equation is the work-energy relationship for fluids that are liquids and gases.
[tex]P_1 + \frac{1}{2} \rho v_1^2 + \rho g y_1 = P2 + \frac{1}{2} \rho v_2^2 + \rho g y_2[/tex]
Where the subscripts 1 and 2 represent points of interest, P is the pressure, ρ the density of the fluid, v the velocity and y the height.
They indicate that the pipe is horizontal, that the pressure in the wide part P₁ = 200 kPa and the velocity is v₁ = 5 m / s and in the narrow part v₂=8.00 m/s, see attached.
Since the pipe is horizontal y₁ = y₂
P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²
P₂ = P₁ + ½ ρ (v₁² - v₂²)
Let's calculate
P₂ = 200 10² + ½ ρ (5² - 8²)
P₂ = 2 10⁴ - 19.5 ρ
For a specific calculation the value of the density of the fluid is needed, suppose that the fluid is water ρ = 1000 kg / m³
P₂ = 2 10² - 19.5 1000
P₂ = 500 Pa
In conclusion using the Bermoulli equation we can find the pressure in the narrow part of the pipe through which water circulates is:
P = 500 Pa
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VELOCITY, SPEED, DISTANCE ETC..
A car follows a curved highway from point A to point B, covering a distance of 50 kilometers and displacement to the east of the 40 kilometers in 0.5 hours. What s speed and velocity of the car in kilometers per hour?
Answer:
Explanation:
Speed = distance / time
Velocity = displacement / time
So ,
Speed = 50 km / 0.5 hr = 100 km/h
Velocity = 40 km / 0.5hr = 80 km/h
NO LINKS Select the choice that shows the helping verb followed by the main verb. I am writing this sentence. I am writing this sentence. I am writing this sentence. I am writing this sentence
The helping verb in the sentence; "I am writing this sentence" is the verb "am".
Helping verbs are verbs that occur in sentences or clauses whose function is to express tense, form negations or form a question. Examples of helping verbs include; Am, is, are, was and were, being, been, and be, Have, has, had, do, does, did, will, would, shall and should, may, might, must, can, could.
In this sentence; "I am writing this sentence", the helping verb is "am". It helps to express the tense of the action that is being carried out.
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PLEASE HELPPPPPPPPPP
Answer:
sorry me computer is blocking the picture but i will try to unblock so i can answer
Explanation:
A 20 kg block (4) rests on a frictionless table;
a cord attached to the block extends
horizontally to a pulley at the edge of the
table. A 10 kg mass (B) hangs
Answer:
Explanation:
F = ma
a = F/m
a = 10(9.8) / (10 + 20)
a = 3.3 m/s²
(T)ension in the cord
20(3.3) = 65 N
LEVEL 3
Write the correct order
of letters to the finish line.
A
B
с
Example:
ABCGH
G
H
IZAI
00
Answer:
We dont know all the info you need to take a sreenshot or piture of what your trying to show us.
Explanation:
Two projectiles are thrown with the same initial velocity, one at an angle and the other at an angle of . (a) Can both projectiles strike the ground at the same distance from the projection point? (b) Can both projectiles be in air for the same time interval?
Answer:
si quiero ser tu novia❤❤
A bullet (m=20g) shot with a speed of 800 m/s hits an oak tree and sticks 4cm inside it.
What is the average force acting on the bullet from the tree?
Hi there!
We can begin by converting cm to m:
4cm = 0.04 m
Use the following equation:
vf² = vi² + 2ad
The final velocity is 0 m/s, so:
0 = vi² + 2ad
vi² = -2(a)d
Plug in given values to solve for the acceleration:
800²/2(0.04) = -a
a = -8,000,000 m/s²
Find the force using the equation:
F = ma
F = (0.02)(-8,000,000) = -160,000 N
I HAVE NOOOO IDEA!!!!!!!!!! HELP!!!!!!!!!!
Use the equation for motion to answer the question.
x=x₀+ v₀t + 1/2at²
An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?
A. 30 m
B. 60 m
C. 32 m
D. 17 m
Answer:
17
Explanation:
A monatomic ideal gas is compressed at a constant pressure of 0.293 atm from a volume of 8.26 L to 3.32 L. In the process, heat energy flows out of the gas. What is the work done on the gas?
The work done on the gas as it is compressed from volume 1 to volume 2 is 146.7 J.
Given the data in the question;
Pressure; [tex]P = 0.293 atm = 29688.225pa[/tex]Initial volume; [tex]v_1 = 8.26L = 0.00826m^3[/tex]Final volume; [tex]v_2 = 3.32L = 0.00332m^3[/tex]Work done on the gas; [tex]W = \ ?[/tex]
From the first law of thermodynamic:
[tex]W = -P\delta v[/tex]
Where W is work done, P is pressure and [tex]\delta v[/tex] is change in volume.
We substitute our values into the equation
[tex]W = -29688Pa * ( 0.00332m^3- 0.00826m^3)\\\\W = -29688Pa * -0.00494m^3\\\\W= 146.7 J[/tex]
Therefore, the work done on the gas as it is compressed from volume 1 to volume 2 is 146.7 J.
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can anyone heelp me plzz
Answer:
the ans is D... good luck
How does the drop height (gravitational potential energy) of a
ball affect the bounce height (kinetic energy) of the ball?
The
A 3.6-kg goose floats on a lake with 46 % of its body below the 1000-kg/m3 water level. Determine the average density of the goose.
The average density of the goose on the given lake is 460 kg/m³.
The given parameters;
mass of the goose, m = 3.6 kgfraction of the goose below the lake, = 46%density of the water, ρ = 1000 kg/m³The specific gravity of the goose is calculated as follows;
[tex]S.G = \frac{46}{100} = 0.46[/tex]
The density of the goose is calculated as follows;
[tex]S.G = \frac{\rho _{g}}{\rho_{w}} \\\\\rho_{g} = S.G \times \rho_{w}[/tex]
where;
[tex]\rho _{w}[/tex] is the density of water[tex]\rho _{g}[/tex] is the density of the gooseThe density of the goose is calculated as;
[tex]\rho _{g}= 0.46 \times 1000 \ kg/m^3\\\\\rho _{g}= 460 \ kg/m^3[/tex]
Thus, the average density of the goose on the given lake is 460 kg/m³.
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Accelerating car is a _______
•Law of inertia
•Law of universal gravitation
•Law of acceleration
•Law of conversation of energy
Acceleration is the rate of change of velocity as a function of time. For example a car traveling at 50 km/hr starts to accelerate, 10 seconds after, its speed changes to 100 km/hr then the acceleration of the car during the time can be calculated as below: initial speed = 50 km/hr.
In a chemical reaction, two molecules with a total mass of 76 amu react to form a single molecule. What is the mass of the molecule that is formed?
FIRST ANSWER GET EVERYTHING IN THE JOVID SUPPORT PACKAGE! :)
Answer:
The total number of atoms does not change, so mass is conserved in the reaction
So answer is 76
Explanation:
If you like my answer than please mark me brainliest thanks
In a chemical reaction, two molecules with a total mass of 76 amu react to form a single molecule. The mass of the molecule that is formed is equal to that of the total mass of two molecules which is 76 amu.
What is a Chemical reaction?A chemical reaction may be defined as a type of reaction in which two or more molecules are combined as reactants in order to form a new compound which is known as a product.
In this question, according to the law of conservation of mass, mass can neither be created nor be destroyed in a given chemical reaction. So, if the total mass of two reactant molecules is 76 amu, then the resultant product also bears the same mass.
Therefore, the mass of the molecule that is formed is equal to that of the total mass of two molecules which is 76 amu.
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#SPJ5
How is an interference pattern formed by a diffraction grating different from the pattern formed by a double slit
Answer:
Evaluate the following numerical expressions.
6 + 3 • 4 =
18
(6 + 3) ÷ (4 – 5) =
Explanation:
Evaluate the following numerical expressions.
6 + 3 • 4 =
18
(6 + 3) ÷ (4 – 5) =
Can a human survive mercury or burn to ashes
just a question trying to find out
No
Explanation:
Nobody body can survive in mercury whithout
spacesuit.The main reasons are given below:-
1)lack of oxygen
2)lack of water
3)very low temp. at night and very high temp. at day
A hooligan throws a stone vertically down with an initial speed of 17 m/s from the roof of a building 51 metres above the
ground. How long in seconds does it take the stone to reach the ground?
Answer:
Explanation:
impact velocity is
√(18² + 2(-9.8)-51) = 36 m/s
average velocity is (17 + 36)/2 = 26.5 m/s
t = d/v = 51 / 26.5 = 1.9 s
or
if ground is origin and UP positive
0 = 51 - 17t - ½(9.8)t²
quadratic formula
t = (17 ±√(17² - 4(-4.9)(51))) / (2(-4.9))
t = (17 ± 36) / -9.8
t = - 5.4 s which we ignore as the stone is not thrown yet
or
t = 19 s
HELP
If a car is traveling at constant speed of 70 kilometers per hour, how many hours will it take for the car to travel a distance of 28 kilometers
If a car is traveling at constant speed of 100 kilometers per hour, how many hours will it take for the car to travel a distance of 280 kilometers ?
If the velocity of a caer changes from 0 meters per second to 100 meters per second in 10 seconds, what is the acceleration over that 10 second period?
If the velocity of a caer changes from 20 meters per second to 60 meters per second in 4 seconds, what is the acceleration over that 4 second period ?
Answer:
Explanation:
28 / 70 = 0.3857142... = 0.39 hr
280 / 100 = 2.8 hrs.
(100 - 0) / 10 = 10 m/s²
(60 - 20) / 4 = 10 m/s²
how do organisms interact with the living and the non-living environment to obtain matter and energy?
Answer:
Seeking matter and energy resources to sustain life, organisms in an ecosystem interact with one another in complex feeding hierarchies of producers, consumers, and decomposers, which together represent a food web.
i have to match the words to its definition i have 15 minutes plz
en que consiste el atletismo de pista y campo?
Answer:
El atletismo es un deporte que incluye competencias atléticas basadas en las habilidades para correr, saltar y lanzar. El nombre se deriva del lugar donde se lleva a cabo el deporte, una pista de atletismo y un campo de hierba para los lanzamientos y algunos de los eventos de salto.
Explanation:
Yo se esto
A photograph of you and your friends at your 8th birthday party.is it secondary or primary source and why?
Answer:
primary source
Explanation:
the explanation is in the image above
brainliest please
3. The displacement of a particle is represented by s = at? + bts where t is time. Deduce the values of the constants a, and b. Solution Hint: The summed quantities must all have the same dimension as s. Dimension of displacement s =. L ..., and t = ...I.......... .... ... = Equate dimension of s and at2 ; dim a= . ; dim b = ..... > Equate dimension of s and bt³
Explanation:
Correct option is
A
As LHS=RHS, formula is dimensionally correct.
Writing the dimensions of either side of the given equation.
LHS=8=displacement=[M
0
LT
0
]
RHS=ut=velocity×time=[M
0
LT
−1
][T]=[M
0
LT
0
]
and
2
1
at
2
=(acceleration)×(time)
2
=[M
0
LT
−2
][T]
2
=[M
0
LT
0
]
As LHS=RHS, formula is dimensionally correct.
can anyone heelp me plz plz
Answer:
the ans is D.... good luck
A 60-kg patient about to have a brain scan is injected with 0.02 Ci of the radionuclide Technetium-99. Technetium-99 decays to the ground state with a half-life of 6.0 hours. The Technetium-99 nucleus decays by emitting a 143-keV photon. Assume that half of these photons escape the body without interacting. What biological equivalent dose does the patient receive? The relative biological effectiveness (RBE) for these photons is 0.97 Assume that all of the Technetium-99 decays while in the body. [10 marks)
u my CCTV camera for video
Explanation:
because I have a big deal for me
A man moves a box horizontally by exerting on it a force of 90 N directed at 60 above the horizontal. If the work done on the box is 450 J, the displacement of the box is
Hi there!
We know that:
W = F · dcosФ
The cosine indicates that work only takes into account the component of the force that is parallel to the displacement.
Thus, we must find the horizontal component of the force:
FcosФ = horizontal component
90cos(60) = 45 N
Now, we can solve for displacement:
W = Fd
W/F = d
450/45 = d = 10 m
An arrow is shot straight up in the air with an initial speed of 54.0 m/s. On striking the ground it embeds itself 15.0 cm into
the ground
What is the time (in units of millseconds and to 1 decimal place) required for it to come to rest once it hits the ground?
Answer:
eueywjfjrh EF dydehfjewue di ko sira ata maka move on di ko babayaran hi hi JH
Q1: Calculate the diameter of a copper conductor 300 m long such that it may carry 500 A with a voltage drop of 8 V. The resistivity of the copper may be taken as 0.019 m.
The diameter of a copper conductor is equal to 21.30 meters.
Given the following data:
Length = 300 mCurrent = 500 A Voltage = 8 VResistivity = 0.019To calculate the diameter of a copper conductor:
First of all, we would determine the resistance of the copper conductor by using the formula:
[tex]Resistance = \frac{Voltage }{Current} \\\\Resistance =\frac{8}{500}[/tex]
Resistance = 0.016 Ohms
Next, we would determine the area of the copper conductor:
[tex]Resistance = \frac{\rho l}{Area} \\\\Area = \frac{\rho l}{Resistance}\\\\Area = \frac{0.019 \times 300}{0.016}[/tex]
Area = 356.25 [tex]m^2[/tex]
For the diameter:
From the area of a circle, diameter is given by the formula:
[tex]Area = \frac{\pi d^2}{4} \\\\d=\sqrt{\frac{4A}{\pi} } \\\\d=\sqrt{\frac{4 \times 356.25}{3.142} }\\\\d=\sqrt{453.53}[/tex]
Diameter, d = 21.30 meters
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