What is it called when a Rock forms due to heat and pressure in the earth?

Using waves of frequency and pich

Explanation:

There's always been water around us

Answer:

dfdfsdf s

Explanation:

fsdfsd fsd fds f vsdvads

Answer:

it will most likely be the free energy

Answer:

iam not sure but I think its NaNO3

Answer:

226.8 kN/m

Explanation:

The work done by the spring, W equals the kinetic energy of the satellite, K

W = K

work done by the spring, W = 1/2kx² where k = force constant and x = extension of spring

kinetic energy of the satellite, K = 1/2mv² where m = mass of satellite = 1060 kg and v = speed of satellite = 3.35 m/s

1/2kx² = 1/2mv²

k = mv²/x²

Also, the spring force F = kx where k = force constant and x = extension of spring.

k = F/x

equation both expressions for k, we have

mv²/x² = F/x

x = mv²/F since F = ma where m = mass of satellite and a = maximum acceleration of satellite = 5.00g and g = 9.8 m/s²

x = mv²/ma = mv²/5.00mg = v²/5.00g

Substituting the values of the variables into the equation, we have

x = v²/5.00g

= (3.35 m/s)²/(5.00 × 9.8 m/s²)

= 11.2225 m²/s²/49 m/s²

=0.229 m

Now k = F/x = 5.00mg/x

Substituting the values of the variables into the equation, we have

k = 5.00mg/x

k = 5.00 × 1060 kg × 9.8 m/s²/0.229 m

k = 51940 kgm/s²/0.229 m

k = 51940 N/0.229 m

k = 226812.23 N/m

k = 226.81223 kN/m

k ≅ 226.8 kN/m

Answer:

A black hole is a region of spacetime where gravity is so strong that nothing—no particles or even electromagnetic radiation such as light—can escape from it. The theory of general relativity predicts that a sufficiently compact mass can deform spacetime to form a black hole.

Answer:

We can write   S = v * t    where S is the distance traveled in time t

S = .12 rad/sec * 30 sec = 3.6 rad     distance traveled

Also 2 * pi * N = S   since there are 2 * pi rad / revolution

So 2 * pi * N = 3.6

N = 3.6 / (2 * pi) = .573 revolutions

Answer:

r = 0.0173 m = 1.73 cm

Explanation:

Here, the centripetal force of the block will be providing the required breaking tension in the string:

[tex]Tension = Centripetal Force\\T = F_c\\\\T = \frac{mv^2}{r} \\\\r = \frac{mv^2}{T}\\[/tex]

where,

r = radius = ?

m = mass of block = 0.13 kg

v = tangential spee of block = 4 m/s

T = Breaking Strength = 30 N

Therefore,

[tex]r = \frac{(0.13\ kg)(4\ m/s)^2}{30\ N}[/tex]

r = 0.0173 m = 1.73 cm

When finding the radius of the string at the point it breaks, the tangential

velocity is assumed to be constant.

Reasons:

The mass of the small block, m = 0.130 kg

Initial radius of the circle of rotation = 0.800 m

Tangential velocity, v = 4.00 m/s

The radius of the path of rotation is reduced as the string is pulled

Breaking strength of the string = 30.0 N

Required:

The radius of the circle when the string brakes

Solution:

[tex]Centripetal \ force = \dfrac{m \cdot v^2}{r}[/tex]

Where;

r = The radius of the circle of rotation

When the string brakes, w have;

Centripetal force = Breaking strength of the string = 30.0 N

Which gives;

[tex]\displaystyle r = \mathbf{\dfrac{m \cdot v^2}{Centrifugal \ force}} = \frac{0.130 \times 4^2}{30} =6.9\overline 3 \times 10^{-2}[/tex]

The radius of the circle when, the string breaks r = [tex]\underline{6.9\overline 3 \times 10^{-2}} \ m[/tex]

Learn more here:

https://brainly.com/question/20905151

Answer:

the angle the ladder makes with the floor as seen by an observer on Earth is 71.9°

Explanation:

Given the data in the question and as illustrated in the diagram below.

speed of the ship v = 0.90c

base of the ladder from the wall x₀ = 3.0 m

top of the later above the floor y = 4.0 m

we determine angle θ.

from the diagram,

tanθ = y/x₀

tanθ = y / x₀√( 1 - v²/c² )

we substitute

tanθ = 4.0 / 3.0√( 1 - ((0.9c)²/c²) )

tanθ = 4.0 / 3.0√( 1 - ((0.9²)c²/c²) )

tanθ = 4.0 / 3.0√( 1 - (0.9²) )

tanθ = 4.0 / 3.0√( 1 - 0.81 )

tanθ = 4.0 / 3.0√0.19

tanθ = 4.0 / 1.30766968

tanθ = 3.058876

θ = tan⁻¹( 3.058876 )

θ = 71.8965 ≈ 71.9°

Therefore, the angle the ladder makes with the floor as seen by an observer on Earth is 71.9°

Answer:

0.5

Explanation:

In this picture,

Answer:

He had a cogenital condition

Explanation:

cogenital conditions are present before or at the time of birth and are considered birth defects

Answer:

The answer is C- He had a congential condition.

Explanation:

Edge

Answer:

a.5.85 s b i. 15.7 m/s ii. 21.1m/s c. 61.62 m

Explanation:

(a) when b will overtake a,

Using s = ut + 1/2at² we express the distance moved by each automobile.

Since both automobiles start at rest, their initial speed, u = 0 m/s, a = acceleration of automobile and t = time of travel or overtaking

So s = 0 × t + 1/2at²

s = 0 + 1/2at²

s = 1/2at²

Let time, t be the time the automobile b start, and its acceleration a = 3.6 m/s²

So, s = 1/2 × 3.6 m/s² × t² = 1.8t²

Since automobile a starts 2 seconds earlier, its time of travel is (t + 2) s. Since its acceleration, a = 2 m/s²,

s = 1/2 × 2 m/s² × (t + 2)²

s = (t + 2)²

Since both distances are equal at overtaking

(t + 2)² = 1.8t²

t² + 4t + 4 = 1.8t²

1.8t²- t² - 4t - 4 = 0

0.8t² - 4t - 4 = 0

dividing through by 0.8, we have

0.8t²/0.8 - 4t/0.8 - 4/0.8 = 0

t² - 5t - 5 = 0

Using the quadratic formula to find t,

[tex]t = \frac{-(-5) +/-\sqrt{(-5)^{2} - 4 X 1 X (-5)} )}{2 X 1} \\t = \frac{5 +/-\sqrt{25 + 20} )}{2} \\t = \frac{5 +/-\sqrt{45} )}{2} \\t = \frac{5 +\sqrt{45} )}{2} or \frac{5 -\sqrt{45} )}{2}\\t = \frac{5 + 6.708 )}{2} or \frac{5 - 6.708)}{2}\\t = \frac{11.708 )}{2} or \frac{-1.708}{2}\\t = 5.854 sor -0.854 s[/tex]

t ≅ 5.85 or -0.85

We take the positive answer since t cannot be negative.

So, t = 5.85 s

So, b will overtake a 5.85 s later.

(b) the speed of each automobile at that time,

Using v = u + at for each automobile, where u =initial speed of automobile = 0 m/s (since they both start from rest), a = acceleration of automobile and t = time of travel of automobile

i. Speed of automobile a

For automobile a, its time of travel is (t + 2) s = 5.85 s + 2 s = 7.85 s and its acceleration is 2 m/s²

So, v = u + at

= 0 m/s + 2 m/s² × 7.85 s

= 0 m/s + 15.7 m/s

= 15.7 m/s

ii. Speed of automobile b

For automobile a, its time of travel is t  s = 5.85 s and its acceleration is 3.6 m/s²

So, v = u + at

= 0 m/s + 3.6 m/s² × 5.85 s

= 0 m/s + 15.7 m/s

= 21.06 m/s

≅ 21.1 m/s

c) the location where b overtakes a relative to the traffic signal. -truck

The location where b overtakes a relative to the traffic signal is the distance each automobile moves before overtaking. In section (a), we foundthat distance s = 1/2at² = (t + 2)² = 1.8t²

Using s = (t + 2)²

= (5.85 + 2)²

= 7.85²

= 61.6225 m

≅ 61.62 m

Answer:

the deeper into the ocean you go, the more pressure is exerted on you

Explanation:

Answer:

Increase

As the mass of either object increases, the force of gravitational attraction between them also increases.

Explanation:

The gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force.

As the mass of either object increases, the force of gravitational attraction between them also increases.

Answered by none other than the ONE & ONLY #QUEEN herself aka #DRIPPQUEENMO

HOPE THIS HELPED!!!

Answer:

Hello your question lacks some information and that is the distance

At r = 0.150 m (outside the cable)  note :  (μ 0 = 4π × 10-7 T · m/A)

answer: 4.7 * 10^-6 T

Explanation:

R1 = 0.03 m

R2 = 0.07 m

R3 = 0.1 m

Inner conductor carries current = 4.5A in one direction

outer conductor carries current = 8A in opposite direction

Determine the value of magnetic field at r = 0.150 m

net current = 8 - 4.5 = 3.5 A

∴ β ( value of  magnetic field )

= ( 4π * 10^-7 * 3.5 ) / ( 2π * 0.150 )

= 4.4*10^-6 / 0.94

= 4.7 * 10^-6 T

Answer:

a)   F = 3.3 10⁴ N,  b)  F = 2.2 10³ N,  c) force when rigid is 15 times greater than when bending the knees

Explanation:

For this exercise we can use the relationship between work and the variation of kinetic energy

          K₀ = ½ m v²

the final kinetic energy is zero because the person is stationary

          W = (∑ F) x

          W = W x - F w

the weight is in the same direction of the displacement therefore the work is positive and the force applied, by the floor, is in the opposite direction to the displacement, consequently the work is negative

we substitute

          ( W-  F ) x = 0-K₀

           F = W + K₀ /x  

          F = mg + [tex]\frac{1}{2} \frac{mv^2 }{2x}[/tex]  

          F = m ( g+  [tex]\frac{v^2 }{2x }[/tex]  )

Let's use kinematics to find the velocity of the person when reaching the floor

           v² = v₀² - 2g (y + y₀)

the initial velocity is true and when reaching the ground y = 0

          v² = -2 g (0-yo)

we calculate

          v = [tex]\sqrt{2 ] 9.8 \ 0.800}[/tex]

          v = - 3.96  m/s

the direction of this velocity is vertical down

let's calculate

a) x = 1.50 cm = 0.0150 m

           F = 62.0 (3.96² / 2 0.0150 + 9.8)

           F = 3.3 10⁴ N

b) x = 30 cm = 0.30 m

           F = 62.0 (3.96² / 2 0.30 + 9.8)

           F = 2.2 10³ N

c) to compare the force let's look for the relationship between the two

           [tex]\frac{F_{rigid} }{ F_{flexible} }[/tex] = 3.3 10⁴ / 2.2 10³

           \frac{F_{rigid}  }{ F_{flexible} } = 15

therefore see that the force when rigid is 15 times greater than when bending the knees

Answer:

B

Explanation:

Answer:

Explanation:

a)

To pass the Coulomb barriers and undergo nuclear fusion, alpha particles must be burned at high temperatures. As a result, the ignition temperature needed for this reaction is 5.4168 × 10¹⁰ K. Helium must be burned at a high temperature and density. As a result, this must occur for hot stars with high densities.

b)

The amount of energy given up can be calculated as follows:

[tex]_2He^4 + _2He^4 \to _4Be^8 ---- (1) \\ \\ _4Be^8 + 2_He^4 \to _6C^{12} ---(2)[/tex]

where;

[tex]M(_2He^4) = 4.002603 \ u \\ \\ M(_4Be^8) = 8.005305 10 \ u[/tex]

Therefore, from the reaction (1);

[tex]Q = \Big ( M(_2He^4) + M(_2He^4) - M(_4Be^8) \Big ) ( 931.5 \ MeV) \\ \\ = \Big ( 2(4.002603 \ u) - (8.00530510 \ u) \Big) \Big ( 931.5 \ MeV/u \Big) \ \\ \mathbf{= -0.092 \ MeV}[/tex]

From the second reaction:

[tex]Q = \Big ( M(_4Be^8) + M(_2He^4) - M(_6C^{12}) \Big ) ( 931.5 \ MeV) \\ \\ = \Big ( 8.00530510 \ u +4.002603 \ u -12 \ u \Big) \Big ( 931.5 \ MeV/u \Big) \ \\ \mathbf{= 7.37 \ MeV}[/tex]

Answer:

Explanation:

At the point when light is vertically polarized is incident on the polarizer whose axes are situated at angle points [tex]\theta _1 , \theta _2 , \theta _3[/tex] the intensity power in the wake of going through all the polarisers is given by the Malus law, applied threefold for every one of the three axes.

[tex]I = I_o \ cos \theta _1 \ cos \theta _2 \ cos \theta _ 3[/tex]

The heading of the direction of the polarization is equivalent to the pivoted axes of the polarizer provided that light is an electromagnetic wave, its course of polarization is therefore controlled by the electric field part.

∴

a)

When sheet A is removed, the transmitted light goes through B, at 30°.

[tex]I = I_o \ cos ^2 \theta _1 \ cos ^2 \theta _2 \ cos^2 \theta _3[/tex]

[tex]I = 20 \ cos ^2 30 \ cos ^2 60 \ cos ^2 30[/tex]

[tex]I = 2.81 \ W/m^2[/tex]

b)

When B is removed, No light passes since the axis of A and the axis of C are perpendicular to each other.

c)

When C is removed, the intensity is indeed zero since the axes are aligned and adjusted at 90° to one another.

[tex]\mathbf{d) \ I - I_o cos^2 (0) cos^2 (30) \ cos^2 (60)}[/tex]

[tex]\mathbf{d = 3.75 \ W/m^2}[/tex]

Answer:

so you have a question

Explanation:

either way,you have a nice day