Answer:
Frame of reference
Your cousin has looked after you your whole life and you always looked up to him. Today he told you he sells drugs; " That's where I get all the money for clothes and stuff. " He asked, Do you want to go into business with me you will make great money?" What do you do/say to him? Use the decision-making process. *
Answer:
Honestly, you should have a firm resolve not to go into drug peddling.
Politely tell him you are not interested in the business, that you are most concerned about your future and the career path you have chosen for yourself already.
He will definitely feel bad, but you can go on to advise him.
You can also advise him to stop and highlight the dangers of doing drugs.
Explanation:
There are a whole lot of disadvantages involved in the drug business,
in fact, the disadvantages out weights the advantages in the long run.
say if one is caught and sent to a life long sentence, or if one is caught up with the effect of the use of hard drugs and the health implication, to the extent that one looses his/her sanity, you see it won't make any sense anymore doing drugs in the long run. so friend you can advise you cousin to stop and thinker of good businesses that cold fetch him cool money, without the law chasing him, with that he can be a contributor to economic growth by paying his taxes too
How many sets of planets would you need to create the mass of the Sun?
Answer:
volume about 1.3 million Earths could fit inside the Sun the mass of the Sun is 1.989 X 10 to the 30 kg about 333000 times the mass of the Earth
Explanation:
step-by-step explanation hope this answer your question
A 2.60-kg box is sliding across the horizontal floor of an elevator. The coefficient of kinetic friction between the box and the floor is 0.380. Determine the kinetic frictional force that acts on the box for each of the following cases. (a) The elevator is stationary. N (b) The elevator is accelerating upward with an acceleration whose magnitude is 1.20 m/s2. N (c) The elevator is accelerating downward with an acceleration whose magnitude is 1.20 m/s2. N Additional Materials
Answer:
a) F = 9.69 N
b) F = 10.88 N
c) F = 8.51 N
Explanation:
a) The kinetic frictional force when the elevator is stationary is the following:
[tex] F_{k} = \mu_{k}N = \mu(mg) [/tex]
Where:
F(k) is the kinetic frictional force
N is the normal force = mg
m: is the mass = 2.60 kg
g: is the gravity = 9.81 m/s²
μ(k) is the coefficient of kinetic friction = 0.380
[tex] F_{k} = \mu(mg) = 0.380*2.60 kg*9.81 m/s^{2} = 9.69 N [/tex]
b) When the elevator is accelerating upward with acceleration "a" equal to 1.20 m/s²
[tex] F_{k} = \mu_{k}N = \mu[m(g + a)] [/tex]
The normal is equal to mg plus ma because the elevator is accelerating upward
[tex] F_{k} = \mu m(g + a) = 0.380*2.60 kg(9.81 m/s^{2} + 1.20 m/s^{2}) = 10.88 N [/tex]
c) When the elevator is accelerating downward with a =1.20 m/s² we can find the kinetic frictional force similar to the previous case:
[tex] F_{k} = \mu m(g - a) = 0.380*2.60 kg(9.81 m/s^{2} - 1.20 m/s^{2}) = 8.51 N [/tex]
I hope it helps you!
a negatively charged particle is attracted to: A) all particles that are located close by B)negatively charged particles C) positively charged particles D)only particles that are large
Answer:
The answer is C) Positively charged particles
Explanation:
Particles with the same charge are repelled by one another, while particles with different charges are attracted to one another.
Answer:
positively charged particles (c)
Explanation:
I got it right on Study Island
Consider a line charge as your source. What is the order of your steps when applying coulomb's law. Below is a sequence of events. Place them in the order they should occur, number 1 being the first item. Select the step number from the drop down next to each item. Items to order: 1. Plug in coulomb's law. 2. Line integrate the expression. 3. Find the position vector of your field point. 4. Find the distance vector between differential source charge and field point. 5. Define your reference. 6. Find the dynamic position vector of these differential charges. 7. Carve the line in differential segments and assign each segment differential charge.
Answer:
the correct order of events is: 5 7 6 3 4 1 2
Explanation:
In this exercise, you order the events to solve the problem of the electric field created by a line of charge a line of charge
the order of events is
a) We define a reference 5
b) cut the line into segments each one is a charge differential 7
c) find the vector of the position of charges 6
d) find the point where field is calculated 3
e) find the distance between each charge point and point of interest 4
f) insert Coulomb's law 1
f) perform the integral of line 2
therefore the correct order of events is: 5 7 6 3 4 1 2
A bowling ball of mass m = 1.7 kg drops from a height h = 14.2 m. A semi-circular tube of radius r = 6.2 m rest centered on a scale. Write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the variables in the problem statement.
Answer:
W_net = mg + 2mgh/r
Explanation:
The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.
Now, gravitational force is; F_g = mg
While centripetal force is; F_c = mv²/r
Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.
Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.
Thus;
F_c = 2mgh/r
Where;
m is ball mass
r is tube radius
h is fall height
Thus, the net force will be;
F_net = F_g + F_c
Now, Net force would be equal to the net weight that will be read on the scale.
Thus;
W_net = F_net = F_g + F_c
W_net = mg + 2mgh/r
At its lowest point, the net force of the bowling ball is equal to its net weight and this is given by [tex]F_{net} = mg + \frac{2mgh}{r}[/tex]
Given the following data:
Mass, m = 1.7 kg.Height, h = 14.2 meters.Radius, r = 6.2 meters.To write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the given variables:
The forces acting on the ball.In this scenario, there are two (2) forces acting on the bowling ball and these include:
Centripetal forceGravitational forceMathematically, centripetal force is given by this formula:
[tex]F_c = \frac{mv^2}{r}[/tex] .....equation 1.
Mathematically, gravitational force is given by this formula:
[tex]F_g= mg[/tex] ....equation 2.
Where:
m is the mass.g is the acceleration due to gravity.v is the velocity.Next, we would derive an expression for the velocity of the ball by applying the Law of Conservation of energy:
[tex]P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\V^2=2gh[/tex] .....equation 3.
Substituting eqn. 3 into eqn. 2, we have:
[tex]F_c = \frac{m(2gh)}{r}\\\\F_c = \frac{2mgh}{r}[/tex]
At its lowest point, the net weight of the bowling ball is equal to its net force and this is given by this mathematical expression:
[tex]W_{net} = F_{net} = F_g + F_c\\\\F_{net} = mg + \frac{2mgh}{r}[/tex]
Read more on net force here: https://brainly.com/question/14361879
A man climbs on to a wall that is 3.6 m high and gains 2222.64 J of potential
energy. What is his mass?
63 kg
17.5 kg
405 kg
617.4 kg
if you apply force on an object such as a ball, what will possibly happen to it?
A 63.9 kg water skier is pulled by a
125 N force at a 31.5° angle, while
the water creates a 84.8 N force
pulling directly backward. What is the
y-component of the acceleration?
Answer:
[tex]a_{x} = 0.342 \frac{m}{ {s}^{2} } \: "x \: component \: of \: acceleration"
\: \\ a_{y} = 1.02 \: \frac{m}{ {s}^{2} } \: "y \: component \: of \: acceleration" [/tex]
Explanation:
Given a mass of 63.9kg with a total applied force of 125 N at a 31.5° inclination relative to the horizontal and vertical, and a horizontal resistance force of 84.8 N. The components of acceleration can be calculated as follows:
Force = mass × acceleration
Vertical component of a vector = vector × Sin(angle)
Horizontal component of a vector = vector × Cos(angle)
extra:
V = √x^2+y^2
θ (angle, "theta") = arctan or inverse tan(y/x) (For this instance. Theta is usually an angle measure though)
x = V cos θ
y = V sin θ
____________________
To find the vertical component of acceleration we must first take the vector quantity of our force which is 125 N (Newtons) and it's angle of 31.5°.
Vertical force = 125 × sin(31.5 degrees) = 125 × 0.5225 = 65.312 N [aka the normal force]
This works because force is a vector, it has both direction(by the angle of force), and magnitude(it's quantity).
Then take the force equation, and rearrange it to solve for the upward acceleration: F = m × a → a = F/m.
a = 65.312/63.9 ≈ 1.02 m/s^2.
Then for the horizontal acceleration, take the cosine for the horizontal part
What are some What are some of the possible advantages of memory being a constructive process?
Titan is special because
9.
Un Pldle UI TUL!
What acceleration is produced on a mass of 200 g, when a force of 10 N is
exerted on it ?
Given parameters:
Mass of the body = 200g
Force on the body = 10N
Unknown parameters:
Acceleration produced by the force = ?
To solve this problem we must first define force in terms of mass and acceleration. This is possible due to the Newton's first law of motion.
Force = mass x acceleration
Here the unknown is acceleration and we can easily solve for it.
But we must take the mass to kilogram in order for it to cancel out.
1000g = 1 kg
200g = x kg = [tex]\frac{200}{1000}[/tex] = 0.2kg
Now input the parameters and solve;
10 = 0.2 x acceleration
Acceleration = [tex]\frac{10}{0.2}[/tex] = 50m/s²
The acceleration produced by the body is 50m/s²
When you shock your self because of a door knob this is an example of
A.the law of conservation of charge
B. Force field
C.static discharge
D.torture lol
Answer:
C
Explanation:
Static electricity is what makes your hair stand up when you rub a balloon against it or gives you a shock from your doorknob. In static electricity, electrons are moved around mechanically (i.e. by someone rubbing two things together).
HOPE THIS HELPED AND LETTER D MADE ME LAUGH
An intrepid treasure-salvage group has discovered a steel box, containing gold doubloons and other valuables, resting in 80 ft of seawater. They estimate the weight of the box and treasure (in air) at 7000 lbf. Their plan is to attach the box to a sturdy balloon, inflated with air to 3 atm pressure. The empty balloon weighs 250 lbf. The box is 2 ft wide, 5 ft long, and 18 in high. What is the proper diameter of the balloon to ensure an upward lift force on the box that is 20% more than required
Answer: the proper diameter is 6.137 ft
Explanation:
first we find the volume of box using the relation, which is;
V = 2 x 5 x 1.5 = 15 ft³
we find the buoyant force on the box by calculating the weight of water displaced.
FB = V x y
where y is the specific weight of sea water(62.4 lbf/ft³)
so we Substitute
FB = 15 x 62.4 = 936 lbf
now we find the upward force required by the balloon
FR = (W - FB) x 120%
= 1.2 (W - FB)
where W is the weight of the box treasure(7000 lb)
so we Substitute,
FB = 1.2( 7000 - 936 ) = 7276.8 lbf
Because the universal gas constant contains a Rankine in its units, we make use of Rankine for our temperature
so we find the density of air at 3 atm using ideal gas relation,
Pair = p/RT
Here, p is the pressure acting (3 atm), R is the universal gas constant (1716 ft²/S²-R), and T is the temperature (520°R),
Substitute so we substitute
Pair = (3 * 2116.22) / (1516 * 520)
= 0.007114 lbf.ft³
next we find the specific weight of air;
Yair = Pair * g
g is acceleration due to gravity(32.2 ft/s²)
Yair =
0.007114 * 32.2
= 0.23 Ibf /ft³
Now we find diameter of the balloon by balancing the net force required
FR = (y - yair) * V - Wb
= (y - yair) x (π/6)d³ - Wb
d is the diameter of the balloon.
so we Substitute, 7276.8 lbf for FR,
62.4 Ibf/ft³ for y, 0.23 for lbf/ft³ for Yair, 350 lb for Wb
so
7276.8 = (62.4 - 0.23)πd³ - 250
d³ = 231.23 ft³
d = 6.137 ft
Therefore, the proper diameter is 6.137 ft
A car drives horizontally off a cliff that is 30 meters high killing the driver on impact. The grieving widow claims her husband would never have driven faster than the posted speed limit of 35 mph and has hired a lawyer to sue the city for negligence. You are sent to investigate the crash site. You measure that the car landed 75 m from the base of the cliff [1 mph = 0.447 m/s].
A. Draw the detailed sketch for this motion with all of the relevant information, variables, and numbers contained in the sketch.
B. Write the three projectile equations with the known values and unknown variables placed into the equation.
C. Determine the time of fall. Then determine vix of the car as it flies off the cliff.
D. Based on what you were able to determine, assess whether the city is held liable for the accident
Answer:
b) 0 = y₀ + 0 - ½ g t² , v₀ₓ = x / t
c) v₀ₓ = 30.31 m / s
Explanation:
This is a projectile launching exercise, in your statement you have units of several systems, we are going to reduce everything to the SI system
v = 35 mph (0.447 m / s / 1 mph) = 15.645 m / s
y₀ = 75 m
A) In the attachment we can see a diagram of the movement of the vehicle in its fall
B) let's find the time for the fall to the base of the cliff (y = 0)
y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²
when the vehicle leaves the cliff it goes horizontally, so its vertical speed is zero (v_{oy} = 0)
0 = y₀ + 0 - ½ g t²
t = √2y₀ / g
with this time we can use the equation of motion on the x axis
x = v₀ₓ t
v₀ₓ = x / t
C) we perform the calculations
t = √ (2 30 / 9.8)
t = 2.474 s
v₀ₓ = 75 / 2.474
v₀ₓ = 30.31 m / s
D) as we can see, the vehicle speed when leaving the cliff is almost twice the allowed speed (15.6 m / s)
therefore the city is not responsible for the accident
Classes are canceled due to snow, so you take advantage of the extra time to conduct some physics experiments. You fasten a large toy rocket to the back of a sled, and take the modified sled to a large, flat, snowy field. You ignite the rocket, and observe that the sled accelerates from rest in the forward direction at a rate of 13.5 m/s2 for a time period of 3.30 s. After this time period, the rocket engine abruptly shuts off, and the sled subsequently undergoes a constant backward acceleration due to friction of 6.15 m/s2.After the rocket turns off, how much time does it take for the sled to come to a stop?By the time the sled finally comes to a rest, how far has it traveled from its starting point?
Answer:
-time it takes for the sled to come to a stop after launch of rocket = 7.244 s
-distance sled has travelled from its starting point by the time it finally comes to rest is = 234.8655 m
Explanation:
From the question, looking at the motion while accelerating, we have;
Initial velocity; u = 0 m/s
Acceleration; a = 13.5 m/s²
Time; t = 3.3 s
Let's use first equation of motion to find final velocity (v).
v = u + at
v = 0 + (13.5 × 3.3)
v = 44.55 m/s
In this forward direction, let's calculate the displacement(d1) using newton's 3rd equation of motion.
d1 = ut + ½at²
d1 = 0(3.3) + ½(13.5 × 3.3²)
d1 = 73.5075 m
Now, let's consider the motion while slowing down and our final velocity will be 0 m/s while initial velocity will now be 44.55 m/s while acceleration is 6.15 m/s².
Thus, from v = u + at, we can find the time it take for the sled to come to a stop.
Now, since it's coming to rest acceleration will be negative. Thus;
0 = 44.55 + (-6.15t)
0 = 44.55 - 6.15t
t = 44.55/6.15
t = 7.244 s
Now we want to find out how far the sled has travelled from its starting point by the time it finally comes to rest.
Thus, we'll use the equation;
v² = u² + 2as
Where s will be the second displacement which we will call d2.
Thus;
0² = 44.55² + (-2 × 6.15 × s)
0 = 1984.7025 - 12.3s
12.3s = 1984.7025
s = 1984.7025/12.3
s = 161.358
Thus, d2 = s = 161.358 m
Thus, distance sled has travelled from its starting point by the time it finally comes to rest is ;
= d1 + d2 = 73.5075 + 161.358 = 234.8655 m
which of the following units is part of the international system of units, or SI?
Pounds meters
ounces inches
it is meters and ounces
classify the planets as inner planets of outer planets explain your answer
Answer: Planets A and B have a rocky mantle and an iron core. They are at a distance of 1 AU or less from the Sun. This means they are relatively close to the Sun. There are the properties of inner (terrestrial) planets. So planet A and B are inner planets.
Explanation:
Planet C is composed if the gases hydrogen and helium. It has a high mass and is much farther from 1 AU from the sun. These properties are consistent with the outer planets. So, planet C is an outer (gas giant) planet.
Answer:
Planets A and B have a rocky mantle and an iron core. They are at a distance of 1 AU or less from the Sun. This means they are relatively close to the Sun. There are the properties of inner (terrestrial) planets. So planet A and B are inner planets.
Explanation:
1. Tectonic plates that move toward each other ...A Mantle
2. Layer with partially melted material that can flow easily _....B. Convergent
3. Tectonic plates that move away from each other C. Transform
4. Tectonic plates that slide past each other D. Divergent
Answer:
Its convergent
Explanation:
There areas where plates move toward each other and collide Also known as compressional pr destructive boundaries.
Calculate the acceleration of the object in free fall (picture shown above)
Answer:
Estimate slope= acceleration of -18.75 m/s^2
Explanation:
In the velocity vs time graph, acceleration is the slope
Let's take two points from the line and find the slope
(0,0) (0.8, -15)
slope = -15-0/ 0.8-0 = -18.75 m/s^2
What do the EM results indicate about what might is causing this disease?
Answer:
In the event of a disease caused by an unknown pathogen, it is hard to know which reagent to pick. ... EM, though it may not be able to identify a virus beyond the family level, at least ... Negative staining of stool specimens from these cattle demonstrated a ... This results in a fuzzy halo around the particles in negative stains.Explanation:
What is the speed of a car that travels 0.200 km in 95 seconds? State your answer in meters per second.
Answer:
2.10 meters per secondExplanation:
speed (velocity) = distance / time
= 0.2 km (1000 m/km)
95 secs.
= 2.10 meters per second
We eat pizza from the inside out???
Answer:
what
Explanation:
what I dont get it??
Answer:
that makes me confused I don't think of pizza the same again LOL
Atoms are ___because they have equal amounts of positive and negative charges?
What is the amount of thermal energy that can be stored in an object depends on?
What is magnetic poles always come in pair
100 POINTS. PLEASE PROVIDE EXPLANATION FOR PART D
Answer:
0.298
Explanation:
Work equals change in energy. So the work done by friction equals the final kinetic energy minus the initial potential energy.
W = ΔE
Fd = ½ mv² − mgh
Nμ (-d) = 46.0 J − (25 N) (3.30 m)
-Nμ d = -36.5 J
Using a free body diagram, the normal force is:
N = mg cos θ
N = (25 N) (4.90 m / d)
N = 122.5 J / d
Nd = 122.5 J
Therefore:
-(122.5 J) μ = -36.5 J
μ = 0.298
PLEASE PROVIDE EXPLANATION FOR D AND E
THANK YOU!
Answer:
d) 14.1 m
e) 8.57 m/s
Explanation:
(a) There are three forces on the ball:
Normal force Fn pushing up,
Weight force Fg pulling down,
Kinetic friction Fk pushing left (resisting motion).
FBD is the correct free body diagram.
(b) Sum of forces in the y direction:
∑F = ma
Fn − Fg = 0
Fn = Fg
Sum of forces in the x direction:
∑F = ma
-Fk = ma
-Fn μk = ma
-mg μk = ma
a = -g μk
a = -(10 m/s²) (0.25)
a = -2.5 m/s²
(c) Sum of torques about the ball's center:
∑τ = Iα
Fk r = ⅖ mr² α
mg μk r = ⅖ mr² α
g μk = ⅖ r α
α = 5g μk / (2r)
α = 5 (10 m/s²) (0.25) / (2 × 0.2 m)
α = 31.25 rad/s²
(d) The velocity and angular velocity at time t is:
v = at + v₀
v = -2.5t + 12.0
ω = αt + ω₀
ω = 31.25t + 0
When the ball begins to roll without slipping, v = ωr.
-2.5t + 12.0 = (31.25t) (0.2)
-2.5t + 12.0 = 6.25t
12.0 = 8.75t
t = 1.37
The distance the ball moves is:
Δx = v₀ t + ½ at²
Δx = (12) (1.37) + ½ (-2.5) (1.37)²
Δx = 14.1 m
(e) v = at + v₀
v = (-2.5 m/s²) (1.37 s) + 12.0 m/s
v = 8.57 m/s
Answer:
a
Explanation:
on egde 2020
A 20-kg bicycle carrying a 50-kg girl is traveling with a kinetic energy of 2,290 J.
What is the velocity of the girl and bicycle?
8 m/s
16 m/s
64 m/s
4 m/s
Answer:
64 m/s
Explanation:
64m/s is the answer of question
64/m/s the answer
What is the average speed of the whole trip?
Answer:
65 miles per hour.
Explanation:
Answer:
Average speed of entire trip is : 3.67 m/s
Explanation:
Speed is calculated as the distance covered divided by time
Average speed will be the :speed before stop add to speed after stopping then divide by 2
Speed before stop = 200/ 60 = 3.33 m/s
Speed after stop = 400/100= 4m/s
Average speed = (3.33+4)/2 = 7.33/2 = 3.67 m/s
