what is 5 ft to 18 in.

Answer:

42%

Step-by-step explanation:

26 - 15 = 11

Take your decrease and divide it by the original price:

11/26 = 0.4230

Multiply 0.4230 by 100 to find the percent:

42.3

Round your answer and you would get -

42%

Answer:

42%

Step-by-step explanation:

You divide 15 by 26 and get 0.5769 and it continues with other numbers. to the nearest percent is 58. Then you subtract it from 100 and get 42%.

Answer:

22

Step-by-step explanation:

Answer:

C = (A*P - 8.4Y -330T + 200I) / 100

Step-by-step explanation:

P = (8.4Y + 330T + 100C -200I ) / A

now we have to calculate completed passes C for given P, Y, T, I, A

A*P = 8.4Y + 330T -200I +100C

100C = A*P - 8.4Y - 330T + 200I

C = (A*P - 8.4Y -330T + 200I) / 100

I just solved the equation for C

Answer:

10%

Step-by-step explanation:

4.5-4.05=.45

.45/4.5=.1

0.1= 10%

Answer:

A = 22

B = 19

Explanation:

Numbers one and two will be a variable A and B respectively.

A + B = 41 Equation one

A + B = 5 Equation two

Isolate one of the variables. Let's use A

A + B = 41 = A = 41 - B

Now replace the A in Equation two.

(41 - B) - B = 5

Simplify: 41 - 2B = 5

Isolate variable: 38 = 2B --> B = 19

Use the value of B to find A

A = 41 - B = 41 - 19 = 22

So the answer is A = 22 and B =19

We want to find the unit rate of the bottles of water given that we know that the cost of 12 bottles is $10.32, we will find that the unit rate is:

r = 1.16 (bottles/$)

The unit rate is defined as the rate of change per unit, in this particular case, the unit rate would be the cost of every single bottle of water.

Here, we do know that for $10.32, you get 12 bottles.

The unit rate is just given by the quotient between these two values:

(12 bottles)/($10.32) = 1.16 (bottles/$)

Meaning that the cost of every single bottle is $1.16

If you want to learn more, you can read:

https://brainly.com/question/18065083

The joint distribution of the numbers of the three colours in the sample without replacement is:

[tex]\mathbf{P(A=a,B=b,C=c) = \dfrac{\Big( ^{p}_{ A} \Big) \Big( ^{q}_{ B} \Big) \Big( ^{r}_{ C} \Big) }{ \mathbf{\Big( ^{p+q+r}_{ \ \ \ n} \Big) } }\ \ \ \ where; n = A+B+C}[/tex]

Let consider A, B, and C to denote the three variables that are black, white, and red balls in the sample.

i.e.

Now, the numbers of ways 'n' balls are chosen without replacement in an urn that comprises of p black balls, q white balls, and r red balls can be computed as follows:

[tex]\mathbf{\implies \Big( ^{p+q+r}_{ \ \ \ n} \Big) }[/tex]

Now, the number of ways whereby A black balls can be chosen from p black balls is expressed as:

[tex]\mathbf{\implies \Big( ^{p}_{ A} \Big) }[/tex]

The number of ways whereby B white balls can be chosen from q white balls is expressed as:

[tex]\mathbf{\implies \Big( ^{q}_{ B} \Big) }[/tex]

The number of ways whereby C red balls can be chosen from r red balls is expressed as:

[tex]\mathbf{\implies \Big( ^{r}_{ C} \Big) }[/tex]

Therefore, we can conclude that the joint distribution of the numbers of the three colours in the sample without replacement is:

[tex]\mathbf{P(A=a,B=b,C=c) = \dfrac{\Big( ^{p}_{ A} \Big) \Big( ^{q}_{ B} \Big) \Big( ^{r}_{ C} \Big) }{ \mathbf{\Big( ^{p+q+r}_{ \ \ \ n} \Big) } }\ \ \ \ where; n = A+B+C}[/tex]

Learn more about joint distribution here:

https://brainly.com/question/17283589?referrer=searchResults

Answer:

x = 100

Step-by-step explanation:

[tex]\frac{x}{5}=20[/tex]

[tex]5*\frac{x}{5} =20*5[/tex]

x = 20 * 5

x = 100

Hope This Helps

Answer:

The answer is 6.5

Step-by-step explanation:

Answer:

D. y = −x2 − 4x + 1

Step-by-step explanation:

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Down

Vertex:  ( − 2 ,  5 )

Focus:  ( − 2 ,  19 /4 )

Axis of Symmetry:  x= − 2

Directrix:  y = 21 /4

x                     y

− 4                   1

− 3                   4

− 2                   5

− 1                    4

0                     1

Answer:

$8.91

Step-by-step explanation:

Multiply $4.95 times 0.80 ( convert 80% to a decimal ) and that will equal 3.96 .

Then , since you're marking it up , you're gonna add the 3.96 to 4.95 which will equal $8.91 .

:)

Answer:

63

Step-by-step explanation:

27/6=4.5

14*4.5=63

Dividing the ratio of red and blue cars:

96 /24 = 4

There are 4 times as many blue cars as red cars.

Multiply the number of red cars by the scale factor:

96 red x 4 = 384 blue cars

Answer:

384 blue cars

Step-by-step explanation:

Here's how I do all of this in my head:

Divide 96 by 24:

96 ÷ 24 = 4

Now that we know that the number we need is 4, all we have to do is multiply both factors by 4.

96 × 4 = 384

24 × 4 = 96 (which is the number we're looking for)

So now that we have 96 red cars, we can see that there's 384 blue cars, which will be your answer.

I hope I helped, and a Branliest is always appreciated! ☺

Answer:

Step-by-step explanation:

I TOO THE TEST ANSWER IS 12.67

Answer: 4

Step-by-step explanation:

since they are comparing it red to blue marbles and in 3:4 ratio 4 is the second one and it is comparing red to BLUE the second 1 is blue

Answer:

Step-by-step explanation:

Given:

Use the given formula and find d:

Answer:

To get the answer use the dinamic format of barnic, its super easy to use please look it up and use the steps provided

Step-by-step explanation:

It willl help you so much.

Answer:

the anwser is indeed 19 i just did the problem rn

Step-by-step explanation:

I JUST DID THE QUIZ

Answer:

  see attached graph

Step-by-step explanation:

There are a couple of ways you can look at this.

Point-Slope Form

The point-slope form of the equation for a line is ...

  y -k = m(x -h) . . . . . . . line with slope m through point (h, k)

Comparing this to the given equation, we see that ...

  k = -14, m = -7, h = 0

That is, the equation describes a line with slope -7 through point (0, -14).

The slope is the ratio of rise to run. Usually, "run" is considered to be positive in the +x direction (to the right). Here, you run out of room on most graphs if you look for a point that is 7 units down and 1 unit right of the y-intercept at (0, -14). (That point is (1, -21).) So, it is more convenient to start at the y-intercept (0, -14) and go 1 unit left and 7 units up to find another point on the line. That point is (-1, -7). With two points plotted, you can draw the graph.

__

Slope-Intercept form

We discovered above that the y-intercept is -14. You can get there also by putting the equation in slope-intercept form:

  y = mx +b . . . . . . line with slope m and y-intercept (0, b)

Adding -14 to both sides of the given equation gives you this form.

  y = -7x -14

The method of plotting is substantially identical to that described above.

__

Standard form

The standard form of the equation is ...

  ax +by = c

where a > 0, and a, b, c are mutually prime integers.

Adding 7x-14 to both sides of the equation puts it into standard form:

  7x +y = -14

The x- and y-intercepts are found by setting the other variable to zero and solving for the one that is left. Here, that means the x-intercept is ...

  c/a = -14/7 = -2

and the y-intercept is ...

  c/b = -14/1 = -14

These x- and y-intercepts are easily plotted on the x- and y-axes. The graph will be the line drawn through them. The attached graph shows the line and the intercepts.

a.

The number of outlets​ in 2007 are 1008 outlets

Since  the number of outlets​ A(t) at these alternative fueling stations t years after 2005 is [tex]A(t) = 233(2.08)^{t}[/tex] with t = 0 corresponding to 2005.

To find the number of outlets in 2007, we substitute t = 2 into the equation.

So,

[tex]A(t) = 233(2.08)^{t}\\A(2) = 233(2.08)^{2}\\A(2) = 233(4.3264)\\A(2) =1008.0512[/tex]

A(2) ≅ 1008 outlets (we round down to the nearest whole number since we can only have a whole number of outlets).

So, the number of outlets​ in 2007 are 1008 outlets

b.

The number of outlets in 2009 are 4361 outlets

To find the number of outlets in 2009, we substitute t = 4 into the equation.

So,

[tex]A(t) = 233(2.08)^{t}\\A(4) = 233(2.08)^{4}\\A(4) = 233(18.72)\\A(4) =4361.23[/tex]

A(4) ≅ 4361 outlets (we round down to the nearest whole number since we can only have a whole number of outlets).

So, the number of outlets in 2009 are 4361 outlets

c.

The number of outlets in 2010 are 9071 outlets

To find the number of outlets in 2010, we substitute t = 5 into the equation.

So,

[tex]A(t) = 233(2.08)^{t}\\A(5) = 233(2.08)^{5}\\A(5) = 233(38.93)\\A(5) = 9071.36[/tex]

A(5) ≅ 9071 outlets (we round down to the nearest whole number since we can only have a whole number of outlets).

So, the number of outlets in 2010 are 9071 outlets

Learn more about exponential increase here:

https://brainly.com/question/18261561

Answer:

im not sure sorry

Step-by-step explanation:

Answer:

34

Step-by-step explanation:

16+10+6=34

Answer:

i need points and this is a long question from before

thanks for the points

Step-by-step explanation:

Answer:

3.60

Step-by-step explanation:

Answer:

last week the where 3.6

Step-by-step explanation:

Answer:

a = 112

Step-by-step explanation:

[tex]a =s^{2} +3b-c[/tex]

Given that,

s = 7

b = 13

c = (-24)

Let's solve for a now.

[tex]a =s^{2} +3b-c[/tex]

[tex]a = 7^{2} +3*13-(-24)\\[/tex]

[tex]a=49+39+24\\[/tex]

[tex]a=88+24[/tex]

[tex]a=112[/tex]

Hope this helps you.

Let me know if you have any other questions :-)

Answer:

answer is I do'not no I am sorry

Answer:

Graph.

y=x+6y=x+17

Step-by-step explanation:

Answer:

It's 17/500

Step-by-step explanation:

I took the same test and I got it right!<3                                                                           pLeAsE gIvE bRaInLiEsT tYsM<3                                                                                           HaVe A wOnDeRfUl... WeEkEnD

(a) There are 2 sequences of length 1 that fit the bill: 0 and 1. So if [tex]b_n[/tex] is the number of permissible sequences, then [tex]b_1=2[/tex].

To the sequence 0, we can attach either 0 or 1 at the end, while the sequence 1 must be followed by 0. Then the permissible sequences of length 2 are 00, 01, and 10, so [tex]b_2=3[/tex].

Now consider a sequence of length n + 1, of which there are [tex]b_{n+1}[/tex].

• If the last digit is 0, then we got this sequence by simply joining 0 to one of [tex]b_n[/tex] sequences. In other words, there are [tex]b_n[/tex] permissible sequences of length n + 1 that end in 0.

• If the last digit is 1, then the previous digit must have been 0. Put another way, we join 01 to a permissible sequence of length n - 1 (there are [tex]b_{n-1}[/tex] of them). So there are [tex]b_{n-1}[/tex] permissible sequences of length n + 1 that end in 1.

These cases are mutually exclusive, so the number of (n + 1)-length permissible sequences is given by

[tex]\begin{cases}b_1 = 2 \\ b_2 = 3 \\ b_{n+1} = b_n + b_{n-2} & \text{for }n\ge2\end{cases}[/tex]

(b) The reasoning for a permissible ternary sequence is similar. Let [tex]t_n[/tex] be the number of sequences of length n not containing 11.

We first note that [tex]t_1 = 3[/tex], since we can have 0, 1, or 2; and [tex]t_2 =  8[/tex], since we can have 00, 01, 02, 10, 12, 20, 21, or 22.

Consider a sequence of length n + 1 ([tex]t_{n+1}[/tex] of these).

• If the last digit is 0, then we joined 0 to a permissible sequence of length n. So there are [tex]t_n[/tex] permissible sequences of length n + 1 ending in 0.

• If the last digit is 1, then the last two digits must be either 01 or 21. Since there are 2 choices for the n-th digit, there are [tex]2t_{n-1}[/tex] permissible sequences of length n + 1 ending in 1.

• If the last digit is 2, then we essentially have the same situation as if the sequence ended in 0, so there are [tex]t_n[/tex] sequences of length n + 1 ending in 2.

Then the recurrence for ternary permissible sequences is

[tex]\begin{cases}t_1 = 3 \\ t_2 = 8 \\ t_{n+1} = 2t_n + 2t_{n-1} & \text{for }n\ge2\end{cases}[/tex]