what formula do I use?​

Answer: the direction of the induced current will change :)

Explanation:

Answer:

The final speed of the second package is twice as much as the final speed of the first package.

Explanation:

Free Fall Motion

If an object is dropped in the air, it starts a vertical movement with an acceleration equal to g=9.8 m/s^2. The speed of the object after a time t is:

[tex]v=gt[/tex]

And the distance traveled downwards is:

[tex]\displaystyle y=\frac{gt^2}{2}[/tex]

If we know the height at which the object was dropped, we can calculate the time it takes to reach the ground by solving the last equation for t:

[tex]\displaystyle t=\sqrt{\frac{2y}{g}}[/tex]

Replacing into the first equation:

[tex]\displaystyle v=g\sqrt{\frac{2y}{g}}[/tex]

Rationalizing:

[tex]\displaystyle v=\sqrt{2gy}[/tex]

Let's call v1 the final speed of the package dropped from a height H. Thus:

[tex]\displaystyle v_1=\sqrt{2gH}[/tex]

Let v2 be the final speed of the package dropped from a height 4H. Thus:

[tex]\displaystyle v_2=\sqrt{2g(4H)}[/tex]

Taking out the square root of 4:

[tex]\displaystyle v_2=2\sqrt{2gH}[/tex]

Dividing v2/v1 we can compare the final speeds:

[tex]\displaystyle v_2/v_1=\frac{2\sqrt{2gH}}{\sqrt{2gH}}[/tex]

Simplifying:

[tex]\displaystyle v_2/v_1=2[/tex]

The final speed of the second package is twice as much as the final speed of the first package.

Answer:

The maximum height reached by the ball is 16.35 m.

Explanation:

Given;

initial velocity of the ball, u = 17.9 m/s

the final velocity of the ball at the maximum height, v = 0

The maximum height reached by the ball is given by;

v² = u² + 2gh

During upward motion, gravity is negative

v² = u² + 2(-g)h

v² = u² -  2gh

0 = u² -  2gh

2gh = u²

h = u² / 2g

h = (17.9)² / (2 x 9.8)

h = 16.35 m

Ttherefore, the maximum height reached by the ball is 16.35 m.

Answer:

Considering first question

    Generally the coefficient of performance of the air condition  is mathematically represented as

   [tex]COP  =  \frac{T_i}{T_o - T_i}[/tex]

Here [tex]T_i[/tex] is the inside temperature

while  [tex]T_o[/tex] is the outside temperature

What this coefficient of performance represent is the amount of heat the air condition can remove with 1 unit of electricity

So it implies that the air condition removes   [tex] \frac{T_i}{T_o - T_i}[/tex] heat with 1 unit of electricity

Now from the question we are told that the rate at which heat enters an air conditioned building is often roughly proportional to the difference in temperature between inside and outside. This can be mathematically represented as

         [tex]Q \ \alpha \ (T_o - T_i)[/tex]

=>        [tex]Q= k (T_o - T_i)[/tex]

Here k is the constant of proportionality

So  

    since  1 unit of electricity  removes   [tex] \frac{T_i}{T_o - T_i}[/tex]  amount of heat

   E  unit of electricity will remove  [tex]Q= k (T_o - T_i)[/tex]

So

      [tex]E =  \frac{k(T_o - T_i)}{\frac{T_i}{ T_h - T_i} }[/tex]

=>   [tex]E = \frac{k}{T_i} (T_o - T_i)^2[/tex]

given that  [tex]\frac{k}{T_i}[/tex] is constant

    =>  [tex]E \  \alpha  \  (T_o - T_i)^2[/tex]

From this above equation we see that the  electricity required(cost of powering and operating the air conditioner) is approximately proportional to the square of the temperature difference.

 Considering the  second question

Assuming that  [tex]T_i   =  30 ^oC[/tex]

 and      [tex]T_o  =  40 ^oC[/tex]

Hence  

     [tex]E = K (T_o - T_i)^2[/tex]

Here K stand for a constant

So  

        [tex]E = K (40 -  30)^2[/tex]

=>      [tex]E = 100K [/tex]

Now if  the  [tex]T_i   =  20 ^oC[/tex]

Then

       [tex]E = K (40 -  20)^2[/tex]

=>      [tex]E = 400 \ K[/tex]

So  from this see that the electricity require (cost of powering and operating the air conditioner)when the inside temperature is low  is  much higher than the electricity required when the inside temperature is higher

Considering the  third question

Now in the case where the  heat that enters the building is at a rate proportional to the square-root of the temperature difference between inside and outside

We have that

       [tex]Q = k (T_o - T_i )^{\frac{1}{2} }[/tex]

So

       [tex]E =  \frac{k (T_o - T_i )^{\frac{1}{2} }}{\frac{T_i}{T_o - T_i} }[/tex]

=>   [tex]E =  \frac{k}{T_i} * (T_o - T_i) ^{\frac{3}{2} }[/tex]

Assuming [tex]\frac{k}{T_i}[/tex] is a constant

Then  

     [tex]E \ \alpha \ (T_o - T_i)^{\frac{3}{2} }[/tex]

From this above equation we see that the  electricity required(cost of powering and operating the air conditioner) is approximately proportional to the square root  of the cube of the  temperature difference.

Answer:

We are given:

mass of the truck (m) = 3000 kg

velocity of the truck (v) = 25 m/s

Calculating the Momentum:

We know that the momentum of an object is equal to its mass times it's velocity

P = mv           (where P is the momentum of the truck)

Momentum of the truck:

replacing with the values of the truck

P = mv

P = 3000 * 25

P = 75000 kg m/s

Therefore, the momentum of the truck is 75000 kg m/s

Complete Question

A pile of bricks of mass M is being raised to the tenth floor of a building of height H = 4y above the ground by a crane that is on top of the building. During the first part of the lift, the crane lifts the bricks a vertical distance h1=3y in a time t1=4T. During the second part of the lift, the crane lifts the bricks a vertical distance h2=y in t2=T. Which of the following correctly relates the power P1 generated by the crane during the first part of the lift to the power P2 generated by the crane during the second part of the lift?

[tex]A.\ \ P_2=4P_1[/tex]

[tex]B.\ \  P_2=\frac{4}{3} P1[/tex]

[tex]C.\ \  P_2=P_1[/tex]

[tex]D. \ \ P_2=\frac{3}{4} P_1[/tex]

[tex]E. \ \ \ P_2=\frac{1}{3} P_1[/tex]

Answer:

The correct option is  B

Explanation:

From the question we are told that  

    The mass of the brick is  M

    The  height height of the 10th floor is  H =  4y

     The height attained during the first part of the lift is  [tex]h_1 =  3y[/tex]

     The time taken is [tex]t_1 =  4T[/tex]

    The height attained during the second part of the lift is  [tex]h_2  = y[/tex]

    The time taken is  [tex]t_2  =  T[/tex]

Generally the velocity of the crane during the first lift is mathematically represented as

         [tex]v_1  =  \frac{h_1}{t_1}[/tex]

=>      [tex]v_1  =  \frac{3y}{4T}[/tex]

Generally the velocity of the crane during the first lift is mathematically represented as

         [tex]v_1  =  \frac{h_2}{t_2}[/tex]

=>      [tex]v_1  =  \frac{y}{T}[/tex]

Generally the power generated during the first lift is  

     [tex]P_1 =  F_1 *  v_1[/tex]

Here [tex]F_1[/tex] force applied during the first lift which is mathematically represented as

       [tex]F_1  =  M  *  g[/tex] here g is the acceleration  due to gravity

So

       [tex]P_1 =  Mg * \frac{3y}{4T}[/tex]

Generally the power generated during the second lift is  

     [tex]P_2 =  F_2 *  v_2[/tex]

Here [tex]F_2[/tex] force applied during the second lift which is mathematically represented as

       [tex]F_2  =  M  *  g[/tex] here g is the acceleration  due to gravity

So

       [tex]P_2 =  Mg * \frac{y}{T}[/tex]

So the ratio  of the first power to the second power is  

      [tex]\frac{P_1}{P_2}  =  \frac{Mg * \frac{3y}{4T}[}{Mg * \frac{y}{T}}[/tex]

=>   [tex]\frac{P_1}{P_2}  = \frac{3}{4}[/tex]

=>    [tex]P_2 = \frac{4}{3} P_1[/tex]

Answer:

it dies

Explanation:

MWUAHHAHAHHA

Answer: h = 2.7 R - 1.7 r

Explanation:    

normally, force is 0 at the top ;

-N - mg = - m v^2 / ( R - r )

-0 - mg = (- mv^2) / ( R-r )

mg = (mv^2) / (R - r)

g = v^2 / ( R - r ) ; ----------------equation 1

conservation of energy ;

ΔK + ΔP = 0 ;

1/2 I ω^2 + 1/2 m v^2 + mg ( h2 - h1 ) = 0 ;  

0.5 * ( 2/5 ) m r^2 * ( v / r )^2 + 0.5 m v^2 + mg ( ( 2R - r ) -h ) = 0 ;

0.5 * ( 2/5 ) m r^2 * ( v / r )^2 + 0.5 m v^2 = mg ( - 2R + r + h ) ;

0.5 * ( 2/5 )r^2 * ( v / r )^2 + 0.5 v^2 = g ( - 2R + r + h ) ;

0.5 * ( 2/5 ) v^2 + 0.5 v^2 = g ( - 2R + r + h ) ;

[ 0.5 * ( 2/5 ) + 0.5 ] v^2 = g ( - 2R + r + h ) ;-------------equation 2

from equation 1 ,  v^2 = g ( R - r ), input in equation 2

[ 0.5 * ( 2/5 ) + 0.5 ] [ g ( R - r ) ] = g ( - 2R + r + h )

[ 0.5 * ( 2/5 ) + 0.5 ] [ ( R - r ) ] = ( - 2R + r + h )

0.7 ( R - r ) = h - 2R + r

0.7R - 0.7r = h - 2R + r

solve for h

h = 0.7R + 2R - 0.7r - r

h = 2.7 R - 1.7 r

they are bananas and bananas are curved because they grow curved

Answer:

The cell will have no electromotive force in it.

Explanation:

The battery provides the chemical energy that produces the force needed to move electron around the circuit and to generate electrical energy.

Answer:

D. Conclusion.

Explanation:

Answer:

hot humid with lots of rain.

Explanation:

ocean currents act as conveyer belts of warm and cold water sending heat to the polar regions and helping the tropical areas cool off, thus influencing both weather and climate. the tropics are particularly rainy because heat absorption , and thus ocean evaporation, is highest.

Mild with cooler weather than similar latitudes type of climate would be near cold ocean currents.

On the eastern side of ocean basins, lower latitudes or the tropics are where cold currents migrate in a direction toward the equator. They carry cold water into regions of the continent that have warm water, which are usually found on the west coastlines.

The Labrador Ocean Current and East Greenland Current flows are two noteworthy examples of cold currents.

From the perspectives of ecology and climate, ocean currents are also advantageous. For example, they are responsible for changing global temperatures.

Learn more about cold ocean currents here:

https://brainly.com/question/377571

#SPJ2

Explanation:

At a height of 93 m, the gravitational potential energy is given by :

P = mgh

Where, m is the mass of a penny

We can find its mass.

[tex]m=\dfrac{P}{gh}\\\\m=\dfrac{3}{9.8\times 93}\\\\m=0.00329\ kg[/tex]

We need to find how much potential energy will have transformed into kinetic energy at the half way point (46.5m). It can be calculated as :

[tex]E=mgh'\\\\E=0.00329\times 9.8\times 46.5\\\\E=1.499\ J[/tex]

Hence, a penny will have transferred 1.499 J of potential energy into kinetic energy.

Answer:

The time for the change in the angular velocity to occur is 14.08 secs

Explanation:

From the question,

the angular acceleration is - 4.46 rad/s²

Angular acceleration is given by the formula below

[tex]\alpha =\frac{\omega -\omega _{o} }{t - t_{o} }[/tex]

Where [tex]\alpha[/tex] is the angular acceleration

[tex]\omega[/tex] is the final angular velocity

[tex]\omega _{o}[/tex] is the initial angular velocity

[tex]t[/tex] is the final time

[tex]t_{o}[/tex] is the initial time

From the question

[tex]\alpha[/tex] = - 4.46 rad/s²

[tex]\omega _{o}[/tex] = 0 rad/s (starting from rest)

[tex]\omega[/tex] = -31.4 rad/s

[tex]t_{o}[/tex] = 0 s

Now, we will determine t

From [tex]\alpha =\frac{\omega -\omega _{o} }{t - t_{o} }[/tex], then

[tex]-4.46 = \frac{-31.4 - 0}{t - 0}[/tex]

[tex]-4.46 = \frac{-31.4}{t}[/tex]

[tex]t = \frac{-31.4}{-4.46}[/tex]

t = 7.04 secs

This is the time spent in one direction,

Since the angular displacement of the wheel is zero ( it returned to its initial position), then the time required for the change in the angular velocity will be twice this time, that is 2t

Hence,

The time is 2×7.04 secs = 14.08 secs

This is the time for the change in the angular velocity to occur.

Answer:

 E ’= E / 8

therefore the correct answer is A

Explanation:

Let's calculate the electric field in an insulating sphere with a radius r <R, let's use Gauus's law, with a spherical Gaussian surface

       Фi = ∫ E. dA = [tex]q_{int}[/tex] /ε₀

       E (4πr²) = q_{int} / ε₀

density is

      ρ = q_{int} / V

      q_{int} = ρ V = ρ 4/3 π r³

we substitute        

        E (4π r²) = ρ 4/3 π r³ /ε₀

        E = 1 /3ε₀   ρ r

let's change the density by

       ρ = Q / V = ​​Q / (4/3 π R³)

         E = 1 / 4πε₀ Q r / R³

if we now distribute the same charge on a sphere of radius R' = 2R

        E ’= 1 / 4pieo Q r / (2R)³

        E ’= 1 / 4ft Qr / R³ ⅛

        E ’= E / 8

therefore the correct answer is A

Answer: the link isnt loading

Answer Yes you answered correctly.

Explanation:

Gases, such as the air or helium inside a balloon, take the shape of the containers they're in. They spread out so that the space is filled up evenly with gas molecules. The gas molecules are not connected.

Answer:

Yea ur right

Explanation:

Explanation:

When the skater is dropped onto the ramp from above, the potential energy decreases and the kinetic energy increases.

Every time the skater bounces from the impact, thermal energy is gained, and both potential and kinetic energy are lost.

Answer:

a) 4.0 s

b) 16 m/s

c) The distance covered between 4 - 5 s is four times the distance covered between 4 - 5 s

d) Equal distance are covered between 0 - 4 s and 4 -5 s

Note: The question is incomplete. The complete question is as follows;

Refer to the chart below that has data about a moving object to answer the following questions.

Time Elapsed         0.0s   1.0s    2.0s    3.0s    4.0s    5.0 s

Distance Traveled 0.0m 10.0m 20.0m 30.0m 40.0m 80.0 m

a. What is the elapsed time between the 0-m mark and the 40-m mark?  

b. How large is the average velocity of the object for the interval from 0-5 s ?  

c. How does the interval of 3-4 s compare with the interval from 4-5 s in terms of distance?    

d. How does the interval of 0-4 s compare with the interval from 4-5 s in terms of distance?    

Explanation:

a. From the data provide, time elapsed between the 0 m - 40 m mark is 4.0 s

b. Average velocity = total distance/ total time

average velocity = 80 m/ 5.0 s = 16.0 m/s

c. Distance covered between 3 - 4 s = 40 m - 30 m = 10 m

Distance covered between 4 - 5 s = 80 m - 40 m = 40 m

The distance covered between 4 - 5 s is four times the distance covered between 4 - 5 s

d. Distance covered between 0 - 4 s = 40 m - 0 m = 40 m

Distance covered between 4 - 5 s = 80 m - 40 m = 40 m

Equal distance are covered between 0 - 4 s and 4 -5 s

Answer:

The displacement of a body has two components: rigid-body displacement and deformation. A rigid-body displacement consists of a simultaneous translation and rotation of the body without changing its shape or size.

Hope this helps :)

Answer:

Q / Q₀ = 3.4 ,      ΔQ = 31.14 10⁻⁶ C

Explanation:

For this exercise we will calculate the charge of the capacitor with and without dielectric

the capacitance is given by

          C = Q /ΔV

we also use the ratio of capacitances

          C = k C₀

           Q /ΔV = kQ₀ /ΔV

           Q = k Q₀

            Q / Q₀ = k

            Q / Q₀ = 3.4

If we want a numerical value

           C = k Q / DV

           Q = C ΔV / k

            Q = 2.5 10⁻⁶ 60 / 3.4

            Q = 44.12 10⁻⁶ C

whereby the charge without dielectric is

          Q₀ = Q / 3.4

          Q₀ = 44.12 / 3.4 10⁻⁶

          Q₀ = 12.98 10⁻⁶ C

therefore the charge when removing the dielectric is reduced, the amount of charge that flows is

          ΔQ = Q - Q₀

          ΔQ = (44.12 - 12.98) 10⁻⁶

          ΔQ = 31.14 10⁻⁶ C

The amount of charge should be Q / Q₀ = 3.4 ,    ΔQ = 31.14 10⁻⁶ C

For this given situation,  we will determine the charge of the capacitor with and without dielectric

We know that

the capacitance is given by

         C = Q /ΔV

Now here we can applied the ratio of capacitances

So,

         C = k C₀

          Q /ΔV = kQ₀ /ΔV

          Q = k Q₀

           Q / Q₀ = k

           Q / Q₀ = 3.4

In case of numerical value

          C = k Q / DV

          Q = C ΔV / k

           Q = 2.5 10⁻⁶ 60 / 3.4

           Q = 44.12 10⁻⁶ C

whereby the charge without dielectric is

         Q₀ = Q / 3.4

         Q₀ = 44.12 / 3.4 10⁻⁶

         Q₀ = 12.98 10⁻⁶ C

Thus the charge at the time when removing the dielectric is decreased , the amount of charge that flows is

         ΔQ = Q - Q₀

         ΔQ = (44.12 - 12.98) 10⁻⁶

         ΔQ = 31.14 10⁻⁶ C

Learn more about battery here: https://brainly.com/question/24841364

Answer:

54mph

Explanation:

Answer:

D) Lifting it to a high shelf

Explanation:

Potential energy is where energy could be released at any moment. For example, if a cat gets on a tree it's creating potential energy, once that cat jumps from the tree the energy releases. D is the answers because if you set the book in a high shelf, you are only creating more potential energy.

hope I explain my self well enough

cheers man and good luck

the measure of how many a wave passes on a certain point in a certain time is

frequency

Answer:

The distance will be x = 1320 [m]

Explanation:

To solve this problem we must use the expression of physics that relates space to time, which is defined as speed.

v = Speed = 11 [m/s]

t = time = 120 [s]

x = distance [m]

v = x/t

x = v*t

x = 11*120

x = 1320 [m]

Answer:

60 kg

80 kg

Explanation:

Work is equal to the change in energy.

W = ΔE = E − E₀

Let's start with block B.  The work done by the tension force is equal to the change in energy.  Initially, the block has potential energy.  Finally, the block has kinetic energy.

W = ΔE

FΔy = ½ mv² − mgh

T (-2.0 m) = ½ m (6.00 m/s)² − m (10 m/s²) (2.0 m)

T (-2.0 m) = m (-2 m²/s²)

T = m (1 m/s²)

Now let's look at block A.  The work done by tension and against friction is equal to the change in energy.  Initially, the block has no energy.  Finally, it has both kinetic and potential energy.

W = ΔE

Fd = ½ mv² + mgh − 0

(T − Nμ) (2.0 m) = ½ (4.00 kg) (6.00 m/s)² + (4.00 kg) (10 m/s²) (⅗ × 2.0 m)

(T − Nμ) (2.0 m) = 120 J

T − Nμ = 60 N

Draw a free body diagram of block A and sum the forces in the perpendicular direction to find the normal force N.

N = mg cos θ

N = (4.00 kg) (10 m/s²) (⅘)

N = 32 N

Substitute:

T − 32μ = 60 N

If μ = 0, then T = 60 N and m = 60 kg.

If μ = ⅝, then T = 80 N and m = 80 kg.

Answer:did you find you answer also i answered so you can give him brainiest

Explanation: