What are the solutions to the system of equations?
y=x^2−5x−6
y=2x−6

(−1, 0) and (−6, 0)
(7, 8) and (0, −6)
(−6, 0) and (0, −1)
(−1, 0) and (0, −6)

Please answer- I will report you if you do not answer and only want the points.

Answer:no image

Step-by-step explanation:

Step-by-step explanation:

No image is overe there please add the image

The truth statements about the function f(x) = 14(0.87)^x is Growth; y = 0

From the question, we have the following parameters that can be used in our computation:

f(x) = 14(0.87)^x

An exponential function is represented as

y = ab^x

Where

a = initial value

b = growth/decay factor

In this case, the exponential function is a decay function

This means that

The value of b is less than 1 i.e.

b = 0.87 and 0.87 < 1

Hence, the function is a decay function

Recall that

f(x) = 14(0.87)^x

So, we have

y = 0 as the the equation of the asymptote

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Answer:

Step-by-step explanation:

Angle KEF and JEK

Answer:

----------------------------

Complementary angles are the angles that together form a right angle.

In the picture we see two right angles:

The first one, ∠DEJ has a pair of complementary angles:

The second one, ∠JEF has a pair of complementary angles:

Answer:

the answer is C

Step-by-step explanation:

the answer is C it converges

Answer:  (5, -1)

Step-by-step explanation:

format:  f(x)

in  f(5)=-1       x=5

also sometimes f(x) is called y so  y= -1

put into ordered pair format

(5, -1)

The remainder that is found when dividing 2x^2+7x-4 by x-3 is 35

From the question, we have the following parameters that can be used in our computation:

Dividing 2x^2+7x-4 by x-3

This means that

Dividend = 2x^2 + 7x - 4

Divisor = x - 3

Set the divisor to 0

So, we have

x - 3 = 0

Evaluate

x = 3

Substitute 3 for x in the dividend equation, so, we have the following representation

Remainder = 2(3)^2 + 7(3) - 4

Evaluate

Remainder = 35

Hence, teh remainder is 35

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The decimals as a power of 10 are given as follows:

A number in scientific notation is given by the notation presented as follows:

[tex]a \times 10^b[/tex]

With the base being [tex]a \in [1, 10)[/tex], meaning that it can assume values from 1 to 10, with an open interval at 10 meaning that for 10 the number is written as 10 = 1 x 10¹, meaning that the base is 1, justifying the open interval at 10.

Hence the numbers are represented as follows:

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The meauser of center is the most appropriate answer for table two is the mean.

Mean, in terms of math, is the total added values of all the data in a set divided by the number of data in the set.

Each mean serves to summarize a given group of data, often to better understand the overall value of a given data set. Pythagorean means consist of arithmetic mean, geometric mean, and harmonic mean

It is the mean because all of the data points are fairly close and there aren't any outliers (extreme values).

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[tex]f(2) = g(2) = 4[/tex], which means that the graphs of the two functions intersect at x = 2.

To show that the graphs of the functions   [tex]f(x) = 2^x[/tex] and [tex]g(x) = \sqrt(4x + 1) + 1[/tex]  intersect at the abscissa point x = 2, we need to show that both functions have the same value at  [tex]x = 2.[/tex]

First, we evaluate f(2):

[tex]f(2) = 2^2 = 4[/tex]

Next, we evaluate g(2):

[tex]g(2) = \sqrt(4(2) + 1) + 1 = \sqrt9 + 1 = 4[/tex]

Therefore,  [tex]f(2) = g(2) = 4[/tex] , which means that the graphs of the two functions intersect at [tex]x = 2[/tex] .

To visualize this, we can plot the two functions on the same set of axes:

As we can see from the graph, the two curves intersect at the point (2, 4).

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The complete question is: How can you show that the graphs of the functions f(x) = [tex]2^x[/tex] and g(x) = √(4x + 1) + 1 intersect?

The functions that have a range of all real numbers include the following:

Option 1; f(x) = -x + 2

Option 3; [tex]h(x) = 2^x +1[/tex]

In Mathematics and Geometry, a range can be defined as the set of all real numbers that connects with the elements of a domain.

Additionally, the vertical extent of any graph of a function represents all range values and they are always read and written from smaller to larger numerical values, and from the bottom of the graph to the top.

By critically observing the graph shown in the image attached above, we can reasonably and logically deduce the following range for f(x) and h(x):

Range = {-∞, ∞}, y|y ∈ R, or all real numbers.

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[tex][D]= \begin{bmatrix} 5&0&-8\\ 10&-2&7\\ -3&-9&6 \end{bmatrix}\implies 2[D] \stackrel{ \textit{scalar multiplication} }{\begin{bmatrix} (2)5&(2)0&(2)-8\\ (2)10&(2)-2&(2)7\\ (2)-3&(2)-9&(2)6 \end{bmatrix}} \\\\\\ ~\hspace{12.5em} 2[D]= \begin{bmatrix} 10&0&-16\\ 20&-4&14\\ -6&-18&12 \end{bmatrix}[/tex]

There was no error in the procedure as we can see below.

In algebra, a formula expresses a relationship between two or more variables. Changing the subject of a formula means isolating a specific variable on one side of the equation. This is done by applying inverse operations in a specific order to eliminate all other variables and isolate the desired one.

We have the formula as;

[tex]A = \pi R^2 - \pi r^2\\A = \pi(R^2 - r^2)\\A/ \pi = R^2 - r^2\\R^2 = A/ \pi + r^2\\R = \sqrt{} A/ \pi + √r^2\\R = \sqrt{} A/ \pi + r[/tex]

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The two roots of the quadratic equation x² - 5x + 3 = 0 are (5 + √13) / 2 and (5 - √13) / 2.

To find the roots of the quadratic equation x² - 5x + 3 = 0, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation.

Substituting the values of a, b, and c from the given equation, we have:

x = (-(-5) ± √((-5)² - 4(1)(3))) / 2(1)

x = (5 ± √(25 - 12)) / 2

x = (5 ± √13) / 2

Therefore, the roots of the equation are (5 + √13) / 2 and (5 - √13) / 2.

To verify that these are indeed the roots of the equation, we can substitute each of these values for x in the original equation and check if the equation is satisfied. For example, if we substitute (5 + √13) / 2 for x, we get:

(5 + √13)² - 5(5 + √13) + 3 = 0

Simplifying this equation, we get:

13 - 5√13 + 8 + 13 - 5√13 + 3 = 0

This equation is true, which means that (5 + √13) / 2 is a root of the equation x² - 5x + 3 = 0. Similarly, we can verify that (5 - √13) / 2 is also a root of the equation.

These roots can be found using the quadratic formula, which is a useful tool for solving quadratic equations.

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Using the property of proportionality for the equation (6-x) : (7-x) :: (18-x) : (22-x), then, x = ⁶/₇.

Solving this problem by using the property of proportionality, which states that the ratio of the first two terms in a proportion is equal to the ratio of the last two terms. In this case:

(6-x) : (7-x) :: (18-x) : (22-x)

Solving for x, cross-multiply the ratios:

(6-x) x (22-x) = (7-x) x (18-x)

Expanding both sides:

132 - 28x + x² = 126 - 25x + x²

Simplifying, we get:

7x = 6

Therefore, x = ⁶/₇.

Thus, the solution to the proportion is:

(6-x) : (7-x) :: (18-x) : (22-x)

or

⁶/₇ : ¹/₇ :: ¹²/₇ : ¹⁶/₇

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Answer: 6s + 10n less than or equal to 90

Answer:

[tex]v = \pi {r}^{2} h[/tex]

[tex] {r}^{2} = \frac{v}{\pi \times h} [/tex]

[tex]r = \sqrt{ \frac{v}{\pi \times h} } [/tex]

D is the correct answer.

You would need an additional $3.88 to buy the skateboard.

We need to calculate the total cost, including sales tax.

The sales tax rate is 6%, so the tax on a skateboard costing $98 would be as follows:

tax = 0.06 x $98 = $5.88

Consequently, the skateboard would have a total cost of:

total cost = $98 + $5.88 = $103.88

Since you have $100 to spend, you do not have enough money to buy the skateboard. You would need:

additional money = $103.88 - $100 = $3.88

Therefore, you would need an additional $3.88 to buy the skateboard.

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According to the given question, Alice should use this equation f(t) = [tex]24,000(0.945)^t[/tex] to represent the value of the car after t years.

Depreciation is the expected decrease in the value of fixed assets over the course of a fiscal year. For physical assets like real estate, machinery, vehicles, and other items, large lump sum acquisitions are made.

The equation[tex]f(t) = 24,000(0.945)^t[/tex] represents the value of the car after t years, where 0.945 represents the remaining value of the car after one year of depreciation at a rate of 5.5%.

To calculate the value of the car after two years, for example, we would substitute t = 2 into the equation:

f(2) = [tex]24,000(0.945)^2[/tex]

f(2) = 24,000(0.893025)

f(2) ≈ 21,433.80

Therefore, the value of the car after two years would be approximately $21,433.80.

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Answer:

D.The way you group numbers in a series of

multiplication problems doesn't change the final

product.

The values that fit in the solution are -4, -3, -2, -1 , 0

g > - 5

Inequalities are described as expressions that are used to represent an unequal relationship between numbers or variables.

They are represented with the symbols;

From the information given, we have that;

4 - 5g > 39

collect the like terms, we get;

-5g > 39 - 4

subtract the values

-5g > 35

Divide by the coefficient of g, we get;

g > -5

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The value of function g (5) is,

⇒ g (5) = 30/13

We have to given that;

Function is,

g (x) = {(x² + 5) / (x + 8)   if x ≠ - 8

      = { x - 1   ; if x = - 8

Hence, The value of function g (5) is,

⇒ g (5) = (x² + 5) / (x + 8)

⇒ g (5) = (5² + 5) / (5 + 8)

⇒ g (5) = (30) / (13)

Thus, The value of function g (5) is,

⇒ g (5) = 30/13

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The following are stated goals for this class:

1. Help students develop their ability to apply math concepts to real-world problems.

2. Increase your knowledge of consumer applications and personal financial management.

3. Explain the basics of home mortgages.

These goals are aimed at providing students with practical skills and knowledge that can be applied to their everyday lives, such as managing personal finances, understanding the mortgage process, and planning for retirement.

By learning math concepts in the context of real-world situations, students are better equipped to make informed decisions and solve problems that they may encounter in their personal and professional lives.

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Answer:

it is 0.94 miles

Step-by-step explanation:

that is because to make a mile you need 63,360 but since you have 60,000 it is not technically a mile

Answer:

m∠R=x=37°; m∠QOR=53°

Step-by-step explanation:

Any line that is tangent to a circle (such as QR) is perpendicular to the circle's radius (QO). Therefore, ΔOQR is a right triangle, with the right angle at Q.

1. You can use  90 + (x+16) + x = 180   or    (x+16) + x = 90 to solve for x.

2. If needed, you can then use the solution from step 1 to find the measure of ∠QOR.

Answer:

exponential graph

Step-by-step explanation:

it is a exponential graph the is negative ,if you substitute x values and find the points to plot you'll see how it is plotted

Answer:

See graph

Step-by-step explanation:

The graph of any function can be identified by making an x-y table.

Choose some values for x (often -2, -1, 0, 1, 2)

f(-2) = - 2^(-2) = - 1/4

f(-1) =  - 2^(-1) = - 1/2

f(-0) =  - 2^(-0) = - 1

f(1) =  - 2^(1) = - 2

f(2) =  - 2^(2) = - 4

a. The missing probability is 0.112

b. The expected number of classes passed is 3.38.

c. Is it unusual for an average student to pass at most 2 classes in a given semester is 0.211

a. Since the whole of all probabilities must rise to 1, we are able to discover the lost likelihood by subtracting the whole of the given probabilities from 1:

1 - 0.001 - 0.098 - 0.175 - 0.419 - 0.195 = 0.112

Subsequently, P(X=2) = 0.112.

b. The anticipated number of classes passed can be found by increasing each possible value of X by its particular likelihood, and after that summing the items:

E(X) = 0(0.001) + 1(0.098) + 2(0.112) + 3(0.175) + 4(0.419) + 5(0.195)

= 3.38

Hence, the anticipated number of classes passed is 3.38.

c. To decide in case it is bizarre for an average student to pass at most 2 classes in a given semester, we have to calculate the likelihood of passing at most 2 classes:

P(X ≤ 2) = P(X=0) + P(X=1) + P(X=2)

= 0.001 + 0.098 + 0.112

= 0.211

Since this likelihood is more noteworthy than 0.05 (i.e., the commonly utilized threshold for determining whether an occasion is unordinary), it isn't abnormal for a normal understudy to pass at most 2 classes in a given semester. 

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