Therefore the solution to this equation is imaginary given by x = [tex]\rm \dfrac { 3 \pm \sqrt{-3}}{2}[/tex]
What is a Quadratic Equation ?A Quadratic equation is an equation that can be written in the form of
ax² +bx+c = 0
The solution of the given quadratic equation
x² -3x +3 = 0
the roots of the equation is given by
[tex]\dfrac { -b \pm \sqrt{b^2 -4ac}}{2a}[/tex]
here a = 1 , b = -3 , c = 3
Substituting the values
The solution is
[tex]\rm \dfrac { 3 \pm \sqrt{(-3)^2 -4*1 *3}}{2}[/tex]
Therefore the solution to this equation is imaginary
given by
x = [tex]\rm \dfrac { 3 \pm \sqrt{-3}}{2}[/tex]
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Work out m and c for the line:
y = 2 − 3 x
Answer:
m = -3
c = 2
Step-by-step explanation:
This equation is given in slope-intercept form. The general structure of these equations is:
y = mx + c
In this form, "m" represents the slope and "c" represents the y-intercept. As you have been given the entire equation, the only thing you have to do is rearrange the equation to find which values correspond with the variables.
y = 2 - 3x -----> y = -3x + 2
Therefore,
m = -3
c = 2
Which best explains the formula? the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector. the central angle measure of the sector divided by the total angle measure of a circle multiplied by the circumference of the circle will yield the area of the sector. the central angle measure of the sector multiplied by the area of the circle will yield the area of the sector. the central angle measure of the sector multiplied by the circumference of the circle will yield the area of the sector.
The sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.
Area of a sectorThe coloured portion of the circle is known as a sector. The formula for calculating the area of a sector is given as:
Area of a sector = θ/360 * πr²
where
θ is the central angle
πr² represents the area of a circle.
Therefore the best statement that explains the formula is expressed as the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.
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Answer:
Its A edge 2023
Step-by-step explanation:
what’s the inverse of f(x)=(x+3)^3-1
Answer:
cbrt(x+1)-3=y
Step-by-step explanation:
The inverse of a function is when the domain and range are swapped. So to find the inverse simply swap the x and y in the equation and then solve for y.
[tex]y = (x+3)^3-1\\x=(y+3)^3-1\\x+1=(y+3)^3\\\sqrt[3]{x+1}=y+3\\\sqrt[3]{x+1}-3=y[/tex]
f(x) = x+3 f ( x ) = x + 3
Answer + Step-by-step explanation:
y = mx + b where m is the slope and b is the y-intercept
y = x + 3 where m = 1 is the slope and b = 3 is the y-intercept
Table of some points:
| x | 0 | 1 | 2 | 3 |
| y | 3 | 4 | 5 | 6 |
when x = 0, y = 0 + 3 and y = 3
when x = 1, y = 1 + 3 and y = 4
when x = 2, y = 2 + 3 and y = 5
Graph:
Domain and range of f(x)=3x^2-9x+8
The range of the function lies between (0,8) to (1.5,1.25).
What are domain and range?Range and Domain. The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values.
The given function is:-
f(x) = 3x² -9x + 8
The value of the range will be from (0,8) to ( 1.5,1.25). When we plot the graph of the function the value of the range lies between the points (0,8) to ( 1.5,1.25). The graph is attached with the answer.
The domain of the function will be all the values of the real numbers for the function ranges from ( 0, ∞ ).
Therefore the range of the function lies between (0,8) to (1.5,1.25).
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Step 1: –10 + 8x < 6x – 4
Step 2: –10 < –2x – 4
Step 3: –6 < –2x
Step 4: ________
What is the final step in solving the inequality –2(5 – 4x) < 6x – 4?
x < –3
x > –3
x < 3
x > 3
Answer:
x < 3
Step-by-step explanation:
The last step is to divide by -2. When you divide by a negative number you must reverse (flip) the inequality symbol.
-6 < -2x
-6/-2 > -2x/-2
3 > x
This is the same as
x < 3 (see the pointy side pointing at the x and the wide open side facing the 3)
What is 2 2/3 - (-3 2/6) show your work
The value of the expression 2 2/3 - (-3 2/6) is 6
How to solve the expression?The expression is given as:
2 2/3 - (-3 2/6)
Open the bracket
2 2/3 + 3 2/6
Express as improper fractions
8/3 + 20/6
Rewrite as:
16/6 +20/6
Evaluate the sum
36/6
Evaluate the quotient
6
Hence, the value of 2 2/3 - (-3 2/6) is 6
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Match each cross section with its perimeter. a cross section parallel to the base of a right rectangular prism that is 10 inches long, 3 inches wide, and 14 inches high a cross section perpendicular to the base of a cube with 12-inch edges a cross section perpendicular to the base and passing through the diagonals of the base and opposite face of a right rectangular prism that is 5 inches long, 12 inches wide, and 4 inches high and measures 13 inches along the diagonal of the base a cross section parallel to the base of a cube whose edges are 16 inches each Perimeter Cross Section 64 inches arrowBoth
the required perimeters are 26 inch, 48 inch, 34 inch and 64 inch respectively.
What is the perimeter?Perimeter, is the measure of the figure on its circumference.
1. perimeter for a cross section parallel to base of right rectangular prisms that is 10 inches long, 3 inches wide and 14 inches high:
length = 10 inches and width = 3 inch
The perimeter of that cross section is given by.
= 2 x length + 2 x width
= 2 x 10 + 2 x 3
= 20 + 6
= 26 inches
2. perimeter of cross section perpendicular to the base of a cube with 12 inch edge is given by.
= 4 x length
= 4 x 12
= 48 inches
3. perimeter of a cross section perpendicular to the base and passing through the diagonal of the base the right rectangle is given by.
length = 5; width = 12; height = 4; diagonal = 13;
perimeter = 2 x height + 2 x diagonal
= 2 x 4 + 2 x 13
= 34 inches
4. perimeter of a cross section of a cube having edges of 16 inches each.
perimeter = 4 x edge
= 4 x 16
= 64
Thus, The required perimeter of the cross section are 26, 48, 34, 64 all in inches.
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4 apples and 3 pears=£2.70 2 apples and 5 pears =£2.40 how much does 1 apple cost and 1 pear
Answer:
The answer is 0.45 pounds for an apple and 0.3 pounds for a pear
Step-by-step explanation:
Answer:
Cost of each apple: [tex]0.45[/tex].
Cost of each pear: [tex]0.30[/tex].
Step-by-step explanation:
Let [tex]x[/tex] denote the cost of each apple. Let [tex]y[/tex] denote the cost of each pear.
The question states that the cost of [tex]4[/tex] apples and [tex]3[/tex] pears is [tex]2.70[/tex]. Thus:
[tex]4\, x + 3\, y = 2.70[/tex].
Likewise, since the cost of [tex]2[/tex] apples and [tex]5[/tex] pears is [tex]2.40[/tex]:
[tex]2\, x + 5\, y = 2.40[/tex].
Solve this system of equations for [tex]x[/tex] and [tex]y[/tex] to find the price of each fruit.
[tex]\left\lbrace \begin{aligned} & 4\, x + 3\, y = 2.70 \\ & 2\, x + 5\, y = 2.40\end{aligned}\right.[/tex].
Multiply both sides of the equation [tex]2\, x + 5\, y = 2.40[/tex] by [tex]2[/tex] to match the coefficient of [tex]x[/tex] in the first equation:
[tex]\left\lbrace \begin{aligned} & 4\, x + 3\, y = 2.70 \\ & (2\times 2)\, x + (2 \times 5)\, y = (2 \times 2.40)\end{aligned}\right.[/tex].
[tex]\left\lbrace \begin{aligned} & 4\, x + 3\, y = 2.70 \\ & 4\, x + 10\, y = 4.80 \end{aligned}\right.[/tex].
Substitute the first equation from the new equation to eliminate [tex]x[/tex] and solve for [tex]y[/tex]:
[tex]\begin{aligned}& 4\, x + 10\, y - (4\, x +3\, y) = 4.80 - 2.70\end{aligned}[/tex].
[tex]10\, y - 3\, y = 2.10[/tex].
[tex]7\, y = 2.10[/tex].
[tex]y = 0.30[/tex].
Substitute [tex]y = 0.30[/tex] into an equation from the original system to eliminate [tex]y[/tex] and solve for [tex]x[/tex].
[tex]2\, x + 5\, y = 2.40[/tex].
[tex]2\, x + 5 \times 0.30 = 2.40[/tex].
[tex]2\, x = 0.90[/tex].
[tex]x = 0.45[/tex].
Thus, [tex]x = 0.45[/tex] and [tex]y = 0.30[/tex].
In other words, the price of each apple would be [tex]0.45[/tex]. The price of each pear would be [tex]0.30[/tex].
What is the solution set for -1<-2f+1<9? Please show work and chose a b c and d
The solution set is 1 ≥ f ≥ -4, and the correct number line is the one in option A.
How to find the solution set?
Here we have the inequality:
-1 ≤ -2f + 1 ≤ 9
To solve this, we need to isolate the "f" on the middle.
First, we can subtract 1 in both sides to get:
-2 ≤ -2f ≤ 8
Now we need to divide both sides by -2, remember that this will change the direction of the symbols:
-2/-2 ≥ f ≥ 8/-2
1 ≥ f ≥ -4
So we need to have a line that starts at -4 and ends at 1, the correct option is number line A.
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the rock cycle is an explanation of the conservation of
A. Magma
B. Matter
C. Sediment
Answer:
B. Matter
Explanation:
When rocks break down and become smaller ex: mountains eventually becoming sand, the matter does not disappear or get destroyed, it becomes smaller particles, but the matter is always preserved.
Hope It Helps!!!
Answer:
matter
Step-by-step explanation:
The conservation of matter states that
matter is neither created nor endorsedHere big matters gets down into smaller pieces
but they are not destroyed
Can someone help me please?
Answer:
C.
Step-by-step explanation:
The reds are counting up in whole numbers by one integer.
Hope this helps!
If not, I am sorry.
Peter gave away 5/12 of his marbles and had 70 left how many marbles he had at first
Answer:
There were 120 marbles to start
Step-by-step explanation:
Let x be the number of marbles at the start
x* 5/12 = number of marbles given away
1 -5/12 = 7/12 = fraction of marbles left
x * 7/12 = number of marbles left
x * 7/12 = 70
Multiply each side by 12/7
x *7/12 * 12/7 = 70 * 12/7
x =120
There were 120 marbles to start
[tex]\sf\large\green{\underbrace{\red{Befikra*}}}:[/tex].
The first term of an arithmetic sequence is 1 and the sum of the first four terms is 100. Find the first four terms
First term f = 1
If first four terms are f, f + d, f + 2d, f + 3d
f + f + d + f + 2d + f + 3d = 100
4f + 6d = 100 (divided by 2 , both sides )
2f + 3d = 50
2 + 3d = 50
3d = 50 – 2
3d = 48
d = 48/3
d = 16
The arithmetic sequence is 1, 17, 33, 49, ………….
Answer:
[tex]\sf\large\blue{\underbrace{\red{itz \: jass*}}}:[/tex]
Step-by-step explanation:
[tex]\sf\large\green{\underbrace{\red{hlo \: \: sat \: shri \: akal \: ji \: \: \: *}}}:[/tex]
. An elevator in a building starts with five passengers and stops at seven floors. Say every passenger is equally likely to get off at each floor and all the passengers leave independently of each other. a. How many ways are there for the passengers to be assigned a floor? b. How many ways are there for the passengers to be assigned a floor but no two passengers are on the same floor?
There are 16807 number of ways the passengers to be assigned a floor and there are 2520 number of ways the passengers to be assigned a floor but no two passengers are on the same floor.
Given that an elevator starts with five passengers and stops at the seven floors of a building.
From the given information, the total number of floors n=7.
The number of passengers r = 5.
(a) Compute the number of ways that 5 passengers can be assigned to seven floors.
Here, repetition is allowed.
From the known information, if r numbers are selected from n number of observations then the total number of observations that can be drawn from n number of observations is [tex]n^r[/tex].
If 5 passengers can be assigned to seven floors is 7⁵ = 16807.
(b) Compute the number of ways that the passengers to be assigned a floor but no two passengers are on the same floor.
Here, repetition is not allowed.
If 5 passengers can be assigned to seven floors but no two passengers are on the same floor is 7x6x5x4x3 = 2520.
Hence, the number of ways that 5 passengers can be assigned to seven floors is 16807, and the number of ways that the passengers to be assigned a floor but no two passengers are on the same floor is 2520.
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please help mee, (30 points will give brainliest!!!)
Answer:
-4
+3
12
-0.5, 12.25
x = -0.5
Step-by-step explanation:
The x intercepts are the values of x when y = 0 ie the roots of the equation
[tex]-x^2 -x +12 = 0[/tex]
or
[tex]x^2 + x - 12 = 0[/tex]
We can re-write the above as:
(x+4) (x-3) = 0
This gives the two roots as x = -4 and x = +3. Leftmost (smallest) root is -4 and rightmost(largest) root is +3
y intercept is when x = 0. Plugging into the original equation, y value at x = 0 is 12
Vertex x value is given by the formula -b/2a where a is the coefficient of x^2 and b the coefficient of x
Here a = -1, b= -1 so vertex x value = - (-1)/(-1).2 = - 1/2 = -0.5
Plugging this value of x into the original function gives the vertex y value
[tex]y = - (0.5^{2}) - (-0.5) + 12\\= -0.25 + 0.5 + 12 = 12.25[/tex]
The line of symmetry is the vertical line corresponding to the vertex x value so line of symmetry is at x = -0.5
The graph of the quadratic function shows these values
What is the decimal multiplier to increase by 93%?
Answer:
0.93
Step-by-step explanation:
Which of the following rational functions is graphed below?
-10
A. F(x)=
(x-1)(x+1)
X+1
B. F(x)=xx-1)
10
C. F(X) = XX+1)
x-1
x(x+1)
D. F(x) = (x+1)(x − 1)
X
Because we have a vertical asymptote at x = -1, we conclude that the correct option is C.
What is mean by Function?A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).
Now, In the graph,
we can see that we have a vertical asymptote at x = -1.
Hence, This means that the denominator of the rational equation becomes zero when x = -1.
So the equation must be:
⇒ y = 1 / (x + 1)
Here, The denominator is x + 1, and as expected, it becomes zero when, x = -1.
Then, we conclude that the correct option is C.
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For some given data, if Z-M = 2 and
x= 33.5, then Z =
(a) 35.5 (b) 36.5 (c) 32.5
(d) 34.5
Answer:
Not enough information. See below.
Step-by-step explanation:
Z-M = 2
x= 33.5, then Z = ?
How does x relate to Z or M? Is the Z-M= 2 equation correct? Or is it M=33.5?
Willing to give brainlyest if you can aswer these for me ASAP
Answer:
65
Step-by-step explanation:
its simple math
Answer:
x+5=12. x = 7,
7x=21. x = 3,
b-2/3=5/6. b = 1.5,
3/4x=6x=8. x = 1/3,
45=3(x+1). x = 14,
22.5+1.5x. x = 15,
20+(5•9). $65
Step-by-step explanation:
Which series of transformations will not map figure Q onto itself?
O(x+2, y-2), reflection over y = x - 1
O(x-2, y + 2), reflection over y = x + 3
O(x+0y-4), reflection over y = x - 1
O(x-3, y-3), reflection over y = -x +1
Question 1 (Answered)
OF
Your question is incomplete. Below you will find the missing content.
Which series of transformations will not map figure H onto itself?
A. O(x+0, y-2), reflection over y = 1
B. O(x+2, y-0), reflection over x=3
C. O(x+3, y+3), reflection over y = -x +7
D. O(x-3, y-3), reflection over y = -x +2
The correct option is Option D: the series of transformation O(x-3, y-3), reflection over y = -x +2 will not map figure H onto itself.
Here given a square with its 4 vertices at coordinates (2,1), (1,2), (2,3) and (3,2).
By checking all the options
Option A:
1st transformation (x+0, y-2) will map 4 vertices of the square into points of coordinates such as
(2,1) → (2,-1)
(1,2) → (1,0)
(2,3) → (2,1)
(3,2) → (3,0)
next transformation which is the reflection over y=1 gives the coordinates (x,2-y)
(2,-1) → (2,3)
(1,0) → (1,2)
(2,1) → (2,1)
(3,0) → (3,2)
These new points are exactly the same as the vertices of the initial square.
Option B:
1st transformation (x+2, y-0) will map 4 vertices of the square into points of coordinates such as
(2,1) → (4,1)
(1,2) → (3,2)
(2,3) → (4,3)
(3,2) → (5,2)
next transformation which is the reflection over x=3 gives the coordinates (6-x,y)
(4,1) → (2,1)
(3,2) → (3,2)
(4,3) → (2,3)
(5,2) → (1,2)
These new points are exactly the same as the vertices of the initial square.
Option C:
1st transformation (x+3, y+3) will map 4 vertices of the square into points of coordinates such as
(2,1) → (5,4)
(1,2) → (4,5)
(2,3) → (5,6)
(3,2) → (6,5)
next transformation which is the reflection over y=-x+7 gives the coordinates such as
(5,4) → (3,2)
(4,5) → (2,3)
(5,6) → (1,2)
(6,5) → (2,1)
These new points are exactly the same as the vertices of the initial square.
Option D:
1st transformation (x-3, y-3) will map 4 vertices of the square into points of coordinates such as
(2,1) → (-1,-2)
(1,2) → (-2,-1)
(2,3) → (-1,0)
(3,2) → (0,-1)
next transformation which is the reflection over y=-x+2 gives the coordinates such as
(-1,-2) → (4,3)
(-2,-1) → (3,4)
(-1,0) → (2,3)
(0,-1) → (3,2)
These new points are not matching with the vertices of the initial square.
Therefore the correct option is Option D: O(x-3, y-3), reflection over y = -x +2 will not map figure H onto itself.
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answer?...................
Step-by-step explanation:
please mark me as brainlest
Answer:
135
Step-by-step explanation:
2x²/x + x(100 - 15x)
If x = 5 ;
2(5)²/5 + 5(100 - 15×5)
= 2×25/5 + 5(100 - 75)
= 2 × 5 + 5 × 25
= 10 + 125
= 135
Evaluate the function: g(x) = -x +4 Find: g(b-3)
Answer:
g(b-3) = -b + 7
Step-by-step explanation:
Plug in the value (b-3) as x into the equation
g(b-3) = -(b-3) + 4
distribute the negative sign
g(b-3) = -b + 3 + 4
combine like terms
g(b-3) = -b + 7
In the figure below, if line r is parallel to line s, m
Answer:
Step-by-step explanation:
I'm not sure exactly what you're trying to ask
but r and s are parallel
and I'm assuming the 3rd line is line m, line m is not parallel to any line
and angles A and B are equal
there were 3 parts to Ritas race she ran the first part which was 4/9 of the total distance, in 20 minutes she ran the second part which was 2/5 of the remaining distance, in 12 minutes. She finally ran the third part in 15 minutes at the speed of 300 meters per minute.
How long was the first part of the race? What was Ritas speed in that section of the race?
Answer:
3/5 .................................. 6/9
Step-by-s4tep explanation:
Answer:
300 meters per minute
Step-by-step explanation:
Step 1
Determine the fraction of the total distance for each part of the race.
Given:
1st part of race = 4/9 of total distance2nd part of race = 2/5 of remaining distance[tex]\begin{aligned} \implies \sf 2nd\:part & = \sf \dfrac{2}{5}\:of\:remaining\:distance\\ & = \sf \dfrac{2}{5} \times\left(1-\dfrac{4}{9}\right)\\& = \sf \dfrac{2}{9}\:of\:total\:distance\end{aligned}[/tex]
[tex]\begin{aligned}\implies \sf 3rd\:part & = \sf 1-1st\:part-2nd\:part\\& = \sf 1-\dfrac{4}{9}-\dfrac{2}{9}\\& = \sf \dfrac{1}{3}\:of\:total\:distance\end{aligned}[/tex]
Step 2
Determine the distance of the third part of the race.
Given:
time = 15 minutesspeed = 300 meters per minute[tex]\begin{aligned}\sf Distance & = \sf speed \times time\\& = \sf 300 \times 15\\& = \sf 4500 \:\:meters\end{aligned}[/tex]
Step 3
If the third part of the race (which is 1/3 of the total distance) is 4500m, then the distance of the whole race is:
[tex]\begin{aligned} \sf Total\:distance & = \sf 4500 \times 3\\& = \sf 13500\:meters \end{aligned}[/tex]
Step 4
Determine the distance of the 1st part of the race:
[tex]\begin{aligned}\sf Distance\:of\:1st\:part\:of\:race & = \sf \dfrac{4}{9} \:of\:total\:distance\\& = \sf \dfrac{4}{9} \times 13500\\& = \sf 6000\:meters \end{aligned}[/tex]
Step 5
Determine the speed of the 1st part of the race:
Given:
time = 20 minutesdistance = 6000 m[tex]\begin{aligned}\sf Speed\:of\:1st\:part\:of\:race & = \sf \dfrac{distance}{time}\\& = \sf \dfrac{6000}{20}\\ & = \sf 300\:meters\:per\:minute\end{aligned}[/tex]
what are simultaneous equations
Answer:
Simultaneous equations are two or more algebraic equations that share variables e.g. x and y . They are called simultaneous equations because the equations are solved at the same time. Each of these equations on their own could have infinite possible solutions.
The number 1.41421356 is a rational or irrational number
Answer:
The real numbers include all the rational numbers, such as the integer −5 and the fraction 4/3, and all the irrational numbers, such as 2 (1.41421356..., the square root of 2, an irrational algebraic number).
If you draw all hearts from a deck of 52 cards,
what is the ratio of the remaining cards to the
whole deck?
Answer:
39
Step-by-step explanation:
Okay so there are 52 cards in a deck and there are 4 of each card. 4 kings 4 Queens 4 Jacks 4 Ace 4 Twos 4 Threes 4 fours 4 fives 4 sixes 4 sevens 4 eights 4 nines 4 tens. One from each group is a heart there are 13 groups so therefore subtract 13 from 52.
Question 8 of 10
What are the zeros of f(x) = x² − 8x + 16?
A. x= -4 and x = 4
B. x=-2 and x = 8
C. x = 4 only
D. x = -4 only
Answer:
c ×=4, only
Step-by-step explanation:
4*-8×+16=0
16-32=-16
-16=-16
Answer:
D. x=4 only
Step-by-step explanation:
You can solve using the quadratic equation which is [tex]x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}[/tex]
where in this case a=1, b=-8, and c=16. But there is any easier way to solve the equation. You can solve by completing the square which consists of moving the constant to the right side and then adding [tex](\frac{b}{2})^2[/tex]. To both sides that way you can rewrite the left side as a perfect square binomial. This is because [tex](x+b)^2[/tex] will expand to [tex]x^2 + 2xb + b^2[/tex]. So when you add [tex](\frac{b}{2})^2[/tex] to both equations. You're able to rewrite the left side as [tex](x+(\frac{b}{2}))^2[/tex]. Because once you expand it out, it becomes [tex]x^2 + 2(\frac{b}{2})x + (\frac{b}{2})^2[/tex]. Which simplifies to [tex]x^2 + bx + (\frac{b}{2})^2[/tex] which is the original equation. In this case there is no need to move the constant, which in this case is 16, to the other side. Since if you calculate the value of (-8/2)^2 it's equal to 16! So this can already be written as a perfect square binomial.
So the equation becomes
[tex]0 = (x+\frac{b}{2})^2[/tex]
Plug values in
[tex]0 = (x+(-\frac{8}{2}))^2[/tex]
Simplify
[tex]0 = (x-4)^2[/tex]
Take the square root of both sides
[tex]0 = x-4[/tex]
Add 4 to both sides
[tex]4 = x[/tex]
Which list is in order from least to greatest?
Answer:
The first option.
Explanation:
Since these numbers are given in scientific notation, we must first look at the exponent to determine whether or not it's big or small. Negative exponents are less, so we start with that. Immediately, that eliminates the second and third options as -8 is less than -6 and 3. The last two numbers given in the first and last options, however, both have 3 as the exponent. Now, we look at the number given in front. 2.5 is less than 7, so we know that the first option is in order from least to greatest.