The length of MQ and QN is 10 and 15 respectively and verify that MQ: QN = 2:3
The coordinate of M = (-12,-5)
The coordinate of N = (8,10)
n = 2 , m = 3
By using the section formula coordinate of Q =( [tex]\frac{mx_{1} + nx_{2} }{m+n }[/tex] , [tex]\frac{my_{1} + ny_{2} }{m+n}[/tex])
Coordinate of Q = ([tex]\frac{(-12)3 + 8(2)}{3+2}[/tex] , [tex]\frac{10(2) + 3(-5)}{2+3}[/tex])
Coordinate of Q = ( -4, 1)
Now using the distance formula
MQ = [tex]\sqrt{ (x_{2}- x_{1} )^{2} +(y_{2} -y_{1} )^{2}[/tex]
MQ = [tex]\sqrt{(-4+12)^{2}+(1+5)^{2} }[/tex]
MQ = √100
MQ = 10
Similarly,
QN = [tex]\sqrt{(8+4)^{2}+(10-1)^{2} }[/tex]
QN = [tex]\sqrt{225}[/tex]
QN = 15
MQ:QN = 10:15
MA :QN = 2:3
Hence it is verified that MQ: QN = 2:3
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Find the magnitude and direction of the vector u = <-4, 7>
The magnitude and direction of the vector u = <-4, 7> are |u| ≈ √65 and θ ≈ 119.74°.
To find the magnitude and direction of the vector u = <-4, 7>, we will use the following steps:
1. Calculate the magnitude using the Pythagorean theorem.
2. Calculate the direction using the arctangent function.
Step 1: Calculate the magnitude.
Magnitude (|u|) = √((-4)^2 + (7)^2) = √(16 + 49) = √65
Step 2: Calculate the direction (angle θ).
θ = arctan(opposite/adjacent) = arctan(7/-4) ≈ -60.26° (in degrees)
Since the vector is in the second quadrant, we need to add 180°.
θ = -60.26° + 180° ≈ 119.74°
So, the magnitude and direction of the vector u = <-4, 7> are |u| ≈ √65 and θ ≈ 119.74°.
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Which graphs represent functions?
4
←
4
•
4
4 -2
++
Graph A
4
2
2
2
4
4
2 4
Graph C
X
-4
-2
4
-2
2
-2-
4
Graph B
у
4-
2
-2
Graph D
4
4
Liquid a has a density of 1.2 g/cm'
150 cm of liquid a is mixed with some of liquid b to make liquid c.
liquid c has a mass of 220 g and a density of 1.1 g/cm
find the density of liquid b.
Density of liquid b = 0.4 g/cm³.
How to find the density of liquid B?Density of liquid A = 1.2 g/cm³Volume of liquid A = 150 cm³Mass of liquid C = 220 gDensity of liquid C = 1.1 g/cm³Let the volume of liquid B added be V cm³.
The total volume of the mixture = Volume of A + Volume of B = 150 + V cm³
Using the formula:
Density = Mass/Volume
Density of C = (Mass of C) / (Volume of C)
1.1 = 220 / (150 + V)
Solving for V, we get:
V = 100 cm³
Therefore, the volume of liquid B added is 100 cm³.
The total mass of the mixture = Mass of A + Mass of B = (Density of A x Volume of A) + (Density of B x Volume of B)
220 = (1.2 x 150) + (Density of B x 100)
Solving for Density of B, we get:
Density of B = (220 - 180) / 100 = 0.4 g/cm³
Therefore, the density of liquid B is 0.4 g/cm³.
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Mrs vilakazi is a retired consumer studies educator .she owns a small business of selling different types of cakes including scones.the cost price for ingredients plus water and electricity is r0,53 per scone .she sells scones at r2 ,00 each . calculate the profit mrs vilakazi will make if she bakes 204 scones and sells 171.
Mrs. Vilakazi will make a profit of r233,88 if she bakes 204 scones and sells 171.
The profit is the difference between the total revenue and the total cost.
The total cost is the cost per scone multiplied by the number of scones baked:
total cost = r0,53/scone × 204 scones = r108,12
The total revenue is the selling price per scone multiplied by the number of scones sold:
total revenue = r2,00/scone × 171 scones = r342,00
Therefore, the profit is:
profit = total revenue - total cost
profit = r342,00 - r108,12
profit = r233,88
Mrs. Vilakazi will make a profit of r233,88 if she bakes 204 scones and sells 171.
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Pls help immediately, and explain…
I did not do it correct pls help
Answer: x=20 y=43
Step-by-step explanation:
That little symbol in <1 means that the angle is a right angle, which is = to 90° so
<1 = 90°
133-y = 90 solve for y by subtracting 133 from both sides
-y = -43 divide by -1 on both sides
y=43
Because all 3 angles make a line, which is 180, and you know <1 = 90 then <2+<3=90 as well.
<2+<3=90
22 + x + 48 =90 simplify
70 + x =90 subtract 70 from both sides
x=20
Consider a point with rectangular coordinates (x,y).
if x<0 then the polar coordinates of the point are (r,θ) where r≥0 and −π/2≤θ<3π/2and:
r=
θ=
if x≥0 then the polar coordinates of the point are (r,θ) where r≥0 and −π/2≤θ<3π/2 and:
r=
θ=
Polar coordinates for rectangular coordinates if x<0: r=√(x²+y²) and θ=tan⁻¹(y/x)+π if y≥0 or θ=tan⁻¹(y/x)−π if y<0, For x≥0: r=√(x²+y²) and θ=tan⁻¹(y/x) if y≥0 or θ=tan⁻¹(y/x)+2π if y<0.
The polar coordinates of a point with rectangular coordinates (x,y) depend on the sign of x.
If x<0, the polar coordinates are (r,θ) where r≥0 and −π/2≤θ<3π/2. If x≥0, the polar coordinates are (r,θ) where r≥0 and −π/2≤θ<3π/2.
If x<0, t
hen r=√(x²+y²) and
θ=tan⁻¹(y/x)+π if y≥0
or θ=tan⁻¹(y/x)−π if y<0.
The value of r is the distance from the origin to the point and θ is the angle between the positive x-axis and the line segment from the origin to the point.
If x≥0, then r=√(x²+y²) and θ=tan⁻¹(y/x) if y≥0 or θ=tan⁻¹(y/x)+2π if y<0.
In this case, θ is the angle between the positive x-axis and the line segment from the origin to the point, measured counterclockwise.
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The edge of a cube-shaped box is 1 yard long. Three students each made an observation about the box. • Janae said that the area of each face of the box is 9 square feet. • Archie said that the perimeter of each face of the box is 3 feet. • Gail said that the volume of the box is 1 cubic yard. Whose observations about the box are correct?
Gail's observations about the box is correct. According to the question the edge of a cube-shaped box is 1 yard.
Now convert the edge length to feet as : 1 yard = 3 feet.
On checking the observations:
1. According to Janae the area of each face is 9 square feet. Calculating the surface area of one face of the cube is given by:
Area = (edge length)² = (3 feet)² = 9 square feet.
Now, Total surface area = 6*9square feet= 54 square feet.
Hence Observations of Janae is not correct.
2. According to Archie perimeter of each face of the box is 3 feet. Calculating the perimeter of each face of the cube is given by:
Perimeter= 4 × (edge length)=4×1 yard= 4×3feet=12 feet
Hence Archie observation is not correct also.
3. According to Gail the volume of the box is 1 cubic yard.
The volume of a cube is given by:
volume= (edge length)³ = (1 yard)³ = 1 cubic yard.
Therefore Gail's observation is correct.
From all the above observations it can be concluded that only Gail's observation is correct.
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Round your answer to three decimal places. A car is traveling at 112 km/h due south at a point = kilometer north of an intersection. A police car 5 2 is traveling at 96 km/h due west at a point kilometer due east of the same intersection. At that instant, the radar in the police car measures the rate at which the distance between the two cars is changing. What does the radar gun register? km/h Round your final answers to four decimal places if necessary. Suppose that the average yearly cost per item for producing x items of a business product is 94 C(x) = 11 + The three most recent yearly production figures are given in the table. Year 012 Prod. (x) 7.2 7.8 8.4 Estimate the value of x'(2) and the current (year 2) rate of change of the average cost. x'(2) = ; The rate of change of the average cost is per year. Plate A baseball player stands 5 meters from home plate and watches a pitch fly by. In the diagram, x is the distance from the ball to home plate and is the angle indicating the direction of the player's gaze. Find the rate e' at which his eyes must move to watch a fastball with x'()=-45 m/s as it crosses home plate at x = 0. 05 Player O'= rad/s. Round your answers to the three decimal places. Repo A dock is 1 meter above water. Suppose you stand on the edge of the dock and pull a rope attached to a boat at the constant rate of a 1 m/s. Assume the boat remains at water level. At what speed is the boat approaching the dock when it is 10 meters from the dock? 15 meters from the dock? Isn't it surprising that the boat's speed is not constant? Guid At 10 meters.x'= at 15 meters x'=
The instant when the radar gun is used, the rate at which the distance between the two cars is changing is g'(t) = 7968t + 368/5 kilometers per hour.
Let's break down the problem. We have two cars, one traveling south at 112 km/h and another traveling west at 96 km/h. The police car is stationed at an intersection and the two cars are at different points relative to the intersection. The first car is 4/5 kilometer north of the intersection while the second car is 2/5 kilometer east of the intersection.
Let's call this distance "d". Using the Pythagorean theorem, we can write:
d² = (4/5)² + (2/5)² d² = 16/25 + 4/25 d² = 20/25 d = sqrt(20)/5 d = 2sqrt(5)/5 kilometers
Now, we need to find the rate at which the distance between the two cars is changing. This is equivalent to finding the derivative of the distance with respect to time. Let's call this rate "r".
To find "r", we need to use the chain rule. The distance between the two cars is a function of time, so we can write:
d = f(t)
where t is time. We can then write:
r = d'(t) = f'(t)
where d'(t) and f'(t) denote the derivatives of d and f with respect to time, respectively.
To find f'(t), we need to express d in terms of t. We know that the first car is traveling at a constant speed of 112 km/h due south. Let's call the position of the first car "x" and the time "t". Then we have:
x = -112t
The negative sign indicates that the car is moving south. Similarly, we can express the position of the second car in terms of time. Let's call the position of the second car "y". Then we have:
y = 96t
The positive sign indicates that the car is moving west.
Now, we can use these expressions to find the distance between the two cars as a function of time. Let's call this function "g(t)". Then we have:
g(t) = √((x + 4/5)² + (y - 2/5)²) g(t) = √((-112t + 4/5)² + (96t - 2/5)²)
To find g'(t), we need to use the chain rule. We have:
g'(t) = (1/2)(x + 4/5)'(x + 4/5)'' + (y - 2/5)'x(y - 2/5)''
where the primes denote derivatives with respect to time. We can simplify this expression by noting that x' = -112 and y' = 96. We also have x'' = y'' = 0, since the speeds of the two cars are constant.
Substituting these values, we get:
g'(t) = -112x(-112t + 4/5)/√((-112t + 4/5)² + (96t - 2/5)²) + 96x(96t - 2/5)/√((-112t + 4/5)² + (96t - 2/5)²)
Simplifying this expression, we get:
g'(t) = (-112x(-112t + 4/5) + 96x(96t - 2/5))/√((-112t + 4/5)² + (96t - 2/5)²)
We can further simplify this expression by multiplying out the terms in the numerator:
g'(t) = (-12544t + 560/5 + 9216t - 192/5)/√((-112t + 4/5)² + (96t - 2/5)²)
g'(t) = (7968t + 368/5)/√((-112t + 4/5)² + (96t - 2/5)²)
g'(t) = 7968t + 368/5
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Complete Question:
A car is traveling at 112 km/h due south at a point 4/5 kilometer north of an intersection_ police, the car Is traveling at 96 km/h due west to at point 2/5 kilometer due cust of the same intersection. At that instant; the radar in the police car measures the rate at which the distance between the two cars [ changing: What does the radar gun register?
h(x)=|2x|-8 domain and range
For the function "h(x) = |2x| - 8", the domain is (-∞, ∞) and the range is [-8, ∞).
The function h(x) = |2x| - 8 is defined for all real numbers x, so the domain of h(x) is the set of all real-numbers, or (-∞, ∞).
To find the range of the function, we determine set of all possible output values of function. Since the function involves the absolute value of 2x, the output can never be less than -8.
When "2x" is positive, |2x| = 2x. When 2x is negative, |2x| = -2x. This means that the function h(x) will have two branches depending on whether 2x is positive or negative.
⇒ When 2x is positive, h(x) = |2x| - 8 = 2x - 8. This branch of the function will have all non-negative values.
⇒ When 2x is negative, h(x) = |2x| - 8 = -2x - 8. This branch of the function will have all non-positive values.
Combining the two , we get the range of the function h(x) as [-8, ∞).
Therefore, the domain of h(x) is (-∞, ∞) and the range of h(x) is [-8, ∞).
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A basketball coach thinks that as his team progresses through the season, his players are not scoring as many points as they were in the previous weeks. He uses a table to record the number of points that his team scores for the first ten weeks of the season. First drop down box answers( positive,negative, or no correlation) second drop down box (correct or incorrect)
The correlation between the number of points scored by the basketball team and the weeks of the season is likely negative.
However, without seeing the actual data, it is difficult to determine the exact correlation. As for the coach's statement, it could be either correct or incorrect depending on the actual data. Based on the given information, the basketball coach's observation suggests a negative correlation between the number of weeks into the season and the points scored by his team. Without the actual data, it is impossible to determine if his observation is correct or incorrect.
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Use the scatter plot to fill in the missing coordinate of the ordered pair.(,12)
Answer: Pairs (0, 14) and (10, 0
Step-by-step explanation:
Solve for f(-2).
f(x) = -3x + 3
4
f(-2) = [?]
Answer:
f(-2) = 9
Step-by-step explanation:
f(x) = -3x + 3 Solve for f(-2)
f(-2) = -3(-2) + 3
f(-2) = 6 + 3
f(-2) = 9
Peter picks one bill at a time from a bag and replaces it,
He repeats this process 100 times and records the results in
the table.
Peter's Experiment
Value Frequency
$1 28
14
$10 56
$20 2
Based on the table, which bill has an experimental
probability of 3 for being drawn from the bag next?
None of the bills have an experimental probability of 3, as all probabilities are between 0 and 1.
Based on the table, the experimental probability for each bill being drawn from the bag next can be calculated by dividing the frequency of each bill by the total number of draws (100). Using this formula, we can calculate the experimental probabilities for each bill:
1. For the $1 bill: Experimental probability = [tex]\frac{(Frequency of $1 bill)}{Total draws} = \frac{8}{100} = 0.28[/tex]
2. For the $10 bill: Experimental probability =[tex]\frac{(Frequency of $10 bill)}{Total draws} = \frac{56}{100} = 0.56[/tex]
3. For the $20 bill: Experimental probability =[tex]\frac{(Frequency of $20 bill)}{Total draws} = \frac{2}{100} = 0.02[/tex]
None of the bills have an experimental probability of 3, as all probabilities are between 0 and 1.
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One day, Bill at the candy shop sold 210 bottles of cherry soda and grape
soda for a total of $230. 30. If the cherry soda costs $1. 15 and the grape
soda costs $0. 99, how many of each kind were sold?
Bill sold 140 bottles of cherry soda and 70 bottles of grape soda.
Let's assume that x is the number of bottles of cherry soda sold and y is the number of bottles of grape soda sold. We can set up a system of equations to represent the given information:
x + y = 210 (equation 1: the total number of bottles sold is 210)
1.15x + 0.99y = 230.30 (equation 2: the total cost of the sodas is $230.30)
We can use the first equation to solve for y in terms of x:
y = 210 - x
Substituting this expression for y into the second equation, we get:
1.15x + 0.99(210 - x) = 230.30
Simplifying and solving for x, we get:
1.15x + 207.9 - 0.99x = 230.30
0.16x = 22.4
x = 140
So Bill sold 140 bottles of cherry soda. Substituting this value into equation 1, we get:
140 + y = 210
y = 70
Therefore, Bill sold 140 bottles of cherry soda and 70 bottles of grape soda.
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The ages of the 5 officers for a school club are 18, 18, 17, 16, and 15. The proportion of officers who are younger
than 18 is 0. 6. The table displays all possible samples of size 2 and the corresponding proportion for each sample,
17, 16
17, 15
16
1
1
1
Sample n = 2 18, 18 18, 17 18, 17 18, 16 18, 16 18, 15 18, 15
Sample
0 0. 5 0. 5 0. 5 0. 5 0. 5 0. 5
Proportion
Using the proportions in the table, is the sample proportion an unbiased estimator?
Yes, the sample proportions are calculated using samples from the population.
Yes, the mean of the sample proportions is 0. 6, which is the same as the population proportion.
No, 0. 6 is not one of the possible sample proportions.
No, 70% of the sample proportions are less than or equal to 0. 5.
The correct answer is option 2. Yes, the mean of the sample proportions is 0.6, which is the same as the population proportion.
To determine if the sample proportion is an unbiased estimator, we need to check if the mean of the sample proportions equals the population proportion. In this case, the population proportion of officers who are younger than 18 is given as 0.6. The sample proportions for all possible samples of size 2 are calculated and given in the table.
To calculate the mean of the sample proportions, we add up all the proportions in the table and divide by the total number of samples, which is 9.
Mean of sample proportions = (0 + 0.5 + 0.5 + 0.5 + 0.5 + 0.5 + 1 + 1 + 1) / 9 = 0.6
Since the mean of the sample proportions equals the population proportion, we can say that the sample proportion is an unbiased estimator.
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Escribe a cuáles de las bolsas anteriores corresponde la notación decimal aproximada a tres cifras
6.2 × 10⁴ in decimal notation is simply 62,000.
In scientific notation, a number is expressed as the product of a decimal number between 1 and 10 and a power of 10.
Now, let's talk about converting a number in scientific notation to decimal notation. Decimal notation simply means expressing a number in the standard way, using digits and a decimal point. To convert a number in scientific notation to decimal notation, we just need to evaluate the product of the decimal number and the power of 10.
In the case of 6.2 × 10⁴, the decimal number is 6.2, and the power of 10 is 4. To evaluate the product, we simply move the decimal point in 6.2 four places to the right, since the power of 10 is positive. This gives us:
6.2 × 10⁴ = 62,000
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Complete Question:
Convert to decimal notation: 6.2 × 10⁴
If represents 10%, what is the length of a line segment that is 100%? Explain.
Proportionately, if 8 cm represents 10%, the length of a line segment that is 100% is 80 cm.
What is proportion?Proportion is the ratio of two quantities equated to each other.
Proportion also represents the portion or part of a whole.
Proportions can be represented using decimals, fractions, or percentages, like ratios.
The percentage of 8 cm length = 10%
The whole length = 100%
Proportionately, 100% = 80 cm (8 ÷ 10%) or (8 x 100 ÷ 10)
Thus, we can conclude that 100% of the line segment will be 80 cm if 8 cm is 10%.
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Complete Question:If 8 cm represents 10%, what is the length of a line segment that is 100%? Explain.
Evaluate the definite integral:
∫(e^z) + 8/ (e^z+8z)^2
The definite integral
[tex]-e^(2z)/u + 16e^z/u - 64ln(u)/u + C[/tex]
To evaluate this definite integral, we need to find the antiderivative of the integrand and evaluate it at the limits of
integration.
Let's start by using u-substitution:
Let [tex]u = e^z+8z[/tex]
Then [tex]du/dz = e^z+8[/tex]
And [tex]dz = 1/e^z+8 du[/tex]
Substituting this into the integral, we get:
[tex]∫(e^z) + 8/ (e^z+8z)^2 dz[/tex]
= [tex]∫(1/u^2)(e^z+8)^2 du[/tex]
= [tex]∫(1/u^2)(e^(2z)+16e^z+64) du[/tex]
= [tex]-e^(2z)/u + 16e^z/u - 64ln(u)/u + C[/tex]
Now we need to evaluate this antiderivative at the limits of integration.
Let's assume the limits are a and b:
= [tex][-e^(2b)/(e^b+8b) + 16e^b/(e^b+8b) - 64ln(e^b+8b)/(e^b+8b)] - [-e^(2a)/(e^a+8a) + 16e^a/(e^a+8a) - 64ln(e^a+8a)/(e^a+8a)][/tex]
Simplifying this expression is not easy, but it can be done with some algebraic manipulation.
Therefore, The definite integral
[tex]-e^(2z)/u + 16e^z/u - 64ln(u)/u + C[/tex]
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find the limit of the sequence \displaystyle a_n = \frac{(\cos n)}{7^n}.
The limit of the sequence a_n is 0. The sequence a_n = (cos n)/[tex]7^n[/tex] oscillates between -1/[tex]7^n[/tex] and 1/[tex]7^n[/tex] since the cosine function is bounded between -1 and 1. Therefore, by the squeeze theorem, the limit of the sequence is 0 as n approaches infinity.
The cosine function oscillates between -1 and 1, so we have:
-1/[tex]7^n[/tex] ≤ cos(n)/7^n ≤ 1/[tex]7^n[/tex]
Dividing each term by [tex]7^n[/tex], we obtain:
-1/[tex]7^n[/tex] ≤ a_n ≤ 1/[tex]7^n[/tex]
By the squeeze theorem, since -1/[tex]7^n[/tex] and 1/[tex]7^n[/tex] both approach zero as n approaches infinity, we have:
lim a_n = 0
Therefore, the limit of the sequence a_n is 0.
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The volume of a large is 210 It is 5 3/5 wide and 3 1/3 high. What is the length of the ?
Answer:
11.86 units
Step-by-step explanation:
Volume = length x width x height
We know that the volume is 210 and the width is 5 3/5 (or 5.6) and the height is 3 1/3 (or 3.33).
Substituting these values into the formula, we get:
210 = length x 5.6 x 3.33
To solve for the length, we can divide both sides of the equation by (5.6 x 3.33):
length = 210 / (5.6 x 3.33)
Simplifying this expression, we get:
length ≈ 11.86
Therefore, the length of the large box is approximately 11.86 units.
The short leg of a triangle measures 17 and the long leg measures 32. What is the measure of the smaller acute angle of the triangle to the nearest tenth of a degree ? Draw a triangle to represent the problem. Be sure to show the trig equation you used when solving
The measure of the smaller acute angle of the triangle to the nearest tenth of a degree is 28.3 degrees.
Let's denote the smaller acute angle of the triangle as θ. We can use the tangent function to find the measure of this angle:
tan(θ) = opposite/adjacent
In this case, the opposite side is the length of the short leg (17) and the adjacent side is the length of the long leg (32). So we have:
tan(θ) = 17/32
Using a calculator, we can take the inverse tangent (tan^-1) of both sides to solve for θ:
θ = tan^-1(17/32) ≈ 28.3 degrees
So the measure of the smaller acute angle of the triangle is approximately 28.3 degrees.
Here's a diagram to illustrate the triangle:
/ l
/ l
17 / l opposite
/ l
/ θ l
/_______l
adjacent
32
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 A customer is comparing the size of oil funnels in a store. The funnels are cone shaped. One funnel has a base with a diameter of 8 in. And a slant height of 12 in. What is the height of the funnel? Round your answer to the nearest hundredth. 
The height of the funnel is 11.31, under the condition that one funnel has a base with a diameter of 8 in. And a slant height of 12 in.
Here we have to apply the Pythagorean theorem to evaluate the height of the funnel. The Pythagorean theorem projects that the square of the hypotenuse (the slant height) is equal to the sum of the squares of the other two sides (the radius and height).
Now, we have a cone that has a base diameter of 8 inches which says that the radius is 4 inches. The slant height is 12 inches. Then the height is
h² + r² = l²
h² + 4² = 12²
h² = 144 - 16
h² = 128
h = √(128)
h ≈ 11.31
Hence, 11.31 inches is the approximate height of the funnel after rounding to the nearest hundredth.
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12. reasoning a rectangular piece of cardboard with dimensions 5 inches
by 8 inches is used to make the curved side of a cylinder-shaped
container. using this cardboard, what is the greatest volume the cylinder
can hold? explain.
answer asap
If a rectangular piece of cardboard with dimensions 5 inches by 8 inches is used to make the curved side of a cylinder-shaped container, the greatest volume the cylinder can hold is 80/π cubic inches.
To find the greatest volume the cylinder can hold, we need to determine the dimensions of the cylinder that can be made from the given cardboard.
First, we need to calculate the circumference of the cylinder using the length of the cardboard, which will be the height of the cylinder. The length of the cardboard is 8 inches, so the circumference of the cylinder will be 8 inches.
The circumference of a cylinder is given by the formula C = 2πr, where r is the radius of the cylinder.
Therefore, 8 = 2πr, or r = 4/π inches.
Next, we need to determine the length of the curved side of the cylinder, which is given by the formula L = 2πr.
So, L = 2π(4/π) = 8 inches.
Finally, we can calculate the volume of the cylinder using the formula V = πr²h, where h is the height of the cylinder, which is 5 inches.
V = π(4/π)²(5) = 80/π cubic inches.
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What is half way between 4/5 and 14/15 in its simpelest form
Half way between 4/5 and 14/15 is 13/15.
To find the halfway point between 4/5 and 14/15, we need to calculate the average of the two fractions. Here's the process:
1. Make sure the fractions have a common denominator. In this case, the least common denominator (LCD) for 5 and 15 is 15.
2. Convert the fractions to equivalent fractions with the common denominator: 4/5 becomes 12/15 (multiply both numerator and denominator by 3), while 14/15 stays the same.
3. Add the two equivalent fractions together: 12/15 + 14/15 = 26/15.
4. Divide the sum by 2 to find the halfway point: (26/15) ÷ 2. To divide a fraction by a whole number, multiply the fraction by the reciprocal of the whole number: 26/15 × 1/2 = 26/30.
5. Simplify the resulting fraction: 26/30 can be simplified by dividing both numerator and denominator by their greatest common divisor (GCD), which is 2 in this case. Thus, 26 ÷ 2 = 13, and 30 ÷ 2 = 15. The simplified fraction is 13/15.
So, the halfway point between 4/5 and 14/15 in its simplest form is 13/15.
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The temperature rose 9 degrees
between 11:00 A. M. And 4:00 P. M.
yesterday. The temperature at 4:00 P. M.
was 87°F. Xin Xin used the following
equation to find the temperature tat
11:00 A. M.
[ + 9 = 87
What was the temperature at
11:00 AM. ?
The temperature at 11:00 A.M. yesterday was 78°F.
To find the temperature at 11:00 A.M., we need to subtract 9 from the temperature at 4:00 P.M. because the temperature rose 9 degrees between those times. So, we can use the following equation:
Temperature at 11:00 A.M. = Temperature at 4:00 P.M. - 9
We know that the temperature at 4:00 P.M. was 87°F, so we can substitute that into the equation and solve for the temperature at 11:00 A.M.:
Temperature at 11:00 A.M. = 87 - 9
Temperature at 11:00 A.M. = 78°F
Therefore, the temperature at 11:00 A.M. yesterday was 78°F.
It's important to remember that when solving word problems like this, we need to pay close attention to the details and make sure we understand what the question is asking us to find. In this case, we needed to use the information given about the temperature rising 9 degrees between 11:00 A.M. and 4:00 P.M. to find the temperature at 11:00 A.M. By using the equation provided and substituting in the known values, we were able to solve for the unknown temperature at 11:00 A.M.
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QUESTION 3 2 - 1 Let () . Find the interval (a,b) where y increases. As your answer please input a+b QUESTION 4 Let(x) = xº - 6x3 - 60x2 + 5x + 3. Find all solutions to the equation f'(x) = 0. As your answer please enter the sum of values of x for which f() -
The interval where y increases for the function f(x) = (4x² - 1)/(x² + 1) is (-∞, -0.5) U (0.5, ∞) is 0.5-(-∞) = ∞.
To find the intervals where the function f(x) = (4x² - 1)/(x² + 1) increases, we need to find its derivative and determine its sign. The derivative of f(x) can be found using the quotient rule:
f'(x) = [(8x)(x² + 1) - (4x² - 1)(2x)]/(x² + 1)²
Simplifying this expression, we get:
f'(x) = (12x - 4x³)/(x² + 1)²
To find the critical points, we need to solve the equation f'(x) = 0:
12x - 4x³ = 0
4x(3 - x²) = 0
This gives us the critical points x = 0 and x = ±√3. We can now test the intervals between these critical points to determine the sign of f'(x) in each interval.
Testing x < -√3, we choose x = -4, and we get f'(-4) = (-224)/(17²) < 0. Therefore, f(x) is decreasing on this interval.
Testing -√3 < x < 0, we choose x = -1, and we get f'(-1) = (16)/(2²) > 0. Therefore, f(x) is increasing on this interval.
Testing 0 < x < √3, we choose x = 1, and we get f'(1) = (16)/(2²) > 0. Therefore, f(x) is increasing on this interval.
Testing x > √3, we choose x = 4, and we get f'(4) = (-224)/(17²) < 0. Therefore, f(x) is decreasing on this interval.
Hence, the interval where f(x) increases is (-∞, -0.5) U (0.5, ∞). Therefore, the answer is 0.5 - (-∞) = ∞.
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(1 point) Assuming that y is a function of x, differentiate x^6y^9 with respect to x. dy Use D for dy/dx in your answer. d/dx (x^6y^9) =
To differentiate x^6y^9 with respect to x, we will use the product rule. The product rule states that the derivative of a product of two functions is the derivative of the first function multiplied with the second function, plus the first function multiplied with the derivative of the second function.
Step 1: Identify the functions
Function 1 (u): x^6
Function 2 (v): y^9
Step 2: Find the derivatives
u' (du/dx): Differentiate x^6 with respect to x, which gives 6x^5
v' (dv/dx): Differentiate y^9 with respect to x, which gives 9y^8 * (dy/dx) = 9y^8D (since D = dy/dx)
Step 3: Apply the product rule
d/dx (x^6y^9) = u'v + uv'
= (6x^5)(y^9) + (x^6)(9y^8D)
= 6x^5y^9 + 9x^6y^8D
So, the derivative of x^6y^9 with respect to x is 6x^5y^9 + 9x^6y^8D.
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Find dy/dt at x = – 1 if y = – 2x^2 + 4 and dx/dt = 4. dy/dt =?
Derivative of y w.r.t t is dy/dt = 16 at x = -1.
How to find dy/dt?We need to find dy/dt at x = -1, given y = -2x² + 4 and dx/dt = 4.
Step 1: Differentiate y with respect to x.
Since y = -2x² + 4, we have:
dy/dx = -4x
Step 2: Substitute x = -1 into the dy/dx equation.
When x = -1, we get:
dy/dx = -4(-1) = 4
Step 3: Use the Chain Rule to find dy/dt.
The Chain Rule states that dy/dt = (dy/dx)(dx/dt). We know dy/dx = 4 and dx/dt = 4, so we have:
dy/dt = (4)(4) = 16
Thus, dy/dt = 16 at x = -1.
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THE ANSWER IS NOT 81!!!
The measures of the angles of a triangle are shown in the figure below solve for X
Find the gross income for selling 348 bushels of apples at 16.50 per bushel
The gross income for selling 348 bushels of apples at a price of $16.50 per bushel is $5,742.
The gross income is the total revenue earned from the sales of a product or service, before any expenses or deductions are taken out. To calculate gross income, we multiply the quantity of goods sold by the price per unit.
In this case, we are given that 348 bushels of apples were sold at a price of $16.50 per bushel. Multiplying these two values together gives us the total revenue earned from the sale of these apples, which is the gross income.
To calculate the gross income, we can use the formula:
Gross income = Quantity sold x Price per unit
Plugging in the given values, we get:
Gross income = 348 x $16.50
Simplifying the calculation, we get:
Gross income = $5,742
Therefore, the gross income for selling 348 bushels of apples at a price of $16.50 per bushel is $5,742.
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