urgent help needed algebra 2

Answer:

Step-by-step explanation:

volume of a cuboid = Length × Width × Height Cubic units

6 × 11 × 6 =

66 * 6 =

396 Km³

to the nearest hundred

400 Km³

Answer:

x = 7

Step-by-step explanation:

3(x - 4) - 5 = x - 3

3x - 12 - 5 = x - 3

2x = -3 + 12 + 5

2x = 14

x = 7

The length of the box made by Mr. Baker is 10-inch

Mr. Baker has strip of 48- inch long  oak, by this strip he is making the rectangle box of width 14-inch.

The rectangle is 4 sided geometric shapes whose opposites are equal in lengths and all angles are about 90°.

As Mr. Baker has a strip that is 48-inch long and he made a rectangle box with it.

The width of the  box = 14 inches
now the length of the box = (total length of the strip - 2* width of the box)/2
⇒ length of the box = (48 - 2*14)/2
⇒ length of the box = 10 inches

Thus the Mr. Baker made the box which is 10 inches long.

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Answer: Rectangles

Step-by-step explanation:

Whenever rectangles are rotated about an axis, a cylinder is formed.

Answer:

1. santina drove 14 more miles than carole

2. the owner will need to buy 8 bags this week

Step-by-step explanation:

1. 203-189= 14

2. if they use 80 pounds a week and can only buy 10 pounds in one bag, they'll need 8 bags to equal 80 pounds since each bag is 10 pounds

1. 14

2. 8

3. 48

4. 318

5. 23

6. 4

7. a) 10 b) 60 c) 8 d) 107

8. $1,532

9. 1

10. $15.50

11. .95

Step-by-step explanation:

Answer:

-2

Step-by-step explanation:

-9/3=-3

-3+b=-1

b=-1+3

b=-2

244x3+1474x2+63x/

x+6

Answer: 6x+12

Step-by-step explanation: Both denominators can be multiplied to create 6x + 12.

2x + 4

2x(3) + 4(3)

6x+12

3x + 6

3x(2) + 6(2)

6x+12

I hope this helps!

Answer:

The answer will be 30.625 m

Answer:

17

Step-by-step explanation:

→ Substitute 7 f(x) into the function

7 + 10

→ Solve

17

Answer:

f(7) = 17

Step-by-step explanation:

To find f(7), substitute x = 7 in the function. Thus, you will receive:

[tex]\displaystyle{f(7)=7+10}\\\\\displaystyle{f(7)=17}[/tex]

Henceforth, the value of f(7) is 17.

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The average rate of change = 109%

Rate of Change is the measure of the increase or decrease in the value with respect to the initial value.

It is given that

No of clown sold in 2010 = 11

No of clown sold in 2015 = 23

The average rate of change  = ((23-11)/11 ) *100 %

The average rate of change = 109%

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Answer:

f(x) = square root of x

g(x) = 4x - 1

Step-by-step explanation:

Answer:

1 HR ---> 42 km

? .----> 119 km

119 * 1/42

2.833

Answer:

[tex]\boxed {2 \frac{5}{6}}[/tex]

Step-by-step explanation:

Formula used :

[tex]\boxed {Time = \frac{Distance}{Speed}}[/tex]

Solving :

Time = 119/42

Time = 17/6

Time = 2 5/6 hours

By applying the theory of separable ordinary differential equations we conclude that the solution of the differential equation [tex]\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0[/tex] with y(0) = e is [tex]y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}[/tex].

In this question we must separate each variable on each side of the equivalence, integrate each side of the expression and find an explicit expression (y = f(x)) if possible.

[tex]\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0[/tex]

[tex](\ln y)^{2}\,dy = -y \cdot \sqrt{x}\, dx[/tex]

[tex]-\frac{(\ln y)^{2}}{y}\, dy = \sqrt{x} \,dx[/tex]

[tex]-\int {\frac{(\ln y)^{2}}{y} } \, dy = \int {\sqrt{x}} \, dx[/tex]

If u = ㏑ y and du = dy/y, then:

[tex]-\int {u^{2}\,du } = \int {x^{\frac{1}{2} }} \, dx[/tex]

[tex]-\frac{1}{3}\cdot u^{3} = \frac{2\cdot x^{\frac{3}{2} }}{3} + C[/tex]

[tex]u^{3} = -2\cdot x^{\frac{3}{2} } + C[/tex]

[tex](\ln y)^{3} = - 2\cdot x^{\frac{3}{2} } + C[/tex]

[tex]C = (\ln e)^{3}[/tex]

[tex]C = 1[/tex]

And finally we get the explicit expression:

[tex]\ln y = \sqrt [3]{-2\cdot x^{\frac{3}{2} }+ 1}[/tex]

[tex]y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}[/tex]

By applying the theory of separable ordinary differential equations we conclude that the solution of the differential equation [tex]\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0[/tex] with y(0) = e is [tex]y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}[/tex].

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Answer:

∠PQT = 97°

∠SQR = 83°

Step-by-step explanation:

Supplementary angles sum to 180°

⇒ ∠PQT + ∠SQR = 180°

Given:

Therefore:

⇒ (3x + 43) + (6x - 25) = 180

⇒ 3x + 6x + 43 - 25 = 180

⇒ 9x + 18 = 180

⇒ 9x = 162

⇒ x = 18

Substitute the found value of x into the expression for each angle:

⇒ ∠PQT = (3x + 43)°

⇒ ∠PQT = (3(18) + 43)°

⇒ ∠PQT = 97°

⇒ ∠SQR = (6x - 25)°

⇒ ∠SQR = (6(18) - 25)°

⇒ ∠SQR = 83°

Check

⇒ ∠PQT + ∠SQR = 97° + 83° = 180°

The foci of the hyperbola represented by (0, –6) and (0, 6). Then the correct option is B.

The hyperbola is the locus of a point such that the difference of distance from point P to two non-movable points. These two points are called foci of hyperbola.

The equation of the parabola is given below.

5y² – 4x² – 80 = 0

Then the equation can be written as

y² / 4 – x² / 5 – 4 = 0

  y² / 16 – x² / 20 = 1

Then the value of eccentricity will be

a² = 16 and b² = 20

Then we have

e = √[1 + (b² / a²)]

e = √[1 + (20 / 16)]

e = 1.5

Then the focus of the parabola will be

⇒ (0, ±ae)

⇒ (0, ± 4 x 1.5)

⇒ (0, ±6)

⇒ (0, –6) and (0, 6)

Then the correct option is B.

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Answer:

Step-by-step explanation:

The domain includes all x values, and here, it is [-2, 4].

Answer: 2 3/4 > 2.68 is correct (only)

Step-by-step explanation: 2 3/4 = 2.75, and 2.75 is greater than 2.68

The rest are incorrect. 7.895 * 10^2 (100) = 789.5, and 5.43 * 10^3 (1000) = 5430. So 789.5 > 5430 is false.

Sqrt(63) = 7.93, and 7.93 > 8.11 is false.

Absolute values ( | | ) mean that no matter if it is negative or positive, it will become positive (unless the negative sign is outside the absolute value). 1.5 > 3.2 is false, and even without the absolute value, -1.5 is still less than 3.2

A set is a mathematical model for a collection of items. The set of W' is {5, 20, 30}.

A set is a mathematical model for a collection of items; it comprises elements or members, which may be any mathematical object: numbers, symbols, points in space, lines, other geometrical structures, variables, or even other sets.

The complete question is given below.

Q13.

T ∪ V = Data points that are in T or V or both.

T ∪ V = {5, 10, 20, 30}

Q14.

T ∩ W = Data points that are in T and W both.

T ∩ W = {10}

Q15.

W' = Data points that are not in W.

W' = {5, 20, 30}

Hence, the set of W' is {5, 20, 30}.

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The point on the number line represents the product (- 4), (- 2), and (- 1) will be the negative 8. Then the correct option is A.

It is also known as the product. If the object n is given to m times, then we just simply multiply them.

The point on the number line represents the product (- 4), (- 2), and (- 1) will be

Then the product will be

-4 x -2 x -1 = -8

Then the correct option is A.

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Answer:

all over the world

Step-by-step explanation:

use g00g!e maps

Answer:

Not in Russia

Step-by-step explanation:

McDonald's left Russia following the violations of human rights

Answer:

Step-by-step explanation:

Remark. Since 6 has a decimal after it, I take it that is the question number.

y = 16x is the basic formula. x starts at 0. Then you add 16 to each number to get the next number in the sequence. Or you could do it the way I propose it.

x      0     1      2     3     4     5     6     7

y      0     16   32   48   64   80  96  112

The attached graph represents the piecewise function.

The complete question is in the image

The function is given as:

[tex]f(x) = \left[\begin{array}{cc}3&x \le -3\\2x + 1&-3 < x < 4 \\-2&x \ge 4\end{array}\right[/tex]

Next, we plot the functions by their domain

See attachment for the piecewise function.

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The graphed trigonometric function is the one in option a.

The key parts that we can see on the graph are:

From this we know that the correct option is either a or b.

Now we can evaluate options a and b in x = 0 and see which one is equal to zero.

for a:

y = sin(0 - pi/2) + 1 = sin(-pi/2) + 1 = -1 + 1 = 0

for b:

y = cos(0 + pi/2) + 1 = 0 + 1 =  1

Then we can see that option a is the correct option.

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our system of inequalities is:

x + y ≤ 13.

x*$15 + y*$10 ≥ $180.

The graph can be seen at the end.

Here we have the variables:

We know that she can only work 13 hours per week, then we have:

x + y ≤ 13.

And she wants to earn at least $180 per week, then:

x*$15 + y*$10 ≥ $180.

So our system of inequalities is:

x + y ≤ 13.

x*$15 + y*$10 ≥ $180.

The graph of the system can be seen below. The solution set is defined by the zone where the two shaded regions intersect (where we also should add the restrictions x >0, y > 0).

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Answer:

okay so I can't see the last option on ur sheet but when u graph this equation the point that lies on the curve is (2,-3) so that is the vertex but if I move up this curved line it passes through the Y axis at (0,-1), the Last answer that I can't see it wouldn't happen to be (-1,6) would it

Answer:

y=55x

Step-by-step explanation:

(y1-y2)/(x1-x2)=(165-55)/(3-1)=55

55 is the slope

To find y-intercept:

y=55x+b

substitute 1 for x and 55 for y

55=55(1)+b

b=0

So y= 55x

the equation of the line passing through the points (3, 165) and (1, 55) is y = 55x. To write the equation of the line that passes through the points (3, 165) and (1, 55), you can use the point-slope form of a linear equation, which is: y - y₁ = m(x - x₁)

where (x₁, y₁) is one of the points on the line, m is the slope of the line.

First, calculate the slope (m) using the given points (3, 165) and (1, 55):

m = (y₂ - y₁) / (x₂ - x₁) = (55 - 165) / (1 - 3) = (-110) / (-2) = 55

Now that you have the slope (m = 55) and one of the points (let's use (3, 165)), you can plug them into the point-slope form:

y - 165 = 55(x - 3)

Now, you can simplify and rewrite this equation in slope-intercept form (y = mx + b):

y - 165 = 55x - 165

To isolate y, add 165 to both sides:

y = 55x

So, the equation of the line passing through the points (3, 165) and (1, 55) is y = 55x.

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The preparation of the journal entry to record the accounting transaction can be seen in the table below.

Initially, when preparing a journal, you have to read the transaction carefully and comprehend it. Discover which accounts need to be credited and debited before entering a journal entry.

From the given information:

The common stock par value = no of shares × par value of shares

The common stock par value = 4000 shares × $5/ share

The common stock par value = $20000

However, the amount paid in capital excess of the par value for the common stock is:

= $35000 - $20000

= $15000

Therefore, the Journal entry can be computed as follows:

Date        Account Title                          Post Ref     Debit ($)    Credit ($)

             Cash                                                            35,000

        Paid-in capital in excess of par

       value, common stock                                                         20,000

       (To record the insurance of common stock)    

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