Tristan is building a triangular roof for his treehouse. He already has two pieces of lumber that measure 6 feet long. Select all of the following pieces of lumber that Tristan can to complete the triangular roof.
6/8/2/12/4/10/14

Answer: When two or more lines cross each other in a plane, they are called intersecting lines. The intersecting lines share a common point, which exists on all the intersecting lines, and is called the point of intersection. Here, lines P and Q intersect at point O, which is the point of intersection.

I think this the answer‍♀️

Answer:

answer:250 pieces

1 metre=100cm so

10metres =100*10 =1000cm

each piece is 4 CM long, so.,

no. of pieces=1000/4

by dividing by 2....

=500/4

again by dividing by2...

=250/1=250 pieces

so 250 pieces of ribbon can be cuttted from 10 metre long ribbon.

Answer:

x = 7

angle (7x + 8) = 57 degrees

Step-by-step explanation:

all triangles interior angles add up to 180 degrees.

(7x+8) + 90 + 33 = 180

7x+8 = 57

7x = 49

x = 7

(7x + 8) = 57

Answer:

57 degrees

Step-by-step explanation:

7x+8+33=90

7x=90-8-33

=90-41

7x=49

x=7

Part (c)

We'll use this identity

[tex]\sin(x+y) = \sin(x)\cos(y) + \cos(x)\sin(y)\\\\[/tex]

to say

[tex]\sin(A+45) = \sin(A)\cos(45) + \cos(A)\sin(45)\\\\\sin(A+45) = \sin(A)\frac{\sqrt{2}}{2} + \cos(A)\frac{\sqrt{2}}{2}\\\\\sin(A+45) = \frac{\sqrt{2}}{2}(\sin(A)+\cos(A))\\\\[/tex]

Similarly,

[tex]\sin(A-45) = \sin(A + (-45))\\\\\sin(A-45) = \sin(A)\cos(-45) + \cos(A)\sin(-45)\\\\\sin(A-45) = \sin(A)\cos(45) - \cos(A)\sin(45)\\\\\sin(A-45) = \sin(A)\frac{\sqrt{2}}{2} - \cos(A)\frac{\sqrt{2}}{2}\\\\\sin(A-45) = \frac{\sqrt{2}}{2}(\sin(A)-\cos(A))\\\\[/tex]

-------------------------

The key takeaways here are that

[tex]\sin(A+45) = \frac{\sqrt{2}}{2}(\sin(A)+\cos(A))\\\\\sin(A-45) = \frac{\sqrt{2}}{2}(\sin(A)-\cos(A))\\\\[/tex]

Therefore,

[tex]2\sin(A+45)*\sin(A-45) = 2*\frac{\sqrt{2}}{2}(\sin(A)+\cos(A))*\frac{\sqrt{2}}{2}(\sin(A)-\cos(A))\\\\2\sin(A+45)*\sin(A-45) = 2*\left(\frac{\sqrt{2}}{2}\right)^2\left(\sin^2(A)-\cos^2(A)\right)\\\\2\sin(A+45)*\sin(A-45) = 2*\frac{2}{4}\left(\sin^2(A)-\cos^2(A)\right)\\\\2\sin(A+45)*\sin(A-45) = \sin^2(A)-\cos^2(A)\\\\[/tex]

The identity is confirmed.

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Part (d)

[tex]\sin(x+y) = \sin(x)\cos(y) + \cos(x)\sin(y)\\\\\sin(45+A) = \sin(45)\cos(A) + \cos(45)\sin(A)\\\\\sin(45+A) = \frac{\sqrt{2}}{2}\cos(A) + \frac{\sqrt{2}}{2}\sin(A)\\\\\sin(45+A) = \frac{\sqrt{2}}{2}(\cos(A)+\sin(A))\\\\[/tex]

Similarly,

[tex]\sin(45-A) = \sin(45 + (-A))\\\\\sin(45-A) = \sin(45)\cos(-A) + \cos(45)\sin(-A)\\\\\sin(45-A) = \sin(45)\cos(A) - \cos(45)\sin(A)\\\\\sin(45-A) = \frac{\sqrt{2}}{2}\cos(A) - \frac{\sqrt{2}}{2}\sin(A)\\\\\sin(45-A) = \frac{\sqrt{2}}{2}(\cos(A)-\sin(A))\\\\[/tex]

-----------------

We'll square each equation

[tex]\sin(45+A) = \frac{\sqrt{2}}{2}(\cos(A)+\sin(A))\\\\\sin^2(45+A) = \left(\frac{\sqrt{2}}{2}(\cos(A)+\sin(A))\right)^2\\\\\sin^2(45+A) = \frac{1}{2}\left(\cos^2(A)+2\sin(A)\cos(A)+\sin^2(A)\right)\\\\\sin^2(45+A) = \frac{1}{2}\cos^2(A)+\frac{1}{2}*2\sin(A)\cos(A)+\frac{1}{2}\sin^2(A)\right)\\\\\sin^2(45+A) = \frac{1}{2}\cos^2(A)+\sin(A)\cos(A)+\frac{1}{2}\sin^2(A)\right)\\\\[/tex]

and

[tex]\sin(45-A) = \frac{\sqrt{2}}{2}(\cos(A)-\sin(A))\\\\\sin^2(45-A) = \left(\frac{\sqrt{2}}{2}(\cos(A)-\sin(A))\right)^2\\\\\sin^2(45-A) = \frac{1}{2}\left(\cos^2(A)-2\sin(A)\cos(A)+\sin^2(A)\right)\\\\\sin^2(45-A) = \frac{1}{2}\cos^2(A)-\frac{1}{2}*2\sin(A)\cos(A)+\frac{1}{2}\sin^2(A)\right)\\\\\sin^2(45-A) = \frac{1}{2}\cos^2(A)-\sin(A)\cos(A)+\frac{1}{2}\sin^2(A)\right)\\\\[/tex]

--------------------

Let's compare the results we got.

[tex]\sin^2(45+A) = \frac{1}{2}\cos^2(A)+\sin(A)\cos(A)+\frac{1}{2}\sin^2(A)\right)\\\\\sin^2(45-A) = \frac{1}{2}\cos^2(A)-\sin(A)\cos(A)+\frac{1}{2}\sin^2(A)\right)\\\\[/tex]

Now if we add the terms straight down, we end up with [tex]\sin^2(45+A)+\sin^2(45-A)[/tex] on the left side

As for the right side, the sin(A)cos(A) terms cancel out since they add to 0.

Also note how [tex]\frac{1}{2}\cos^2(A)+\frac{1}{2}\cos^2(A) = \cos^2(A)[/tex] and similarly for the sin^2 terms as well.

The right hand side becomes [tex]\cos^2(A)+\sin^2(A)[/tex] but that's always equal to 1 (pythagorean trig identity)

This confirms that [tex]\sin^2(45+A)+\sin^2(45-A) = 1[/tex] is an identity

Answer:

I think no. Because degree is the sum all variables in first equation degree. Is14 but second equation degree not 14.

What is the answer?

here is the image

Polygon ABCD was dilated by a scale factor of 2 to create A'B'C'D'.

Dilation is the increase or decrease in the size of a figure by a scale factor of k, thereby creating an image.

From the diagram:

Scale factor = A'B' / AB = 6/3 = 2

Center = (6, -6)

Polygon ABCD was dilated by a scale factor of 2 to create A'B'C'D'.

Find out more on dilation at: https://brainly.com/question/10253650

9514 1404 393

Answer:

  No

Step-by-step explanation:

If the relationship were proportional, the ratio of y to x would be a constant.

  y/x = 3/1 ≠ 7/3

x and y are not proportional.

Answer:

25

Step-by-step explanation:

Do 400 divided by 16 to convert to pounds

400/16=25

Hope this helped :)

Answer:

25 pounds

Step-by-step explanation:

1 Pound=16 ounces

? Pounds=400 ounces

400 divided by 16=25

25 pounds=400 ounces

Answer:

2p should be the correct answer!

Answer:

2p is the answer

Step-by-step explanation:

I took the answer edg2021

Answer:no he misses the rate he needs to run by 30m seconds

Step-by-step explanation:

45/5=9

Answer: No because in 5 miles he needs to run for 42.5 minutes or less

Answer:

k = 8

Step-by-step explanation:

Given that y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 32 when x = 4, then

32 = 4k ( divide both sides by 4 )

8 = k

Answer:

Me too

Step-by-step explanation:

Answer: hello

your answer will be C

Step-by-step explanation:

Answer:

If Ron works 8 hours a day and get's paid $15 an hour

for 5 days a week and works for 12 weeks

1 hour = $15

8 hours = $120

So Ron get's paid $120 a day

So if he works 5 days a week then

120 x 5 = $600

Ron get's paid $600 a week

So if Ron works for 12 weeks then

600 x 12 = $7,200

Ron's gross pay is $7,200

Step-by-step explanation:

Answer:

3/8!! hope i helped :))

Answer:

c-a=b

Step-by-step explanation:

Answer:

Both sides that are parallel ( 6 inches I believe ) would be 12 in total for both sides. Then the top and bottom would be 3 inches ( I believe ) which would be 6. I think you need to do 6 times 12 until you get 360 and then see how many times you multiplied it and that is your answer. But I am not FULLY sure. Hope this helps somehow!

Step-by-step explanation:

Answer:

A is a concave polygon,....,.

Answer:

the answer will be A.

Step-by-step explanation:

Answer:

1 135

2 80

3 145

4 45

Step-by-step explanation:

Thats the answer

.

.

.

Answer:

First Answer is correct

Step-by-step explanation:

Answer:

Option A is the right one

Answer:

Step-by-step explanation:

A)8

Answer:

9

Step-by-step explanation:

because the FIM and LAK are similar, then

FI/LA=IM/AK=MF/KL

MF/KL=2/3

Answer:

x=4

Step-by-step explanation:

Answer:

28m

Step-by-step explanation:

Answer:

when x=-3 y=10

when x=0 y=4

when x=3 y=-2

Step-by-step explanation:

all you have to do is plug in -3 0 and 3 for x

-2(-3)=6

6+4=10 so when x=-3 y=10

-2(0)=0

0+4=4

so when x=0 y=4

-2(3)=-6

-6+4=-2

so when x=3 y=-2

Answer:

1

Step-by-step explanation:

Answer:

1 is missing

Step-by-step explanation:

As 4285 ÷ 7 = Quotient- 612 , Remainder - 1

Answer:

a

Step-by-step explanation:

Answer:

should be a hope it helps

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

90/1=90

140/2=70

190/3=63.3333333

240/4=60

so the first hour cost more than the others, hope this helps!