Triangle ABC is shown on the coordinate plane below . The triangle is reflected across the y - axis and then translated 3 units to the right to form triangle A'B'C ' .
PLEASEEE HURRRY

Answer:

perpendicular lines

Step-by-step explanation:

Kahn Academy

The given lines are intersecting but not perpendicular.

In Euclidean geometry, the empty set, a point, or another line can intersect another line. For instance, computer graphics, motion planning, and collision detection can all benefit from differentiating these cases and locating the intersection.

Given:

        y = 6x - 2

2x - 12y = 24

⇒  6x - y = 2         ..(1)

2x - 12y = 24       ..(2)

Multiply second equation by 3,

6x - 36y = 72           ..(3)

Subtract equation (1) from equation (3).

    6x - 12y = 24

-    6x -    y  = 2

_______________

         -11y = 22

   y = -2

Plug y = -2 in equation (1)

6x - (-2) = 2

6x + 2 = 2

      6x = 2 - 2

      6x = 0

        x = 0

The solution of the given system is (0, -2).

Hence, the given lines are intersecting but not perpendicular.

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complete question:

What do the following two equations represent?

.y=6x-2

.2x-12y=24

Answer:

AAS

Step-by-step explanation:

Two angles are equivalent and they share a side

Answer with step-by-step explanation:

Since you're calculating 1/6 of 2/3, you'd need to do 1/6 × 2/3, which would get you 1/9

Hope this helped!

Answer:

49 or 1

Step-by-step explanation:

answer 1 14+10+13+12=49 answer 2 (14+10)-(13+12)=1

Answer:

x = 6

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Answer:

[tex]\sqrt[/tex]3x+4=5

Step-by-step explanation:

3x+4=25

3x=21

x=7

Answer:

a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55

b)0.6004

c)19.607

Step-by-step explanation:

Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2

X ~ Poisson(A) where [tex]\lambda = \frac{10.2}{200} = 0.051[/tex]

a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar

[tex]\frac{1}{4} \times 200 = 50[/tex]

50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55

So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55

b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment

Let X denotes the number of grams to be eaten before another fragment is detected.

[tex]P(X>10)= e^{-\lambda \times x}= e^{-0.051 \times 10}= e^{-0.51}=0.6004[/tex]

c)The expected number of grams to be eaten before encountering the first fragments :

[tex]E(X)=\frac{1}{\lambda}=\frac{1}{0.051}=19.607 gram[/tex]s

Answer:

The sample space for selecting the group to test contains 2,300 elementary events.

Step-by-step explanation:

There are a total of N = 25 aluminum castings.

Of these 25 aluminum castings, n₁ = 4 castings are defective (D) and n₂ = 21 are good (G).

It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

[tex]{n\choose k}=\frac{n!}{k!(n-k)!}[/tex]

Compute the number of samples that are possible as follows:

[tex]{25\choose 3}=\frac{25!}{3!\times (25-3)!}[/tex]

      [tex]=\frac{25\times 24\times 23\times 22!}{3!\times 22!}\\\\=\frac{25\times 24\times 23}{3\times 2\times 1}\\\\=2300[/tex]

The sample space for selecting the group to test contains 2,300 elementary events.

Answer:

13 weeks

Step-by-step explanation:

it will take 13 weeks because 26 devided by 2 is 13.

Answer:

3⁷

Step-by-step explanation:

When you multiplying or dividing numbers with exponents, you keep the base the same and specifically with dividing, you subtract the exponents themselves. So, you would be doing 3-(-4), which is 7.

[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Exponents and power,

Since we know the concept that, any power in denominator of a fraction is shows as negative power when it comes to the Numerator of the fraction,like eg:-

[tex]1 \div ( {5}^{8} ) = {5}^{ - 8} [/tex]

so we apply here same,

also

[tex]1 \div ({5}^{ - 8} ) = {5}^{8} [/tex]

so we get as,

[tex] {3}^{3} \div {3}^{ - 4} = {3}^{3} \times {3}^{4} [/tex]

this is the answer.

Answer:

weak in maths sorry I cannot give answer

Answer:

Consider one of eight positions separately from all others. There are 10 possible ways to choose

a digit to place on this position since there are ten digits from 0 to 9, and this choice is

independent of all other positions since each digit can be repeated and there is no restriction on

how to choose digits.

So, we have 8 positions and each one is filled by a digit in 10 ways independently from each other,

therefore the total number of possible codes equals to ways it can be done for each independent

position multiplied altogether. This is 10 × 10 × … × 10 = 108

(100 million).

Answer: 108 different codes.

Step-by-step explanation:

Answer:

look im putting this here bc i have to answer 50 questionsfor a quest sdo dont report me ;-;

Step-by-step explanation:

Answer:

Step-by-step explanation:

hockey canada

Answer:

The puck changes direction at  

✔ (25, 0) .

The puck goes into the opponent’s score zone located at  

✔ (50, 20)

, because the graph is  

✔ symmetric .

Step-by-step explanation:

Answer:

YES

Step-by-step explanation:

ITS JUST YES

Answer:

the answer is 7.5

Answer:

B, it will float bc it is less dence. give me brainliest ;)

Step-by-step explanation:

Answer: −2x+y=−11

(4,-3) = −2x+y=−11.

Answer: −2x+y=−11.

Answer:

C. -2n² - n + 5

Step-by-step explanation:

In expression C, the coefficient of the n term is -1;

  The expression in choice C is given as:

               -2n² - n + 5

The coefficient is the number before a variable;

  For n², the coefficient is -2

    for n, the coefficient is -1

Answer:

Please find the correct placement in a tabular format in the attached image. The explanation has been done below.

Step-by-step explanation:

The process of photosynthesis occurs in two stages viz: light-dependent and light-independent reactions.

- In the light-dependent reaction, which occurs in the THYLAKOID MEMBRANE of the chloroplast, energy from SUNLIGHT is used to breakdown WATER to release electrons in order to synthesize ATP and NADPH from ADP and NADP+. In a nutshell, the processes involved in this stage are Electron transport chain, photosystem I, photosystem II, and ATP synthase.

- In the light-independent stage, also called CALVIN CYCLE, the ATP, NADPH, and CO2 are used as reactants to synthesize SUGAR (glucose), NADP+ and ADP (which goes back to the first stage) as products.

Answer:

[tex]A = (32.7,47.7)[/tex]

Step-by-step explanation:

Given

[tex]M = (25.5,60.1)[/tex]

[tex]C = (18.3,72.5)[/tex]

Required

Determine the coordinates of A

Midpoint is calculated as thus:

[tex]M(x,y) = (\frac{A_x + C_x}{2}, \frac{A_y + C_y}{2})[/tex]

Substitute the given values

[tex](25.5,60.1) = (\frac{A_x + 18.3}{2}, \frac{A_y + 72.5}{2})[/tex]

Multiply through by 2

[tex]2 * (25.5,60.1) = (\frac{A_x + 18.3}{2}, \frac{A_y + 72.5}{2}) * 2[/tex]

[tex]2 * (25.5,60.1) = (A_x + 18.3, A_y + 72.5)[/tex]

[tex](51,120.2) = (A_x + 18.3, A_y + 72.5)[/tex]

By comparison:

[tex]A_x + 18.3 = 51[/tex]

[tex]A_y + 72.5 = 120.2[/tex]

[tex]A_x + 18.3 = 51[/tex]

[tex]A_x = 51 - 18.3[/tex]

[tex]A_x = 32.7[/tex]

[tex]A_y + 72.5 = 120.2[/tex]

[tex]A_y = 120.2 - 72.5[/tex]

[tex]A_y = 47.7[/tex]

Hence:

[tex]A = (32.7,47.7)[/tex]

Answer:

A

Step-by-step explanation:

The equation of the perpendicular line is y = -1/2x + 3. The correct option is (B).

A linear equation is a equation that has degree as one.

To find the solution of n unknown quantities n number of equations with n number of variables are required.

The coordinates of the given points are (-2, 0) and (0, 4).

The equation of the line for the given points can be written as follows,

(y - 4)/(x - 0) = (4 - 0)/(0 - (-2))

=> y - 4 = 2x

=> y = 2x + 4

Comparing the above equation with the general equation y = mx + c the  slope is given as,

m = 2

Now, the product of the slopes of two perpendicular lines is -1.

Thus, the slope of the perpendicular line is,

m' = -1/2.

In order to find the the correct answer compare all the options with general equation y = mx + c and check if the slope is -1/2 as below,

(a) y = 1/2x - 2

m = 1/2

(b) y = -1/2x + 3

m = -1/2

(c) y = 2x + 1

m = 2

(d) y = -2x + 4

m = -2

Hence, the equation for the line perpendicular to the given line is  y = -1/2x + 3.

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Answer:

a) The object reaches its maximum height at t=2.5 seconds

b) The maximum height is 300 m

Step-by-step explanation:

Maximum Value of a Function

First derivative criteria:

If f(t) is a real continuous function of t and the first derivative of f called f'(t) exists, then solving the equation:

f'(t)=0

Gives the critical points of f, some of which could be maximum or minimum.

Second derivative criteria:

If t=t1 is a critical point of f(t) and the second derivative of f:

f''(t1) is positive, then t1 is a minimum of f

f''(t1) is negative, then t1 is a maximum of f.

f''(t1)=0, no conclusion can be drawn.

The height of the object is modeled by the function:

[tex]h(t) = -16t^2+80t + 200[/tex]

a)

To find the maximum height, we use the above criteria.

Find the first derivative:

h'(t) = -32t+80

Equate h'(t)=0

-32t+80=0

Solve:

[tex]-32t=-80[/tex]

[tex]t=80/32=2.5[/tex]

t=2.5 seconds

Find the second derivative:

h''(t)=-32

Since the second derivative is negative, the critical point is a maximum.

The object reaches its maximum height at t=2.5 seconds

b) Evaluate h(2.5)

[tex]h(2.5) = -16\cdot 2.5^2+80\cdot 2.5 + 200[/tex]

[tex]h(2.5) = -100+200 + 200[/tex]

h(2.5)=300 m

The maximum height is 300 m

Answer:

a) 15.866%

b) Middle 95% = 350 ml to 750 ml

c) 0.3829

d) Middle 90% of men’s bladder fall = 385.5ml to 714.5 ml

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

The distribution of bladder volume in men is approximately Normal with mean 550 ml and standard deviation 100 ml.

Required:

a. What percent of men have a bladder volume smaller than 450 ml?

z = 450 - 550/100

= -1

P-value from Z-Table:

P(x<450) = 0.15866

Convert to percentage

0.15866 × 100

= 15.866%

b. Between what volumes do the middle 95% of men’s bladders fall?

Middle 95% falls between 2 standard deviation of the mean

μ ± 2σ

μ - 2σ

550 - 2(100)

= 550 - 200

= 350 ml

μ + 2σ

= 550 + 2(100)

= 550 + 200

= 750 ml

Middle 95% = 350 ml to 750 ml

c. What proportion of male bladders are between 500 and 600 ml?

For 500ml

z = 500 - 550/100

= -0.5

Probability value from Z-Table:

P(x = 500) = 0.30854

For 600ml

z = 600 - 550/100

= 0.5

Probabilty value from Z-Table:

P(x = 600) = 0.69146

Proportion of male bladders are between 500 and 600 ml

P(x = 600) - P(x = 500)

0.69146 - 0.30854

= 0.38292

≈ 0.3829

d. What volumes do the middle 90% of men’s bladder fall?

The z score for middle 90% + / – 1.645

Hence,

1.645 = x - 550/100

1.645 × 100 = x - 550

164.5 + 550 = x

x = 714.5 ml

-1.645 = x - 550/100

-1.645 × 100 = x - 550

- 164.5 + 550 = x

x = 385.5ml

Middle 90% of men’s bladder fall = 385.5ml to 714.5 ml