(Translations LU)
Use the graph to answer the question.
-6 -5
A'
-4
В'
-3
D'
-2 -1
A
0
C'
4
-5
-6
B
2
D
Determine the translation used to create the image.
3
4
C
5

Part(a),

The price that yields maximum profit is $35.

Part(b),

The average cost per unit is equal to $40.49.

Profit is the financial benefit from a commercial transaction or an investment that remains after deducting all related costs, costs of capital, and taxes. It represents the discrepancy between the revenue obtained from the sale of goods or services and the overall expenses incurred in their production.

The profit function can be modeled as follows:

P(x) = (117 - 0.5x)x - (40x + 31.75)

P(x) = 117x - 0.5x² - 40x - 31.75

P(x) = -0.5x² + 77x - 31.75

(a) Determine the value of x that maximizes the profit function in order to determine the price that generates the greatest profit. This happens at the parabola's vertex.

which has x-coordinate,

[tex]\dfrac{-b}{2a} = \dfrac{-77}{(-0.5)} = 154.[/tex]

Therefore, the price that yields maximum profit is,

p = 117 - 0.5(154) = $ 35 per unit.

(b) When the profit is maximized, we can find the average cost per unit by evaluating the total cost function at x = 154 and dividing by the number of units:

C(154) = 40(154) + 31.75 = $ 6231.75

Average cost per unit = C(154)/154 = $ 40.49 per unit.

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The average cost per unit when the profit is maximized is $40.28 per unit.

To find the price that yields a maximum profit, we need to first determine the profit function. The profit function is given by:

Profit = Total Revenue - Total Cost

The total revenue is given by the product of the price and the quantity demanded, so we have:

Total Revenue = p * x = (117 - 0.5x) * x

The total cost is given by the cost function, so we have:

Total Cost = C = 40x + 31.75

Substituting these expressions for total revenue and total cost into the profit function, we get:

Profit = (117 - 0.5x) * x - (40x + 31.75)

Simplifying this expression, we get:

Profit = -0.5x^2 + 77x - 31.75

To find the price that yields a maximum profit, we need to take the derivative of the profit function with respect to x and set it equal to zero:

dProfit/dx = -x + 77 = 0

Solving for x, we get:

x = 77

So, the number of units that yields a maximum profit is 77. To find the price that yields a maximum profit, we substitute x = 77 into the demand function:

p = 117 - 0.5x = 117 - 0.5(77) = 77.5

Therefore, the price that yields a maximum profit is $77.50 per unit.

To find the average cost per unit when the profit is maximized, we substitute x = 77 into the cost function:

C = 40x + 31.75 = 40(77) + 31.75 = 3103.75

The average cost per unit is given by the total cost divided by the number of units, so we have:

Average Cost = C/x = 3103.75/77 = 40.28

Therefore, the average cost per unit when the profit is maximized is $40.28 per unit.

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The area of the given composite figure is found to be 69 cm² which can be calculated by adding the area of triangle and rectangle comprising the figure.

Area is a measure of the size of a shape or surface. It is calculated by multiplying the length by the width of a shape, or by finding the area of each part of a shape and then adding them together.

The figure is composed of one triangle and one rectangle.

To find the area of the overall figure, we need to add the individual area of the triangle and the rectangle.

Area of triangle= 1/2 b.h

Here, base of triangle is 6.

(As the the length of Rectangle is 12 cm, we can find the base by subtracting 6 from 12)

And the triangle is a right angled triangle, thus the perpendicular is the height.

11-4= 7cm

So, A = 1/2 . 7 . 6

= 21cm²

Now, area of Rectangle= l ×  w

A= 12× 4

= 48cm²

Now, area of composite figure= 21+48

= 69 cm²

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Cindy's time from the total time that was covered by the whole team mates would be = 13/10.

The total number of the team mates that where involved in a relay race = 4 girls

The total number of the that was used by the whole team for the relay race = 3 11/5 minutes.

If four people = 3 11/5

1. person = X

Make X the subject of formula;

X = 3 11/5/4

= 26/5 ÷ 1/4

= 5.2/4

= 1.3

= 13/10

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To find the estimated margin of error, you need to calculate the difference between the upper and lower bounds of the confidence interval, then divide by 2. In this case, the confidence interval is (3.9, 4.3).
Estimated margin of error = (4.3 - 3.9) / 2 = 0.4 / 2 = 0.2 cm.
To find the sample mean, you need to take the average of the upper and lower bounds of the confidence interval.
Sample mean = (3.9 + 4.3) / 2 = 8.2 / 2 = 4.1 cm.
So, the estimated margin of error is 0.2 cm and the sample mean is 4.1 cm.

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Sure, I'd be happy to help! To start, we need to sketch the area under the standard normal curve between the z-scores of 2.49 and 1.86.
First, let's draw the standard normal curve:
(please imagine a bell curve here)
Next, we need to shade in the area between the z-scores of 2.49 and 1.86. This area is shown in red in the graph below:
(please imagine the red shaded area on the graph above)
Now, we need to find the specified area of this shaded region. To do so, we will use a standard normal distribution table or calculator.
Using a calculator, we can find that the area to the left of 2.49 is 0.9938, and the area to the left of 1.86 is 0.9693. Therefore, the area between these two z-scores is:
0.9938 - 0.9693 = 0.0245
So, the specified area of the shaded region is approximately 0.0245.

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The cost of storing the particles on the fourth day is approximately $232.50.

The decay of 200 particles of a particular radioactive substance is given by y = 200(0.93)ˣ

To find the cost of storing the particles on the fourth day, we first need to calculate how many particles are left on the fourth day.

Substituting x = 4 into the equation y = 200(0.93)ˣ, we get

y = 200(0.93)⁴ ≈ 154.98

So, approximately 155 particles are left on the fourth day.

Now, we can calculate the cost of storing the particles on the fourth day by multiplying the number of particles by the cost per particle

155 particles × $1.50/particle/day = $232.50

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The given question is incomplete, the complete question is:

The decay of 200 particles of a particular radioactive substance is given by y = 200(0.93)ˣ, where x is the number of days and y is the number of particles remaining. It costs the laboratory $1.50 per day to store each particle. What is the cost of storing the particles on the fourth day?

By using the property of integration we get s(t)= t³/6 - 3t²+4t+8.

What is integration?

Integration is a part of calculus which defines the calculation of an integral that are used to find many useful quantities such as areas, volumes, displacement, etc. When we speak about integrals, it is generally related to definite integrals. The indefinite integrals are used for antiderivatives mainly.

A particle is moving with the given data.

a(t)= t-6

so v(t)= ∫(t-6)dt

integrating we get,

v(t)= t²/2 - 6t +c where c is the integrating constant

Now again integrating we get,

s(t) = ∫ ( t²/2 - 6t +c) dt

     = t³/6 - 3t²+ct+k where k is another integrating constant.

now putting , s(0)= 8 and v(0)= 4 which means at t=0 , s=8 and v=4 we get,

c=4 and k= 8

Hence, s(t)= t³/6 - 3t²+4t+8.

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For problem 1, (a) F′(x) = ∫0 u² cos(u) du, (b) F′(x) = x√(x² - 1), (c) 6∫3 L′(t) dt represents the total change in horn length between t = 3 and t = 6. (d)

The units of the definite integral are the units of the integrand (in this case, cm/year) multiplied by the units of the variable of integration (in this case, years), so the units of r(t) (cm/year) and t (years) are reflected in the units of the definite integral.

In (c), the integral represents the total increase in horn length between t=3 and t=6, which can also be expressed as the change in L(t) between these values.

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The 95% confidence interval for the population mean is (594.06, 605.94) hours.

To find the confidence interval, we'll use the following formula:

CI = x ± (z × σ / √n)

where CI is the confidence interval, x is the sample mean, z is the z-score for a 95% confidence interval, σ is the population standard deviation, and n is the sample size.

In this case, x = 600 hours, σ = 25 hours, and n = 68. For a 95% confidence interval, the z-score is approximately 1.96.

Now we can plug these values into the formula:

CI = 600 ± (1.96 × 25 / √68)

CI = 600 ± (49 / √68)

CI = 600 ± (49 / 8.246)

CI = 600 ± 5.94

So the 95% confidence interval for the population mean is (594.06, 605.94) hours. This means we can be 95% confident that the true population mean of the light bulb lifetimes is between 594.06 and 605.94 hours.

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we have shown that cos 2x tan x = 2 sin x cos x sin x tan x for all values of x.

How to solve the question?

To prove that cos 2x. tanx = 2 sin x cos x sin x tanx for all values of x, we can start with the following trigonometric identities:

cos 2x = cos²x - sin² x (1)

tan x = sin x / cos x (2)

Substituting equation (2) into the right-hand side of the expression to be proved, we get:

2 sin x cos x sin x tan x = 2 sin²x cos x / cos x

= 2 sin² x

Using equation (1), we can express cos 2x in terms of sin x and cos x:

cos 2x = cos² x - sin² x

= (1 - sin²x) - sin²x

= 1 - 2 sin²x

Substituting this into the left-hand side of the expression to be proved, we get:

cos 2x tan x = (1 - 2 sin² x) sin x / cos x

= sin x / cos x - 2 sin³ x / cos x

Using equation (2), we can simplify the first term:

sin x / cos x = tan x

Substituting this back into the previous equation, we get:

cos 2x tan x = tan x - 2 sin³ x / cos x

We can then multiply both sides by cos x to eliminate the denominator:

cos 2x tan x cos x = sin x cos x - 2 sin³x

Using the double-angle identity for sine, sin 2x = 2 sin x cos x, we can rewrite the left-hand side:

cos 2x sin x = sin 2x / 2

Substituting this and simplifying the right-hand side, we get:

sin 2x / 2 = sin x cos x - sin³x

= sin x (cos x - sin² x)

Finally, using equation (1) to substitute cos²x = 1 - sin²x, we get:

sin 2x / 2 = sin x (2 sin²x - 1)

= sin x (2 sin² x - sin²x - cos²x)

= sin x (sin² x - cos² x)

= -sin x cos 2x

Therefore, we have shown that cos 2x tan x = 2 sin x cos x sin x tan x for all values of x.

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the area of the geographical region is 77910 square mile.

What is square?

Having four equal sides, a square is a quadrilateral. There are numerous square-shaped objects in our immediate environment. Each square form may be recognised by its equal sides and 90° inner angles. A square is a closed form with four equal sides and interior angles that are both 90 degrees. Numerous different qualities can be found in a square.

Here given a rectangle of length= 308mile

and breadth = 270miles

The area will be A1= 308*270 = 83160 miles²

A portion is missing in the region of length =105

and bredth =50

A2= 105*50 = 5250 mile²

The actual area will be A1-A2= 83160-5250 = 77910 mile²

Hence, the area of the geographical region is 77910 square mile

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The derivative of the given function is [tex]-12x^{2}(u^2 - 1)u(du/dx)/(u^2 + 1)^3[/tex]under the condition the given function is g(x) = S3x 2x (u²-1)/(u²+1)du.

The derivative of the given function

g(x) = S3x 2x (u²-1)/(u²+1)du is

[tex]g'(x) = 3x * 2x * (u^2 - 1)/(u^{2}+ 1) * d/dx(S(u^{2} + 1)^{-1})[/tex]

Applying the chain rule, then

[tex]d/dx(S(u^2 + 1)^-1) = -2u(du/dx)/(u^2 + 1)^2[/tex]

Staging this  into prime original equation

[tex]g'(x) = -12x^2(u^2 - 1)u(du/dx)/(u^2 + 1)^3[/tex]

The derivative of the given function is [tex]-12x^2(u^2 - 1)u(du/dx)/(u^2 + 1)^3[/tex]

Function refers to the law which determines the relationship between one variable and other.

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The rate at which the infected population is growing after 9 days is approximately 309.076 people per day.

We have,

To find the rate at which the infected population is growing after 9 days, we need to calculate the derivative of the function I(t) with respect to t and evaluate it at t = 9.

The given equation is:

[tex]I(t) = 5200e^{0.08t}[/tex]

Let's differentiate I(t) with respect to t using the chain rule:

[tex]dI/dt = d/dt [5200e^{0.08t}]\\= 5200 \times d/dt [e^{0.08t}]\\= 5200 \times 0.08 \times e^{0.08t}[/tex]

Now, we can evaluate the derivative at t = 9:

[tex]dI/dt (t=9) = 5200 \times 0.08 \times e^{0.08 \times 9}\\= 5200 \times 0.08 \times e^{0.72}[/tex]

≈ 309.076

Therefore,

The rate at which the infected population is growing after 9 days is approximately 309.076 people per day.

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Answer:

Step-by-step explanation:

You can draw it.   the points given are top left, bottom left and bottom right

This is the last point, top right.

(5,3)

Answer:

(5, 3).

Step-by-step explanation:

The fourth vertex needed to create a rectangle with vertices located at (-5, 3), (-5, -7), and (5, -7) would be (5, 3).

A rectangle is a quadrilateral with opposite sides of equal length and all angles equal to 90 degrees. In this case, the given points (-5, 3), (-5, -7), and (5, -7) form three vertices of the rectangle, with the sides connecting them being the sides of the rectangle.

To complete the rectangle, we need to find the fourth vertex that would complete the right angles and equal side lengths. Among the given options, (5, 3) is the only point that would complete the rectangle, as it has the same x-coordinate as (5, -7) and the same y-coordinate as (-5, 3), and would form a right angle with these points, completing the rectangle. Therefore, the correct answer is (5, 3).

The correlation coefficient (r) is approximately -0.6417.

We can calculate the correlation coefficient (r) using the following steps:

1. Calculate the coefficient of determination (R²), which is given by: R² = 1 - (SSE/SST)
2. Take the square root of R² to get the absolute value of the correlation coefficient: |r| = √(R²)
3. Determine the sign of the correlation coefficient (r) by looking at the regression slope (b1). If b1 is negative, r is negative; if b1 is positive, r is positive.

Given the values: SST = 17000, SSE = 10000, and b1 = -17.29:

1. R² = 1 - (10000/17000) = 1 - 0.5882 ≈ 0.4118
2. |r| = sqrt(0.4118) ≈ 0.6417
3. Since b1 is negative, r is also negative: r = -0.6417

Therefore, The correlation coefficient (r) is approximately -0.6417.

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The x-value a such that 98% of x-values are less than or equal to a, with a mean (μ) of 4.4 and standard deviation (σ) of 2.8, is approximately 9.62.

To find this x-value (a), we follow these steps:
1. Identify the given information: μ = 4.4, σ = 2.8, and the desired percentile (98%).
2. Convert the percentile to a z-score using a z-table or calculator. For 98%, the z-score is approximately 2.33.
3. Use the z-score formula to find the x-value: x = μ + (z * σ).
4. Plug in the values: x = 4.4 + (2.33 * 2.8).
5. Calculate the result: x ≈ 9.62.

Thus, 98% of x-values in this normal distribution are less than or equal to 9.62.

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The value of the given definite integral after performing a series of calculations is 14, under the condition the given definite integral is [tex]\int\limits^2_1 (4x^{3} -3x^{2}+ 2x)dx.[/tex]

A definite integral is  known as an integral expressed as the difference in comparison to the values of the integral at specified upper and lower limits . In short , it is a given way of evaluating the area undergoing a curve between two points on the x-axis .

The definite integral of (4x³-3x² + 2x)dx from 1 to 2 can be evaluated as

[tex]\int\limits^2_1 (4x^{3} -3x^{2} + 2x)dx[/tex]

= [x⁴ - x³ + xx²]₂¹

= [(2)⁴ - (2)³ + (2)²] - [(1)⁴ - (1)³ + (1)²]

= 14

The value of the given definite integral after performing a series of calculations is 14, under the condition the given definite integral is [tex]\int\limits^2_1 (4x^{3} -3x^{2}+ 2x)dx.[/tex]

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The Maclaurin series for f(x) = xe²ˣ is Σ [(2n-1) 2⁽ⁿ⁻¹⁾ / n!] xⁿ. The radius of convergence is infinity.

To find the Maclaurin series for f(x) = xe²ˣ, we can start by finding its derivatives:

f(x) = xe²ˣ

f'(x) = e²ˣ + 2xe²ˣ

f''(x) = 4xe²ˣ + 4e²ˣ

f'''(x) = 12xe²ˣ + 8e²ˣ

f''''(x) = 32xe²ˣ + 24e²ˣ ...

At each step, we can see a pattern emerging: the nth derivative of f(x) is of the form:

fⁿ (x) = (2n)x e²ˣ

+ (2n-1) 2ⁿ e^(2x)

Using this pattern, we can write the Maclaurin series for f(x) as:

f(x) = f(0) + f'(0)x + f''(0)x²/2! + f'''(0)³/3! + ...

f(x) = 0 + 1x e⁰+ x²/2! (4e⁰+ 1) + 0³/3! (12e⁰+ 8) + ...

Simplifying, we get:

f(x) = x + 2x²+ 8³/3 + 32x⁴/3 + ...

Therefore, the Maclaurin series for f(x) is:

Σ (n=1 to infinity) [(2n-1) 2⁽ⁿ⁻¹⁾ / n!] xⁿ

The radius of convergence of this series can be found using the ratio test:

lim (n→∞) |(2n+1) 2ⁿ / (n+1)!| / |(2n-1) 2⁽ⁿ⁻¹⁾ / n!| = lim (n→∞) (4/(n+1)) = 0

Since the limit is less than 1, the series converges for all values of x. Therefore, the radius of convergence is infinity.

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The equation that has a solution of x = 2 is given as follows:

A number represents a solution to an equation when we replace each instance of the unknown variable by the number and the equality is true.

For this problem, we have that option b will have a solution of x = 2, as:

-3(7 - 2x) = -1 - 4x

-21 + 6x = -1 - 4x

10x = 20

x = 2.

Hence, replacing x = 2 on the equations, we have that:

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A function z(x, y) and its partial derivative (∂z/∂y)x is aslo a function.

Function:

In set math, function refers an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable)

Given,

Consider a function z(x, y) and its partial derivative (∂z/∂y)x.

Here we need to identify that the partial derivative still be a function of x.

In order to find the solution for this function, we must know the definition of partial derivative,

The definition of partial derivative is, "partial derivative of any function having several variables is its derivative with respect to one of those variables where the others are held constant."

Here the partial derivative of a function f with respect to the differently x is variously denoted by f’x, fx, ∂xf or ∂f/∂x.

The symbol ∂ is partial derivative.

So, as per the definition of the partial derivative, the given partial derivative  (∂z/∂y)x is also a function.

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complete question:

consider a function z(x, y) and its partial derivative (∂z/∂y)x. can this partial derivative still be a function of x?

The converted integral is:
∬[0 to 1][0 to π/3] r*sin(θ) sin(r*cos(θ) + r*sin(θ)) dr dθ

To rewrite the integral using polar coordinates, we'll first define the given region D and then convert the integral.

The region D is bounded by the following curves:
1. Circle: r^2 + y^2 = 1 (x = r*cos(θ), y = r*sin(θ))
2. Circle: x^2 + y = 4 (x = r*cos(θ), y = r*sin(θ))
3. Line: y = 0 (θ = 0)
4. Line: x = √3y (θ = π/3)

Now, let's convert the integral:
∬D sin(x + y) dA = ∬(r*sin(θ)) sin(r*cos(θ) + r*sin(θ)) dr dθ

To determine the limits of integration, we analyze the given region:
- The angle θ varies from 0 to π/3.
- The radial coordinate r varies from the intersection of the two circles to the first circle.

By solving the two circle equations simultaneously, we find the intersection point is (1/2, √3/2). Thus, the radial limit for r is from 0 to 1.

The converted integral is:
∬[0 to 1][0 to π/3] r*sin(θ) sin(r*cos(θ) + r*sin(θ)) dr dθ

Now, you can proceed with the evaluation of the integral using standard techniques.

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Answer:

Step-by-step explanation:

The total number of ways to divide the teams into 32 pairs and assign each pair to a different day is 1.120935e+47

To determine the number of ways to divide the teams into 32 pairs and assign each pair to a different day, we can use the formula for permutations:

nPr = n! / (n-r)!

Where n is the total number of teams and r is the number of teams we want to select at a time.

Since we need to divide the 32 teams into 16 pairs, we can calculate the number of ways to do this as:

32P16 = 32! / (32-16)!

32P16 = 32! / 16!

32P16 = 258,048,954,114,000

This gives us the total number of ways to form 16 pairs from the 32 teams. However, we also need to assign each pair to a different day, which means we need to arrange the pairs over the 32 days.

The number of ways to do this is simply 32!, since we have 32 pairs to assign to 32 days.

Thus, the total number of ways to divide the teams into 32 pairs and assign each pair to a different day is:

32! * 32P₁₆

= 32! * (32! / 16!)

= 1.120935e+47

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The brand of cell phone and the number of cell phones sold may have a relationship, but it may be influenced by many other factors and may not be linear.

The relationship between the high temperature of the day and the number of zoo visitors that day could be described using correlation. Correlation measures the strength of the relationship between two variables, and in this case, we can expect that on hotter days, more people may visit the zoo, and on cooler days, fewer people may visit the zoo.

The other relationships listed are not necessarily suitable for correlation analysis because they involve a categorical variable or a variable that does not have a clear linear relationship with the other variable. For example, the number of books read and the gender of a student are categorical variables, and correlation analysis is not appropriate for these types of variables. The number of football games played and the position of a football player could have a relationship, but it may not be linear or straightforward. Similarly, the type of beverage ordered and the time of day it was ordered may have a relationship, but it may not be linear or easily quantifiable. The brand of cell phone and the number of cell phones sold may have a relationship, but it may be influenced by many other factors and may not be linear.

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The 95% confidence interval for p is 0.9 ± 0.067, or (0.833, 0.967) rounded to three decimal places.

To find the confidence interval for a proportion, we can use the normal distribution, assuming that the sample size is large enough and the sample proportion is not too close to 0 or 1.

We are given that the sample proportion is 0.9 and the sample size is 130, so we can calculate the standard error of the proportion as sqrt(0.9 x (1-0.9)/130) = 0.034.

To find the 95% confidence interval, we can use the z-score associated with a 95% confidence level, which is 1.96. The point estimate for p is simply the sample proportion, which is 0.9. The margin of error is the product of the standard error and the z-score, which is 0.034 x 1.96 = 0.067.

This means that we are 95% confident that the true population proportion falls within this interval. It is important to note that this is not a statement about the probability of the true population proportion being within this interval, but rather a statement about the reliability of our estimate based on the sample data.

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Upon answering the query  As a result, the object's location at time t = 2 function is 35. Solution: (D) 35.

Mathematics is concerned with integers and their variations, equations and related structures, shapes and their places, and possible placements for them. The relationship between a collection of inputs, each of which has an associated output, is referred to as a "function". An relationship between inputs and outputs, where each input yields a single, distinct output, is called a function. Each function has a domain or a codomain, often known as a scope. The letter f is frequently used to represent functions (x). X is the input. The four main types of functions that are offered are on functions, one-to-one operations, many-to-one functions, within processes, and on functions.

We must integrate the acceleration twice to get the object's position function in order to determine its location at time t = 2.

We may integrate the acceleration function, which is provided by a(t) = 6t, to get the velocity function:

[tex]v(t) = \int\limits { a(t) ) \, dt = \int\limits 6t dt = 3t^2 + C1[/tex]

We may utilise the knowledge that the object's velocity is 10 at time t = 0 to solve for the constant C1 as follows:

[tex]v(0) = 3(0)^2 + C1 = C1 = 10[/tex]

The velocity function is as a result:

[tex]v(t) = 3t^2 + 10[/tex]

The velocity function may now be integrated to produce the position function.:

[tex]s(t) = \int\limit v(t) dt = \int\limit (3t^2 + 10) dt = t^3 + 10t + C2[/tex]

Once more, we can utilise the knowledge that the object's location at time t = 0 is 7 to find the value of the constant C2:

[tex]s(0) = (0)^3 + 10(0) + C2 = C2 = 7\\s(t) = t^3 + 10t + 7\\s(2) = (2)^3 + 10(2) + 7 = 8 + 20 + 7 = 35\\[/tex]

As a result, the object's location at time t = 2 is 35. Solution: (D) 35.

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Answer:

x = 14

Step-by-step explanation:

7x + 2 = 100

7x = 98

x = 14

Let's Check

7(14) + 2 = 100

98 + 2 = 100

100 = 100

So, x = 14 is the correct answer.

The linearization at a suitably chosen integer near 'a' at which the given function and its derivative are easy to evaluate f(x) = sin(x) a = 0 is L(x) = x

To find the linearization of the function f(x) = sin(x) at a suitably chosen integer near a, where the derivative of f(x) is easy to evaluate, we first need to find the derivative of f(x). The derivative of sin(x) is cos(x).
Next, we need to choose an integer near a. Let's say we choose a = 0, since it is easy to evaluate the derivative of sin(x) at this point.
To find the linearization at a, we use the formula for linearization:

L(x) = f(a) + f'(a)(x-a)

Plugging in the values, we get:
L(x) = sin(0) + cos(0)(x-0)
L(x) = 0 + 1(x)
L(x) = x
Therefore, the linearization of f(x) = sin(x) at a = 0 is L(x) = x.

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The store should order calculators 8.73 times per year and each order should have a size of 44.24 calculators to minimize costs.

We have,

Let's assume that the store orders the calculators 'n' times a year and each order has a size of 'Q' calculators.

Then, the total cost (TC) can be expressed as:

TC = Cost of ordering + Cost of holding inventory

Cost of order = Total number of orders x Cost per order

= n x (8 + 2.25Q)

Cost of holding inventory = Cost of holding one calculator x Total number of calculators held

= 2 x 800/Q x Q/2

= 800

Therefore, the total cost can be expressed as:

TC = n(8 + 2.25Q) + 800

To minimize the total cost, we need to find the values of 'n' and 'Q' that minimize TC.

To do that, we can take partial derivatives of TC with respect to 'n' and 'Q' and set them to zero:

∂TC/∂n = 8 + 2.25Q = 0

∂TC/∂Q = 2.25n - 800/Q^2 = 0

Solving these equations, we get:

Q = √(800/2.25n) = 16.97√n

n = (2.25Q^2)/800 = 0.025Q^2

We can substitute the expression for 'Q' in terms of 'n' in the equation for 'n' to get:

n = 0.025(16.97√n)² = 2.293n

Solving for 'n', we get:

n = 8.73

Substituting this value of 'n' in the equation for 'Q', we get:

Q = 16.97√n = 44.24

Therefore,

The store should order calculators 8.73 times per year and each order should have a size of 44.24 calculators to minimize costs.

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