tommy solved the equation x ^²-x-12=0 select the factores of x^-x-12

Start with the base graph: y = |x|

Translate the graph one unit to the right: y = |x - 1|

---We use a minus/negative/subtraction sign when dealing with horizontal translations because it is the opposite of the way we want to go. If the translation occurs within parenthesis/absolute value bars, we always do the opposite of what we think we should.

Translate the graph one unit down: y = |x - 1| - 1

---If the translation occurs to the y-value/vertically, we use the expected operation/sign. If the translation occurs outside of parenthesis, we use the same operation/sign as the translation (+ for up, - for down).

Answer: y = |x - 1| - 1

Hope this helps!

Answer:

y=|x-1|-1

Step-by-step explanation:

The function for a v shaped graph is an absolute value function: y=|x|

Subtracting 1 from the absolute value y=|x|, we move the graph 1 unit right of the x axis

Subtracting 1 from the whole equation, y=|x-1|, we move the graph 1 unit down the y axis

So, the equation would be y=|x-1|-1

To maximize the company's profit, we need to find the profit function and then differentiate it with respect to the quantities produced by each plant to find the optimal values.

The profit function is given by:

π = TR - TC

where TR is the total revenue and TC is the total cost.

Using the demand function p = 40 - 0.04q, we can express the total revenue as:

TR = p * q = (40 - 0.04q) * q = 40q - 0.04q²

The total cost is the sum of the costs of each plant, so we have:

TC = C1 + C2 = 6.7 + 0.03q1² + 7.9 + 0.04q2² = 14.6 + 0.03q1² + 0.04q2²

Substituting these expressions into the profit function, we get:

π = 40q - 0.04q² - 14.6 - 0.03q1² - 0.04q2²

To find the optimal values of q1 and q2, we differentiate the profit function with respect to each quantity and set the derivatives equal to zero:

∂π/∂q1 = 40 - 0.06q1 - 0.04q2 = 0

∂π/∂q2 = 40 - 0.03q2 - 0.04q1 = 0

Solving these equations, we get:

q1 = 357.14

q2 = 285.71

So each plant should produce 357.14 and 285.71 units of the item, respectively, in order to maximize the company's profit.

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We can  draw at the 5% significance level, the p-value is 0.02. we reject h0 at the 5% significance level because the p-value 0.02 is less than 0.05. The correct answer is a.

To find the p-value, we need to find the area to the right of t = 2.15 under the t-distribution curve with 24 degrees of freedom (df = n - 1 = 25 - 1 = 24). Using a t-table or a calculator, we find that the area to the right of t = 2.15 is approximately 0.02.

Since the p-value (0.02) is less than the significance level (0.05), we reject the null hypothesis H0: μ = 8 and conclude that there is sufficient evidence to support the alternative hypothesis Ha: μ > 8 at the 5% significance level. This means that we can say with 95% confidence that the true population mean is greater than 8.

Therefore the correct answer is a.

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The mean of the thickness of paper is 39 inches, and the standard deviation is 0.1 inches.

To find the mean and standard deviation of the thickness of paper after dividing by 0.0001, you should follow these steps:

1. Divide the mean by 0.0001:
Mean after dividing = 0.0039 inches / 0.0001
Mean after dividing = 39 inches

2. Divide the standard deviation by 0.0001:
Standard deviation after dividing = 0.00001 inches / 0.0001
Standard deviation after dividing = 0.1 inches

The mean of the thickness of paper after dividing by 0.0001 is 39 inches, and the standard deviation is 0.1 inches.

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Answer:

609 pages

Hope this helps!

Step-by-step explanation:

9 books = 5481 pages

1 book = ? pages

9 books ÷ 9 = 1 book  so  5481 pages ÷ 9 = 609 pages

1 book has 609 pages.

The value of k is -2

Let a line passes through the point [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. Thus the equation of line can be given as,

[tex](y -y_1)=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]......Eq.(1)

We have the information from the graph:

The graph of f(x) and g(x) are given in the problem.

The equation given is,

g(x) = k × f(x)

We have to find the value of k and also find the equation of f(x) and g(x).

The line y = f(x) lies on the points, (2,1) and (0,-3). Thus the equation of this line is,

Plug all the values in eq.(1)

[tex](y -(-3))=\frac{-3-1}{0-2}(x-0)[/tex]

[tex]y+3=\frac{-4}{-2}x[/tex]

y + 3 = 2x

y = 2x -3

So, it can be written as:

f(x) = 2x -3

The line y = f(x) lies on the points, (0,6) and (2,-2). Thus the equation of this line is,

[tex](y -6)=\frac{-2-6}{2-0}(x-0)[/tex]

[tex](y-6)=\frac{-8}{2}x[/tex]

(y- 6) = -4x

y = -4x + 6

It can be written as:

g(x) = -4x + 6

The equation given in the problem is:

g(x) = k × f(x)

Put all the values in above given equation:

-4x + 6 = k(2x - 3)

-2(2x - 3) = k × (2x - 3)

Compare the value of k :

k = -2

Hence, The value of k = -2

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For complete question, to see the attachment:

Answer:

Based on the image, we can see that matrix A is a 3x2 matrix, and matrix B is a 2x3 matrix. In order to multiply matrices A and B, the number of columns in matrix A must match the number of rows in matrix B.

Since matrix A has 2 columns and matrix B has 2 rows, we can multiply them together, resulting in a 3x3 matrix. Therefore, the answer is B. The dimensions of AB are 3x3.

Ans. (c) 2X3

Dimension of matrix is given by row x column

6d^2 - 51d + 24

that's it

...............................

Answer:

√429.

Step-by-step explanation:

Triangles BCD and ABC are similar, so corresponding sides are in the same ratio, so:

x/ AC = DC/x

x/39 = 11/x

x^2 = 11*39

x^2 = 429

x = √429

The completed statements, obtained from the relationship between the exterior angles of a triangle and supplementary angles are;

The m∠MXN is greater than m∠YZX

The m∠LZX is equal to m∠ZYX + m∠YXZ

The m∠MYL is equal to 180° - m∠ZYX

Supplementary angles are angles that form a linear pair and when added together are equivalent to 180°

The exterior angle of a triangle theorem indicates, that we get;

m∠MXN = m∠YZX + m∠ZYX

∠MYL is a supplementary angle to the angle ∠ZYX

Therefore; m∠MYL + m∠ZYX = 180°

The completed statements are therefore;

m∠MXN is greater than m∠YZX

m∠LZX equal to m∠ZYX + m∠YXZ

m∠MYL equal to 180° - m∠ZYX

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The possible values of x that satisfy the equation |x+5| = c are x = c - 5 and x = -c - 5.

what is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas.

The production level that will yield maximum revenue is 6000 units, the maximum revenue is $180,000, and the price the company needs to charge at that level is $30. The production level that will yield maximum profit is 5250 units, the maximum profit is $59,250, and the price the company needs to charge at that level is $37.25.

To find the production level that will yield maximum revenue, we need to determine the quantity demanded that maximizes the revenue. The revenue function is given by

R(x) = xp(x) = x(-0.005x + 60) = -0.005x^2 + 60x

To find the maximum value of R(x), we need to take the derivative of R(x) and set it equal to zero

R'(x) = -0.01x + 60 = 0

x = 6000

So the production level that will yield maximum revenue is 6000 units.

To find the maximum revenue, we can plug this value into the revenue function

R(6000) = -0.005(6000)^2 + 60(6000) = $180,000

To find the price the company needs to charge at that level, we can plug the production level into the demand function

p(6000) = -0.005(6000) + 60 = $30

To find the production level that will yield maximum profit, we need to determine the quantity that maximizes the profit function. The profit function is given by

P(x) = R(x) - C(x) = -0.005x^2 + 60x - (-0.001x^2 + 18x + 4000) = -0.004x^2 + 42x - 4000

To find the maximum value of P(x), we need to take the derivative of P(x) and set it equal to zero

P'(x) = -0.008x + 42 = 0

x = 5250

So the production level that will yield maximum profit is 5250 units.

To find the maximum profit, we can plug this value into the profit function

P(5250) = -0.004(5250)^2 + 42(5250) - 4000 = $59,250

To find the price the company needs to charge at that level, we can plug the production level into the demand function

p(5250) = -0.005(5250) + 60 = $37.25

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The area of the triangle to the nearest tenth is 5.8cm²

A triangle is a closed, 2-dimensional shape with 3 sides, 3 angles, and 3 vertices. A triangle is also a polygon. Examples of triangle include, isosceles, equilateral , scalene e.t.c

The area of a triangle is expressed as;

A = 1/2 b h for right angle triangle and A = absinC for others.

Here; x = 4.7, y = 7.9, W = 162

area = 1/2× 4.7 × 7.9 sin162

= 1/2 × 4.7 × 7.9 × 0.31

= 5.8 cm²( nearest tenth)

Therefore the area of the triangle is 5.8cm²

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The average cost per day for the four service is $3.23 per day

Average cost refers to the per-unit cost of production, which is calculated by dividing the total cost of production by the total number of units produced.

Therefore average cost = total cost/ number of unit

total cost = $108

average cost for the three services = $108/3

= $36

total average cost = $36+$54.30

= $90.30

therefore average cost for a day will be average cost for a month over 28day i.e 7days ×4

= 90.30/28

= $3.23 per day

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It is a fifth order polynomial

The constant term is -7

The leading term is [tex]x^5/7[/tex]

The coefficient of the leading term is [tex]1/7[/tex]

The term with the highest degree—i.e., the term with the largest power of the variable—is the leading term. The leading coefficient is the leading term's coefficient.

We frequently rearrange polynomials so that the powers are descending or ascending because of the definition of the "leading" term. We can see that the leading term in the expression here is [tex]x^5/7[/tex].

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Assuming that the muffins were actually ready at two minutes to five in the afternoon, we can determine that it took Robert approximately 38 minutes to prepare and bake the muffins.

To arrive at this conclusion, we can use the following logic:

Robert got home from school at 3:33 PM (twenty-seven minutes before 4:00 PM).

The muffins were ready at 4:58 PM (two minutes before 5:00 PM).

Therefore, the time between when Robert got home and when the muffins were ready is 85 minutes (58 minutes + 27 minutes).

Since Robert decided to bake the muffins immediately upon arriving home, it took him 85 minutes to prepare and bake them.

Of course, this assumes that Robert did not take any breaks or perform other activities during the time between getting home and the muffins being ready. In reality, the actual time it took to prepare and bake the muffins may have been longer or shorter depending on various factors, such as the recipe, equipment used, and Robert's baking experience.

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Check the picture below.

[tex](x)(18)=(x+1)(16)\implies 18x=16x+16\implies 2x=16 \\\\\\ x=\cfrac{16}{2}\implies x=8=RW[/tex]

The critical value for the given problem is 1.282.

To determine if there's sufficient evidence that the average Trifecta winnings exceed $50, follow these steps:

1. State the hypotheses:
  H0: µ ≤ $50 (null hypothesis)
  H1: µ > $50 (alternative hypothesis)

2. Choose the significance level:
  α = 0.10

3. Calculate the test statistic (t-score):
  t = (sample mean - population mean) / (sample standard deviation / √sample size)
  t = ($52.23 - $50) / ($3.35 / √13)
  t ≈ 2.15

4. Determine the critical value:
  Using a t-distribution table or calculator, find the critical value for a one-tailed test with 12 degrees of freedom (13-1) and α = 0.10. The critical value is 1.282.

5. Compare the test statistic to the critical value:
  Since the test statistic (2.15) is greater than the critical value (1.282), we reject the null hypothesis.

In conclusion, there is sufficient evidence to conclude that the average Trifecta winnings exceed $50 at a 10% significance level.

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Complete question:

A random sample of 13 $1 Trifecta tickets at a local racetrack paid a mean amount of $52. 23 with a sample standard deviation of $3. 35. Is there sufficient evidence to conclude that the average Trifecta winnings exceed $50? Use a 10% significance level and assume the distribution is approximately normal.What is the critical value?

Below is attached t-table image:

The correct option for each individual question is c. X - 1. 5= 5. 25, c. 72 = 9b and B/1.75 = 6.

1. Total food = poured food + remaining food

Keep the values in formula

x = 1.5 + 5.25

Rearranging the equation

x - 1.5 = 5.25

Thus, correct option is c. X - 1. 5= 5. 25

2. Cost of one box × number of boxes = total cost

9 × number of boxes = 72

Let us represent the number of boxes as b. So,

9b = 72

Hence, correct option is c. 72 = 9b.

3. Length of each section × number of sections = total length of bookcase sections

Let us represent total length of bookcase sections as B

1.75 × 6 = B

Rearranging the equation

B/1.75 = 6

So, the correct option is a. B/1. 75 = 6.

Thus, correct option are c. X - 1. 5= 5. 25, c. 72 = 9b and B/1.75 = 6.

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The velocity of the particle at time t is given by [tex]v(t) = 70t/(3t^2 + 8)^2.[/tex]

The expression for the acceleration of the particle is a(t) [tex]= (210t^2 + 1120)/(3t^2+8)^3.[/tex]

A) To find the velocity of the particle, we need to take the derivative of its position with respect to time:

[tex]X(t) = (t^2 - 9)/(3t^2 + 8)[/tex]

[tex]v(t) = dX/dt = [(2t)(3t^2+8) - (t^2-9)(6t)]/(3t^2+8)^2[/tex]

[tex]v(t) = (6t^3 + 16t - 6t^3 + 54t)/(3t^2 + 8)^2[/tex]

[tex]v(t) = 70t/(3t^2 + 8)^2[/tex]

Therefore, the velocity of the particle at time t is given by[tex]v(t) = 70t/(3t^2 + 8)^2.[/tex]

B) To determine whether the particle is moving toward or away from the origin at time t = 2, we need to examine the sign of the velocity v(2). Plugging t = 2 into the expression for v(t), we get:

[tex]v(2) = 70(2)/((3(2)^2 + 8)^2) = 280/169[/tex]

Since v(2) is positive, the particle is moving away from the origin at time t = 2.

C) The acceleration of the particle is given by the derivative of its velocity with respect to time:

[tex]v(t) = 70t/(3t^2 + 8)^2[/tex]

[tex]a(t) = dv/dt = (70(3t^2+8)^2 - 2(70t)(2t)(3t^2+8))/(3t^2+8)^4[/tex]

[tex]a(t) = (210t^2 + 1120)/(3t^2+8)^3[/tex]

Therefore, the expression for the acceleration of the particle is [tex]a(t) = (210t^2 + 1120)/(3t^2+8)^3[/tex]. To find the value of a(2), we plug in [tex]t = 2:a(2) = (210(2)^2 + 1120)/(3(2)^2+8)^3 = 175/677[/tex]

D) To find the position that the particle approaches as t approaches infinity, we examine the behavior of X(t) as t gets very large. We can do this by looking at the leading term of the numerator and denominator of X(t) as t approaches infinity:

[tex]X(t) = (t^2 - 9)/(3t^2 + 8)[/tex]

As t approaches infinity, the numerator is dominated by the t^2 term, and the denominator is dominated by the 3t^2 term. Therefore, as t approaches infinity, X(t) approaches:

[tex]X(infinity) = t^2/3t^2 = 1/3[/tex]

So the particle approaches the point x = 1/3 as t approaches infinity.

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(a) The first derivative of f is f'(x) = 3x² - 15.

(b) The second derivative of f is f''(x) = 6x.

(c) f is increasing on the interval (-∞, √5) and decreasing on the interval (√5, ∞).

(d) f is decreasing on the interval (-∞, √5) and increasing on the interval (√5, ∞).

(e) f is concave downward on the interval (-∞, 0) and concave upward on the interval (0, ∞).

(a) To find the first derivative of f, we differentiate each term of the function with respect to x using the power rule. Thus, f'(x) = 3x² - 15.

(b) To find the second derivative of f, we differentiate f'(x) with respect to x. Thus, f''(x) = 6x.

(c) To determine the intervals where f is increasing, we set f'(x) > 0 and solve for x. Thus, 3x² - 15 > 0, which simplifies to x² > 5. Therefore, x is in the interval (-∞, √5) or (√5, ∞). To determine which interval makes f increasing, we can test a point within each interval.

For example, when x = 0, f'(0) = -15, which is negative, so f is decreasing on (-∞, √5). When x = 10, f'(10) = 285, which is positive, so f is increasing on (√5, ∞). Thus, f is increasing on the interval (√5, ∞) and decreasing on the interval (-∞, √5).

(d) To determine the intervals where f is decreasing, we set f'(x) < 0 and solve for x. Thus, 3x² - 15 < 0, which simplifies to x² < 5. Therefore, x is in the interval (-∞, √5) or (√5, ∞). Again, we can test a point within each interval to determine which one makes f decreasing.

For example, when x = 0, f'(0) = -15, which is negative, so f is decreasing on (-∞, √5). When x = 10, f'(10) = 285, which is positive, so f is increasing on (√5, ∞). Thus, f is decreasing on the interval (-∞, √5) and increasing on the interval (√5, ∞).

(e) To determine the intervals of concavity, we examine the sign of the second derivative of f. If f''(x) > 0, then f is concave upward, and if f''(x) < 0, then f is concave downward. If f''(x) = 0, then the concavity changes. Thus, we set f''(x) > 0 and f''(x) < 0 and solve for x. We get f''(x) > 0 when x > 0 and f''(x) < 0 when x < 0.

Therefore, f is concave upward on (0, ∞) and concave downward on (-∞, 0).

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Answer:Therefore, the cost of a utility pole with a diameter of 42 cm and a height of 740 cm is approximately $1957.43.

Step-by-step explanation:First, we need to calculate the volume of the cylinder-shaped utility pole:

The radius of the pole is half the diameter, so it's 42 cm / 2 = 21 cm.

The height of the pole is 740 cm.

The volume of a cylinder is given by the formula V = πr²h, where π is approximately 3.14, r is the radius, and h is the height.

Substituting the values we have, we get V = 3.14 x 21² x 740 = 1,034,462.4 cm³.

Now we can calculate the mass of the pole:

The density of the metal is 6.3 g/cm³, which means that 1 cm³ of the metal has a mass of 6.3 g.

The volume of the pole is 1,034,462.4 cm³, so its mass is 6.3 x 1,034,462.4 = 6,524,772.72 g.

Next, we convert the mass to kilograms and calculate the cost:

1 kg is equal to 1000 g, so the mass of the pole in kilograms is 6,524,772.72 g / 1000 = 6524.77 kg.

The cost of the metal is $0.30 per kilogram, so the cost of the pole is 6524.77 kg x $0.30/kg = $1957.43.

The solution to this system of equations are x = -5 and y = 8.

In order to determine the solution to a system of two linear equations, we would have to evaluate and eliminate each of the variables one after the other, especially by selecting a pair of linear equations at each step and then applying the elimination method.

Given the following system of linear equations:

x + y = 3                .........equation 1.

x - 3y = -29                .........equation 2.

By subtracting equation 2 from equation 1, we have:

(x - x) + (y - (-3y) = 3 - (-29)

y + 3y = 3 + 29

4y = 32

y = 32/4 = 8

x = 3 - y

x = 3 - 8

x = -5

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amount of paint needed to cover all the wood in the frame, we need to first determine the total length of the wood in meters. Let's assume that each plank of wood is 1 meter long, so the total length of wood in the frame is 3 meters.

Next, we need to calculate the amount of paint required per meter of wood. The problem states that 80ml of emulsion paint is needed per meter of wood. So, we can multiply 80ml by 3 meters to get the total amount of paint needed for the entire frame.

80ml/meter x 3 meters = 240ml
Therefore, we need 240ml of emulsion paint to cover all the wood in the frame.
It is important to note that this calculation assumes that only one coat of paint will be applied to the wood. If multiple coats are desired, the amount of paint required will need to be adjusted accordingly.

In conclusion, to paint the wooden frame made of three planks of wood attached with glue and nails, we would need 240ml of emulsion paint.

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Answer:

(-∞, 1) ∪ (1, ∞)

Step-by-step explanation:

1 - x = 0

-x = -1

x = 1

In interval notation, the domain is (-∞, 1) U (1, ∞)

The error caused an understatement of the gross profit for the year, as the cost of goods sold was overstated by $14,750.

The error in inventory caused an understatement of the inventory value on the balance sheet, which in turn caused an overstatement of the cost of goods sold. This is because the cost of goods sold is calculated by subtracting the cost of the ending inventory from the cost of goods available for sale.

Therefore, an understatement of the ending inventory leads to an overstatement of the cost of goods sold, which ultimately results in an understatement of the gross profit. None of the other items on the balance sheet are directly affected by the error in inventory.

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Answer:8

Step-by-step explanation:

There is about a 47.62% or 0.476 chance that the rock hit the windshield in the driver's line of sight. Option D.

To determine the probability that the rock hit the driver's line of sight on the windshield, we need to compare the area of the driver's line of sight rectangle to the total area of the windshield rectangle.

The area of the windshield rectangle is:

A1 = 28 in x 54 in = 1512 sq in

The area of the driver's line of sight rectangle is:

A2 = 30 in x 24 in = 720 sq in

Therefore, the probability that the rock hit the driver's line of sight on the windshield is:

[tex]P= \frac{A2}{A1}= \frac{720 \:sq in}{1512 \:sq in }[/tex] = 0.476 or 47.6%

So, there is about a 47.62% chance that the rock hit the windshield in the driver's line of sight.

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Answer:

(x-4)^2+(y-1)^2=9

Step-by-step explanation:

diameter = 6

radius = diameter/2 = 3

center (h,k) = (4,1)

standard equation of a circle (x-h)^2 + (y-k)^2=r^2

(x-4)^2+(y-1)^2=9

Answer: AB = 16.4

Step-by-step explanation:

You can use tan x = opposite/adjacent

tan 38 = AB/21

21 tan 38 = AB

AB = 16.4