Tina's application for graduate school was ranked 54 out of 300 applications. Her twin sister's application to a
different graduate school was ranked 23 out of 175 applications.
a. Which sister had the higher percentile ranking?
b. If you had the data on the cumulative GPA of each student in each school in June 2019, which measure of
average would be the most meaningful - mean, median, mode? Explain

A mean is an arithmetic average of a set of observations. The correct option is B.

A mean is an arithmetic average of a set of observations. it is given by the formula,

Mean = (Sum of observations)/Number of observations

The average pay does not differ significantly since the average wage for subpopulations is not significant. As a result,  the subpopulations of mechanical and civil engineers are Not earning different salaries.

Hence, the correct option is B.

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Answer:

-4

Step-by-step explanation:

x^2+4x+5=0

a=1,b=4^1 C=5

4^2-4×1×5

-4

Answer:

{x∈R | [tex]\frac{2x}{3\pi } +\frac{1}{2}[/tex], x∉Z}

Step-by-step explanation:

Given the function y=3tan(2/3x)

We know that tangent is a function that's continuous within it's domain but not continuous on all real numbers

Also, the roots of y=3tan(2/3x) is [tex]3\pi n/2[/tex] where n is an integer

Note that the domain of the function cannot be within [tex]3\pi n/2[/tex]

Therefore, {x∈R | [tex]\frac{2x}{3\pi } +\frac{1}{2}[/tex], x∉Z}

Answer:

(-32, 0)

Step-by-step explanation:

Answer:

(-32,0)

Step-by-step explanation:

Answer:

It is arithmetic progression

Step-by-step explanation:

If wwe see, the numbers are going down by 3 each time, therfore the common difference is 3

Hii!

_________________________________________________________

[tex]\stackrel\star{\rightsquigarrow\circ\boldsymbol{\underbrace{Answer}\circ\leftharpoonup}}[/tex]

1. This sequence is arithmetic

2. The common ratio is 3.

[tex]\stackrel\star{\rightsquigarrow\circ\boldsymbol{\underbrace{Explanation.}}}\circ\leftharpoonup[/tex]

[tex]\bullet[/tex] Difference between arithmetic and geometric sequences

[tex]\twoheadrightarrow\sf Arithmetic\quad sequences[/tex] - In arithmetic sequences, we add the same amount to obtain the next term.

[tex]\twoheadrightarrow\sf Geometric\quad sequences[/tex] - In geometric sequences we multiply times the same amount to obtain the next term.

[tex]\bullet[/tex] Since we add the same amount to get the next term, the given sequence is arithmetic

[tex]\twoheadrightarrow\sf Common\;difference:-3[/tex]

[tex]\bullet[/tex] In the given sequence we add -3, or subtract 3, to obtain the next term

--

Hope that this helped! Best wishes.

[tex]\stackrel\ast{\textsl{Reach far. Aim high. Dream big.}}[/tex]

--

The equation of Q(n) is [tex]Q(n) = \frac89 * (88n + 23)[/tex]

The functions are given as:

[tex]R(d) = \frac89 d[/tex]

[tex]P(n) = 88n + 23[/tex]

From the question, we understand that:

d = P(n)

This means that:

d = 88n + 23

Substitute d = 88n + 23 in R(d)

[tex]R(n) = \frac89 * (88n + 23)[/tex]

Also, from the question

Q(n) = R(n)

So, we have:

[tex]Q(n) = \frac89 * (88n + 23)[/tex]

Hence, the equation of Q(n) is [tex]Q(n) = \frac89 * (88n + 23)[/tex]

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Answer: C) Age Group Number of People:

18–24 20

25–31 40

32–38 120

39–45 80

Have a good day/night! I hoped this helped. :D

Answer:

  A:

Step-by-step explanation:

You want to know the table that accurately reflects the data in the described graph.

As presented here, this is a reading comprehension problem.

The problem statement tells you the first bin is labeled 18–24, and the graph there extends to 80. This eliminates tables C and D. Tables A and B show 80 people in the 18–24 age group.

The second bin is labeled 25–31, and the graph there extends to 120. This matches the entry in Table A.

Table A matches the graph.

<95141404393>

Answer:

6n+1

Step-by-step explanation:

Eliminate the parenthesis by changing the symbol of each term inside

3+[5n-2+n]

Eliminate the bracket and group similar terms

5n+n+3-2

Simplify terms

6n+1

These [tex]N[/tex] outcomes make up the entire sample space, so

[tex]\displaystyle \sum_{k=1}^N P(e_k) = P(e_1) + P(e_2) + P(e_3) + \cdots + P(e_N) = 1[/tex]

We're given that [tex]P(e_{j+1}) = 2 P(e_j)[/tex] for all [tex]j\in\{1,2,\ldots,N-1\}[/tex], so

[tex]P(e_1) + 2 P(e_1) + 2^2 P(e_1) + \cdots + 2^{N-1} P(e_1) = 1 \\\\ \implies P(e_1) = \dfrac1{1 + 2 + 2^2 + \cdots + 2^{N-1}} = \dfrac1{2^N - 1}[/tex]

Then we can solve the recurrence relation to get the probability of the [tex]j[/tex]-th outcome,

[tex]P(e_{j+1}) = 2 P(e_j) = 2^2 P(e_{j-1}) = 2^3 P(e_{j-2}) = \cdots \\\\ \implies P(e_{j+1}) = 2^j P(e_1) \\\\ \implies P(e_j) = 2^{j-1} P(e_1) = \dfrac{2^{j-1}}{2^N - 1}[/tex]

The probability of getting this sequence of [tex]k[/tex] outcomes is then

[tex]\displaystyle P(E_k) = P(e_1) + P(e_2) + \cdots + P(e_k) = \sum_{j=1}^k \frac{2^{j-1}}{2^N-1} = \frac{2^k-1}{2^N-1}[/tex]

as required.

Some preliminary results: If [tex]S[/tex] is the sum of the first [tex]n[/tex] terms of a geometric series with first term [tex]a[/tex] and common ratio [tex]r[/tex], then

[tex]S = a + ar + ar^2 + \cdots + ar^{n-1}[/tex]

[tex]\implies rS = ar + ar^2 + ar^3 + \cdots + ar^n[/tex]

[tex]\implies S - rS = a(1 - r^n)[/tex]

[tex]\implies S = \dfrac{a(1 - r^n)}{1 - r}[/tex]

which gives us, for instance,

[tex]1 + 2 + 2^2 + \cdots + 2^{N-1} = \dfrac{1 - 2^N}{1 - 2} = 2^N-1[/tex]

Answer:

-4.5

Step-by-step explanation:

You arrange the numbers from lowest to highest value:

-17, -12, -11, -10, -7, -2, 7, 10, 16, 20

Then you find the one in the middle:

-7, -2

Because there are two in the middle, you add them and divide them by two:

(-7 + -2)/2 = -4.5

Your answer is -4.5.

Step-by-step explanation:

firstly arrange it increasingly

-2,-7,-10,-11,-17, 7,10,16,20

n=9 it is odd so we use (n+1/2 )th formula

9+1/2

10/2=5th

os it is -17

Answer:

  it saves 2.5 minutes

Step-by-step explanation:

The expected value of a random variable is the sum of products of possibilities and the probability of each.

Here, you have a probability of 0.9 of saving 5 minutes, and a probability of 0.1 of adding 20 minutes.

__

The expected value of the shortcut is ...

  0.9(-5) +0.1(20) = -4.5 +2.0 = -2.5

The shortcut is expected to save 2.5 minutes on average.

_____

Additional comment

The probability of 0.9 comes from the 9 of 10 trips that result in a time saving.

Answer:

They are not similar because corresponding sides are not proportional.

Condition for similarity of two triangles -

The ratio of corresponding sides should be equal.

Condition for congruence of two triangle -

Any of the following -

Side side side

side angle side

angle angle

angle side angle

Answer:

Y=72

Step-by-step explanation:

First we set up the equation which is (20-2) times 4=Y

Then we solve, 20 minus 2 is risk since it is in the parentheses. 20 minus 2 is 18.

After that 18 times 4 is 72

Y=72

The labeled angles are both equal to c by the corresponding angles theorem.

Thus, a+b=c by the exterior angle theorem.

32 pints of each of the two existing types of drink must be used to make 40 pints of a mixture that is 45% pure fruit juice.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

Let x be the pints of 60% pure fruit juice

0.60x + 0.35(40 - x) = 0.40(40)

x = 8

= 40 - 8 (pints of 35% juice)

= 32

Thus, 32 pints and 8 pints of each of the two existing types of drink must be used to make 40 pints of a mixture that is 45% pure fruit juice.

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Answer:

Linear Equations In One Variable =

[6(x-1)6] / 7 = 12

[(6x - 6)6] = 84

[36x - 36] = 84

36x = 84 + 36

36x = 120

x = 120/36

x = 10/3

equation solved (Answer : 10/3)

Answer:

[tex]\boxed{\sf x= -29.5}[/tex]

Step-by-step explanation:

[tex]\sf \sqrt{-2x+5}-3=5[/tex]

[tex]\sf \sqrt{-2x+5}=8[/tex]

[tex]\sf -2x+5=64[/tex]

[tex]\sf -2x=59[/tex]

[tex]\sf \cfrac{-2x}{-2}=\cfrac{59}{-2}[/tex]

Therefore, x = -29.5.

The sequence of transformations used to obtain figure A'B'C'D'from figure ABCD are a reflection across the y-axis followed by a horizontal translation 1 unit right

Figure ABCD is transformed to figure A'B'C'D', as shown below: (see attachment)

Which of the following sequences of transformations is used to obtain figure A'B'C'D'from figure ABCD?

From the attached figure, we can see that:

ABCD and A'B'C'D' are on either sides of the y-axis.

This means that ABCD is first reflected across the y-axis.

ABCD is 2 units from the y-axis, while A'B'C'D' is 1 unit from the y-axis.

This means that the reflection is followed by a translation.

The unit of translation is:

Unit = 2 - 1

Evaluate

Unit = 1

1 represents a right translation

Hence, the sequence of transformations are a reflection across the y-axis followed by a horizontal translation 1 unit right

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I consider the original fraction: x/y.

If the numerator "x" increases by 20%, it can be interpreted in this way:

"x" represents 100% (the unit) and when increasing by 20% we have that the value of "x" becomes 120%

120% of "x" is [tex]\bf{\frac{120*x}{100}=1,2x }[/tex]

This is what we have left in the numerator.

By the same reasoning, in the denominator "y" remains:

100% - 40% = 60% of "and"

60% of "y" is...[tex]\bf{\frac{60*y}{100}=0.6 y }[/tex]

The new fraction is: 1,2x / 1,6y.

...simplifying by dividing top and bottom by 0.6,... 2x / y

To find out the percentage by which the original fraction has changed, we first find the relationship or ratio between the original fraction and the new fraction with the fraction quotient:

[tex]\bf{\dfrac{\frac{2x}{y} }{\frac{x}{y} }=\frac{2xy}{xy}=2 }[/tex]

... that is to say that the new fraction has doubled in relation to the original.

Therefore, the percentage of variation per increase is 100%.

Total: 48

DIning Hall: 48(3/8)=18

so theres 30 left for the classes

30/5(#of classes)=6 per class

Answer:

y≤x²+4x-1.

Step-by-step explanation:

1) to define the equation of the given graph; it is y=x²+4x-1 (its vertex is (-2;-5));

2) to define inequation accorging to the given graph (the area outside of the parabola means ≤).

Using the normal distribution, it is found that the girl's score of 10 is higher than 99.62% of the population.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation are given, respectively, by:

[tex]\mu = 6, \sigma = 1.5[/tex].

Her z-score is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{10 - 6}{1.5}[/tex]

Z = 2.67

Z = 2.67 has a p-value of 0.9962.

Hence her score is higher than 99.62% of the population.

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The maximum number of turns for the graph given by the function is; 2.

It follows from the task content that the graph given is that of a cubic function. On this note, it follows that the graph has 2 turning points.

This follows from the fact that the degree of the polynomial is 3 and hence, the maximum number of turns on the graph is 2.

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Volume is a three-dimensional scalar quantity. As per the Cavaleri's principle the volume of both the figures will be the same.

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

According to Cavalieri's principle, if two figures have the same height and cross-sectional area throughout each point along that height, they have the same volume.

The height of both the objects is 16 cm, also the base area of both the objects is 96 cm². As it can be observed that for both the object there base area is the same through out their height.

Hence, as per the Cavaleri's principle the volume of both the figures will be the same.

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By writing Z in polar form, we will see that:

[tex]z^3 = C[/tex]

First, we can see that:

z = (-1 - i)

If we write it in polar form, we get:

[tex]z = \sqrt{2} *e^{i(\pi + \pi/4)[/tex]

If we apply the power 3, we get:

[tex]z^3 = (\sqrt{2} *e^{i(\pi + \pi/4)})^3\\\\z^3 = 2^{3/2}*e^{i*(3\pi + 3\pi/4)}\\\\z^3 = 2^{3/2}*e^{i*15\pi/4}[/tex]

Notice that:

[tex]\frac{15\pi}{4}[/tex]

Is an angle equivalent to:

[tex]\frac{15\pi}{4} - 2\pi = \frac{15\pi}{4} - \frac{8\pi}{4} = \frac{7\pi}{4} = 1.75\pi[/tex]

Because the angle is measured from the positive x-axis, this means that we will have:

[tex]z^3 = C[/tex]

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Based on the annual coupons on the bond and the current price, the current yield will be 9.27%.

This can be found as:

= Annual coupon amount / Bond price

Annual coupon:

= 10% x 100

= $10

The current yield is:

= 10 / 107.87

= 9.27%

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Answer:

The smaller bottle holds 12.5 ml of perfume.

====================

Find the scale factor, the ratio of corresponding dimensions:

We know the volume is the function of three dimensions, therefore the ratio of volumes is the cube of the scale factor:

Substitute the known values and find the volume of small bottle:

The smaller bottle holds 12.5 ml of perfume.

The smaller bottle holds 12.5 ml of perfume.

I solved it and came with this result.

The probability that a single can will contain 11.6 ounces or less of soda is 0.2843

The given parameters are:

x = 11.6

Mean = 12

Standard deviation = 0.7

Calculate the z value using:

[tex]z = \frac{x - \bar x}{\sigma}[/tex]

This gives

[tex]z = \frac{11.6-12}{0.7}[/tex]

z = -0.57

The probability is then calculated as:

P(x ≤ 11.6) = P(z ≤ -0.57)

Using the z table of probabilities, we have:

P(x ≤ 11.6) = 0.2843

In (a), the probability that a can contains 11.6 ounces or less is 0.2843

The probability that all cans in a pack contains 11.6 ounces or less is

P(6) = 0.2843^6

P(6) = 0.00053

In (a), the probability that a can contains 11.6 ounces or less is 0.2843

The probability that all cans in a case contains 11.6 ounces or less is

P(36) = 0.2843^36

P(36) ≈ 0

See attachment for the normal distributions

The summary of the graph is that, as the sample size increases the probability decreases

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