The partial pressure of each gas are:
Partial pressure of CH₄ is 1.22 atmPartial pressure of C₂H₆ is 1.46 atmPartial pressure of C₃H₈ is 1.02 atmHow do i determine the partial pressure of each gas?First, we shall determine the mole of 8.00 g of methane, CH₄ and 18.0 g of ethane, C₂H₆. Details below:
For methane, CH₄
Mass of CH₄ = 8 g Molar mass of CH₄ = 16 g/mol Mole of CH₄ =?Mole = mass / molar mass
Mole of CH₄ = 8 / 16
Mole of CH₄ = 0.5 mole
For ethane, C₂H₆
Mass of C₂H₆ = 18 g Molar mass of C₂H₆ = 30 g/mol Mole of C₂H₆ =?Mole = mass / molar mass
Mole of C₂H₆ = 18 / 30
Mole of C₂H₆ = 0.6 mole
Next, we shall determine the total mole. Details below:
Volume (V) = 750 mL = 10 LTemperature (T) = 23 °C = 23 + 273 = 296 KPressure (P) = 3.70Gas constant (R) = 0.0821 atm.L/mol KTotal of mole (n) =?PV = nRT
3.70 × 10 = n × 0.0821 × 293
Divide both sides by (0.0821 × 293)
n = (3.70 × 10) / (0.0821 × 293)
n = 1.52 mole
Finally, we shall determine the partial pressure of each gas. Details below:
For methane, CH₄
Mole of CH₄ = 0.5 moleTotal mole = 1.52 moleTotal pressure = 3.70 atmPartial pressure of CH₄ =?Partial pressure = (Mole / total mole) × total pressure
Partial pressure of CH₄ = (0.5 / 1.52) × 3.70
Partial pressure of CH₄ = 1.22 atm
For ethane, C₂H₆
Mole of C₂H₆ = 0.6 moleTotal mole = 1.52 moleTotal pressure = 3.70 atmPartial pressure of C₂H₆ =?Partial pressure = (Mole / total mole) × total pressure
Partial pressure of C₂H₆ = (0.6 / 1.52) × 3.70
Partial pressure of C₂H₆ = 1.46 atm
For propane, C₃H₈
Partial pressure of CH₄ = 1.22 atmPartial pressure of C₂H₆ = 1.46 atmTotal pressure = 3.70 atmPartial pressure of C₃H₈ =?Partial pressure of C₃H₈ = Total pressure - (Partial pressure of CH₄ + Partial pressure of C₂H₆)
Partial pressure of C₃H₈ = 3.7 - (1.22 + 1.46)
Partial pressure of C₃H₈ = 1.02 atm
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Need help matching pairs of structures to diastereomers, enantiomers, constitutional isomers, not isomers, diff representations of the same?
A pair of molecules which exist in two forms that are mirror images of each other but cannot be superimposed one upon the other are called the enantiomers. They are present in pairs and have similar molecular shape.
The compounds with the same molecular formula but are non-superimposable non-mirror images are called diastereomers. They have distinct physical properties and molecular shape.
The constitutional isomers have the same molecular formula but have different bonding atomic organization and bonding patterns.
So here:
1st structure is constitutional isomers (c), 2nd structures are enantiomers (b) and the 3rd are completely different not isomers (d).
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What is the difference between practical work inside a laboratory and outside a laboratory
Answer:
The main difference between practical work inside and outside a laboratory is that the practical work inside the lab includes good equipment and chemicals which are very advanced and the practical outside a laboratory is more about the safety of life.
Explanation:
Practicals are set up at stations with lab equipment and chemicals, where students can learn, and researchers can experiment and find different new things.
Thus, the practical work inside the lab includes lab equipment and chemicals, and the practical outside a laboratory is more about conserving nature.
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please help asap!
3. A double replacement reaction occurs between two solutions of lead (II) nitrate and potassium bromide. Write a
balanced equation for this reaction-identifying the product that will precipitate, and the product that will remain in
solution.
a) Write the balanced equation for this double replacement reaction.
b) If this reaction starts with 32.5 g lead (II) nitrate and 38.75 g potassium bromide, how many grams of the
precipitate will be produced? Remember to use the limiting reactant to calculate the amount of precipitate
formed.
c) How many grams of the excess reactant will remain?
Answer:
Explanation:
a) The balanced equation for the double replacement reaction between lead (II) nitrate and potassium bromide is:
Pb(NO₃)₂(aq) + 2KBr(aq) → PbBr₂(s) + 2KNO₃(aq)
In this reaction, lead (II) bromide (PbBr₂) will precipitate, while potassium nitrate (KNO₃) will remain in solution.
b) To determine the amount of precipitate produced, we need to first determine the limiting reactant. We can do this by calculating the number of moles of each reactant and comparing it to the stoichiometry of the balanced equation.
The molar mass of lead (II) nitrate is 331.21 g/mol and the molar mass of potassium bromide is 119.00 g/mol.
The number of moles of lead (II) nitrate is 32.5 g / 331.21 g/mol = 0.0981 mol The number of moles of potassium bromide is 38.75 g / 119.00 g/mol = 0.3256 mol
According to the balanced equation, one mole of lead (II) nitrate reacts with two moles of potassium bromide to produce one mole of lead (II) bromide. This means that if all the lead (II) nitrate were to react, it would require 0.0981 mol * 2 = 0.1962 mol of potassium bromide.
Since we have more than enough potassium bromide (0.3256 mol > 0.1962 mol), lead (II) nitrate is the limiting reactant.
The number of moles of lead (II) bromide produced will be equal to the number of moles of lead (II) nitrate consumed, which is 0.0981 mol.
The molar mass of lead (II) bromide is 367.01 g/mol, so the mass of lead (II) bromide produced will be 0.0981 mol * 367.01 g/mol = 36.0 g.
c) To determine the amount of excess reactant remaining, we need to subtract the amount consumed from the initial amount.
The number of moles of potassium bromide consumed is half the number of moles of lead (II) nitrate consumed, which is 0.0981 mol / 2 = 0.04905 mol.
The mass of potassium bromide consumed is 0.04905 mol * 119.00 g/mol = 5.84 g.
The mass of potassium bromide remaining is 38.75 g - 5.84 g = 32.91 g.
What is the equilibrium constant, K? 3 A(g) + 3 B(g) <-> 5 C(g) + 2 D(g)
The equilibrium constant is written as;
Keq = [tex][D]^2 [C]^5/[A] [B]^3[/tex]
What is the equilibrium constant?The equilibrium constant's value is influenced by the reaction's chemical make-up and temperature.
The product of the product concentrations, each raised to the power of their stoichiometric coefficient, divided by the product of the reactant concentrations, each raised to the power of their stoichiometric coefficient, is known as the equilibrium constant.
The equilibrium constant is Keq = [tex][D]^2 [C]^5/[A] [B]^3.[/tex]
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Which statements are TRUE about fossil fuels? (Select all that apply.)
They are in a limited supply.
They do not replenish themselves.
They are expensive to extract compared to other forms of energy.
They release large amounts of carbon dioxide when burned
✎help its an exam✎ ☕︎if any links I WILL REPORT☕︎
Answer:
All is Correct
Explanation:
Fossil fuels have the following properties:
They are in a limited supply. Fossil fuels are non-renewable resources, meaning that they cannot be replenished at the same rate as they are consumed. Once they are used up, they are gone forever.They do not replenish themselves. Fossil fuels take millions of years to form under specific geological conditions. They cannot be regenerated by natural processes in a human timescale.They are expensive to extract compared to other forms of energy. Fossil fuels require complex and costly methods to locate, drill, mine, transport, and refine. They also have negative externalities, such as environmental damage, health risks, and social conflicts, that are not reflected in their market prices.They release large amounts of carbon dioxide when burned. Fossil fuels contain carbon that was stored underground for millions of years. When they are burned, they release carbon dioxide (CO2) into the atmosphere, which is a greenhouse gas that contributes to global warming and climate change.Therefore, the answer is to select all
Answer:
It's A, B, and D
Explanation:
Maybe not D, because that is burning wood like charcoal. Not sure about that. Hope this helps!
8. The compound C2H4 has van der Waals constants a = 4.612 atm•L2/mol2 and b = 0.0582 L/mol. Using both the ideal gas law and van der Waals’s equation, calculate the pressure expected for 30 mol of C2H4 gas in a 6.00-L container at 20 °C.
Using the Ideal Gas Law, the pressure expected for 30 mol of [tex]C_2H_4[/tex] gas in a 6.00-L container at 20 °C is 1210.07 atm, and using the van der Waals equation, the pressure is 1179.71 atm.
To calculate the pressure expected for 30 mol of [tex]C_2H_4[/tex] gas in a 6.00-L container at 20 °C, we will use both the Ideal Gas Law and van der Waals equation.
Ideal Gas Law: PV = nRT
P = pressure
V = volume (6.00 L)
n = moles (30 mol)
R = ideal gas constant (0.0821 L•atm/mol•K)
T = temperature (20 °C + 273.15 = 293.15 K)
Solve for P (pressure):
P = nRT / V
P = (30 mol)(0.0821 L•atm/mol•K)(293.15 K) / 6.00 L
P = 1210.07 atm
Van der Waals equation:
(P + a(n/V)²)(V - nb) = nRT
a = 4.612 atm•L²/mol²
b = 0.0582 L/mol
Solve for P (pressure):
(P + (4.612)(30/6)²) (6 - 0.0582 * 30) = (30)(0.0821)(293.15)
P = 1179.71 atm
Using the Ideal Gas Law, the pressure is 1210.07 atm, and using the van der Waals equation, the pressure is 1179.71 atm.
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What are four methods of separating mechanical mixture?
Answer: Mixtures can be physically separated by using methods that use differences in physical properties to separate the components of the mixture, such as
evaporation, distillation, filtration and chromatography.Explanation:
please help me pair pka values with displayed molecules
If we label the compounds ABCD from left to right;
A - 12.10
B - 15.90
C - 12.66
D - 12.35
What is the pKa?A molecule or compound's acidity is quantified by the pKa, which is the negative logarithm (base 10) of the acid dissociation constant (Ka). The lower the pKa value, the stronger the acid; it reflects a compound's propensity to give a proton (H+) in a solution.
The compound that has the highest number of attachment of the most electronegative elements would have the greatest pKa.
The justification of the answer above is that, seeing that the compound labelled B has three highly electronegative atoms hence it would have the most or the highest pKa of about 15.90 among the other compounds. The other compounds A, C and D have fewer electronegative atoms attached and thus a lower pKa as shown
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N2(g)+3H2(g)->2NH3(g), ΔH=-92.40kJ 1. How many grams of H2 are needed to involve 150.9kJ of heat? 2. How many moles of NH3 were produced in the process?
1. To solve for the grams of H2 needed, we need to use the given ΔH value to calculate the amount of moles of N2 that reacted. From the balanced chemical equation, we know that for every 3 moles of H2 that reacts, 1 mole of N2 reacts. Therefore, we can use the mole ratio to convert the moles of N2 to moles of H2 and then use the molar mass of H2 to convert to grams.
First, we need to calculate the moles of N2 that reacted to produce 150.9kJ of heat:
ΔH = -92.40 kJ/mol N2
150.9 kJ = (1 mol N2 / -92.40 kJ) x (-150.9 kJ)
mol N2 = 1.63 mol
Using the mole ratio from the balanced chemical equation:
1 mol N2 : 3 mol H2
We can calculate the moles of H2 needed:3 mol H2 = 1 mol N2
3 mol H2 = 1.63 mol N2
mol H2 = 0.543 mol
Finally, we can convert moles of H2 to grams:
mol H2 = 0.543 mol
molar mass of H2 = 2.02 g/mol
grams of H2 = (0.543 mol) x (2.02 g/mol)
grams of H2 = 1.10 g
Therefore, 1.10 grams of H2 are needed to involve 150.9kJ of heat.
2. To solve for the moles of NH3 produced, we can use the same mole ratio from the balanced chemical equation:
1 mol N2 : 2 mol NH3
From the moles of N2 that reacted calculated in part 1, we can calculate the moles of NH3 produced:
1 mol N2 = 2 mol NH3
1 mol N2 = 1.63 mol N2
mol NH3 = (2 mol NH3 / 1 mol N2) x (1.63 mol N2)
mol NH3 = 3.26 mol
Therefore, 3.26 moles of NH3 were produced in the process.
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A student is tasked with writing the net ionic equation for the following
reaction:
4
Al(s) + 3 AgNO3(aq) → Al(NO3)3(aq) + 3 Ag(s)
What is the net ionic equation?
The net ionic equation of the reaction is as follows:
4 Al3+(aq) + 12 NO3-(aq) + 3 Ag(s) = 4 Al(s) + 12 Ag+(aq) + 12 NO3-(aq)
Ions which remain in their ground state and do not take part in the reaction are called spectator ions. The net ionic equation cancels out these ions, which are present on both the reactant and product sides of the equation.
Spectator ions, which can be found on both the reactant and product sides, but are not included in the finished reaction from the net ionic equation. The [tex]NO^3^-[/tex] ions are spectator ions in this example, thus taking them out of the equation. The net ionic equation makes up the rest of the species.
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5. A sample of unknown metal has a mass of 135 grams. As the sample cools from 100.5 °C to 35.5 °C, it releases 7500 joules of energy. What is the specific heat of the sample?
please show work
The sample of the unknown metal has the mass of the 135 grams. The sample cools from the 100.5 °C to the 35.5 °C, and it releases the 7500 joules of the energy. The specific heat of the sample is 0.854 J/g °C.
Th mass of the metal = 135 g
The initial temperature = 100.5 °C
The final temperature = 35.5 °C
The heat energy releases = - 7500 J
The heat energy is expressed as :
Q = mc ΔT
Where,
The m is mass of the metal = 135 g
The c is the specific heat capacity = ?
The Q is heat energy releases = - 7500 J
The ΔT is the change in the temperature = final temperature - initial temperature.
The ΔT is the change in the temperature = 35.5 - 100.5
The ΔT is the change in the temperature = - 65 °C
The specific heat capacity, c = Q / m ΔT
The specific heat capacity, c = - 7500 / 135 × - 65
The specific heat capacity, c = 0.854 J/g °C
The specific heat capacity of metal is 0.854 J/g °C.
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Determine the rate constant for the reaction at 350.0 K
_____M-¹S-¹
The rate constant (k) for a chemical reaction can be determined experimentally by measuring the reaction rate (v) at different concentrations of reactants and plotting the data using a suitable rate law equation.
How to explain the reactionThere are different methods to determine the rate constant depending on the type of reaction, but a general approach is as follows:
Conduct the reaction under different initial concentrations of reactants while keeping other variables constant such as temperature, pressure, and pH.
Measure the reaction rate at each concentration by monitoring the change in concentration of reactants or products over time.
An overview was given based on incomplete information.
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please provide explanation!! thank you in advance!!
The molarity of the product is 0.00368 M. Option B
What is the reaction equilibrium?When the rates of the forward and reverse reactions in a chemical reaction are equal and the concentrations of reactants and products are stable over time, this condition is referred to as reaction equilibrium.
The equilibrium constant is a measure of the relative concentrations of reactants and products at equilibrium.
[tex]Keq = [H_{2} O] [CO]/[H_{2}] [CO_{2} ]\\0.106 = x^2/(0.0113)^2\\x = \sqrt{} 0.106 (0.0113)^2\\x = 0.00368 M[/tex]
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Why does the air feel "sticky" on warm summer days? What is in the air that caausses this
What mass (grams) of oxygen will be released when 268.9 grams of Potassium Chlorate is thermally decomposed?
KClO3 --> KCl + O2
The centripetal acceleration experienced by the object can be calculated using the formula a = v^2/r, where v is the speed of the object and r is the radius of the circle. Substituting the given values, we get:
a = (50 cm/s)^2 / (250 cm)
a = 10 cm/s^2
Therefore, the centripetal acceleration experienced by the object is 10 cm/s^2.
To calculate the centripetal acceleration experienced by the object, you can use the formula:
Centripetal acceleration (a_c) = (velocity^2) / radius
Here, the velocity (v) is 50 cm/s and the radius (r) is 250 cm. Plugging in these values, we get:
a_c = (50^2) / 250 = 2500 / 250 = 10 cm/s²
So, the centripetal acceleration experienced by the object is 10 cm/s².
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Based on the solubility rules, which one of these phosphate compounds is insoluble in water?
A) Li2CO3
B) Na3PO4
C) Ba(OH)2
D) (NH4)3PO4
(NH4)3PO4 is insoluble in water. The correct option is D
What is solubility rules ?According to their chemical formula and ionic charges, ionic compounds generally follow a set of solubility laws that define their solubility patterns in water. These guidelines aid in determining whether an ionic compound will dissolve in water or not as well as if it will precipitate when combined with other ionic compounds.
Therefore, (NH4)3PO4 is the compound that is expected to be insoluble in water based on the solubility rules.
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A sample of an ideal gas has a volume of 2.31 L
at 279 K
and 1.01 atm.
Calculate the pressure when the volume is 1.09 L
and the temperature is 308 K.
The pressure of the gas when the volume is 1.09 L and the temperature is 308 K is 2.36 atm.
What is the final pressure of the gas?The final pressure of the gas is calculated by applying ideal gas law as follows;
(P₁V₁)/T₁ = (P₂V₂)/T₂
where
P₁, V₁, and T₁ are the initial pressure, volume, and temperature, P₂, V₂, and T₂ are the final pressure, volume, and temperature,P₂ = (P₁V₁ x T₂)/(V₂ x T₁)
P₂ = (1.01 atm x 2.31 L x 308 K) / (1.09 L x 279 K)
P₂ = 2.36 atm
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Balloons for a New Years Eve party in Fargo, ND, are filled to a volume of 1.90 L at a temperature of 22.0 c and then hung outside. what is the volume of the balloon once they have cooled to the outside temperature of -34.0 c?
The volume of the balloon once they have cooled to the outside temperature of -34.0 c is 1.53 L.
Charles' law predicts the relationship between the volumes and the temperatures of a sample of an ideal gas at different conditions. For this equation to hold true, the number of molecules and the pressure must remain constant despite changes in the environment.
Determine the volume of the balloon outside, V2. We do this by applying Charles' law, such that we relate the volume, V, and the temperature, T, of a sample of gas as
V₁ /T₁ = V₂/ T₂
at two conditions. We are given the following values for the variables:
• V₁ = 1.90 L
T₁ = 22.0+ 273.15 = 295.15 K
T₂= 34.0+273.15= 239.15 K
We proceed with the solution.
V₁/T₁ = V₂/T₂
V₁ /T₁ × T₂ = V₂
1.90 L/295.15 K x 239.15 K = V₂
1.53 L =V₂
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The complete question is
Balloons for a New Year's Eve party in Fargo, ND, are filled to a volume of 1.90 L at a temperature of 22.0 degrees Celsius and then hung outside where the temperature is -34.0 degrees Celsius. What is the volume of the balloons after they have cooled to the outside temperature? Assume that atmospheric pressure inside and outside the house is the same.
PLEASE HELP!!
351.6g of Chromium-63 is allowed to decay for 128.8 years, how much Chromium-63
is left? (The half life of 63 Cr is 32.2 days.) Please, enter your answer as a one decimal
place number with no units.
A crucial trace mineral is chromium. Trivalent chromium, which is safe for people, and hexavalent chromium, which is toxic, are the two types.
Thus, Foods and dietary supplements both contain trivalent chromium. It might assist maintain normal blood sugar levels by enhancing the body's utilization of mineral.
Chromium is used by people to treat deficiencies. Additionally, it is used to treat bipolar disorder, diabetes, high cholesterol, and a variety of other conditions, but the majority of these uses are not well-supported by science.
Chromium by mouth doesn't help control blood sugar levels in people with prediabetes. Schizophrenia. Taking chromium by mouth doesn't affect weight or mental health in people with schizophrenia.
Thus, A crucial trace mineral is chromium. Trivalent chromium, which is safe for people, and hexavalent chromium, which is toxic, are the two types.
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Anyone know how to solve this?
The ratio of the concentrations at equilibrium is as follows:
3.7 0.85 0.04 21.3 42.6 12212.92 0.81 0.11 7.4 14.8 6012.2 0.63 0.43 1.5 3 274What are reactions in equilibrium?Chemical equilibrium is the point in a chemical reaction where both the forward and backward processes are occurring at the same rate.
The concentrations of the reactants and products are constant at equilibrium because the forward and reverse speeds are equal.
Considering the given statements based on the reaction equilibrium concentrations, the correct options are:
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The mass of calcium release same number of valence electron as same number of 23g Na
20 g of calcium would release the same number of valence electrons as 23 g of sodium.
The atomic number of calcium (Ca) is 20, which means it has 20 electrons in its neutral state. When calcium loses two electrons, it becomes a Ca2+ ion with 18 electrons.
On the other hand, the atomic number of sodium (Na) is 11, which means it has 11 electrons in its neutral state. When sodium loses one electron, it becomes a Na+ ion with 10 electrons.
To release the same number of valence electrons as 23 g of Na, we need to calculate how many moles of Na there are in 23 g:
Molar mass of Na = 23 g/mol
Number of moles of Na = 23 g / 23 g/mol = 1 mol
Since each Na+ ion has lost one electron, 1 mol of Na+ ions has lost 1 mol of valence electrons.
To release the same number of valence electrons as 1 mol of Na+ ions, we need to calculate how many moles of Ca2+ ions are required:
1 mol of Na+ ions = 1 mol of valence electrons
1 mol of Ca2+ ions = 2 mol of valence electrons
Therefore, we need 0.5 mol of Ca2+ ions to release the same number of valence electrons as 1 mol of Na+ ions.
Finally, we can calculate the mass of calcium that would release the same number of valence electrons as 23 g of Na:
Molar mass of Ca = 40 g/mol
Mass of Ca required = 0.5 mol x 40 g/mol = 20 g
Therefore, 20 g of calcium would release the same number of valence electrons as 23 g of sodium.
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You want to make a 50 mL SATURATED solution of potassium chloride at 40 degrees Celsius. How many grams of potassium chloride do you need?
We need 21 grams of potassium chloride to make a 50 mL saturated solution at 40 degrees Celsius. It's important to note that if the temperature or volume of the solution were to change, the amount of solute needed to make a saturated solution would also change, as solubility is dependent on both temperature and volume.
According to the solubility table, the solubility of potassium chloride at 40 degrees Celsius is 42 grams per 100 mL of water. This means that we can dissolve 42 grams of potassium chloride in 100 mL of water at 40 degrees Celsius to make a saturated solution.
To make a 50 mL saturated solution, we can use the following formula:
mass of solute = (volume of solution x solubility)/100
mass of solute = (50 x 42)/100
mass of solute = 21 grams
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How many grams of magnesium oxide would be formed if 28.2 grams of magnesium was burned?
Mg + O2 --> MgO
When 28.2 grams of Mg is burned, 46.7 grams of MgO will be formed.
How to determine the amount of MgO formed when 28.2 grams of Mg is burnedThe balanced chemical equation for the combustion of magnesium is:
2 Mg + O2 --> 2 MgO
This equation shows that 2 moles of Mg react with 1 mole of O2 to produce 2 moles of MgO.
To determine the amount of MgO formed when 28.2 grams of Mg is burned, we first need to convert the given mass of Mg to moles:
molar mass of Mg = 24.31 g/mol
moles of Mg = mass of Mg / molar mass of Mg
moles of Mg = 28.2 g / 24.31 g/mol
moles of Mg = 1.16 mol
According to the balanced chemical equation, 2 moles of Mg produce 2 moles of MgO. Therefore, we can use the mole ratio to calculate the moles of MgO formed:
moles of MgO = moles of Mg x (2 moles of MgO / 2 moles of Mg)
moles of MgO = 1.16 mol x 1
moles of MgO = 1.16 mol
Finally, we can convert the moles of MgO to grams using its molar mass:
molar mass of MgO = 40.31 g/mol
mass of MgO = moles of MgO x molar mass of MgO
mass of MgO = 1.16 mol x 40.31 g/mol
mass of MgO = 46.7 g
Therefore, when 28.2 grams of Mg is burned, 46.7 grams of MgO will be formed.
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Strychnine, a deadly poison, has a molecular mass of 334 g/mol and a percentage composition of 75.45% carbon, 6.59% hydrogen, 8.38% nitrogen, and the balance oxygen. What is the molecular formula of strychnine?
The molecular formula of the strychnine, given that it is composed of 75.45% carbon, 6.59% hydrogen, 8.38% nitrogen, and the balance oxygen is C₂₁H₂₂N₂O₂
How do i determine the molecular formula?First, we shall obtain the empirical formula of compound. Details below:
Carbon (C) = 75.45%Hydrogen (H) = 6.59%Nitrogen (N) = 8.38%Oxygen (O) = 100 - (75.45 + 6.59 + 8.38) = 9.58%Empirical formula =?Divide by their molar mass
C = 75.45 / 12 = 6.2875
H = 6.59 / 1 = 6.59
N = 8.38 / 14 = 0.5986
O = 9.58 / 16 = 0.59875
Divide by the smallest
C = 6.2875 / 0.5986 = 10.5
H = 6.59 / 0.5986 = 11
N = 0.5986 / 0.5986 = 1
O = 0.59875 / 0.5986 = 1
Multiply through by 2 to express in whole number
C = 10.5 × 2 = 21
H = 11 × 2 = 22
N = 1 × 2 = 2
O = 1 × 2 = 2
Thus, we can conclude that the empirical formula is C₂₁H₂₂N₂O₂
Now, we shall determine the molecular formula of strychnine. Details below
Empirical formula = C₂₁H₂₂N₂O₂Molar mass of compound = 334 g/molMolecular formula =?Molecular formula = empirical × n = mass number
[C₂₁H₂₂N₂O₂]n = 140.22
[(12×21) + (1×22) + (14×2) + (16×2)]n = 334
334n = 334
Divide both sides by 334
n = 334 / 334
n = 1
Molecular formula = [C₂₁H₂₂N₂O₂]n
Molecular formula = [C₂₁H₂₂N₂O₂]1
Molecular formula = C₂₁H₂₂N₂O₂
Thus, we can conclude that the molecular formula of strychnine is C₂₁H₂₂N₂O₂
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If the amount of solute present in a solution at a given temperature is less than the maximum amount that can be dissolved at that tempature the solution is said to be
Answer:
Unsaturated
Explanation:
A solution is unsaturated when it contains less than the maximum amount of solute that is capable of being dissolved.
d. Given this law, 4 of 4.
Select Choice
of hydrogen (H2) is produced in the following reaction.
Zn + 2HCl → ZnCl2 + H2
65 g 72 g 135 g ?
The mass of hydrogen produced in the reaction is 2g.
What is Mole?The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.
A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.
Given,
Mass of Zn = 65g
Mass of HCl = 72g
Moles of Zn = mass / molar mass
= 65 / 65 = 1 mole
Moles of HCl = 72 / 36.5
= 1.97 moles
Since moles of Zn is lesser, therefore it is the limiting reagent.
From the reaction, 1 mole of Zn gives 1 mole of hydrogen
Moles of hydrogen = 1 mole
mass of hydrogen = moles × molar mass
= 1 × 2 = 2g
Therefore, the mass of hydrogen produced in the reaction is 2g.
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Which of the following statements confirms the law of conservation of energy?
Statement that shows that the total energy of a system remains constant and is conserved would confirm the law of conservation of energy.
What is law of conservation?
The law of conservation of energy states that energy cannot be created or destroyed, only transformed from one form to another. Therefore, any statement that shows that the total energy of a system remains constant and is conserved would confirm the law of conservation of energy.
Here are some examples of statements that confirm the law of conservation of energy:
The total energy of a closed system, such as a roller coaster, remains constant as the coaster moves from one point to another. Even though the potential energy of the coaster decreases as it goes downhill and the kinetic energy increases, the total energy of the coaster (potential plus kinetic) remains constant.When a pendulum swings back and forth, the potential energy is converted into kinetic energy and back again, but the total energy of the pendulum remains constant.In a chemical reaction, the total energy of the reactants is equal to the total energy of the products. Although energy can be released or absorbed during the reaction, the total energy of the system is conserved.When a ball is thrown into the air, it gains potential energy as it rises and loses potential energy as it falls back down. However, the total energy of the ball (potential plus kinetic) remains constant, neglecting air resistance.All of these statements confirm the law of conservation of energy by showing that the total energy of a system is conserved over time.
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Complete question is: "The total energy of a system remains constant and is conserved" statement would confirm the law of conservation of energy.
what element has 68 degrees Celsius
Isoprenol (C₅H₁₀O) can be produced from isobutene (C₄H₈) and formaldehyde (CH₂O) via the following reaction scheme. What is the change in enthalpy in kJ associated with the production of 155.3 g C₅H₁₀O (isoprenol)?
C₄H₈(g) + CH₂O(g) → C₅H₁₀O(l) ∆H = -191.3 kJ
To determine the change in enthalpy associated with the generation of 155.3 g of [tex]C_5H_1_0O[/tex] we must first calculate the moles of [tex]C_5H_1_0O[/tex] produced using its molar mass.
The molar mass of C₅H₁₀O is:
5(12.01 g/mol) + 10(1.01 g/mol) + 16.00 g/mol = 88.15 g/mol
Moles of C₅H₁₀O produced:
155.3 g / 88.15 g/mol = 1.763 mol C₅H₁₀O
The balanced chemical equation states that the formation of 1 mol of C₅H₁₀O results in an enthalpy change of -191.3 kJ.
As a result, the enthalpy change during the formation of 1.763 mol of C₅H₁₀O is: -191.3 kJ/mol x 1.763 mol = -337.8 kJ
The enthalpy change for the production of 155.3 g of C5H10O is -337.8 kJ.
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A sample of air occupies 0.75 L at standard conditions. What is the pressure in atm if the volume is 100.0 mL at 25oC?
P1 = 760 mmHg P2 = ?
V1 = 0.750 L V2 = 100.0 mL
T1 = 273 K T2 = 25oC
According to the ideal gas law, a gas's pressure is inversely related to its volume and directly proportionate to its temperature. So, if a gas sample's volume is reduced, the gas sample's pressure must also increase.
As a result, in order to determine the pressure of the gas sample under the specified circumstances, we must first determine the ratio of the two volumes before multiplying the starting pressure of the sample by that ratio.
We may get the ratio of the two volumes using the ideal gas law as follows: V2/V1 = (100.0 mL/0.75 L) x (273 K/25oC) = 8.02 As a result, the gas sample's pressure at 25 oC with a volume of 100.0 mL is 8.02 times higher than the sample's original pressure.
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