Where every student offer at least one of the subjects, there are 4 students who offer all three subjects.
To find the number of students who offer only one subject, we can use the formula:
number of students offering only one subject = total number of students offering the subject - number of students offering both subjects
For math, there are 22 students offering math and 5 offering both math and biology, so the number of students offering math only is:
22 - 5 = 17
Similarly, for physics and biology, the numbers of students offering the subjects only are:
14 - 7 = 7 (physics)
16 - 5 = 11 (biology)
To find the number of students offering all three subjects, we can use the formula:
number of students offering all three subjects = total number of students offering at least one subject - number of students offering only one subject in each subject + number of students offering no subject
We know that there are 7 students offering at least one subject. To find the number of students offering no subject, we can subtract this from the total number of students:
39 - 7 = 32
Now we can plug in the numbers:
number of students offering all three subjects = 7 - 17 - 7 - 11 + 32
= 4
Therefore, there are 4 students who offer all three subjects.
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Sariah has just begun training for a half-marathon, which is Latex: 13. 1 13. 1 miles. Since she was on vacation, she started the training program later than the rest of her running club. There are Latex: 6 6 weeks of training runs remaining before the race. In her first week of training, Sariah ran Latex: 3 3 miles. She ran Latex: 4. 5 4. 5 miles the second week and Latex: 6 6 miles the third week. If she continues to increase the length of her runs the same way, will there be enough time left in the training program for her to get up to half-marathon distance?
If she continues to increase the length of her runs the same way, it will not be enough to reach the half-marathon distance of 13.1 miles within the remaining time of the training program.
Sariah has just begun training for a half-marathon, which is 13.1 miles. There are 6 weeks of training runs remaining before the race. In her first week of training, Sariah ran 3 miles. She ran 4.5 miles the second week and 6 miles the third week.
To determine if there is enough time left in the training program for her to get up to half-marathon distance, let's analyze the pattern of her weekly increases in distance:
Week 2 - Week 1 = 4.5 miles - 3 miles = 1.5 miles increase
Week 3 - Week 2 = 6 miles - 4.5 miles = 1.5 miles increase
Sariah is consistently increasing her weekly mileage by 1.5 miles. With 3 weeks of training already completed, she has 3 more weeks to go. Let's see if she can reach the half-marathon distance of 13.1 miles:
Week 4: 6 miles + 1.5 miles = 7.5 miles
Week 5: 7.5 miles + 1.5 miles = 9 miles
Week 6: 9 miles + 1.5 miles = 10.5 miles
After 6 weeks of training, Sariah will have increased her longest run to 10.5 miles. Unfortunately, this is not enough to reach the half-marathon distance of 13.1 miles within the remaining time of the training program.
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The diameter of a circle is 2 kilometers. What is the circle's circumference? d=2 km Use 3. 14 for . Kilometers?
The circumference of the circle is 6.28 kilometers if the diameter of the circle is 2 kilometers and assuming the value of π is 3.14 kilometers.
The diameter of the circle = 2 kilometers
The circumference of a circle is calculated by using the formula,
C = π *d
where,
C = circumference of a circle
d = diameter of the circle
π = Constant value = 3. 14 Km
Substituting the above-given values into the equation, we get:
C = π*d
C = 3.14 x 2 km
C = 6.28 km
Therefore, we can conclude that the circumference of the circle is 6.28 kilometers.
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The three busiest airports in Europe are in London England ; Paris, France; and Frankfurt, Germany. The airport in London has 12.9 million more arrivals and departures than the Frankfurt airport. The Paris airport has 5.2 million more arrivals and departures than the Frankfurt airport. Write the sum of the arrivals and departures from these three cites as a simplified algebraic expression. Let x be the number of the arrivals and departures at the Frankfurt airport.(Source:Association of European Airline).
The sum of the arrivals and departures from these three cities is 3x + 18.1 million.
How to determine the sum of the arrivals and departures from these three citiesIf we let x be the number of arrivals and departures at Frankfurt airport, then the number of arrivals and departures at London airport is x + 12.9 million
The number of arrivals and departures at Paris airport is x + 5.2 million.
The sum of the arrivals and departures from these three cities is:
x + (x + 12.9 million) + (x + 5.2 million)
Simplifying this expression, we can combine like terms:
3x + 18.1 million
Therefore, the sum of the arrivals and departures from these three cities is 3x + 18.1 million.
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A 3-inch candle burns down in 3 hours. At what rate does the candle burn, in inches per hour?
Answer 1 inch per hour
Step-by-step explanation:
Answer:
1 inch per hour
Step-by-step explanation:
Let x represent inches burned per hour
The equation to finding the rate of the candle burning:
3x=3
For those who dont know, whenever you have a variable with a term, its basically multiplying, and we want to do the opposite to get x by itself, so we divide
x=3/3
Which can be simplified as:
x=1
Where x is the inches burned per hour, which equal 1
The function f(x) = –2x^3 + 39x^2 -216x + 6 has one local minimum and one local maximum.
The function f(x) = –2x^3 + 39x^2 -216x + 6 has one local minimum at x = 4 and one local maximum at x = 9.
To determine if the function f(x) = –2x^3 + 39x^2 -216x + 6 has a local minimum or maximum, we need to find the critical points of the function and then determine the nature of those critical points.
First, we take the derivative of the function to find the critical points:
f(x) = –2x^3 + 39x^2 -216x + 6
f'(x) = –6x^2 + 78x - 216
f'(x) = –6(x^2 - 13x + 36)
f'(x) = –6(x - 4)(x - 9)
Setting f'(x) = 0, we get:
–6(x - 4)(x - 9) = 0
This gives us two critical points at x = 4 and x = 9.
To determine the nature of these critical points, we need to look at the sign of the derivative on either side of each critical point.
When x < 4, we have:
f'(x) = –6(x^2 - 13x + 36) < 0
When 4 < x < 9, we have:
f'(x) = –6(x^2 - 13x + 36) > 0
When x > 9, we have:
f'(x) = –6(x^2 - 13x + 36) < 0
This means that f(x) is decreasing on the interval (–∞, 4), increasing on the interval (4, 9), and decreasing on the interval (9, ∞). Therefore, we have a local minimum at x = 4 and a local maximum at x = 9.
To confirm this, we can evaluate the function at these critical points:
f(4) = –2(4)^3 + 39(4)^2 -216(4) + 6 = –26
f(9) = –2(9)^3 + 39(9)^2 -216(9) + 6 = 603
Therefore, the function f(x) = –2x^3 + 39x^2 -216x + 6 has one local minimum at x = 4 and one local maximum at x = 9.
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1 Let us consider the series (n + 16)(n+18) Note: Write the exact answer not the decimal approximation (for example write not 0.8). Answer: (0) Let {sn} be the sequence of partial sums. Then 35 2n+32 Osn = 1/2 306 n2+35n+306 32 2n+32 306 72 +32n+306 O Sn = n Osn= ( 35 306 2n+35 12+35n+306 O Sn = 32 306 2n+32 72 +32n+306 (i) If s is the sum of the series then S =
S = lim[n → ∞] sn
= lim[n → ∞] (306n^2 + 35n + 306)
= ∞
So unfortunately, the series (n + 16)(n + 18) diverges to infinity and does not have a finite sum.To find the sum S of the series (n + 16)(n + 18), we need to take the limit of the sequence of partial sums as n approaches infinity. So let's first find the formula for the nth partial sum sn:
sn = (1 + 16)(1 + 18) + (2 + 16)(2 + 18) + ... + (n + 16)(n + 18)
= ∑[(k + 16)(k + 18)] (from k = 1 to n)
Using the formula for the sum of squares, we can expand each term in the sum:
(k + 16)(k + 18) = k^2 + 34k + 288
So now we have:
sn = ∑(k^2 + 34k + 288) (from k = 1 to n)
= ∑k^2 + 34∑k + 288n (from k = 1 to n)
= n(n + 1)(2n + 1)/6 + 34n(n + 1)/2 + 288n
= 306n^2 + 35n + 306
Now we can take the limit of sn as n approaches infinity to find S:
S = lim[n → ∞] sn
= lim[n → ∞] (306n^2 + 35n + 306)
= ∞
So unfortunately, the series (n + 16)(n + 18) diverges to infinity and does not have a finite sum.
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Los lados de un triangulo miden, en cm, tres numeros enteros consecutivos. Encuentra la longitud de los tres lados
There are infinitely many possible solutions for the lengths of the three sides of the triangle.
What is triangle?
A triangle is a three-sided polygon with three angles. It is a fundamental geometric shape and is often used in geometry and trigonometry.
If we call x the length of the smallest side, then the other two sides are x+1 and x+2 (since they are three consecutive integers). According to the triangle inequality, the sum of any pair of sides must be greater than the length of the third side.
Therefore, we have:
x + (x+1) > (x+2) (and also x + (x+2) > (x+1) and (x+1) + (x+2) > x)
Simplifying each inequality, we get:
2x + 1 > x + 2 (and also 2x + 2 > x + 1 and 2x + 3 > x)
Which gives:
x > 1
So the smallest side must be greater than 1 cm.
Now, to find the length of the three sides, we can choose any value greater than 1 for x. For example, if we take x=2, then the three sides are:
2 cm, 3 cm, and 4 cm
If we take x=3, then the three sides are:
3 cm, 4 cm, and 5 cm
And so on. Therefore, there are infinitely many possible solutions for the lengths of the three sides of the triangle.
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Suppose that you are gambling at a casino. Every day you play at a slot machine, and your goal is to minimize your losses. We model this as the experts problem. Every day you must take the advice of one of n experts (i. E. A slot machine). At the end of each day t, if you take advice from expert i, the advice costs you some c t i in [0, 1]. You want to minimize the regret R, defined as:
To minimize your losses while gambling at a casino and playing slot machines, you need to minimize your regret R in the experts problem. R is defined as the difference between your total cost and the best expert's cost.
To minimize R, follow these steps:
1. Begin by assigning equal weight to each expert (slot machine).
2. After each day t, observe the cost c_ti for each expert i.
3. Update the weights by multiplying them by (1 - c_ti), making sure they remain non-negative.
4. Normalize the weights so they sum up to 1.
5. On day t+1, choose the expert with the highest weight to take advice from.
By following this adaptive strategy, you will minimize your regret R, allowing you to reduce your losses while gambling at the slot machines.
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Two circles, which are tangent externally, are inside and internally tangent to a third circle of radius 1. A diameter of the third circle is a common tangent of the two circles with one point of tangency at its midpoint. What are the radii of the first two circles?
Answer: That made no sense
Step-by-step explanation:
What is the inverse of y = 2^(x - 3)?
show how you got the answer
Answer:
(3-x)^2=y
Step-by-step explanation:
A hot water pipe needs to be insulated to prevent heat loss. The outer pipe has a diameter D = 48.7 cm (correct to 3 significant figures). The inner pipe has a diameter d = 19.25 cm (correct to 2 decimal places). Work out the upper and lower bound of the cross-sectional area of the insulation, A (the shaded area between the inner and outer pipes) in cm2 to the nearest whole number. Give your answer in interval form, using A as the variable.
The upper and lower bound of the cross-sectional area of the insulation, would be A = [ 3129, 3137 ] cm².
How to find the upper and lower bond ?The upper and lower bound of A would be found by the formula :
A = π x ( R ² - r ² )
The upper bound is therefore:
= π x (( 48. 75 / 2) ² - ( 19.2 45 / 2) ²)
= π x ( 1183. 0625 - 184. 857025 )
= π x 998. 205475
= 3, 137 cm²
The lower bound will then be:
= π x ( ( 48. 65 / 2 ) ²- (19. 255 / 2) ²)
= π x ( 1180. 9225 - 184. 963025)
= π x 995. 959475
= 3, 129 cm²
The interval form is therefore A = [ 3129, 3137 ] cm²
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(−3m
5
)(−2m
4
)=left parenthesis, minus, 3, m, start superscript, 5, end superscript, right parenthesis, left parenthesis, minus, 2, m, start superscript, 4, end superscript, right parenthesis, equals
The solution to the equation is m = 0.
What is an algebraic expression?
An algebraic expression is a mathematical phrase that contains variables, constants, and mathematical operations. It may also include exponents and/or roots. Algebraic expressions are used to represent quantities and relationships between quantities in mathematical situations, often in the context of problem-solving.
To solve the equation:
(-3m^ {5}) (-2m^ {4}) = (-6m^ {9})
We can simplify the left side of the equation by multiplying the terms:
(-3m^ {5}) (-2m^ {4}) = (6m^ {9})
Now we have:
6m^ {9} = (-6m^ {9})
To solve for m, we can divide both sides by 6m^ {9}:
m^ {9} = -m^ {9}
Since the powers of m on both sides are equal, we can simplify to:
2m^ {9} =0
Dividing both sides by 2, we get:
m^ {9} =0
Taking the ninth root of both sides, we get:
m = 0
Therefore, the solution to the equation is m = 0.
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Complete Question:
Simplify the expression: $(-3m^ {5}) (-2m^ {4}) $.
Students measured the length of several pencils and recorded their data in a table.
Pencil Lengths (Inches)
3
7
8
,
5
1
4
,
4
,
6
1
8
,
4
1
2
,
5
1
4
,
3
1
2
,
5
3
8
,
4
3
4
,
5
The students will make a line plot of the data. They will use only one fraction in their scale. They must be able to plot all of the data above a label. Which should this fraction be?
Step-by-step explanation:
To determine the appropriate fraction for the line plot, we need to find the greatest common factor (GCF) of all the pencil lengths, and then express each length as an equivalent fraction with the GCF as the denominator.
The GCF of the pencil lengths is 1. Therefore, we can simply express each pencil length as an equivalent fraction with 1 as the denominator:
3/1, 7/1, 8/1, 5/1, 1/1, 4/1, 6/1, 8/1, 4/1, 2/1, 5/1
Now, we can see that the smallest unit increment we can use on the line plot is 1/8. This is because 1/8 is the smallest fraction that can represent all of the pencil lengths above the label (5/8, which is equivalent to 10/16).
Therefore, the students should use 1/8 as the fraction for the line plot.
If Ethan’s monthly expenses are $1160 and his debt to income ratio is 0. 8, what is his monthly salary?
Ethan's monthly salary is $1450.
Ethan's monthly salary, we can use the debt to income ratio formula, which is calculated by dividing monthly debt expenses by monthly income.
Given:
Monthly expenses = $1160
Debt to income ratio = 0.8
Let's assume Ethan's monthly salary as S.
We can set up the equation using the debt to income ratio formula:
Debt to income ratio = Monthly expenses / Monthly income
0.8 = $1160 / S
To solve for S (monthly salary), we can rearrange the equation:
S = $1160 / 0.8
Dividing $1160 by 0.8 gives us:
S ≈ $1450
Therefore, Ethan's monthly salary is approximately $1450.
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What is the graph of g?
Answer:
Vertical Compression by factor of 1/4
Step-by-step explanation:
Two methods:
Method 1. Transformations
Method 2. Algebraic input-output tables
Method 1. Transformations
The Main concept of this question is about Transformations of functions -- specifically, multiplying on the outside by a positive number less than 1.
The transformation that occurs when multiplying a function by a positive number on the outside of the function is a vertical stretch or compression.
Positive numbers larger than 1 will stretch it vertically, whereas positive numbers smaller than 1 will compress it vertically.
Therefore, multiplying by 1/4 on the outside, a positive number less than 1, will vertically compress the function down to one-fourth the size.
This means that for g(x), all points on the original function f will have their heights reduced to 1/4 their original height (or depth) -- making all points on g(x) 1/4 their previous distance from the x-axis on the "f" function.
Method 2. Algebraic input-output tables
Observe on the graph three points on the function f:
(0,0), (1,4) and (3,0) --- points on the function "f"In function notation, this means [tex]f(0)=0[/tex], [tex]f(1)=4[/tex], and [tex]f(3)=0[/tex]Using the equation relating f and g, [tex]g(x)=\frac{1}{4}f(x)[/tex], we can find how those points would look like on the new function g(x).
For [tex]f(0)=0[/tex]
[tex]g(0)=\frac{1}{4}[f(0)]\\g(0)=\frac{1}{4}[0]\\g(0)=0[/tex]
For [tex]f(1)=4[/tex]
[tex]g(1)=\frac{1}{4}[f(1)]\\g(1)=\frac{1}{4}[4]\\g(1)=1[/tex]
For [tex]f(3)=0[/tex]
[tex]g(3)=\frac{1}{4}[f(3)]\\g(3)=\frac{1}{4}[0]\\g(3)=0[/tex]
These known points should correctly identify the graph from the possible choices.
what is the volume of a cylinder, in cubic feet, with. height of 7 inches and a base diameter of 18ft
148.35 cubic feet is the volume of a cylinder with height of 7 inches and a base diameter of 18ft
We have to find the volume of a cylinder
V=πr²h
h is the height of cylinder and r is radius of the base.
Given height is 7 inches which is 0.583333 feet
Diameter is 18 ft
Radius is 9 ft
Now plug in value of height and radius
Volume=π(9)²×0.5833
=3.14×81×0.5833
=148.35 cubic feet
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The Greens bought a condo for $110,000 in 2005. If its value increases at 6% compounded annually, what will the value be in 2020?
Answer:
$264,000
Step-by-step explanation:
PV = $110,000
i = 6%
n = 15 years
Compound formula:
FV = PV (1 + i)^n
FV = 110,000 (1 + 0.06)^15
FV = 110,000 · 2.40(rounded) = $264,000
Question 7 2 pts 1 Details 2 Some value of f(a) and f'() are given in the table. If no value is given, then you should assume that the value exists but is unknown. 4 5 6 f(x) 1 ') 1 DNE 2 Which of the following might be a graph of y = f(x)? O a o o a
The direction of the vector is (-5, -8).
How to calculate the direction ?To find the direction in which the function is increasing most rapidly at point P(2, -1),
we need to find the gradient vector of the function at that point.
The gradient vector of the function f(x, y) = xy^2 - yx^2 is given by:
∇f(x, y) = ( ∂f/∂x , ∂f/∂y ) = ( y^2 - 2xy , 2xy - x^2 )
So, at point P(2, -1), we have:
∇f(2, -1) = ( (-1)^2 - 2(2)(-1) , 2(2)(-1) - 2^2 ) = (-5, -8)
The direction of greatest increase is in the direction of the gradient vector.
So, the direction in which the function is increasing most rapidly at point P(2, -1) is in the direction of the vector (-5, -8).
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You and a group of friends are off to have a day of fun! Before you head out on your adventure, you need to choose a mode of transportation to get to your destinations. The four different transportation choices are represented by the functions below. Decide which method of transportation you would like to use for the day. Use your choice to answer the questions that follow.
1. Which mode of transportation did you choose? Why?
The mode of transportation that I will choose is motorized scooter this is because it is relatively cheap when compared to the other forms of transportation.
What is the forms of transportation?A motorized scooter could be a moderately cheap mode of transportation compared to other alternatives such as cars, cruisers, or indeed bikes.
The starting price of obtaining a motorized bike is for the most part lower than that of a car or cruiser, and the continuous costs such as fuel, support, and protections are too ordinarily lower.
From the question, you can see that the price of the scooter at 5 miles is $10 and it is relatively cheap when compared to the rest.
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What is the volume of the composite figure if both the height and the diameter of the cylinder are 3. 5 feet? Give the exact answer and approximate to two decimal places
The exact volume of the composite figure with a cylinder of height and diameter 3.5 feet and a hemisphere on top is 49.92 cubic feet.
How to find the volume?To find the volume of the composite figure, we need to add the volumes of the cylinder and the hemisphere on top of it.
The formula for the volume of a cylinder is:
V_cylinder = π[tex]r^2[/tex]h
where r is the radius of the cylinder and h is its height.
The formula for the volume of a hemisphere is:
V_hemisphere = (2/3)π[tex]r^3[/tex]
where r is the radius of the hemisphere.
In this case, the diameter of the cylinder is given as 3.5 feet, so the radius is half of that, or 1.75 feet. The height of the cylinder is also given as 3.5 feet. Therefore, the volume of the cylinder is:
V_cylinder = π(1.75[tex])^2[/tex](3.5) ≈ 32.67 cubic feet
To find the volume of the hemisphere, we need to first find its radius. Since the diameter of the cylinder is also the diameter of the hemisphere, the radius of the hemisphere is also 1.75 feet. Therefore, the volume of the hemisphere is:
V_hemisphere = (2/3)π(1.75[tex])^3[/tex] ≈ 17.25 cubic feet
Finally, we add the volumes of the cylinder and hemisphere to get the total volume of the composite figure:
V_total = V_cylinder + V_hemisphere
≈ 32.67 + 17.25
= 49.92 cubic feet
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The grass in the backyard
of a house is a square
with side length 10 m. A
square patio is placed in
the centre. If the side
length, in metres, of the patio is x, then the
area of grass remaining is given by the
relation A=-x^2+100
The problem presents a scenario where a square patio is placed in the centre of a 10m x 10m square backyard. The side length of the patio is given by x, and the remaining area of grass is expressed as A=-x^2+100.
To find the area of grass remaining, we can substitute different values of x into the equation.
For instance, if the patio is 5m x 5m, then x = 5 and the area of grass remaining is[tex]A = -5^2 + 100 = 75[/tex] square metres. Similarly, if the patio is 8m x 8m, then x = 8 and the area of grass remaining is [tex]A = -8^2 + 100 = 36[/tex] square metres.
As we can see, the area of grass remaining decreases as the size of the patio increases.
This problem illustrates the concept of content loaded and content remaining, where the initial content is the entire area of the square backyard, and the loaded content is the area of the square patio.
The remaining content is what is left after the loaded content is subtracted from the initial content. In this case, the loaded content is the patio area, and the remaining content is the grass area.
In summary, the area of grass remaining in the backyard after a square patio is placed in the centre can be calculated using the equation [tex]A=-x^2+100,[/tex] where x is the side length of the patio in metres.
The concept of content loaded and content remaining is also illustrated in this problem, where the loaded content is the patio area and the remaining content is the grass area.
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A cyclist went out for a solo ride but has become lost. He knows from his inexpensive cycletracker GPS the distance he has traveled and in which direction, but he has no idea how to get home short of retracing his path. The different legs of his trip are listed below.
Determine in which direction and how far he needs to ride to get back where he started in the shortest distance possible. (assume there are no obstacles in his way and he can travel in a straight line) (5 marks)
Leg #1-8 km [North]
Leg #2-10 km [East]
Leg #3-12 km [15 S of East]
Leg #4-14 km [South]
The cyclist needs to ride approximately 23.21 km in the direction of 23.13° W of North to get back to the starting point.
How to solve for the distanceWe can use trigonometry to find the x and y components.
x3 = 12 * cos(15°) ≈ 11.59 km (east)
y3 = -12 * sin(15°) ≈ -3.10 km (south, hence the negative sign)
Leg #4: 14 km [South]
x4 = 0 km (no east/west movement)
y4 = -14 km (south, hence the negative sign)
Now, let's find the total x and y displacements:
x_total = x1 + x2 + x3 + x4 ≈ 0 + 10 + 11.59 + 0 ≈ 21.59 km
y_total = y1 + y2 + y3 + y4 ≈ 8 + 0 - 3.10 - 14 ≈ -9.10 km
Now, we can find the distance and direction he needs to ride to get back to the starting point:
Distance=
[tex]\sqrt{21.59^2 + (-9.10)^2}[/tex])
23.21 km
Direction:
angle =
arctan(9.10 / 21.59)
= 23.13°
The cyclist needs to ride approximately 23.21 km in the direction of 23.13° W of North to get back to the starting point.
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1/2 (7)(4) + 6(5)=
I can not figure this out! Can you answer with middle school techniques?
The value of the given expression is 44. The solution has been obtained by using the arithmetic operations.
What are arithmetic operations?
The four basic operations, also referred to as "arithmetic operations," are thought to explain all real numbers. Operations like division, multiplication, addition, and subtraction come before operations like quotient, product, sum, and difference in mathematics.
We are given an expression as [tex]\frac{1}{2}[/tex] (7) (4) + 6 (5).
We know that when there is no sign in between two numbers, it denotes multiplication.
So, we get
⇒ [tex]\frac{1}{2}[/tex] * (7) * (4) + 6 * (5)
⇒ 14 + 30
⇒ 44 (Using addition operation)
Hence, the value of the given expression is 44.
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Use the image to determine the direction and angle of rotation.
Graph of triangle ABC in quadrant 1 with point A at 1 comma 3. A second polygon A prime B prime C prime in quadrant 4 with point A prime at 3 comma negative 1.
90° clockwise rotation
180° clockwise rotation
180° counterclockwise rotation
90° counterclockwise rotation
The rotation used in this problem is given as follows:
90º clockwise rotation.
What are the rotation rules?The five more known rotation rules are given as follows:
90° clockwise rotation: (x,y) -> (y,-x)90° counterclockwise rotation: (x,y) -> (-y,x)180° clockwise and counterclockwise rotation: (x, y) -> (-x,-y)270° clockwise rotation: (x,y) -> (-y,x)270° counterclockwise rotation: (x,y) -> (y,-x)A vertex and it's equivalent is given as follows:
A(1,3) and A'(3, -1).
Hence the rule is:
(x,y) -> (y, -x).
Which is the rule for a 90° clockwise rotation = 270º counterclockwise rotation.
Missing InformationThe image is presented at the end of the answer.
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Answer:
90° clockwise rotation
Step-by-step explanation:
I did the exam and got it correct
Each day three church bells are rung in a random order. what is the probability that the smallest bell rings first three days in a row?
The probability that the smallest bell rings the first three days in a row is 1/27. when Each day three church bells are rung in a random order
In the given data there are 3 bells in the church in which there is a small bell and the three bells are rung in a random order. we need to find the probability that the smallest bell rings the first three days in a row.
The probability that the smallest bell rings on any given first day can be given as = 1/3
Because there are three bells and each bell has an equal chance of being rung first. The probability that this happens three days in a row is given as
= (1/3) × (1/3) × (1/3)
= 1/27
Therefore, the probability that the smallest bell rings the first three days in a row is 1/27
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Find the measure of Tu in the photo
The value of the tangent TU for the circle with secant through U which intersect the circle at points V and W is equal to 12
What are circle theoremsCircle theorems are a set of rules that apply to circles and their constituent parts, such as chords, tangents, secants, and arcs. These rules describe the relationships between the different parts of a circle and can be used to solve problems involving circles.
For the tangent TU and the secant through U which intersect the circle at points V and W;
TU² = UV × VW {secant tangent segments}
(5x)² = 9 × 16
(5x)² = 144
5x = √144 {take square root of both sides}
5x = 12
x = 12/5
so;
TU = 5(12/5)
TU = 12
Therefore, the value of the tangent TU for the circle with secant through U which intersect the circle at points V and W is equal to 12
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A box contains green marbles and blue marbles. Yosef shakes the box and chooses a marble at random. He records the color, then places the marble back into the box. Yosef repeats the process until he chooses 50 marbles. The table shows the count for each color. Write a probability model for choosing a marble.
green: 36
blue: 14
The probability model for choosing a marble from the box is P(green) = 36/50 and P(blue) = 14/50.
To create this probability model, first, count the total number of marbles chosen, which is 50. Then, count the number of green and blue marbles chosen, which are 36 and 14, respectively.
Divide the number of each color by the total number of marbles to find the probability of choosing a green or blue marble.
P(green) is calculated as 36/50 or 0.72, and P(blue) is calculated as 14/50 or 0.28. This model represents the likelihood of choosing a green or blue marble from the box based on Yosef's experiment.
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Suppose a mouse is placed in the maze at the right. if each desicion about direction is made at random, create a simulation to determine the probability that the mouse will find its way out before coming to a dead end or going out in the opening.
The probability of the mouse finding its way out before reaching a dead end or going out in the opening can be estimated by dividing the number of successful outcomes by the total number of trials in the sample.
To create a simulation to determine the probability that the mouse will find its way out before coming to a dead end or going out in the opening, we can follow these steps:
Create a model of the maze in a programming language such as Python.Define the starting position of the mouse as the position on the right side of the maze.Define the exit position of the maze as the position on the left side of the maze.Randomly choose a direction for the mouse to move in (up, down, left or right).Check if the chosen direction leads to a dead end or out of the maze. If it does, return a failure outcome.If the chosen direction leads to a viable path, move the mouse to that position and repeat steps 4-6 until the mouse either reaches the exit or gets stuck in a dead end.Repeat steps 2-6 multiple times to generate a sufficient sample size.Calculate the proportion of successful outcomes (i.e. the mouse finding its way out before reaching a dead end or going out in the opening) from the generated sample.The probability of the mouse finding its way out before reaching a dead end or going out in the opening can be estimated by dividing the number of successful outcomes by the total number of trials in the sample. This simulation approach can help us understand the probability of success in a random maze environment, and also explore the impact of various factors such as maze complexity, size and starting position of the mouse on the outcome.
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A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with a = 19. 0 milligrams. Construct a 95% confidence interval for the
true mean cholesterol content,, of all such eggs.
We can say with 95% confidence that the true mean cholesterol content of all such eggs is between 223.99 milligrams and 232.01 milligrams.
To construct a 95% confidence interval for the true mean cholesterol content of all such eggs, we can use the following formula:
CI = X ± Zα/2 * σ/√n
where:
X = sample mean = 228 milligrams
Zα/2 = the critical value from the standard normal distribution corresponding to a 95% confidence level, which is 1.96
σ = population standard deviation = 19.0 milligrams
n = sample size = 82
Substituting the values into the formula, we get:
CI = 228 ± 1.96 * 19.0/√82
= 228 ± 4.01
= (223.99, 232.01)
Therefore, we can say with 95% confidence that the true mean cholesterol content of all such eggs is between 223.99 milligrams and 232.01 milligrams.
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A radioactive isotope is decaying at a rate of 18% every hour. Currently there
are 120 grams of the substance.
Write an equation that will represent the number of grams, y, present after
hours.
=
Can you tell me the answer please
The decay of the radioactive substance can be modeled by the exponential decay function:
y = a(1 - r)^t
where:
- y is the amount of substance present after t hours
- a is the initial amount of substance (in grams), which is 120 grams in this case
- r is the decay rate per hour, which is 18% or 0.18 in decimal form
- t is the time elapsed in hours
Plugging in the values we get:
y = 120(1 - 0.18)^t
Simplifying:
y = 120(0.82)^t
So this is the equation that represents the number of grams, y, present after t hours, given the initial amount of 120 grams and a decay rate of 18% per hour.
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