Answer:
The velocity of the center of mass (Vcm) of a system of particles can be calculated using the formula:
Vcm = (m1v1 + m2v2 + m3v3 + ... + mnvn) / (m1 + m2 + m3 + ... + mn)
where m1, m2, m3, ... mn are the masses of the particles and v1, v2, v3, ... vn are their velocities.
In this problem, we have three particles with masses of 20g, 30g, and 50g and velocities of 2i, 10j, and 10k respectively. We can convert the masses to kg to make the calculations easier:
m1 = 20g = 0.02kg
m2 = 30g = 0.03kg
m3 = 50g = 0.05kg
Using the formula above, we can calculate the velocity of the center of mass:
Vcm = (m1v1 + m2v2 + m3v3) / (m1 + m2 + m3)
Vcm = (0.02kg * 2i + 0.03kg * 10j + 0.05kg * 10k) / (0.02kg + 0.03kg + 0.05kg)
Vcm = (0.04i + 0.3j + 0.5k) / 0.1kg
Vcm = 0.4i + 3j + 5k m/s
Therefore, the velocity of the center of mass of the three particles is 0.4i + 3j + 5k m/s.
mark me brilliant
How many centimeters is half of a 87.3 km road?
Your result must be in multiples of 108 cm. That means if, for example, you get a result of a
9.2200x108 just type 9.2200 in the answer box. Include four digit after the decimal point and
maximum of 1% of error is accepted in your answer.
Half of 87.3 km is 43.65 km.
To convert km to cm, we need to multiply by 100,000 (since there are 100,000 cm in 1 km).
So, 43.65 km = 43.65 x 100,000 = 4,365,000 cm.
To express the answer in multiples of 108 cm, we need to divide by 108 and round to four decimal places.
4,365,000 cm ÷ 108 = 40,416.6667
Rounding to four decimal places gives us 40.4167.
Therefore, half of an 87.3 km road is approximately 40.4167 x 108 cm.
Mel adjusted, in a futile attempt to strengthen his pectoral muscles, stretches a spring exercise device 0.73 meters by exerting a force of 177N. What is the stiffness constant
In the case, Mel stretches a spring exercise device by 0.73 meters with a force of 177 N. We can use Hooke's law, which states that the force applied to a spring is directly proportional to the displacement of the spring from its equilibrium position, to calculate the stiffness constant.
Hooke's law is given by the equation:
F = kx, where F is the force applied to the spring, k is the stiffness constant, and x is the displacement of the spring from its equilibrium position.
Plugging in the given values:
Force (F) = 177 N Displacement (x) = 0.73 m
We can rearrange the equation to solve for the stiffness constant (k):
k = F / x
Plugging in the values:
k = 177 N / 0.73 m
k ≈ 242.47 N/m (rounded to two decimal places)
Therefore, the stiffness constant of the spring exercise device is approximately 242.47 N/m.
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3.
What is sonography?
using infrasonic waves to communicate long distances
through the ground
using ultrasonic waves to communicate and hunt for prey
MacBook Air
using infrasonic waves to create images of submerged
objects
using ultrasonic waves to create images of objects found
inside other objects
The correct answer is using ultrasonic waves to create images of objects found inside other objects.
What do the terms "infrasonic" and "ultrasonic" mean?Infrasonic Wave: An infrasonic wave is a longitudinal elastic wave whose frequency is lower than that of sound, or 20Hz. For instance: It typically occurs during an earthquake. Ultrasonic Wave: An ultrasonic wave is a longitudinal wave with a frequency greater than the threshold of human hearing, or 20 kHz.
What do ultrasonic and infrasonic waves consist of?The audible range of frequencies below 20 Hz is known as infrasonic. Volcanoes, earthquakes, and thunder all emit sound in the infrasonic range. Human ears cannot hear this sound, but elephants and whales can. Ultrasonic frequencies are those that are above 20,000 Hz.
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A 0.1 kg toy train car moving at 1.0 m/s runs into a stationary car with a mass of 0.15 kg. At what speed do they move off together?
We can use the conservation of momentum principle to solve this problem. According to this principle, the total momentum of a system of objects remains constant if there are no external forces acting on the system. In this case, we can assume that there are no external forces acting on the two cars after they collide, so the total momentum of the system before the collision must be equal to the total momentum of the system after the collision.
The momentum of an object is defined as its mass multiplied by its velocity:
momentum = mass * velocity
Before the collision, the momentum of the first car (m1) is:
p1 = m1 * v1 = (0.1 kg) * (1.0 m/s) = 0.1 kg⋅m/s
Since the second car is stationary, its momentum before the collision is zero:
p2 = m2 * v2 = (0.15 kg) * (0 m/s) = 0 kg⋅m/s
The total momentum of the system before the collision is:
p1 + p2 = 0.1 kg⋅m/s + 0 kg⋅m/s = 0.1 kg⋅m/s
After the collision, the two cars move together with a common velocity (v), so the momentum of the system is:
p = (m1 + m2) * v
We can set the total momentum before the collision equal to the total momentum after the collision:
p1 + p2 = p
0.1 kg⋅m/s + 0 kg⋅m/s = (0.1 kg + 0.15 kg) * v
0.1 kg⋅m/s = 0.25 kg * v
v = 0.1 kg⋅m/s ÷ 0.25 kg
v = 0.4 m/s
Therefore, the two cars move off together at a speed of 0.4 m/s after the collision.
I need help with this problem
If we rank these magnets from the strongest to the weakest magnetic field the correct order is 4, 3, 2, 1.
How does the magnetic field relate to the radius of a magnet?The magnetic field and radius are related in the context of a charged particle moving in a circular path under the influence of a magnetic field. When a charged particle moves in a circular path under the influence of a magnetic field, the force on the particle is directed toward the center of the circle. In this force, the radius can be expressed as r = mv / Bq.
This equation shows that the radius of the circular path is directly proportional to the velocity of the particle, and inversely proportional to the magnetic field strength and the charge of the particle.
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What is the S-P difference (sec)?
What is the amplitude (mm)?
What is the distance (km)?
What is the magnitude (M)?
(a) The S-P difference (sec) is 40 sec.
(b) The amplitude (mm) is 10 mm
(c) The distance (km) is 380 km
(d) The magnitude (M) is 4.5
What is the S-P wave difference (sec)?The S-P wave difference (sec) is a measure used in seismology to determine the distance between a seismic station and an earthquake source.
From the graph, the S-P difference, that is between S and P = 40 s - 0 s
= 40 s
The distance (km) corresponding to 40 sec is 380 km.
The amplitude of the wave is the maximum displacement of the wave and it is equal to 10 mm.
The corresponding magnitude of the wave is 4.5.
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Which of the following is not considered a bloodborne pathogen
Influenza virus is not considered as a bloodborne pathogen. The correct answer is option D.
Bloodborne pathogens are infectious microorganisms that can cause disease when transmitted through contact with infected human blood or other body fluids.
They can include viruses, bacteria, and other microorganisms that can cause serious illness or even death.
Influenza virus is not considered a bloodborne pathogen because it is primarily a respiratory virus that spreads through droplets when an infected person talks, coughs, or sneezes.
It can also spread through contact with contaminated surfaces or objects, but it is not primarily transmitted through contact with blood or other body fluids.
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The probable question may be:
Which of the following is not considered a bloodborne pathogen
A. Hepatitis B virus
B. Human immunodeficiency virus (HIV)
C. Hepatitis C virus
D. Influenza virus
A solution of ethanol is pumped to a vessel 25 m above a reference level through a 25-mm-inside-diameter steel pipe at a rate of 10 m3 /h. The length of pipe is 30 m and contains two elbows with friction equivalent to 20 diameters each. Compute the power requirements of the pump. Solution properties include density of 975 kg/m3 and viscosity of 4 3 1024 Pa s
dx=7.14 m and dy=-7.55 m find the direction
Explanation:
arctan ( -7.55/7.14) = - 46.6 degrees ( or 313.4 degrees)
The pressure difference between two locations is 0.005 Torr .Which one of the following barometers is preferred to measure the small pressures accurately? (knowing that: Density of mercury = 13600 kg/m³, density water = 1000 kg/m³, density of oil = 800 kg/m³
A-Mercuric barometer
B-Oil-water barometer
C-Water barometer
D-Oil barometer
Due to its high density, the mercury barometer is the greatest option for precisely measuring minor changes in pressure. The correct option is A.
A barometer is an instrument used to measure atmospheric pressure. It typically consists of a long glass tube filled with a liquid, usually mercury, and inverted in a container of the same liquid.
The preferred barometer to measure small pressures accurately would be the mercury barometer (option A), because it has a higher density compared to the other options and hence it can detect smaller changes in pressure.
To see why the other options are not as good for measuring small pressures accurately, we can compare their densities:
Oil-water barometer: The density of oil is lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.
Water barometer: The density of water is much lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.
Oil barometer: The density of oil is lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.
Therefore, option A, the mercury barometer, is the best choice for measuring small changes in pressure accurately due to its high density.
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What is the natural period of oscillation of your leg when you march? Compute your velocity? Explain your answer; make comments. (Please use formula and explain with your words clearly)
Electric Electronics Engineering course - Vibrations and Titrations
The natural period of oscillation of a leg when marching is the time it takes for one complete cycle of oscillation. It can be calculated using the formula:
T = 2π √(L/g)
What is the oscillation about?Where T is the natural period of oscillation, L is the length of the leg, and g is the acceleration due to gravity (9.81 m/s^2).
Assuming an average leg length of 1 meter, the natural period of oscillation of a leg is:
T = 2π √(1/9.81) ≈ 0.64 seconds
To compute the velocity of the leg during the march, we can use the formula:
v = 2πL/T
where v is the velocity, L is the length of the leg, and T is the natural period of oscillation.
Substituting the values, we get:
v = 2π(1)/(0.64) ≈ 9.8 m/s
Therefore, This means that during the march, the leg moves back and forth with a velocity of approximately 9.8 meters per second. It's important to note that this calculation assumes a simple harmonic motion, which may not be the case in reality due to the complex motion of various joints and muscles involved in marching.
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1.
A megaphone amplifies sound by
all the above
increasing the range of frequencies that can be produced.
focusing sound energy into one specific direction.
spreading out the sound waves over a large area.
The correct statement explaining how a megaphone amplifies sound is: "A megaphone amplifies sound by focusing sound energy into one specific direction."
How does a loudhailer increase sound volume?By increasing the acoustic impedance perceived by the vocal chords and bringing them into closer proximity to the air, the loudhailer amplifies the sound and increases the amount of sound power that is emitted.
What kind of sound does a loudhailer produce?Many people are familiar with the distinctively distorted sound of a human voice amplified by a loudhailer thanks to its use in train and bus stations and sporting venues. It produces the sound of a vintage acoustic phonograph record player when used with music.
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A block is dropped from rest. It takes a time t, to fall the first third of the distance. How long does it take to fall the entire distance? a) √3t₁ b) 3t₁ c) 9t₁ d) None of the above to = 0 ti t₂ TITI Vo = 0 S₂ = X S₁ = x/3
The time it will take the block to fall the entire distance is (a) √3t₁.
How to determine time in motion?Use the equations of motion to solve this problem. The equation to use is:
S = (1/2)gt²
where S = distance, g = acceleration due to gravity, and t = time.
First find the time it takes to fall the first third of the distance. The distance fallen is S₁ = x/3, so:
x/3 = (1/2)gt₁²
Solving for t₁:
t₁ = √((2x)/(3g))
Now, find the time it takes to fall the entire distance. The total distance is S₂ = x, so:
x = (1/2)gt₂²
Solving for t₂:
t₂ = √((2x)/g)
Substituting x with 3S₁:
t₂ = √((6S₁)/g)
Substituting t₁:
t₂ = √((4x)/(3g)) = √(4/3)t₁
Therefore, the answer is (a) √3t₁.
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When a wave reaches a surface, the new material absorbs all the energy of the wave.
O True
O False
Answer: true
Explanation: if the current element is above the current water level then it is true
PLEASE HELP!!! 25 points
The statement that is true regarding the circuit shown in the question is I₁ > I₃ > I₂ (last option)
How do i know which statement is true?To know the true statement, we shall determine the current flowing through each resistance. Details below:
For resistor 1
Resistance (R₁) = 2 Ω Voltage (V) = 12 V Current (I₁) =?Voltage (V) = Current (I) × resistance (R)
12 = I₁ × 2
Divide both sides by 2
I₁ = 12 / 2
I₁ = 6 A
For resistor 2
Resistance (R₂) = 8 Ω Voltage (V) = 12 V Current (I₂) =?Voltage (V) = Current (I) × resistance (R)
12 = I₂ × 8
Divide both sides by 8
I₂ = 12 / 8
I₂ = 1.5 A
For resistor 3
Resistance (R₃) = 5 Ω Voltage (V) = 12 V Current (I₃) =?Voltage (V) = Current (I) × resistance (R)
12 = I₃ × 5
Divide both sides by 5
I₃ = 12 / 5
I₃ = 2.4 A
From the above calculation, we can see that I₁ > I₃ > I₂.
Thus, we can conclude that the true statement is I₁ > I₃ > I₂ (last option)
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Can the potential of a non uniform charged sphere be the same as that of a point charge? Explain in details
No. The potential of a non-uniform charged sphere cannot be the same as that of a point charge.
Non-uniform charged sphere as a point chargeThe potential at any point in space is determined by the distribution of charge within the system, and a non-uniform charged sphere has a different charge distribution than a point charge.
A point charge has all of its charges concentrated at a single point, while a non-uniform charged sphere has charge distributed throughout its volume.
As a result, the electric field and potential will be different for these two systems, even if they have the same total charge. Therefore, the potential of a non-uniform charged sphere cannot be the same as that of a point charge.
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1. solve this!!! pls help
The angle of arc m RNW is 60°, given that M is the center and RE and AN are diameters.
How to calculate arc angle?Since RE and AN are diameters, we know that ∠REO and ∠ANO are right angles, where O is the center of the circle. Since M is also the center of the circle:
m∠RMO = 180° - m∠RMN = 80°
m∠EMO = 180° - m∠EMW = 140°
Since ∠RMO and ∠EMO share a common vertex and their non-common sides are radii of the circle, they are congruent. Therefore:
m∠RMO = m∠EMO
80° = 140° - m∠RNW
m∠RNW = 60°
So m RNW = 60°.
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Image transcribed:
10.5.5 Your Turn! HOMEWORK
1. In Circle M, m∠RMN = 100° and m∠EMW = 40°. Calculate m RNW given that M is the center and RE and AN are diameters.
What is the S-P difference (sec)?
What is the amplitude (mm)?
What is the distance (km)?
What is the magnitude (M)?
(a) The S-P difference of the wave is determined as is 40 sec.
(b) The amplitude of the wave is determined as is 10 mm
(c) The distance of the wave is determined as is 380 km
(d) The magnitude of the wave is determined as is 4.5
What is amplitude of a wave?The amplitude of a wave is the maximum displacement or distance that a wave moves from its rest position to its crest (the highest point) or trough (the lowest point). In other words, it is the measure of the strength or intensity of a wave.
Question 1:
From the graph, the S-P difference, that is between S and P = 40 s - 0 s
= 40 s
Question 2:
The distance (km) corresponding to 40 sec is 380 km.
Question 3:
The amplitude of the wave is the maximum displacement of the wave and it is equal to 10 mm.
Question 4:
The corresponding magnitude of the wave is 4.5.
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Which of the following occurs when an oscillating spring system reaches its equilibrium position?
The kinetic energy is at its maximum.
The restoring force is at its maximum.
The potential energy is at its maximum.
The velocity is 0.
Answer: Velocity=0
Explanation: At equilibrium the spring system is not moving.
(i) The car starts from rest. From time = 0 to time = 15 s, the car has a constant acceleration to a speed of 28 m/s. From time = 15 s to time = 32 s, the car has a constant speed of 28 m/s. From time = 32 s, the car has a constant deceleration of 2.0 m/s² until it comes to rest. On Fig. 1.1, draw the graph, using the space below for any calculations.
The total distance covered during all three phases is approximately 882.375 m.
How to solveThe car undergoes three phases: initial acceleration, constant speed, and deceleration.
In the first phase, it accelerates at 1.8667 m/s² for 15 seconds, covering 210.375 m.
In the second phase, it travels at a constant 28 m/s for 17 seconds, covering 476 m.
In the final phase, it decelerates at 2 m/s² for 14 seconds, covering 196 m.
The total distance covered during all three phases is approximately 882.375 m.
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What is the inertia of motion?
THE INABILITY OF A BODY TO CHANGE ITS STATE OF MOTION BY ITSELF ⚡
._Its_Ńämüđà_.The tendency of matter to resist changes in its velocity or direction of motion is known as the inertia of motion. One of the cornerstones of traditional mechanics, it is also known as the law of inertia.
What is the inertia of motion? This principle states that, without an external force, an object at rest tends to remain at rest and an object in motion tends to maintain its current speed and direction. This means that until a force acts on the moving item to cause it to modify its motion, it will continue to proceed in a straight path and at a constant speed due to inertia of motion.
An object's mass affects how much inertia of motion it possesses. An object's inertia of motion increases with bulk, making it more challenging to alter its speed or direction of motion. This feature of matter has a wide range of practical uses, including predicting how moving objects will behave and creating and building systems that need to precisely regulate motion and forces.
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Identify how each machine changes the way work is done so as to be useful.
The machine changes how work is done, by making the process easier and increasing output with less effort.
What is a machine?Any device that uses energy to carry out a task is a machine. Machines can be simple, like a lever or pulley, or complex, like a computer or a car engine. The purpose of a machine is to make work easier, faster, or more efficient than it would be without the machine. Different types of energy, including human power, electricity, and fuel, can be used to power machines.
Bicycle: A bicycle is a human-powered machine that allows people to move faster and with less effort than walking or running. A person can travel farther distances faster and with less physical effort by turning the wheels and shifting gears with their pedaling motion.
Ax blade: An ax blade is a cutting tool used for chopping wood. It facilitates the process of splitting wood by utilizing a sharp metal blade to cut through the wood fibers, rather than depending exclusively on physical power to break the wood apart.
Car jack: A car jack is a mechanical device used to lift a car off the ground. A person can raise the car to access the underside for repairs or maintenance by pulling a lever and applying hydraulic pressure. Compared to attempting to lift the car manually, this makes maintenance and repairs easier and safer.
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The graph shows how the speed of a car travelling in a straight line changes with time. Which section shows the largest acceleration? speed A B C D time
The section that shows the largest acceleration on the graph would be section B, as it has the steepest slope.
This indicates that the car is increasing in speed at a faster rate during this section compared to the other sections.
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complete question not found in search engine.
Which of the rays drawn above would be correct as the light goes from the air into the water? (5 points)
A
B
C
Answer:
First option A
Explanation:
Since the light is passing from air (less dense) into water (more dense), it is bends downwards.
The answer above is wrong because like I mentioned light bends when it goes through a medium and option B doesn't match that, so please don't use that answer.
Hope I helped and have a great day ahead.
Ritalin and the pain medication Demerol have a high risk of dependence but may be used for medicinal purposes under a doctor's supervision. These substances are _____ of the CSA list.
Ritalin and Demerol are both controlled substances that have a high risk of abuse and dependence.
What is the list?Schedule II drugs are believed to have a high abuse potential that could lead to severe psychological or physical dependence. They do, however, occasionally have other known medical applications and can be prescribed by a licensed healthcare provider.
Ritalin is an example of a stimulant, whereas Demerol is an example of an opioid. Thus the drugs that have been mentioned here are drugs that are strictly controlled.
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What pressure does a 500N - pound girl produce while standing on the floor if the area of the sole of one of her shoes is 60 cm²?. pleaaasee guysss help meee
The pressure exerted by the girl is approximately 833,333.33 Pa (Pascals).
what happens according to newton if you let an untide ballon go?
The mass of a density bottle is 20g when empty 70g when full of water and 695g when full of another liquid. Calculate the density of the other liquid (take density of water as 1g/cm³ (2mk) Mass of 20cm³ of the liquid ()
Answer:
The answer is 13.5g/cm³
Explanation:
m1=20g
m3=70g
m2=695g
v=20cm³
m2-m1/m3-m1
R.d=695-20/70-20
R.d=675/50
R.d=13.5
R.d=density of liquid/density of water
density of liquid =R.d×density of water
D=13.5×1
D=13.5g/cm³
what is scientific learning
Answer:
the learning which is gained through observation and experimentation
A rifle with a weight of 30 N fires a 5.0-g bullet with a speed of 300 m/s. (a) Find
the recoil speed of the rifle. (b) If a 700-N man holds the rifle firmly against his
shoulder, find the recoil speed of man and rifle.
The recoil speed of the rifle is 0.5 m/s.
Weight of the rifle, W = 30 N
Mass of the rifle, M = W/g = 30/10 = 3 kg
Mass of the bullet, m = 5 g = 5 x 10⁻³kg
Speed of the bullet, v = 300 m/s
a) The expression for the recoil speed of the rifle is given by,
v(r) = mv/M
v(r) = 5 x 10⁻³ x 300/3
v(r) = 0.5 m/s
b) Weight of the man, W' = 700 N
Mass of the man, M' = W'/g = 700/10 = 70 kg
So, the combined mass of the man and the rifle,
M₁ = M + M'
M₁ = 3 + 70
M₁ = 73 kg
Therefore, the recoil speed of man and rifle,
v(r)' = mv/M₁
v(r)' = 5 x 10⁻³ x 300/73
v(r)' = 0.0205 m/s
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