Answer:
A) $102,400
Step-by-step explanation:
For these answers, we must assume the increase is linear.
The two-point form of the equation for a line is ...
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
Filling in the given (x, y) values of (3, 25000) and (23, 68000), we have ...
y = (68000 -25000)/(23 -3)(x -3) +25000
y = 2150x +18,550
Then for x = 39, we find the predicted sales to be ...
y = (2150)(39) +18,550 = 102,400
The predicted sales after 39 months is $102,400.
_____
The graph shows sales in thousands of dollars.
What is the vertex of f(x) = |x+ 8|– 3?
(-8, -3)
(-8,3)
(8, -3)
(8,3)
Answer:
The vertex is at (-8,-3)
Step-by-step explanation:
The function is of the form
y = a|x-h| + k where (h,k) is the vertex
f(x) = |x+ 8|– 3
f(x) = |x - - 8|– 3
The vertex is (-8,-3)
Trey is out shopping and sees that striped shirts are on sale for $25.00 each, and plaid pants are on sale for $22.50 each. He buys 2 shirts and 4 pairs of pants. What is the total of his
purchase?
The total was $______
Answer:
$140
Step-by-step explanation:
You can add up the prices to find the total. Most of us find it easier to multiply the price by the number of items.
cost of 2 shirts = (2)($25.00) = $50
cost of 4 pants = (4)(22.50) = $90
The total was $50 +90 = $140.
The function f determines the volume of the box (in cubic inches) given a cutout length (in inches). Use function notation to represent the volume of the box (in cubic inches) when the cutout length is 0.2 inches. Use function notation to represent the volume of the box (in cubic inches) when the cutout length is 1.3 inches. Use function notation to represent how much the volume of the box (in cubic inches) changes by if the cutout length increases from 0.2 inches to 1.3 inches. Use function notation to represent how much the volume of the box (in cubic inches) changes by if the cutout length increases from 5.5 inches to 5.6 inches.
Complete Question
A box is formed by cutting squares from the four corners of a sheet of paper and folding up the sides. However, the size of the paper is unknown!
Answer:
(a)[tex]f(0.2)=0.2(l-0.4)(w-0.4)[/tex]
(b)[tex]f(1.3)=1.3(l-2.6)(w-2.6)[/tex]
(c)f(1.3)-f(0.2)
(d) f(5.6)-f(5.5)
Step-by-step explanation:
Let the Length of the paper =l (in inches)
Let the Width of the paper =w (in inches)
Let the length of the cutout square = x (in inches)
Base Length of the Box = l-2xBase Width of the box =w-2xHeight of the box =xVolume of the box: [tex]f(x)=x(l-2x)(w-2x)[/tex]
(a)When the cutout length is 0.2 inches.
x=0.2
Volume of the box (in cubic inches) ,
[tex]f(0.2)=0.2(l-0.4)(w-0.4)[/tex]
(b)When the cutout length is 01.3 inches.
x=1.3
Volume of the box (in cubic inches) ,
[tex]f(1.3)=1.3(l-2.6)(w-2.6)[/tex]
(c)If the cutout length increases from 0.2 inches to 1.3 inches.
Change In volume (in cubic inches):
[tex]f(1.3)-f(0.2)\\=1.3(l-2.6)(w-2.6)-0.2(l-0.4)(w-0.4)[/tex]
(d)If the cutout length increases from 5.5 inches to 5.6 inches.
Change In volume (in cubic inches):
[tex]f(5.6)-f(5.5)\\=5.6(l-11.2)(w-11.2)-5.5(l-11)(w-11)[/tex]
Really easy math question!
the answer is A: 146 ≤ 9c + 10
a large which has topics of Capsicum and onion in there in total there are 25 pieces of both on the pizza if there are four times as many onions pieces as capsicum pieces how many pieces of eat vegetable are there on the pizza
Step-by-step explanation:
I think there should be 5 capsicums because
4 times onions = 5 x 4 = 20
Then 5 capsicums = 20 + 5 = 25
Answer:
A large pizza has toppings of capsicum and onion. In total there are 36 pieces of both on the pizza .If there are 5 times as many onions pieces as capsicum pieces,how many of each vegetable are there on the pizza?
Step-by-step explanation:
Can you please help with this one
Math Is TU parallel to VW explain
Answer: C ( yes, both lines have a slope of 2/3. )
Step-by-step explanation:
Answer: C
Step-by-step explanation:
HELP PLEASE!!!!!!!!!!!!!!
Answer:
Savannah
Step-by-step explanation:
Emery has solved it incorrectly;
x = 100
NEED HELP ASP Find the common difference of the arithmetic sequence -8, -15, -22, ...
Answer:
-7
Step-by-step explanation:
To find the differences in a sequence, subtract the term before:
-15 -(-8) = -7
-22 -(-15) = -7
These differences are the same, so constitute the "common" difference.
The common difference of the sequence is -7.
A gumball machine has 100 red gumballs. If the red gumballs are 25% of the total number of gumballs, how many gumballs are in the gumball machine?
Answer: 400
Step-by-step explanation:
25% is equal to one quarter (1/4). If theres 100 red gumballs then there must be 300 more gumballs in the machine because a quarter of a number is always even.
A store has 8 puppies, including 3 poodles, 3 terries, and 2 retrievers. If Rebecca and Jas, in that order, each select one puppy at random without replacement, find the probability that Jas Selects a retriever, given that Rebecca selects a poodle.
Answer:
2/7
Step-by-step explanation:
Since Rebecca is garunteed to pick a poodle, there are 7 puppies left. There are 2 retrievers so the probability is 2/7
Answer:2/7
Step-by-step explanation:
While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between 2.00 m and 7.00 m. What is the probability that a randomly selected depth is between 2.25 m and 5.00 m?
Answer:
55% probability that a randomly selected depth is between 2.25 m and 5.00 m
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X between c and d is given by the following formula.
[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]
While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between 2.00 m and 7.00 m.
This means that [tex]a = 2, b = 7[/tex]
What is the probability that a randomly selected depth is between 2.25 m and 5.00 m?
[tex]P(2.25 \leq X \leq 5) = \frac{5 - 2.25}{7 - 2} = 0.55[/tex]
55% probability that a randomly selected depth is between 2.25 m and 5.00 m
Let x = 8.99999 . (a) Is x < 9 or is x = 9? x < 9 It is neither; x > 9 x = 9 x < 9 and x = 9 It cannot be determined. (b) Sum a geometric series to find the value of x. x = (c) How many decimal representations does the number 9 have? decimal representations (d) Which numbers have more than one decimal representation? the integers the rational numbers except for 0 all rational numbers that have a terminating decimal representation except for 0 all integers except for 0 all real numbers
Answer: idk
Step-by-step explanation:
idk
One third of the sum of 15
and thrice a certain number is
equal to twice the number. Find
the number
Answer:
x=-1/39
Step-by-step explanation:
Solve the equation. 4c = 3
Answer:
Brainelist~~~!!!
Step-by-step explanation:
4c=3
c=3/4
c=0.75
The solution of the linear equation 4·c = 3, obtained by solving for the variable c is; c = 3/4
What is a linear equation?A linear equation is an equation that can be expressed in the form; y = m·x + c
The equation 4·c = 3 is a linear equation
In order to solve the equation 4·c = 3 for the variable c, the variable c needs to be isolated to one side of the equation, by dividing both sides of the equation by 4 as follows;
4·c = 3
(4·c)/4 = 3/4
c = 3/4
Therefore, the solution of the equation, 4·c = 3 is; c = 3/4
Learn more on linear equations here: https://brainly.com/question/30338252
#SPJ6
An employee wants to invest $50,000 in a pension plan. One investment offers 6% compounded quarterly. Another offers 5.75% compounded continuously.
(a) Which investment will ear more interest in 5 yr?
(b) How much more will the better plan earn?
Answer:
a. 6% one is better
b. $12,285.95
Step-by-step explanation:
a. For determining which investment earn more first we have to calculate both the investment which are as follows
a. Based on compound quarterly, the amount is find out by using the following formula
[tex]Amount = {Present\ value\times (1 + interest\ rate)} ^{number\ of\ years}[/tex]
where,
Present value is $50,000
Interest rate is = [tex]\frac{0.06}{4}[/tex] = 0.015
And, the number of years is
= [tex]4\times4[/tex]
= 16
So, the amount is
[tex]= \$50,000 \times (1 + 0.015)^{16}[/tex]
= $63,449.28
And, based on compounded continuously, the amount is determined by using the following formula
[tex]Amount = Present\ value\times e^{rt}[/tex]
[tex]= \$50,000 \times e.^{0575(4)}[/tex]
= $51,163.33
Therefore, The the investment at 6% is better
b. Now the difference in earning is
= $63,449.28 - $51,163.33
= $12,285.95
In a recent​ year, the total scores for a certain standardized test were normally​ distributed, with a mean of 500 and a standard deviation of 10.4. A) Find the probability that a randomly selected medical student who took the test had a total score that was less than 484. The probability that a randomly selected medical student who took the test had a total score that was less than 484 is:_______.B) Find the probability that a randomly selected study participant's response was between 4 and 6 The probability that a randomly selected study participant's response was between 4 and 6 is:_______.C) Find the probability that a randomly selected study participant's response was more than 8. The probability that a randomly selected study participant's response was more than 8 is:________.
Answer:
A) The probability that a randomly selected medical student who took the test had a total score that was less than 484 = 0.06178
B) The probability that a randomly selected study participant's response was between 504 and 516 = 0.29019
C) The probability that a randomly selected study participant's response was more than 528 = 0.00357
D) Option D is correct.
Only the event in (c) is unusual as its probability is less than 0.05.
Step-by-step explanation:
The b and c parts of the question are not complete.
B) Find the probability that a randomly selected study participant's response was between 504 and 516
C) Find the probability that a randomly selected study participant's response was more than 528.
D) Identify any unusual event amongst the three events in A, B and C. Explain the reasoning.
a) None.
b) Events A and B.
C) Event A
D) Event C
Solution
This is a normal distribution problem with
Mean = μ = 500
Standard deviation = σ = 10.4
A) Probability that a randomly selected medical student who took the test had a total score that was less than 484 = P(x < 484)
We first normalize or standardize 484
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - μ)/σ = (484 - 500)/10.4 = - 1.54
To determine the required probability
P(x < 484) = P(z < -1.54)
We'll use data from the normal distribution table for these probabilities
P(x < 484) = P(z < -1.54) = 0.06178
B) Probability that a randomly selected study participant's response was between 504 and 516 = P(504 ≤ x ≤ 516)
We normalize or standardize 504 and 516
For 504
z = (x - μ)/σ = (504 - 500)/10.4 = 0.38
For 516
z = (x - μ)/σ = (516 - 500)/10.4 = 1.54
To determine the required probability
P(504 ≤ x ≤ 516) = P(0.38 ≤ z ≤ 1.54)
We'll use data from the normal distribution table for these probabilities
P(504 ≤ x ≤ 516) = P(0.38 ≤ z ≤ 1.54)
= P(z ≤ 1.54) - P(z ≤ 0.38)
= 0.93822 - 0.64803
= 0.29019
C) Probability that a randomly selected study participant's response was more than 528 = P(x > 528)
We first normalize or standardize 528
z = (x - μ)/σ = (528 - 500)/10.4 = 2.69
To determine the required probability
P(x > 528) = P(z > 2.69)
We'll use data from the normal distribution table for these probabilities
PP(x > 528) = P(z > 2.69) = 1 - P(z ≤ 2.69)
= 1 - 0.99643
= 0.00357
D) Only the event in (c) is unusual as its probability is less than 0.05.
Hope this Helps!!!
A loan of $8 000 was repaid in 2 years in
monthly payments of $400.00. The interest
on the loan, as e percentage, was?
Answer:
P = 8000
t = 2
I = p × r × t
400 = 8000 × r/100 × 2
r = 400/160 per year
r = 40/16 = 2.5 %
Suppose I claim that the average monthly income of all students at college is at least $2000. Express H0 and H1 using mathematical notation, and clearly identify the claim and type of testing.
Answer:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): [tex]\mu \geq 2000[/tex]
Alternative hypothesis (H1): [tex]\mu <2000[/tex]
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no
Step-by-step explanation:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): [tex]\mu \geq 2000[/tex]
Alternative hypothesis (H1): [tex]\mu <2000[/tex]
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no
A marketing analyst randomly surveyed 150 adults from a certain city and asked which type of tooth paste they were currently using - Extra Whitening or Regular. 96 said they were currently using Extra Whitening while the rest said they were using Regular. The analyst wants to determine if this is evidence that more than half of the adults in this city are using Extra Whitening. Suppose a p-value from the correct hypothesis test was 0.0003. Which of the following is a correct interpretation of this p-value?
A. HA: p_extra White > p_Regular.
B. HA: p > 0.5, where p = the proportion of all adults in this city using Extra Whitening.
C. HA: p = 0.64, where p = the proportion of all adults in this city using Extra Whitening.
D. HA: p=0.5, where p = the proportion of all adults in this city using Extra Whitening.
A professor gives her 100 students an exam; scores are normally distributed. The section has an average exam score of 80 with a standard deviation of 6.5. What percentage of the class has an exam score of A- or higher (defined as at least 90)? Type your calculations along with your answer for full credit; round your final percentage to two decimal places.
Answer:
6.18% of the class has an exam score of A- or higher.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 80, \sigma = 6.5[/tex]
What percentage of the class has an exam score of A- or higher (defined as at least 90)?
This is 1 subtracted by the pvalue of Z when X = 90. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{90 - 80}{6.5}[/tex]
[tex]Z = 1.54[/tex]
[tex]Z = 1.54[/tex] has a pvalue of 0.9382
1 - 0.9382 = 0.0618
6.18% of the class has an exam score of A- or higher.
Please help! I don’t get what I’m supposed to put in those boxes
The volume of any cylinder is
V = pi*r^2*h
where r is the radius and h is the height. We are keeping r = 2 the same the entire time, as the first part of the instructions indicate. In contrast, h is allowed to vary or change based on the values shown in the table.
If h = 1, then,
V = pi*r^2*h
V = pi*2^2*1
V = pi*4
V = 4pi
So you'll write "4pi", without quotes of course, in the V column next to h = 1. This first row shows a height of 1 leads to a volume of 4pi.
-------------
Then if h = 2, we have,
V = pi*r^2*h
V = pi*2^2*2
V = pi*8
V = 8pi ... this is written in the second box
and finally if h = 3, we would say,
V = pi*r^2*h
V = pi*2^2*3
V = pi*12
V = 12pi .... and this is placed in the third box
---------------
The values of V we got were: 4pi, 8pi, 12pi
This is for h = 1,2 and 3 respectively in that order.
The sequence 4,8,12 is linear because we are adding 4 each time. More specifically, it fits the equation y = 4x where x = 1,2,3. Think of y = 4x as y = 4x+0 and that fits the slope intercept form y = mx+b.
Please help! Correct answer only, please! The following information matrices shows how many of each vehicle type sold and the bonus amount each salesperson receives for selling that type of vehicle for the car dealership for the week. What does the element LaTeX: A_{2,3}A 2 , 3represent? A. Mark sold 2 vans B. Scott sold 1 Van C. Mark sold 4 trucks D. Kelly sold 2 trucks
Answer: B) Scott sold 1 van
Step-by-step explanation:
A₂,₃ represents: matrix A - 2nd row - 3rd column
The second row is Scott and and the 3rd row is Vans
If you look at Scott - Vans, you will see that Scott sold 1 van.
Graph y < x2 + 4x. Click on the graph until the correct graph appears.
Answer: The correct answer is:
_________________________
The given "graph" in the bottom right, lowest corner
Step-by-step explanation:
_________________________
Note: When there is only one (1) equation give for a graph;
and/or: only one (1) "inequality given";
we look for the symbol.
If the symbol is "not" an "equals" symbol (i.e. not an: = symbol) ;
we check for the type of "inequality" symbol.
If there is a: "less than" (<) ; or a "greater than" (>) symbol; the graph of the "inequality" will have "dashed lines" (since there will be a "boundary").
If there is an "inequality" that is a: "less than or equal to" (≤) ;
or a: "greater than or equal to" (≥) ;
→ then there will be not be a dashed line when graphed;
but rather—a "solid line" ; since "less than or equal to" ;
or "greater than or equal to" —is similar to:
"up to AND including"; or: "lesser/fewer than AND including".).
_________________________
Note: We are given the "inequality" :
→ " y < x² + 4x " .
_________________________________
Note that we have a "less than" symbol (< ) ; so the graph will have a:
"solid line" [and not a "dotted line".].
_________________________________
Note that all of the graphs among our 4 answer choices have "dotted lines".
Not that all values (all x and y coordinated) within the "shaded portion" of the corresponding graph are considered part of the graph.
As such, given any point within the shaded part, the x and y coordinates must match the inequality (i.e. the given inequality must be true when one puts in the "x-coordinate" and "y-coordinate" into the "given inequality" :
→ " y < x² + 4x " .
_________________________
Likewise, we can take any point within the "white, unshaded" portion of any of the graph, and take the "x-coordinate" and "y-coordinate" of that point, and the inequality: → " y < x² + 4x " ; will not hold true when the "x-coordinate" and "y-coordinate" values of that point— are substituted into the "inequality".
_________________________
{Note: Answer is continued on images attached.}.
Wishing you the best!
This chart shows Dan’s budget:
A 3-column table has 5 rows. The first column is labeled Item with entries Internet, food, rent, discretionary spending, income. The second column is labeled Amount budgeted with entries 35, 100, 500, 100, 750. The third column is labeled Amount spent with entries 35, 95, 500, 140, blank.
Did Dan stay on budget? Why or why not?
Yes, Dan spent as much as he earned.
No, Dan should move to a new apartment.
Yes, Dan uses his savings to cover extra expenses.
No, Dan should reduce his discretionary spending
The correct answer is D No, Dan should reduce his discretionary spending
Explanation:
For Dan to stay on the budget he needs to spend the amount budgeted for each expense or less than the amount budgeted. This occurred in the case of the Internet, food, and rent; for example, the amount budgeted for the internet was $35 and Dan spent this money, also, the amount budgeted for food was $100 and Dan spent $95, which means he stood in the budget. However, this did not occur with discretionary spending, which refers to other non-necessary expenses, because in this case, Dan spent $140 even when the budget limit was $100. Also, this exceeds the total income considering 35 + 95 + 500+ 140 = $770, which is above the income ($750). Thus, Dan did not stay in the budget because he spent more money than expected in discretionary spending and should reduce this.
The correct answer is D. No, Dan should reduce his discretionary spending.
Hope this helps
:)
M is the midpoint of st. Sm= 3x+16 and MT = 6x+4. Find the length of SM.
No figure required. If M is the midpoint of ST then SM=MT or
3x + 16 = 6x + 4
12 = 3x
x = 4
SM = 3(4)+16=28
Answer: 28
Ann pays $300 for membership to a local gym. She is allowed to bring one guest on any visit. John pays Ann $5 to go to the gym with her occasionally. Describe what the expression 300 - 5t could represent. Then evaluate the expression for T equals five 10 15 and 20
Answer:
f
Step-by-step explanation:
Henry, Brian and Colin share some sweets in the ratio 6:4:1. Henry gets 25 more sweets than Colin. How many sweets are there altogether?
Answer:
There are 55 sweets in total.
Step-by-step explanation:
The total number of sweets is t.
Henry, Brian and Colin share some sweets in the ratio 6:4:1.
This means that Henry earns [tex]\frac{6}{6+4+1} = \frac{6}{11}[/tex] of the total(t).
Brian earns [tex]\frac{4}{11}[/tex] of the total.
Colin earns [tex]\frac{1}{11}[/tex] of the total
Henry gets 25 more sweets than Colin.
Henry earns [tex]\frac{6t}{11}[/tex]
Colin earns [tex]\frac{t}{11}[/tex]
So
[tex]\frac{6t}{11} = \frac{t}{11} + 25[/tex]
Multiplying everything by 1
[tex]6t = t + 275[/tex]
[tex]5t = 275[/tex]
[tex]t = \frac{275}{5}[/tex]
[tex]t = 55[/tex]
There are 55 sweets in total.
Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below are the jersey numbers of 11 players randomly selected from the roster of a championship sports team. What do the results tell us? 24 72 41 76 15 29 64 93 74 38 99
Answer:
a) 56.82
b) 64
c) there is no mode
d) 57
e) the jersey numbers are nominal data and they do not measure or count anything, so the resulting statistic are meaningless
Step-by-step explanation:
The first thing is to organize the data from least to greatest:
15 24 29 38 41 64 72 74 76 93 99
a) the mean would be the average of the data, thus:
m = (15 + 24 + 29 + 38 + 41 + 64 + 72 + 74 + 76 + 93 + 99) / 11
m = 56.82
b) the median is the data of half, when the data is organized, in this case the value of half would be the sixth data that is 64.
c) the mode is the value that is most repeated, therefore as none is repeated there is no mode.
d) the midrange is the average between the minimum value and the maximum value:
mr = (15 + 99) / 2
mr = 57
e) the jersey numbers are nominal data and they do not measure or count anything, so the resulting statistic are meaningless
Two barrels are mathematically similar
The smaller barrel has a height of [tex]h[/tex]cm and a capacity of 100 Liters
The larger barrel has a height of 90cm and a capacity of 160 Liters
-Work out the value of [tex]h[/tex]
Answer:
h ≈ 77 cm
Step-by-step explanation:
Let us convert the liters to cm³.
Smaller barrel
0.001 litres = 1 cm³
100 litres = 100000 cm³
Larger barrel
0.001 litres = 1 cm³
160 litres = 160000 cm³
For a similar solid figure the cube of their corresponding sides is equal to the volume ratio.
This means
h³/90³ = 100000/160000
cube root both sides
h/90 = ∛100000 / ∛160000
h/90 = 46.4158883/54.2883523
cross multiply
54.2883523h = 46.4158883 × 90
54.2883523h = 4177.429947
divide both side by 54.2883523
h = 4177.429947/54.2883523
h = 76.9489175858
h ≈ 77 cm
John leaves school to go home.his bus drives 6 kilometers north and then goes 7 kilometers west.how far is John's house from the school?
Answer:
John is 9.21 km form the school.
Step-by-step explanation:
John leaves school to go home. His bus drives 6 kilometres north and then goes 7 kilometres west. It is required to find John's distance from the school. It is equal to the shortest path covered or its displacement. So,
[tex]d=\sqrt{6^2+7^2} \\\\d=9.21\ km[/tex]
So, John is 9.21 km form the school.