The time required for one complete cycle of a mass oscillating at the end of a spring is 0.40 s. What is the frequency of oscillation?

Answer:

hello your question is incomplete below is the missing part

Consider the sum of sinusoids de (t) = sin(24(941)t) + sin(27(1336)t)

answer : Value of DFT frequency = 684 Hz

Explanation:

Given data:

sample signal ( Fs ) = 8000 Hz

Fourier transform using an FFT with 4096 points

Determine the value of DFT frequency bins closest to the two frequencies of the sinusoids ( 941 and 1336 Hz )    ( in HZ )

fs = 8000 Hz

4096 parts are divided with a gap of Fs/N

 attached below is the detailed solution

Answer: 800

Explanation:

1/2 x m x v^2 = m x g x h

KE = 10 x 10 x 8

KE= 800

The energy of the body by the virtue of its motion is known as the kinetic energy of the body. The kinetic energy of the rock just before it hits the ground will be 784.8 J.

The energy of the body by the virtue of its motion is known as the kinetic energy of the body. It is defined as the product of half of mass and square of the velocity.

According to the law of conservation of energy, energy can not be created nor be destroyed can be transferred from one form to another form.

Kinetic energy= potential energy

Kinetic energy= mgh

Kinetic energy= 10×9.81×8

Kinetic energy=784.8 J

Hence the kinetic energy of the rock just before it hits the ground will be 784.8 J.

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Answer:

the impulse must be the same in these two cases    F t = m ([tex]\sqrt{2g h_f } - \sqrt{2g h_o}[/tex])

Explanation:

For this exercise we use the relationship between momentum and momentum

         I = Δp

         F t = m v_f - m v₀

To know the speed we use the conservation of energy

starting point. Highest point

       Em₀ = U = m g h

fincla point. Just before the crash

      Em_f = K = ½ m v²

energy is conserved

        Em₀ = Em_f

        m g h = ½ m v²

         v = [tex]\sqrt{2gh}[/tex]

we substitute in the impulse relation

     F t = m ([tex]\sqrt{2g h_f } - \sqrt{2g h_o}[/tex])

therefore we can see that as in case the initial and final heights are equal, the impulse must be the same in these two cases

Answer:

a)  k = 701.8 N / m, b)  m_{ast} = 61.1 kg, c)  v ’= -1.3 10⁻⁴ m / s

Explanation:

a) For this exercise let's use the relationship of the angular velocity

         w = [tex]\sqrt{ \frac{k}{m} }[/tex]

          k = w² m

the angular velocity is related to the period

          w = 2π / T

we substitute

          k = 4 π²    [tex]\frac{m}{T^2}[/tex]

let's calculate

          k = 4 π²   10 /0.75²

          k = 701.8 N / m

b) now repeat the measurement with an astronaut on the chair

         w = [tex]\sqrt{ \frac{k}{m} }[/tex]

where the mass Month the mass of the chair plus the mass of the astronaut

        M = m + [tex]m_{ast}[/tex]

          M = k / w²

          w = 2π / T

let's calculate

           w = 2π / 2

            w = π rad / s

            M = 701.8 /π²

            M = 71,111 kg

now we use that

          M = m + m_{ast}

          m_{ast} = M - m

          m_{ast} = 71.111 - 10.0

          m_{ast} = 61.1 kg

c) if the astronaut's movement is simple harmonic

          x = A cos wt

therefore the speed is

         v = [tex]\frac{dx}{dt}[/tex]

         v = -Aw sin wt

maximum speed is

          v = - Aw

          v = 0.100 π

          v = 0.31416 m / s

we can suppose that the movement of the space station and the astronaut  is equivalent to division of the same

initial instant. Before the move

         p₀ = 0

final instant. When the astronaut is moving

        p_f = M_station v’+ m_{ast} v

the moment is preserved

         p₀ = pf

         0 = M__{station} v ’+ m_{ast} v

         v ’= - [tex]\frac{m_{ast} }{M_{station} } \ v[/tex]

we substitute

         v ’= [tex]\frac{61.1 }{ 100000 } \ 0.31416[/tex]

         v ’= -1.3 10⁻⁴ m / s

the negative sign indicates that the station is moving in the opposite direction from the astronaut

Answer:

No answer

Explanation:

no explanation

Answer:

mgh

Explanation:

Assume the height of the body is 1.8m.

The gravity?of the body is G=mg

the height of the gravity center is about 0.9m

E=mgh

=m*9.8m/s*0.9m

= 8.82mJ

Answer:

d

Explanation:

velocity=frequency × wavelength

frequency=speed/wavelength

frequency=3.5÷4

=0.875~0.88

The frequency of the waves is (d) 0.88 Hz. So, correct answer is option (d).

The frequency of a sinusoidal wave is the number of full oscillations performed by any wave constituent in a unit of time. According to the definition of frequency, if a body is moving periodically, it has completed one cycle after going through a number of situations or postures and then returning to its initial position. Therefore, frequency is a quantity that describes the rate of oscillation and vibration.

Given parameter,

Velocity of the waves = 3.5 m/s.

distance between the crests of each wave, that is, wavelength of the waves = 4 m.

We know that, for a wave transmission,

velocity of wave =frequency of wave  × wavelength of wave

⇒ frequency of wave=speed of wave/wavelength of wave

⇒ frequency of wave =3.5 m/s ÷4m

=0.875 Hz

≈ 0.88 Hz

Hence, the frequency of the waves is 0.88 Hz.

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Answer:It will take about 3000 years

Explanation:

Answer:

Quantum mechanics is a key hypothesis in material science that gives a portrayal of the actual properties of nature at the size of iotas and subatomic particles. It is the establishment of all quantum physical science including quantum science, quantum field hypothesis, quantum innovation, and quantum data science.

Explanation:

It is the greatest of issues, it is the littlest of issues. At present physicists have two separate rule books clarifying how nature functions. There is general relativity, which perfectly represents gravity and everything it overwhelms: circling planets, impacting worlds, the elements of the growing universe all in all. That is enormous. At that point there is quantum mechanics, which handles the other three powers – electromagnetism and the two atomic powers. Quantum hypothesis is very proficient at portraying what happens when a uranium molecule rots, or when singular particles of light hit a sun based cell. That is little.

Answer:

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects.

Explanation:

Answer:

0.25 J

Explanation:

The strength of the egg shell, the size of the egg, and the force used to break it are just some of the variables that affect how much energy is needed to crack an egg. When an object hits the egg with an impact energy of 12–26 mJ, cracks occur.

The capacity of a system or object to do work is called energy, which is a fundamental term in physics. Kinetic energy, potential energy, heat energy, electromagnetic energy, and nuclear energy are just a few of the different forms of energy.

While potential energy is the energy possessed by an object as a result of its position or position, kinetic energy is the energy of motion. While electromagnetic energy is energy carried by electromagnetic waves like light, thermal energy is energy related to the temperature of a substance. The energy stored in the nucleus of an atom is called nuclear energy.

Therefore, when an object hits the egg with an impact energy of 12–26 mJ, cracks occur.

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Answer:

Friction and Air resistence

Explanation:

i already passed this grade years ago...

The forces responsible for exerting forces to the left on a cyclist are -

Air resistance describes the forces that are in opposition to the relative motion of an object as it passes through the air. We can write air resistance as -

[tex]$F_{D}=\frac{1}{2} \rho v^{2} C_{D} A[/tex]

where -

F{D} = drag

{ρ} = density of fluid

{v} = speed of the object relative to the fluid

C{D}  = drag coefficient

{A} = cross sectional area

Given is to find what 2 forces would be responsible for exerting forces to the left on a cyclist that is already in motion moving to the right.

The forces responsible for exerting forces to the left on a cyclist are -

Therefore, the forces responsible for exerting forces to the left on a cyclist are -

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Answer:

POSITIVE CHARGE,  NEGATIVE CHARGE,  ZERO

Explanation:

To solve this completion exercise, we must remember that charges of the same sign repel each other and in a metallic object (frying pan) the charge is mobile.

Let's analyze the situation when we touch the pan, the charges are neutralized, therefore when we bring the pan to the plate that has a positive charge, it attracts the mobile negative charges in the pan, until it is neutralized, therefore on the opposite side of the pan. pan (edge ​​with a glued tape) is left with a positive charge; therefore the edge and the tape, which is very light, have positive charges and repel each other.

We must assume that the frying pan is insulated so that the net charge is zero, since the induction process.

Consequently the words to complete the sentence are

When the pan is on the plate, the edge of the plate has a _POSITIVE CHARGE_____.

This means that the base of the container is loaded NEGATIVE CHARGE_____ because the net charge of the container is ___ZERO_

Answer:

M-1 L3 T-2

Explanation:

Where,

M = Mass

L = Length

T = Time

Derivation

From Newton’s law of gravitation,

Force (F) = [GM1M2] × r-2

Gravitational Constant (G) = F × r2 × [Mm]-1  . . . . (1)

Since, Force (F) = Mass × Acceleration = M × [LT-2]

∴ The dimensional formula of force = M1 L1 T-2 . . . . (2)

On substituting equation (2) in equation (1) we get,

Gravitational Constant (G) = F × r2 × [Mm]-1

Or, G = [M1 L1 T-2] × [L]2 × [M]-2 = [M-1 L3 T-2].

Therefore, the gravitational constant is dimensionally represented as M-1 L3 T-2.

Answer:

[tex]a=20\ m/s^2[/tex]

Explanation:

Given that,

The mass of an object, m = 3 kg

The radius of a circle, r = 0.2 m

The speed of the object, v = 2 m/s

We need to find the centripetal acceleration. Its formula is given by :

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(2)^2}{0.2}\\\\a=20\ m/s^2[/tex]

So, the centripetal acceleration is [tex]20\ m/s^2[/tex].

Answer:I know the answer for B cus I’m doing the same problem. For B, you would only take the coefficient of friction given and then multiply it by the Normal Force, which in this case is the same as the Gravitational Force.

Explanation:

Answer:

2 seconds

Explanation:

From the question,

Applying the equation of motion for a body falling under gravity

s = ut+1/2gt²................................. Equation 1

Where, s = hieght of fall, u = initial velocity, t = time, g = acceleration due to gravity.

Given: s = 20 m, u = 0 m/s, t = ?, g = 10 m/s²

Substitute these values into equation 1

10 = 0(t²)+1/2(10×t)

10 = 5t

Solve for t

5t/5 = 10/5

t = 2 seconds

Answer & Explanation:

1 N-m = 1 Joule

So 82 kJ of energy put into the system during (i).

45 kJ of heat leaves the system, so 82 kJ - 45 kJ  = 37 kJ is remaining.

(ii) requires 100 kJ of energy but only 37 kJ is available, so 100 kJ - 37 kJ = 63 kJ of heat energy must be added to the system.

The heat given would be equal to the heat emitted from the system and by providing some external source of energy the volume or temperature of the system may increase.

The amount of heat added to the system is 63kJ.

The energy can be estimated as:

Given,

During compression stroke:

We know that,

[tex]\rm Q_{1-2} = (U_{2} - U_{1}) + W[/tex]

Therefore,

[tex]\begin{aligned}-45 &= \rm (U_{2} - \rm U_{1}) + (-82)\\\\\rm (U_{2}-U_{1}) &= 37\rm (U_{2} - U_{1}) = 37\; kJ \end{aligned}[/tex]          (equation 1 )

During Expansion system:

Work done by the piston [tex]\rm (W_{2-1})[/tex] = 100000 Nm or 100 kJ

Now putting values in the equation:

[tex]\begin{aligned}\rm Q_{2-1} &= \rm U_{1} - U_{2} + W\\\\&=\rm (U_{1} - U_{2}) + W\end{aligned}[/tex]

Substituting value from equation 1:

[tex]\begin{aligned}\rm Q_{2-1} &= - 37+100\rm \;kJ\\&= 63\rm \; kJ\end{aligned}[/tex]

Therefore, 63kJ of energy is added to the system.

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Answer:

b. the net force exerted on the car is directed to the left.

Explanation:

Applying Newton's second law of motion, the car will move in the direction of the applied force. If the applied forces are on different directions, the car will move in the direction of the greater force (net force).

Therefore, if a car is moving to the left with constant velocity, one can conclude that the net force exerted on the car is directed to the left.

The correct option is "b. the net force exerted on the car is directed to the left"

Answer:

the height above the ground through Mr. Voytko lifted the apple is 2.5 m.

Explanation:

Given;

energy of Mr. Voytko, E = 7.35 J

mass of the apple, m = 0.3 kg

Apply the principle of conservation of energy.

Energy of Mr. Voytko = Potential energy of the apple due to its height above the ground.

E = mgh

where;

h is the height above the ground through Mr. Voytko lifted the apple.

g is acceleration due to gravity = 9.8 m/s²

h = E / (mg)

h = 7.35 / (0.3 x 9.8)

h = 2.5 m

Therefore, the height above the ground through Mr. Voytko lifted the apple is 2.5 m.

Answer:

140

Explanation:

Answer:

★ Pressure and depth have a directly proportional relationship. This is due to the greater column of water that pushes down on an object submerged. Conversely, as objects are lifted, and the depth decreases, the pressure is reduced.

Explanation:

Hope you have a great day :)

You can see if the person your talking to and being mindfull they  will see respect towards you or they see you as a mindful person.It shows a person that you care.

Explanation:

Answer:

Part 1

Steve is measuring his average speed

Part 2

Average velocity is equal to 60 miles per hour

Explanation:

Part 1

Average velocity is equal to total distance travelled divided by total time taken. It also takes into consideration the change of direction through out the journey.

Hence, Steve is measuring his average speed

Option A is correct

Part 2

Average velocity is equal to 60 miles per hour only because velocity is a vector quantity

Option B is correct

Answer:

By using the most simple velocity equation, velocity = distance / time, meaning the speed would be 247.5 meters per second.

Answer:

0.08m/s

Explanation:

Given data

M1= 69kg

v1= 2.61m/s

M2= 0.22kg

v2= 25.2m/s

Before snowball is thrown:

Total mass of skater + snowball = 69+ 0.22 = 69.22kg

Total Momentum of skater + snowball = mv = 69.22 x 2.61 = 180.7 kgm/s

After snowball is thrown:

Let's call the velocity of the skater V.

Total momentum = momentum of skater + momentum of snowball

=69.22V + (5.544)

= 69.22V + 5.544

So:

180.7  = 69.22V+5.544

180.7- 5.544= 69.22V

175.156= 69.22V

V= 175.156/69.22

V = 2.53m/s

The total momentum after catching the snowball is mV or:

(69.0 + 0.22) x V

So:

5.544= 69.22V

V= 5.544/69.22

V=0.08m/s

The velocity of the ice skater after throwing the snowball is 0.08m/s

Answer:

22.54 m/s^2

Explanation:

vf = final velocity = 95 m/s

vi = initial velocity = 59 m/s

d = displacement = 123 m

a = acceleration, unknown

Use this kinematics equation to find a:

vf^2 = vi^2 + 2a*d

95^2 = 59^2 + 2*a*123

22.54 m/s^2 = a

Hope this helps!! :)

Answer:

hope this helps

hope this is what u want

Answer:

1. Temperature= 869.35 K

2. Pressure of combustion = 12994.043 kpa

3. Thrust = 127x10⁶N

Explanation:

this problem has been fully explained in the attachment. please use it to get a clearer explanation of the answer.

1.

The temperature = (273+2400k) - (3800)²/2(4003)

= 2673 - 14440000/8006

= 2673 - 1803.65

= 869.35 K

Approximately 869.4K

2. We first get mach number

= 3800/√1.3(923.8)(869.35)

= 3800/1021.78

= 3.719

Pressure = 100kpa[1+2.07464415]^1.3/0.3

= 12995.043kpa

C. Thrust

Pi/4(3800)²(0.3)²(100x10³)/(923.8)(869.4)

= 12678.621

= 126.781 kN

Thrust is approximately 127kN = 127x10⁶N