The target heart rate zone is:
a
the level your recovery heart rate should reach.
b
where you want your exercise heart rate.
c
where you want your resting heart rate.
d
your maximum heart rate.

Answers

Answer 1
I think C. Cause normally if it’s too fast you could have high blood pressure or other problems
Answer 2

The target heart rate zone is where you want your exercise heart rate to be. Option B is correct.

The target heart rate zone is a specific range of heart rates that you should aim to achieve during exercise to maximize the benefits of your workout. This range is typically calculated based on a percentage of your maximum heart rate. For example, if your maximum heart rate is 180 beats per minute, your target heart rate zone might be between 120 and 150 beats per minute.

The objective pulse is 50 to 85 percent of your greatest pulse. It is the level at which your heart is pulsating with moderate to extreme focus. To decide your greatest pulse, take 220 and deduct your age. Supporting an exercise at this speed works on cardiorespiratory perseverance.

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Related Questions

PLS HELP WILL GIVE 50 POINTS
How is energy sent from Earth to space?
conduction and convection
radiation and conduction
reflection and conduction
radiation and reflection

Answers

Answer:

I'm pretty sure its radiation and reflection. Some of the Sun's energy gets reflected off into space. (I could be wrong though)

Answer:

radiation and reflection

hope helps you

have a nice day

Explanation:

hope this will surely be helpful to you

what is the slope of the line

Answers

Answer:

[tex]m=\frac{1}{3}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Slope Formula: [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Explanation:

Step 1: Define

Point (0, -1)

Point (3, 0)

Step 2: Find slope m

Substitute:                    [tex]m=\frac{0+1}{3-0}[/tex]Add/Subtract:               [tex]m=\frac{1}{3}[/tex]

what does this quote mean? ​

Answers

Answer:

Basically, it means that you never know until you try.

Explanation:

A 56 kg diver runs and dives from the edge of a cliff into the water which is located 4.0 m below. If she is moving at 8.0 m/s the instant she leaves the cliff, determine the following.
Her gravitational potential energy relative to the water surface when she leaves the cliff
Her kinetic energy when she leaves the cliff
Her total mechanical energy relative to the water surface when she leaves the cliff
Her total mechanical energy relative to the water surface just before she enters the water.
The speed at which she enters the water.

Answers

Answer:

1) 2197.44 J

2) 0 J

3) 2197.44 J = Constant

4) 2197.44 J

5) Approximately 8.86 m/s

Explanation:

The given parameters are;

The mass of the diver, m = 56 kg

The height of the cliff, h = 4.0 m

The speed with which the diver is moving, vₓ = 8.0 m/s

The gravitational potential energy = Mass, m × Height of the cliff, h × Acceleration due to gravity, g

1) Her gravitational potential energy = 56 × 4.0 × 9.81 = 2197.44 J

2) The kinetic energy = 1/2·m·u²

Where;

u = Her initial velocity = 0 when she just leaves the cliff

Therefore;

Her kinetic energy when she just leaves the cliff = 1/2 × 56 × 0² = 0 J

3) The total mechanical energy = Kinetic energy + Potential energy

The total mechanical energy is constant

Her total mechanical energy relative to the water surface when she leaves the cliff = Her gravitational potential energy = 2197.44 J = Constant

4) Her total mechanical energy relative to the water surface just before she enters the water = 2197.44 J

5) The speed with which she enters the water, v, is given from, v² = u² + 2·g·h

Where;

u = The initial velocity at the top of the cliff before she jumps= 0 m/s

∴ v² = 0² + 2 × 9.81 × 4 = 78.48

v = √78.48 ≈ 8.86 m/s

The speed with which she enters the water, v ≈ 8.86 m/s

1) Her gravitational potential energy relative to the water surface when she leaves the cliff is; GPE(leaves cliff) = 2195.2 J

2) Her kinetic energy when she leaves the cliff is; KE = 0J

3) Her total mechanical energy relative to the water surface when she leaves the cliff is; ME_total = 2195.2 J

4) Her total mechanical energy relative to the water surface just before she enters the water is; ME_total = 2195.2 J

5) The speed at which she enters the water is; v = 8.85 m/s

We are given;

Mass of the diver; m = 56 kg

Height of the cliff; h = 4 m

Speed at which she is moving; vₓ = 8 m/s

1) Formula for gravitational potential energy is;

GPE = mgh

where;

m is mass

g is acceleration due to gravity

h is height

Thus;

GPE = 56 × 4 × 9.8

GPE(leaves cliff) = 2195.2 J

2) The formula for kinetic energy when she leaves the cliff is;

KE = ¹/₂mu²

Where;

m is mass

u = initial velocity = 0 m/s

Thus;

KE = ¹/₂ × 56 × 0²

KE(leaves cliff) = 0 J

3) The total mechanical energy relative to the water surface when she leaves the cliffis;

ME_total = GPE(leaves cliff) + KE(leaves cliff)

Thus;

ME_total = 2195.2 + 0

ME_total = 2195.2 J  

4) Her total mechanical energy relative to the water surface just before she enters the water is same as that when she leaves the cliff = 2195.2 J

5) The speed with which she enters the water, v, is gotten from newtons third equation of motion;

v² = u² + 2gh

Thus;

v² = 0² + (2 × 9.8 × 4)

v² = 78.4

v = √78.4

v = 8.85 m/s

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a supersonic aircraft travels faster than the speed of sound. What might be the top speed of such an aircraft? 200 Kilometers per hour 500 Kilometers per hour O 1000 Kilometers per hour O 1500 Kilometers per hour​

Answers

‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎1500 kpm

Describe Kinetic Energy.​

Answers

In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body when decelerating from its current speed to a state of rest.

Two positively charged particles are 0.03 m apart. The first
particle has a charge of 8.1 C, and the second a charge of 2.6
C. Which change would lead to the smallest increase in the
- electric force between the two particles?
A. Reduce the charge on the first particle by one half.
O B. Double the distance between the particles.
O C. Double the charge on the second particle.
OD. Reduce the distance between the particles by one
half

Answers

The correct option is option C.

Doubling the charge on the second particle produces the smallest increase in force.

Electrostatic force:

Let the given charges be Q and q such that:

Q = 8.1C and q = 2.6C

separated by a distance of R = 0.03m

Now, we have to calculate the minimum increase in electric force.

The electrostatic force is given by:

F  = kQq/R²

Option A is wrong since reducing the charge will reduce the force.

Option B is wrong since the force is inversely proportional to the distance, so increasing the distance will decrease the force.

Option C ⇒ Double the charge on the second particle:

F = 2kQq/R²

Option D ⇒ Reduce the distance between the particles by one half:

So, the new distance between the charges is R/2, then

F = kQq/(R/2)²

F = 4kQq/R²

Clearly, the operation in option C gives the smallest increase in the force.

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Which statement best describes the difference between acceleration and velocity?
A. acceleration only shows a change in direction, but velocity shows a change in speed.

B .acceleration depends on direction, but velocity does not.

C. acceleration is a change in velocity, but velocity is speed in a given direction.

D. acceleration only shows change in speed, but velocity only shows a change in direction.

Answers

c. is the answer because acceleration is the change in velocity in time while velocity is speed with a direction

Which is one limitation to technological design?

being innovative
designing a solution
having product appeal
identifying a problem

Answers

Answer:

c. Having product appeal

Explanation:

Answer:

c

Explanation:

A 12.0 kg box is being pulled along level ground at constant velocity by a horizontal force of 38.0 N. What is the coefficient of kinetic friction between the box and the floor?

Answers

Coefficient = 0.32
Friction force = 38 = μ x (9.8x12)
μ = 38/117.6 = 0.32

The coefficient of kinetic friction between the box and the floor is 0.323.

By Newton's Law of Motion we understand that an object is at equilibrium if and only if it is at rest or it is moving at constant velocity. If a horizontal force is applied on the box and it is moving, then a force with equal magnitude and opposed to that force must exists, which corresponds to the kinetic friction. Let suppose that the box is moving on a horizontal ground.

The equation of equilibrium for the box is described below:

[tex]\Sigma F = P - \mu_{k}\cdot m\cdot g = 0[/tex] (1)

Where:

[tex]P[/tex] - External force, in newtons.[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, no unit.[tex]m[/tex] - Mass, in kilograms.[tex]g[/tex] - Gravitational constant, in meters per square second.

An expression for the kinetic coefficient of friction is derived by clearing the variable in (1):

[tex]\mu_{k} = \frac{P}{m\cdot g}[/tex] (2)

If we know that [tex]P = 38\,N[/tex], [tex]m = 12\,kg[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then the kinetic coefficient of friction is:

[tex]\mu_{k} = \frac{38\,N}{(12\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}[/tex]

[tex]\mu_{k} = 0.323[/tex]

The coefficient of kinetic friction between the box and the floor is 0.323.

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A bus initially moving at 20 m/s with an acceleration of -4m/s² for 5
seconds. What is the displacement AND final velocity?

Answers

Answer:

50m; 0m/s.

Explanation:

Given the following data;

Initial velocity = 20m/s

Acceleration, a = - 4m/s²

Time, t = 5secs

To find the displacement, we would use the second equation of motion;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Substituting into the equation, we have;

[tex] S =20*5 + \frac{1}{2}*(-4)*5^{2}[/tex]

[tex] S =100 + (-2)*25[/tex]

[tex] S =100 - 50[/tex]

S = 50m

Next, to find the final velocity, we would use the third equation of motion;

[tex] V^{2} = U^{2} + 2aS [/tex]

Where;

V represents the final velocity measured in meter per seconds. U represents the initial velocity measured in meter per seconds. a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

[tex] V^{2} = 20^{2} + 2(-4)*50 [/tex]

[tex] V^{2} = 400 - 400[/tex]

[tex] V^{2} = 0[/tex]

V = 0m/s

Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.

Assuming the system is in equilibrium, calculate the missing distance d

Answers

Answer:

d=3.4m

Explanation:

From principle of equilibrium,

TOTAL C.WISE MOMENTS = TOTAL A.C.WISE

10N×d = 2N ×2m + 6N×5m

10Nd =4Nm+ 30Nm

10Nd=34Nm

10N 10N

d=3.4m

The system is in equilibrium, calculate the missing distance d=3.4 m.

What is Displacement?

Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude.

From principle of equilibrium,

TOTAL C.WISE MOMENTS = TOTAL A.C.WISE

10 N×d = 2 N ×2 m + 6 N×5 m

10 Nd = 4 N m+ 30 N m

10 Nd = 34 N m

d = 3.4 m

The system is in equilibrium, calculate the missing distance d=3.4 m.

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A boxer hits punching bag and gives it a change in momentum of 12 kg multiplied by m divided by s over 7.0ms what is the magnitude of the net force on the punching bag

Answers

Answer: 1700

Explanation:

my teacher gave us an answer saying "The sugar in soda does this because it doesn’t settle at the bottom of its container." and were supposed to get an 8 letter word and the fourth letter has an s and i dont know what the word is

Answers

Answer:

dissolve

Explanation:

Which terms describe the motion of most objects in our solar system?
This is a Earth Science question

Answers

Answer:Geography, Earth Science, Astronomy

Rotation describes the circular motion of an object around its center.

Explanation:

Answer:

it is Cyclic and predictable

What type of motion is illustrated in the diagram below?


A. Oscillating motion faster than the speed of sound.
B. Oscillating motion slower than the speed of sound.
C. Circular motion faster than the speed of sound.
D. Circular motion slower than the speed of sound.

Answers

Answer:

Explanation:

C

Erica (39 kg ) and Danny (46 kg ) are bouncing on a trampoline. Just as Erica reaches the high point of her bounce, Danny is moving upward past her at 4.6 m/s . At that instant he grabs hold of her.

Answers

Answer:

V = 2.79 m/s

Explanation:

Momentum before = momentum after

Erica's momentum = 0

Danny momentum = 49 kg * 4.9 m/s = 240.1 kg-m/s

240.1 + 0 = (37 + 49) kg * V

86 V = 240.1

V = 2.79 m/s

A race is held between a sports car and a motorcycle. The sports car can accelerate at 5.0 m/s^2 and the motorcycle can accelerate at 8.0 m/s^2. The two vehicles start the race at the same time and accelerate from rest. After 5.0 s, how fast is the sports car going? After 6.0 s, how distance will the motorcycle have gone? To make the race fair, the sports car starts 50.0 m ahead of the motorcycle. If the course is 200.0 m long, which vehicle wins the race?

Answers

Answer:

Vf₁ = 30 m/s

s₂ = 90 m

car wins the race.

Explanation:

To find the speed of car after 5 s, we use 1st equation of motion:

Vf₁ = Vi₁ + a₁t₁

where,

Vf₁ = Final Speed of Car = ?

Vi₁ = Initial Speed of Car = 0 m/s

a₁ = acceleration of car = 5 m/s²

t₁ = time = 5 s

Therefore,

Vf₁ = 0 m/s + (5 m/s²)(5 s)

Vf₁ = 25 m/s

To find the distance of motorcycle after 6 s, we use 2nd equation of motion:

s₂ = Vi₂ t₂ + (1/2)a₂t₂²

where,

s₂ = distance covered by the motorcycle = ?

Vi₁ = Initial Speed of motorcycle = 0 m/s

a₂ = acceleration of motorcycle = 8 m/s²

t₂ = time = 6 s

Therefore,

s₂ = (0 m/s)(6 s) + (1/2)(5 m/s²)(6 s)²

s₂ = 90 m

We can use 2nd equation of motion to find time taken by each car and motorcycle to reach the finish point:

For Car:

s₁ = Vi₁ t₁ + (1/2)a₁t₁²

where,

s₁ = 200 m - 50 m = 150 m (since, car starts 50 m ahead)

Therefore.

150 m = (0 m/s)(t₁) + (1/2)(5 m/s²)t₁²

t₁ = √60 s²

t₁ = 7.74 s

For Motorcycle:

s₂ = Vi₂ t₂ + (1/2)a₂t₂²

where,

s₁ = 200 m

Therefore.

200 m = (0 m/s)(t₂) + (1/2)(5 m/s²)t₂²

t₂ = √80 s²

t₂ = 8.94 s

Since, the car takes less time to reach finish line.

Therefore, car wins the race.

this is also for a Digital Electronics class​

Answers

Answer:

Rt = 908.25 [ohm]

Explanation:

In order to solve this problem, we must remember that the resistors connected in series are added up arithmetically.

In this case, R2 and R3 are in series therefore.

R₂₃ = 200 + 470

R₂₃ = 670 [ohm]

Now this new resistor (R₂₃) is connected in parallel with the resistor R4. therefore we must use the following arithmetic expression, to add resistances in parallel.

[tex]\frac{1}{R_{4-23} }= \frac{1}{R_{4}}+\frac{1}{R_{23} } \\\frac{1}{R_{4-23} }=\frac{1}{1800}+\frac{1}{670} \\R_{4-23}=488.25[ohm][/tex]

In this way R₁, R₅ and R₄₋₂₃ are connected in series.

Rt = R₁ + R₅ + R₄₋₂₃

Rt = 150 + 270 + 488.25

Rt = 908.25 [ohm]

Which does not contain a lens?



a mirror



binoculars



an eye



a camera



Help Me get A good grade PLZ

Answers

Im pretty sure it’s A eye

Why is your physical and mental health important?

Answers

Answer: Mental health and physical health are very closely connected. Mental health plays a major role in your ability to maintain good physical health. Mental illnesses, such as depression and anxiety, affect your ability to participate in healthy behaviors.

Explanation: Hope this helped. Have a great day!!!!

Answer:

Both maths are very important to our daily lives. Physical math helps us understand the reality of life. Learning to do certain math strategies is the first stage to finding answers to problems. Mental math can help us get answers faster through memory. This can help improve strategic methods and strengthen our minds.

a runner makes one lap around a 200m track in 25s, what is the runners (a) average speed and (b) average velocity

Answers

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When blocking in football, why does a defending lineman often attempt to get his body under that of his opponent and push forward?

Answers

Answer:

because he is trying to break past you and sack your quarterback

Explanation:

With the lineman's weight underneath the defender's, traction is increased with the lineman's feet and the ground. Friction is increased because the total force of both linemen give a larger opposing force of friction, making it harder for the defender to get around him.


A rally car accelerates from 10 m s−1 to 58 m s−1 in 8 seconds as it moves along a straight road. Given that the acceleration is constant, what is the acceleration of the car?

Answers

Answer:

a = 6 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics

[tex]v_{f} =v_{o} +a*t[/tex]

where:

Vf = final velocity = 58 [m/s]

Vo = initial velocity = 10 [m/s]

a = acceleration [m/s²]

t = time = 8 [s]

Now replacing:

58 = 10 + (a*8)

58 - 10 = 8*a

48 = 8*a

a = 6 [m/s²]

what is biosphere hydrosphere and atmosphere

Answers

Answer:

Biosphere are the regions of the surface, atmosphere, and hydrosphere of the earth.

Hydrosphere is when all the waters on the earth's surface, such as lakes and seas, and sometimes including water over the earth's surface, such as clouds.

Atmosphere is the envelope of gases surrounding the earth or another planet.

Explanation:

Hope this helps you out !!!

What role does the battery play in this circuit design? A) The battery works as the system's wires.
B) The battery is the electrical power supply.
C) The battery is the circuit's main conductor.
D) The battery works as the system's electrical switch.

Answers

Answer:

B

Explanation:

i got it right on the usatestprep


A ferry boat is 4.0 m wide and 6.0 m long. When a truck pulls onto it,
the boat sinks 4.00 cm in the water, What is the weight of the boat?

Answers

Should the question say “what is the weight of the truck”? :)
I can then answer it. There is no information to find the weight of the boat ;)

Compare the momentum of a 7160 kg truck moving at 5.00 m/s to the
momentum of a 2240 kg car moving at 15.0 m/s.

Answers

Answer:

2,200

Explanation:

truck=35800,car=33600

What is the Range of the projectile motion?

Answers

Answer:

Range of projectile, R

For projection above ground surface, the range of the angle of projection with respect to horizontal direction, θ, is 0° ≤ θ ≤ 90° and the corresponding range of 2θ is 0° ≤ 2θ ≤ 180°.S

hope you're looking for this.

The range of a projectile is how far it travels in the horizontal direction. If you know the horizontal speed you then multiply by the time in flight and you have the range. I hope this helps :)

explain the difference in how particles are arranged in a solid,liquids and gases

Answers

Answer:

hope this helps

Explanation:

solid particles are arranged according to the size of the object

while liquid particles are arranged how they move freely together in the object they are in.

while gas particles are arranged scatterly like they spread.

Particles in a: gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.
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