The square of the difference between a number and 7 is 81 . Find the​ number(s).

The number represented by the arrow is 9 if each unit is represented by 1 option fourth is correct.

It is defined as the representation of the numbers on a straight line that goes infinitely on both sides.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have a number line shown in the picture.

As we can see each unit is represented by 1.

So after 2 there will be 3 and after 4 there will be 5 and so on.

So after 8, there will be 9 which is represented by the arrow.

Thus, the number represented by the arrow is 9 if each unit is represented by 1 option fourth is correct.

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Answer: 9

Step-by-step explanation:

The number line going from - 4 to + 12 represents the range of possible values for the dividend of the division expression. The arrow going from 0 to 9 indicates the actual value of the dividend. Therefore, the number represented by the arrow is 9.

Answer

(0,3)

Step-by-step explanation:

Answer:

Zeros: 0, 1, and 7

Step-by-step explanation:

Given function: f(x) = 3x(x - 1)²(x - 7)²

To find the zeros (also known as the x-intercepts) of the function, first substitute f(x) = 0 into the equation and simplify.

1. Substitute f(x) = 0:

[tex]\sf f(x) = 3x(x - 1)^2(x - 7)^2\\\\\Rightarrow 0 = 3x(x - 1)^2(x - 7)^2[/tex]

2. Divide both sides by 3:

[tex]\sf \dfrac{0}{3} = \dfrac{3x(x - 1)^2(x - 7)^2}{3}\\\\\Rightarrow 0=x(x-1)^2(x-7)^2[/tex]

3. Separate into possible cases:

[tex]\sf a)\ x = 0\\b)\ (x - 1)^2 = 0\\c)\ (x - 7)^2 = 0[/tex]

4. Simplify:

[tex]\sf a)\ x = 0\ \textsf{[ already simplified ]}[/tex]

[tex]\sf b)\ (x - 1)^2=0\ \textsf{[ take the square root of both sides ]}\\\\\sqrt{(x - 1)^2}=\sqrt{0}\\\\\Rightarrow x-1=0\ \textsf{[ add 1 to both sides ]}\\\\x-1+1=0+1\\\\\Rightarrow x=1[/tex]

[tex]\sf c)\ (x - 7)^2=0\ \textsf{[ take the square root of both sides ]}\\\\\sqrt{(x - 7)^2}=\sqrt{0}\\\\\Rightarrow x-7=0\ \textsf{[ add 7 to both sides ]}\\\\x-7+7=0+7\\\\\Rightarrow x=7[/tex]

Therefore, the zeros of this function are: 0, 1, and 7.

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Answer:

The formula is: y = y•e^(-k•x)

In this specific case the function is: 512•e^(-x/1.44)

The number of players in the round 7 is 4

Answer:

Step-by-step explanation:

thomas age:44

huilan age: 29

Step-by-step explanation:

h = t + 15

t + t + 15 = 73

2t = 73 - 15

2t = 58

t = 29

The quotient is -27m/ 55.

Algebra is a branch of mathematics dealing with symbols and the rules for manipulating those symbols.

Given:

(9mn²)(−3m*6n)÷33m*10n³

=9mn² *(-18mn) / 330mn³

= -162m²n³/ 330mn³

= -27m/ 55

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Answer:

Step-by-step explanation:

We know that, 252 = 625

And, 262 = 676

Now, 676 - 625 = 51

So, there are 51 - 1 = 50 numbers lying between 252 and 262

Answer:

From what my calculations said its 20%

Answer is B.

Step-by-step explanation:

Since we know that in 30-60-90 triangle, the side corresponding to angle 90 degrees is two times the length of side corresponding to 30 degree angle. The length of side corresponding to 60 degree angle is  times the length corresponding to 30 degree angle.

We can see from our given choices that the side corresponding to 30 degree angle is 5 units.  

Therefore, the side lengths of a 30-60-90 triangle will be  and option B is the correct choice.  

PLS MARK ME AS BRAINLIEST.

Considering the given operations, the discrete sets are given as follows:

It is the operation of elements that are in set A but not in set B, hence, since A - B = {1, 5, 7, 8}, we have that:

A = {1,5,7,8}

It is the operation of elements that are in set B but not in set A, hence, since B - A = {2,10}, we have that:

B = {2,10}

It contains the elements that are in both sets, hence, since [tex](A \cap B) = \{3,6,9\}[/tex], we have that the sets are completed as follows:

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[tex]\dfrac{x!-(x-3)!}{23}=1\\x!-(x-3)!=23\\(x-3)!((x-2)(x-1)x-1)=23\\(x-3)!((x^3-x^2-2x^2+2x)-1)=23\\(x-3)!((x^3-3x^2+2x)-1)=23[/tex]

23 is a prime number, therefore there are two possibilities:

[tex]\text{I.}\, (x-3)!=1 \wedge x^3-3x^2+2x-1=23[/tex]

or

[tex]\text{II.}\, (x-3)!=23 \wedge x^3-3x^2+2x-1=1[/tex]

[tex]\text{I.}\\(x-3)!=1\\x-3=0 \vee x-3=1\\x=3 \vee x=4[/tex]

Now, we check if any of these solutions is also a solution to the second equation:

[tex]3^3-3\cdot3^2+2\cdot3-1=23\\27-27+6-1-23=0\\ -18=0[/tex]

Therefore, 3 is not a solution.

[tex]4^3-3\cdot4^2+2\cdot4-1=23\\64-48+8-1-23=0\\0=0[/tex]

Therefore, 4 is a solution.

[tex]\text{II.}[/tex]

[tex](x-3)!=23[/tex]

We know that [tex]3!=6[/tex] and [tex]4!=24[/tex], therefore there isn't any [tex]n\in\mathbb{N}[/tex], for which [tex]n!=23[/tex], so there's no solution.

So, the only solution is [tex]x=4[/tex].

The sales of skin diving and scuba equipment in the year 2008 is (d) 424,550,000

The regression equation is given as;

y = 7.36x - 14,354.33

In 2008, the value of x is

x = 2008

So, we have:

y = 7.36 * 2008 - 14,354.33

Evaluate

y = 424.55

Hence, the sales of skin diving and scuba equipment in the year 2008 is (d) 424,550,000

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The sales of skin diving and scuba equipment in the year 2008 is (d) 424,550,000.

We have given that,

The table below shows the amount of money spent on skin diving and scuba equipment in some recent years.

The regression equation is given as

y = 7.36x - 14,354.33

In 2008, the value of x is

x = 2008

So, we have y = 7.36 * 2008 - 14,354.33

Evaluate y = 424.55

Hence, the sales of skin diving and scuba equipment in the year 2008 is (d) 424,550,000

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The area of the sector, to 4 decimal places, is: 78.6794 cm².

Area of sector = ∅/360 × πr².

Given the following:

Area of sector = 46/360 × π(14²)

Area of sector ≈ 78.6794 cm²

The area of the sector is approximately 78.6794 cm².

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Answer:

Graph of the given equation is a opening up parabola passing through origin (0,0) and (2,0) and having vertex (1,-1)

Step-by-step explanation:

parabola - it is a plane curve generated by a point moving so that its distance from a fixed point is equal to its distance from a fixed line.

vertex - The vertex of a parabola is the point at the intersection of the parabola and its line of symmetry.

the given equation can be resolved as:

[tex]g(x)=(x-1)^2-1\\g(x) = x^2 -2x +1 -1\\g(x) = x^2 - 2x[/tex]

now substituting x = 0,

[tex]g(x) = x^2 - 2x\\g(x) = (0)^2- 2(0)\\g(x) = 0[/tex]

therefore the equation satisfies the point (0,0)that is origin.

now putting g(x) = 0,

[tex]g(x) = x^2 - 2x\\0 = x^2- 2x\\2x = x^2\\2=x[/tex]

so when y coordinate is 0 x coordinate is 2,

therefore the equation also satisfies the (2,0)

general equation of a parabola is

[tex]f(x) = ax^2 + bx + c[/tex]

and the vertex of the parabola is given by  [tex]\frac{-b}{2a}{,}{f{(}\frac{-b}{2a}{)}}[/tex]

given equation of parabola [tex]g(x) = x^2 - 2x[/tex]

here a = 1 and b= -2

substituting in the vertex formula,

vertex of the parabola is [tex]{(}{1}{,}{f{(}{1}{)}}{)}[/tex]

[tex]f(1) = 1 - 2 = -1[/tex]

therefore the vertex is (1,-1).

so the parabola is passing through origin(0,0) and (2,0) with vertex (1,-1).

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Answer:

Step-by-step explanation:

Let :

C = number of cats

D = number of dogs

Raul's pet store has a play area that can fit up to 30 cats and dogs.

C + D = 30

The pet store never has more than 8 cats in the play areas.

(there can never be 9 or more cats)

As or the number of dogs :

C + D = 30

C = 30 - D

Since we know that C < 9. To get the number of dogs allowed, we just plug in 30 - D for C.

30 - D < 9

30 - 9 < D

or

(dogs have to be 22 or more)

Answer:

It has been a while. I think it is ASA and AAS

The triangles ΔLMN and ΔOPQ are congruent triangles by the ASA and AAS postulates

Transformations change the size or position of shapes. Congruent shapes are identical, but may be reflected, rotated or translated. Scale factors can increase or decrease the size of a shape. Congruent Triangles simply mean the triangles that possess the same size and shape

The three sides are equal (SSS: side, side, side)

Two angles are the same and a corresponding side is the same (ASA: angle, side, angle)

Two sides are equal and the angle between the two sides is equal (SAS: side, angle, side)

A right angle, the hypotenuse and a corresponding side are equal (RHS, right angle, hypotenuse, side)

Given data ,

Let the first triangle be represented as ΔLMN

Let the second triangle be represented as ΔOPQ

Now , the measure of ∠MNL = 90°

The measure of ∠PQO = 90°

And , the measure of side MN = measure of side PQ

And , the measure of ∠MLN = measure of ∠POQ

So , the two angles are the same and a corresponding side is the same (ASA: angle, side, angle)

Therefore , the triangles are congruent by AAS and ASA theorems

Hence , the ΔLMN and ΔOPQ are congruent triangles

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Using the normal distribution, it is found that 7.64% of of sample means are greater than 8.8 hours.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The parameters are given as follows:

[tex]\mu = 8.4, \sigma = 1.77, n = 40, s = \frac{1.77}{\sqrt{40}} = 0.2799[/tex]

The proportion of sample means greater than 8.8 hours is one subtracted by the p-value of Z when X = 8.8, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{8.8 - 8.4}{0.2799}[/tex]

Z = 1.43

Z = 1.43 has a p-value of 0.9236.

1 - 0.9236 = 0.0764.

7.64% of of sample means are greater than 8.8 hours.

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0.072 is the margin of error.

The standard error (SE) of a statistic is the standard deviation of its sampling distribution or an estimate of that standard deviation.

According to the question,

In a random sample of 250 students,

p= 0.98 (or 98%) were in favor of longer hours at the school library.

The standard error of p(the sample proportion) is (approximately)

The standard error of p =   [tex]\sqrt{\frac{p(1-p)}{n} }[/tex]

p = 0.98

1 - p = 1 - 0.98 = 0.02

Here,

n = 250

The standard error of p =   [tex]\sqrt{ \frac{0.98 (0.02) }{250}[/tex]

The standard error of p ≈   0.072

Therefore,

The margin of error is 0.072.

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The average time taken to travel to Toronto by  the swarm of Rasberry Crazy Ants  is 12,947 Years

To arrive at the solution above, we need to look at the information given and the information assumed.

Step 1 - Information given:

Step 2 - Information assumed:

The swarm are travelling to the location of the student which is assumed to be Toronto.

Hence,

Time taken for the swam to get to Toronto (TTS) =

Distance between Austin, Texas and Toronto (DBTT) / Average distance covered per day by the Rasberry Ants. (ADC)

Estimated distance between Austin Texas and Toronto = 2592.6 Kilometers

Time travelled per day by the ants (In Km) = 0.00054864

Thus,

TTS  = DBTT/ADC

= 2592.6 /0.00054864

≈ 4,725,503.06 days or

≈ 12,947 Years

The answer to both questions is NO.

The average life expectancy in Toronto (as at 2022) is 80 years. Assuming I was born today, it is expected that the time between now and when my last grand child will die is about:

80 x 3 = 240 years.

Given that the ants have to travel 12,947  to get to Toronto, the possibility of my grand children seeing them is zero.

Besides, even if they by chance got to Toronto and infested my grandchildren's residence, they would have nothing to worry about because Rasberry Crazy Ants are 100% harmless.

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Answer:

Define different tipes of discontuinity of a function .also,write the condition for increasing, decreasing and concave of function

Because both lines have the same slope but different y-intercepts, we conclude that the lines are parallel.

Here we have the two lines:

6x - 2y = -2

y = 3x + 12

If we write both of these in the slope-intercept form, we get:

y = (-2 - 6x)/-2  = 3x + 1

y = 3x + 12

So, as you can see, both lines have the same slope but different y-intercepts. That means that the two lines are parallel, so they never do intercept.

Then we can conclude that the correct option is parallel.

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Answer:

Yes.

Step-by-step explanation:

In mathematics, a number line ends in arrows on both sides, signifying it going infinite in the positive and negative directions.

Answer:

Yes.

Step-by-step explanation:

A number line is infinite in both directions it faces. This means left or right there is a infinite amount of numbers.

The complete question is :

Question: What is the coefficient in the expression 10x²-7?

The coefficient in the expression [tex]10x^{2} -7[/tex] is 10

A numerical or constant quantity placed before and multiplying the variable in an algebraic expression.

According to the question,

The expression given is [tex]10x^{2} -7[/tex]

The variable given is x

We need to find the coefficient in the expression.

In the given expression x is the variable and the number before the x is coefficient which is 10 .

Hence the coefficient in the expression is 10.

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Considering that the mean of the normal distribution is the same as the median, the median is of 88%.

It states that, for a normally distributed random variable:

For the normal distribution, the median is the same of the mean, that is, the median is of 88%.

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Answer:

The number in the green box should be 3.

Step-by-step explanation:

[tex]c + 4 {c}^{2} - 2 + 2c - {c}^{2} + 5 = 3 {c}^{2} + 3c + 3[/tex]

Answer:

D -6, 15

Step-by-step explanation:

Because 3,11 is the middle, and 12,7 is the other end, you can do

12 - 3 = 9

3 - 9 = 6

then

11 - 7 = 4

11 + 4 = 15

so

6 is you x and 15 is your y

Answer:

y = 21x + 413

Step-by-step explanation:

Use y = mx + b

m represents the slope which in this case is 21.

b represents the y - intercept which in this case is 413.

Now, just fill in the variables.

y = 21x + 413

Hope this helps!

The sounds of music are related to trigonometric functions because trigonometry is used in measuring the level of the pitch of a sound wave or musical note.

It should be noted trigonometry is important for measuring pitch level. The notes are measured in Hertz.

A sound wave's amplitude relates to the change in the pressure that's caused by the wave measured at a specific location.

The sound is perceived as louder when the amplitude increases.

Pieces of music often have repetitive choruses or bars, similar to patterns. In mathematics, we look for patterns to interpret and predict the unknown. Music uses the same techniques. If you look at a piece of music, artists look at the notes they see to find the rare (high or low) and uncommon notes.

In this way, the notes are related. Relationships are important in mathematics and create an interesting link between music and mathematics.

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Answer:

C. 261

Step-by-step explanation:

45 times 7= 315

326-315=11

125 times 2=250

250+11=261

so the answer is C. $261