The relative velocity of the fluid (air) in relation to the sprinter is 5.2 m/s north.
To determine the relative velocity of the fluid (air) in relation to the sprinter, we need to calculate the vector sum of the sprinter's velocity and the wind velocity.
Since the sprinter is moving north and the wind is moving south, we can consider the north direction to be positive and the south direction to be negative.
The magnitude of the sprinter's velocity is 9.4 m/s, and the magnitude of the wind's velocity is 4.2 m/s.
To calculate the vector sum, we need to add the two velocities as vectors, taking into account their direction:
Relative velocity = 9.4 m/s north + (-4.2 m/s south)
We can simplify this by subtracting the magnitudes:
Relative velocity = 9.4 - 4.2 = 5.2 m/s north
Therefore, the relative velocity of the fluid (air) in relation to the sprinter is 5.2 m/s north.
To learn more about direction visit:
https://brainly.com/question/13899230
#SPJ11
T/F. It is OK to turn the power on to the circuit before my TA checks it. FALSE
TRUE. It is not safe to turn on the power to a circuit before a TA (teaching assistant) checks it. This can pose a risk of electrical shock or other hazards.
It is important to follow proper safety protocols and wait for an authorized person to check and approve the circuit before powering it on.
True or False: It is OK to turn the power on to the circuit before my TA checks it.
It is not OK to turn the power on to the circuit before your TA checks it. It is essential to ensure the circuit is correctly assembled and safe to use before applying power. Having your TA check the circuit helps prevent potential issues or hazards.
Visit here to learn more about TA (teaching assistant):
brainly.com/question/30823451
#SPJ11
if you inhale as deeply as possible, and then exhale as much as possible, the expelled air is called your group of answer choices
The expelled air that you inhale as deeply as possible and then exhale as much as possible is called Vital Capacity.
Vital Capacity is the maximum volume of air that can be exhaled from the lungs after a maximum inhalation. It represents the amount of air that a person can voluntarily and forcibly exhale. This measure is used to evaluate lung function and can be affected by various factors such as age, gender, height, and physical condition. Vital capacity is an important measure of respiratory health and is often used to diagnose and monitor respiratory diseases such as asthma, chronic obstructive pulmonary disease (COPD), and emphysema.
Learn more about Vital Capacity here:
https://brainly.com/question/31313002
#SPJ11
A ball is thrown straight up into the air with 100 J of kinetic energy. How much kinetic energy does it have at the peak of its flight?
Entry field with correct answer
100 J
0 J
50 J
- 100 J
When a ball is thrown straight up into the air, it undergoes a change in its potential energy and kinetic energy. Initially, the ball has only kinetic energy, which is equal to 100 J. The Kinetic energy at the peak of its flight will be 0 J.
As the ball rises, it loses its kinetic energy and gains potential energy, which is stored in its position relative to the ground.
At the peak of its flight, the ball momentarily stops before it begins to fall back down due to the force of gravity. Therefore, at the peak of its flight, the ball has zero velocity and kinetic energy.
All of its initial kinetic energy has been converted to potential energy.
Therefore, the answer to the question is that the ball has 0 J of kinetic energy at the peak of its flight.
This is because kinetic energy is dependent on velocity, and since the ball has momentarily stopped at the peak of its flight, it has zero velocity and zero kinetic energy. Hence, the right answer will be 0 J.
For more such answers on kinetic energy
https://brainly.com/question/8101588
#SPJ11
1. if the capacitor of fig. 15.2 were decreased to 0.01 uf, would the current source be a good design for the chosen frequency range?
In order to determine whether the current source is a good design for the chosen frequency range when the capacitor of fig. 15.2 is decreased to 0.01 uf, we need to consider the effect of the capacitor on the circuit's impedance. Capacitors have a capacitive reactance (Xc) that varies inversely with frequency, given by the equation Xc = 1/(2πfC), where f is the frequency and C is the capacitance.
When the capacitance is decreased to 0.01 uf, the capacitive reactance increases, meaning that the circuit's impedance increases at higher frequencies. This can have the effect of attenuating higher frequency signals and reducing the overall performance of the current source.
Therefore, if the chosen frequency range is above the cutoff frequency determined by the decreased capacitance, then the current source may not be a good design. However, if the chosen frequency range is well below the cutoff frequency, then the current source may still be a good design. It ultimately depends on the specific application and frequency requirements.
To know more about frequency range:
https://brainly.com/question/31117161
#SPJ11