The solubility of the magnesium fluoride, MgF₂, in the water is 1.5 × 10⁻² g/l. The solubility of magnesium fluoride in 0.13 M of the sodium fluoride, NaF is 0.88 M.
The solubility, Ksp = 1.5 × 10⁻² g/L
The concentration , NaF = 0.13 M
The solubility of the magnesium fluoride that is MgF₂ is expressed as :
The solubility of the magnesium fluoride = Ksp / NaF²
The solubility of the magnesium fluoride = 1.5 × 10⁻² / (0.13 )²
The solubility of the magnesium fluoride = 0.88 M
Therefore, the solubility of the magnesium fluoride in 0.13 M of the sodium fluoride is 0.88 M.
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why is iron widely extracted in the industries
Answer: it's an integral component of steel
Explanation: it's also an economic essential to US growth and is used for transportation, energy, and construction
A 100 n force pulls a box horizontally across a floor for 2 m. how much was done by the force of gravity (which pulls straight down on the box)?
a. 50 j
b. 0 j
c. 100 j
d. 200 j
The net work done is 0 J. (B)
The force of gravity only affects the box vertically, not horizontally, so it doesn't do any work in this scenario. Only the applied force of 100 N pulling the box horizontally for 2 m does work.
This work can be calculated using the formula: Work = Force x Distance x Cos(theta), where theta is the angle between the force and the displacement.
In this case, since the force is applied horizontally, theta is 0, so the work done is simply: Work = 100 N x 2 m x Cos(0) = 200 J. Therefore, the correct answer is (b) 0 J for the work done by the force of gravity.(B)
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0.97 g of product were generated in a reaction, which corresponds to 63.1% yield. what is the theoretical yield of this reaction in grams?
The theoretical yield of this reaction in grams is approximately 1.54 g.
The theoretical yield of a reaction is the maximum amount of product that could be obtained if the reaction went to completion. In this case, since we know the actual yield (0.97 g) and the percent yield (63.1%), we can use this information to calculate the theoretical yield.
First, we can use the percent yield formula to calculate the actual amount of product that was expected based on the theoretical yield:
Percent yield = (actual yield / theoretical yield) x 100
Rearranging this formula, we can solve for the theoretical yield:
Theoretical yield = actual yield / (percent yield / 100)
Plugging in the values we know, we get:
Theoretical yield = 0.97 g / (63.1 / 100) = 1.54 g
Therefore, the theoretical yield of this reaction is 1.54 g. This means that if the reaction had gone to completion, we would have expected to obtain 1.54 g of product. The actual yield of 0.97 g represents only 63.1% of the theoretical yield.
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Katja plans an experiment that measures the temperature of different colors of paper placed in sunlight. Her hypothesis is that if black, blue, yellow, red, and white sheets of paper are exposed to white light, then the black sheet of paper will increase the most in temperature. Katja will place a sheet of each color of paper of the same size and thickness in the same location for the same amount of time. Why will katja use different colors of paper in her experiment?
Katja will use different colors of paper in her experiment to test her hypothesis and determine which color of paper will increase the most in temperature when exposed to sunlight.
By using a variety of colors, Katja can compare the results and determine if her hypothesis is correct or if another color of paper increases the most in temperature.
This experiment will provide valuable information about the effects of different colors on temperature and can be useful in a variety of applications, such as in the development of materials that are resistant to heat or for designing energy-efficient buildings that reflect sunlight.
Ultimately, the use of different colors of paper in this experiment allows for a more thorough and accurate analysis of the relationship between color and temperature.
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KOH (aq) + H3PO4 (aq) → K3PO4 (aq) + H2O (l)
The above chemical reaction is an example of
A. Synthesis
B. Single replacement
C. Double replacement
D. Decomposition
C. Double Replacement. The double replacement reaction occurs when two compounds exchange their cations and anions to form two new compounds. In the given equation, the cation of KOH (potassium) and the anion of H3PO4 (phosphate) switch places to form K₃PO₄ and H₂O.
What is compound?Compound is a type of molecule that is made up of two or more atoms of different elements bonded together. This type of bond is called a covalent bond, and it is formed when the atoms share electrons. Compounds can be organic or inorganic, and can be found almost everywhere in nature. Organic compounds are made up of carbon and hydrogen, and are found in living organisms. Inorganic compounds do not contain carbon and can be found in water, soil, rocks, and many other places. Compounds can be used in everyday life, such as in medicines, plastics, and fuels.
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The temperature of a sample of gas in a steel tank at 50.0 kPa is
increased from -100.0°C to 35.0 °C. What is the final pressure
inside the tank?
The final pressure inside the tank is 88.9 kPa.
How to find the final pressureTo solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas.
The combined gas law is given by:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
where
P1 and T1 are the initial pressure and temperature of the gas,
V1 is the initial volume of the gas,
P2 is the final pressure of the gas,
V2 is the final volume of the gas, and
T2 is the final temperature of the gas.
We can assume that the volume of the gas in the tank remains constant, since it is a steel tank. Therefore, V1 = V2.
We can convert the temperatures to Kelvin by adding 273.15 to each temperature value. Therefore,
T1 = 173.15 K and
T2 = 308.15 K.
Substituting these values into the combined gas law, we get:
(50.0 kPa * V1) / (173.15 K) = (P2 * V1) / (308.15 K)
P2 = (50.0 kPa * 308.15 K) / 173.15 K
P2 = 88.98 kPa
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Answer:
88.98 kPa (2 d.p.)
Explanation:
To find the final pressure inside the steel tank, we can use Gay-Lussac's law since the volume is constant.
Gay-Lussac's law[tex]\boxed{\sf \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}}[/tex]
where:
P₁ is the initial pressure.T₁ is the initial temperature (in kelvins).P₂ is the final pressure.T₂ is the final temperature (in kelvins).As we are solving for the final pressure, rearrange the equation to isolate P₂:
[tex]\sf P_2=\dfrac{P_1T_2}{T_1}[/tex]
Convert the given temperatures from Celsius to Kelvin by adding 273.15:
[tex]\implies \sf T_1=-100+273.15=173.15\;K[/tex]
[tex]\implies \sf T_2=35+273.15=308.15\;K[/tex]
Therefore, the values to substitute into the equation are:
P₁ = 50.0 kPaT₁ = 173.15 KT₂ = 308.15 KSubstitute the values into the equation and solve for P₂:
[tex]\implies \sf P_2=\dfrac{50.0\cdot 308.15}{173.15}[/tex]
[tex]\implies \sf P_2=\dfrac{15407.5}{173.15}[/tex]
[tex]\implies \sf P_2=88.98354028...[/tex]
[tex]\implies \sf P_2=88.98\;kPa\;(2\;d.p.)[/tex]
Therefore, the final pressure inside the steel tank is 88.98 kPa when the temperature is increased from -100.0°C to 35.0°C.
Which solubility curve on the right best represents the data table on the left?
A solubility curve is a graphical representation of the solubility of a substance in a specific solvent as a function of temperature.
The solubility is typically expressed in grams of solute per 100 grams of solvent. In order to answer the question of which solubility curve on the right best represents the data table on the left, we need to compare the solubility values in the data table with the solubility values on each of the curves.
We can see from the data table that the solubility of the substance increases with temperature, which is a common trend for most substances. As the temperature increases, the solvent molecules move faster, which allows more solute molecules to dissolve.
To compare the data table with the solubility curves, we need to look for the curve that shows an increase in solubility with increasing temperature. We can see that Curve A fits this description. The solubility values on Curve A increase as the temperature increases, just like the data table.
Therefore, we can conclude that Curve A best represents the data table on the left.
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Plan an investigation to explore the relationship between properties of substances and the electrical forces within those substances.
What can properties of substances tell us about the electrical forces within those substances?
In this activity, you will plan and conduct an investigation to compare a single property across several substances. You must select a measurable property, such as boiling point or surface tension. After your investigation, you will compare the results and use your data to make inferences about the strength of the electrical forces in each substance you tested
The first step in this investigation will be to select several substances to test. It is important to choose substances that have similar chemical composition but differ in physical properties.
Once the substances have been selected, the next step is to measure the single property across each of the substances. This can be done through a variety of methods, such as using a thermometer to measure boiling points or a microscope to measure surface tension.
After the data has been collected, it should be compared and analyzed to determine how the property is related to the strength of the electrical forces in the substance. By comparing the data and making inferences, it is possible to determine how properties of substances can indicate the strength of the electrical forces within those substances.
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If you start with 29. 25 g of NaOH and 107 g of FeCl3, find the reaction yield and the limiting reactant. Show your work
Starting with 29.25 g of NaOH and 107 g of FeCl₃, the limiting reactant is NaOH with yeild percentage of 60%.
To find the reaction yield and the limiting reactant, starting with 29.25 g of NaOH and 107 g of FeCl₃, you need to perform the following steps:
1. Write the balanced chemical equation:
FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl
2. Calculate moles of each reactant:
NaOH: 29.25 g / (23.0 g/mol Na + 15.99 g/mol O + 1.01 g/mol H) ≈ 0.729 moles
FeCl₃: 107 g / (55.85 g/mol Fe + 3 * 35.45 g/mol Cl) ≈ 0.397 moles
3. Identify the limiting reactant:
For every mole of FeCl₃, you need 3 moles of NaOH. Divide moles of each reactant by their coefficients in the balanced equation:
NaOH: 0.729 moles / 3 ≈ 0.243
FeCl₃: 0.397 moles / 1 ≈ 0.397
The smaller value is for NaOH, so it is the limiting reactant.
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1. )There are Blank 1 grams in one mole of KI. Please round atomic masses to the nearest whole number.
2. )There are Blank 1 grams in one mole of ZnCl2. Please round atomic masses to the nearest whole number.
3. )The molar mass of P2O5 is Blank 1 grams per mole. Please round atomic masses to the nearest whole number.
4. )The molar mass of barium cyanide is Blank 1 grams per mole. Please round atomic masses to the nearest whole number.
5. )The molar mass of nickel (I) chromate is Blank 1 grams per mole. Please round atomic masses to the nearest whole number
How many grams of KNO3 are needed to make 1. 50 liters of a 0. 50 M KNO3 solution?
We need 75.825 grams of KNO₃ to make 1.50 liters of a 0.50 M KNO₃ solution.
To calculate the number of grams of KNO₃ needed to make a 0.50 M solution of KNO₃ in 1.50 L of water, we need to use the following formula:
Molarity (M) = moles of solute/liters of solution
Rearranging the formula, we can find the moles of solute needed:
moles of solute = Molarity (M) x liters of solution
Substituting the given values, we get;
moles of KNO₃ = 0.50 M x 1.50 L = 0.75 moles
To find the mass of KNO₃ required, we need to use the molar mass of KNO₃. The molar mass of KNO₃ is;
K; 39.10 g/mol
N; 14.01 g/mol
O; 16.00 g/mol
Molar mass of KNO₃ = 39.10 + 14.01 + (3 x 16.00)
= 101.10 g/mol
Now, we can calculate the mass of KNO₃ needed as follows;
mass of KNO₃ = moles of KNO₃ x molar mass of KNO₃
= 0.75 moles x 101.10 g/mol
= 75.825 g
Therefore, we need 75.825 grams of KNO₃.
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The pressure at the bottom of a lake is 2. 35 atm. If water saturated with oxygen
(concentration 0,34 g/L) is carried by a current to to a depth where the solubility
of oxygen is 0. 21 g/L, what is the pressure of the water.
The pressure at the bottom of a lake is given as 2.35 atm, and we are asked to find the pressure of the water. Since water is the fluid in question, we can assume that it is incompressible and that its density is constant. To find the pressure of the water, we can use the following formula:
Pressure = Density x Acceleration due to gravity x Height
Here, the height refers to the depth of the lake, which we can assume to be the same as the height of the water column. The acceleration due to gravity is a constant, and the density of water is given as 0.21 g/L.
Substituting these values in the formula, we get:
Pressure = 0.21 g/L x 9.8 m/s^2 x Depth
Since the pressure at the bottom of the lake is given as 2.35 atm, we can convert this to SI units using the conversion factor:
1 atm = 101325 Pa
Therefore, 2.35 atm = 2.35 x 101325 Pa = 2.38 x 10^5 Pa
Substituting this value in the formula, we can solve for the depth:
2.38 x 10^5 Pa = 0.21 g/L x 9.8 m/s^2 x Depth
Depth = 114.7 m
Therefore, the pressure of the water at this depth is:
Pressure = 0.21 g/L x 9.8 m/s^2 x 114.7 m = 240.3 kPa
In conclusion, the pressure of the water at the bottom of the lake is 240.3 kPa. This is the pressure exerted by the water column due to its weight, and it is in addition to the atmospheric pressure. Understanding the pressure of fluids is important in many fields, such as hydrology, engineering, and physics.
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It’s due tomorrow and I don’t know how to do it.
Two students made the Lewis dot diagrams of NH3. The diagrams are as shown.
Two visual diagrams of an N H three molecule are shown. Student As diagram on the left has nitrogen at the center and connects with each hydrogen atom by an arrow pointing away from nitrogen, one below, one on the right, and one on the left. There is a pair of dots above the nitrogen atom. Student Bs diagram on the right has nitrogen at the center connecting by a straight line to each hydrogen positioned below, to the left, and to the right of nitrogen.
Which student drew the correct Lewis dot diagram? (4 points)
Group of answer choices
Only Student A
Only Student B
Both Student A and Student B
Neither Student A nor Student B
Answer:
only student B
Explanation:
five electrons int eh valence shell of nitrogen atoms
Unit 6 Critical Thinking Questions! (HELP) - 30 POINTS
1. Compare and contrast positive and negative feedback loops of the endocrine system. Provide a specific example of each, including which gland is responsible for the hormone related to that loop.
2. What is the difference between endocrine and exocrine glands in terms of both form and function? Why is one type not considered part of the endocrine system?
3. Describe the cascade of events that occurs when blood glucose levels decline, including which organ and cells respond, which hormones are released, and how the process helps maintain homeostasis. Your answer should cover all three ways glucose is re-introduced to the body. What is the ultimate use of the glucose created in this process?
4. Why can both type I and type II diabetes, untreated, result in impaired vision or blindness as someone ages? How does type II diabetes turn into type I diabetes as someone ages?
5. Imagine you have a patient who has come to you and is exhibiting symptoms such as fatigue and increased thirst and urination. What would you check for to determine whether the patient has Cushing’s, type I diabetes, or type II diabetes?
1. Positive feedback loops amplify or increase changes, while negative feedback loops counteract or reduce changes.
2. The main difference between endocrine and exocrine glands is that endocrine glands secrete hormones directly into the bloodstream, while exocrine glands secrete substances through ducts.
3. When blood glucose levels decline, the pancreas' alpha cells release glucagon, which signals the liver to break down glycogen into glucose, promotes gluconeogenesis, and releases glucose into the bloodstream.
4. Both type I and type II diabetes can result in impaired vision or blindness due to high blood sugar damaging blood vessels in the retina.
5. To determine if a patient has Cushing's, type I diabetes, or type II diabetes, check for cortisol levels (Cushing's), insulin levels, and blood sugar levels (diabetes).
1. An example of a positive feedback loop is oxytocin release during childbirth from the posterior pituitary gland. An example of a negative feedback loop is the regulation of thyroid hormones by the thyroid gland, where a decrease in hormone levels triggers the release of more hormones.
2. Endocrine glands are part of the endocrine system, while exocrine glands are not, due to their use of ducts for secretion.
3. The ultimate use of this glucose is to provide energy for the body.
4. Type II diabetes doesn't turn into type I diabetes as they are distinct conditions.
5. Additional tests may include glucose tolerance and autoimmune marker tests.
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Which substance is always produced in the reaction between hydrochloric acid and sodium hydroxide.
The reaction between hydrochloric acid ([tex]HCl[/tex]) and sodium hydroxide ([tex]NaOH[/tex]) is a classic example of an acid-base neutralization reaction. In this reaction, the hydrogen ions ([tex]H+[/tex]) in the acid react with the hydroxide ions ([tex]OH-[/tex]) in the base to form water ([tex]H2O[/tex]) and a salt, which in this case is sodium chloride ([tex]NaCl[/tex]).
The balanced chemical equation for the reaction is:
[tex]HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)[/tex]
So, the substance that is always produced in the reaction between hydrochloric acid and sodium hydroxide is water and a salt, which is sodium chloride. This reaction is exothermic and the heat released during the reaction can be used to increase the temperature of the solution.
This reaction is widely used in the chemical industry for various applications such as neutralizing acidic waste, producing table salt, and in the production of soap and detergents.
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Find the number of grams of zinc (Zn) metal that will completely react with 730
grams of hydrochloric acid (HCl) to produce zinc chloride (ZnCl2) and hydrogen gas
(H2).
Write the balanced chemical equation.
Use coefficients from balanced equation to determine mole ratio
654 grams of Zn metal will completely react with 730 grams of HCl
The balanced chemical equation for this reaction is:
Zn + 2HCl → ZnCl2 + H2
From the equation, we can see that for every 1 mole of Zn, 2 moles of HCl are required for a complete reaction. This means the mole ratio of Zn to HCl is 1:2.
To determine the number of moles of HCl used, we need to convert the given mass of HCl to moles. The molar mass of HCl is 36.5 g/mol, so:
730 g HCl x (1 mol HCl/36.5 g HCl) = 20 moles HCl
Using the mole ratio from the balanced equation, we can determine the number of moles of Zn required:
20 moles HCl x (1 mol Zn/2 mol HCl) = 10 moles Zn
Finally, we can convert the number of moles of Zn to grams using its molar mass of 65.4 g/mol:
10 moles Zn x (65.4 g Zn/mol) = 654 grams of Zn
Therefore, 654 grams of Zn metal will completely react with 730 grams of HCl to produce ZnCl2 and H2.
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Drag each label to the correct location on the diagram. Each label can be used more than once.
What is the correct way to represent the ionic compound sodium fluoride?
thank you so much
There is the transfer of one electron from sodium to fluorine atoms.
What is the ionic bonding?Ionic bonding is a type of chemical bond that occurs between atoms that have a large difference in their electronegativity, which is the ability of an atom to attract electrons towards itself in a chemical bond.
In ionic bonding, one atom transfers one or more valence electrons to another atom, forming two oppositely charged ions. The atom that loses electrons becomes a positively charged ion, called a cation, while the atom that gains electrons becomes a negatively charged ion, called an anion.
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Calculate the theoretical yield of alf3 obtained from 0.45 mol of al in the reaction 2ai + 3f2 2aif3
The theoretical yield of aluminum fluoride (AlF₃) obtained from 0.45 mol of aluminum (Al) is 0.45 mol.
The balanced chemical equation for the reaction between aluminum (Al) and fluorine (F₂) to form aluminum fluoride (AlF₃) is:
2 Al + 3 F₂ → 2 AlF₃
According to the equation, 2 moles of aluminum react with 3 moles of fluorine to produce 2 moles of aluminum fluoride. Therefore, the stoichiometric ratio of aluminum to aluminum fluoride is 2:2 or 1:1.
Given that 0.45 mol of aluminum is used in the reaction, the theoretical yield of aluminum fluoride can be calculated as follows:
0.45 mol Al × (2 mol AlF₃ ÷ 2 mol Al) = 0.45 mol AlF₃
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If the molal concentration in water is the same for the following substances, rank these solutions in decreasing melting point. Highest placed in the rank will have the highest melting point.
calcium phosphate, Ca3(PO4)2
glucose, c6h12o6
sodium chloride, NaCl
magnesium chloride, MgCl2
The ranking of these solutions in decreasing melting point is: calcium phosphate > magnesium chloride > sodium chloride > glucose.
To rank the solutions with the same molal concentration in decreasing order of their melting points, we need to consider their van't Hoff factor (i), which represents the number of particles a solute dissociates into when dissolved in water. The formula to calculate the effect of a solute on the melting point of a solution is ΔTf = Kf × m × i, where Kf is the cryoscopic constant of water, m is the molality, and i is the van't Hoff factor.
Here are the van't Hoff factors for each substance:
1. Calcium phosphate, Ca₃(PO₄)₂: This substance dissociates into 5 ions (3 Ca²⁺ + 2 PO₄³⁻), so i = 5.
2. Glucose, C₆H₁₂O₆: This substance is a molecular compound and does not dissociate into ions, so i = 1.
3. Sodium chloride, NaCl: This substance dissociates into 2 ions (Na⁺ + Cl⁻), so i = 2.
4. Magnesium chloride, MgCl₂: This substance dissociates into 3 ions (Mg²⁺ + 2 Cl⁻), so i = 3.
Using the van't Hoff factor, we can rank the solutions in decreasing order of their melting points:
1. Calcium phosphate, Ca₃(PO₄)₂ (i = 5)
2. Magnesium chloride, MgCl₂(i = 3)
3. Sodium chloride, NaCl (i = 2)
4. Glucose, C₆H₁₂O₆ (i = 1)
So, the ranking of these solutions in decreasing melting point is: calcium phosphate > magnesium chloride > sodium chloride > glucose.
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1. -
Averigua la molaridad de una disolución que contiene 58,8 gramos de yoduro de calcio (CaI2) , por litro
The molarity of the solution comes out to be 0.200 M, which is calculated in the below section.
The number of moles of calcium iodide can be calculated as follows-
n = m / M ......(1)
Molar mass (M) of Calcium iodide = 293.887 g/mol
Mass (m) = 58.8 grams
Substitute the known values in equation (1) as follows-
n = 58.8 grams / 293.887 g/mol
= 0.200 moles
Now, the molarity can be calculated using the below formula-
Molarity = no. of moles / Volume
= 0.200 moles / 1 L
= 0.200 M
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Complete question-
Find the molarity of a solution that contains 58.8 grams of calcium iodide (CaI2), per liter.
The temperature of CI 2 is changed from 836. 06 K to 625. 29 K. If its new volume is 14. 509 L, what was its original volume in liters?
The original volume of CI₂ was 19.33 L.
According to Charles' Law, the volume of a gas is directly proportional to its temperature at constant pressure. This can be expressed as V₁/T₁ = V₂/T₂, where V₁ and T₁ are the initial volume and temperature, and V₂ and T₂ are the final volume and temperature.
In this problem, we are given the initial temperature (T₁ = 836.06 K), final temperature (T₂ = 625.29 K), and final volume (V₂ = 14.509 L). We are asked to find the initial volume (V₁). To do this, we can rearrange the Charles' Law equation to solve for V₁:
V₁ = (V₂/T₂) x T₁
Plugging in the values, we get:
V₁ = (14.509 L/625.29 K) x 836.06 K
V₁ = 19.35 L
As a result, the initial volume of CI₂ was 19.33 L.
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For each of the following compounds, decide whether the compound's solubility in aqueous solution changes with pH. If the solubility does change, pick the pH at which you'd expect the highest solubility. You'll find Ksp data in the ALEKS Data tab.
compound Does solubility change with pH? highest solubility pH = 5 | pH = 7. PH | pH = 8
NaBr Васо, OOOOO Сасі, X 5 ? Formula BaCrO4 BaSO4 CaCO3 CaF2 Co(OH)2 CuBr CuCO3 Fe(OH)2 POCO3 PbCr04 PbF2 Mg(OH)2 Ni(OH)2 AgBroz A92CO3 AgCI Ag2 CrO4 SrCO3 ZnCO3 Zn(OH)2 AgBr Aucl Ksp 1. 17x10-10 1. 08x10-10 3. 36x10-9 3. 45x10-11 5. 92x10-15 6. 27x10-9 1. 4x10-10 4. 87x10-17 7. 40x10-14 2. 8x10-13 3. 3x10-8 5. 61x10-12 5. 48x10-16 5. 38x10-5 8. 46x10-12 1. 77x10-10 1. 12x10-12 5. 60x10-10 1. 46x10-10 3. 0x10-17 5. 35x 10-13 1. 77x10-10
The solubility of some compounds does change with pH. Specifically, the solubility of compounds containing hydroxide ions (OH-) or carbonate ions (CO3^2-) will increase as the pH becomes more basic. For example, CaCO3 and Mg(OH)2 will have higher solubility at pH 8 compared to pH 5 or 7.
On the other hand, compounds containing sulfates (SO4^2-) or fluorides (F-) will have minimal pH dependence. For example, BaSO4 and CaF2 will have similar solubility at pH 5, 7, and 8.
For compounds with Ksp values given in the table, the pH at which highest solubility is achieved is dependent on the specific compound. The highest solubility pH for each compound can be determined by examining the specific ion involved and its dependence on pH.
Based on the provided Ksp values, I'll analyze the solubility of some of the compounds at different pH levels:
1. NaBr: Solubility does not change with pH as it's a neutral salt and neither cation nor anion react with water.
2. BaCrO4: Solubility changes with pH. Highest solubility at pH = 7, because the anion (CrO4^2-) can form a precipitate with Ba^2+ at lower pH levels.
3. CaCO3: Solubility changes with pH. Highest solubility at pH = 5, because the anion (CO3^2-) can form a precipitate with Ca^2+ at higher pH levels.
4. CaF2: Solubility does not significantly change with pH as it's a slightly soluble salt, and the anion (F-) does not react with water.
5. Co(OH)2: Solubility changes with pH. Highest solubility at pH = 5, because the compound can form a precipitate at higher pH levels due to increased hydroxide concentration.
Note that due to the format of the provided information, it's not possible to analyze all compounds. However, this methodology can be applied to the remaining compounds based on their Ksp values and potential reactions with water.
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If a person consumes 5. 33 × 105 kcal in a day and one barrel of oil can produce 3. 70 × 106 kcal, what is the equivalent of energy consumed per year by that person in terms of barrels of oil?
The person consumes approximately 144 barrels of oil equivalent energy per year.
To calculate the equivalent energy consumed by the person in barrels of oil per year, we need to divide the total energy consumed by the person in a year by the energy produced by one barrel of oil.
Energy consumed per year = 5.33 × 10⁵ kcal/day × 365 days = 1.94945 × 10⁸ kcal/year
Energy produced by one barrel of oil = 3.70 × 10⁶ kcal/barrel
Therefore, the equivalent energy consumed by the person in barrels of oil per year is:
1.94945 × 10⁸ kcal/year ÷ 3.70 × 10⁶ kcal/barrel = 52.6 barrels of oil/year
Rounding this to the nearest whole number, we get that the person consumes approximately 144 barrels of oil equivalent energy per year.
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Shaving cream has gas dispersed throughout the cream. What type of mixture is this?
colloid is the answer
What is the molality of 653. grams of ethylene glycol C₂H6O2 in 500. mL of water?
Regardless of the electron or hydrogen acceptor used, one of the products of fermentation is always:.
The product of fermentation that is always produced regardless of the electron or hydrogen acceptor used is ethanol (C2H5OH) or lactic acid (C3H6O3) depending on the type of fermentation.
Fermentation is a metabolic process that occurs in the absence of oxygen and involves the breakdown of glucose or other organic compounds by microorganisms.
It is a type of anaerobic respiration, which does not require oxygen as the final electron acceptor. During fermentation, the organic compounds are partially oxidized, and the energy released is used to generate ATP, the energy currency of cells.
Different microorganisms can carry out fermentation using different electron or hydrogen acceptors, such as pyruvate, acetaldehyde, or acetyl-CoA.
However, regardless of the acceptor used, the end products are typically ethanol or lactic acid, along with carbon dioxide and small amounts of other byproducts.
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A sample of copper has a mass of 500. grams. If this sample absorbs 12 750 joules of heat,
how much will its temperature change?
The amount by which the temperature of the sample of copper will change is 66.23°C.
How to calculate change in temperature?The change in temperature (∆T) of a substance can be calculated using the following calorimetric equation:
Q = mc∆T
Where;
Q = quantity of heat absorbed or releasedm = mass c = specific heat capacity∆T = change in temperatureAccording to this question, a sample of copper has a mass of 500 grams. If this sample absorbs 12750 joules of heat, the ∆T can be calculated thus;
∆T = 12750J ÷ (500g × 0.385J/g°C)
∆T = 66.23°C
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Help what’s the answer?
The mass of the NF3 that is produced from the calculation in the question is 21 g.
How does the limiting reactant decide the product?The limiting reactant determines the amount of product that can be formed in a chemical reaction because it is the reactant that is completely consumed during the reaction.
Number of moles of F2 = 16.5 g/38 g/mol
= 0.43 moles
Number of moles of N2 = 16.5g/28 g/mol
= 0.59 moles
Now;
If 1 mole of N2 reacts with 3 moles of F2
0.59 moles of N2 reacts with 0.59 * 3/1
= 1.77 moles of F2
Thus F2 is the limiting reactant
3 moles of F2 produces 2 moles of NF3
0.43 MOLE OF F2 will produce 0.43 * 2/3
= 0.29 moles
Mass of NF3 produced = 0.29 moles * 71 g/mol
= 21 g
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6-hydroxy-3,4-dimethyl-2-heptanone forms a cyclic hemiacetal, which predominates at equilibrium in aqueous solution. how many stereoisomers are possible for 6-hydroxy-3,4-dimethyl-2-heptanone? how many stereoisomers are possible for the hemiacetal?
6-hydroxy-3,4-dimethyl-2-heptanone has four stereoisomers and the cyclic hemiacetal derived from it can exist as two stereoisomers.
6-hydroxy-3,4-dimethyl-2-heptanone has two chiral centers (carbon atoms with four different substituents attached), which gives rise to four possible stereoisomers: two pairs of enantiomers, each pair of which are diastereomers of the other pair.
When 6-hydroxy-3,4-dimethyl-2-heptanone forms a cyclic hemiacetal, it creates another chiral center at the carbon atom that is involved in the formation of the hemiacetal. The hemiacetal can exist as two possible diastereomers, depending on the configuration of the hydroxyl group and the methyl group on the newly formed chiral center. Therefore, there are two possible stereoisomers for the cyclic hemiacetal.
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