The relationship that exists between gravity and distance and mass respectively.

A. The gravitational force is directly proportional to the distance between objects and inversely
proportional to the mass of the objects.
B. The gravitational force is inversely proportional to the distance between objects and directly
proportional to the mass of the objects.
C. The gravitational force is inversely proportional to the distance between objects and inversely
proportional to the mass of the objects.
D. The gravitational force is directly proportional to the distance between objects and directly
proportional to the mass of the objects.

Answer:

It would take the cyclist 2 hours to cycle to school.

Explanation:

5km/hr for 2 hours would be 10km.

Answer:

sound travels faster in the night

Explanation:

Answer:

it is a the answer is a btw

Explanation:

Answer:

It is a constant when the light is traveling in a vacuum.

Answer:

I believe gravity is acting on it

Answer: D. 332n

Explanation: I took the quiz and that was the correct answer

Answer:

Protons and electrons are charged particles. Neutrons have no charge.

Answer:

10N each

Explanation:

Doing a little math here to make it balanced. 10+10=20 therefore you have the same on both sides.

Hope this helps!

Answer:

The ones that are after the light that went out are also out.

Explanation:

Answer:

they all go out

Explanation:

they are wired together so they all go out. i am an electrician.

Answer:

(a) Cyclist A travels faster.

(b) The time taken by cyclists A and B is 10 minutes and 8.58 minutes respectively.

Explanation:

Given that the speed of cyclist A= 24 km/h

As 1 km = 1000 m and 1 hour= 3600 seconds.

So, [tex]24 \frac {km}{h}=24\times \frac{1000 m}{3600 s}=\frac{20}{3}\frac {m}{s}=6.67 m/s[/tex]

and the speed of cyclist B = 6.8 m/s.

The length of the road = 4 km=4000 m.

(a) Speed of cyclist A is 6.67 m/s which is more than the 6.8 m/s.

Hence, cyclist A travels faster.

(b) If d be the distance to be traveled and V be the speed, than the time, t, required is,

[tex]t=\frac{d}{V}\cdots(i)[/tex]

For cyclist A:

As A is located at the beginning of the road, he has to cover full length of the road.

So, the distance to be covered by cyclist A =4 km.

Hence, from equation (i), the time taken by cyclist A is

[tex]t=\frac{4}{24}=\frac{1}{6}[/tex] hour

[tex]=\frac{1}{6}\times {60}=10[/tex] minutes. [ as 1 hour = 60 minumes]

So, time taken by cyclist A is 10 minutes.

For cyclist B:

As B is located 500 meters later from the beginning of the road, he has to cover the remaining length of the road.

So, the distance to be covered by cyclist B =4000 m-500 m= 3500 m.

Hence, from equation (i), the time taken by cyclist B is

[tex]t=\frac{3500}{6.8}=514.71[/tex] seconds

As 60 seconds= 1 minute.

So, t= 514.71/60 minutes = 8.58 minutes.

[tex]=\frac{1}{6}\times {60}=10[/tex] minutes. [ as 1 hour = 60 minumes]

So, the time taken by cyclist B is 8.58 minutes.

Answer:

balance is tha answer hope it us helpful

Explanation:

for most everyday objects scientist use a balance to obtain an object mass .A Balance compares an object with a known mass to object the question

Answer:

This system uses angular momentum and torque to do work on objects, typically against the force of gravity. The wheel and axle simple machine is closely related to gears.

Answer: C. Light energy.

Explanation:

Answer:

agear lever or agear stick is the lever that you use to change gear in acar or other vehicle

Answer:

5m/s is the answer s=d/t 25/5=5m/s

Answer:

5m/s

Explanation:

The formula for speed is s=distance/time. The distance traveled was 25 meters. The time it took to travel that distance was 5 seconds. Therefore, s= 25m/5s to give an answer of 5 m/s

weather is everyday things

weather could be a hurricane

weather could be a tornado

climate is more long term over time

example the climate in Antarctica is cold because it happens over long periods overtime

Initial speed of the coin (u)= 0 (As the coin is released from rest)

Acceleration due to gravity (a) = g = 9.81 m/s²

Time of fall (t) = 1.5 s

From equation of motion we have:

[tex] \boxed{ \bf{v = u + at}}[/tex]

By substituting values in the equation, we get:

[tex] \longrightarrow [/tex] v = 0 + 9.81 × 1.5

[tex] \longrightarrow [/tex] v = 14.715 m/s

[tex] \therefore [/tex] Speed of the coin as it hits the ground/Final speed of the coin = 14.715 m/s

The speed of the coin as it hits the ground is 14.715 m/s.

We can solve the problem above using the equation of acceleration under gravity.

⇒ Equation:

v = u+gt................... Equation 1

⇒ Where:

From the question,

⇒ Given:

Substitute these values into equation 1

Note the speed has a negative sign because it acts in the same direction as the acceleration due to gravity

Hence, the speed of the coin as it hits the ground is 14.715 m/s.

Learn more about gravitational motion here: https://brainly.com/question/17785701

Answer: a piece of iron near a magnet

Explanation:

Answer:

PE = mgh

Explanation:

m is mass, g is gravitational constant (9.81) and h is height

Answer:

Explanation:

Well, lets say you park your car on the top of a hill, gravitational energy prevents it from the car falling back. Or a snow pack, aka before a potential avalanche. Though gravity cannot keep it safe forever, gravitational energy keeps it from crashing asap. In this case, it gives you time to escape. Altogether, gravitational force keeps the earth in it's atmosphere.

Answer:

Hope this helps.

Explanation:

Let's start b writing down coordinates of all points:

A(0,0,0)

B(0,5,0)

C(3,5,0)

D(3,0,0)

E(3,0,4)

F(0,0,4)

G(0,5,4)

H(3,5,4)

a.) When we reflect over xz plane x and z coordinates stay same, y coordinate  changes to same numerical value but opposite sign. Moving front-back is moving over x-axis, moving left-right is moving over y-axis, moving up-down is moving over z-axis.

A(0,0,0)

Reflecting

A(0,0,0)

B(0,5,0)

Reflecting

B(0,-5,0)

C(3,5,0)

Reflecting

C(3,-5,0)

D(3,0,0)

Reflecting

D(3,0,0)

b.)

A(0,0,0)

Moving

A(-2,-3,1)

B(0,-5,0)

Moving

B(-2,-8,1)

C(3,-5,0)

Moving

C(1,-8,1)

D(3,0,0)

Moving

D(1,-3,1)

hello

Explanation:

I haven't read the poem because you didn't attach it but here is my go at answering the question- although we find it hard to imagine being lonely while with others... if you lack emotional or intellectual connection even being physically near someone you are not mentally there

Answer:

medium

Examples:

A medium is a thing that the sound wave would travel through, like sound waves traveling through air. A mechanical wave cannot travel without a medium, like if the wave were trying to travel through a vacuum.

Answer:

Explanation:

Step one:

given data

initial velocity u= 40m/s

time taken t=3seconds

final velocity v=?

Step two:

applying the first equation of motion

v=u-gt---  (the -ve sign implies that the arrow is against gravity)

assume g=9.81m/s^2

v=40-9.81*3

v=40-29.43

v=10.57m/s

Step three:

how high the target is located

applying

s=ut-1/2gt^2

s=40*3-1/2(9.81)*3^2

s=120-88.29/2

s=120-44.145

s=75.86m

Explanation:

Both galaxies show bicones of high ionisation gas extending along their minor axes. In NGC 4676A the high gas velocity .

please. follow. me

I think there's a typo in the question...

Vertically, the box is in equilibrium, so its weight and the normal force (magnitudes w and n, respectively) are such that

n + (-w) = 0

The box has mass 70 kg, and assuming gravitational acceleration with magnitude g = 9.80 m/s², it has a weight of

w = (70 kg) g = 686 N

and hence

n = 686 N

Horizontally, the box is accelerated 3.0 m/s², so the net force acting on it is

∑ F = (70 kg) (3.0 m/s²) = 210 N

and the only forces acting in this dimension are the pulling force with magnitude 130 N and the friction force with magnitude f so that

130 N - f = 210 N

The friction force is proportional to the normal force by a factor of µ, the coefficient of kinetic friction, so that

f = µ n

and so we have

130 N - µ (686 N) = 210 N   →   µ ≈ -0.117

but µ can't be negative!

The problem is that the pulling force should have a magnitude larger than that of the net force, so either the given mass, acceleration, or pulling force are incorrect.

Answer:

q₂ = 3.81 x 10⁻⁸ C = 38.1 nC

q₁ = 7.63 x 10⁻⁸ C = 76.3 nC

Explanation:

The force between two charges is given by Coulomb's:

F = kq₁q₂/r²

where,

F = Force = 0.00081 N

k = Coulomb's Constant = 9 x 10⁹ Nm²/C²

q₁ = magnitude of 1st charge

q₂ = magnitude of second charge

r = distance between charges = 18 cm = 0.18 m

Therefore,

0.00081 N = (9 x 10⁹ Nm²/C²)q₁q₂/(0.18 m)²

q₁q₂ = (0.00081 N)(0.18 m)²/(9 x 10⁹ Nm²/C²)

q₁q₂ = 2.916 x 10⁻¹⁵ C²

q₁ = 2.916 x 10⁻¹⁵ C²/q₂   --------------- equation (1)

It is given that:

q₁ = 2q₂   --------------- equation (2)

Comparing equation (1) and equation (2):

2q₂ = 2.916 x 10⁻¹⁵ C²/q₂

q₂² = 2.916 x 10⁻¹⁵ C²/2

q₂ = √14.58 x 10⁻¹⁶ C²

q₂ = 3.81 x 10⁻⁸ C = 38.1 nC

using this value in equation (2):

q₁= 2(3.81 x 10⁻⁸ C)

q₁ = 7.63 x 10⁻⁸ C = 76.3 nC

Answer:

a blaring trumpet is sound energy

Explanation:

Answer:

Negatively charged, to positively charged parts

Explanation:

Electrons are negative, negative is attracted to positive.

Answer:

distance and time

Explanation: the farther you go and how much time it will take you