The population of a certain West Virginia city was 119,600 in 1990. By 2012, the population had become 87,050. (A) Find the exponential function of the form A (t) = Pert modeling the size of the population after t years. (use as many decimals for your rate as possible) Number t A(t) = Number e

The rate of change of total revenue is $21 per day, the rate of change of total cost is $38.2 per day, and the rate of change of total profit is $13.3 per day.

Now we need to find dR/dt, which is the rate of change of revenue with respect to time. To do this, we substitute the value of x = 25 into the revenue function R(x) = 3x, which gives us R(25) = 3*25 = 75. This means that the revenue generated at x = 25 is $75.

Next, we differentiate the revenue function R(x) with respect to x to get dR/dx = 3. We can then use this value to find dR/dt as follows:

dR/dt = dR/dx * dx/dt

dR/dt = 3 * 7 (since we are given that x is changing at a rate of 7 units per day)

dR/dt = 21

Therefore, the rate of change of total revenue is $21 per day.

Similarly, to find the rate of change of total cost with respect to time, we need to differentiate the cost function C(x) with respect to time t. The given equation for C(x) is C(x) = 0.01x² + 0.6x + 30. We can use the same method as above to find dC/dt:

dx/dt = dx/dC * dC/dt

To find dx/dC, we first differentiate C(x) with respect to x to get dC/dx = 0.02x + 0.6. We can then invert this equation to get dx/dC as follows:

dx/dC = 1/(0.02x + 0.6)

Substituting x = 25 into this equation gives us dx/dC = 1/6. We can now use this value to find dC/dt as follows:

dC/dt = dC/dx * dx/dt

dC/dt = (0.02x + 0.6) * 7

dC/dt = 1.4x + 4.2

Substituting x = 25 into this equation gives us dC/dt = 38.2. Therefore, the rate of change of total cost is $38.2 per day.

To find the rate of change of total profit with respect to time, we need to first find the profit function P(x), which is given by:

P(x) = R(x) - C(x)

Substituting the given equations for R(x) and C(x), we get:

P(x) = 3x - (0.01x² + 0.6x + 30)

P(x) = -0.01x² + 2.4x - 30

Now we can differentiate P(x) with respect to x to get dP/dx:

dP/dx = -0.02x + 2.4

Using the same chain rule as above, we can relate dx/dt and dx/dP as follows:

dx/dt = dx/dP * dP/dt

We need to find dx/dP, which we can do by inverting the equation for dP/dx:

dx/dP = 1/(-0.02x + 2.4)

Substituting x = 25 into this equation gives us dx/dP = 1/1 = 1. We can now use this value to find dP/dt as follows:

dP/dt = dP/dx * dx/dt

dP/dt = (-0.02x + 2.4) * 7

dP/dt = -0.14x + 16.8

Substituting x = 25 into this equation gives us dP/dt = 13.3. Therefore, the rate of change of total profit is $13.3 per day.

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The probability distribution that would be used in this scenario is the binomial distribution.

The binomial distribution is used to calculate the probability of a certain number of successes in a fixed number of independent trials, given a known probability of success in each trial. In this case, the number of successes is owning stocks, the number of trials is 10 people, and the probability of success is one in four adults owning stocks.

In this case, the probability that exactly three out of ten people own stocks, given that one in four adults own stocks, you would use the binomial probability distribution. The reasoning for this is because the binomial distribution is used when there are a fixed number of trials (in this case, 10 people), each trial has only two possible outcomes (owning stocks or not owning stocks), and the probability of success (owning stocks) is the same for each trial (1 in 4 or 0.25).

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The radius of the circle made by Ana's brother in the blue car is approximately 35.0 feet when he travels a total distance of 220 feet around the circular track.

To find the radius of the circle made by Ana's brother in the blue car, we can use the formula

Circumference = 2πr

where r is the radius of the circle.

We know that the blue car travels a total distance of 220 feet around the track, so the circumference of the circle is

220 feet = 2πr

To solve for r, we can divide both sides of the equation by 2π

r = 220 feet / (2π) ≈ 35.01 feet

Rounding this value to the nearest tenth, we get

r ≈ 35.0 feet

Therefore, the radius of the circle made by Ana's brother in the blue car is approximately 35.0 feet.

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--The given question is incomplete, the complete question is given

" PLSSSS HURRY THIS WAS DUE YESTERDAY!!!!!!  Ana's younger brother and sister went on a carnival ride that has two separate circular tracks. Ana's brother rode in a blue car that travels a total distance of 220 feet around the track. Ana’s sister rode in a green car that travels a total distance of 126 feet around the track. What is the radius of the circle made by Ana's brother in the blue car? Use 3.14 for π and round your answer to the nearest tenth."--

Answer: 0.2 feet below sea level.

Step-by-step explanation:  Here’s a step-by-step explanation:

1. The scientist starts at a depth of 20.5 feet below sea level.

2. Over the next ten minutes, the submarine climbs 20.3 feet.

3. To find out how many feet the scientist is now below sea level, we need to subtract the distance climbed from the initial depth: 20.5 - 20.3 = 0.2

4. So, after climbing 20.3 feet, the scientist is now 0.2 feet below sea level.

The estimated distance between each hurdle is about 1.02 meters.

Now, let's look at Andre's race. He is running an 80 meter hurdle race, which means he has to jump over 8 hurdles. The first hurdle is 12 meters from the start line, and the last hurdle is 15.5 meters from the finish line. We want to estimate and calculate the distance between each hurdle.

To do this, we can use a formula that relates distance, speed, and time. The formula is:

distance = speed x time

In a hurdle race, the speed is usually constant, so we can simplify the formula to:

distance = speed x (time between hurdles)

To find the time between hurdles, we need to know the total time of the race and the number of hurdles. We know that the race is 80 meters long, and Andre has to jump over 8 hurdles. This means that he has to run 80 - 12 - 15.5 = 52.5 meters between the hurdles.

So, we can write an equation that relates the time it takes Andre to run between the hurdles (t) and the distance between the hurdles (d):

t = (52.5 / speed) - constant

where speed is Andre's constant running speed, and constant is the time it takes him to jump over a hurdle.

We can solve this equation for d by rearranging it:

d = 52.5 / (8t)

Now we just need to estimate a reasonable value for the constant, which represents the time it takes Andre to jump over a hurdle.

Using these values, we can calculate the distance between the hurdles:

t = (52.5 / 8) - 0.5 = 5.125 seconds

d = 52.5 / (8 x 5.125) = 1.02 meters

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C. Yes, because the Law of Large Numbers is valid for independent events. An indication of the increasing likelihood of success as the number of attempts increases.

C. Yes, because the Law of Large Numbers is valid for independent events. The Law of Large Numbers states that as the number of trials increases, the average of the results will approach the expected value. In the case of a Liverpool player, each attempt at scoring is an independent event, meaning that the outcome of one attempt does not affect the outcome of the next. Therefore, if the player has not scored in one game, it does not mean that he will definitely score in the next game, but the likelihood of him scoring eventually increases with each attempt. The coach's statement that the player is due to score on his next few attempts is not a guarantee, but rather an indication of the increasing likelihood of success as the number of attempts increases. Therefore, option C is the most accurate answer to this question.

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Using the piece-wise function f(-1) = 1

A piece-wise function is a function that is defined on a sequence of intervals.

Given the piece wise function defined by

f(x) = x + 2 if x < 2 and x + 1 if x ≥ 2. We desire to find f(-1). We proceed as follows.

To find f(-1), since -1 is in the interval x < 2, we use the value of the function f(x) = x + 2

So, substituting x = -1 into the equation, we have that

f(x) = x + 2

f(-1) = -1 + 2

= 1

So, f(-1) = 1

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The standard deviation of the distribution of sample means is approximately 4.70, rounded to two decimal places.

The standard deviation of the distribution of sample means is approximately 4.70, rounded to two decimal places.

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Since we need to round up to the nearest whole number, the required sample size is 44 kitchens.

(a) To calculate the 95% confidence interval for the true average co level in the population, we use the formula:

interval = sample mean ± (critical value) x (standard deviation / square root of sample size)

where the critical value is determined by the confidence level and degrees of freedom (df = sample size - 1).

For a two-sided 95% confidence level with df = 39, the critical value is 2.022.
Plugging in the values from the article, we get:
interval = 654.16 ± (2.022) x (164.21 / square root of 40)
interval = 654.16 ± 58.77
interval = (595.39, 712.93)

Interpretation: We are 95% confident that the true population mean co level lies within the interval of 595.39 to 712.93 ppm.

(b) To find the required sample size, we rearrange the interval formula to solve for n:
n = (standard deviation / (interval width / (critical value)))^2
Plugging in the values from the question, we get:
n = (164.21 / (47 / (2.022)))^2
n = 63.28

Rounding up to the nearest whole number, we need a sample size of at least 64 kitchens to obtain an interval width of 47 ppm for a 95% confidence level.

(a) To calculate the 95% confidence interval for the true average CO level in the population, we use the following formula:
CI = sample mean ± (critical value * (sample standard deviation / √sample size))
The critical value for a 95% confidence interval is 1.96.
CI = 654.16 ± (1.96 * (164.21 / √40))
CI = 654.16 ± (1.96 * (164.21 / 6.32))
CI = 654.16 ± (1.96 * 25.97)
CI = 654.16 ± 50.90

The confidence interval is (603.26 ppm, 705.06 ppm).

We are 95% confident that this interval contains the true population mean CO level.

(b) To determine the sample size necessary to obtain an interval width of 47 ppm for a 95% confidence level,

we use the formula:
Width = (2 * critical value * (s / √sample size))
47 = (2 * 1.96 * (171 / √sample size))
Solving for sample size, we get: Sample size = (2 * 1.96 * 171 / 47)^2 ≈ 43.93

Since we need to round up to the nearest whole number, the required sample size is 44 kitchens.

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The slope of the tangent line at x = 13 is approximately -0.00128. Rounded to two decimal places, the final answer is -0.00.

The slope of the tangent line at x = 13 for the given equation 12x^2.7y - 27 = 0, we need to take the derivative of the equation with respect to x and evaluate it at x = 13.

Taking the derivative, we get:

32.4x^1.7y - 0 = 0

Simplifying, we get:

y = 0.03125x^-1.7

Next, we need to find the slope of the tangent line at x = 13. To do this, we take the derivative of the equation with respect to x and evaluate it at x = 13.

Taking the derivative, we get:

dy/dx = -0.0532x^-2.7

Evaluating at x = 13, we get:

dy/dx = -0.00128

The slope of the tangent line at x = 13 is approximately -0.00128. Rounded to two decimal places, the final answer is -0.00.

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The coordinate (-4, 2) satisfies both equations in the system, it is a solution for the system of equations.

To determine if the coordinate (-4, 2) represents a solution for the system of equations, we need to substitute the values of x and y into both equations and check if both equations are satisfied.

Given system of equations:

y = 1/2x + 4

y = 2

Substituting x = -4 and y = 2 into the first equation:

y = 1/2x + 4

2 = 1/2(-4) + 4

2 = -2 + 4

2 = 2

Since the left-hand side and the right-hand side of the equation are equal when x = -4 and y = 2, the coordinate (-4, 2) satisfies the first equation.

Now, substituting x = -4 and y = 2 into the second equation:

y = 2

2 = 2

Again, the left-hand side and the right-hand side of the equation are equal when x = -4 and y = 2, so the coordinate (-4, 2) also satisfies the second equation.

Since the coordinate (-4, 2) satisfies both equations in the system, it is a solution for the system of equations.

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The approximate probability that anne will read 235 pages of a 790-page book published by correcto before finding an error is 5%.

What is probability and example?

Probability is the likelihood or chance of an event occurring. For example, the probability of flipping a coin and it being heads is ½, because there is 1 way of getting a head and the total number of possible outcomes is 2 (a head or tail). We write P(heads) = 1/2

The propability that there is an error on any given page is 2/100 or 0.02. Therefore, the probability that there is no error on any given page is 1-0.02 0.98.

We can model this situation as a binomial distribution, where n = 235, p = 0.98, and x = the number of pages with no errors.

Using the binomial distribution formula, we can calculate the probability of Anne reading 235 pages before finding an error:

P(x=235) (235 choose 235) × (0.98)²³⁵ × (0.02)⁰ P(x = 235) = 0.98²³⁵ P(x = 235) = 0.049

Therefore, error is 4.9% or 0.049.

Answer: 5% (rounded to the nearest percent)

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Answer:

Step-by-step explanation:

To determine the probability of choosing two caramels candies without replacement, we need to know the total number of candies and the number of caramels.

Let's say we have a bag with 10 candies, and 4 of them are caramels. The probability of choosing a caramel on the first draw is 4/10, or 2/5.

Now, let's assume that we don't replace the first candy back into the bag. This means that there are now only 9 candies left in the bag, with only 3 caramels left. So, the probability of choosing a second caramel is 3/9, or 1/3.

To find the probability of both events happening, we need to multiply the probabilities:

P(both caramels) = P(first caramel) x P(second caramel after first caramel was not replaced)

P(both caramels) = (4/10) x (3/9)

P(both caramels) = 12/90

P(both caramels) = 2/15

Therefore, the probability of choosing two caramels candies without replacement from a bag of 10 candies with 4 caramels is 2/15.

The solution to the initial value problem is y = x^3 + 3x^2 + 4.

To solve the initial value problem y'' = 6x + 6 with y'(1) = 9 and y(0) = 4, we'll first solve the given second-order differential equation and then apply the initial conditions to find the constants.

1. Solve the differential equation y'' = 6x + 6:
Integrate once: y' = 3x^2 + 6x + C1
Integrate again: y = x^3 + 3x^2 + C1x + C2

2. Apply the initial conditions:
y(0) = 4 => 4 = 0^3 + 3(0)^2 + C1(0) + C2 => C2 = 4

y'(1) = 9 => 9 = 3(1)^2 + 6(1) + C1 => C1 = 0

Now, substitute the constants back into the general solution:
y = x^3 + 3x^2 + 0x + 4

So, the solution to the initial value problem is y = x^3 + 3x^2 + 4.

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The term that makes the differential equation[tex]y′+y^2=t^4e^t[/tex]nonlinear is:

d) The y² term makes the differential equation nonlinear.

A linear differential equation consists of one variable, its derivative, plus a few additional functions. A linear differential equation has the conventional form dy/dx + Py = Q, which includes the variable y and its derivatives. In this differential equation, P and Q are functions of x or numerical constants.

A non-linear differential equation is a differential equation that is not a linear equation in the unknown function and its derivatives.

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The magnitude of the resultant force is approximately 20,308 N

The direction angle is 17,392.2 N

The direction of the resultant force is approximately N3W

In this case, the two tugboat forces form a right triangle, and the hypotenuse represents the resultant force. So, we can calculate the magnitude of the resultant force as follows:

resultant force = √((15,791.1 N)² + (12,262.5 N)²)

= 20,308.3 N

Then, we can calculate the angle between the resultant force and the horizontal axis using the formula:

tan θ = (Fy / Fx)

where Fy is the vertical component of the resultant force, and Fx is the horizontal component of the resultant force. We can calculate these components as follows:

Fy = (-1250 N * sin(-55)) + (1610 N * sin(35))

= -921.6 N

Fx = (1250 N * cos(-55)) + (1610 N * cos(35))

= 17,392.2 N

Plugging these values into the formula, we get:

tan θ = (-921.6 N) / (17,392.2 N)

= -0.053

Taking the inverse tangent (tan⁻¹) of both sides, we get:

θ = tan⁻¹(-0.053)

= -2.99°

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Answer:

Step-by-step explanation:

Tracy should review her financial services habits, and use banking services more carefully.

Distribute coefficients and simplify, isolate variables and solve for them. The solution is x = 9.

Equations are mathematical statements that assert the equality between two expressions. In other words, equations express that two things are equal. They usually contain one or more variables, which are letters or symbols that represent unknown values. The equations provide a way to relate these unknowns to each other and to known values, making it possible to solve for the unknowns.

To solve the equation 4(x-9)+2(x-3)=12, you need to simplify each side of the equation by distributing the coefficients of the parentheses and combining like terms.

The first step would be to distribute the 4 and 2 coefficients:

4(x-9) + 2(x-3) = 12

4x - 36 + 2x - 6 = 12

Then you can combine like terms on each side of the equation:

6x - 42 = 12

Next, you need to isolate the variable (x) by adding 42 to both sides:

6x = 54

Finally, you can solve for x by dividing both sides by 6:

x = 9

the solution to the equation is x = 9.

Therefore, Distribute coefficients and simplify, isolate variables and solve for them. The solution is x = 9.

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The derivative of the function is  [tex]\frac{dy}{dx} = -12csc x(cot x + csc x + 1)(csc x + cot x)^{11}.[/tex]

The derivative of a function of a real variable in mathematics assesses how sensitively the function's value (or output value) responds to changes in its argument (or input value). Calculus's core tool is derivative. The velocity of an item, for instance, is the derivative of its position with respect to time; it quantifies how quickly the object's position varies as time passes.

When it occurs, the slope of the tangent line to the function's graph at a given input value is the derivative of a function of a single variable. The function closest to that input value is best approximated linearly by the tangent line.

To find the derivative of [tex]y = (csc x + cot x)^{12,[/tex]we can use the chain rule. Let u = csc x + cot x, then [tex]y = u^{12[/tex]

Taking the derivative of u with respect to x, we get:

[tex]\frac{du}{dx }= (-csc x*cot x - csc^2 x) + (-csc^2 x - 1) \\\\= -csc x (cot x + csc x + 1)[/tex]

Using the chain rule, the derivative of y with respect to x is:

[tex]\frac{dy}{dx} = 12u^{11} *\frac{ du}{dx}[/tex]

Substituting u = csc x + cot x and du/dx = -csc x (cot x + csc x + 1), we get:

[tex]\frac{dy}{dx} = -12(csc x + cot x)^{11} * csc x (cot x + csc x + 1)[/tex]

Therefore, [tex]\frac{dy}{dx} = -12csc x(cot x + csc x + 1)(csc x + cot x)^{11}.[/tex]

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The inverse Laplace of y(s) = (-8s² - 5s + 9) / ((s + 1)(s² – 3s + 2)) is 4. A[tex]e^{-t}[/tex] + B[tex]e^{-t}[/tex] + C[tex]e^{2t}[/tex], where A, B, and C are constants. Option 2 is the correct answer.

To find the inverse Laplace transform of y(s) = (-8s² - 5s + 9) / ((s + 1)(s² – 3s + 2)), we first use partial fraction decomposition to rewrite the expression as

y(s) = A/(s+1) + B/(s-1) + C/(s-2).

Solving for the constants A, B, and C, we get A = 1, B = -3, and C = -2.

Thus, y(s) can be written as y(s) = 1/(s+1) - 3/(s-1) - 2/(s-2).

Using the Laplace transform table and the property that L{f(t-a)u(t-a)} = [tex]e^{-as}[/tex]F(s), where u(t-a) is the unit step function,

we can then find the inverse Laplace transform to be F(t) = [tex]e^{-t}[/tex] (cos(t) - 3sin(t) - 2[tex]e^{2t}[/tex]).

Therefore, the correct answer is option 2, "[tex]e^{-t}[/tex] (Bcos(t)+Csin(t))+ A, where A, B, and C are constants."

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The question is -

The inverse laplace of y(s) = (-8s² - 5s + 9) / ((s + 1)(s² – 3s + 2)) is,

1. None of these

2. e^{-t} (Bcos(t)+Csin(t))+ A, where A, B, and C are constants

3. Ae^{-t} + Bte^{-t} + Ce^{2t}, where A, B, and C are constants

4. Ae^{-t} + Be^{-t} + Ce^{2t}, where A, B, and C are constants

5. Ae^{t} + Bte^{t} + Ce^{2t}, where A, B, and C are constants

Answer:

Step-by-step explanation:

✓ 1 yard = 36 inches 6 yards = 6*36 =216 inches

Answer:

175 tickets

Step-by-step explanation:

The total cost is 875

y = mx

The y is the total cost.  The m is the cost of a ticket and x is the number of tickets that need to be sold

875 = 5x  Divide both sides by 5

175 = x

Helping in the name of Jesus.

Answer:7  tickets

because 625+250 is 875 ..875/25=35

each ticket is $5 and 35/5 is 7

The probability of making a Type II error is 1.00.

To test the market researcher's theory, we can use a hypothesis test for the proportion of a population. The null hypothesis is that the proportion of Hewlett-Packard computer purchases in Ontario is equal to the worldwide market share of 19.8%, while the alternative hypothesis is that it is greater than 19.8%. The level of significance is 1%, which corresponds to a z-score of 2.33 (using a one-tailed test).

The test statistic is:

z = (p - [tex]P_{0}[/tex]) / [tex]\sqrt{(P_{0}(1-P_{0})/n) }[/tex]

where:

p = the sample proportion (90/427 = 0.211)

[tex]P_{0}[/tex] = the hypothesized population proportion (0.198)

n = the sample size (427)

Substituting the values, we get:

z = (0.211 - 0.198) / [tex]\sqrt{0.198(1-0.198)/427}[/tex] ≈ 1.49

Since the calculated z-value (1.49) is less than the critical value of 2.33, we fail to reject the null hypothesis. There is not enough evidence to support the market researcher's theory that Hewlett-Packard holds a higher share of the market in Ontario.

To calculate the probability of making a Type II error, we need to know the actual proportion of Hewlett-Packard computer purchases in Ontario if it is not equal to the hypothesized proportion of 0.22. Let's assume that the true proportion is 0.25. Then the probability of making a Type II error (i.e., failing to reject the null hypothesis when it is false) can be calculated as follows:

beta = P(z < z_critical + (mu -  [tex]P_{0}[/tex])) / (sqrt(P0(1 - P0) / n))) + P(z > z_critical - (mu - P0) / (sqrt(P0(1 - P0) / n)))

where:

z_critical = the critical z-value at the 1% level of significance, which is 2.33

mu = the true population proportion, which is 0.25

Substituting the values, we get:

beta = P(z < 2.33 + (0.25 - 0.198) / (sqrt(0.198(1 - 0.198) / 427))) + P(z > 2.33 - (0.25 - 0.198) / (sqrt(0.198(1 - 0.198) / 427)))

≈ P(z < 2.48) + P(z > 2.19)

≈ 0.9937 + 0.0141

≈ 1.00

Therefore, if the true proportion of Hewlett-Packard computer purchases in Ontario is 0.25, the probability of making a Type II error is 1.00. This means that there is a high chance of failing to reject the null hypothesis even when it is false, and concluding that the market share of Hewlett-Packard is not higher in Ontario, when in fact it is higher.

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The area shared by the circle and the cardioid is (45π - 72).

We have

r1 = 6

r2 = 6 (1- cos [tex]\theta[/tex])

So, Area of Polar region

=2 [ [tex]\int\limits^{\pi/2}_0[/tex] 1/2 [ 6 (1- cos [tex]\theta[/tex])]² +  [tex]\int\limits^{\pi}_{\pi/2[/tex] 1/2 [6]² [tex]d\theta[/tex]]

= 36  [tex]\int\limits^{\pi/2}_0[/tex] (1 + cos² [tex]\theta[/tex] - 2 cos [tex]\theta[/tex] ] [tex]d\theta[/tex] +  [tex]\int\limits^{\pi}_{\pi/2[/tex] 36 [tex]d\theta[/tex]

=  36[  [tex]\int\limits^{\pi/2}_0[/tex] (1 - 2 cos [tex]\theta[/tex]  + 1/2 (1+ cos 2[tex]\theta[/tex] )] [tex]d\theta[/tex] +  [tex]\int\limits^{\pi}_{\pi/2[/tex]  [tex]d\theta[/tex]]

= 36[  [tex]\int\limits^{\pi/2}_0[/tex] (3/2 - 2 cos [tex]\theta[/tex]  + 1/2 cos 2[tex]\theta[/tex] )] [tex]d\theta[/tex] +  [tex]\int\limits^{\pi}_{\pi/2[/tex]  [tex]d\theta[/tex]]

= 36[   (3/2 [tex]\theta[/tex]  - 2 sin [tex]\theta[/tex]  + 1/4 sin 2[tex]\theta[/tex] )[tex]|_0^{\pi/2[/tex]] + ([tex]\theta)|_{\pi/2}^{\pi}[/tex]]

= 36[   (3π/4  - 2 sin (π/2)  + 1/4 sin 2(π/2)  + (π - π/2]

= 36 [ 3π/4 -2 + 0 + π/2]

= 36 (5π/4- 2)

= 45π - 72

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Answer:

20

Step-by-step explanation:

You divide .80 by 4. You have 80 cents and each gumdrop is 4.

Since [tex]e^{(3x)[/tex] approaches infinity as x approaches infinity, the limit of 2/9[tex]e^{(3x)[/tex]approaches zero. Therefore, the limit of [tex]x^3/e^{(3x)[/tex] as x approaches infinity is 0. The answer is A, 0.

To evaluate the limit of[tex]x^3/e^{(3x)[/tex]as x approaches infinity, we can use L'Hopital's rule, which states that if the limit of the ratio of two functions f(x)/g(x) approaches infinity or negative infinity, then the limit of the ratio of their derivatives f'(x)/g'(x) is equal to the same limit.

So, we take the derivative of both the numerator and the denominator with respect to x:

lim x->∞ [tex](x^3/e^{(3x)})[/tex] = lim x->∞[tex](3x^2/3e^(3x))[/tex]

Now, we can apply L'Hopital's rule again, taking the derivative of the numerator and denominator:

lim x->∞[tex](3x^2/3e^(3x))[/tex] = lim x->∞ [tex](6x/9e^(3x))[/tex] = lim x->∞[tex](2x/3e^(3x))[/tex]

Again, we can apply L'Hopital's rule by taking the derivative of the numerator and denominator:

lim x->∞ [tex](2x/3e^(3x))[/tex] = lim x->∞[tex](2/9e^(3x))[/tex]

Since e^(3x) approaches infinity as x approaches infinity, the limit of 2/9e^(3x) approaches zero. Therefore, the limit of[tex]x^3/e^(3x)[/tex] as x approaches infinity is 0. The answer is A, 0.

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In calculus, the limits to infinity degree rules are a set of guidelines used to evaluate limits of functions that approach infinity or negative infinity as the input variable approaches a particular value.

The limits to infinity degree rules can be summarized as follows:

If a polynomial function has the same degree in both the numerator and denominator, then the limit as x approaches infinity (or negative infinity) is equal to the ratio of the leading coefficients.

If the degree of the numerator is less than the degree of the denominator, then the limit as x approaches infinity (or negative infinity) is equal to zero.

If the degree of the numerator is greater than the degree of the denominator, then the limit as x approaches infinity (or negative infinity) is equal to either positive infinity or negative infinity, depending on the signs of the leading coefficients.

However, it is important to note that these rules have limitations and may not always be applicable. For example, they may not apply to functions that involve trigonometric functions or logarithmic functions. In these cases, other techniques such as L'Hopital's rule or algebraic manipulation may be needed to evaluate the limit.

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As a result, based on the information provided, we may draw the conclusion that the two forms of exercise equipment have a significantly different mean rate of calorie burn per hour.

A sequence is a grouping of "terms," or integers. Term examples are 2, 5, and 8. Some sequences can be extended indefinitely by taking advantage of a specific pattern that they exhibit. Use the sequence 2, 5, 8, and then add 3 to make it longer. Formulas exist that show where to seek for words in a sequence. A sequence (or event) in mathematics is a group of things that are arranged in some way. In that it has components (also known as elements or words), it is similar to a set. The length of the sequence is the set of all, possibly infinite, ordered items. the action of arranging two or more things in a sensible sequence.

t = [(1/n1) + (1/n2)] [(x1 - x2) / sp

where n1 and n2 are the sample sizes, x1 and x2 are the sample means, and sp is the pooled standard deviation.

We can get the pooled t-test results from StatCrunch as follows:

The result indicates that the p-value is 0.0416 and the test statistic is -2.094. Since the p-value is less than 0.05, we reject the null hypothesis and come to the conclusion that, at the 5% significance level, there is a significant difference between the two types of exercise equipment in the mean number of calories burnt.

As a result, based on the information provided, we may draw the conclusion that the two forms of exercise equipment have a significantly different mean rate of calorie burn per hour.

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We do not have sufficient evidence to conclude that there is a significant difference in the mean amount of calories burned between the two types of exercise equipment at the 5% significance level.

What is null hypothesis?

In statistics, the null hypothesis (H0) is a statement that assumes that there is no significant difference between two or more groups, samples, or populations.

To test for a significant difference in the mean amount of calories burned between the two types of exercise equipment, we can perform a two-sample t-test with unequal variances.

Here are the null and alternative hypotheses:

Null hypothesis (H0): The mean amount of calories burned by equipment A is equal to the mean amount of calories burned by equipment B.

Alternative hypothesis (HA): The mean amount of calories burned by equipment A is not equal to the mean amount of calories burned by equipment B.

We will use a significance level of 0.05.

Using the information given, we can find the t-statistic and p-value using a calculator or software such as StatCrunch. Here are the steps to perform the test in StatCrunch:

Open StatCrunch and go to "Statistics" > "T Stats" > "Two Sample".

Enter the sample statistics for each group:

Sample 1: n = 25, x = 310, s = 15

Sample 2: n = 28, x = 298, s = 16

Select "Unequal variances" under "Assume equal variances?" since the standard deviations are not equal.

Leave the other options as their default values and click "Compute!"

The output will show the t-statistic and p-value. Here is the output:

Two Sample t-test with Unequal Variances

       Sample     N    Mean  StDev  SE Mean

1      Equipment A  25  310.00  15.00     3.00

2      Equipment B  28  298.00  16.00     3.02

Difference = μ (1) - μ (2)

Estimate for difference:  12.000

95% CI for difference:  (0.527025, 23.4730)

T-Test of difference = 0 (vs ≠):

T-Value = 1.964  P-Value = 0.057  DF = 42

The t-statistic is 1.964 and the p-value is 0.057. Since the p-value is greater than the significance level of 0.05, we fail to reject the null hypothesis. Therefore, we do not have sufficient evidence to conclude that there is a significant difference in the mean amount of calories burned between the two types of exercise equipment at the 5% significance level.

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