The physics of wind instruments is based on the concept of standing waves. When the player blows into the mouthpiece, the column of air inside the instrument vibrates, and standing waves are produced. Although the acoustics of wind instruments is complicated, a simple description in terms of open and closed tubes can help in understanding the physical phenomena related to these instruments. For example, a flute can be described as an open-open pipe because a flutist covers the mouthpiece of the flute only partially. Meanwhile, a clarinet can be described as an open-closed pipe because the mouthpiece of the clarinet is almost completely closed by the reed.
Consider a pipe of length 80.0 cm open at both ends. What is the lowest frequency f of the sound wave produced when you blow into the pipe?

Answers

Answer 1

Answer:

Explanation:

Lowest frequency will be the fundamental frequency . For fundamental note

λ /2 = L where λ is wavelength of sound produced and L is length of open end pipe .

Given L = 80 cm

λ /2 = 80

λ = 160 cm .

= 1.6 m

frequency of note = velocity of sound / wavelength

= 330 / 1.6

= 206.25 Hz .

206 Hz approx.


Related Questions

1: Give one word answer.

The bouncing back of the light rays after hitting a smooth surface _____

Answers

Answer:

RThe answer is Reflection....

At what tempreture will the of and oC
be the same​

Answers

Answer:

-40 degrees

To find the temperature when both are equal, we use an old algebra trick and just set �F = �C and solve one of the equations. So the temperature when both the Celsius and Fahrenheit scales are the same is -40 degrees.

Explanation:

Hope it is helpful.....

Answer:

To find the temperature when both are equal, we use an old algebra trick and just set �F = �C and solve one of the equations. So the temperature when both the Celsius and Fahrenheit scales are the same is -40 degrees.

difine precision and accuracy​

Answers

-precision refers to the closeness of two or more measurements to each other.

-Accuracy refers to the closeness of a measured value to a standard or known value.
the accuracy (as in binary or decimal places) with which a number can be represented usually expressed in terms of the number of computer words available for representation.

degree of conformity of a measure to a standard or a true value

The force between two charges when they are 2 cm apart is
0.036 N. If the sum of two charges is 10uC, what are the
charges? (1/4ttɛo=9x109 Nm-C-2).​

Answers

Answer:

[tex]q_1=9.9998\mu C[/tex] and [tex]q_2=0.0002\mu C[/tex]

Or

[tex]q_1=0.00016\mu C[/tex] and [tex]q_2=9.99984\mu C[/tex]

Explanation:

We are given that

Force between two charges=0.036 N=[tex]36\times 10^{-3}N[/tex]

Distance between two charges, r=2cm=[tex]2\times 10^{-2}[/tex]m

1m=100cm

Sum of two charges=[tex]10\mu C[/tex]

Let one charge=[tex]q_1=q\mu C=q\times 10^{-6}C[/tex]

[tex]q_2=(10-q)\times 10^{-6} C[/tex]

We know that

Electric force between two charges

[tex]F=\frac{kq_1q_2}{r^2}[/tex]

Where [tex]k=\frac{1}{4\pi \epsilon_0}=9\times 10^{9}[/tex]

Using the formula

[tex]36\times 10^{-3}=9\times 10^{9}\times \frac{q\times 10^{-6}\times(10-q)\times 10^{-6}}{(2\times 10^{-2})^2}[/tex]

[tex]\frac{144\times 10^{-7}}{9\times 10^{9}\times 10^{-12}}=q(10-q)[/tex]

[tex]0.0016=10q-q^2[/tex]

[tex]q^2-10q+0.0016=0[/tex]

[tex]10000q^2-100000q+16=0[/tex]

[tex]q=\frac{100000\pm\sqrt{(100000)^2-4\times 10000\times 16}}{2\times 10000}[/tex]

Using the formula

[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

[tex]q=9.999[/tex] and [tex]q=0.00016[/tex]

[tex]q_2=10-9.9998=0.0002[/tex]

[tex]q_2=10-0.00016=9.99984[/tex]

Hence, two charges are

[tex]q_1=9.9998\mu C[/tex] and [tex]q_2=0.0002\mu C[/tex]

Or

[tex]q_1=0.00016\mu C[/tex] and [tex]q_2=9.99984\mu C[/tex]

Problem 4.13: Sound waves travel through air at a speed of 330 m/s. A whistle blast at a frequency of about 1.0 kHz lasts for 2.0 s. (a) Over what distance in space does the "wave train" representing the sound extend? (b) What is the wavelength of the sound? (c) Estimate the precision with which an observer could measure the wavelength. (d) Estimate the precision with which an observer could measure the frequency.

Answers

Answer:

a)  x = 660 m, b)  λ = 0.330 m, c) Δλ = 0.1 cm, d)    Δf = 104

Explanation:

a) the distance in which the train of waves extends can be obtained from the uniform movement

             v = x / t

             x = v t

             x = 330 2

             x = 660 m

b) the speed of sound is related to the wavelength and frequency

             v = λ f

              λ = v / f

              λ = 330/1000

              λ = 0.330 m

c) The precision in the measurement of the wavelength refers to the error or uncertainty in the measurement, if the measurement is direct with a tape measure the precision is the appreciation of the tape measure, in general it is 0.1 cm

d) the accuracy of the frequency in general the frequency is calculated from the measurements of period T

                f = 1 / T

The precision of the period is data by the chronometer used, in general time a press of 0.01s, by the response time of the people

               Δf = df / dT    ΔT

               Δf = 1 / T² ΔT

                Δf = 1 / (0.001)² 0.01

                 Δf = 104

As we can see, a much more precise system is needed to reduce the error

Which of the following is not an example of energy transfer?
A. Riding a bike down a hill.
B. Sliding a table across a floor.
C. Holding a sign in the air.

Answers

Answer:

c.holding a sign in the air

Explanation:

because b is kinetic energy and a is also kinetic energy

C holding a sign in the air

A proud new Jaguar owner drives her car at a speed of 35 m/s into a corner. The coefficients of friction between the road and the tires are 0.70 (static) and 0.40 (kinetic). What is the minimum radius of curvature for the corner in order for the car not to skid

Answers

Answer:

178.6 m

Explanation:

Since the car moves in a circular path, it experiences a centripetal force, F = mv²/r where m = mass of car, v = speed of car = 35 m/s and r = radius of curvature of path.

Now, for the car not to skid, this centripetal force must be equal to the frictional force, F' acting in the opposite direction.

So, F' = μN where μ = coefficient of static friction(since the car does not move in this direction) and N = normal force = mg where m = mass of car and g = acceleration due to gravity = 9.8m/s²

F' = μmg

Since F = F'

mv²/r = μmg

dividing both sides by m, we have

v²/r = μg

multiplying both sides by r, we have

v² = μgr

dividing both sides by μg, we have

r = v²/μg

Here we use μ = coefficient of static friction(since the car does not move in this direction) = 0.70. Substituting the other variables into the equation, we have

r = v²/μg

r = (35 m/s)²/(0.70 × 9.8m/s²)  

r = 1225 m²/s²/6.86m/s²)  

r = 178.6 m

So, the minimum radius of curvature of the corner is 178.6 m

Help plz I’ll mark brainliest

Answers

Answer:

It's A

Explanation:

sound waves are longitudinal they need a medium to travel through

Which example describes a nonrenewable resource?

Answers

Answer: Examples of nonrenewable resources include crude oil, natural gas, coal, and uranium. These are all resources that are processed into products that can be used commercially. For example, the fossil fuel industry extracts crude oil from the ground and converts it to gasoline.

A 0.15 kg baseball is traveling at 40 meters per second (about 90 miles per hour) if the ball comes to a complete stop when it hits the catchers mitt, what is the change in velocity?

Answers

Answer:

Please find attached pdf

Explanation:

In an experiment similar to the one pictured below, an electron is projected horizontally at a speed vi into a uniform electric field pointing up. The magnitude of the total vertical deflection, ye, of the electron is measured to be 1 mm. The same experiment is repeated with a proton (whose mass is 1840 times that of the electron) that is also projected horizontally at a speed vi into the same uniform electric field. What is the magnitude of the total vertical deflection, yp, for the proton

Answers

I think you need Graph to figure it out

Using Newton's second law and kinematic projectile motion we can find the proton deflection y = 5.43 10⁻⁷ m, in the opposite direction to the electron deflection.

given parameters

The deflection of the electorn    y₁ = 1 mm = 0.001 m The initial velocity of the electron and proton v_i The mass of the proton m_p = 1840 me

to find

deflection of the proton

For this exercise we will use Newton's second law where the force is electric

            F = ma

            F = q E

where F is the force, q the charge, E the electric field, m the mass and the acceleration of the particle

           q E = m a

           a = q / m E

This acceleration is the direction of the electric field that is perpendicular to the initial velocity (v_i)

Having the acceleration we can use the kinematics relations

If we make the direction of the initial velocity coincide with the x-axis

             v_i = cte

             v_i = x / t

             t = x/ v_i

       

on the y-axis is in the direction of the electric field

            y = v_{iy}  t + ½ a t²

on this axis the initial velocity is zero

            y = [tex]\frac{1}{2} (\frac{q}{m} E) \ t^2[/tex]

subtitute

            y =            (1)

Electron motion.

Let us propose the expression for the electron situation, the length of the displacement must be the same for electron and proton, suppose that it is x = L

In this case the charge q = -e and the mass m = m_e

its substitute in  equation 1

            y₁ = [tex]\frac{1}{2} \ ( \frac{-e}{m_e} E) \ \frac{x^2}{v_i^2}[/tex]  

where y₁, is the lectron deflection.

Proton motion

Between the proton and the electron we have some relationships

          q_p = -e

          m_ = 1840 m_e

we substitute in the equation  1

         y₂ = ½ e / 1840 me E x² / vi²

         y₂ =

         y₂ = - y₁ / 1840

         y₂ = - 0.001 / 1840

         y₂ = - 5.43 10⁻⁷ m

The negative sign indicates that the deflection of the proton is in the opposite direction to the deflection of the electron.

In conclusion they use Newton's second law and kinematics we can find the proton deflection is y = 5.43 10⁻⁷ m

learn more about electric charge movement here:  https://brainly.com/question/19315467

Why are we seeing extremely old light from Canopus instead of light in real-time?

Answers

Answer:

Canopus is more than 300 light years away from earth. This means it takes the light we see more than 300 years to reach us.

A man pushes a block of ice across a frozen pond at a constant velocity. While the coefficients of static and kinetic friction for ice are low, they are not zero. Consider this problem to involve friction. If necessary, use Fs for the force of static friction, and Fk as the force of kinetic friction.

Required:
Draw the Free Body Diagram for the block of ice.

Answers

Answer:

   F₁> F₂

Explanation:

For this exercise Newton's second law is used, in the adjoint we can see the unapplied forces in this exercise.

Y axis y

        N- W = 0

in this axis there is no movement

X axis

          F -fr = m a

as they indicate that the velocity is consonant the acceleration is worth zero

          F - fr = 0

friction force has the expression

           fr = μ N

           fr = μ mg

we substitute

           F = μ m g

by the time the block is stopped the deferred force is

           F₁ = μ_s m g

when it begins to move the force should decrease to

           F₂ = μ_k k m g

as the static coefficient is greater than the dynamic coefficient

             F₁> F₂

The free body diagram consists of applied force (F) and kinetic frictional force acting in opposite direction.

Net force on the block

The net force on the block will result constant speed of the block which is zero acceleration.

[tex]\Sigma F= 0\\\\F - F_f = 0\\\\F - \mu_k F_n= 0\\\\F - \mu_k mg = 0\\\\F - \mu k W = 0\\\\F = F_f\ \ \ or \ \ F = \mu_k W[/tex]

Free body diagram

The free body diagram consists of applied force (F) and kinetic frictional force acting in opposite direction.

                        F →  Ф ← Ff

Learn more about free body diagram here: https://brainly.com/question/21691401

Which hand is negatively charged?

Answers

Answer:

Left

Explanation:

Answer:

Your Left hand is negatively charged, and receives energy. It emits the energy that "allows things to happen''.

Explanation:

did some research

What is the acceleration of an object going from O m/s to 25 m/s in 5s?

Answers

Answer:

5m/s^2 is the acceleration.

Answer:

[tex]\boxed {\boxed {\sf a= 5 \ m/s^2}}[/tex]

Explanation:

Acceleration is the change in speed over time.

[tex]a=\frac{ v_f-v_i}{t}[/tex]

The object accelerates from 0 meters per second to 25 meters per second in 5 seconds.

[tex]v_f= 25 \ m/s\\v_i= 0 \ m/s \\t= 5 \ s[/tex]

Substitute the values into the formula.

[tex]a=\frac{ 25 \ m/s -0 m/s }{ 5 \ s}[/tex]

Solve the numerator.

[tex]a=\frac{25 \ m/s}{5 \ s}[/tex]

Divide

[tex]a= 5 \ m/s/s= 5 \ m/s^2[/tex]

The object's acceleration is 5 meters per square second.

a 6.25-gram bullet traveling at 365 ms strikes and enters a 4.50-kg crate. The crate slides 0.15 m along a wood floor until it comes to rest. What is the change in kinetic energy of the system after the collision

Answers

Answer:

the change in kinetic energy of the system is 0.577 J

Explanation:

Given;

mass of the bullet, m₁ = 6.25 g = 0.00625 kg

initial velocity of the bullet, u₁ = 365 m/s

mass of the crate, m₂ = 4.5 kg

initial velocity of the crate, u₂ = 0

distance moved by the system after collision, d = 0.15 m

Determine the final velocity of the system after collision;

m₁u₁ + m₂u₂ = v (m₁ + m₂)

0.00625 x 365 + 4.5 x 0 = v(0.00625 + 4.5)

2.2813 + 0 = v(4.5063)

2.2813 =  v(4.5063)

v = 2.2813 / 4.5063

v = 0.506 m/s

The change in kinetic energy of the system after collision is calculated as;

ΔK.E = ¹/₂ (m₁ + m₂)v²

ΔK.E =  ¹/₂ (4.506) x 0.506²

ΔK.E = 0.577 J

Therefore, the change in kinetic energy of the system is 0.577 J

Atoms of which pair of elements will form covalent bonds in a compound? ASAP PLZ

A. Li and Al
B. C and O
C. Co and Fe
D. Na and F

Answers

Answer:B

Explanation:

C and O

Atoms of C and O pair of elements will form covalent bonds in a compound.Therefore the correct option is B.

What is a Chemical compound?

The chemical compound is a combination of two or more  either similar or dissimilar chemical elements

for example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom.

These chemical compounds are formed because of different types of bonds between the constituents elements ,the chemical bonds are mainly ionic bonds, covalent bonds,s, and hydrogen bonds.

Ionic bonds are formed due to the transfer of electrons between two bond forming pairs differentiated by their electronegativity.

Covalent bonds are formed by the sharing of electrons.Generally organic compound are formed as the reason of covalent bonds.

The carbon and oxygen atoms share their valence electrons to form a covalent bond, therefore the correct option is B.

Learn more about a chemical compound from here

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#SPJ5

1. A wheel with spokes of length r has four masses
attached at various points where the spokes intersect the
circumference of the wheel. The wheel and spokes are
massless and spokes are all 30° apart. Determine the net
torque on the wheel.
(A) Zero (B) 22 (C) 13/2
(D) 1

Answers

I can help here 20 q 45

When rubbing a balloon against your head, you notice the balloon pulling your hair away from your head. What best explains why the balloon and your hair are attracted to each other?

They become oppositely charged, which causes them to be attracted to each other.

They become similarly charged, which causes them to be attracted to each other.

They stick together because of the friction between the two objects.

They are made of different materials, which is why they attract each other.

Answers

Answer:

They become oppositely charged, which causes them to be attracted to each other.

Answer: number A

Explanation:

If a positive charge and a negative charge interact, their forces act in the same direction, from the positive to the negative charge. As a result opposite charges attract each other: The electric field and resulting forces produced by two electrical charges of opposite polarity. Have a nice day <3

The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of the axon (nerve fiber). If the nerve cell connecting the spinal cord to your feet is 1.3 m long, and the nerve impulse speed is 33 m/s, how long (in s) does it take for the nerve signal to travel this distance?

Answers

Answer:

Explanation:

Speed of electrical nerve signal = 33 m /s

Distance travelled = 1.3 m

time taken = distance / speed

= 1.3 / 33  

= .039 s

= 39 ms ( millisecond )  .

Student pushes a 50 N block across the floor for a distance of 15 m how much work was done to move the block

Answers

Answer:

750 J

Explanation:

We have a student that pushes a 50N block  across the floor for a distance of 15m. The question is asking how much work was done to move the block.

To solve this, we must know that we are looking for a certain thing called joules. And to get the answer, we must follow the formula of W = FS

F being the force and S being the distance.

W = FS

W = (50)(15)

W = 750

Therefore, 750 joules is our answer.

HURRY!!!
I need helppppp!!!

Answers

Answer:

ok i think the answer would be C. or B. hope im right

Any change in the cross section of the vocal tract shifts the individual formant frequencies, the direction of the shift depending on just where the change in area falls along the standing wave. Constriction of the vocal tract at a place where the standing wave of a formant exhibits minimum-amplitude pressure oscillations generally causes the formant to drop in frequency; expansion of the tract at those same places raises the frequency. Three other major tools for changing the shape of the tract in such a way that the frequency of a particular formant is shifted in a particular direction are the jaw, the body of the tongue and the tip of the tongue. Moving the various articulatory organs in different ways changes the frequencies of the two lowest formants over a considerable range [18].

One way to increase formant frequency is to ________ the vocal tract at a place where the standing wave of a formant frequency exhibits minimum-amplitude pressure oscillations.

a. Stretch
b. Vibrate
c. Contract
d. Expand

Answers

Answer:

The correct answer is option D.

Explanation:

It is stated in the question that constriction of the vocal tract at a place where the standing wave of a formant exhibits minimum-amplitude pressure oscillations generally causes the formant to drop in frequency so to increase formant frequency, the vocal should expand where the standing wave of a formant exhibits minimum-amplitude pressure oscillations. The answer is D.

I hope this helps.

what type of reaction is being shown in this energy diagram?

X exothermic, because energy is absorbed from the surroundings

O exothermic, because energy is released into the surrounding

X endothermic, because energy is released into the surrounding

X endothermic, because energy is absorbed from the surroundings​

best of luck nerds

Answers

Answer:

O exothermic, because energy is released into the surrounding

Explanation:

From the diagram the energy of the reactant is higher than the energy of the product, thereby making it exothermic. If you study diagram well, exothermic reaction means that the reactions releases energy into the surroundings.

Honeybees accumulate charge as they fly, and they transfer charge to the flowers they visit. Honeybees are able to sense electric fields; tests show that they can detect a change in field as small as 0.77 N/C. Honeybees seem to use this sense to determine the charges on flowers in order to detect whether or not a flower has been recently visited, so they can plan their foraging accordingly. As a check on this idea, let's do a quick calculation using typical numbers for charges on flowers.If a bee is at a distance of 24 cm, can it detect the difference between flowers that have a +30 pC charge and a +40 pC charge?

Answers

Answer:

difference between the field  = 1.56 N/C

as; 1.56 N/C is greater than 0.77 N/C;

Hence, Honeybees can detected the difference

Explanation:

Given the data in the question;

distance r = 24 cm = 0.24 m

charge 1 Q1 = +30 pC = 30×10⁻¹² C

charge 2 Q2 = +40 pC = 40×10⁻¹² C

Now, electric field due to +30 pC charge

E1 = kQ1/r²

where coulomb constant k is 9 × 10⁹ N.m²/C²

so we substitute

E1 = [( 9 × 10⁹ ) × (30×10⁻¹²)] / (0.24)²

E1 = 0.27 / 0.0576

E1 = 4.69 N/C

electric field due to +40 pC charge

E2 = kQ1/r²

E2 = [( 9 × 10⁹ ) × (40×10⁻¹²)] / (0.24)²

E2 = [( 9 × 10⁹ ) × (40×10⁻¹²)] / (0.24)²

E2 = 0.36 / 0.0576

E2 = 6.25 N/C

Now,

E2 = E1 =  6.25 N/C - 4.69 N/C = 1.56 N/C

difference between the field  = 1.56 N/C

as; 1.56 N/C is greater than 0.77 N/C;

Hence, Honeybees can detected the difference

You are trying to push a 30 kg canoe across a beach to get it to a lake. Initially, the canoe is
at rest, and you exert a force over a distance of 3 m until it has a speed of 1.2 m/s.

a. How much work was done on the canoe?

b. The coefficient of kinetic friction between the canoe and the beach is 0.2. How much work was done by friction on the canoe?

c. How much work did you perform on the canoe?

d. What force did you apply to the canoe?

Answers

Answer:

m = 30, g = 9.8, coefficient = 0.2, so force due to friction = 30 x 9.8 x 0.2 = 58.8 N, so work done by friction = 58.8 x 1.2 = 70.56 J

Explanation:

How much force is needed to accelerate a 9,760 kg airplane at a rate of 3.6 m/s2?
OA. 2,711 N
OB. 35,136 N
OC. 126,490 N
OD. 9,760 N

Answers

Answer:

the answer is B: 35,136

Explanation:

force = mass × acceleration

force = 9760 × 3.6

35,136 = 9760 × 3.6

Please help I will fail

Answers

Answer:

6. A

7. C

8. B

9. The average speed is the distance (a scalar quantity) per time ratio. Speed is ignorant of direction. The average velocity is the displacement or position change (a vector quantity) per time ratio.

In a physics lab experiment for the determination of moment of inertia, a team weighs an object and finds a mass of 2.15 kg. They then hang the object on a pivot located 0.163 m from the object's center of mass and set it swinging at a small amplitude. As two of the team members carefully count 113 cycles of oscillation, the third member measures a duration of 241 s. What is the moment of inertia of the object with respect to its center of mass about an axis parallel to the pivot axis

Answers

Answer:

0.339 kgm²

Explanation:

We know the period of this pendulum, T = 2π√(I/mgh) where I = moment of inertia of the object about the pivot axis, m = mass of object = 2.15 kg, g = acceleration due to gravity = 9.8 m/s² and h = distance of center of mass of object from pivot point = 0.163 m.

Since T = 2π√(I/mgh), making I subject of the formula, we have

I = mghT²/4π²

Now since it takes 241 s to complete 113 cycles, then it takes 241 s/113 cycles to complete one cycle.

So, T = 241 s/113 = 2.133 s

So, Substituting the values of the variables into I, we have

I = mghT²/4π²

I = 2.15 kg × 9.8 m/s² × 0.163 m × (2.133 s)²/4π²

I = 15.63/4π² kgm²

I = 0.396 kgm²

Now from the parallel axis theorem, I = I' + mh² where I' = moment of inertia of object with respect to its center of mass about an axis parallel to the pivot axis

I' = I - mh²

I' = 0.396 kgm² - 2.15 kg × (0.163 m)²

I' = 0.396 kgm² - 0.057 kgm²

I' = 0.339 kgm²

A 4.0-g bead carries a charge of 20 μC. The bead is accelerated from rest through a potential difference V, and afterward the bead is moving at 3.0 m/s. What is the magnitude of the potential difference V? *
1 point
900 V
400 V
200 V
400 kV

Answers

Answer:

The magnitude of the potential difference is 900 V.

Explanation:

Given;

mass of the bead, m = 4.0 g = 0.004 kg

charge of the bead, Q = 20 μC = 20 x 10⁻⁶ C

final velocity of the bead, v = 3 m/s

What is the magnitude of the potential difference V?

Apply the principle of conservation of energy;

The electric potential energy at the beginning is equal to kinetic energy of the bead  at the end of the journey.

qV = ¹/₂mv²

[tex]V = \frac{mv^2}{2q} \\\\V = \frac{0.004 \ \times \ (3)^2}{2(20 \times 10^{-6})}\\\\V = 900 \ V[/tex]

Therefore, the magnitude of the potential difference is 900 V.

The magnitude of the potential difference (V) is equal to 900 Volts.

Given the following data:

Mass of bead = 4.0 g to kg = 0.004 kgCharge of bead = 20 μC = [tex]20 \times 10^{-6} \;C[/tex]Final velocity of bead = 3 m/s

To determine the magnitude of the potential difference (V):

How to calculate the potential difference (V).

We would apply the law of conservation of energy, which states that the electric potential energy possessed by the bead at the beginning is equal to the kinetic energy possessed by the bead at the end of the journey:

[tex]qV = \frac{1}{2} mv^2\\\\V = \frac{\frac{1}{2} mv^2}{q} \\\\V = \frac{\frac{1}{2} \times 0.004 \times 3.0^2}{20 \times 10^{-6}} \\\\V = \frac{ 0.002 \times 9}{20 \times 10^{-6}}[/tex]

V = 900 V.

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