Answer:
The answer is 16
Explanation:
i need soon this is due at 10:30 pm its curently 6:00 pm
What is parasitism?
Answer:
the practice of living as a parasite in or on another organism.
Hope this HELPS!!!
Explanation:
These elements look like steps on the periodic table. They share properties of both metals and nonmetals. Computer chips contain elements from this family.
A) these elements are nonmetals
B) These elements are radioactive
C) these elements are metalloids
D) these elements are metals
Answer:
The answer would be C the metalloid in computer chips is silicone, it has luster like metal but is brittle like non metal.
Explanation:
These elements look like steps on the periodic table. They share properties of both metals and nonmetals. These elements are metalloids. Thus option C is correct.
What is periodic table?Periodic table is defined as an arrangement of all known elements in order of increasing atomic number and recurrent chemical attributes.
It is also defined as an ordered grouping of the 118 known chemical elements.
Metals are defined as a substance that has a glossy appearance when freshly manufactured, polished, or shattered and conducts electricity and heat reasonably effectively.
Non metals are defined as a natural materials that are physically fragile and do not generate heat or electricity.
Metalloids are defined as a type of chemical element with properties that are mostly intermediate between those of metals and nonmetals.
Thus, these elements look like steps on the periodic table. They share properties of both metals and nonmetals. These elements are metalloids. Thus option C is correct.
To learn more about periodic table, refer to the link below:
https://brainly.com/question/11155928
#SPJ5
What might a peasized gland within the skull be?
salivary gland
pituitary gland
mammary gland
sebaceous gland
Answer:
Explanation:
pituitary gland
Answer:
B
Explanation:
The pituitary gland is a pea-sized structure that is attached to the undersurface of the brain by a thin stalk.
How many moles are found in 10.5 g of Pb?
Answer:
Number of moles = 0.05 mol
Explanation:
Given data:
Mass of Pb = 10.5 g
Number of moles of Pb = ?
Solution:
Formula:
Number of moles = mass/molar mass
Molar mass of Pb is 207.2 g/mol.
Now we will put the values in formula.
Number of moles = 10.5 g/207.2 g/mol
Number of moles = 0.05 mol
Which of the following is an example of chemical weathering?
A . Rock grinded away by other rocks in a stream bed
B. Ice freezing and thawing in cracks
C. Waves beating on the shoreline
D. Dissolving of rock due to acid rain
Answer:
D. Dissolving of rock due to acid rain.
ou are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A and 2% B. What is the ee of this solution
Complete Question
You are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A and 2% B. What is the enantiomeric excess?
Answer:
The value is [tex]k = 96 %[/tex]
Explanation:
From the question we are told that
The percentage of enantiomer A is A = 98%
The percentage of enantiomer B is B = 2%
Generally the enantiomeric excess is mathematically represented as
[tex]k = \frac{A -B}{A+B} * 100[/tex]
=> [tex]k = \frac{98 -2}{98+2} * 100[/tex]
=> [tex]k = 96 %[/tex]
what is the point of doing an experiment. Help thank you
Answer:
to find out how somethings work
Explanation:
Answer:
Doing experiments is good because when you try these possibilities you can learn about something that you've tried or see why this experiment didn't really work. It also helps you understand that not everything you try will work. that's why we experiment.
Explanation:
Hope this helps:)
Two fruit flies that are heterozygous for body color and eye color are crossed. Brown body color is dominant to black body color. Red eye color is dominant to brown eye color.
Determine the genotypes of offspring 1-8.
1
2
3
4
5
6
7
8
A 4-column table has 4 rows. The labels of the columns are Upper B Upper E, Upper B e, b Upper E, b e. The labels of the rows are Upper B Upper E, Upper B e, b Upper E, Upper B b Upper E e. The first column has entries 1, Upper B Upper B Upper E e, 4, Upper B b Upper E e. The second column has entries Upper B Upper B Upper E e, 3, Upper B b Upper E e, 7. The third column has entries Upper B b Upper E Upper E, Upper B b Upper E e, 5, b b Upper E e. The fourth column has entries 2,Upper B b e e, 6, 8.
Answer:
the answer is simple
Explanation:
jnnn B upper up of the eye color
Answer:
1. BBEE
2. BbEe
3. BBee
4. BbEE
5. bbEE
6. bbEe
7. Bbee
8.bbee
Sulfur trioxide, SO3 , is produced in enormous quantities each year for use in the synthesis of sulfuric acid.
S(s) + O2(g) -------> SO2(g)
2SO2(g) + O2(g) ---------> 2SO3(g)
What volume of O2(g) at 340.°С and a pressure of 4.75 atm is needed to completely convert 6.30 g sulfur to sulfur trioxide?
Volume =_____ L
Answer:
3.14 L of oxygen (O₂).
Explanation:
We'll begin by calculating the number of mole in 6.3 g of sulphur (S). This can be obtained as follow:
Molar mass of S = 32 g/mol
Mass of S = 6.3 g
Mole of S =.?
Mole = mass / molar mass
Mole of S = 6.3/32
Mole of S = 0.197 mole
Next, we shall write the overall equation of the reaction between sulphur (S) and oxygen (O₂) to produce sulphur trioxide (SO₃) .
This is illustrated below:
S (s) + O₂ (g) —> SO₂ (g)
SO₂ (g) + O₂ (g) —> 2SO₃ (s)
Overall reaction:
2S (s) + 3O₂ (g) —> 2SO₃ (g)
Next, we shall determine the number of mole of oxygen (O₂) needed to completely convert 6.30 g (i.e 0.197 mole) of sulfur.
This is illustrated below:
From the balanced equation above,
2 moles of sulphur (S) required 3 moles of oxygen (O₂) .
Therefore, 0.197 mole of sulphur (S) will require = (0.197 × 3)/2 = 0.296 mole of oxygen (O₂).
Therefore, 0.296 mole of oxygen (O₂) is needed.
Finally, we shall determine the volume of oxygen (O₂) needed as follow:
Number of mole (n) of oxygen (O₂) = 0.296 mole
Temperature (T) = 340 °С = 340 °С + 273 = 613 K
Pressure (P) = 4.75 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) of oxygen (O₂) =.?
PV = nRT
4.75 × V = 0.296 × 0.0821 × 613
Divide both side by 4.75
V = (0.296 × 0.0821 × 613) / 4.75
V = 3.14 L
Therefore, 3.14 L of oxygen (O₂) is needed for the reaction.
Hydrogen sulfide decomposes according to the following reaction, for which Kc=9.30E-8 at 700 degrees Celsius. 2 H2S(g) --> 2 H2(g) + S2(g) If 0.29 moles of H2S is placed in a 3.0-L container, What is the equilibrium concentration of H2(g) at 700 degrees Celsius?
Answer: The equilibrium concentration of [tex]H_2(g)[/tex] at 700 degrees Celsius is 0.0012 M
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_c [/tex]
Moles of [tex]H_2S[/tex] = 0.29 mole
Volume of solution = 3.0 L
Initial concentration of [tex]H_2S[/tex] = [tex]\frac{0.29mol}{3.0L}=0.097M[/tex]
The given balanced equilibrium reaction is,
[tex]2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)[/tex]
Initial conc. 0.097 M 0M 0M
At eqm. conc. (0.097-2x) M (2x) M (x) M
The expression for [tex]K_c[/tex] is written as:
[tex]K_c=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}[/tex]
[tex]K_c=\frac{(2x)^2\times x}{(0.097-2x)^2}[/tex]
[tex]9.30\times 10^{-8}=\frac{(2x)^2\times x}{(0.097-2x)^2}[/tex]
[tex]x=0.00060[/tex]
Equilibrium concentration of [tex][H_2][/tex]= 2x= [tex]2\times 0.00060=0.0012M[/tex]
Select the reagents you would use to synthesize the compounds below from benzene. Use the minimum number of steps. No more than three steps are required in any synthesis.
a. Br2, FeBr3
b. CH3COCi. AICl3
c. SO3, H2SO4
d. Cl2, FeCl3
e. KMnO4, H2O
f. HNO3, H2SO4
g. Fe, H3O then OH
h. CH3Cl, AICl3
m-chlorobenzenesulfonic acid:
2,4,6-tribromoaniline
Answer:
f and a. That is reagents f[HNO3, H2SO4] is used first then followed by reagent a[Br2, FeBr3]
Explanation:
So, in the production of m-bromonitrobenzene[3-Nitro-1-bromobenzene/1-Bromo-3-nitrobenzene] from benzene from the reagents provided by using the fastest reagents that is to say the reagent with the minimum number of steps, we are going to make use of reagents in option 'f' followed by reagents in option 'a'.
STEP ONE: The first step in the production of m-bromonitrobenzene[3-Nitro-1-bromobenzene/1-Bromo-3-nitrobenzene] from benzene to give the minimum number of steps from the reagents given is nitration by using the reagents in option 'f'' that is HNO3, H2SO4 to give nitrobenzene. The equation for the chemical reaction is given below as:
C₆H₆ + HNO₃, H₂SO₄ -------------------------------------------------------> C6H5NO2.
It is the N⁺O₂ that is been used in the reaction mechanism [from the reaction: HNO₃ + H₂SO₄ < -----------------> N⁺O₂ + HSO₄⁻ + H₂O].
STEP TWO: The next thing to do is to react the nitrobenzene got from the nitration of benzene in step one above with the reagents in option 'a'[Br2, FeBr3]. This step is known as the bromination of nitrobenzene.
C₆H₅NO₂ + Br₂, FeBr3 ------------------------------------------------> C₆H₄BrNO₂.
The discrete group of atoms that are held together by sharing valence electrons
Answer:
Molecule
Explanation:
Molecule is defined as the discrete group of atoms that are held together by sharing valence electrons.
This is because two or more atoms is known as a molecule and for electron sharing to occur then there must be a minimum of two atoms which is also known as a molecule present in the sharing process.
In the situations described below, what is the free energy change if 1 mole of Na+ is transported across a membrane from a region where the concentration is 267 μM to a region where it is 80 mM? (Assume T=37∘C.)
Answer:
ΔG = 19.5 kJ/mol
Explanation:
The free energy change for moving an ion is given by the following formula:
ΔG = RT㏑(C₂/C₁) + ΖЭψ
where R is molar gas constant = 8.315 J/mol;
T = 273 +37 = 310 K;
C₂ is concentration outside the cell = 267 μM = 0.000267 M;
C₁ is concentration inside the cell = 80 mM = 0.005 M;
Ζ is charge on ion = +1;
Э is Faraday's constant = 96500 J/V;
ψ is standard transmembrane potential = 0.05 V
ΔG = (8.315 J/mol * 310 K) ㏑(0.08/0.000267) + 1 *(96500 J/V * 0.05 V)
ΔG = (14692.60 + 4825)J/mol
ΔG = 19517.6 J/mol
ΔG = 19.5 kJ/mol
When you finish exercising, you are hot, tired, and sweating. After a bottle of juice, you feel a lot better. Which organ systems are working together in this scenario?
Answer:
Nervous and Excretory
Explanation:
The nervous system makes you thirsty. The integumentary system makes you sweat. the integumentary system is very similar to the Excretory system.
Nervous and Excretory systems are working together in this scenario.
The nervous system makes you thirsty. The integumentary system makes you sweat. the integumentary system is very similar to the Excretory system.
The blood flow increases, your brain is exposed to more oxygen and nutrients. Exercise also induces the release of beneficial proteins in the brain. Sweating cools the body when it becomes warm. When the body temperature rises, such as when exercising on a hot day, the dermal blood vessels dilate.The excretory system works with the endocrine system to help maintain homeostasis.Learn more:
brainly.com/question/17342396
Which graph best matches a person walking away at a constant speed
What is the pH of 0.166 M triethylammonium chloride, (C2H5)3NHCl. The Kb of triethylamine, (C2H5)3N, is 5.2 x 10-4.?
Answer:
5.7
Explanation:
(C₂H₅)₃NHCl dissociates according to the following equation.
(C₂H₅)₃NHCl ⇒ (C₂H₅)₃NH⁺ + Cl⁻
The molar ratio of (C₂H₅)₃NHCl to (C₂H₅)₃NH⁺ is 1:1. Then, the concentration of (C₂H₅)₃NH⁺ is Ca = 0.166 M.
(C₂H₅)₃NH⁺ is the conjugate acid of (C₂H₅)₃N. Given the Kb of (C₂H₅)₃N, we can calculate Ka for (C₂H₅)₃NH⁺ using the following expression.
Ka × Kb = Kw
Ka = Kw / Kb
Ka = 1.0 × 10⁻¹⁴ / 5.2 × 10⁻⁴
Ka = 1.9 × 10⁻¹¹
(C₂H₅)₃NH⁺ dissociates according to the following equation.
(C₂H₅)₃NH⁺ ⇄ (C₂H₅)₃N + H⁺
We can calculate [H⁺] using the following expression.
[H⁺] = √(Ca × Ka) = √(0.166 × 1.9 × 10⁻¹¹) = 1.8 × 10⁻⁶
The pH is:
pH = -log [H⁺] = -log 1.8 × 10⁻⁶ = 5.7
2.28 is the pH of 0.166 M triethylammonium chloride, [tex](C_2H_5)_3NHCl[/tex]. The Kb of triethylamine, [tex](C_2H_5)_3N[/tex], is [tex]5.2 \times 10^{-4}[/tex].
The term "potential of hydrogen" (pH) refers to a solution's acidity or alkalinity. It is a scale from 0 to 14, with 7 representing neutrality. A pH value of 7 or higher suggests alkalinity, whereas one below 7 indicates acidity. Since the pH scale is logarithmic, each number corresponds to a tenfold increase or decrease in acidity or alkalinity. For instance, a pH of 3 solution is ten times more acidic than a pH 4 solution. Similar to this, a pH 10 solution is ten times more alkaline than a pH 9 solution.
[tex](C_2H_5)_3NH^+ (aq) + H_2O (l) \rightarrow (C_2H_5)_3N (aq) + H_3O^+ (aq)[/tex]
Kb = [triethylamine] [[tex]H_3O^+[/tex]] / [triethylammonium chloride]
5.2 x[tex]10^{-4}[/tex] = (x) (x) / (0.166 - x)
x ≈ 5.32 x [tex]10^{-3}[/tex] M.
pH= -log(x)
= -log(5.32 x [tex]10^{-3}[/tex]))
≈ 2.28
To know more about pH, here:
https://brainly.com/question/32258715
#SPJ6
Literally struggling with this concept.(problem set included below)
Air containing 20.0 mol% water vapor at an initial pressure of 1 atm absolute is cooled in a 1- liter sealed vessel from 200°C to 15°C. (a) What is the pressure in the vessel at the end of the process? (Hint: The partial pressure of air in the system can be determined from the expression pair = nairRT/V and P = pair + pH2O. You may neglect the volume of the liquid water condensed, but you must show that condensation occurs.) (b) What is the mole fraction of water in the gas phase at the end of the process? (c) How much water (grams) condenses?
Answer:
This solution is quite lengthy
Total system = nRT
n was solved to be 0.02575
nH20 = 0.2x0.02575
= 0.00515
Nair = 0.0206
PH20 = 0.19999
Pair = 1-0.19999
= 0.80001
At 15⁰c
Pair = 0.4786atm
I used antoine's equation to get pressure
The pressure = 0.50
2. Moles of water vapor = 0.0007084
Moles of condensed water = 0.0044416
Grams of condensed water = 0.07994
Please refer to attachment. All solution is in there.
Select the word that is incorrect in the paragraph and replace it with a word which makes the statement correct:
Group 2 elements have two valence electrons in their outer shell and are considered metals. In order to form an ion, a Group 2 element will
gain two electrons and form a cation.
Ions can be made by single element or covalently bonded group of elements. The covalently bonded group of elements is called polyatomic ions or polyatomic atoms. In order to form an ion, a Group 2 element will loose two electrons and form a cation.
What is Ions?Any species that contain charge whether it is positive charge or negative charge is called ions. The example of polyatomic ions are sulfate, phosphate, nitrate etc.
Cation is the species that loose electron and attain positive charge while anion is a species which gain electron and attains negative charge so when anion and cation combine in fixed ration the the overall charge of the molecule is zero that is molecule is neutral, the charge over cation and anion is also called oxidation state. In order to form an ion, a Group 2 element will loose two electrons and form a cation.
Therefore, in order to form an ion, a Group 2 element will
loose two electrons and form a cation.
To learn more about ions, here:
https://brainly.com/question/13692734
#SPJ2
Why does sodium chloride form a crystal lattice
Answer:
Ions of opposite charge strongly attract each other; those of like charges repel. As a result ions in an ionic compound are arranged in a particular manner.
Explanation:
Google is smart
Identify the correct equation for the equilibrium constant Kc for the reaction given. C u ( s ) + 2 A g N O 3 ( a q ) − ⇀ ↽ − C u ( N O 3 ) 2 ( a q ) + 2 A g ( s ) Cu(s)+2AgNOX3(aq)↽−−⇀Cu(NOX3)X2(aq)+2Ag(s) Select one: K c = [ Cu ( NO 3 ) 2 ] [ Ag ] 2 [ AgNO 3 ] 2 [ Cu ] Kc=[Cu(NO3)2][Ag]2[AgNO3]2[Cu] K c = [ Cu ( NO 3 ) 2 ] 2 [ Ag ] [ AgNO 3 ] [ Cu ] 2 Kc=[Cu(NO3)2]2[Ag][AgNO3][Cu]2 K c = [ Cu ( NO 3 ) 2 ] [ AgNO 3 ] 2 Kc=[Cu(NO3)2][AgNO3]2 K c = [ Cu ( NO 3 ) 2 ] [ AgNO 3 ] Kc=[Cu(NO3)2][AgNO3]
Answer:
Kc = [Cu(NO₃)₂]/[2 AgNO₃]²
Explanation:
Let's consider the following balanced redox equation.
Cu(s) + 2 AgNO₃(aq) ⇄ Cu(NO₃)₂(aq) + 2 Ag(s)
The concentration equilibrium constant (Kc) is equal to the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species.
The concentration equilibrium constant for this reaction is:
Kc = [Cu(NO₃)₂]/[2 AgNO₃]²
The density of wind-packed snow is estimated to be 0.35 g/cm^3. A flat roof that is 35 by 43 feet has 28 inches of snow on it. How many pounds of snow are on the roof?
Answer:
There are 76728.2 pounds of snow on the roof
Explanation:
To determine how many pounds of snow are on the roof,
First we will determine the mass of the snow in grams.
From the question,
Density of snow = 0.35 g/cm³
From
Density = Mass / Volume
To determine the mass, we will first find the volume.
From the question, a flat roof that is 35 by 43 feet has 28 inches of snow on it, that is, the height of the snow on the roof is 28 inches.
Area of the roof = 35 ft × 43 ft = 1505 ft²
Volume of the snow = Area of the roof × Height of the snow
Height of the snow = 28 inches
12 inches = 1 foot
∴ 28 inches = 28/12 feet = 2.3333 ft
Hence,
Volume of the snow = 1505 ft² × 2.3333 ft = 3511.62 ft³
Volume of the snow = 3511.62 ft³
This is the volume of the snow in cubic feet
Now, we will convert cubic feet (ft³) to cubic centimeter (cm³)
1 ft = 30.48 cm
and 1 ft³ = 30.48³ cm³ = 28316.84659 cm³.
If 1 ft³ = 28316.84659 cm³
∴ 3511.62 ft³ will be 3511.62 × 28316.84659 cm³ = 99438004.83 cm³
Hence, Volume of snow = 99438004.83 cm³
Now, we can determine mass of snow in grams
From
Density = Mass / Volume
Mass = Density × Volume
Mass = 0.35 g/cm³ × 99438004.83 cm³
Mass = 34803301.69 g
Now, we will convert the mass from grams to pounds
1 pound = 453.592 grams
If 453.592 grams = 1 pound
Then, 34803301.69 g will be 34803301.69 / 453.592 pounds = 76728.2 pounds
Hence, there are 76728.2 pounds of snow on the roof.
Cathode rays are deflected toward a negatively charged plate in an electric field.
True
False
Answer:
true. cathode rays are deflected
What are the factors affecting your limitations? How about possibilities?
Explanation:
My physiological make-up that governs the attributes I have and my climate, i.e. the conditions I have, are the variables influencing my limits. Biological make-up also regulates my prospects when they depend on my attributes, i.e. my ability and my environment , i.e. the conditions under which I am. This has been shown by experiments on twins, that our limits and opportunities are controlled by both genetics and environment.
A helium filled blimp will rise just so high into the atmosphere and then stop. Why? Will a smaller blimp rise higher than a larger one, if both are filled to the same pressure?
Answer:
See explanation
Explanation:
When a helium blimp rises in the atmosphere, a point eventually comes when the buoyancy of the blimp compared to the air it displaces is no longer greater than gravity's pull on the blimp hence it stops rising.
A smaller blimp will rise more than a larger blimp at the same pressure because the weight of the blimp determines the altitude to which it will rise.
The half life of oxygen is 2 minutes. What fraction of a sample of 0.15 will remain after 5 half lives?
Answer:
3.13%.
Explanation:
The following data were obtained from the question:
Original amount (N₀) = 0.15
Half life (t½) = 2 mins
Number of half-life (n) = 5
Fraction of sample remaining =.?
Next, we shall determine the amount remaining (N) after 5 half-life. This can be obtained as follow:
Amount remaining (N) = 1/2ⁿ × original amount (N₀)
NOTE: n is the number of half-life.
N = 1/2ⁿ × N₀
N = 1/2⁵ × 0.15
N = 1/32 × 0.15
N = 0.15/32
N = 4.69×10¯³
Therefore, 4.69×10¯³ is remaining after 5 half-life.
Finally, we shall the fraction of the sample remaining after 5 half-life as follow:
Original amount (N₀) = 0.15
Amount remaining (N) = 4.69×10¯³
Fraction remaining = N/N₀ × 100
Fraction remaining = 4.69×10¯³/0.15 × 100
Fraction remaining = 3.13%
You make up a solution of a diprotic acid, H2A, having pKa values of 5.0 and 9.0. Identify the primary, secondary, and tertiary species when you set the pH equal to 8.0 by addition of KOH.
Answer:
Explanation:
A solution with a pH value of 7 is neutral i.e neither acidic nor alkaline. A solution with a pH less than 7 is said to be acidic, while one with a pH value more than 7 is alkaline. Acidity increases as the value decrease below 7, while alkalinity increases as the value increase about 7.
Given that H2A is a diprotic weak acid have pKa values of 5.0 ad 9.0, it will undergo dissociation in the solution as:
NOTE: These reactions are reversible reactions.
[tex]\mathbf{H_2A \to H^+ + HA^- \ \ \ pKa = 5.0}[/tex]
[tex]\mathbf{HA^- \to H^+ +A^{2-} \ \ \ pKa = 9.0}[/tex]
Thus;
The primary species is HA⁻
The secondary species is A²⁻
A sample of methane gas is collected at 285 K and cooled to 245 K. At 245 K the volume of the gas is 75.0 L. Calculate the volume of the methane gas at 285 K. Assume constant pressure
Answer:
V₂ = 87.24 L
Explanation:
Charle's law states that at constant pressure, the volume of the gas is directly proportional to the temperature. Its mathematical form is given by :
[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]
We have, V₁ = 75, T₁ = 245 K, T₂ = 285, V₂ = ?
Putting all the values, we get :
[tex]V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{75\times 285}{245}\\\\V_2=87.24\ L[/tex]
So, the new volume is 87.24 L.
what is the oxidation number of cesium in Cs2Cr2O7
+1 for each Cs, -2 for each O, +6 for each Cr
What is the name???????
Answer:
Carbon Hydrogen
Explanation:
I believe it means carbon (C) to one atom of hydrogen (H).
