The molar solubility of C a ( O H ) 2 was experimentally determined to be 0. 020 M. Based on this value, what is the K s p of C a ( O H ) 2 ?

Answers

Answer 1

Answer:

Ksp = [tex]3.2*10^{-5}[/tex]

Explanation:

If 0.020 M of Ca(OH)2 dissociates, then we can follow the Ksp formula.

Ksp = [tex][A]^{a} [B]^{b}[/tex]     Eq.1

[tex]Ca(OH)2 -- > Ca^{2+} (aq) + 2 OH^{-} (aq)[/tex]      Eq.2

[tex]0.02M Ca(OH)2 -- > 0.02 M Ca^{2+} + 2*0.02 M OH^{-}[/tex]

Here, Ca is our A and since it has a coefficient of 1, a = 1

OH is our B. The concentration is doubled because there are 2 moles of OH per mole of Ca(OH)2. Due to this it also has a coefficient of two (Eq.2), making b = 2.

Ksp = [tex][0.02][0.02*2]^{2}[/tex]

Ksp = 0.000032

Ksp = [tex]3.2*10^{-5}[/tex]


Related Questions

you need to make an aqueous solution of 0.172 m iron(ii) nitrate for an experiment in lab, using a 250 ml volumetric flask. how much solid iron(ii) nitrate should you add?

Answers

We need to add 7.7 g of solid iron(II) nitrate to make a 0.172 M solution in 250 mL volumetric flask.

First, we can use molarity and volume of solution to find the number of moles of iron(II) nitrate needed:

moles of [tex]Fe(NO_3)_2[/tex]= Molarity × Volume in liters

moles of [tex]Fe(NO_3)_2[/tex] = 0.172 mol/L × 0.250 L = 0.043 mol

Next, we can use the molar mass of iron(II) nitrate to find the mass of the solid that needs to be added:

mass of [tex]Fe(NO_3)_2[/tex] = moles of [tex]Fe(NO_3)_2[/tex] × molar mass of [tex]Fe(NO_3)_2[/tex]

mass of [tex]Fe(NO_3)_2[/tex]= 0.043 mol × (55.85 g/mol + 2 × 14.01 g/mol + 6 × 16.00 g/mol)

mass of [tex]Fe(NO_3)_2[/tex]= 0.043 mol × 179.86 g/mol = 7.7 g

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A spiderweb and a kevlar jacket have some obvious differences. Which property is similar between the web and the jacket?.

Answers

One property that is similar between a spiderweb and a Kevlar jacket is their tensile strength.

Tensile strength is the ability of a material to resist breaking under tension or stretching.

Spider silk is known to be one of the strongest natural fibers, with a tensile strength comparable to steel. Kevlar is a synthetic polymer that is widely used in body armor, ropes, and other products that require high strength-to-weight ratios.

Kevlar has a tensile strength five times stronger than steel, making it an ideal material for applications where high strength and durability are required.

Both spider silk and Kevlar are known for their remarkable strength, and their ability to withstand tensile forces, making them highly desirable for use in a variety of applications where strength and durability are essential.

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A truck weighs 7280 pounds. If the pressure exerted by its tires on the ground is 87. 5 pounds per square centimeter,what is the area of one tire that in contact with the road

Answers

The area of one tire in contact with the road is approximately 378 square centimeters.

To solve this problem, we need to use the formula:

Pressure = Force/Area

We can rearrange this formula to solve for the area:

Area = Force/Pressure

First, we need to convert the weight of the truck from pounds to newtons, since pressure is typically measured in newtons per square meter. We can use the conversion factor 1 pound = 4.44822 newtons.

Weight of truck = 7280 pounds x 4.44822 newtons/pound
Weight of truck = 32,355.26 newtons

Now we can plug in the values for force and pressure:

Area = 32,355.26 newtons / 87.5 pounds per square centimeter

To convert pounds per square centimeter to newtons per square meter, we need to use the conversion factor 1 pound per square centimeter = 98,066.5 newtons per square meter.

Area = 32,355.26 newtons / (87.5 pounds per square centimeter x 98,066.5 newtons per square meter per pound per square centimeter)

Area = 0.0378 square meters

Finally, we can convert square meters to square centimeters by multiplying by 10,000:

Area = 0.0378 square meters x 10,000 square centimeters per square meter

Area = 378 square centimeters

Therefore, the area of one tire in contact with the road is approximately 378 square centimeters.

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Counting Atoms and Elements in a Chemical Formula (8. 5D)

Answers

For example, the chemical formula for water is H₂O. This tells us that there are two hydrogen atoms (H) and one oxygen atom (O) in each molecule of water. To count the number of atoms in a chemical formula, we can use the subscripts (the numbers that come after each element symbol) to determine how many atoms of each element are present. For example, in the chemical formula NaCl (which represents salt), there is one sodium (Na) atom and one chlorine (Cl) atom in each molecule.

Let us discuss this in detail. To count atoms and elements in a chemical formula, you need to understand the following terms:

- Atoms: The basic unit of a chemical element, consisting of protons, neutrons, and electrons.
- Elements: A substance that cannot be broken down into simpler substances, consisting of only one type of atom.
- Chemical Formula: A representation of a substance using symbols for its constituent elements and numbers to indicate the ratio of atoms in the compound.

Now, let's count the atoms and elements in a given chemical formula, for example, H₂O (water):

1. Identify the elements in the formula: In this case, we have two elements - Hydrogen (H) and Oxygen (O).
2. Count the atoms of each element: The subscript number next to each element symbol indicates the number of atoms of that element in the compound. For Hydrogen (H), the subscript is 2, meaning there are 2 Hydrogen atoms. For Oxygen (O), there is no subscript, which means there is only 1 Oxygen atom (when no subscript is present, it is understood to be 1).

So, in the chemical formula H₂O, there are 2 Hydrogen atoms and 1 Oxygen atom, for a total of 3 atoms.

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What happens in a decomposition reaction? A. Two ions trade places. B. Two substances combine to form one substance. C. The charges of the atoms change. D. Compounds break down into smaller compounds.​

Answers

A single compound decomposes into two or more smaller compounds or components during a decomposition reaction. Option D

A number of mechanisms, such as heat, light, or the addition of another molecule, can cause this. A significant quantity of potential energy is often held in the chemical bonds of the reactant component, and this energy is released during the reaction.

For instance, hydrogen peroxide's typical breakdown reaction involves the molecule dissolving into water and oxygen gas:

[tex]2H_2O_2 \rightarrow 2 H_2O + O_2[/tex]

The heat breakdown of calcium carbonate to produce calcium oxide and carbon dioxide gas is another illustration:

[tex]CaO + CO_2 = CaCO_3[/tex]

Decomposition reactions are crucial components of several chemical processes in both nature and industry. They are characterised by the dissolution of bigger molecules into smaller ones. Option D

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Write the following chemical reactions and balance:



Potassium reacts with sodium oxide to produce potassium oxide and sodium

Answers

The chemical reaction between potassium and sodium oxide results in the formation of potassium oxide and sodium. The balanced equation for this reaction is:
2K + Na₂O -> K₂O + 2Na


This reaction is an example of a displacement reaction, where a more reactive element (potassium) displaces a less reactive element (sodium) from its compound (sodium oxide). The displacement occurs because potassium has a greater tendency to lose electrons and form cations compared to sodium.

Potassium oxide is an important chemical compound with many industrial applications, including in the production of glass, ceramics, and fertilizers. It is also used as a drying agent and catalyst in organic reactions.

Sodium, on the other hand, is a highly reactive metal that is commonly found in compounds such as sodium chloride (table salt) and sodium hydroxide (lye). It is an essential element for many biological processes, including nerve and muscle function.

Overall, this chemical reaction between potassium and sodium oxide is important because it highlights the reactivity of these elements and the formation of useful compounds such as potassium oxide. It also emphasizes the importance of balancing chemical equations to ensure that the reactants and products are in the correct proportions.

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What volume of a 1.2M solution must be used to produce .5 L of a .7M solution?

Answers

Answer:

1,2million or meter

Explanation:

or 1 million until 7m

How many moles of aluminium are needed to react completely with 213 g CL2?

Answers

2.00 moles of aluminum are needed to react completely with 213 g of Cl₂.

How to get the number of moles

Prior to calculating the moles of aluminum (Al) required for a complete reaction with 213 g chlorine gas (Cl₂), it is necessary to write and balance the Al and Cl₂ chemical equation:

2Al + 3Cl₂ → 2 AlCl₃.

compute the quantity of Cl₂ in moles

molar mass of Cl₂

= 2 x atomic mass of Cl

= 2 x 35.45 g/mol

= 70.90 g/mol

To obtain moles of Cl₂ simply divide its mass by its molar weight as per this formula:

= 213 g / 70.90 g/mol = 3.00 mol.

moles of Al

= (moles of Cl₂ x 2) / 3

= (3.00 mol x 2) / 3

= 2.00 mol

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A gas has a pressure of 499.0 mm Hg at 50.0 °C. What is the
temperature at standard pressure (1 atm = 760 mmHg)?

Answers

The temperature of the gas at standard pressure is 219.02 °C.

What is the temperature of the gas at standard pressure (1 atm = 760 mmHg)?

Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.

It is expressed as;

P₁/T₁ = P₂/T₂

We know that the pressure (P1) is 499.0 mmHg at a temperature (T1) of 50.0°C. We want to find the temperature (T2) at standard pressure (P2 = 1 atm = 760 mmHg). We also know that the volume (V1) is constant, so we can write:

P₁/T₁ = P₂/T₂

Solving for T2, we get:

T2 = (P2 × T1)/P1

T2 = (760 mmHg × 323.15 K)/499.0 mmHg

T2 = 492.172 K

Converting this temperature to °C, we get:

T2 = 492.172 K - 273.15

T2 = 219.02 °C

Therefore, the temperature is 219.02 °C.

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Answer:

492.17 K (2 d.p.) = 219.02 °C (2 d.p.)

Explanation:

To find the final pressure inside the steel tank, we can use Gay-Lussac's law since the volume is constant.

Gay-Lussac's law

[tex]\boxed{\sf \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}}[/tex]

where:

P₁ is the initial pressure.T₁ is the initial temperature (in kelvins).P₂ is the final pressure.T₂ is the final temperature (in kelvins).

As we are solving for the final temperature, rearrange the equation to isolate T₂:

[tex]\sf T_2=\dfrac{P_2T_1}{P_1}[/tex]

Convert the initial temperature from Celsius to Kelvin by adding 273.15:

[tex]\implies \sf T_1=50+273.15=323.15\;K[/tex]

The standard pressure is 1 atm = 760 mmHg.

Therefore, the values to substitute into the equation are:

P₁ = 499.00 mmHgT₁ = 323.15 KP₂ = 760 mmHg

Substitute the values into the equation and solve for T:

[tex]\implies \sf T_2=\dfrac{760 \cdot 323.15}{499}[/tex]

[tex]\implies \sf T_2=\dfrac{245594}{499}[/tex]

[tex]\implies \sf T_2=492.172344689...[/tex]

[tex]\implies \sf T_2=492.17\;K\;(2\;d.p.)[/tex]

Therefore, the temperature at standard pressure for a gas with a pressure of 499.0 mmHg at 50.0 °C is 492.17 K (or 219.02 °C).

What volume of nitrogen reacts with 33. 6 litres of oxygen to produce nitrogen

dioxide

Answers

The balanced chemical equation for the reaction of nitrogen and oxygen to produce nitrogen dioxide is:

2NO + O2 → 2NO2

According to the equation, 1 mole of nitrogen reacts with 0.5 moles of oxygen to produce 1 mole of nitrogen dioxide.

To determine the volume of nitrogen required to react with 33.6 L of oxygen, we need to convert the volume of oxygen to moles, and then use the mole ratio to find the moles of nitrogen required, and finally convert to volume of nitrogen.

Using the ideal gas law, we can convert the given volume of oxygen to moles:

n(O2) = PV/RT

where P is the pressure, V is the volume, R is the gas constant, and T is the temperature in Kelvin.

Assuming standard temperature and pressure (STP) conditions of 1 atm and 273 K, we get:

n(O2) = (1 atm) × (33.6 L) / [(0.0821 L·atm/mol·K) × (273 K)] = 1.37 moles of O2

Using the mole ratio from the balanced chemical equation, we know that 2 moles of NO react with 1 mole of O2. So the number of moles of NO required to react with 1.37 moles of O2 is:

n(NO) = 2 × (1.37 moles of O2) = 2.74 moles of NO

Finally, we can convert the moles of NO to volume using the ideal gas law:

V(NO) = n(NO)RT/P

Assuming STP conditions again, we get:

V(NO) = (2.74 mol) × (0.0821 L·atm/mol·K) × (273 K) / (1 atm) ≈ 60.4 L

Therefore, approximately 60.4 L of nitrogen would be required to react with 33.6 L of oxygen to produce nitrogen dioxide, under the given conditions.

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What volume (in litres) of 0. 200 M NaOH is required to neutralize 22. 3 mL of 0. 152 M HCl?

Answers

To solve this problem, we can use the following equation:

Moles of acid = Moles of base

where "acid" refers to the HCl and "base" refers to the NaOH.

First, let's calculate the moles of HCl:

moles of HCl = concentration of HCl × volume of HCl

            = 0.152 mol/L × 0.0223 L

            = 0.0033856 mol

Next, let's calculate the volume of NaOH required to neutralize the HCl:

moles of NaOH = moles of HCl

volume of NaOH = moles of NaOH / concentration of NaOH

We know the concentration of NaOH (0.200 M), so let's substitute in the values:

moles of NaOH = 0.0033856 mol

volume of NaOH = 0.0033856 mol / 0.200 mol/L

              = 0.016928 L

              = 16.928 mL (rounded to three decimal places)

Therefore, 16.928 mL of 0.200 M NaOH is required to neutralize 22.3 mL of 0.152 M HCl.

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what would earth be like if vascular plants never developed

Answers

If the vascular plants never developed, the Earth would be drastically different. Vascular plants are responsible for much of the oxygen production on our planet, so the atmosphere would contain significantly less oxygen. Additionally, without the root systems of vascular plants, soil erosion would be much more prevalent and the landscape would likely be more barren.

The evolution of many animals, including insects and birds, would have been impacted as well, as many of these species rely on vascular plants for food and shelter. Overall, the absence of vascular plants would have a profound effect on the ecology and biodiversity of our planet.

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A compound is made up of 94. 5 g of aluminum and 199. 5 g or fluorine. Determine the empirical formula of the compound.



HELPPPP

Answers

The empirical formula of a compound made up of 94.5 g of aluminum and 199.5 g of fluorine is AlF₃.

To determine the empirical formula of the compound, we need to first calculate the moles of each element present in the sample.

Moles of aluminum = 94.5 g / 26.98 g/mol = 3.50 mol

Moles of fluorine = 199.5 g / 18.99 g/mol = 10.51 mol

Next, we need to determine the smallest whole number ratio between these two values.

Dividing both values by 3.50, we get:

Moles of aluminum = 1

Moles of fluorine = 3

Therefore, the empirical formula of the compound is AlF₃.

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The Si unit of hurtz equals one wave passing a fixed point in one _____

Answers

The Si unit of Hertz (Hz) represents the frequency of a wave, which is defined as the number of complete cycles of a wave passing a fixed point per second.

In other words, one Hertz equals one wave passing a fixed point in one second. This unit is commonly used to measure the frequency of various types of waves, including sound waves, electromagnetic waves, and radio waves.

For example, if a sound wave has a frequency of 440 Hz, it means that the sound wave completes 440 cycles of compression and rarefaction (the peaks and troughs of the wave) per second. Similarly, if a radio wave has a frequency of 100 MHz (megahertz), it means that the wave completes 100 million cycles per second.

The Hertz unit was named after Heinrich Hertz, a German physicist who was the first to demonstrate the existence of electromagnetic waves. Hertz's experiments in the late 19th century paved the way for the development of modern radio, television, and other forms of wireless communication.

In summary, the Si unit of Hertz equals one wave passing a fixed point in one second, and it is a fundamental unit of measurement for the frequency of various types of waves.

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How many moles are in a sample having 9. 3541 x 10^13 particles?

Answers

The sample has approximately 0.000155 moles.

To determine the number of moles in a sample of a substance given the number of particles, we need to use Avogadro's number, which states that there are[tex]6.022 x 10^23[/tex] particles in one mole of a substance.

Using this conversion factor, we can calculate the number of moles in the sample as follows:

[tex]9.3541 x 10^13[/tex]particles x 1 mole / [tex]6.022 x 10^23[/tex] particles ≈ 0.000155 moles

Therefore, the sample has approximately 0.000155 moles.

It's important to note that the number of particles in a sample does not depend on the substance's molar mass or atomic weight, but rather on the number of atoms, molecules, or ions present in the sample. Knowing the number of moles in a sample can be useful in determining other properties of the substance, such as its mass or volume.

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`Name:
Date:
Properties of Matter - Crunch time Review
1. If two objects balance like the ones shown below, what must be true?
A. Object A has more mass than object B.
Both objects have the same mass.
C. Object A has more volume than object B.
D. Both objects have the same volume.

Answers

Answer:

d

Explanation:

because i did it

Calculate the mass of iron that releases 2432 J of energy as its temperture rises from 25. 0 degrees * C to 87. 0 degrees * C. (The specific heat of iron is 0. 448 J/g^ C)

Answers

To solve this problem, we can use the formula:

q = m * c * ΔT

where q is the heat energy absorbed or released, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

We know that the heat energy released by the iron is 2432 J, the specific heat capacity of iron is 0.448 J/g°C, the initial temperature of the iron is 25.0°C, and the final temperature of the iron is 87.0°C.

The mass of iron that releases 2432 J of energy as its temperature rises from 25.0°C to 87.0°C is 96.2 g.

Substituting the values in the formula, we get:

2432 J = m * 0.448 J/g°C * (87.0°C - 25.0°C)

Simplifying the equation, we get:

m = 2432 J / (0.448 J/g°C * 62.0°C)

m = 96.2 g

Therefore, the mass of iron that releases 2432 J of energy as its temperature rises from 25.0°C to 87.0°C is 96.2 g.

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Balance equation for 15 g of solid Mg reacts with 15 g of HCl and produce MgCl2 and H2

Answers

When 15 g of Mg reacts with 15 g of HCl, 19.6 g of MgCl₂ and 0.208 g mass of H₂ are produced.

The molar mass of Mg is 24.31 g/mol, and the molar mass of HCl is 36.46 g/mol. To determine the number of moles of each substance, we divide the given mass by its molar mass:

moles of Mg = 15 g ÷ 24.31 g/mol = 0.618 mol

moles of HCl = 15 g ÷ 36.46 g/mol = 0.411 mol

Determine the limiting reactant in the reaction by comparing the number of moles of each reactant:

Mg: 0.618 mol

HCl: 0.411 mol × (1 mol Mg ÷ 2 mol HCl) = 0.206 mol

Since HCl is the limiting reactant, it will be completely consumed in the reaction. The amount of MgCl₂ produced can be calculated as:

moles of MgCl₂ = moles of HCl = 0.206 mol

mass of MgCl₂ = moles of MgCl₂ × molar mass of MgCl₂

mass of MgCl₂ = 0.206 mol × 95.21 g/mol = 19.6 g

Similarly, the amount of H₂ produced can be calculated as:

moles of H₂ = moles of HCl × (1 mol H₂ ÷ 2 mol HCl)

moles of H₂ = 0.206 mol × (1 mol H₂ ÷ 2 mol HCl) = 0.103 mol

mass of H₂ = moles of H₂ × molar mass of H₂

mass of H₂ = 0.103 mol × 2.02 g/mol = 0.208 g

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Complex Ion Formation:Cu(NH3)42 Ecell, after adding 6 M NH3to the copper cell 0. 77V. Use the Nernst equation to calculate the concentration of that free copper (II) ion that is in equilibrium with the complexed copper (II) ion, Cu(NH3)42 in the solution. Does the calculated value for the [Cu2 ] make sense (look up the Kf for the formation of Cu(NH3)42 ) and rationalize your findings)

Answers

The concentration of free copper (II) ions in equilibrium with Cu(NH₃)₂ is 5.15 x 10⁻¹⁰ M.

1. Write the half-reaction for Cu²⁺ and Cu(NH₃)₂: Cu²⁺ + 2NH₃ ⇌ Cu(NH₃)₂²⁺
2. Use the Nernst equation: E = E° - (0.05916/n) * log(Q)
3. Rearrange for [Cu²⁺]: [Cu²⁺] = 10^((E° - E) * n / 0.05916)
4. Plug in the values: E° = 0.77V, E = 0, n = 2
5. Calculate [Cu²⁺]: [Cu²⁺] = 5.15 x 10⁻¹⁰ M

The calculated value for [Cu²⁺] makes sense, as the Kf for Cu(NH₃)₂ formation is large, indicating a strong complex formation and low [Cu²⁺] concentration.

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How many liters of H2O gas are produced when


7. 25 liters of C3H8 are


burned at STP?


C3H8 + 5O2 → 3CO2 + 4H2O

Answers

At STP, 27.8 liters of H2O gas are produced when 7.25 liters of C3H8 are burned .

When 7.25 liters of C3H8 are burned at STP, according to the balanced chemical equation, 4 moles of H2O gas are produced for every 1 mole of C3H8.

First, we need to determine the number of moles of C3H8 in 7.25 liters. We can use the ideal gas law:

PV = nRT

Where P = pressure (STP = 1 atm), V = volume (7.25 L), n = number of moles, R = gas constant (0.0821 L atm/mol K), and T = temperature (STP = 273 K).

Solving for n:

n = PV/RT
n = (1 atm)(7.25 L)/(0.0821 L atm/mol K)(273 K)
n = 0.296 moles

Now we can use the mole ratio from the balanced equation to determine the number of moles of H2O produced:

1 mole C3H8 : 4 moles H2O

0.296 moles C3H8 x (4 moles H2O/1 mole C3H8) = 1.184 moles H2O

Finally, we can convert moles of H2O to liters of gas at STP using the same ideal gas law:

n = PV/RT

V = nRT/P
V = (1.184 mol)(0.0821 L atm/mol K)(273 K)/(1 atm)
V = 27.8 L

Therefore, 27.8 liters of H2O gas are produced when 7.25 liters of C3H8 are burned at STP.

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Your shopping cart has a mass of 20 kg. If you push it with a force of 20 N, what is the acceleration of the cart?

Answers

Answer:

1000m/s^2

Explanation:

since F=ma

:a=m/F

Yo convert ur m from kg to g

20×1000

20000

a=20000\20

a=1000m/s^2

A 98. 5°C metal bolt is placed in a calorimeter of 23. 1°C water. Which way will the heat energy flow?

Answers

Hi! The heat energy will flow from the 98.5°C metal bolt to the 23.1°C water in the calorimeter.

This is because heat always flows from a higher temperature object to a lower temperature object until thermal equilibrium is reached.

This principle is known as the second law of thermodynamics or the law of heat transfer. It describes the natural tendency for heat to move from regions of higher temperature to regions of lower temperature.

Heat transfer occurs through three main mechanisms: conduction, convection, and radiation.

In the given scenario, conduction is the primary mechanism of heat transfer. When the hot metal bolt comes into contact with the water in the calorimeter, the thermal energy from the bolt is transferred to the water molecules in direct contact with it.

The water molecules gain kinetic energy and begin to vibrate more rapidly, thereby increasing their temperature. As a result, the metal bolt loses thermal energy, and its temperature decreases.

This transfer of heat will continue until the metal bolt and water reach thermal equilibrium, where both objects have the same temperature. At this point, the heat flow between them will cease, as there is no longer a temperature difference to drive the transfer of thermal energy.

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Someone help me please

Answers

Answer: C

Explanation: When distinguishing between opinion and fact, it's important to pick out certain words or phrases.

EX 1: Apple's are healthy, but you shouldn't eat too many of them. Fact

EX 2: I don't think you should eat that banana, they don't taste good to me. Opinion

Try to say the sentence in your head as if you were talking to another person, and try to determine your answer that way.

7. 50 mL of an acetic acid (CH3CO2H, 60. 05 g/mole) stock solution was added to an analyte flask, along with 15 mL of water. 14. 36 mL of 0. 0915 M NaOH titrant was required to titrate the analyte solution to the endpoint. Calculate the concentration of the stock solution. Watch significant figures

Answers

The concentration of the acetic acid stock solution is 0.026259 M, considering significant figures.

To solve this problem, we first need to write out the balanced chemical equation for the reaction between acetic acid (CH₃CO₂H) and sodium hydroxide (NaOH):

CH₃CO₂H + NaOH → CH₃CO₂Na + H₂O

We can see from this equation that the stoichiometry of the reaction is 1:1 - that is, one mole of acetic acid reacts with one mole of NaOH. We also know that the volume of the analyte solution is 50 mL + 15 mL = 65 mL.

Next, we need to use the volume and concentration of the NaOH titrant to calculate the number of moles of NaOH that were added to the analyte solution:

V1 = 14.36 mL = 0.01436 L (convert mL to L)
C1 = 0.0915 M

n(NaOH) = V1 x C1 = 0.01436 L x 0.0915 mol/L = 0.00131294 mol

Since the stoichiometry of the reaction is 1:1, we know that this is also the number of moles of acetic acid that were present in the analyte solution. We can use this information to calculate the concentration of the stock solution:

n(CH₃CO₂H) = n(NaOH) = 0.00131294 mol
V2 = 50 mL = 0.05 L (convert mL to L)

M = n/V = 0.00131294 mol / 0.05 L = 0.026259 M

So the concentration of the acetic acid stock solution is 0.026259 M.

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Nicolaas' model demonstrates that and are primarily responsible for the movement of water on earth

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Nicolaas' model is a scientific model that explains the movement of water on Earth. According to the model, the two primary factors responsible for the movement of water on Earth are evaporation and precipitation.

Evaporation occurs when water changes from a liquid to a gas state due to heat from the sun. This process results in the formation of water vapor that rises into the atmosphere. Precipitation occurs when water vapor condenses in the atmosphere and falls back to the surface as rain, snow, or hail. These two processes play a critical role in the water cycle, which is essential for the survival of life on Earth. Therefore, Nicolaas' model highlights the significance of evaporation and precipitation in the movement of water on Earth.

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If 2. 40 mol of carbon are exposed to 3. 10 mol of steam identify the limiting reactant? How many moles of each product are formed? SHOW WORK OR NO CREDIT!!

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Limiting reactant in the given condition is Carbon, Moles of CO formed is 2.40 mol and moles of H2 formed is 2.40 mol

To determine the limiting reactant, we need to compare the amount of each reactant to their stoichiometric coefficients in the balanced chemical equation. The balanced equation for the reaction between carbon and steam is:

C (s) + H2O (g) → CO (g) + H2 (g)

The stoichiometric coefficients tell us that 1 mole of carbon reacts with 1 mole of steam to produce 1 mole of carbon monoxide and 1 mole of hydrogen gas.

So, for 2.40 moles of carbon, we need 2.40 moles of steam to react completely. However, we only have 3.10 moles of steam available, which means that steam is in excess and carbon is the limiting reactant.

To find the number of moles of products formed, we use the stoichiometric coefficients. Since carbon is the limiting reactant, we can use its amount to determine the theoretical yield of products.

From the balanced equation, 1 mole of carbon produces 1 mole of CO and 1 mole of H2. Therefore, 2.40 moles of carbon will produce 2.40 moles of CO and 2.40 moles of H2.

So, the answer to the question is:
Limiting reactant: Carbon
Moles of CO formed: 2.40 mol
Moles of H2 formed: 2.40 mol

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What is the pH of a solution where [OH⁻]=0. 00030M

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The pH of the solution where [tex][OH⁻][/tex]=0.00030 M is 11.48. This indicates that the solution is basic, or alkaline, since the pH is greater than 7.

To determine the pH of a solution where[tex][OH⁻][/tex]=0.00030 M, we can use the relationship between the concentrations of hydrogen ions and hydroxide ions in water, which is defined by the equation[tex]Kw = [H⁺][OH⁻].[/tex]At 25°C, the value of Kw is [tex]1.0 x 10^-14[/tex].

If we substitute the concentration of hydroxide ions given in the question ([tex][OH⁻][/tex]=0.00030 M) into this equation, we can solve for the concentration of hydrogen ions:

[tex]Kw = [H⁺][OH⁻]\\1.0 x 10^-14 = H⁺\\[H⁺] = 3.3 x 10^-12 M[/tex]

Now that we know the concentration of hydrogen ions, we can use the formula for pH, which is defined as [tex]pH = -log[H⁺][/tex], to find the pH of the solution:

[tex]pH = -log(3.3 x 10^-12)[/tex]

pH = 11.48

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The evaporation heat of mercury is 296 kJ/ kg. Calculate how much heat needs to be provided to change 50 g of this substance into vapour at its boiling point

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To calculate the amount of heat required to change 50 g of mercury into vapor at its boiling point, we need to use the following formula:

Q = m * H_vap

where Q is the amount of heat required, m is the mass of the substance, and H_vap is the heat of vaporization.

We are given that the heat of vaporization of mercury is 296 kJ/kg. To use this value, we need to convert the mass of mercury to kilograms:

m = 50 g = 0.05 kg

Now we can use the formula to calculate the amount of heat required:

Q = 0.05 kg * 296 kJ/kg = 14.8 kJ

Therefore, 14.8 kJ of heat needs to be provided to change 50 g of mercury into vapor at its boiling point.

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Two students in a chemistry lab start a particular lab with 1. 23 g of aluminum. They react it with excess sulfuric acid to produce aluminum sulfate. If they produce 3. 00 g of aluminum sulfate what is their percent yield

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The percent yield for the reaction of 1.23 g of aluminum with excess sulfuric acid to produce 3.00 g of aluminum sulfate is 38.46%.

To find the percent yield for the reaction of aluminum with sulfuric acid to produce aluminum sulfate, you need to follow these steps:

1. Write the balanced chemical equation for the reaction:
2 Al + 3 H₂SO₄ → Al₂(SO₄)₃ + 3 H₂

2. Calculate the molar mass of aluminum (Al) and aluminum sulfate (Al₂(SO₄)₃):
Al: 26.98 g/mol
Al₂(SO₄)₃: (2 × 26.98) + (3 × [4 × 16.00 + 32.07]) = 53.96 + 342.15 = 342.15 g/mol

3. Determine the moles of aluminum used in the reaction:
moles of Al = mass of Al / molar mass of Al = 1.23 g / 26.98 g/mol = 0.0456 mol

4. Calculate the theoretical yield of aluminum sulfate based on the moles of aluminum:
moles of Al₂(SO₄)₃ = 0.0456 mol Al × (1 mol Al₂(SO₄)₃ / 2 mol Al) = 0.0228 mol Al₂(SO₄)₃
mass of Al₂(SO₄)₃ = moles of Al₂(SO₄)₃ × molar mass of Al₂(SO₄)₃ = 0.0228 mol × 342.15 g/mol = 7.80 g (theoretical yield)

5. Calculate the percent yield:
percent yield = (actual yield / theoretical yield) × 100% = (3.00 g / 7.80 g) × 100% = 38.46%

So, the percent yield for the reaction of 1.23 g of aluminum with excess sulfuric acid to produce 3.00 g of aluminum sulfate is 38.46%.

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how does backbone help?​

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Answer:

Backbone help us to be straight ,walk ,sleep etc

Explanation:

Backbone is the part of human body which is located back of our body.

It effort helps us to be straight do various work

The spine or the backbone is the central structure of the vertebrate body and it serves a few imperative capacities:

Bolster: The spine gives bolster for the body and makes a difference keep up its shape.Security: The spine encases and ensures the spinal rope, which is mindful for transmitting signals between the brain and the rest of the body.Connection: Muscles, tendons, and ligaments join to the spine, permitting for development and giving steadiness.Blood cell generation: The springy tissue interior a few of the bones of the spine produces ruddy and white blood cells.Mineral capacity: The bones of the spine store minerals such as calcium and phosphorus, which are imperative for bone quality and other substantial capacities. 

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