The least expensive type of life insurance is _____.

Answer:

That depends on how accurate you are with pen and paper.

You can tell it's a growing exponential, so the form is the traditional one. If you are particularly inclined in crunching numbers and working on a grid I would pick 0, 1 and -1, 1/2 and -1/2, a few positive integers, and that's it.

If not, i would be satisfied saying that when x = 0 (ie, the y intercept) y= 3, and that's all. Then, my drawing is made with paint, don't expect a masterpiece.

Answer:

1. (2,5)

2. (-1.25, 1.75)

3. (-5,-2)

4.(-2.66, -4.33)

5. (-0.6, -0.2)

Step-by-step explanation:

Solve by substituting the y's and solve for x. Plug in x into one of the equations and find the y value for your point of intersection

Answer:

Ur reatarded

Step-by-step explanation:

The domain and range of the functions are:

Function (A):

Function (B):

So, the domain and range of the function:

Function (A):

Function (B):

Therefore, the domain and range of the functions are:

Function (A):

Function (B):

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if 2+8=10 then 12+8=20 so Asher is 12 years old while His sister is 20 cus we're adding Ash age to his sister which we don't kno what her age is but at the same time we both know that whatever her age is it adds up to 20

Recall that

cos²(t) + sin²(t) = 1

Then solving for cos(t) and sin(t), we have

x = 3 cos(t)   ===>   cos(t) = x/3

y = -6 sin(t)   ===>   sin(t) = -y/6

so that the above identity gives us

(x/3)² + (-y/6)² = 1

x²/9 + y²/36 = 1

36 (x²/9 + y²/36) = 36

(C) 4x² + y² = 36

The parametric equation in the Cartesian form is 4x² + y² = 36 the correct choice is (C).

A parametric equation in mathematics specifies a set of numbers as functions of one or more independent variables known as parameters.

We have two parametric equations:

x = 3cos(t) and

y = -6sin(t).

As we know, the trigonometric identity:

sin²θ + cos²θ = 1

For checking the option (A):
2x² + y² = 36

= 2(3cos(t))² + (-6sin(t))²

= 18cos²t + 36sin²t ≠ 36

Similarly, for checking the option:

4x² + y² = 36

= 4(3cost)² + (-6sint)²

= 36cos²t + 36sin²t

= 36(cos²t + sin²t)

= 36(1) = 36

Thus, the parametric equation in the Cartesian form is 4x² + y² = 36 the correct choice is (C).

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Answer:

48

11

Step-by-step explanation:

5 glasses  ------  20 sec

12 glasses ------  ?

so 5 * x = 12 * 20

x = 12 * 4

x = 48

12 glasses -------  48 sec

?   glasses -------  44 sec

so 12 * 44 = x * 48

44 = x * 4

x = 44/4 = 11

x = 11

Answer:

12 - 48

11 - 44

Step-by-step explanation:

20 ÷ 5 = 4

12 · 4 = 48

44 ÷ 4 = 11

I hope this helps!

Answer:

We can conclude that someone used more tiles then the other because both equations are not equal.

Step-by-step explanation:

If you try to solve it both equations will not be shown as equal.

Answer:

C

Step-by-step explanation:

-5(x - 19) ≤ -6 + 2x                           Remove the brackets on the left

-5x +95 ≤ -6 +2x                             Add 5x to both sides.

95 ≤ -6 + 2x +5x                             combine

95 ≤ -6 + 7x                                    Add 6 to both sides

101 ≤ 7x                                           Divide by 7

101 /7 ≤ x                  

What you do next is both tricky and time consuming. You have to get x on the left and the fraction on the right. So subtract x from both sides. And subtract 101/7 from both sides. They both become minus.

101/7 - 101/7 ≤ -101/7 + x

0 ≤ -101/7+ x                                   Now subtract x from both sides

-x ≤ -101/7 + x -x

-x ≤  -101/7

Now comes the really nasty part. You have to get x > 0 and -101/7>0 That's easy enough. You just multiply both sides by -1

x ≤ 101/7

But when you do that (and this where you have to pay attention) the ≤ becomes ≥

x≥ 101/7

The expected number of a dataset is the mean of the dataset

The given parameters are:

[tex]\mathbf{n = 100}[/tex] --- sample size

[tex]\mathbf{r = 3}[/tex] --- selection of 3 people

(a) The expected number of birthdays

The probability of a having a birthday on a certain day is:

[tex]\mathbf{p = \frac{1}{365}}[/tex]

The probability of not having a birthday on the day is:

[tex]\mathbf{q = \frac{364}{365}}[/tex]

For a selection of 3 people in 100, the expected number of selection is:

[tex]\mathbf{E(x) =Days \times ^{100}C_3 \times p^3 \times q^{100 - 3}}[/tex]

So, we have:

[tex]\mathbf{E(x) = Days \times ^{100}C_3 \times \frac{1}{365}^3 \times \frac{364}{365}^{100 - 3}}[/tex]

Rewrite as:

[tex]\mathbf{E(x) =Days \times ^{100}C_3 \times \frac{1}{365}^3 \times \frac{364}{365}^{97}}[/tex]

There are 365 days in a year.

So, the expression becomes

[tex]\mathbf{E(x) =365\times ^{100}C_3 \times \frac{1}{365}^3 \times \frac{364}{365}^{97}}[/tex]

(b) Expected number of distinct birthdays

The probability that a person from the has his birthday on a certain day is:

[tex]\mathbf{p = 1 - (\frac{364}{365})^{100}}[/tex]

For 365 days, the expected number of distinct birthdays is:

[tex]\mathbf{E(x) = Days \times (1 - (\frac{364}{365})^{100})}[/tex]

There are 365 days in a year.

So, the expression becomes

[tex]\mathbf{E(x) = 365\times (1 - (\frac{364}{365})^{100})}[/tex]

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Answers:

Domain: all real numbers

Range: [tex]y \le 6[/tex]

Graph is below.

====================================================

Explanation:

This is a piecewise function that is composed of two parts:

This piecewise function has split identities or multiple aliases so to speak. It all depends on what the x input is.

The graph is shown below.

The domain is the set of all real numbers since any x value will lead to some y output. Even x = 0 itself is allowed. Note the arrows indicate the graph stretches on forever to the left and to the right.

The range on the other hand isn't all real numbers. Instead, it's [tex]y \le 6[/tex] indicating that y = 6 is the largest y can get. Simply locate the highest point on the graph (similar to the concept of the vertex) and you'll spot the highest y value.

Side notes:

Answer:

Rounded up percentages:

Corn: 15.65%

Green Beans: 16.52%

Tomatoes: 6.96%

Carrots: 13.04%

For exact percentages divide this with a calculator:

Corn: 360/2300

Green Beans: 380/2300

Tomatoes: 160/2300

Carrots: 300/2300

Answer:

Lea messed up on line one when you flip a fraction the exponents become negative hers haven't changed

Step-by-step explanation:

Answer: Input values are 8,-2,12,9, and 18, so select 9 and -2.

Answer:

40

Step-by-step explanation:

4x2=8

8x5=40

Answer:

Function: c = 2(m) + 5

A: Jason will spend $11 because 2(3) + 5 = (6 + 5) =11

B: No, because 2(7) + 5 = (14 + 5) = 19 and he only has 15 dollars.

Step-by-step explanation:

Cost = $2(the rate per mile) x (M)(miles driven) plus $5 (base cost)

For A and B I solved using the function.

Answer:

b) I think. sorry if its wrong.

Step-by-step explanation:

Answer:

increase

$750

y=750x+1000

Answer:

4 weeks

Step-by-step explanation:

Answer:

About 4 weeks

Step-by-step explanation:

Answer:

X= 65

Y= 120

Step-by-step explanation:

3y +235 = y-5

2y +235 = - 5

2y = 240

Y = 120

2x - 60 = x-5

X - 60 = - 5

X = 65

Answer: x=13/3

Step-by-step explanation:

Answer:  11/6 0r 1 5/6

Step-by-step explanation:

12x = 22

x = 22/12

x = 11/6 or 1 5/6

Answer:

Rate per day: 6 rooms

estimate: 6*5 = 30 rooms

Answer:

40cm :)

Step-by-step explanation:

Answer -162

Step-by-step explanation:

Answer:

=−162

Step-by-step explanation:

Answer:36

Step-by-step explanation:36÷ -4 = -9

The answer would be 36 which is 36÷ -4 = -9 after applying the arithmetic operation.

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has basic four operators that is +, -, ×, and ÷.

It is given that:

The quotient of a number and -4 is -9

Mathematically we can write:

x ÷ -4 = -9

x/(-4) = -9

x = 36

OR

36 ÷ -4 = -9

Thus, the answer would be 36 which is 36÷ -4 = -9 after applying the arithmetic operation.

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Answer:

14/15

Step-by-step explanation:

9/15+5/15=14/15

3/5+1/3

common denominator is 15 ( just think about the 3 times table and 5 times table )

5*3=15

3*5=15

Multiply the denominator and numerator by 3 for 3/5

Multiply the denominator and numerator by 5 for 1/3

(3)(3)/(5)(3) +(1)(5)/3(5)

9/15+5/15= 14/15

Answer : 14/15

Answer:

1

Step-by-step explanation:

Subsitute x and y:

x + y - 4

= 4 + 1 - 4

= 1

Answer:

30

Step-by-step explanation:

WE use permutation for this question:

since the letters in SQUARE are all distinct, so：

[tex]^{6}P_{2} = 6*5=30[/tex]

The number of ways of arranging 2 letters from the word S Q U A R E is given by A = 15 ways

The number of ways of selecting r objects from n unlike objects is given by combinations

ⁿCₓ = n! / ( ( n - x )! x! )

where

n = total number of objects

x = number of choosing objects from the set

Given data ,

Let the number of ways of arranging 2 letters from the word S Q U A R E be represented as A

Now , to select 2 letters from the 6 letters in the word SQUARE, without regard to order.

This is a combination problem, since the order in which we select the letters does not matter. Therefore, we can use the formula:

6 C 2 = 6! / 2!(6 - 2)!

= 6 x 5 / (2 x 1) x (4 x 3 / (2 x 1))

= 15

Hence , there are 15 ways to arrange 2 letters from the word SQUARE

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The midpoint of a segment divides the segment into equal halves

The given parameters are:

[tex]\mathbf{R =(24,0)}[/tex]

[tex]\mathbf{N =(12,18)}[/tex]

[tex]\mathbf{T =(12,6)}[/tex]

[tex]\mathbf{E =(18,15)}[/tex]

K is the midpoint of N and T.

So, we have:

[tex]\mathbf{K = (\frac{N_x + T_x}{2},\frac{N_y + T_y}{2})}[/tex]

This gives

[tex]\mathbf{K = (\frac{12 + 12}{2},\frac{18+ 6}{2})}[/tex]

[tex]\mathbf{K = (12,12)}[/tex]

E is the midpoint of T and I.

So, we have:

[tex]\mathbf{E = (\frac{I_x + T_x}{2},\frac{I_y + T_y}{2})}[/tex]

This gives

[tex]\mathbf{(18,15) = (\frac{I_x + 12}{2},\frac{I_y+ 6}{2})}[/tex]

Multiply through by 2

[tex]\mathbf{(36,30) = (I_x + 12,I_y+ 6)}[/tex]

By comparison

[tex]\mathbf{I_x + 12 = 36.\ I_y + 6 =30}[/tex]

So, we have:

[tex]\mathbf{I_x= 24.\ I_y =24}[/tex]

Hence, the coordinates of I are:

[tex]\mathbf{I = (24,24)}[/tex]

I is the midpoint of E and B.

So, we have:

[tex]\mathbf{I = (\frac{E_x + B_x}{2},\frac{E_y + B_y}{2})}[/tex]

This gives

[tex]\mathbf{(24,24) = (\frac{18 + B_x}{2},\frac{15 + B_y}{2})}[/tex]

Multiply through by 2

[tex]\mathbf{(48,48) = (18 + B_x,15 + B_y)}[/tex]

By comparison

[tex]\mathbf{18 + B_x = 48,\ 15 + B_y = 48 }[/tex]

So, we have:

[tex]\mathbf{B_x = 30,\ B_y = 33 }[/tex]

Hence, the coordinates of B are:

[tex]\mathbf{B = ( 30,33 )}[/tex]

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