The Image shows a magnetic field around the poles of a magnet. Identify the areas where the magnetic force is the strongest.
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The Image Shows A Magnetic Field Around The Poles Of A Magnet. Identify The Areas Where The Magnetic

Answers

Answer 1

Answer:

strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.

Explanation:

The lines of magnetic force are drawn so that the density of lines is proportional to the intensity of the magnetic field.

Therefore, the sections where the magnetic field is strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.


Related Questions

Helppp answer question pic in photo

Answers

Im pretty sure its wave D

if the dissipated power between a and b equal 210 watt then VB equal​

Answers

Answer:

correct answer is A

Explanation:

The diagram shows a series circuit with three resistors and two power sources.

In a series circuit the current through the entire circuit is constant and the resistance is the sum of the resistances in the circuit.

When the power sources are placed in opposite position the voltage between them is subtracted.

     

     V_b - 30 = I (10 + 4 + 6)

     V_b = I (20) - 30

      V_b = 30 - 2 20

       V_b = 10 V

the correct answer is A

The impact wrench consists of a slender 1-kg rod AB which is 580 mm long, and cylindrical end weights at A and B that each have a diameter of 20 mm and a mass of 1 kg. This assembly is free to turn about the handle and socket, which are attached to the lug nut on the wheel of a car. If the rod AB is given an angular velocity of 4 rad/s and it strikes the bracket C on the handle without rebounding, determine the angular impulse imparted to the lug nut.

Answers

Answer:

0.8324 kgm^2/s

Explanation:

Attached below is the detailed solution to the given problem

First step :

Calculate mass moment of Inertia of the section about the axle

I axle = 0.20813 kgm^2

next : apply the principle of Angular impulse and momentum to determine the angular impulse imparted to the lug nut

Angular impulse imparted to lug nut = 0.8324 kgm^2/s

A wheel rotating with a constant angular acceleration turns through 19 revolutions during a 3 s time interval. Its angular velocity at the end of this interval is 18 rad/s. What is the angular acceleration of the wheel? Note that the initial angular velocity is not zero. Answer in units of rad/s 2 .

Answers

Answer:

The magnitude of the angular acceleration of the wheel is 14.53 rad/s².

Explanation:

The angular acceleration can be found by using the following equation:

[tex] \omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \Delta \theta [/tex]  (1)

Where:

[tex] \omega_{f}[/tex]: is the final angular velocity = 18 rad/s

[tex]\omega_{0}[/tex]: is the initial angular velocity

α: is the angular acceleration =?

Δθ = 19 rev*(2π/1 rev) = 119.4 rad

The initial angular velocity can be found knowing that the wheel turns through 19 revolutions during a 3 s time interval:

[tex] \omega_{f} = \omega_{0} + \alpha t [/tex]

Where:  

t: is the time = 3 s

By solving the above equation for ω₀ we have:

[tex] \omega_{0} = \omega_{f} - \alpha t [/tex]   (2)

Now, by entering equation (2) into (1) we have:

[tex] \omega_{f}^{2} = (\omega_{f} - \alpha t)^{2} + 2\alpha \Delta \theta [/tex]                        

[tex] \omega_{f}^{2} = \omega_{f}^{2} - 2\omega_{f} \alpha t + (\alpha t)^{2} + 2\alpha \Delta \theta [/tex]                              

[tex](9\alpha)^{2} + 130.8 \alpha = 0[/tex]  

By solving the above equation for "α" we have:

α = -14.53    

The minus sign means that the wheel is decelerating.

Hence, the angular acceleration of the wheel is -14.53 rad/s².                                                                                            

I hope it helps you!

A bicycle rider pushes a 13kg bicycle up a steep hill. the incline is 24 degree and the road is 275m long. the rider pushes the bike parallel to the road with a force of 25N.
A. How much work does the rider do on the bike?
B. How much work is done by the force of gravity on the bike?

Answers

Answer:

A. W = 6875.0 J.

B. W = -14264.6 J.

Explanation:

A. The work done by the rider can be calculated by using the following equation:

[tex] W_{r} = |F_{r}|*|d|*cos(\theta_{1}) [/tex]

Where:                

[tex]F_{r}[/tex]: is the force done by the rider = 25 N

d: is the distance = 275 m

θ: is the angle between the applied force and the distance

Since the applied force is in the same direction of the motion, the angle is zero.

[tex] W_{r} = |F_{r}|*|d|*cos(0) = 25 N*275 m = 6875.0 J [/tex]

Hence, the rider does a work of 6875.0 J on the bike.

B. The work done by the force of gravity on the bike is the following:

[tex] W_{g} = |F_{g}|*|d|*cos(\theta_{2}) [/tex]  

The force of gravity is given by the weight of the bike.

[tex] F_{g} = -mgsin(24) [/tex]     

And the angle between the force of gravity and the direction of motion is 180°.

[tex] W_{g} = |mgsin(24)|*|d|*cos(\theta_{2}) [/tex]  

[tex] W_{g} = 13 kg*9.81 m/s^{2}*sin(24)*275 m*cos(180) = -14264.6 J [/tex]  

The minus sign is because the force of gravity is in the opposite direction to the motion direction.

Therefore, the magnitude of the work done by the force of gravity on the bike is 14264.6 J.  

I hope it helps you!                                                                                          

1.00 x 10^3 kg of clear liquid (specific heat
capacity = 5.11 x 10^2 J/kg-°C) at a temperature
of 15.0°C gains 3.33 x 10° J of heat. What is the
final temperature of the liquid? (Assume the
melting point is less than 15.0°C and the boiling
point is greater than 62.0°C.)

Answers

Answer:

15.00000652 °C

Explanation:

From the question,

Q = cm(t₂-t₁)................ Equation 1

Where Q = heat gained by the liquid, c = specific heat capacity of the liquid, m = mass of the liquid, t₁ = Initial Temperature of the liquid, t₂ = Final temperature of the liquid.

Given: Q = 3.33 J, c = 511 J/kg°C, m = 1000 kg, t₁ = 15°C

Substitute these values into equation 1 and solve for t₂

3.33 = 511×1000(t₂-15)

3.33 = 511000(t₂-15)

(t₂-15) = 3.33/511000

(t₂-15) = 0.0000065

t₂ = 15+ 0.0000065

t₂ = 15.00000652 °C

Electron spin: Radio astronomers can detect clouds of hydrogen too cool to radiate optical wavelengths of light by means of the 21 cm spectral line corresponding with the flipping of the electron in a hydrogen atom from having its spin parallel to the proton spin to having it antiparallel. From this wavelength, and thus E between states, find the magnetic field experienced by the electron in a hydrogen atom

Answers

Answer:

the magnetic field experienced by the electron is 0.0511 T

Explanation:

Given the data in the question;

Wavelength λ = 21 cm = 0.21 m

we know that Bohr magneton μ[tex]_B[/tex] is 9.27 × 10⁻²⁴ J/T

Plank's constant h is 6.626 × 10⁻³⁴ J.s

speed of light c = 3 × 10⁸ m/s

protein spin causes magnetic field in hydrogen atom.

so

Initial potential energy = -μ[tex]_B[/tex]B × cos0°

= -μ[tex]_B[/tex]B × 1

= -μ[tex]_B[/tex]B

Final potential energy = -μ[tex]_B[/tex]B × cos180°

= -μ[tex]_B[/tex]B × -1

= μ[tex]_B[/tex]B

so change in energy will be;

ΔE = μ[tex]_B[/tex]B - ( -μ[tex]_B[/tex]B )

ΔE = 2μ[tex]_B[/tex]B

now, difference in energy levels will be;

ΔE = hc/λ

2μ[tex]_B[/tex]B = hc/λ

2μ[tex]_B[/tex]Bλ = hc

B = hc /  2μ[tex]_B[/tex]λ

so we substitute

B = [(6.626 × 10⁻³⁴) × (3 × 10⁸)]  /  [2(9.27 × 10⁻²⁴) × 0.21 ]

B = [ 1.9878 × 10⁻²⁵ ]  /  [ 3.8934 × 10⁻²⁴ ]

B = 510556326.09

B = 0.0511 T

Therefore, the magnetic field experienced by the electron is 0.0511 T

d. What is the net force on the bowling ball rolling lane

Answers

Answer:

Friction.

Explanation:

3. At an early age, what happened to Cesar’s home?

Answers

Answer: He died later in 78 BC and was accorded a state funeral. Hearing of Sulla's death, Caesar felt safe enough to return to Rome. Lacking means since his inheritance was confiscated, he acquired a modest house in the Subura, a lower-class neighbourhood of Rome. hope this helps. Can u give me brainliest

Explanation:

A car, initially at rest, travels from 0 m/s to 17.7 m/s in 21.7 s. What is the car's acceleration?

Answers

A car, initially at rest, travels from 0 m/s to 17.7 m/s in 21.7 s. What is the car's acceleration? A Moving to the next question prevents changes to this answer.

HELP ME PLEASE <333, NUMBER 3 ONLY! ​

Answers

Answer:

b

Explanation:

is correct .....................

i think

1. If a spring has a spring constant of 2 N/m and it is stretched 5 cm, what is the force of
the spring?

Answers

DO NOT PRESS THE LINK IT IS GOING TO HACK YOU

According to Kepler's second law at the two shaded areas above are equal then...

A. it takes the same amount of time for planet A to travel between T1 and T2 as it does to travel between T3 and T4

B. Planet A will cause an eclipse on Planet B during those time intervals

C. it takes Planet A more time to travel between T1 and T2 as it does to travel between T3 and T4

D. it takes Planet A less time to travel between T1 and T2 as it does to travel between T3 and T4 ​

Answers

Answer:

A.  Kepler's second law says that the radius vector sweeps equal areas in             equal times.

A 1.4-cm-tall object is 22 cm to the left of a lens with a focal length of 11 cm . A second lens with a focal length of -5 cm is 37 cm to the right of the first lens.

Calculate the distance between the final image and the second lens.

Calculate the image height.

Answers

Answer:

can you explain yourself more please

Explanation:

large roll of fabric
Costume Rendering

Scissors

Pattern

Bolt

Answers

Answer:

Do we have to choose out of those three?

Explanation:

PLEASE HELP ME PLEASE! BRAINLEST ​

Answers

Answer:

10kg

Explanation:

Weight is "how much does gravity drag this down".

Mass is "how much matter is there here".

The relation is:

[tex]F_g = mg[/tex]

where [tex]F_g[/tex] is the weight, [tex]m[/tex] is the mass and [tex]g[/tex] is the gravitational acceleration (roughly equal to 10N/kg on Earth).

From the task we know that:

[tex]F_g = 100N\\g = 10\frac{N}{kg}[/tex]

So let's input it into the relation:

[tex]100N = m\cdot 10\frac{N}{kg}\\10N = m \cdot 1\frac{N}{kg}\\10N \cdot \frac{kg}{N} = m\\~\\m = 10kg[/tex]

A wheelbarrow full of bricks is lifted to the top of a wall. If the mass of the loaded wheelbarrow is 3000.0 g and the height of the wall is 0.45 meters, what is its GPE?

Answers

Answer:

the Gravitational potential energy is 13.23 J

Explanation:

The computation of the GPE is shown below:

GPE stands for Gravitational potential energy

The following formula should be used for the same

= mass × gravity × height

= 3000 g × 9.8m/sec^2 × 0.45 m

= 13.23 J

Hence, the Gravitational potential energy is 13.23 J

We simply applied the above formula so that we can easily determine the GPE

PLEASE HELP ME IN THE QUESTION ALSO!​

Answers

Answer:

467

Explanation:

The volumes of two bodies are measured to be

V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³. Calculate sum and difference in

volumes with error limits.​

Answers

Answer:

sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

Explanation:

Here,

V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³.

Now,

∆V = ± (∆V₁ + ∆V₂)

= ± (0.02 + 0.01) cm³

= ± 0.03 cm³

V₁ + V₂ = (10.2 + 6.4) cm³ = 16.6 cm³ and

V₁ - V₂ = (10.2 - 6.4) cm³ = 3.8 cm³

Thus, sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

-TheUnknownScientist

Answer:

I hope it's helpful .............

what is liang most likely trying to do

Answers

Answer:

Who is liang

Explanation:

i need more info if i'm going to help you out

He is most likely trying to figure out how to upload the picture to Brainly.

He knows that his question cannot be answered as long as nobody can see the picture.


3. A ball thrown vertically upward returns to its starting point in 4s. Find its initial speed. [4]

Answers

Answer:

9.8 ×4 equal 39.2 m/s This is v intial

4
What happens because the Earth's orbit
is NOT a perfect circle?
Help Resources
A. We are always the exact same distance away from the
Sun throughout the entire year.
B. At certain timesh during the year, we are closer to the Sun
than at other times.
C. The shape of Earth's orbit does not affect the distance
from the Sun.

Answers

The answer would be B because there is one point where the Earth is closest to the sun, and one point where the Earth is farthest from the sun because it’s not a perfect circle. Also, because the Earth orbit around the sun is an ellipse, the Earth cannot be always the same exact distance from the sun.

What would be a good reason to increase friction between surfaces? to allow objects to slide past each other easily to reduce wear and tear to provide traction so that slipping does not occur to avoid contact that results in increased temperature and overheating

Answers

Answer:

B to provide traction so that slipping does not occur

Explanation:

To increase friction between two surfaces, allow the objects to slide past each other thereby  force that is called friction.

What is friction?

Friction is  a type of force acting on an object to hinder its motion . It is negative by direction, since this force, hinder the motion of the object. Friction is also known as an opposing force because it always acts in the opposite direction of a moving or attempting to move body.

The virtue of friction causes a moving body to slow down. Friction is useful at times because it prevents car tires from skidding on the road and also allows us to walk on the pavement without slipping.

To increase friction , make an uneven, rugged, or sticky point of contact. When two or more bodies slide or rub against each other, three things can happen: small irregularities, nooks and crannies on the surfaces can catch on each other.

To find more on friction, refer here:

https://brainly.com/question/13000653

#SPJ2

You set a tuning fork into vibration at a frequency of 683 Hz and then drop it off the roof of the Physics building where the acceleration due to gravity is 9.80 m/s2. Determine how far the tuning fork has fallen when waves of frequency 657 Hz reach the release point

Answers

Answer:

The distance traveled by the tuning fork is 9.37 m

Explanation:

Given;

source frequency, [tex]f_s[/tex] = 683 Hz

observed frequency, [tex]f_o[/tex] = 657 Hz

The speed at which the tuning fork fell is calculated by applying Doppler effect formula;

[tex]f_o = f_s [\frac{v}{v + v_s} ][/tex]

where;

[tex]v[/tex] is speed of sound in air = 343 m/s

[tex]v_s[/tex] is the speed of the falling tuning fork

[tex]657 = 683[\frac{343}{343 + v_s} ]\\\\\frac{657}{683} = \frac{343}{343 + v_s}\\\\0.962 = \frac{343}{343 + v_s}\\\\0.962(343 + v_s) = 343\\\\343 + v_s = \frac{343}{0.962} \\\\343 + v_s = 356.55\\\\v_s = 356.55 - 343\\\\v_s = 13.55 \ m/s[/tex]

The distance traveled by the tuning fork is calculated by applying kinematic equation as follows;

[tex]v_s^2 = v_o^2 + 2gh[/tex]

where;

[tex]v_o[/tex] is the initial speed of the tuning fork = 0

g is acceleration due to gravity = 9.80 m/s²

[tex]v_s^2 = 0 + 2gh\\\\h = \frac{v_s^2}{2g} \\\\h = \frac{13.55^2 }{2\times 9.8} \\\\h = 9.37 \ m[/tex]

Therefore, the distance traveled by the tuning fork is 9.37 m

balance Al +N₂ --> AIN​

Answers

Answer:

[tex]2Al + N_{2} ==> 2AlN[/tex]

Explanation:

Answer pls quick or dont i dk what to say

Answers

Answer:

C!

Explanation:

Cold fronts generally advance at average speeds of 20 to 25 mph. toward the east — faster in the winter than summer — and are usually oriented along a northeast to southwest line.

Answer:

I think not sure B sorry if this is wrong yay if im right

Explanation:

What does the outer part of the disk turn into?

1) Planets and Moons

2) Interstellar Cloud

3) Planetary Nebula

4) It gets sucked into the star

Answers

Answer:

what does the outer part of the disk turn into

Explanation:

4) it gets sucked into the star

Which of the following is NOT a geological event caused by the movement of tectonic plates?
A) Sand Dunes
B) Mountain forming
C) Earthquakes
D) Volcanoes

Answers

The answer is A. Mountains form because tectonic plates overlap. Earthquakes form because of the moving of tectonic plates. The moving of tectonic plates causes holes in the crust so magma from the mantle escapes and erupts from volcanoes. I hope I helped!

In Milgram's experiment:

A. Yale University would not allow the experiment to be done.

B. participants overwhelmingly did not go all the way to 450 volts.

C. the "learner" was working with Milgram.

D. the "teacher" was working with Milgram.

Answers

Answer:

B. The "Learner" was working with Milgram.

Explanation:

just took the test

give brainliest, please. :)

State the collective name given to protons, neutrons in the nucleus of an atom.

2 Define the mass number.
3 An atom has atomic number of 28 and mass number of 64.
Find
1, Neutron number.
2, Proton number.

Answers

Answer: See explanation

Explanation:

1. The collective name given to protons, neutrons in the nucleus of an atom is referred to as the nucleon.

2. The mass number simply means the total number of both the protons and the neutrons that we have in a nucleus.

3. Atomic number = Protons = 28

Mass number = 64.

Neutron = Mass Number - Protons

Neutron = 64 - 28 = 36

4. The number of Protons is also the number of atomic number which is 28.

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