a serving of a particular fruit dessert contains 20.0 g of sugar. if all the sugar is sucrose, c12h22o11, how many molecules of sugar are present in this serving?
Taking into account the definition of Avogadro's number and molar mass, 3.49334×10²² molecules of sucrose are present.
Definition of molar massThe molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
Avogadro's NumberAvogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
Molecules of sugar in this caseIn first place, the molar mass of sucrose is 342 g/mole. So, you can apply the following rule of three: If by definition of molar mass 342 grams of the compound are contained in 1 mole, 20 grams of the compound are contained in how many moles?
[tex]amount of moles=\frac{20 gramsx1 mole}{342 grams}[/tex]
amount of moles= 0.058 moles
Now, considering the Avogadro's number, you can apply the following rule of three: If 1 mole of the compound contains 6.023×10²³ molecules, 0.058 moles contains how many molecules?
amount of moleculas= (6.023×10²³ molecules × 0.058 moles)÷ 1 mole
amount of molecules= 3.49334×10²² molecules
Finally, 3.49334×10²² molecules of sucrose are present.
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Avogadro's Number:
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How many grams Fe2O3 would be
required to make 187 g Fe?
Fe₂O3 + 3CO → 2Fe + 3CO₂
266.63g of Fe2O3 would be required to make 187 g Fe in accordance with the following equation: Fe₂O3 + 3CO → 2Fe + 3CO₂.
How to calculate mass?The mass of a product or reactant can be calculated using stoichiometry as follows:
According to this question, iron oxide reacts with carbon monoxide as follows:
Fe₂O3 + 3CO → 2Fe + 3CO₂
1 mole of Fe2O3 produces 2 moles of Fe
Moles of Fe = 187/56 = 3.34mol
3.34/2 = 1.67 moles of Fe2O3 will be required to produce 3.34 moles of Fe.
mass of Fe2O3 = 1.67 mol × 159.69 g/mol = 266.63g
Therefore, 266.63g of Fe2O3 would be required to make 187 g Fe in accordance with the following equation: Fe₂O3 + 3CO → 2Fe + 3CO₂.
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Hello can someone help me please and thanksss
the equation of the parabola is given as [tex]y = 1/4 (x-6)^2 +1[/tex]. D
How to find the parabolaGiven the focus(6,2) and the directrix, y = 0
Use the formula
[tex]\sqrt{(x-6)^{2} + (y-2)^{2} } }[/tex] = (y - 0)
Find the square of both sides, square root is removed from the side with it and square added on the other side
[tex](x-6)^2 + (y-2)^2 = (y- 0)^{2}[/tex]
Expand the expression and bring all terms to one side
[tex]x^{2} - 6x - 6x + 36 +y^{2} -2y- 2y +4[/tex] = [tex]y^{2} - 0[/tex]
Collect like terms
[tex]x^{2} - 12x -4y + 40 = 0[/tex]
Make 'y' the subject of the formula
[tex]4y = x^{2} - 12x + 40[/tex]
Divide through by 4 and substrate 4 from 40 to give a perfect quadratic equation
[tex]y = 1/4( x^{2} - 12x + 36) + 4[/tex]
1/4 is dividing the quadratic equation [tex]x^2 - 12x +36[/tex]
Then divide factor by 4 to give 1, this is so because of the nature of the options given
[tex]y = 1/4( x^{2} -6x -6x +36) + 1[/tex]
Simplify the expanded quadratic equation
[tex]y = x (x -6) - 6 (x- 6)[/tex], we have [tex](x - 6) ^2[/tex]
Then insert in place into previous equation
[tex]y = 1/4 (x-6)^2 + 1[/tex]
Thus, the equation of the parabola is given as [tex]y = 1/4 (x-6)^2 +1[/tex]
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pls help
1.
when a magnet spins within a coil of wires, what is produced?
-blue sparks
-glowing light
-nuclear energy
-an electric current
2.
when an electric current flows through a wire:
-a gravitational field is created around the wire
-the wire becomes very cold
-the wire begins to spin
-a magnetic field is created around the wire
help pls
Answer:
1d and 2d is the answer. Hope it helps
How many moles of na2so4 are present in 284.078 grams of na2so4?
a. 2
b. 3
c. 5
d. 6
Which are the two major greenhouse gases?
OA. CO₂ and CH4
OB. 0₂ and H₂0
OC. CH₂0 and CO
OD. NO and NO₂2
Answer:
A. CO2 and CH4
The two major greenhouse gases are CO₂ and CH₄ and the correct option is option A.
What are Greenhouse Gases?Greenhouse gases are gases in Earth’s atmosphere that trap heat. They let sunlight pass through the atmosphere, but they prevent the heat that the sunlight brings from leaving the atmosphere.
These gases have the property of absorbing infrared radiation (net heat energy) emitted from Earth’s surface and reradiating it back to Earth’s surface, thus contributing to the greenhouse effect.
Each of these gases can remain in the atmosphere for different amounts of time, ranging from a few years to thousands of years.
Examples of greenhouse gases are carbon dioxide, methane and water vapour.
Therefore, the two major greenhouse gases are CO₂ and CH₄ and the correct option is option A.
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what's the geometry of sp³ hybridization ~
Answer:
For sp3 hybridized central atoms the only possible molecular geometry is tetrahedral.
An electron on an energy level has an energy of 16.32 x 10−19 J. It moves to another level by absorbing 5.4 x 10−19 J of energy. Which of the following descriptions most likely explains what occurred?
The electron moved down to an energy level and has an energy of 10.92 x 10−19 J.
The electron moved down to an energy level and has an energy of 21.72 x 10−19 J.
The electron moved up to an energy level and has an energy of 10.92 x 10−19 J.
The electron moved up to an energy level and has an energy of 21.72 x 10−19 J.
Answer:
The electron moved up to an energy level and has an energy of 21.72 x 10−19 J.
Explanation:
i know
Answer:
D) The electron moved up to an energy level and has an energy of 21.72 x 10−19 J.
Explanation:
I took the test and got it right.
The energy produced by the snack in an experiment is calculated to be 41,800 J/g. What is the energy of the snack in Calories/
gram?
snack energy = [?] Cal/g or kcal/g
remember there are 4.18J per 1 calorie
The energy of the snack in calories per gram is 9983.3 Calories/gram.
What is the energy of a snack?The energy that is contained in a snack is obtained from a calorimeter when the snack is burnt in a calorimeter. The mass of the snack that is burnt is measured in terms of energy output of the calorimeter.
If 1 calorie = 4.18J
x calorie = 41,800 J
x = 41,800 J * 1 calorie/4.18J
x = 9983.3 Calories/gram
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Which of the following reactions depicts a decompostion reaction?
Answer:
B it is decomposition reaction
Explanation:
In decomposition reaction compound is broken into two or other elements
What is a spring tide? When and why does it occur?
A spring tide occurs when there is a new or full moon in the solar system.
What is Spring tide?This is the type of tide which occurs when the sun, moon and earth are in line and occurs between three to four times per year.
Lunar and solar tides also line up and reinforce each other to produce this type of tide.
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What is the noble gas configuration for tellurium (Te)?
The Periodic Table
OA. [Kr] 5s²4d105p4
O B. [Kr] 5s25p65d8
O C. [Xe] 5s25065
O D. [Xe] 5s24d1¹05p4
The correct answer to this question is option A.
The ideal gas law only approximates the behaviour of real gases. The conditions
under which the ideal gas law is MOST accurate are
a. Low pressure and high temperature
b. Low pressure and low temperature
c. High pressure and high temperature
d. High pressure and low temperature
which experimental technique was most likely used by the students to determine the rate of reaction?
The students can determine the rate of reaction by measuring change in concentration of reactant or product with time.
What is rate of reaction?The rate of a reaction is the rate at which reactant molecules are used up or the rate at which product molecules are formed.
The rate of a reaction can be determined by measuring the change in concentration of the reactant at each given time in a reaction.
The rate of reaction can be also be determined by measuring the change in concentration of the product at each given time in a reaction.
Therefore, the students can determine the rate of reaction by measuring change in concentration of reactant or product with time.
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would mean alot to help
Answer:
n
Explanation:
nobody knows
Answer: O
Explanation:
Out of the given elements, oxygen has the highest electronegativity.
When hydrated copper(II) sulfate crystals are heated, anhydrous copper(II) sulfate forms. A mass of 12.5 g of hydrated copper(II) sulfate crystals is heated in a crucible until all the water of crystallisation is removed.
A mass of 8.0 g of anhydrous copper(II) sulfate forms.
Calculate the formula of hydrated copper(II) sulfate CuSO4.nH2O
Show your working.
[Mr of CuSO4 = 159.5 Mr of H2O = 18]
Mass of water = g
Water of crystallization (n) =
Formula of hydrated copper(II) sulfate =
The formula of hydrated copper(II) sulfate is CuSO4.10H2O
What is the formula of the hydrated copper (ii) sulfate salt?The formula of the hydrated copper (ii) sulfate is determined as follows:
Mass of hydrated salt = 12.5 g
Mass of anhydrous salt = 8.0 g
Mass of water = 12.5 - 8 = 4.5 g
mole ratio of water and anhydrous salt is;
4.5/18 : 8.0/159.5
0.562 : 0.05
10 : 1
Water of crystallization (n) = 10.
Therefore, the formula of hydrated copper(II) sulfate is CuSO4.10H2O
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6. How many grams are present in 13.2 moles of O₂?
Answer:
422.3868 Grams
Explanation:
13.2 (MOLES) * 31.999 (Dioxygen's Molar Mass) = 422.3868 (Grams Present)
What are the environmental impacts of chemical industries using distillation to separate chemical solutions?
Answer:
The production process often produces offensive odours and may also create by-products that can contaminate air and ground water. Many industrial separation processes have requirements and consequences that influence where they are located.
Explanation:
hope it's helpful to you
A 250.ml sample of water was
boiled to 97.0°C then placed on
the counter to cool. If the water
cooled to11.0°C, how much heat
did it lose? Remember the
specific heat of water is 4.184
J/g°C.
Answer: The solubility of this gaseous solute will be,
Explanation :
First, we have to calculate the concentration of solute.
Now we have to calculate Henry's law constant.
Using Henry's law :
where,
C = concentration of solute =
p = partial pressure = 27.59 kPa
= Henry's law constant =?
Now put all the given values in the above formula, and we get:
Now we have to calculate the solubility of this gaseous solute when its pressure is 79.39 kPa.
Therefore, the solubility of this gaseous solute will be,
There are 4.9875 mol C, 7.9802 mol H,
and 2.00 mol O in the sample.
Divide each by the smallest number of
moles. What is the ratio for the C?
[?] C [ ]H[ ]0
Answer:
So, in 1 mol there are 6.02x10^23 atoms, regardless of the susbtance, only the weight of the mol changes. Doing a simple rule of 3 we can get many of the answers to your questions.
Explanation:
1mol of Ar → 6.02x10^23 atoms
0.25 mol → X
So now what we do is (0.25mol * 6.02x10^23 atoms)/1 mol = X
That gives us 1.505x10^23 atoms in 0.25 mol of Ar.
For this I'm guessing you mean the stable form of oxygen, O2. The Avogadro constant stays well, constant.
1 mol of O2 → 6.02x10^23 molecules
1.0×10^-4 mol of O2 → X molecules
So you can do (1.0×10^-4 * 6.02x10^23) / 1mol = X
(I feel like this is homework, so i will help you, but not give you all the answer, will be good practice to try yourself) :)
For this you need to know the weight of a mol of Be. Luckily the periodic table gives us that number. The number under each element is the weight in grams of 1 mol .
Answer:
C- 2.48925 H- 3.9901 O- 1
Explanation:
Read the instructions
Using a ph meter, you find the ph of an unknown solution to be 8. 0. How would you describe this solution?.
Answer:
Just Barely Base/Neutral
Explanation:
a pH of 8.0 is greater than Neutral (7.0) but is still neutral due to it being more neutral than a base
How many grams of nitrogen,
N2, would be required to create 9.3
moles ammonia, NH3?
Answer:
Explanation:
Hi there!
N₂+3H₂⇋2NH₃
The molecular mass of NH₃ is 34
The mass of N₂ is 28 and mass of H₂ is 2.
Then,
2 moles of NH₃ is created by 28 g of N₂
1 moles of NH₃ is created by 28/2 g of N₂
9.3g of NH₃ is created by (28/2)*9.3 moles of N₂
Therefore, 130.2 g of N₂ is required to create 9.3 moles of NH₃.
Hope it helps!
N₂+3H₂⇔2NH₃
moles N₂ = 1/2 x 9.3 = 4.65
mass N₂ = 4.65 x 28 g/mol = 130.2 g
Select the correct answer.
Which substance in this redox reaction is the oxidizing agent?
Cu + 2AgNO3 → 2Ag + Cu(NO3)2
A.
N
B.
AgNO3
C.
Cu
D.
NO3−
E.
Cu(NO3)2
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Post Test: Chemical Reactions
© 2022 Edmentum. All rights reserved.
Answer:
CU
Explanation:
Cu is the correct answer if I'm correct
how power station that produce electricity affect our environment what can we do to minimize these harmful effects?
Answer:
they help becuz they dont use any extra power and the are reneable
●
As a solution becomes more basic or alkaline, how does it affect the concentration of
H3O* and OH ions?
Calculate the bond length (in picometers) of a chemical bond between bromine and sulfur.
Bromine—atomic radius: 119 pm; covalent radius: 114 pm; ionic radius: 182 pm.
Sulfur—atomic radius: 109 pm; covalent radius: 102 pm; ionic radius: 184 pm.
The bond length of a chemical bond between bromine and sulfur is 216 picometers.
Explanation:Bromine and sulfur reacts with each other to form Sulfur dibromide.Sulfur dibromide is a covalent compound which means that a chemical bond exist between them is covalent bond.So, for finding a bond length of a covalently bonded compound we need to add the covalent radiuses of the two atoms.Given,
Covalent radius of bromine is 114 pm;
and covalent radius of sulfur is102 pm.
∴ Bond length of the sulfur dibromide= Covalent radius of bromine + covalent radius of sulfur
∴ Bond length = 114 + 102
∴ Bond length = 216 pm.
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Which are correct statements about the emission spectrum of hydrogen in the visible region
The statement that is correct about the emission spectrum of hydrogen in the visible region is that the line corresponding to the greatest emission of energy is in the ultraviolet region.
What is hydrogen spectrum?Hydrogen spectrum is defined as the dissociation of hydrogen atom upon action of electric current into spectral lines that can be seen in that visible light.
These lines falls under the electromagnetic wave of ultraviolet and infrared regions. But the lines of greatest emission is found in the ultraviolet region.
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How many moles of fluorine atoms are in a sample of fluorine that contains 7.45 x 10^24 fluorine atoms? (Report your answer to one place past the decimal point.
Based on the calculations, the number of moles of fluorine atoms present is equal to 12.4 moles.
How to calculate the moles of fluorine atoms?In order to determine the number of moles of fluorine atoms, we would calculate the number of atoms in 1 mole of an fluorine atoms in accordance with Avogadro's constant.
1 mole of fluorine atom = 6.02 × 10²³ molecules
X moles of fluorine atom = 7.45 × 10²⁴ molecules
Cross-multiplying, we have:
X = 7.45 × 10²⁴/6.02 × 10²³
X = 12.4 moles.
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The liquids having same boiling point cannot be seperated from its mixture by distillation, why?
Answer:
Explanation:
They cannot be separated by distillation since it depends on a liquid's ability to boil at a certain temperature. If you have two liquids with the same boiling temperatures, the proportion of each in the vapor phase will be about equal, making it impossible to separate them. Although they presumably do not have the same freezing point, you might use a different method like chromatography or work with their freezing points instead. You could then selectively crystallize one component while leaving the other as a pure liquid.
____________
Definitions:
Distillation:
#1: The volatilization or evaporation and subsequent condensation of a liquid, as when water is boiled in a retort and then the steam is condensed in a cool receiver.
Answer:
Because different compounds often have different boiling points, the components often separate from a mixture when the mixture is distilled. The boiling point is the temperature at which the vapor pressure of the liquid phase of a compound equals the external pressure acting on the surface of the liquid.
Explanation:
When 4 mol of glucose is fermented, a mass of 55.2 g of ethanol is produced. Show that the percentage yield of ethanol is 15%
(Mr of C2H5OH = 45)
Theoretical yield =0.15 g
% yield = 15%
reaction
C6H12O6 → 2C2H5OH + 2CO2
from above reaction, we get to know that,
1 mole of glucose → 2 mole ethanol
for 4 mole of glucose → 8 mole of ethanol
\frac{55.2}{8(46)} = yield of ethanol
yield of ethanol = 0.15g
% yield = (experimental/theoretical )*100
% yield of ethanol = 0.15 x 100 =15%
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