The graphs of the functions f (x) = 2x+ 7 and g(x) = x2 -1 intersect in t
xy-coordinate plane. What are the points of intersection?

Answers

Answer 1

Answer:

See below

Step-by-step explanation:

This is a line and a parabola......where they intersect the two equations are      equal :

2x+7 = x^2 - 1

x^2 - 2x -8 = 0

(x-4)(x+2) = 0         shows the x-coordinate for intersections at x = 4 and -2

sub these x values into one of the equations to calculate the y coordinate

 y = 2(4) + 7 = 15      so one point is  4,15

y = 2(-2) + 7 = 3      the other point is then  -2, 3


Related Questions

(9x + 1) − (−7x² + 4x + 10)

Answers

Answer:

7x² + 5x - 9

Step-by-step explanation:

(9x + 1) - (- 7x² + 4x + 10) ← distribute parenthesis by - 1

= 9x + 1 + 7x² - 4x - 10 ← collect like terms

= 7x² + 5x - 9

Need help simple explanation if possible

Answers

that’s correct answer is person is correct above

Answer: 21 sqrt(43)/43

Step-by-step explanation: The tangent identity states that tanx = sinx/cosx. Thus, we get 21/22 / sqrt(43)/22. We can simplify this to 21 sqrt(43)/43

Please mark my answer as brainliest if this helped you.

what are the pair of intergers whose product is -12

Answers

Answer:

The answer is -4×3 or -3×4 or -6×2 or -2×6 or -1×12 or -12×1

Step-by-step explanation:

Josh and Bella picked apples from a tree. Josh had 3 less than 2/3 of Bellas apples. If Josh had 7 apples, how many apples did Bella have?

Answers

Answer:

Bella had 15 apples

Step-by-step explanation:

First, you see that Josh has 3 less than 2/3 of Bellas apples. If Josh has 7 apples you would add 3 to 7 which = 10. Assuming that 10 = 2/3 of Bellas apples, then you would subtract half of 10 and get 5. 1/3 = 5 apples. Lastly, you should do 5 * 3 which = 15. Bella had 15 apples.

anwer this question with full method please​

Answers

Step-by-step explanation:

Let simplify the identity

[tex] \frac{ \csc {}^{2} (x) - \sec {}^{2} (x) }{ \csc {}^{2} (x) + \sec {}^{2} (x) } [/tex]

[tex] \frac{ \frac{1}{ \sin {}^{2} (x) } - \frac{1}{ \cos {}^{2} (x) } }{ \frac{1}{ \sin {}^{2} (x) } + \frac{1}{ \cos {}^{2} (x) } } [/tex]

Combine Like Fractions

[tex] \frac{ \frac{ \cos {}^{2} (x) - \sin {}^{2} (x) }{ \sin {}^{2} (x) \cos {}^{2} (x) } }{ \frac{ \sin {}^{2} (x) + \cos {}^{2} (x) }{ \cos {}^{2} (x) \sin {}^{2} (x) } } [/tex]

Multiply by reciprocals.

[tex] \frac{ \cos {}^{2} (x) - \sin {}^{2} (x) }{ \sin {}^{2} (x) \cos {}^{2} (x) } \times \frac{ \cos {}^{2} (x) \sin {}^{2} (x) }{ \sin {}^{2} (x) + \cos {}^{2} (x) } [/tex]

Pythagorean Identity

[tex] \frac{ \cos {}^{2} (x) - \sin {}^{2} (x) }{1} [/tex]

Double Angle Identity

[tex] \frac{ \cos(2x) }{1} [/tex]

[tex] \cos(2x) [/tex]

Now, we need to find cos 2x. Given that we have tan x.

Note that

[tex] \cos {}^{2} (x) - \sin {}^{2} (x) = \cos(2x) [/tex]

So let find cos x and tan x.

We know that

[tex] \tan(x) = \frac{ \sin(x) }{ \cos(x) } [/tex]

We know that

[tex] \tan(x) = \frac{o}{a} [/tex]

[tex] \sin(x) = \frac{o}{h} [/tex]

[tex] \cos(x) = \frac{a}{h} [/tex]

So naturally,

[tex] \tan(x) = \frac{ \frac{o}{h} }{ \frac{a}{h} } = \frac{o}{a} [/tex]

So we need to find the hypotenuse,

remember Pythagorean theorem.

[tex]h {}^{2} = {o}^{2} + {a}^{2} [/tex]

Here o is 1

h is root of 5.

So

[tex] {h}^{2} = {1}^{2} + ( \sqrt{5} ) {}^{2} [/tex]

[tex] {h}^{2} = 1 + 5[/tex]

[tex] {h}^{2} = 6[/tex]

[tex]h = \sqrt{6} [/tex]

Now, we know h, let plug in to find sin x and cos x.

[tex] \sin(x) = \frac{1}{ \sqrt{6} } [/tex]

[tex] \cos(x) = \frac{ \sqrt{5} }{ \sqrt{6} } [/tex]

Let's find these values squared

[tex] \sin {}^{2} (x) = \frac{1}{6} [/tex]

[tex] \cos {}^{2} (x) = \frac{5}{6} [/tex]

Finally, use the trig identity

[tex] \frac{5}{6} - \frac{1}{6} = \frac{2}{3} [/tex]

So part I.= 2/3

ii. Use the definition of sine and cosine and Pythagorean theorem

Let sin x= o/h

Let cos x= a/h.

So

sin x squared is

[tex] \sin {}^{2} (x) = \frac{o {}^{2} }{h {}^{2} } [/tex]

[tex] \cos {}^{2} (x) = \frac{ {a}^{2} }{h {}^{2} } [/tex]

By definition,

[tex] \frac{ {o}^{2} }{ {h}^{2} } + \frac{ {a}^{2} }{h {}^{2} } = 1[/tex]

[tex] \frac{ {o}^{2} + a {}^{2} }{h {}^{2} } = 1[/tex]

Remember that

[tex]{ {o}^{2} + {a}^{2} } = {h}^{2} [/tex]

So

[tex] \frac{ {h}^{2} }{h {}^{2} } = 1[/tex]

[tex]1 = 1[/tex]

Determine which sequences of transformations could be applied to the parent function f(x) = x to obtain the graph of g.

Answers

Answer:

Reflect over the y-axis, vertically stretch by a factor of 3, and then shift down 1 unit

Step-by-step explanation:

Parent function:  [tex]f(x)=x[/tex]

The graph of the parent function is a straight line graph that intersects the axes at the origin (0, 0) and has a positive slope of 1 unit.

To determine the sequence of transformations, find the equation of the transformed function in slope--intercept form.

Slope-intercept form of a linear function:  [tex]f(x)=mx+b[/tex]

(where m is the slope and b is the y-intercept)

To calculate the slope of the transformed function, choose two points on the line and use the slope formula:

Let (x₁, y₁) = (0, -1)Let (x₂, y₂) = (1, -4)

[tex]\implies \sf slope\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-4-(-1)}{1-0}=-3[/tex]

The y-intercept (where the line crosses the y-axis) of the transformed function is (0, -1).

Therefore the equation of the transformed function is:

[tex]g(x)=-3x-1[/tex]

Translations

For a > 0

[tex]f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}[/tex]

[tex]f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}[/tex]

[tex]f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}[/tex]

[tex]f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}[/tex]

[tex]y=a\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis (vertically) by a factor of}\:a[/tex]

[tex]y=f(ax) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{a}[/tex]

[tex]y=-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}[/tex]

[tex]y=f(-x) \implies f(x) \: \textsf{reflected in the} \: y \textsf{-axis}[/tex]

Comparing the transformed function's equation with the parent function:

[tex]\begin{cases}f(x)=x\\g(x)=-3x-1\end{cases}[/tex]

Transformations

1.  Reflection in the y-axis:

    [tex]f(-x)=-x[/tex]

2.  Vertically stretched by a factor of 3:

    [tex]3f(-x)=-3x[/tex]

3.  Shifted 1 unit down:

    [tex]3f(-x)-1=-3x-1[/tex]

Summary

Reflect over the y-axis, vertically stretch by a factor of 3, and then shift down 1 unit

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Consider the function given below. f(x)=x Plot the x- and y- intercepts of the function.

Answers

jdjxnz an
ensueñan dhsjJnw shi na wuxi whzizja akmA

Question 7 of 25
If f(x)=6x²,-4 and g(x)=2x+2, find (f- g)(x).
OA. 2x-5x2-2
OB. 6x²-2x-6
OC. 4x²-6
O D. 6x²2-2x-2

Answers

Answer:

x2

Step-by-step explanation:

x2

what is the factor expression of x2 + 7x + 10

Answers

Answer:

[tex](x+5)(x+2)[/tex]

Step-by-step explanation:

[tex]\textbf{Given that,}\\\\~~~~x^2 +7x +10\\\\=x^2 +5x +2x +10~~~~~~~~~~~~~~~~~~~~;\textbf{Rewrite}~ 7x ~ \textbf{as}~ 5x +2x\\\\=x(x+5) +2(x+5)\\\\=(x+5)(x+2)~~~~~~~~~~~~~~~~~~~~~~~~~;\textbf{Take out the common factor}~ x+5[/tex]

Find the difference quotient f(x)−(3)−3 when ()=1+4−5^2. Simplify the expression fully as if you were going to compute the limit as →3. In particular, cancel common factors of −3 in the numerator and denominator if possible. (Use symbolic notation and fractions where needed.)

Answers

The difference quotient of the expression will be 4.

How to find the quotient?

f(x) = 5 + 5x + 4x²

f(3) = 5 + 5(3) + 4(3)³

= 56

Now [f(x) - f(3)]/(x - 3) will be:

= (4x² + 5x + 5 - 56)/(x - 3)

= (4x² + 5x - 51)/(x - 3)

= (4x² + 17x - 12x - 5)/(x - 3)

= (4x + 17)(x - 3)/(x - 3)

= 4x + 17

The difference quotient will be:

g(x + h) = 4(x + h) + 17

= [g(x + h) - g(x)]/h

= (4x + 4h + 17 - 4x - 17)/h

= 4h/h

= 4

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Which graph represents the function h(x) = |x| + 0.5?

On a coordinate plane, an absolute value graph has a vertex at (0, 1.5).

On a coordinate plane, an absolute value graph has a vertex at (negative 0.5, 0).

On a coordinate plane, an absolute value graph has a vertex at (0, 0.5).

On a coordinate plane, an absolute value graph has a vertex at (negative 1.5, 0).

Answers

Answer:

On a coordinate plane, an absolute value graph has a vertex at (0, 0.5).

Step-by-step explanation:

properties of the given function

domain=X€Rrange=[1/2,+♾️)minimum (0,1/2)

Answer: it's the second option

Step-by-step explanation:

Question 10(Multiple Choice Worth 1 points)
(04.02 LC)
Solve the system of equations using substitution.
y = -2x + 1
4x + 2y = -3

Answers

Answer:

no solutions

Step-by-step explanation:

[tex]4x + 2(-2x+1) = -3\\4x-4x+2 = -3\\2 = -3\\[/tex]

this means there are no solutions.

What is the answer?????

Answers

Answer:

36.7075 Hz is the answer

what is the value of k such that x-2y=5 and 4x+ky=3 are perpendicular?

Answers

Answer:

k= -4/3

Step-by-step explanation:

Solve for x (12x-7)/4=(5x+18)/3

Answers

Answer:

x = 5.81

Step-by-step explanation:

3(12x-7) = 4(5x+18)

36x-21 = 20x +72

16x = 93

x = 5.81

In 20 years charlie will be three times as old as he is now.how old is charlie is he now

Answers

Answer:

10 years old

Step-by-step explanation:

let his age be x , then in 20 years

x + 20 = 3x ( subtract x from both sides )

20 = 2x ( divide both sides by 2 )

10 = x

Charlie is 10 years old

If f(x) = 2x² + 3x and g(x)= x - 2, what is (f+ g)(2)?

Answers

Answer:

14.

Step-by-step explanation:

If f(x) = 2x2 + 3x and g(x) = x - 2, (f + g)(2) is 14.

Answer:

14

Step-by-step explanation:

f(x) = 2x² + 3x

f(2) = 2 * 2^2 + 3(2) = 2*4 + 6 = 8+6 = 14

g(x)= x - 2

g(2) = 2-2 = 0

(f+ g)(2) = 14+0 = 14

What can be concluded if ÐABC and ÐCBD are a linear pair? Select all statements that you think are correct.

Answers

If ÐABC and ÐCBD are a linear pair, then it means that their sum is 180°.

What is Linear pair of angles?

Linear pair of angles are angles formed when two lines intersect each other at a single point.

Now, the angles are also said to be linear if they are adjacent to each other after the intersection of the two lines and the sum of the linear pair of angles is always equal to 180°.

Looking at the definition above we can say that if ÐABC and ÐCBD are a linear pair, then it means that their sum is 180°.

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Need help urgently please

Answers

L is Y=4
M is Y=-2x+4
N is Y=x-1
P is X= -4

A foam cylinder, with a diameter of 3 inches in height of 8 inches, is carved into the shape of a cone. What is the maximum volume of a cone that can be carved? Round your answer to the nearest hundredths place. One point

Answers

Answer:

volume of cone = 1/3 volume of cylinder

according to the question, volume of cylinder =

V =

[tex]\pi \times (r) {}^{2} h[/tex]

diameter = 3 inches

radius = 3/2 inches

height = 8 inches

V = 22.7 * (3/2)²* 8

V = 22.7 * 9/4 * 8

V = 22.7 * 18

maximum volume a cone can have = 1/3 of cylinder

Volume of cone = 1/3 * 22.7 * 18

= 22.7 * 6

= 132.6

___________is a relation in which each element of the domain is paired with exactly one element of the range.

Answers

Answer:

A function

Step-by-step explanation:

A function is a relation in which each element of the domain is paired with exactly one element of the range.

What is the intersection of line CA a and line XA?

Answers

Answer:

point A is the intersection point between XA and AC

Which expression is equivalent to 3√64ab²c³?
2abc²[√4a²b³c]
4a²b²c³ (3√5)
8a³b³c¹ (3√/bc)
8a²b²c³(3√/b)

Answers

Answer:

[tex]4a^2b^2c^3\left(\sqrt[3]{b}\right)[/tex]

Step-by-step explanation:

**Please note that the expression quoted in the question is likely incorrect (see attachment)**

Assuming the expression is:

[tex]\sqrt[3]{64a^6b^7c^9}[/tex]

[tex]\textsf{Apply radical rule} \quad \sqrt{ab}=\sqrt{a}{ \cdot \sqrt{b}[/tex]

[tex]\implies \sqrt[3]{64} \cdot \sqrt[3]{a^6}\cdot \sqrt[3]{b^7}\cdot \sqrt[3]{c^9}[/tex]

Rewrite 64 as 4³:

[tex]\implies \sqrt[3]{4^3} \cdot \sqrt[3]{a^6}\cdot \sqrt[3]{b^7}\cdot \sqrt[3]{c^9}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \sf to\:\:b^7[/tex]

[tex]\implies b^7=b^{6+1}=b^6b^1=b^6b[/tex]

Therefore:

[tex]\implies \sqrt[3]{4^3} \cdot \sqrt[3]{a^6}\cdot \sqrt[3]{b^{6}b}\cdot \sqrt[3]{c^9}[/tex]

[tex]\implies \sqrt[3]{4^3} \cdot \sqrt[3]{a^6}\cdot \sqrt[3]{b^{6}}\cdot \sqrt[3]{b}\cdot \sqrt[3]{c^9}[/tex]

[tex]\textsf{Apply exponent rule} \quad \sqrt[n]{a^m}=a^{\frac{m}{n}}[/tex]

[tex]\implies 4^{\frac{3}{3}} \cdot a^{\frac{6}{3}} \cdot b^{\frac{6}{3}} \cdot \sqrt[3]{b} \cdot c^{\frac{9}{3}}[/tex]

Simplify:

[tex]\implies 4^1 \cdot a^2 \cdot b^2 \cdot \sqrt[3]{b} \cdot c^3[/tex]

[tex]\implies 4a^2b^2c^3\left(\sqrt[3]{b}\right)[/tex]

³√64ab²c³√4³ab²c³4c√a^{2/3}b^{2/3}

The expression is seemed to have none of the above solutions

help honestly MARKING BRAINLIESt

Answers

Answer:

See below ~

Step-by-step explanation:

a) Forming the equation :

⇒ We start with a number, x

⇒ Now we double it so : 2(x) = 2x

⇒ Then we add 11 to it : 2x + (11) = 2x + 11

⇒ It is equal to 25 : 2x + 11 = 25

b) Solving the equation :

Subtract 11 from both sides :

⇒ 2x + 11 - 11 = 25 - 11

⇒ 2x = 14

Divide 2 on both sides :

⇒ 2x/2 = 14/2

x = 7

Let unknown number be x

Double it

2x

Add eleven

2x+11

You got 25

2x+11=25

Lets solve the equation

2x=25-112x=14x=7

Angle AMO is 50 degrees. If ray MB bisects angle AMO, what would be the measure of angle AMB?​

Answers

The answer I’m guessing would be 25 since it’s bisecting the angle in the middle

The graph of F(x), shown below, resembles the graph of G(x)= x², but it has
been changed somewhat. Which of the following could be the equation of
F(x)?
A. F(x) = 3(x+4)2 +4
B. F(x)=3(x-4)2 - 4
C. F(x)=-3(x+4)² +4
D. F(x) = -3(x-4)² +4

Answers

The equation of the function is  F(x) = -3(x-4)² +4 , the correct answer is Option D

The missing graph is attached with the answer

What is a function ?

A function is a law that relate the independent variable and the dependent variable.

It is given that

The graph of F(x), shown below, resembles the graph of G(x)= x², but it has been changed

From the graph, it is seen that,

G(x) when shifted by -4 on the negative x axis.

and graph shifted by +4 on the positive y axis.

F(x) is scaled by a factor of -⅓ of G(x)

it is reflected across the x-axis.

So the equation of the function is

F(x) = -3(x-4)² +4

Therefore ,  the correct answer is Option D.

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Find the equation of a circle with a center at (1, 4) where a point on the circle is (4, 8). ( x - 1) 2 + ( y - 4) 2 = 25 ( x - 4) 2 + ( y - 1) 2 = 25 ( x - 1) 2 + ( y - 4) 2 = 5

Answers

Answer:

 (x-1)^4    +  (y-4)^2  = 25

Step-by-step explanation:

Center at 1,4 means the circle is of the form:

   (x-1)^4    +  (y-4)^2  = r^2

Find r^2 using distance formula from center to the given point

 r ^2 = ( 8-4)^2 + (4-1)^2

 r^2 = 16 +9 = 25

so you answer is      (x-4)^4    +  (y-8)^2  = 25

When Manny goes on vacation, he boards his dog at a kennel. The kennel charges a flat fee
of $25, plus $15.50 per night.
Write an equation that shows how the cost of a kennel stay, y, depends on the number of
nights, x.

Answers

Step-by-step explanation:

y = 25 + 15.5x

it's $25 plus the number of nights times $15.5 per night

R is the midpoint of QS. If QR = 7x and QS = 15x − 7, what is QR?

Answers

Answer: 49

Step-by-step explanation:

If R is the midpoint of QS, QS=2(QR)=2(RS).

[tex]15x-7=2(7x)\\15x-7=14x\\-7=-x\\\\x=7\\\\QR=7(7)=\boxed{49}[/tex]

If side c measures 32.3 units long, how long is side a?

Answers

Answer:

16.15

Step-by-step explanation:

sin(30) = a / c

a = c * sin(30)

a = 32.3 * 0.5

a = 16.15

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