The graph shows f(x) and its transformation g(x).


Enter the equation for g(x) in the box.

C) The probability that you pick at least one purple marble is 98%.

The question is incomplete, since the number of marbles of each color in the bag is missing: 3 blue, 5 green, and 2 purple marbles.

Now, to answer the questions, the following calculations must be done:

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Answer:C) The probability that you pick at least one purple marble is 98%.

Step-by-step explanation:

Answer:

([tex]\frac{7}{2}[/tex],[tex]\frac{1}{2}[/tex])

Step-by-step explanation:

For this you use the midpoint formula

[tex](\frac{x_{2} +x_{1} }{2} ,\frac{y_{2} +y_{1} }{2} )[/tex]

the points would be (2,1) and (5,2)

The midpoint would be ([tex]\frac{7}{2}[/tex],[tex]\frac{1}{2}[/tex])

Answer:

Greatest number which divides 6168 is 3084,the greatest number which divides 2447 is1223.5 , and the greatest number which divides 3118 is 1559.

Answer:

[tex] - \frac{1}{6} [/tex]

Step-by-step explanation:

Using the slope formula:

[tex] \frac{ - 1 - 0}{0 - ( - 6)} = - \frac{1}{6} [/tex]

Five number summary and IQR of both the data sets are different.

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Part A:

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set into four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

The interquartile range of the data is

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

[tex]IQR=Q_3-Q_1\\ =Q_3-Q_1\\ =16-6.2\\ =9.5[/tex]

The interquartile range of the data is

[tex]IQR=Q_3-Q_1\\ =Q_3-Q_1\\ =15.5-8\\ =7.5[/tex]

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data sets are different.

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The solution of the given expression is 9. So the correct answer is option B.

The complete question is given below:-

(√16 - √49 )² The solution of the given equation will be

A. 16

B .9

C .49

D. 316

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

The given expression will be calculated as:-

(√16 -√49 )² = (√16)² -2 (√16)(√46) + (√49 )²

                    = ( 16 - 2(4)(7) + 49 )

                    = ( 16 - 56 + 49 )

                    = 9

Therefore the solution of the given expression is 9. So the correct answer is option B.

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D. 9.5 cm

To find the perimeter you need to add all the sides.

2.1 + 2.1 + 1 + 3.3 + 1 = 9.5

Answer:

it depends on which state your in or in your even in the us usually it is either 6% or 4% some times more or less % so im going to do both

50*0.06=53

50*0.04=52

Hope This Helps!!!

The question is incomplete. Below you will find the missing content in the figure.

Prove: m/EIF = m/GIH

Step                                                                    Reason

m∠EIF+m∠FIG = 180°

m∠FIG+m∠GIH= 180°

m∠EIF+m∠FIG= m∠FIG+m∠GIH

m∠EIF = m∠GIH

The figure is shown below.

The correct answer is m∠EIF = m∠GIH

Here lines FH and GE intersect each other at the point I.

we have to prove the angle

m∠EIF = m∠GIH

so,

m∠EIF+m∠FIG = 180° as angels ∠EIF and ∠FIG forming a linear pair summing up to 180°. angels ∠EIF and ∠FIG form straight angels on a line EG.

m∠FIG+m∠GIH= 180° as angels ∠FIG and ∠GIH forming a linear pair summing up to 180°. angels ∠FIG and ∠GIH form straight angels on a line FH.

m∠EIF+m∠FIG= m∠FIG+m∠GIH because of the substitution property of equality. we replace 180° by m∠FIG+m∠GIH.

m∠EIF = m∠GIH because of the subtraction property of equality. We can subtract the same elements from both sides by the subtraction property of equality.

Therefore m∠EIF = m∠GIH.

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f(x) is a linear function, so both the domain and the range are the set of real numbers.

The monthly payment for purchasing the home will be $457.85.

The term loan refers to a sort of credit vehicle in which a sum of money is lent to another party in exchange for the value or principal amount being repaid in the future.

Then the formula of monthly payment (MP) will be

[tex]\rm MP = P \times \dfrac{r(1+r)^n}{(1+r)^n - 1}\\[/tex]

In order to purchase a home, a family borrows $110,000 at 2.9% for 30 years.

We have

P = $110,000

r = 0.029 / 12 = 0.0024

n = 30 × 12 = 360

Then the monthly payment will be

[tex]\rm MP = 110,000\times \dfrac{0.0024(1+0.0024)^{360}}{(1+0.0024)^{360} - 1}\\\\[/tex]

On further solving, we have

MP = 110000 × 0.0024 × 1.723

MP = $ 457.85

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Answer:

1/4 + x = (-5)/4

x = -5/4 - 1/4

x = (-5)-1 /4

x = (-6)/4

Answer:

y = 5 and y = 1

Step-by-step explanation:

[tex]\textsc {Subtract 7 from each side :}[/tex]

⇒ (3y - 2)² + 7 - 7 = 43 - 7

⇒ (3y - 2)² = 36

[tex]\textsc {take the square root on each side :}[/tex]

⇒ √(3y - 9)² = √36

⇒ 3y - 9 = ±6

[tex]\textsc {When equal to +6, add 9 on each side :}[/tex]

⇒ 3y - 9 + 9 = 6 + 9

⇒ 3y = 15

[tex]\textsc {Divide by 3 on each side :}[/tex]

⇒ 3y/3 = 15/3

⇒ y = 5

[tex]\textsc {When equal to -6, add 9 on each side :}[/tex]

⇒ 3y - 9 + 9 = -6 + 9

⇒ 3y = 3

[tex]\textsc {Divide by 3 on each side :}[/tex]

⇒ 3y/3 = 3/3

⇒ y = 1

[tex]{\huge \underline{{ \fbox \color{red}{A}}{\fbox \color{green}{n}}{\fbox \color{purple}{s}}{\fbox \color{brown}{w}}{\fbox \color{yellow}{e}}{\fbox \color{gray}{r } }}}[/tex]

Answer :- The result is 5cm

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\bf \red {c {}^{2} = a {}^{2} + b {}^{2}} }[/tex]

[tex] \: \: \: \: \: \: \boxed{ \bf \green{c {}^{2} = (3cm) {}^{2} + (4cm) {}^{2}}}[/tex]

[tex] \: \: \: \: \: \: \: \: \boxed{ \bf \gray{c {}^{2} = 9cm {}^{2} + 16cm {}^{2} }}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \bf \blue {c {}^{2} = 25cm {}^{2} }}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \bf \green{\not{\sqrt {c {}^{ \not{2} }}} = \sqrt{25cm {}^{2} }}}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \bf \red{c = 5cm}}[/tex]

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: hypotenuse = 5 \:\:cm [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex] \textsf{Pythagoras Theorem } [/tex]

[tex]\qquad \tt \rightarrow \: h {}^{2} = p {}^{2} + b {}^{2} [/tex]

[ h = hypotenuse, p = perpendicular and b = base ]

[tex]\qquad \tt \rightarrow \: {h}^{2} = {3}^{2} + {4}^{2} [/tex]

[tex]\qquad \tt \rightarrow \: {h}^{2} = 9 + 16[/tex]

[tex]\qquad \tt \rightarrow \: h {}^{2} = 25[/tex]

[tex]\qquad \tt \rightarrow \: h = \sqrt{25} [/tex]

[tex]\qquad \tt \rightarrow \: h = 5 \: \: cm[/tex]

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Answer:

0.2   [or 2/10    ;     or 1/5]

Step-by-step explanation:

100x = 1/10×200

100x = 20

÷100     ÷100

x = 0.2

check:

100 × 0.2 = 20

1/10 × 200 = 20

20 = 20

[true statement]

(Or, you know that 100 is half of 200, and to get from 100 to 200 we had to multiply by 2, and that 100 x 2/10 will be equal; this is harder to word though)

Answer: Wasp has greater kinetic energy of 0.002 Joules

Given for bee:

Given for wasp:

Formula:

Kinetic energy of bee:

Kinetic energy of wasp:

From this, it is determined wasp has greater kinetic energy.

By critically observing the given graphs, we can logically deduce that "graph C" returns greatest integer that is less than or equal (≤) to x.

A greatest integer function can be defined as a type of function which returns the greatest integer that is less than or equal (≤) to the number.

Mathematically, the greatest integer that is less than or equal (≤) to a number (x) is represented as follows:

y = [x].

By critically observing the given graphs, we can logically deduce that y in "graph C" returns greatest integer that is less than or equal (≤) to x.

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Answer:

X=5

Step-by-step explanation:

f(1)= -1^2+4(1)+12=15

f(2)= -2^2+4(2)+12=16

f(3)= -3^2+4(3)+12=15

f(4)= -4^2+4(4)+12=12

f(5)= -5^2+4(5)+12=7

g(1)=1+2=3

g(2)=2+2=4

g(3)=3+2=5

g(4)=4+2=6

g(5)=5+2=7

so g(5)=f(5)= X=5

Answer:

Step-by-step explanation:

You're suppose to plug in the values 1, 2, 3, 4, 5, and 6 into f(x) and g(x) to find where they're equal to find the solution to f(x) = g(x) (when the column values are equal).

So for example

f(1) = -(1)^2 + 4(1) + 12

f(1) = -1 + 4 + 12

f(1) = 15

g(1) = 1 + 2

g(1) = 3

put these two values in the table for f(1) and g(1)

f(2) = -(2)^2 + 4(2) + 12

f(2) = -4 + 8 + 12

f(2) = 16

g(2) = 2 + 2

g(2) = 4

f(3) = -(3)^2 + 4(3) + 12

f(3) = -9 + 12 + 12

f(3) = 15

g(3) = 3 + 2

g(3) = 5

f(4) = -(4)^2 + 4(4) + 12

f(4) = -16 + 16 + 12

f(4) = 12

g(4) = 4 + 2

g(4) = 6

f(5) = -(5)^2 + 4(5) + 12

f(5) = -25 + 20 + 12

f(5) = 7

g(5) = 5 + 2

g(5) = 7

f(5) = g(5) so the solution is when x=5

f(6) = -(6)^2 + 4(6) + 12

f(6) = -36 + 24 + 12

f(6) = 0

g(6) = 6 + 2

g(6) = 8

Answer: [tex]\sum^{24}_{n=1} (4n+5)[/tex]

Step-by-step explanation:

This is an arithmetic series with a common difference of 4, so we can immediately eliminate the two left-hand options.

To determine which of the two options on the right is correct, we can determine the first term of each sum expanded out.

The length of CD is 7-3=4.

Therefore, if we dilate by a scale factor of 3, the length is 4(3) = 12

Answer:

b) 12

Step-by-step explanation:

the length of the image is 12. i just know. trust me.

replace F with 95:

95 = 9/5C + 32

Subtract 32 from both sides:

63 = 9/5C

Divide both sides by 9/5:

C = 35

answer: 35 Celsius

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\texttt {\:Thomas's age = 44 years } [/tex]

[tex]\texttt {\:Hulian's age = 36 years } [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex] \textsf{Assume Thomas's age be ' x ' } [/tex]

[tex] \textsf{and that of Huilan's age be y } [/tex]

[tex] \texttt{we have two conditions :} [/tex]

[tex]\qquad \tt \rightarrow \:y = x + 8[/tex]

it can be simplified as : -

[tex]\qquad \tt \rightarrow \:y - x= 8 \: \: \: \: \: \: \: \: \: - (1)[/tex]

[tex] \texttt{Next condition } [/tex]

[tex]\qquad \tt \rightarrow \:x + y = 80 \: \: \: \: \: \: \: - (2)[/tex]

`` Add both equations ``

[tex]\qquad \tt \rightarrow \:y - x + x + y = 8 + 80[/tex]

[tex]\qquad \tt \rightarrow \:2y = 88[/tex]

[tex]\qquad \tt \rightarrow \:y = 44[/tex]

[tex] \large \textsf{For x :} [/tex]

[tex]\qquad \tt \rightarrow \:y - x = 8[/tex]

[tex]\qquad \tt \rightarrow \:44 - x = 8[/tex]

[tex]\qquad \tt \rightarrow \:x = 44 - 8[/tex]

[tex]\qquad \tt \rightarrow \:x = 36[/tex]

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Answer:

[tex]\fbox {36 years old}[/tex]

Step-by-step explanation:

Let :

⇒ Age of Huilan = x

⇒ Age of Thomas = x - 8

Then :

⇒ x + x - 8 = 80

⇒ 2x = 88

⇒ x = 44

Thomas's age :

⇒ x - 8

⇒ 44 - 8

⇒ 36 years old

Answer:

0.125 mm

Step-by-step explanation:

A/L=W

W=0.125

A straight line passing through the point (-2,1) and having a gradient of -3 yields the equation y = -3x - 5.

We know that a straight line is an infinitely long line with no curves on it. A straight line's equation is

y = mx + c...(1), where m is the gradient of the straight line and c is a constant.

Given that the gradient of the given straight line = m = -3.

Putting this value in (1), we get

y = -3x + c ...(2)

Again, the given straight line passes through the point (-2,1). So, we can put x = -2 and y = 1 to get the value of the constant c.

So, 1 = (-3)(-2) + c

i.e. 6 + c = 1

i.e. c = 1 - 6 = -5

(2) can be written as

y = -3x - 5

Therefore the equation of the given straight line is

y = -3x - 5

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Answer:

The answer is $2.80.

Step-by-step explanation:

The price was reduced to two dollars and you buy 28 cans for the same price in which you got 20 cans at original price. So you need to take 28 cans times 2, which you will receive 56. Take 56 the price divided by 20 the original price cans and you will receive 2.8 or $2.80. To double check your work, take 2.80 times 20 and see if you get 56. #BallersKnowMath

Using conditional probability, it is found that there is a 0.3349 = 33.49% probability that a student is a 9th grader, given that fishing is their favorite leisure activity.

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which:

In this problem, we have that the probabilities are given as follows:

[tex]P(A) = 0.433, P(A \cap B) = 0.29 \times 0.50 = 0.145[/tex]

Hence the conditional probability is:

[tex]P(B|A) = \frac{0.145}{0.433} = 0.3349[/tex]

0.3349 = 33.49% probability that a student is a 9th grader, given that fishing is their favorite leisure activity.

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Answer:

3x-4=5

Step-by-step explanation:

it is correct

Answer:

73,358,400

Step-by-step explanation:

(2465)8 × (465)8

= 19,720 × 3,720

= 73,358,400