We can say with 90% confidence that the true mean GPA of all accounting students at this university lies between 2.7107 and 3.0493.
We are given:
Sample size n = 21
Sample mean X = 2.88
Sample standard deviation s = 0.16
Confidence level = 90% or α = 0.10 (since α = 1 - confidence level)
Since the sample size is small and population standard deviation is unknown, we will use a t-distribution to construct the confidence interval.
The formula for the confidence interval is given by:
X ± t(α/2, n-1) * s/√n
where t(α/2, n-1) is the t-score with (n-1) degrees of freedom, corresponding to the upper α/2 percentage point of the t-distribution.
Using a t-table with (n-1) = 20 degrees of freedom and α/2 = 0.05, we find the t-score to be 1.725.
Plugging in the values, we get:
2.88 ± 1.725 * 0.16/√21
= (2.7107, 3.0493)
Therefore, we can say with 90% confidence that the true mean GPA of all accounting students at this university lies between 2.7107 and 3.0493.
Note: The confidence interval can also be written as [2.71, 3.05] rounding to two decimal places.
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Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 samples are summarized as follows conformsupplier yes no1 22 82 25 53 30 10Let A denote the event that a sample is from supplier 1 and let B denote the event that a sample conforms to specifications. Determine the number of samples in A' ∩ B, B' and A ∪ B
The number of samples in A ∪ B is 105 + 100 - 22 = 183.
Using the given information, we can fill in the table below:
| Conforms to specifications | Does not conform to specifications | Total
----------------|---------------------------|------------------------------------|-------
Supplier 1 (A) | 22 | 78 | 100
----------------|---------------------------|------------------------------------|-------
Supplier 2 (not A) | 53 | 47 | 100
----------------|---------------------------|------------------------------------|-------
Supplier 3 (not A) | 30 | 70 | 100
----------------|---------------------------|------------------------------------|-------
Total | 105 | 195 | 300
To find the number of samples in A' ∩ B, we need to find the number of samples that are not from Supplier 1 (i.e., suppliers 2 and 3) and also do conform to the specifications.
From the table, we can see that the number of samples that conform to the specifications but are not from Supplier 1 is 53 + 30 = 83. Therefore, the number of samples in A' ∩ B is 83.
To find the number of samples in B', we need to find the number of samples that do not conform to the specifications. From the table, we can see that the number of samples that do not conform to the specifications is 195. Therefore, the number of samples in B' is 195.
To find the number of samples in A ∪ B, we need to find the number of samples that are either from Supplier 1 or conform to the specifications (or both).
From the table, we can see that there are 105 samples that conform to the specifications and 100 samples that are from Supplier 1.
However, we need to be careful not to double-count the samples that are both from Supplier 1 and conform to the specifications. From the table, we can see that there are 22 such samples.
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If 20 daffodils cost $11.60, how much would 10 daffodils cost?
Answer: 5.80?
Step-by-step explanation:
Just divide by 2, like
11.60 divided by 2
the volume obtained by rotating the region enclosed by
y = 1/(x^5)
y = 0
x = 3
x = 7
about the line y = -2 can be computer using the method of disks or washers via an integral V = ________
with limits of integration a = ___ and b = ___
The volume obtained by rotating the region enclosed is V = ∫[from x=3 to x=7] π * (-2 - 1/(x⁵))² dx
Given data ,
To find the volume of the solid obtained by rotating the region enclosed by the curves y = 1/(x⁵), y = 0, x = 3, and x = 7 about the line y = -2 using the method of disks or washers, we can set up an integral that represents the volume.
First, let's determine the limits of integration, which are the values of x where the region is bounded. From the given information, we know that the curves intersect at x = 3 and x = 7. So, our limits of integration will be from x = 3 to x = 7.
Next, let's consider the method of disks. We can imagine taking slices perpendicular to the axis of rotation (y-axis) that are infinitesimally small and represent disks. The volume of each disk is given by the formula for the area of a disk, which is π * r² * Δx, where r is the distance from the axis of rotation to the curve, and Δx is the thickness of the disk.
In this case, the axis of rotation is y = -2, so the distance from the axis of rotation to the curve y = 1/(x^5) is the difference between -2 and 1/(x^5), which is -2 - 1/(x⁵).
Therefore, the volume of each disk is given by π * (-2 - 1/(x⁵))² * Δx.
Integrating this expression from x = 3 to x = 7 with respect to x will give us the total volume of the solid. So, the integral representing the volume is:
V = ∫[from x=3 to x=7] π * (-2 - 1/(x⁵))² dx
Hence , the volume is V = ∫[from x=3 to x=7] π * (-2 - 1/(x⁵))² dx
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7. Let C be the the line segment directed from P = (x1, y) to Q = (22,42). Show that 5. « dy – yder = nin-ran. What is the geometric significance of this integral?
The integral ∫xdy - ydx represents the signed area of the parallelogram or triangle formed by the vectors P and Q, and its value is equal to x₂y₁ - x₁y₂.
We can parametrize the line segment C as a vector-valued function r(t) = P + t(Q-P), where 0 <= t <= 1. This gives us the following parametric equations for x and y:
x = x₁ + t(x₂ - x₁)
y = y₁ + t(y₂ - y₁)
Taking the differentials of x and y with respect to t, we get:
dx = x₂ - x₁ dt
dy = y₂ - y₁ dt
Substituting these into the integral, we get:
∫xdy - ydx = ∫(x₂ - x₁)(y₁ + t(y₂ - y₁)) - (y₂ - y₁)(x₁ + t(x₂ - x₁)) dt
Simplifying, we get:
∫xdy - ydx = ∫(x₂y₁ - x₁y₂) dt
Evaluating the integral, we get:
∫xdy - ydx = x₂y₁ - x₁y₂
This shows that the value of the integral is equal to the signed area of the parallelogram formed by the vectors P and Q. If P and Q are arranged so that P is the initial point and Q is the terminal point, then the integral is equal to the area of the triangle formed by P and Q, with the sign indicating the orientation of the triangle.
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Complete question is:
Let C be the the line segment directed from P = (x₁, y₁) to Q = (x₂,y₂). Show that ∫xdy – ydx = x₁y₂-x₂y₁. What is the geometric significance of this integral?
Find the critical value(s) and rejection region(s) for the indicated t-test, level of significance a, and sample size n. Right-tailed test, a = 0.005, n = 8
Click the icon to view the t-distribution table.
The critical value(s) is/are ______ . (Round to the nearest thousandth as needed. Use a comma to separate answers as needed.)
The critical value for a right-tailed t-test with a level of significance of 0.005 and 8 degrees of freedom is 3.355. The rejection region is t > 3.355.
To find the critical value for a right-tailed t-test with a level of significance (α) of 0.005 and a sample size (n) of 8, you will need to use a t-distribution table.
Since the sample size is 8, the degrees of freedom (df) is n-1, which equals 7.
Now, look up the t-value in the t-distribution table using α = 0.005 and df = 7. The critical value is 3.499.
So, the critical value is 3.499 (rounded to the nearest thousandth). The rejection region for this right-tailed test is any t-value greater than 3.499.
The critical value for a right-tailed t-test with a level of significance of 0.005 and 8 degrees of freedom is 3.355. The rejection region is t > 3.355.
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A radioactive substance decays exponentially: The mass at time t is m(t) = m(0)ekt, where m(0) is the initial mass and k is a negative constant. The mean life M of an atom in the substance isM = -kFor the radioactive carbon isotope, 14C, used in radiocarbon dating, the value of k is -0.000121. Find the mean life of a 14C atom.
The mean life of a 14C atom is approximately 8,267 years.
For a radioactive substance, the mean life M is defined as the average amount of time it takes for half of the atoms in a sample to decay.
In this case, we have the equation for the mass of a radioactive substance
m(t) = m(0) [tex]e^{kt}[/tex]
where m(0) is the initial mass, k is a negative constant, and t is time.
To find the mean life of a 14C atom, we need to find the value of M when k = -0.000121.
First, we need to solve for t when the mass of a sample of 14C is half of its initial mass:
0.5m(0) = m(0) [tex]e^{-0.000121t}[/tex]
Dividing both sides by m(0), we get
0.5 = [tex]e^{-0.000121t}[/tex]
Taking the natural logarithm of both sides:
ln(0.5) = -0.000121t
Solving for t
t = ln(0.5) / (-0.000121)
t ≈ 5,732 years
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Find the probability that a female college student from the group chose "housework" as their most likely activity on Saturday mornings? (Round to the nearest thousandth)
The probability that a female college student from the group chose "housework" as their most likely activity on Saturday mornings cannot be determined without additional information.
The question states that the probability of a female college student choosing "housework" as their most likely activity on Saturday mornings needs to be determined. However, no information is given regarding the number of female college students in the group or the number of students who chose "housework" as their most likely activity.
Therefore, it is impossible to calculate the probability without any additional information. In order to calculate the probability, we would need to know the number of female college students in the group and the number of those students who chose "housework" as their most likely activity. Therefore, the probability cannot be determined without additional information.
Therefore, we can conclude that without additional information, the probability that a female college student from the group chose "housework" as their most likely activity on Saturday mornings cannot be calculated.
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A plant distills liquid air to produce oxygen, nitrogen, and argon. The percentage of impurity in the oxygen is thought to be linearly related to the amount of impurities in the air as measured by the pollution count" in part per million (ppm). A sample of plant operating data is shown below. Pollution count (ppm) Purity (%) 933 1145 1.59 92.4 91.7 94 1.08 Purity (%) 946 12 93.6 0.99 0.83 12 932 1.47 1.81 05 115 Pollution count (ppm)
The link between two variables, such as pollution count and oxygen purity, can be determined using linear regression, with the result that Purity (%) = 90.3%.
Making predictions about one variable based on another can be done using the regression line. Inferring future values for one variable from another using the regression line.
Utilizing linear regression, we may determine the linear relationship between the amount of pollution and the oxygen's purity.
The regression line's equation is: which can be discovered using a calculator or statistical software.
Pureness (%) = -0.020(ppm) + 110.3
Accordingly, the quality of oxygen is reduced by 0.02% for every rise in pollution of 1 ppm.
In order to forecast the oxygen purity for a specific pollution level, we can also use the regression line. As an illustration, we may estimate the oxygen purity to be: if the pollution level is 1000 ppm.
Hence, Pureness (%) = -0.020(1000) + 110.3 = 90.3%
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1. Find the Laplace transform of f(t)=e-sin(51) using the appropriate method.
To find the Laplace transform of f(t)=e-sin(51), we will use the definition of the Laplace transform and the property of the Laplace transform of a sinusoidal function.
Using the definition of the Laplace transform, we have:
L{f(t)} = ∫0∞ e^(-st) e^(-sin(51)t) dt
Next, we will use the property that L{sin(at)} = a/(s^2 + a^2) to simplify the integral:
L{f(t)} = ∫0∞ e^(-st) e^(-sin(51)t) dt
= ∫0∞ e^(-st) sin(51)t (1/sin(51)) e^(-sin(51)t) dt
= (1/sin(51)) ∫0∞ e^(-(s+sin(51))t) sin(51)t dt
= (1/sin(51)) L{sin(51)t} with a = 51
= (1/sin(51)) (51/(s^2 + 51^2))
Therefore, the Laplace transform of f(t)=e-sin(51) is:
L{f(t)} = (51/sin(51)(s^2 + 51^2))
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i need help asap pleasee
Answer:
y<=x+2
Step-by-step explanation:
in 2012, the general social survey asked a sample of 1312 people how much time they spent watching tv each day. the mean number of hours was 2.97 with a standard deviation 2.61. a sociologist claims that people watch a mean of 3 hours of tv per day. do the data provide sufficient evidence to conclude that the mean hours of tv watched per day is less than the claim? use the a
We reject the null hypothesis and conclude that the data provide sufficient evidence to support the claim that the mean hours of TV watched per day is less than 3 hours.
What is mean?
In statistics, the mean is a measure of central tendency, also known as the average. It is calculated by adding up all the values in a dataset and dividing the sum by the number of values in the dataset.
To determine whether the data provide sufficient evidence to conclude that the mean hours of TV watched per day is less than the claim of 3 hours, we can conduct a one-sample t-test with the following hypotheses:
Null hypothesis: The mean hours of TV watched per day is greater than or equal to 3 hours (µ ≥ 3).
Alternative hypothesis: The mean hours of TV watched per day is less than 3 hours (µ < 3).
We will use a significance level (alpha) of 0.05.
First, we need to calculate the test statistic (t-value) using the formula:
t = ([tex]\bar{x}[/tex] - µ) / (s / sqrt(n))
Where:
[tex]\bar{x}[/tex] = sample mean (2.97)
µ = population mean claim (3)
s = sample standard deviation (2.61)
n = sample size (1312)
Plugging in the values, we get:
t = (2.97 - 3) / (2.61 / sqrt(1312)) = -2.64
Next, we need to determine the degrees of freedom (df), which is equal to n - 1 = 1311.
Using a t-distribution table with df = 1311 and a significance level of 0.05, we find the critical t-value to be -1.645.
Since our calculated t-value of -2.64 is less than the critical t-value of -1.645, we reject the null hypothesis and conclude that the data provide sufficient evidence to support the claim that the mean hours of TV watched per day is less than 3 hours.
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Use this information to answer the question:
A = {1,2,3,4,6,12} B={2,4,6,8,10,12} C={1,3,5,7,9,11} D={2,4,6}
U={1,2,3,4,5,6,7,8,9,10,11,12}
IsD⊂A?Whyorwhynot?
Yes, the set D is a subset of set A that is D⊂A because all the elements of set D are present in set A.
Universal set is,
U={1,2,3,4,5,6,7,8,9,10,11,12}
Element present in different set are as follow,
Set A = {1,2,3,4,6,12}
Set B={2,4,6,8,10,12}
Set C={1,3,5,7,9,11}
Set D={2,4,6}
D is a subset of A.
If and only if all the elements of set D are also present in set A.
Element of set D = {2, 4, 6}
Element of set A = {1, 2, 3, 4, 6, 12}
All the elements of D, namely 2, 4, and 6, are also present in set A.
This implies,
D is a subset of A.
It is denoted as D ⊂ A.
Therefore, yes D is subset of A ' D⊂A' as all the element of set D are in set A.
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Solve the differential equation, subject to the given initial condition. dy X + 4y = 7x?; + dx y(4) = 22
[tex]\:y\:=\:\left(7/4\right)x^3\:+\:\left(C/e^{\left(4x\right)}\right)e^{\left(4x\right)}[/tex] is the solution of the differential equation x dy/dx + 4y =7x²
The given differential equation is a linear first-order differential equation. By using the integrating factor technique, we can solve this equation.
The integrating factor for this equation is [tex]e^{\left(4\int dx\right)}\:=\:e^{\left(4x\right)}.\:[/tex]
Multiplying both sides of the equation by the integrating factor, we get [tex]\left(xe^{\left(4x\right)}\right)dy\:+\:4e^{\left(4x\right)}y\:=\:7x^2e^{\left(4x\right)}.\:[/tex]
Integrating both sides of the equation
[tex]\left(1/4\right)e^{\left(4x\right)}y\:=\:\left(7/8\right)x^3e^{\left(4x\right)}\:+\:C,[/tex]
where C is the constant of integration.
we get [tex]\:y\:=\:\left(7/4\right)x^3\:+\:\left(C/e^{\left(4x\right)}\right)e^{\left(4x\right)}[/tex].
Now, we can use the initial condition to solve for the constant of integration.
When x = 4 and y = 22
substituting these values into the equation,
we get [tex]22\:=\:\left(7/4\right)\cdot 64\:+\:\left(C/e^{\left(16\right)}\right)e^{\left(16\right)}[/tex].
Solving for C, we get [tex]C\:=\:e^{\left(16\right)}\cdot \left(22\:-\:\left(7/4\right)\cdot 64\right)[/tex]
Hence, [tex]\:y\:=\:\left(7/4\right)x^3\:+\:\left(C/e^{\left(4x\right)}\right)e^{\left(4x\right)}[/tex] is the solution of the differential equation x dy/dx + 4y =7x²
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Use the formula V = s³, where V is the volume and s is the edge length of the cube, to solve this probler
A cube-shaped container has an edge length of 2/3 feet.
What is the volume of the container?
Enter your answer, as a fraction in simplest form, in the box.
ft³
The volume of the cube-shaped container with an edge length of 2/3 feet is 8/27 cubic feet.
Given the formula for the volume of a cube: V = s³
where V is the volume of the cube.
if we know the edge length of the cube, we can use this formula to calculate it's volume.
In this case, the edge length of the cube is given as 2/3 feet.
V= s³= (2/3)³= 8/27 cubic feet
Therefore, the volume of the cube-shaped container with an edge length of 2/3 is 8/27 cubic feet.
You are constructing box for your cat to sleep in. The plush material for the square bottom of the box costs 58/ft? and the materia for the sides costs s4/ft? . You need box with volume Find the dimensions (in ft) of the box that minimize cost: Use to represent the length of the side of the box and to represent the height:
The dimensions of the box are length = 1.474 feet and height = 1.85.
We need an equation for surface area. We will assume that there is no top on the box. Let us assume that the length is 'L' and the height is 'H'. The surface area of the bottom of the box is [tex]L *L[/tex]. The surface area of the two ends is [tex]L * H[/tex]. The surface area of the two sides is also [tex]L * H[/tex].
So, the total surface area is
= [tex]L * L + 4(L *H)[/tex]
As we know that we are limited to a volume of 4 cubic feet. Therefore,
[tex]L *L *H = 4[/tex]
[tex]H = 4/L^{2}[/tex]
The cost for the bottom is $5 and the cost for the sides is $2. Therefore,
Cost = [tex]5*L*L + 2.4L(4/L^2)[/tex]
[tex]C(L) = 5L^{2} + 32/L[/tex]
We will take the derivative and set it to 0 as we have to minimize the cost.
[tex]C'(L) = 10L + -32L^{-2}[/tex]
[tex]10L + -32/L^{2} = 0[/tex]
[tex]32/L^{2} = 10L[/tex]
[tex]32 = 10L^{3}[/tex]
32/10 = [tex]L^3[/tex]
[tex]L^3 = 16/5[/tex]
L = 1.474 ft
As we know, H = [tex]4/L^2[/tex]
Therefore, H = 4/2.16 = 1.85 ft
Therefore, the dimensions of the box are Length = 1.47 ft and Height = 1.85 ft.
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The complete question is "You are constructing a box for your cat to sleep in. The plush material for the square bottom of the box costs $5/ft^2. and the material for the sides costs $2/ft^2. You need a box with a volume of 4 ft^2. Find the dimensions (in ft) of the box that minimize cost."
Which of the following gives a single solution of the inequality |x+3|-2<=0 and shows a graph that can be used to determine the entire solution set of the inequality?
Upon answering the query All x values that fall within the range [-5, -1] and meet the inequality are represented by the darkened rectangle.
What is inequality?A connection between two words or variables that is not equal in mathematics is referred to as an inequality. Thus, inequity results from imbalance. In mathematics, an inequality establishes the connection between two non-equal numbers. Egality and inequality are not the same. The not equal symbol () is most frequently used to indicate that two numbers are not equal. Values of any size can be contrasted using a variety of inequalities. By changing the two sides until just the variables are left, many straightforward inequalities may be solved. However, a variety of factors support inequality: Both sides' negative values are split or added. Exchange the left and the right.
inequality |x+3| - 2 ≤ 0 can be
[tex]| x + 3 | - 2 \leq 0\\| x + 3 | \leq 2\\-2 \leq x + 3 \leq 2\\-5 \leq x \leq -1\\[/tex]
The range [-5, -1] is therefore the solution set for the inequality.
You may draw the points -5 and -1 on a number line and darken the area in between them to graph the solution set. The diagram would resemble:
---------------------------
-5 -3 -1
All x values that fall within the range [-5, -1] and meet the inequality are represented by the darkened rectangle.
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The single solution for the inequality is: x=-4
The graph of the inequality can be drawn by first plotting the points -5 and -1 on the number line and then shading the interval between them.
What is inequalities?
In mathematics, an inequality is a mathematical statement that indicates that two expressions are not equal. It is a statement that compares two values, usually using one of the following symbols: "<" (less than), ">" (greater than), "≤" (less than or equal to), or "≥" (greater than or equal to).
The inequality |x+3|-2<=0 can be rewritten as:
|x+3|<=2
This means that the distance between x and -3 is less than or equal to 2.
To find the solution set, we can split the inequality into two cases:
Case 1: x+3>=0
In this case, the inequality becomes:
x+3<=2
Solving for x, we get:
x<=-1
So, for x>=-3, the solution set is:
-3<=x<=-1
Case 2: x+3<0
In this case, the inequality becomes:
-(x+3)<=2
Solving for x, we get:
x>=-5
So, for x<-3, the solution set is:
x>=-5
Combining the two solution sets, we get:
-5<=x<=-1
Therefore, the single solution for the inequality is:
x=-4
The graph of the inequality can be drawn by first plotting the points -5 and -1 on the number line and then shading the interval between them. The point -4 should be included in the shaded interval.
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Question 1B. 7 points in total. Industrial psychologists wish to investigate the effect of music in the factory on the productivity of workers. Four distinct music programs and no music make up the five treatments. The experiment is run in 8 plants. Each music program is used for one week. For each plant, the five music treatments are assigned at random to weeks (1,2,3,4,5) so that all music programs are used in each plant. The production is recorded at the end of each week. (a) Identify the type of design that was used (Select one from the following types: Completely Randomized Design (CRD), Randomized Complete Block Design (RCBD), Balanced Incomplete Block Design (BIBD), and factorial experiments). (2 points) (6) Determine experimental units and blocks, if used. (2 points) (c) Write out ANOVA table including the column "Source" and "OP". (3 points)
the design is balanced and each treatment is used in each block the same number of times, we can use the ANOVA table to test for treatment effects, block effects, and treatment-block interactions
(a) The type of design used is a Balanced Incomplete Block Design (BIBD), where each treatment is assigned to a specific week within each plant, with each treatment appearing in each block (plant) the same number of times.
(b) The experimental units are the workers in each plant, and the blocks are the plants themselves.
(c) The ANOVA table would be:
Source SS df MS F p-value
Treatment SS(T) 4 MS(T) F = MS(T)/MS(E) p-value
Block SS(B) 7 MS(B) F = MS(B)/MS(E) p-value
Error SS(E) 28 MS(E)
Total SS(Total) 39
where SS denotes sum of squares, df denotes degrees of freedom, MS denotes mean squares, F denotes the F statistic, and p-value denotes the probability of observing an F statistic at least as extreme as the observed F value, assuming the null hypothesis is true.
Note that since the design is balanced and each treatment is used in each block the same number of times, we can use the ANOVA table to test for treatment effects, block effects, and treatment-block interactions
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∫sinx dx over the interval [ 0 , Π/4 ]
The average ordinate of y = sin x over the interval [0,π] is 2/π or approximately 0.6366.
Now, let's look at the function y = sin x over the interval [0,π]. The graph of this function is a wave that oscillates between 1 and -1 over the interval [0,π]. The average ordinate of this function over the interval [0,π] is the mean value of all the y-coordinates of the points on the curve over that interval.
To find the mean value, we need to calculate the total area under the curve between x = 0 and x = π, and then divide that by the length of the interval (which is π). The total area under the curve can be found by integrating the function y = sin x over the interval [0,π]:
∫sin x dx = [-cos x] from 0 to π = -cos(π) - (-cos(0)) = 2
So, the total area under the curve is 2. To find the average ordinate, we divide the total area by the length of the interval:
Average ordinate = (total area under curve) / (length of interval)
= 2 / π
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Complete Question:
The average ordinate of y = sin x over the interval [0,π] is -
Let X1,..., Xn be iid with pdf f(x\0) = 0x9-1, OSI<1, 0
the second derivative is negative, the likelihood function is concave and the value of θ_hat is a maximum.
The first step is to find the likelihood function, which is the product of the pdf of the random variables, given the observed sample:
L(X1, X2, ..., Xn; θ) = f(X1; θ) * f(X2; θ) * ... * f(Xn; θ)
= (θ^n) * exp(-θ * (X1 + X2 + ... + Xn))
Next, we take the logarithm of the likelihood function to simplify it:
log L(X1, X2, ..., Xn; θ) = n * log(θ) - θ * (X1 + X2 + ... + Xn)
To find the maximum likelihood estimator (MLE) of θ, we take the derivative of the logarithm of the likelihood function with respect to θ and set it equal to zero:
d/dθ (log L(X1, X2, ..., Xn; θ)) = n/θ - (X1 + X2 + ... + Xn) = 0
Solving for θ, we get:
θ = n / (X1 + X2 + ... + Xn)
Therefore, the MLE of θ is the reciprocal of the sample mean of X1, X2, ..., Xn:
θ_hat = 1 / (X1 + X2 + ... + Xn) * n
To check if this is a maximum, we take the second derivative of the logarithm of the likelihood function with respect to θ:
d^2/dθ^2 (log L(X1, X2, ..., Xn; θ)) = -n/θ^2 < 0
Since the second derivative is negative, the likelihood function is concave and the value of θ_hat is a maximum. Therefore, the MLE of θ is θ_hat = 1 / (X1 + X2 + ... + Xn) * n
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Solve the problem: If u = (-5,7) and v= (1,6), and w= (-11, 2), evaluate u · (v + w) : 106, 87, 96, 114
To evaluate u · (v + w), we first need to calculate the vector v + w by adding the corresponding components of vectors v and w:So, the answer is 106.
v + w = (1, 6) + (-11, 2) = (-10, 8)
Then, we use the dot product formula to calculate u · (v + w):
u · (v + w) = (-5, 7) · (-10, 8) = (-5)(-10) + (7)(8) = 50 + 56 = 106
Therefore, the answer is 106.
Hi! To solve this problem, you first need to find the sum of vectors v and w, and then take the dot product of u and the sum of v and w.
1. Find the sum of vectors v and w:
v + w = (1, 6) + (-11, 2) = (1 - 11, 6 + 2) = (-10, 8)
2. Calculate the dot product of u and (v + w):
u · (v + w) = (-5, 7) · (-10, 8) = (-5 * -10) + (7 * 8) = 50 + 56 = 106
So, the answer is 106.
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You are building jet packs for paramedics. Jet pack thrust is normally distributed and you want to know if the average maximum thrust produced by your jet packs is different from 317 lbs. You tested fifteen jetpacks and recorded their maximum thrusts. 317.5, 316.8, 318.4, 320.7, 314.2, 300.9, 323.8, 315.6, 321.1, 324.6, 316.3, 319.7, 311.7, 313.5, 322.4 11. (1pt)
List the following summary statistics and use correct notation (sample size, sample average, sample standard deviation, median, and range). Round to four decimal places where appropriate. Round to fewer than four decimals when the answer is exact and has less than four decimal places.
Set up the hypothesis test that would test what you are interested in knowing with a Type 1 Error of 0.04. List H_O,H_1,α.
Calculate the p-value for the hypotheses from the previous problem.
Under the appropriate distribution, draw the rejection region. Label every key feature (including, but not limited to, the distribution itself and the area under the curve in the rejection region). 1 * = 2.2638
In the context/units of the problem, calculate, draw and label the rejection region. Label every key feature. Investors would be interested if the average maximum thrust was actually 313 lbs. In the context/units of the problem, draw and label the power. Label every key feature.
Calculate the power of your test to detect the investor's alternative of interest.
The p-value for the hypotheses from the previous problem is 0.7935.
The power of your test to detect the investor's alternative of interest is 323.5624
To begin with, we need to calculate some summary statistics to describe the data. The sample size (n) is 15, the sample average (x) is 317.267, the sample standard deviation (s) is 6.0281, the median is 317.5, and the range is 23.5 (from 300.9 to 324.6).
Now, we can set up the hypothesis test to determine if the average maximum thrust produced by our jet packs is different from 317 lbs. Let µ represent the population mean of maximum thrust produced by the jet packs.
Our null hypothesis, H0, is that the population mean of maximum thrust is equal to 317 lbs (µ = 317). The alternative hypothesis, H1, is that the population mean of maximum thrust is different from 317 lbs (µ ≠ 317).
To control the Type 1 Error at 0.04, we set α (significance level) equal to 0.02 on each tail of the distribution.
The next step is to calculate the p-value for the hypotheses from the previous problem. The p-value is the probability of observing a sample mean as extreme or more extreme than the observed value, assuming the null hypothesis is true. We can use the t-distribution to calculate the p-value.
The t-value for our sample is (317.267 - 317) / (6.0281 / √(15)) = 0.7935. The degrees of freedom (df) for the t-distribution is n - 1 = 14.
Using a t-table or calculator, the two-tailed p-value is 0.4433. Since the p-value is greater than the significance level (0.02), we fail to reject the null hypothesis. We do not have sufficient evidence to conclude that the population mean of maximum thrust is different from 317 lbs.
To draw the rejection region under the t-distribution, we first need to calculate the critical t-value. With α = 0.02 and df = 14, the critical t-value is ±2.4469.
The rejection region consists of all t-values that are less than -2.4469 or greater than 2.4469. This area corresponds to 0.02 in each tail of the distribution.
To draw the rejection region in the context of the problem, we need to convert the t-values to the units of the problem, which is lbs. Using the formula for the t-value, we get:
t = (x - µ) / (s / √(n))
Substituting the values, we get:
t = (317.267 - 317) / (6.0281 / √(15)) = 0.7935
The rejection region is then:
x < 317 - 2.4469 * (6.0281 / √(15)) = 310.4376 or x > 317 + 2.4469 * (6.0281 / √(15)) = 323.5624
This means that if the sample mean falls outside the rejection region, we fail to reject the null hypothesis.
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Find the value of a in the triangle shown below.
The value of x in the triangle is 3
How to determine the valueIt is crucial that we note the different trigonometric identities in mathematics are;
sinetangentcosinecotangentsecantcosecantAlso, using the Pythagorean theorem stating that the square of the hypotenuse is equal to the sum of the squares of the other two sides
5² = x² + 4²
find the squares
25 = x² + 16
collect the like terms
x² = 9
Find the square root
x = 3
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Example: Comparing Samples
Compare the dispersions in the two samples A and B.
A: 12, 13, 16, 18, 18, 20
B: 125, 131, 144, 158, 168, 193
Sample A is less variable than sample B as the standard deviation of sample A is smaller than that of sample B, so, the values of sample A are less scattered than those of sample B.
To compare the dispersion in two samples, one can calculate their variances and compare them.
First, let's calculate the sample variance A:
Find meaning:
average(A) = (12 + 13 + 16 + 18 + 18 + 20) / 6 = 97/6 = 16.17
Find the squared deviation:
squared_deviations(A) = (17.41, 10.05, 0.03, 3.35, 3.35, 14.70)
Find the distance:
variance(A) = sum(deviation_squared(A)) / (n-1) = 49.11
Next, we will calculate the sample variance B:
Find meaning:
average(B) = (125 + 131 + 144 + 158 + 168 + 193)/6 = 919/6 = 153.17
deviation from the mean:
deviation(B) = (-28.17, -22.17, -9.17, 4.83, 14.83, 39.83)
Find the squared deviation:
squared_deviations(B) = (792.78, 490.61, 84.11, 23.34, 220.36, 1586.39)
Find the space:
variance(B) = sum(squared_deviations(B)) / (n-1) = 7107.67
Therefore, the variance of sample A is 49.11 and the variance of sample B is 7107.67. However, we can compare standard deviations with the same scale as the original data:
standard deviation(A) = [tex]sqrt(variance(A))[/tex] = 7.01
standard deviation(B) =[tex]sqrt(variance(B))[/tex]= 84.26
The standard deviation of sample A is smaller than that of sample B, hence, the values of sample A are less scattered than those of sample B.
hence, sample A is less variable than sample B.
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Pleas help quick. Please show all work.
Answer:
m∠Q = 62.6°
Step-by-step explanation:
We can find m∠Q in degrees (°) using one of the trigonometric ratios.
If we allow ∠Q to be our reference angle, we see that side s is the adjacent side and side r is the hypotenuse. Thus, we can use the cosine ratio, which is
[tex]cos=adjacent/hypotenuse[/tex]
Thus, we have cos (Q) = 29 / 63
In order to find angle measures, you have to use inverse trig and inverse cos ratio is
[tex]cos^-^1(adjacent/hypotenuse)=Q\\cos^-^1(29/63)=Q\\62.59240547=Q\\62.6=Q[/tex]
CAN SOME PLEASE HELP ASAP
Answer:
1: 57,310
2: 89,600
3: 37,000
Step-by-step explanation:
a 1 =−4a, start subscript, 1, end subscript, equals, minus, 4 a i = a i − 1 ⋅ 2 a i =a i−1 ⋅2a, start subscript, i, end subscript, equals, a, start subscript, i, minus, 1, end subscript, dot, 2 Find the sum of the first 50
terms in the sequence.
The answer of the given question based on the sequence is , the sum of the first 50 terms in the sequence is approximately 4.5036 × 10¹⁵.
What is Explicit formula?In mathematics, an explicit formula is a formula that defines a specific term or element of a sequence or function, in terms of the preceding terms or elements or some other input. Explicit formulas are also sometimes called closed-form formulas.
To find the sum of the first 50 terms in the sequence, we need to use the explicit formula:
aᵢ = aᵢ₋₁ × 2
where a₁ = -4.
Using the formula repeatedly, we can find the values of the first few terms:
a₂ = a₁ × 2 = -4 × 2 = -8
a₃ = a₂ × 2 = -8 × 2 = -16
a₄ = a₃ × 2 = -16 × 2 = -32
and so on.
We can see that the sequence is a geometric sequence with a common ratio of 2 and a first term of -4. So we use formula for sum of geometric sequence:
S₅₀ = a₁(1 - rⁿ) / (1 - r)
where a₁ = -4, r = 2, and n = 50.
Plugging in these values, we get:
S₅₀ = (-4)(1 - 2⁵⁰) / (1 - 2)
= (-4)(1 - 1,125,899,906,842,624) / (-1)
= (4)(1,125,899,906,842,623)
= 4.503599627370494e+15
Therefore, the sum of the first 50 terms in the sequence is approximately 4.5036 × 10¹⁵.
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For the population of chief executive officers (CEO), let salary be annual salary in millions of dollars, and let roe be the average return for the previous three years. Return on equity (roe) is defined in terms of net income as a percentage of common equity. For example, if roe = 10, then average return on equity is 10%. Using the data, the OLS regression line relating salary to roe is salary = 1.25 + 0.33roe n = 209, R^2 = 0.213 (a) Interpret the intercept clearly. (b) Interpret the slope estimate clearly. (c) What is the predicted salary when roe = 25? (d) Explain the meaning of R^2 = 0.213 clearly
The intercept of the regression line (1.25) represents the predicted salary of a CEO when their average return on equity (roe) is zero. However, this interpretation may not be practically meaningful as it is unlikely for a CEO to have a roe of zero.
The slope estimate (0.33) represents the change in the predicted salary of a CEO for every one unit increase in their roe. In other words, for every 1% increase in roe, the predicted salary of a CEO increases by $330,000 (0.33 million dollars).
To find the predicted salary when roe = 25, we simply plug in 25 for roe in the regression equation: salary = 1.25 + 0.33(25) = $9.00 million. Therefore, the predicted salary for a CEO with a roe of 25 is $9.00 million.
The coefficient of determination (R^2) measures the proportion of variation in the dependent variable (salary) that can be explained by the independent variable (roe). In this case, R^2 = 0.213 indicates that approximately 21.3% of the variation in CEO salaries can be explained by their average return on equity (roe). The remaining 78.7% of the variation in CEO salaries is likely due to other factors not included in the regression model.
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sample of size n = 8 from a Normal(1, 0) population results in a sample standard deviation of s = 5.4. A 95% lower bound for the true population standard deviation is A: 0 > 1.016. B: 0 > 2.687. C: 0 > 0.384 D: 0 > 1.783. E: o > 3.809
Answer:
Step-by-step explanation:
To calculate a lower bound for the population standard deviation with a 95% confidence level, we can use the following formula:
lower bound = (n - 1) * s^2 / chi-squared(alpha/2, n-1)
where n is the sample size, s is the sample standard deviation, chi-squared(alpha/2, n-1) is the chi-squared value at the alpha/2 percentile with n-1 degrees of freedom.
In this case, n = 8 and s = 5.4. For a 95% confidence level, alpha/2 = 0.025, so we need to find the chi-squared(0.025, 7) value.
Using a chi-squared table or calculator, we find that chi-squared(0.025, 7) = 14.0671.
Plugging in the values, we get:
lower bound = (8 - 1) * 5.4^2 / 14.0671
= 19.4175
Taking the square root of this value gives us the lower bound for the population standard deviation:
sqrt(19.4175) = 4.4084
Therefore, the correct answer is E: o > 3.809, as the lower bound for the population standard deviation is greater than 3.809.
Gray must score a mean of 94 on 2 math tests to earn an "A" in the class. He scored a 99 on the 1st of these tests. Which inequality correctly describes the score(s) Gray must make on his next math test to earn an "A"?
Answer:
89
Step-by-step explanation:
First multiply 94*2 = 188
Subtract 99 from 188
188 - 99 = 89
Check:
89 + 99 = 188
188/2 = 94
The annual number of passengers going through Hartsfield-Jackson Atlanta International Airport between 2000 and 2008 can be modeled as
p(t) = -0.102t + 1.3912 - 3.295 + 79.25
where output is measured in million passengers and t is the number of years since 2000.1
(a) Numerically estimate p'(6) to the nearest thousand passengers.
_______passengers per year Interpret the result.
At the end of 2006, the number of passengers going through Hartsfield-Jackson International Airport was ---Select--- by approximately_______ per year.
(b) Calculate the percentage rate of change of p at t = 6. (Round your answer to three decimal places.) _________% per year
Interpret the result. (Round your answer to three decimal places.)
At the end of 2006. the number of passengers going through Hartsfield-Jackson International Airport was ---- V by approximately _______% per year.
The percentage rate of change equation is -1.274%
What is percentage?
Percentage is a way of expressing a fraction or proportion out of 100. It is commonly used in many different areas such as finance, math, science, and everyday life.
(a) To numerically estimate p'(6), we need to take the derivative of p(t) with respect to t and evaluate it at t=6.
p(t) = -0.102t + 1.3912t - 3.295 + 79.25
p'(t) = -0.102
p'(6) ≈ -0.102 ≈ -0.102 million passengers per year ≈ -102,000 passengers per year
(b) To calculate the percentage rate of change of p at t=6, we need to calculate the relative change in p over a small interval of time. We can use the formula:
percentage rate of change = [p(t+Δt) - p(t)] / [p(t)] × 100%
where Δt is a small change in time. Let's use Δt = 0.01 years.
percentage rate of change = [p(6+0.01) - p(6)] / [p(6)] × 100%
= [-0.102(0.01)] / [p(6)] × 100%
= -1.02 / [p(6)] × 100%
We can use the given equation to find p(6):
p(6) = -0.102(6) + 1.3912(6) - 3.295 + 79.25
≈ 80.135 million passengers
Substituting this value into the percentage rate of change equation:
percentage rate of change ≈ -1.02 / 80.135 × 100%
≈ -1.274%
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