What is the proportionality constant between an object and
its acceleration by a given force?
Answer:
The net force acting on an object is proportional to the acceleration of that object with respect to an inertial frame of reference. The constant of proportionality in this, Newton's second law, is the classical mass of the object.
Explanation:
A 5 kg ball and a 2 kg ball are placed at opposite ends of a massless beam so that the system is in equilibrium. What is the ratio of the length of the beam to the distance from the heavier ball to the pivot
Answer:
L/x = 3.5 (The ratio of length of beam to the distance from heavier ball to pivot).
Explanation:
In order for the system to be in equilibrium, the moment created by both masses about the pivot point must be equal:
m₁x = m₂y
where,
m₁ = 5 kg
m₂ = 2 kg
x = distance of 5 kg ball from pivot
y = distance of 2 kg ball from pivot
Therefore,
(5 kg)x = (2 kg)y
y = (5kg/2kg)x
y = 2.5 x
but,
x + y = L
where,
L = length of beam
using the value of y from the previous equation:
x + 2.5 x = L
3.5 x = L
L/x = 3.5 (The ratio of length of beam to the distance from heavier ball to pivot).
Why is creativity important in constructing scientific explanations?
A. There are very few scientists who are creative people.
B. Science works when scientists make up their data.
C. The results of some experiments might not be explained by any
known theories.
D. Scientists all think in exactly the same way.
A train slows down as it rounds a sharp horizontal turn, going from 88.0 km/h to 52.0 km/h in the 18.0 s that it takes to round the bend. The radius of the curve is 120 m. Compute the acceleration at the moment the train speed reaches 52.0 km/h. Assume the train continues to slow down at this time at the same rate.
Answer:
The acceleration at the moment the train speed reaches 52 kilometers per hour is approximately 1.826 meters per square second.
Explanation:
According to Rotational Physics, the total acceleration of the train rounding the horizontal turn is a combination of tangential ([tex]a_{t}[/tex]) and radial accelerations ([tex]a_{r}[/tex]), measured in meters per square second. The former one represents the change in the magnitude of the velocity, whereas the latter one represents the change in its direction. By definition of magnitude and Pythagorean Theorem we get that magnitude of total acceleration ([tex]a[/tex]), measured in meters per square second, is:
[tex]a = \sqrt{a_{r}^{2}+a_{t}^{2}}[/tex] (Eq. 1)
Magnitudes of tangential and radial accelerations are determined by using the following formulas:
[tex]a_{t} = \frac{v_{f}-v_{o}}{t}[/tex] (Eq. 1)
[tex]a_{r} = \frac{v_{f}^{2}}{R}[/tex] (Eq. 2)
Where:
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds, measured in meters per second.
[tex]t[/tex] - Time, measured in seconds.
[tex]R[/tex] - Radius, measured in meters.
If we know that [tex]v_{o} = 24.444\,\frac{m}{s}[/tex], [tex]v_{f} = 14.444\,\frac{m}{s}[/tex], [tex]t = 18\,s[/tex] and [tex]R = 120\,m[/tex], then the magnitude of the total acceleration when the train speed reaches 52 kilometers per hour is:
[tex]a_{t} = \frac{14.444\,\frac{m}{s}-24.444\,\frac{m}{s} }{18\,s}[/tex]
[tex]a_{t} = -0.556\,\frac{m}{s^{2}}[/tex]
[tex]a_{r} = \frac{\left(14.444\,\frac{m}{s} \right)^{2}}{120\,m}[/tex]
[tex]a_{r} = 1.739\,\frac{m}{s^{2}}[/tex]
[tex]a = \sqrt{\left(-0.556\,\frac{m}{s^{2}} \right)^{2}+\left(1.739\,\frac{m}{s^{2}} \right)^{2}}[/tex]
[tex]a \approx 1.826\,\frac{m}{s^{2}}[/tex]
The acceleration at the moment the train speed reaches 52 kilometers per hour is approximately 1.826 meters per square second.
A gas was compressed to 30.0 mL at 1.5 atm from 65
mL. What was the original pressure?
A rocket is fired in deep space, where gravity is negligible. In the first second it ejects 1/160 of its mass as exhaust gas and has an acceleration of 14.0 m/s^2.
Required:
What is the speed vgas of the exhaust gas relative to the rocket?
Answer:
840 m/s
Explanation:
Given that,
In the first second the rocket ejects 1/160 of its mass as exhaust gas and has an acceleration of 14.0 m/s².
We need to find the speed of the exhaust gas relative to the rocket.
The thrust of rocket is given by :
[tex]T=v_{gas}\dfrac{dm}{dt}\\\\ma=v_{gas}\dfrac{dm}{dt}\\\\v_{gas}=\dfrac{ma}{\dfrac{dm}{dt}}\\\\v_{gas}=\dfrac{14m}{\dfrac{1}{60}m}\\\\v_{gas}=840\ m/s[/tex]
So, the speed of the exhaust gas relative to the rocket is 840 m/s.
The speed ( Vgas) of the exhaust gas relative to rocket is : 840 m/s
Given data :
In first round Rocket ejects 1/60 of mass as exhaust gas
Acceleration of rocket ( a ) = 14.0 m/s²
Determine the speed of the exhaust gas relative to rocket
We will apply the equation for Rocket thrust
T = Vgas * [tex]\frac{dm}{dt}[/tex]
where : T = ma
∴ Vgas = ma / [tex]\frac{dm}{dt}[/tex]
= 14 m / [tex]\frac{1}{60}[/tex] m
therefore V gas = 840 m/s
Hence we can conclude that the speed ( Vgas) of the exhaust gas relative to rocket is : 840 m/s
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Describe the difference between simply taking measurements and doing a scientific experiment.
In 2-3 sentences
answer pls urgent pls
Answer:
I think its A: Magnesium
Explanation:
Basic oxide is formed by metal, and magnesium is the only metal in these options :)
Please inform me if this is incorrect
If a 25 kg lawnmower produces 347 w and does 9514 J of work, for
how much time did the lawnmower run?
Steps 1 and 2)
The variables are W = work, P = power, and t = time. In this case, W = 9514 joules and P = 347 watts.
The goal is to solve for the unknown time t.
-----------------------
Step 3)
Since we want to solve for the time, and we have known W and P values, we use the equation t = W/P
-----------------------
Step 4)
t = W/P
t = 9514/347
t = 27.4178674351586
t = 27.4 seconds
-----------------------
Step 5)
The lawn mower ran for about 27.4 seconds. I rounded to three sig figs because this was the lower amount of sig figs when comparing 9514 and 347.
-----------------------
Note: we don't use the mass at all
A basketball has a volume of 300 cm3. If Michael pumped 200 cm3 and Fandi pumped another 200 cm3 into it then the total volume of air in the basketball is 400 cm3.
Answer:
...
Explanation:
If a basketball has a volume of 300 cm³. If Michael pumped 200 cm³ and Fandi pumped another 200 cm³ into it then the total volume of air in the basketball would be 300 cm³.
What is the matter?Anything which has mass to keep the same when comparing the hardness of the solid and occupies space is known as matter, mainly there are four states of matter solid liquid gases, and plasma.
As given in the problem if a basketball has a volume of 300 cm³. If Michael pumped 200 cm³ and Fandi pumped another 200 cm³.
The volume of the basketball would remain the same as the gas pumped in the basketball compress would take the volume of the basketball.
Thus, If Michael pumped 200 cm³ and Fandi pumped another 200 cm³ into it then the total volume of air in the basketball would be 300 cm³.
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what is the voltage of A simple circuit with one battery
Answer:
depends on the battery
A robot probe drops a camera off the rim of a 239 m high cliff on Mars, where the free-fall acceleration rate is -3.7m/s². Find the velocity with which the camera hits the ground.
Answer:
42.1m/s
Explanation:
Given parameters:
Height of cliff = 239m
Free fall acceleration = -3.7m/s²
Unknown:
Final velocity of the camera = ?
Solution:
When the body is falling under free fall, the acceleration = 3.7m/s² ;
The appropriate motion equation is:
V² = U² + 2gH
V = final velocity
U = initial velocity
g = free fall acceleration
H = height of the fall
Insert the parameters and solve;
U = 0
V² = 0² + 2 x 3.7 x 239
V² = 1768.6
V = 42.1m/s
A piece of wood from a nearby construction site floats near the shore of a lake. It floats in very calm water with half of its volume just above the surface. What is the density of this piece of wood
Answer:
Explanation:
The density of a substance can be described as the mass per volume of the substance. The density of the piece of wood described in the question can be calculated as the mass of the wood divided by the volume of the water the wood displaced (which was referred to in the question as making half of the wood's volume i.e half of the thickness of the wood was in the water).
Is Nuclear Energy renewable or nonrenewable? Use in your own words.
A photon has 8.0 x 10-15 J of energy. Planck's constant
is 6.63 x 10-34 Jos.
What is the frequency of the photon?
O 1.21 x 1019 Hz
O 8.3 x 10-20 HZ
O 1.21 10-19 Hz
O 8.3 x 1020 HZ
Answer:
^I dont know how he got 12 but the answer is A i believe
Explanation:Smart like dat
The frequency of a photon is related to its energy and Planck's constant by the equation:
frequency = energy / Planck's constant.
frequency =[tex](8.0 x 10-15 J) / (6.63 x 10-34 J) = 1.21 x 10^19 Hz[/tex]
Therefore, the correct answer is [tex]1.21 x 10^19 Hz[/tex]
What is Planck's constant?Planck's constant is a fundamental constant in physics that is related to the behavior of particles at the atomic and subatomic level. It is denoted by the letter "h" and is approximately equal to 6.63 x 10^-34 Joule-seconds. Planck's constant is named after Max Planck, a German physicist who proposed its existence in 1900 to explain the behavior of radiation emitted by black bodies.
Planck's constant plays a central role in quantum mechanics, which is the branch of physics that describes the behavior of particles at the atomic and subatomic level. It appears in a number of important equations, including the equation for the energy of a photon (E = hf) and the equation for the uncertainty principle (ΔxΔp ≥ h/4π).
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A 30kg boxed is pushed with a force of 20N. What is the boxes acceleration. Please show work
Answer:
The answer is 0.67 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass
From the question we have
[tex]a = \frac{20}{30} = \frac{2}{3} \\ = 0.6666666...[/tex]
We have the final answer as
0.67 m/s²Hope this helps you
What are the differences between elastic and inelastic collisions when it comes to how momentum is conserved and spread between the balls after a collision?
Answer:
Collision can be classified as either elastic or inelastic. The main difference between elastic and inelastic collisions is that, in elastic collisions, the total kinetic energy of the colliding objects before the collision is equal to the their total kinetic energy after the collision. In inelastic collisions, the total kinetic energy of the objects after the collision is less than the total kinetic energy of the objects before the collision.
GIVE. BRAINLIEST
PLEASE
A person applies a force of 200N to move an object initially at rest weighing 400N. What could be the coefficient of static friction between the object and the surface?
Answer:
[tex]\mu=0.5[/tex]
Explanation:
Given that,
Applied force, F = 200 N
Weight of the object, or the normal force, N = 400 N
We need to find the coefficient of static friction between the object and the surface.
The force of friction has the same magnitude as that of applied force. It can be given by :
[tex]F=\mu mg[/tex]
mg is weight of the object
[tex]\mu=\dfrac{F}{mg}\\\\\mu=\dfrac{200}{400}\\\\\mu=0.5[/tex]
So, the coefficient of static friction between the object and the surface is 0.5.
A freight train has a mass of 3.8 x 10^7 kg. The locomotive can exert a force of 6.5 x 10^5 N to pull the train.
Required:
a. How long does it take the train to go from rest to 50 km/hr?
b. If there is air resistance of 2.0 x 10^5 N, what is the acceleration of the train, and how long does it take the train to go from rest to 50 km/hr?
Answer:
(a) The time taken for the plane to reach 50 km/hr is 811.97 s
(b) (i) the acceleration of the plane is 0.012 m/s²
(ii) The time taken for the plane to reach 50 km/hr is 1172.85 s
Explanation:
Given;
mass of the freight train, m = 3.8 x 10⁷ kg
force applied to pull the train, F = 6.5 x 10⁵ N
a. How long does it take the train to go from rest to 50 km/hr?
Given;
initial velocity, u = 0
final velocity, v = 50 km/hr = 13.889 m/s
Apply Newton's second law of motion to determine the time traveled by the train at the given speed;
[tex]F = ma = \frac{m(v-u)}{t}\\\\t = \frac{m(v-u)}{F}\\\\t = \frac{3.8*10^7(13.889-0)}{6.5*10^5}\\\\t = 811.97 \ s[/tex]
(b)
(i) the acceleration of the plane
Given;
air resistance, = 2.0 x 10⁵ N
Apply Newton's second law of motion;
∑F = ma
6.5 x 10⁵ N - 2.0 x 10⁵ N = ma
4.5 x 10⁵ N = ma
[tex]a = \frac{4.5 * 10^5 }{m}\\\\a = \frac{4.5 * 10^5 }{3.8*10^7}\\\\a = 0.012 \ m/s^2[/tex]
(ii) time taken for the plane to reach 50 km/hr is given by;
[tex]F = \frac{m(v-u)}{t}\\\\t = \frac{m(v-u)}{F}\\\\t = \frac{3.8*10^7(13.889-0)}{4.5*10^5}\\\\t = 1172.85 \ s[/tex]
Romeo is a 68 kg astronaut. Juliet is a beautiful cosmonaut who is standing on the balcony of a 4.58 x 10^5kg space station that is at rest and out of gas. Romeo is floating 25 meters away from the space station’s center of mass, how strong is the force between Romeo and Juliet?
Answer:
F = 3.32 x 10⁻⁶ N
Explanation:
The force of attraction between two masses is given by Newton's Law of Gravitation, as follows:
F = Gm₁m₂/r²
where,
F = Force between Romeo and Juliet = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = mass of Romeo = 68 kg
m₂ = mass of space station = 4.58 x 10⁵ kg
r = distance = 25 m
Therefore,
F = (6.67 x 10⁻¹¹ N.m²/kg²)(68 kg)(4.58 x 10⁵ kg)/(25 m)²
F = 3.32 x 10⁻⁶ N
1.The
across each resistor is
the same in a series circuit.
) voltage
current
Answer:
The answer is Current.
Explanation:
In a series circuit, every component will have the same current.
In parallel circuit, all voltage of component remains the same.
Answer:
In a series circuit, each resistor has the same charge flowing through it.
Explanation:
If you have resistors arranged in a chain, the current only has one path to take which results in an equal charge in each resistor.
What is the main function of an earthworm organ
Answer:
brain
Explanation:
brain and blood
How do you determine: how many significant figures should you to round to when doing addition and subtraction?
draw a force body diagram represnting various forces on book
Explanation:
thanks me and dont forget to mark mi as brainlist
During a race, a runner runs with an average velocity of 4.26 m/s toward city hall. What is the runner’s displacement after 167s?
Answer:
d = 711.42 m
Explanation:
Given that,
The average velocity of a runner, v = 4.26 m/s
Time, t = 167 s
We need to find the runner's displacement.
The average velocity of an object is equal to the displacement per unit time. It can be given by :
[tex]v=\dfrac{d}{t}\\\\d=vt\\\\d=4.26\ m/s\times 167\ s\\\\d=711.42\ m[/tex]
So, the runner's displacement is 711.42 m.
This is my question
Answer:
N = 470 [N]
Explanation:
The normal force is defined as the reaction exerted by the surface where the body is located in the opposite direction to the weight component.
It can be easily calculated by means of the product of mass by gravitational acceleration.
N = m*g
where:
N = normal force [N] (units of Joules)
m = mass = 47 [kg]
g = gravity acceleration = 10 [N]
N = 47*10
N = 470 [N]
Which describes Hans Oersteds work with electricity and magnetism
Hans Oersteds works with electricity and magnetism is that he developed electromagnetism when he observed compass needle that was deflected when electric current flow through it.
What is electromagnetism?Electromagnetism is a type of electromagnetic force that occur between electric field and magnetic field and the interaction that exhaust between them and charged particles.
Therefore, Hans Oersteds works with electricity and magnetism is that he developed electromagnetism.
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A 12 volt car battery pushes charge through the headlight resistance of 10 ohms. How much current is passing through the circuit
Answer:50
Explanation:
The current flowing through the given circuit is 0.12 A.
The given parameters;
voltage of the battery, V = 12Vresistance of the headlight, R = 10 OhmsThe current passing through the headlight is calculated by applying Ohms law as shown below;
V = IR
where;
I is the current flowing the circuitR is the resistance to the flow of current in the circuitSubstitute the given parameters and solve the current flowing in the circuit;
[tex]V = IR\\\\I = \frac{V}{R} \\\\I = \frac{12}{10} \\\\I = 0.12 \ A[/tex]
Thus, the current flowing through the given circuit is 0.12 A.
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During a soccer game, the goalie kicks the ball out toward the other end of the field. It travels 60 yards in 8 seconds before landing on the ground. What is the velocity of the ball?
Answer:
velocity = 7.5 yards / second
Explanation:
velocity = distance / time
where distance = 60 yards
time = 8 seconds
plug in values into the formula:
velocity = 60 yards
8 seconds
velocity = 7.5 yards / second
Answer:
the velocity of the ball is 7.5 yards/second
Explanation:
A rock is sitting at the edge of a flat merry-go-round at a distance of 1.6 meters from the center. The coefficient of static friction between the rock and the merry-go-round is 0.70. What is the minimum angular velocity of the merry-go-round that would cause the rock to begin sliding off?
Answer:
ω = 2.1 rad/sec
Explanation:
As the rock is moving along with the merry-go-round, in a circular trajectory, there must be an external force, keeping it on track.This force, that changes the direction of the rock but not its speed, is the centripetal force, and aims always towards the center of the circle.Now, we need to ask ourselves: what supplies this force?In this case, the only force acting on the rock that could do it, is the friction force, more precisely, the static friction force.We know that this force can be expressed as follows:[tex]f_{frs} = \mu_{s} * F_{n} (1)[/tex]
where μs = coefficient of static friction between the rock and the merry-
go-round surface = 0.7, and Fn = normal force.
In this case, as the surface is horizontal, and the rock is not accelerated in the vertical direction, this force in magnitude must be equal to the weight of the rock, as follows:Fn = m*g (2)This static friction force is just the same as the centripetal force.The centripetal force depends on the square of the angular velocity and the radius of the trajectory, as follows:[tex]F_{c} = m* \omega^{2}*r (3)[/tex]
Since (1) is equal to (3), replacing (2) in (1) and solving for ω, we get:[tex]\omega = \sqrt{\frac{\mu_{s} * g}{r} } = \sqrt{\frac{0.7*9.8m/s2}{1.6m}} = 2.1 rad/sec[/tex]
This is the minimum angular velocity that would cause the rock to begin sliding off, due to that if it is larger than this value , the centripetal force will be larger that the static friction force, which will become a kinetic friction force, causing the rock to slide off.