The forces that hold atoms together in an element determine its
F. conductivity
G.melting temperature only
H.hardness only
J.melting temperature and hardness

Answer:

omggggggggg that is sooo confusing what grade are you in?

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\[/tex]

From the question

mass = 123 g

density = 12.8 g/mL

We have

[tex]volume = \frac{123}{12.8} \\ = 9.609375...[/tex]

We have the final answer as

Hope this helps you

Answer:

The answer is C) Gravity keeps all matter on Earth.

Explanation:

I took the test and this was correct!

(Not a fake answer like some, I promise!)

The answer would be B.

Answer:

4.81×10¹⁰ atoms.

Explanation:

We'll begin by converting 3.2 pg to Ca to grams (g). This can be obtained as follow:

1 pg = 1×10¯¹² g

Therefore,

3.2 pg = 3.2 pg × 1×10¯¹² g / 1 pg

3.2 pg = 3.2×10¯¹² g

Therefore, 3.2 pg is equivalent to 3.2×10¯¹² g

Next, we shall determine the number of mole in 3.2×10¯¹² g of Ca. This can be obtained as follow:

Mass of Ca = 3.2×10¯¹² g

Molar mass of Ca = 40.08 g/mol

Mole of ca=.?

Mole = mass /molar mass

Mole of Ca = 3.2×10¯¹² / 40.08

Mole of Ca = 7.98×10¯¹⁴ mole.

Finally, we shall determine the number of atoms present in 7.98×10¯¹⁴ mole of Ca. This can be obtained as illustrated below:

From Avogadro's hypothesis,

1 mole of Ca contains 6.02×10²³ atoms.

Therefore, 7.98×10¯¹⁴ mole of Ca will contain = 7.98×10¯¹⁴ × 6.02×10²³ = 4.81×10¹⁰ atoms.

Therefore, 3.2 pg of Ca contains 4.81×10¹⁰ atoms.

Given :

Mass of given magnesium chloride, m = 256 g.

To Find :

How many grams of chloride are there in 256 g of magnesium chloride.

Solution :

Molecular formula of magnesium chloride is [tex]MgCl_2[/tex].

Molecular formula of [tex]MgCl_2[/tex] is, M = 95.211 g/mol .

Mass of chlorine in 1 mol of [tex]MgCl_2[/tex]  is , m = 35.5 × 2 = 71 g.

So, amount of chlorine in 256 gram [tex]MgCl_2[/tex] :

[tex]m =\dfrac{71\times 256}{95.211}\\\\m = 190.90\ g[/tex]

Hence, this is the required solution.

Answer:

The correct answer is 0.22 mol Te.

Explanation:

First, we have to calculate the mass of Te in the sample. We simply multiply the sample mass by the percentage of Te (28.53%= 28.53/100)

100.00 g x 28.53/100 = 28.53 g Te

The molar mass of Te is 127.60 g. Thus, the mass of 1 mol of Te is 127.60 g. With this, we calculate how many moles of Te there are in 28.53 g of Te:

28.53 g Te x 1 mol Te/127.60 g Te= 0.223 mol ≅ 0.22 mol

Answer:

Liquid: water

Solid: Rocks

Gas: Air

Explanation:

Answer:

For number 5 it is the 2nd one some stants has a mass of 1.25 g And the 2nd 1 number 6It is the 1st 1A subject has a melting point of 40

Answer:

This should help :)

Explanation:

The cart has a lot of potential energy, little kinetic energy, and little thermal energy when it is in position A. The kinetic energy and potential energy both rise as the cart moves towards position B, while the thermal energy rises as thermal energy from the track is transmitted to the cart through friction

Kinetic energy, which may be seen in the movement of an object, particle, or group of particles, is the energy of motion.

The cart has a lot of kinetic energy, little potential energy, and little thermal energy after it reaches position C. The cart has some thermal energy and a high potential energy at point D.

It also has a low kinetic energy. Gravity, momentum, and friction are all connected with potential energy, kinetic energy, and thermal energy, respectively.

Position A is when the potential energy is at its highest, and its kinetic energy is at its peak in position C and at its lowest in position A, whereas thermal energy is at its peak in position B and at its lowest in position A.

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Answer:

biology

Explanation:

biology is the study of living g things

Answer:

The answer you would be looking for is Biology

Answer:

option (3) P is the correct answer.

Explanation:

electronegativity of As is 2.0

electronegativity of Li is 1.0

Electronegativity of P is 2.1

Electronegativity of Al is 1.5

electronegativity of Ge is 1.6

So P (phosphorus) would be expected to have highest electronegativity.

Electronegativity measures the Capability of an atom to pull the shared paired of electrons.

Electronegativity is determined by the following factors

nuclear charge.

the number and the location of different electrons inside the atomic shells.

Answer:

Its B

Explanation:

Because im just built different

The statement  featuring the single replacement reaction has been statement B.

The single replacement reaction has been defined as the reaction of the highly reactive element with the compounds, that results in the formation of the new compound with the replacement of the less reactive element.

The single replacement reaction can be given as:

G + XY [tex]\rightarrow[/tex] GY + X

In the reaction, G being more reactive than X has been able to displace X and forms bond with Y. Thus, statement  featuring the single replacement reaction has been B.

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Answer:

kg, m^3, kg/m^3

Explanation:

the SI units for these are:

mass: kilogram

volume: cubic meter

density: kilogram per cubic meter

Answer:

C, increases/decreases

Explanation:

As you move down a group on the periodic table, the electronegativity of an element decreases because the increased number of energy levels puts the outer electrons very far away from the pull of the nucleus.

Answer:

Explanation:

During a physical temperature change, one substance, such as water will be heated. Because one compound is mixed in with another. Therefore, these reactants produce a product. When the reactants are mixed, the temperature change caused by the reaction is an indicator of a chemical change.

Answer:

c. baking soda

Explanation:

Answer: A homogeneous mixture is a solid, liquid or gaseous mixture that has the same proportions of its components throughout any given sample.

Explanation:

A homogeneous mixture is composed of different parts that are indistinguishable in their color, texture, or appearance.

The extent of the elements' mixing together and the uniformity of their composition distinguish heterogeneous mixtures from homogeneous ones.

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Answer:

d.All of the above

Explanation:

They can do all of the above

Answer:

D

Explanation:

The nucleus was postulated as small and dense to account for the scattering of alpha particles from thin gold foil, as observed in a series of experiments performed by undergraduate Ernest Marsden under the direction of Rutherford and German physicist Hans Geiger in 1909.

Answer:

7630

Explanation:

eAnswer:

Explanation:

Math

Answer:

b is the answer

Explanation:

non metals are not shiny, brittle, unmalleable, and are poor conductors of thermal energy and electrical current.

A nonmetal is brittle, dull, and low in density.  

• Non-metals refer to the elements that produce negative ions by gaining or accepting electrons. The non-metals generally possess 4, 5, 6, or 7 electrons in their valence shell. The non-metals are those, which are devoid of all the metallic properties.  

• The non-metals in their solids-state are brittle, thus, they lack ductility and malleability exhibited by the metals.  

• The non-metals are not shiny like metals, they are dull in color.  

• The non-metals seem to possess low density, primarily as non-metals seem to prevail either in a liquid or solid-state. The non-metals lack the dense and closed packing in the lattice, which is seen in metals.  

Thus, non-metals are brittle, dull, and low in density.  

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Answer:

Mass of liquid B = 271.2 gram

Explanation:

Given:

Density of liquid A = 1000 kg/m³

Density of liquid B = 600 kg/m³

Density of mixture = 850 kg/m³

Mass of mixture = 1 kg

Assume:

Volume of liquid A = Va

Volume of liquid B = Vb

So,

Volume of mixture = Va + Vb

Mass of liquid A = 1000(Va)

Mass of liquid B = 600(Vb)

Mass of mixture = Mass of liquid A + Mass of liquid B

1 = 1000(Va) + 600(Vb)

Volume of mixture = 1 / 850

So,

(1/850) = Va + Vb

Vb = (1/850) - Va

1 = 1000(Va) + 600[(1/850) - Va]

Va = 7.25 × 10⁻⁴

Vb = (1/850) - Va

Vb = (1/850) - [7.25 × 10⁻⁴]

Vb = 4.25 × 10⁻⁴

Mass of liquid B = 600(Vb)

Mass of liquid B = 600(4.25 × 10⁻⁴)

Mass of liquid B = 271.2 gram

The mass of liquid B in the 1 Kg mixture is 300 g

Let the volume of liquid A be Va

Let the volume of liquid B be Vb

From the question given above, the following data were obtained:

Density of liquid A = 1000 kg/m³

Density of liquid B = 600 kg/m³

Density of mixture = 850 kg/m³

Mass of mixture = 1 kg

For Liquid A:

Density of liquid A = 1000 kg/m³

Volume of liquid A = Va

Mass of Liquid A =?

Mass = Density × Volume

Mass of Liquid A = 1000 × Va

For Liquid B:

Density of liquid B = 600 kg/m³

Volume of liquid B= Va

Mass = Density × Volume

Mass of Liquid B = 600 × Va

Density of mixture = 850 kg/m³

Mass of mixture = 1 kg

Volume = mass /density

Volume of mixture = 1 / 850

Mass of mixture = 1 Kg

Mass of mixture = Mass of liquid A + Mass of liquid B

Volume of mixture = Va + Vb

Volume of mixture = 0.0012 m³

Thus,

0.0012 = Va + Vb

Substitute Vb in equation 2 into equation (1)

1 = 1000(Va) + 600[0.0012 – Va]

1 = 1000Va + 0.72 – 600Va

Collect like terms

1 – 0.72 = 1000Va – 600Va

0.28 = 400Va

Divide both side by 400

Va = 0.28 / 400

Volume of mixture = 0.0012 m³

Volume of liquid A (Va) = 0.0007 m³

Vb = 0.0012 – Va

Vb = 0.0012 – 0.0007

Volume of liquid B (Vb) = 0.0005 m³

Mass of liquid B = 600(Vb)

Mass of liquid B = 600(0.0005)

Mass of liquid B = 0.3 Kg

Multiply by 1000 to express in grams

Mass of liquid B = 0.3 × 1000

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Answer:

The amino sequence of an octapeptide can be determined by :

i.Amino acids present in the peptide

ii.By the behaviour shown by the treatment of these material with different biological and chemical reactions

As shown ammonium was released from the peptide,which shows that the peptide contains either Asn or Gln.

As there is presence of Asp in the amino acid analysis which indicates that the octapeptide contains Asp.

Acid hydrolysis hydrolyzes the peptide bonds which yields a Ala-Val  which is the result of partial acid hydrolysis.

Chymotrypsin is on the C-terminal side of the aromatic amino acids Phe, Tyr, and Trp. The peptide has Tyr which indicates that  the two present tetrapeptides after chymotrypsin treatment are fourth and eighth amino acids i-e N--Tyr-C and Tyr as the fourth amino acid and Ala-Val somewhere in the octapeptide

As Arg is only present on the C terminal side  of the Trypsin cleavage therefore Arg must be the second or the sixth amino acid for the two dipeptides to form as a result of arginine treatment of a tetrapeptide

Cyanogen bromide cleaves on the C-terminal side of Met residues. For free Tyr to be produced from cyanogen bromide treatment of one of the tetrapeptides, Met must be either the third or seventh amino acid. Because Ala was present in both tetrapeptides, Ala must be either the first or fifth amino acid, present in the same tetrapeptide as Arg and Met,i-e N.-Tyr-C and Ala-Val somewhere in the octapeptide and Ala-Arg-Met as the first, second, and third or fifth, sixth, and seventh amino acids and Tyr as the fourth amino acid.

One of the tetrapeptides contains Ala-Val as its second and third amino acids and Asn as its N-terminal amino acid. Therefore two combinations are possible as below

N-Asn-Ala-Val-Tyr-Ala-Arg-Met-Tyr-C or N-Ala-Arg-Met-Tyr-Asn-Ala-Val-Tyr-C

Answer:

The amino aciid sequence of an octapeptide can be determined from the amino acids that are present in the peptide and from the results of different chemical and biological treatments.

One equivalent of ammonium was released fro the peptide, indicating that the peptide contains either Asn or Gln. The presence os Asp in the amino analysis indicates that the octapeptide contains Asn.

A) Acid hydrolysis hydrolyzes peptide bonds. The dipeptide Ala-Val is obtained by partial acid hydrolysis. The indicates that Ala-Val is present in the peptide

B) Chymotrypsin cleaves on the C-terminal side of the aromatic amino acids. Phe, Tyr, and Trp. The peptide contains only Tyr. The presence of tetrapeptides after the treatment of ohymotrypsin indicates that Tyr is the fourth and eighth amino acids.

N-Tyr-C and Tyr present as the fourth amino acid. in constrast, Ala-Val is present in the octapeptide

C) Trpsin cleaves on the C-terminal side of Arg and Lys residues. only Arg is present in the octapeptide. Arg must be the second or sixth amino acid, for two dipeptide to be formed from arginine during the treatment of one tetrapeptide.

D) Cyanogen bromide cleaves on the C-terminal side of Met residues. For free Tyr to be produced from cynogen bromide treatment of one of the tetrapeptides, Met must be either the third or seventh amino acid. Because Ala is present in both tetrapeptides, Ala must be either the first or fifth amino acid, present in the same tetrapeptide as Arg and Met.

In addition, presence of N-...-Tyr-C and Ala-Val in the octapeptide and Ala-Arg-Met as the first, second, third or fifth, sixth or seventh amino acids and Tyr as the fourth amino acid.

E) One of the tetrapides contains Asn as its N-terminal amino acid, and Ala-Val as its second and third amino acids. Two octapeptides are possible from this peptide analysis.

The amino acid sequence of the octapeptide is the following:

N-Asn-Ala-Val-Tyr-Ala-Arg-Met-Tyr-C:

N-Ala-Arg-Met-Tyr-Asn-Ala-Val-Tyr-C:

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Answer:

Rb = +1 , Sr = +2, In= +3,  Sn = +4, Sb= +5

Explanation:

Formula:

Zeff = Z - S

Z = atomic number

S = number of core shell or inner shell electrons

For Sn:

Electronic configuration:

Sn₅₀ = [Kr] 4d¹⁰ 5s² 5p²

Zeff = Z - S

Zeff = 50 - 46

Zeff = +4

For Rb:

Electronic configuration:

Rb₃₇ = [Kr] 5s¹

Zeff = Z - S

Zeff = 37 - 36

Zeff = +1

For Sb:

Electronic configuration:

Sb₅₁ = [Kr] 4d¹⁰ 5s² 5p³

Zeff = Z - S

Zeff = 51 - 46

Zeff = +5

For In:

Electronic configuration:

In₄₉ = [Kr] 4d¹⁰ 5s² 5p¹

Zeff = Z - S

Zeff = 49 - 46

Zeff = +3

For Sr:

Electronic configuration:

Sr₃₈= [Kr]  5s²

Zeff = Z - S

Zeff = 38 - 36

Zeff = +2

Answer:

what are the options?

Explanation:

Answer:

7.47 × 10^-1 M-1 s-1

Explanation:

Using the form k[A]^m[B]^n we arrive at the fact that the rate constant of the reaction can be written in the form;

Rate = k[NO2] [CO] where both m and n =1

We can use data from any of the experiments to establish the rate constant hence;

From experiment 1

[NO2] = 0.374M

[CO] = 0.300 M

R= 8.39 × 10^-2

Hence k =8.39 × 10^-2 / [0.374] [0.300]

k= 7.47 × 10^-1 M-1 s-1