The first step in the formation of all three products is the loss of the ots leaving group to give a carbocation intermediate. this intermediate is resonance-stabilized, and products b and c are generated from a different resonance structure than the one used to generate product a. draw the other resonance structure (using the carbon skeleton provided) and add curved arrow(s) to convert the first resonance structure into the second one.

The most common way to monitor the rate of reaction is by observing the increase in the absorbance of the solution.

The rate of reaction is the rate at which reactants are converted into products or the rate at which the reactants disappear.

Given that the reaction is a colorimetric reaction, the most common way to monitor the rate of reaction is by observing the increase in the absorbance of the solution.

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Answer:

b

Explanation:

b is the ketone because it is and that's a fact

Answer:

D

Explanation:

Ketones are a class of organic compounds that have an Oxygen double bonded to the middle of the main carbon chain.

Option A is not a ketone (despite having an Oxygen double bonded to the middle of the main carbon chain) because it has an adjacent single bonded Oxygen in the main carbon chain.  This type of compound is classified as an "Ester".

Option B is not a ketone, but is instead classified as an aldehyde, a group of compounds with their Oxygen double bonded at the end of the main carbon chain.

Option C is not a ketone (despite having an Oxygen double bonded to the middle of the main carbon chain), but is instead classified as an Carboxylic Acid, because it has an adjacent single bonded Oxygen in the main carbon chain, and both of these pieces (with the single bonded O pointing outward) are at the end of the main carbon chain.

Option D is a ketone because it does have an Oxygen double bonded somewhere to the middle of main carbon chain, not at an end, and not with another Oxygen single bonded adjacently in the carbon chain.  Specifically, this ketone is "2-pentanone" or "methyl propyl ketone"

Answer:

93.5 moles N₂

Explanation:

To find the moles, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = number of moles

-----> R = constant (0.0821 atm*L/mol*K)

-----> T = temperature (K)

You can plug the given values into the equation and simplify to find moles. The final answer should have 3 sig figs to match the lowest number of sig figs among the given values.

P = 95.0 atm                  R = 0.0821 atm*L/mol*K

V = 224 L                       T = 2773 K

n = ?

PV = nRT

(95.0 atm)(224 L) = n(0.0821 atm*L/mol*K)(2773 K)

21280 = n(227.6633)

93.5 = n

Answer:

93.5 moles N₂

Explanation:

You can plug the given values into the equation and simplify to find moles. The final answer should have 3 sig figs to match the lowest number of sig figs among the given values.

P = 95.0 atm                  R = 0.0821 atm*L/mol*K

V = 224 L                       T = 2773 K

n = ?

PV = nRT

(95.0 atm)(224 L) = n(0.0821 atm*L/mol*K)(2773 K)

21280 = n(227.6633)

93.5 = n

Explanation:

The greatest progress in reducing atmospheric levels of lead pollution resulted from the elimination of leaded gas.

Atmospheric lead pollution refers to the presence of lead particles in the atmosphere.

Lead is a pollutant which affects the respiratory system.

Fuels that contains lead when burned releases lead into the atmosphere.

Therefore, the greatest progress in reducing atmospheric levels of lead pollution resulted from the elimination of leaded gas.

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Answer:For jewellery and ornaments, gold, platinum and silver are being used.

For building purposes, iron and steel can be used.Iron and aluminium are used as utensils.

The thermometer uses mercury and helps to monitor the temperature.

The insulation wires are made of aluminium.

Aluminium foils are being used as wrappers for food.In sweets, a silver foil is being used.

To avoid rusting, zinc is used for galvanizing.In vehicles, iron is being used.

For making cable wires, copper is being used.

Explanation:

Answer:

1. For jewellery and ornaments, gold, platinum and silver are being used.

2. For building purposes, iron and steel can be used.

3. Iron and aluminium are used as utensils.

4. The thermometer uses mercury and helps to monitor the temperature.

5. The insulation wires are made of aluminium.

6. Aluminium foils are being used as wrappers for food.

7. In sweets, a silver foil is being used.

8. To avoid rusting, zinc is used for galvanizing.

9. In vehicles, iron is being used.

10. For making cable wires, copper is being used.

Iced tea's energy increases while the energy of the glass decreases.

Energy is the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other forms

Iced tea's energy increases while the energy of the glass decreases because the ice is getting warmer so the glass is also getting warmer. meaning that the glass is decreasing in energy while the ice tea is increasing in energy.

Hence, iced tea's energy increases while the energy of the glass decreases.

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Answer:

6) 47588

4.7 * 10 power 4 ( by rounding off)

7) 1 mm ---> 1,000,000

? 120

120 * 1 / 1000000

12/ 100000

0.0012

1.2 * 10 power -4.

8) Volume is the amount of space something occupies

The label appears in the organic product and not in the water owing to the fact that water is eliminated as -OCH3 replaces -OH.

Isotopic labelling is one of the methods by which a chemical reaction is studied. In this case, we can see that the reaction occurs with the hemiacetal reacting with a labeled methanol.

By looking at the reaction products we can see that the label appears in the organic product and not in the water owing to the fact that water is eliminated as -OCH3 replaces -OH.

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Answer: C

Explanation:

iron sulfide.

Answer:

C. Iron sulfide

Explanation:

Stay safe, stay healthy and blessed

Have a good day

Thank you

If the earth is completely an oxidizing atmosphere, materials would ignite spontaneously when they are exposed to air.

Let us recall that oxidation has to do with an increase in oxidation number. If the earth is left as an oxidizing atmosphere without any attenuation, we can not have pure substances.

Secondly, materials would ignite spontaneously when they are exposed to the oxidizing atmosphere of the earth.

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Answer: Initially when the student spilled the bottle of ammonia the ammonia gas particles diffused with the particles of air in the room. We know that the rate of diffusion of gases is very high. So the entire room filled up with the pungent smell of ammonia.

When he opened the doors and windows and switched on the exhaust fan, the air from the room along with the ammonia gas diffused with the air outside the room.Moreover, outside air entered into the room so the concentration of ammonia gas in the room air reduced.Due to these reasons the student got relief.

Answer:

See attached image.

Explanation:

Answer:

Tin bromine = Snbr2

aluminum fluorate = AlFe3

iron oxide = Fe2o3

potassium chloride = KCL or 2KCL = K2CL2

All Pairs are correct

+3

Hence, the magnetic behaviour of the complex is paramagnetic. The oxidation number of the central metal atom: The oxidation number of the metal iron is +3.

Answer:

the oxidation number of iron in the complexion is +3 or x=+3

N₂ + 3H₂ → 2NH₃

moles N₂ = 1/3 x 6.25 = 2.083

Answer:

2.083 moles of N₂ would be required to react with 6.25 moles of H₂.

Explanation:

Let us first write the balanced chemical equation :

      N₂ + 3H₂ → 2NH₃

Therefore from this equation it is clear that:

3 moles of H₂ require 1 mole of N₂

∵ 1 mole of H₂ requires [tex]\frac{1}{3}[/tex]  moles of N₂

∵ 6.25 moles of H₂ requires [tex]\frac{(1*6.25)}{3}[/tex][tex]=2.083[/tex] moles of N₂

MOLE CONCEPT :

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter. A mole is defined as the amount of substance containing the same number of discrete entities (such as atoms, molecules, and ions) as the number of atoms in a sample of pure 12C weighing exactly 12 g. One Latin connotation for the word “mole” is “large mass” or “bulk,” which is consistent with its use as the name for this unit. The mole provides a link between an easily measured macroscopic property, bulk mass, and an extremely important fundamental property, number of atoms, molecules, and so forth.

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Fluorite is harder than gypsum but softer than apatite. Thus, the correct option is B.

The hardness of any element may be defined as the capability of a material to oppose the process of deformation and remains in actual shape precisely.  

According to the table of hardness scales by Mohs, the increasing order of given hardness of given elements is as follows:

Gypsum < Fluorite < Apatite.

Therefore, Fluorite is harder than gypsum but softer than apatite. Thus, the correct option is B.

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This happens because the beaker is open.

The Law of Mass Conservation says that in a close system all the mass and energy should be the same.

If the system is open, as in the case, we can have loss of mass, due to formation of gas, that will leave the beaker to the environment, and we can also have loss of energy, because the system will exchange the energy, as heat, with the environment, causing a loss on the total energy.

Answer:

Its C its C its C

Explanation:

i dislike expert verifeid beacause he wont say C

Answer:

CO_(2)` molecules removed `= 10^(21)` <br> No. of `CO_(2)` molecules left `= 2.74 xx 10^(21) - 10^(21) = 1.74 xx10^(21)` <br>

Explanation:

Answer:

Calcite

Explanation:

When in contact with hydrochloric acid, calcite releases carbon dioxide gas.

Answer:

0.736

Explanation:

*I am not sure what you mean by "carbon tetrahedral". I'm assuming you are just referring to individual carbon.*

To find the mole percent, you need to (1) convert grams benzene and grams carbon to moles (via their molar masses) and then (2) calculate the mole fraction (via the mole fraction formula).

(Step 1)

Benzene = C₆H₆

Molar Mass (C₆H₆) = 6(12.01 g/mol) + 6(1.008 g/mol)

Molar Mass (C₆H₆) = 78.108 g/mol

70 g C₆H₆          1 mole
---------------  x  ------------------  =  0.896 mole C₆H₆
                         78.108 g

Molar Mass (C) = 12.01 g/mol

30 g C           1 mole
------------  x  -----------------  =  2.50 mole C
                       12.01 g

(Step 2)

                                           moles solute
Mole Fraction  =  ----------------------------------------------
                              moles solute + moles solvent

                                              2.50 mole C
Mole Fraction  =  -------------------------------------------------  =  0.736
                             (0.896 mole C₆H₆ + 2.50 mole C)

Answer:

0.893mol

Explanation:

n = m ÷ M

= 275 ÷ (23 + 80)

= 2.67 mol

* now use the Mol ratio *

NaBr : FeBr3

6 : 2

2.67 : x

5.67 = 6x

n( FeBr3 ) = 0.893 mol

The percent yield of the reaction is 63.4%; option D

Percent yield of a reaction is given as:

Actual yield of the reaction = 0.856 g

Expected yield = 1.8/32 * 4/5 * 30 = 1.35 g

Percent yield = 0.856/1.35 * 100 % = 63.4 %

Therefore, the percent yield is 63.4%.

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Answer:

B

Explanation:

The answer is B, O2

O₂ is the limiting reagent.

A limiting reactant is described as the one that will be consumed first in a chemical reaction.

C₁₀H₈ + 12O₂ → 10CO₂ + 4H₂O

Given, Mass of O₂ = 23.3 g

           Mass of C₁₀H₈ = 18.3 g

Molar mass of O₂ = 32 g

No. of moles of O₂ = 32/23.3 = 1.4 moles

Molar mass of C₁₀H₈ = 128 g

No. of moles of C₁₀H₈ = 128/18.3 = 6.9 = 7 moles

According to the equation,

1 mole of C₁₀H₈ yields 10 moles of CO₂. So, 7 moles of C₁₀H₈, give 70 moles of CO₂.

12 moles of O₂ yields 10 moles of CO₂. So, 1.4 moles of O₂ give 1.16 moles of CO₂.

We do know, however, that based on our balanced equation, if we were to totally react all 1.4 moles of O2, we could only produce a maximum of 1.16 moles of CO2. Even while there is enough C10H8 to generate more, the amount of O2 we have is a limiting factor because it will be consumed first.

So, our limiting reactant is O₂.

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The concentration (molarity) of the Ca(OH)₂ solution needed to neutralize 31.5 mL of 0.1 M HC₂H302 solution is 0.162M (option D).

The molarity of a solution can be calculated using the following formula:

CaVa = CbVb

Where;

31.5 × 0.1 = 19.4 × Cb

3.15 = 19.4Cb

Cb = 0.162M

Therefore, the concentration (molarity) of the Ca(OH)₂ solution needed to neutralize 31.5 mL of 0.1 M HC₂H302 solution is 0.162M.

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Answer:

Electric current

Definition:

The time rate of flow of electric charge, in the direction that a positive moving charge would take and having magnitude equal to the quantity of charge per unit time: measured in amperes.

Everything begins inside in the battery. The battery's zinc metal undergoes oxidation; here is where the flow of electrons into the conductors begins. Electrical field attraction will lead the wire's existing electrons to move towards the battery's positive terminal, and the loose electrons caused by the zinc metal will begin to fill the wire's empty spaces. process continues until the zinc metal's oxidation ceases. At rechargeable batteries, the oxidation-reduction process is also reversed by charging the battery, allowing the stored electrons in the positive terminal to flow back to the zinc metal's negative terminal.

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