∠1 and ∠2 are congruent because they are a pair of alternate interior angles , Option C is the right answer.
What are Parallel Lines ?When two lines do not meet at any point and the distance between them remains constant , then the two lines are called parallel to each other .
It is given that the parallel lines are cut by a transversal and the angles are marked
The angle 1 and angle 2 are congruent because they are pair of alternate interior angles .
Therefore Option C is the right answer.
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Follow the steps to find the
area of the shaded region.
First, use the formula
below to find the area
of the whole sector.
=
angle of sector
360
¹) πr²
Sector Area = [?] cm²
Round to four decimal places.
Sector Area
14 cm
46°
14 cm
Enter
Based on the calculations, the area of the whole sector is equal to 4,508 cm².
Given the following data:
Angle of sector = 46°.Radius of circle = 14 cm.How to calculate the area of a sector?Mathematically, the area of a sector can be calculated by using this formula:
Area of sector = θr²/2
Where:
r is the radius.θ is the central angle.Substituting the given parameters into the formula, we have;
Area of sector = 46 × 14²/2
Area of sector = 46 × 196/2
Area of sector = 9016/2
Area of sector = 4,508 cm².
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Polynomial of lowest degree with zeros of 3/4 (multiplicity 2) and 1/3 (multiplicity 1) and with f(0) = -81
The polynomial is given by f(x) = 9(4x − 3)² (3x - 1) .
What is a Polynomial ?A polynomial is an expression that consists of indeterminate , Coefficients , exponents and mathematical operations.
It is given that
The zero of the function is at 3/4 with multiplicity of 2 = (x - 3/4)²
The zero of the function is at 1/3 with multiplicity of 1 = (x - 1/3)
The polynomial can be written as
f(x) = a (4x − 3)² (3x - 1)
-81 = a (0 − 3)² (0 -1)
a = 9
f(x) = 9(4x − 3)² (3x - 1)
Therefore the polynomial is given by f(x) = 9(4x − 3)² (3x - 1) .
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Consider a student loan of $12, 500 at a fixed APR rate of 9% for 25 years.
a. Calculate the monthly payment
b. Determine the total amount paid over the term of the loan
c. Of the total amount paid, what percentage is paid toward the principal and what percentage is paid for interest.
The monthly payment is; $104.9; The total amount paid over the term of the loan is; $31470
How to calculate APR?
We are given;
Loan principal = $12,500
Interest rate = 12%
Number of payments per year = 12 payments per year.
Loan term = 25 years.
Formula for monthly payment is;
PMT = (p * APR/n)/[1 - (1 + APR/n)^(-nY)]
Where;
p is principal
APR is interest rate
n is number of payments per year
Y is loan term
Thus;
PMT = (12500 * 0.09/12)/[1 - (1 + 0.09/12)^(-12 * 25)]
PMT = 93.75/(1 - 0.106288)
PMT = $104.9
B) Total amount paid over the loan term is;
A = PMT * m * n
where;
m is number of months in a year,
n is number of years
A = 104.9 * 12 * 25
A = $31470
C) The principal as a percentage of the loan is;
P/A = 12500/31470
P/A = 39.72%
Percentage paid for interest is = 100% - 39.72% = 80.28%
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What is:
[tex]5x + 5 = 5 \times (10 \div 5)[/tex]
Solve this equation.
Answer:
x = 1
Step-by-step explanation:
To solve an equation for a variable, we need to isolate (get the variable alone on one side)
(the order of the following was determined by PEMDAS)
5x + 5 = 5 (10 ÷ 5) [simplify inside parentheses]
5x + 5 = 5 (2)
5x + 5 = 10
- 5 -5 [subtract 5 from both sides to isolate x]
5x = 5
÷5 ÷5 [divide both sides to get x]
x = 1
hope this helps!!
What is the solution to the linear equation?
-12 +3b-1-5-b
b=-2
b = -1.5
b = 1.5
b = 2
Answer:
[tex]b = 2[/tex]
Step-by-step explanation:
[tex]( - 12 - 1 - 5) + (3b - b) \\ - 18 + 2b \\ 2b - 18 \\ b = 2[/tex]
Which value is a solution to the inequality x – 4 > 15.5? A) x = 21.4 B) x = 17.3 C) x = 15.5 D) x = 19.3
Answer:
A.) x = 21.4
Step-by-step explanation:
When solving the inequality, you can treat the sign like an equal sign. To isolate the "x" variable, you can add "4" to both sides. This eliminates the -4 from the right side.
You are left with the inequality:
x > 19.5
If "x" must be greater than 19.5, the only answer that satisfies this is A.) x = 21.4. All of the other answers are less than 19.5.
[tex]\bf{x -4 > 15.5}[/tex]
[tex]\bf{Add \ 4 \ to \ both \ sides.}[/tex]
[tex]\bf{x-4+4 > 15.5+4 }[/tex]
[tex]\bf{x > 19.5 === > Answer }[/tex]
[tex]\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]
for what value of k will the relation not be a function
R={(k-8.3+2.4k,-5),(3/4k,4)}
Step-by-step explanation:
hope you can understand
i need to Match each equation that represents each situation.
Step-by-step explanation:
this is quite easy, when you use just common sense and identify the right numbers and variable names.
they is nothing special needed, you don't even need to create the equations yourself.
$4.99 per pound. buys b pounds and pays $14.95.
14.95 = 4.99 × b
$4.99 per pound. buys b pounds and pays c.
this is exactly the same as before, just that this time the total amount is not given as a constant but as a variable.
c = 4.99 × b
d dollars per pound. buys b pounds and pays t.
the same as the 2 cases before, just now everything is a variable. no more constants, but otherwise the completely same structure and method.
t = d × b
earned $275, which is $45 more than Noah ("n").
$275 = n + $45
earned m dollars, which is $45 more than Noah ("n").
m = n + $45
earned m dollars, which is y dollars more than Noah (we are asked that Noah's earnings are now called "v").
here your teacher made a mistake.
sure, the only remaining answer is
v = m + y
but it is not correct. given the names of the prime and associated variables the correct answer would be
m = v + y or v = m - y
A survey of 600 randomly selected high school students determined that 290 play organized sports. what is the probability that a randomly selected high school student plays sports
Answer:
29/60
Step-by-step explanation:
probability of playing is 290/600 which when simplified is29/60
What is the asymptote of the graph of f(x)=5x−1?
The asymptotes of the graph of [tex]f(x) = \frac{5}{x - 1}[/tex] are as follows:
Vertical: x = 1.Horizontal: y = 0.What are the asymptotes of a function f(x)?The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.In this problem, the function is:
[tex]f(x) = \frac{5}{x - 1}[/tex]
For the vertical asymptote, we have that:
[tex]x - 1 = 0 \rightarrow x = 1[/tex].
For the horizontal asymptote, we have that:
[tex]y = \lim_{x \rightarrow \infty} f(x) = \frac{5}{\infty - 1} = 0[/tex].
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1. The function j(x) is shown on the graph below.
Answer:
1) k = -3
2) B. The curve would be narrower, but the vertex would be in the same position.
Step-by-step explanation:
Transformations
For a > 0
[tex]f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}[/tex]
[tex]f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}[/tex]
[tex]f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}[/tex]
[tex]f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}[/tex]
[tex]y=a\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis (vertically) by a factor of}\:a[/tex]
[tex]y=f(ax) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{a}[/tex]
[tex]y=-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}[/tex]
[tex]y=f(-x) \implies f(x) \: \textsf{reflected in the} \: y \textsf{-axis}[/tex]
Question 1
When a graph is shifted up or down we add or subtract the number of units it has shifted from the function.
From inspection of the graph, the vertex of function j(x) is (0, 2)
From inspection of the graph, the vertex of function j(x) + k is (0, -1)
Therefore, function j(x) has been translated 3 units down.
Therefore, the value of k is -3, since the function of the graph is j(x) -3
Question 2
When discussing the stretching of curves, it is usual to always refer to it as a "stretch" rather than a stretch or compression.
If the scale factor a is 0 < a < 1 then the graph gets wider.
If the scale factor a is a > 1 then the graph gets narrower (i.e. "compressed").
h(x) to h(2x) means that the function h(x) has been stretched horizontally by a factor of 1/2. The other way to say this is that is have been compressed horizontally by a factor of 2. In any case, as a > 1 the graph gets narrower.
Therefore, the vertex would stay in the same place but the curve would be narrower.
Simplify this equation 10 ^-8
Why can’t 1.07 pounds of sugar be compared to 1.23 cups of sugar.
What is the domain of the function
f(x) = [tex]\sqrt{1/3 x + 2}[/tex]
The domain of the function is:
D: {x ∈ R | x ≥ -6}
How to get the domain of the function?
Here we have:
[tex]f(x) = \sqrt{(1/3)*x + 2}[/tex]
Remember that the argument of a square root can be only numbers equal to or larger than zero, so the domain of that function is such that:
[tex](1/3)*x + 2 \geq 0[/tex]
Now we can solve that for x.
[tex](1/3)*x + 2 \geq 0\\(1/3)*x \geq -2\\\\x \geq -2*(3/1)\\\\x \geq -6[/tex]
So the domain of the function is:
D: {x ∈ R | x ≥ -6}
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Answer:
The domain of the function is:
D: {x ∈ R | x ≥ -6}
What is the equation for a cosecant function with vertical asymptotes found at x equals pi over 3 plus pi over 3 times n comma such that n is an integer?
f (x) = 3csc4x
g(x) = 3csc2x
h(x) = 4cscx
j (x) = 4csc3x
Despite not being a part of the function graph, a vertical asymptote is a vertical line that serves as a guide f (x) = 3csc4x.
How do you find a vertical asymptote?The denominator of the function, n(x), is the place where vertical asymptotes can be located.
If the numerator, t(x), is not zero for the same value of x, then the vertical asymptotes can be determined by solving the equation n(x) = 0 where n(x) is the denominator.
f (x) = 3csc4x.
Periodicity of 3csc(4x) : π / 2
Domain of 3csc(4x) :
Solution : π / 2 n<x < π / 4 + π / 2 n or π /4 + π / 2 n< x < π /2 + π /2 n
Interval Notation : ( π / 2 n,π /4 + π /2)n) ∪ (π / 4 + π /2 n, π / 2 + π /2 n)
Range of 3csc(4x) :
Solution : f(x) ≤ -3 or f(x) ≥ 3
Interval notation : ( - ∝ , -3 ) ∪ (3,∝)
Axis interception points of 3csc(4x) : None
Asymptotes of 3csc(4x) : vertical: x = π / 2 n, x = π / 4 + π/2 n
extreme points of 3csc(4x) :
Minimum (π /8 + π / 2 n,3 ),
Maximum ( 3π / 8 + π/2n, -3).
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Despite not being a part of the function graph, a vertical asymptote is a vertical line that serves as a guide f (x) = 3csc4x.
How do you find a vertical asymptote?The denominator of the function, n(x), is the place where vertical asymptotes can be located.
If the numerator, t(x), is not zero for the same value of x, then the vertical asymptotes can be determined by solving the equation n(x) = 0 where n(x) is the denominator.
f (x) = 3csc4x.
Periodicity of 3csc(4x) : π / 2
Domain of 3csc(4x) :
Solution : π / 2 n<x < π / 4 + π / 2 n or π /4 + π / 2 n< x < π /2 + π /2 n
Interval Notation : ( π / 2 n,π /4 + π /2)n) ∪ (π / 4 + π /2 n, π / 2 + π /2 n)
Range of 3csc(4x) :
Solution : f(x) ≤ -3 or f(x) ≥ 3
Interval notation : ( - ∝ , -3 ) ∪ (3,∝)
Axis interception points of 3csc(4x) : None
Asymptotes of 3csc(4x) : vertical: x = π / 2 n, x = π / 4 + π/2 n
extreme points of 3csc(4x) :
Minimum (π /8 + π / 2 n,3 ),
Maximum ( 3π / 8 + π/2n, -3).
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PLSSS! Fast! I will give 5 stars! At noon, the temperatures in Portland, Maine and Phoenix, Arizona had opposite values. The temperature in Portland was lower than in Phoenix. What was the temperature in each city? Explain your reasoning.
Opposite values are those values which on the number line has the same distance between them and zero. The temperature in each city is PoT=-PhT and PhT =+PoT.
What are opposite values?Opposite values are those values which on the number line has the same distance between them and zero. Although the sign on the values may be difference. For example if the first value is 4, then its opposite value is -4.
In general, the temperature equation for Portland, Maine is stated mathematically as
PoT=-PhT
As it is given in the question that the Portland, Maine and Phoenix, Arizona had opposite values. Also, the temperature in Portland is lower than in Phoenix. Therefore, the temperature in each city can be written as,
PoT=-PhT
PhT =+PoT
Hence, the temperature in each city is PoT=-PhT and PhT =+PoT.
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A rocket is launched in the air. The graph below shows the height of the rocket hh in meters after tt seconds.
help pls
Answer:
The answers are=
(38, 0)time in seconds(19, 1768.9)Heightin metersThe x-coordinate of the vertex is (38, 0) and the y-coordinate of the vertex is (19, 1768.9).
What is a parabola?It is defined as the graph of a quadratic function that has something bowl-shaped.
(x - h)² = 4a(y - k)
(h, k) is the vertex of the parabola:
a = √[(c-h)² + (d-k²]
(c, d) is the focus of the parabola:
It is given that:
The graph of the parabolic path is shown in the picture.
From the graph:
The x-coordinate of the vertex is (38, 0)
The x-coordinate represents time in seconds
The y-coordinate of the vertex is (19, 1768.9)
The y-coordinate represents the height in meters
Thus, the x-coordinate of the vertex is (38, 0) and the y-coordinate of the vertex is (19, 1768.9).
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What is the midpoint of AB?
Answer: Point G.
Step-by-step explanation:
Count the number of spaces between points A and B. Then divide that number by 2 and count that many spaces from one point.
14/2=7
I hope this helps!! Pls mark brainliest :)
(4₊√₋81)₋(9₊√₋9) i cant resolve this equation. thanks for help
The question can't be solved because we can't have negative sign under square root
Answer:
-5 +6i
Step-by-step explanation:
Square roots of negative numbers are imaginary. This is asking for the difference of two complex numbers. A suitable calculator can show you what that is.
__
simplify radicalsWe know that √(-1) ≜ i. This means the radicals can be simplified to ...
[tex]\sqrt{-81}=\sqrt{9^2(-1)}=9\sqrt{-1}=9i\\\\\sqrt{-9}=\sqrt{3^2(-1)}=3\sqrt{-1}=3i[/tex]
So the expression becomes ...
(4 +9i) -(9 +3i)
combine termsLike terms can be combined in the usual way. For the purpose here, i can be treated as though it were a variable.
(4 +9i) -(9 +3i) = 4 +9i -9 -3i
= (4 -9) +(9 -3)i
= -5 +6i
Which equation is made true by the opposite angles theorem? A. 40 − 2x = 85 + y B. x − 8 = 40 − 2x C. x − 8 = 3y − 15 D. 3y − 15 = 85 + y
Option B. x-8 = 40-2x is the correct equation for the opposite angle theorem.
According to the Opposite angles theorem,
Vertical angles theorem or vertically opposite angles theorem states that two opposite vertical angles formed when two lines intersect each other are always equal (congruent) to each other.
[tex]= > x-8=40-2x[/tex] ( : Because opposite vertex angles are equal)
So option B is correct in the given question
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Answer:
D.) 3y-15 =85+
Step-by-step explanation:
simply put, opposite angles theorem is where the angles are on the opposite side so the parallelogram in the photo shows that 3y-15 is on the opposite angle as 85+y (I also got this one right lol)
binomial expansion of (2+3x)^5
From this diagram, select the
pair of lines that must be
parallel if 27 and 25 are
supplementary. If there is no
pair of lines, select "none."
Answer:
l
Step-by-step explanation:
Answer:
Lines L and n are parallel
Explanation -
In the question it is given that angle 7 and angle 5 are supplementary.
which means that sum of this angle is 180°
so line L and n are parallel
5.2 Two concentric circles have radii 7cm and 4cm respectively. PQ, a chord to the larger circle, is 13cm. 5.2.1 Draw the sketch. (2) 5.2.2 Calculate AB (a chord to a smaller circle), correct to 2 decimal places. (6)
The length of the chord AB will be 6.08 cm
A chord of a circle is a section of a straight line whose ends both fall on an arc of a circle. A secant line, often known as secant, is a chord's infinite line extension. A chord is, more broadly speaking, a line segment connecting two points on any curve, such as an ellipse.
Given two concentric circles have radii 7cm and 4cm respectively. PQ, a chord to the larger circle, is 13cm
We have to find the length of chord AB drawn to smaller circle
Given:
PQ = 13 cm
R = 7 cm
r = 4 cm
The formula to find length of chord is as follow:
Length of chord = 2 x √(R²-d²)
Where,
R = radius of circle
D = Perpendicular distance from center of circle to chord
So,
PQ = 2 x √(R²-d²)
13 = 2 x √(7²-d²)
d = 2.59 cm
Now,
AB = 2 x √(r²-d²)
AB = 2 x √(4²-2.59²)
AB = 6.08 cm
Hence the length of chord AB will be 6.08 cm
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Suppose Jenny places 9500 in an account that pays 13% interest compounded each year. Assume that no withdrawals are made from the account.
tell me your the greatest but once you turn they hate us
PLEASE PLEASEEEEEEE HELPPPPPP!! 100 POINTSSSS :)
A Ferris wheel, called the Atlanta Skyview, recently opened in Centennial Olympic Park in the Atlanta, GA area. The diameter of this Atlanta attraction is 200 feet and has 42 gondolas evenly spaced out along the circle. Each sector starts and ends at the point at which the gondola is attached to the Ferris wheel circle.
Answer the following questions about this Ferris wheel. Be sure to show and explain all work for each problem.
a. Area of the wheel?
b. measure the central angle in degrees
c. Measure of a central angle in radians
d. Arc length between two gondolas
e. Area of each sector.
The area of the wheel is 31415.9 ft².
The Central angle in degrees is 34.29°
Measure of a central angle in radians is 0.5984 radians
How to calculate the area and central angle of a circle?
A) The image shows an example of this Ferris wheel.
We are given;
Diameter; d = 200 ft
Radius; r = 100 ft
Number of gondolas = 42
Area of the circle wheel = πr²
Area = π * 100²
Area = 31415.9 ft²
B) Now, the sum of angles in a circle is 360°.
Since there are 42 gondola's, then;
Each angle = 360/42 = 60/7°
The central angle will be an angle with its vertex at the center of a circle and with sides that are radii of the circle. From the image, we see that it covers approximately 4 gondola's. Thus;
Central angle = 4 * 60/7° = 34.29°
C) Central Angle in radians will be converted as 0.5984 rad.
D) Arc length between two gondolas is;
S = rθ
S = 100 * 0.5984
S = 59.84 radians
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Given A(-2, 5) and B(13, -7), find the midpoint of AB.
Answer:
The mid-point is (9,-9/2)
Step-by-step explanation:
You would use the mid-point formula for this
[tex](\frac{x_{2} +x_{1} }{2} , \frac{y_{2}+y_{1} }{2} )[/tex]
if you plug that in it is ([tex]\frac{13-2}{2}, \frac{-7+5}{2}[/tex])
resulting in (11/2,-2/2) = (11/2,-1)
Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
In this graph, the number of containers is plotted along the x-axis and the amount of water in the containers is along the y-axis.
The proportionality constant of the graph (y to x) is
The constant of the proportional relationship graphed in this problem is of 10.
What is a proportional relationship?A proportional relationship is a function in which the output variable is given by the input variable multiplied by a constant of proportionality, that is:
y = kx
In which k is the constant of proportionality.
In this problem, the points on the graph are: (0,0), (2,20), (4,40), ..., hence the constant is:
k = 40/4 = 20/2 = 10.
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Help me with this i need steps :c!
Answer:
The area of a triangle is 1/2 × base × height. 24 = 1/2 × 12 × height. Therefore height = 24/6 = 4 .
Answer:
8
Step-by-step explanation:
24=6*h/2
48=6*h
8=h
h is altitude
Determine the equation of the tangent line in both cases
1. x^2/x+2 at (2,1)
2. x^3+2y^2=10y at (2,1)
Differentiate the function/equation with respect to x and solve for the derivative, dy/dx. The value of dy/dx at the given point is the slope of the tangent line to the curve at that point. Then use the point-slope formula to get the equation of the tangent.
1.
[tex]y = \dfrac{x^2}{x+2} \implies \dfrac{dy}{dx} = \dfrac{2x\times(x+2) - x\times1}{(x+2)^2} = \dfrac{x(x+4)}{(x+2)^2}[/tex]
When x = 2, the derivative is
[tex]\dfrac{dy}{dx}\bigg|_{x=2} = \dfrac{2(2+4)}{(2+2)^2} = \dfrac34[/tex]
Then the equation of the tangent line at (2, 1) is
[tex]y - 1 = \dfrac34 (x - 2) \implies \boxed{y = \dfrac{3x}4 - \dfrac12}[/tex]
2.
[tex]x^3 + 2y^2 = 10y \implies 3x^2 + 4y \dfrac{dy}{dx} = 10 \dfrac{dy}{dx} \implies \dfrac{dy}{dx} = \dfrac{3x^2}{10-4y}[/tex]
When x = 2 and y = 1, the derivative is
[tex]\dfrac{dy}{dx}\bigg|_{(x,y)=(2,1)} = \dfrac{3\times2^2}{10-4\times1} = 2[/tex]
Then the tangent at (2, 1) has equation
[tex]y - 1 = 2 (x - 2) \implies \boxed{y = 2x - 3}[/tex]
In the standard Normal distribution, which z-score represents the 99th percentile?
Find the z-table here.
–3.00
–2.33
2.33
3.00
Picture posted below
The Z- score representing the 99th percentile is given by 2.33
Problems of commonly distributed samples can be solved using the z-score formula.
For a set with a standard deviation, the z-score scale X is provided by:
Z = ( x- mean )/ standard deviation
Z-score measures how many standard deviations are derived from the description. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the scale is less than X, that is, the X percentage. Subtract 1 with p-value, we get the chance that the average value is greater than X.
To Find the z-result corresponding to P99, 99 percent of the normal distribution curve.
This is the Z value where X has a p-value of 0.99. This is between 2.32 and 2.33, so the answer is Z = 2.33
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