The energy transferred to the water in 100 seconds was 155 000 J. specific heat capacity of water = 4200 J/kg °C
Determine the mass of water in the kettle.
Use Figure 10.
Give your answer to 2 significant figures.
Any help would be appreciated

The Energy Transferred To The Water In 100 Seconds Was 155 000 J. Specific Heat Capacity Of Water = 4200

Answers

Answer 1

Answer:

0.37 kg

Explanation:

I'm not a professor myself, but this is how I worked it out:

using the graph, after 100 seconds, the temperature is 100 degrees Celsius.

If we now substitute everything into the specific heat capacity equation, making the mass "m", we would come up with:

4200 = 155000/(m x 100)

If we rearrange and solve for m, we get 0.37 kg.

I'm not sure if I have done this correctly, feel free to correct me.

Hope this helps!

Answer 2

By using the specific heat capacity formula, the  mass of water in the kettle is 0.47 kg

Give that the energy transferred to the water in 100 seconds was 155 000 J and the specific heat capacity of water = 4200 J/kg °C

From the graph;

The initial temperature of the water at time zero is 22 degree Celsius

The final temperature of the water at time 100s is 100 degree Celsius

Change in temperature (T) = 100 - 22 = 78 degree Celsius

To determine the mass of water in the kettle, use the heat energy formula below

E = mcT

Substitute all the parameters into the equation

155000 = 4200 x 78 M

Make M the subject of the formula

M = 155000/327600

M = 0.47 kg

Therefore, the  mass of water in the kettle is 0.47 kg

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Explanation:

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Question 5 (1 point)
graph

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Answers

Answer:

It is D

Explanation: Use of these terms stretches back to World War I. One American field order from September 1918 noted, “The First Army will attack at H-Hour on D-Day with the object of forcing the evacuation of the St. Mihiel salient.” Other nations had their own shorthand. In World War I, the French used the code date “le Jour J,” while the British called their operation start days “Z-Day” and “Zero Hour.”

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The time rate of change of velocity with time.

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The force F =mass x acceleration.

The lesser mass greater will be the acceleration. Your sister with half weight of yours will accelerate more.

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What heat transfer are uv rays from the sun. Radiation, conduction, or convection

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Answer:

The ans is Radiation

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Elements grouped as a column on the periodic table belong to a ______.

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answer) group not sure

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Answers

Answer:

yes her device can produce

Explanation:

An electromagnetic force is produced by this setup.

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Answer:

1. troposphere

2. troposphere (still)

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Explanation:

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3. Explained in the answer.

4. Explained in the answer.

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Answers

Answer:

230.4 N

Explanation:

Applying,

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F = 230.4 N.

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Answers

Answer:

1. Ultraviolet light (UV)

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Answers

Answer:

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Answers

The sun creates energy through nuclear fusion

The Sun creates energy through a series of steps known as nuclear fusion.

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Please solve this worksheet for me It’s very important please don’t write unnecessary things or else I’ll report please help me i request

Answers

Answer:

1. 231.25 mL

2. 218.75 kPa

3. 6.21 L

4. 427.5 mL

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Explanation:

This questions describes Boyle's law. Using Boyle's law equation to solve the questions as follows:

P1V1 = P2V2

Where;

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P2 = final pressure

V1 = initial volume

V2 = final volume

Please find the answers to each question as an attachment.

Which of the following is not true about a scientific name?

a. they should be typed in italics
b. they are derived from Greek and Latin words
c. they contain a genus and species name
d. they can vary from location to location

Answers

Then answer would be D

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Answer:

1) C, 2) C, 3) B, 4) D, 5) A/B, 6) D, 7) D, 8) A, 9) B, 10) A

Explanation:

1) Seconds, minutes and days are time units. (Correct answer: C)

2) The displacement is shortest distance between the point of origin and the point of destination. (Correct answer: C)

3) The velocity is the rate of change of position in time. (Correct answer: B)

4) Graphs are a very useful ressource to infer characteristics inherent to a studied physical variable. (Correct answer: D)

5) There are two possible answers, since both milimeters and meters are units for distance. (Correct answers: A/B)

6) The distance is the arc length of the entire path that object travelled. (Answer: D)

7) Traditionally, in a position vs. time graph we plot time in the x-axis. (Answer: D)

8) In this case, we use a distance-time graph, where travelled distance is the dependent variable and time is the independent variable. (Answer: A)

9) The point of origin is the initial position of the object. (Answer: B)

10) The point of destination is the final position of the object. (Answer: A)

What is the average speed of a car that travelled 400 miles in 6 hours?

Answers

Answer:

About 66 miles per hour

Explanation:

Based on the information given we can assume the car traveled the same number of miles every hour meaning all we need to do is divide.

400/6 ≈ 66 miles per hour

Answer

66 mph

Explanation:

400 ÷ 6 = 66.666666666666666.......

How do I solve this arithmetic sequence?

Answers

Answer:

The 16ᵗʰ term of this sequence is 82

Step-by-step explanation:

Here,

First Term = a₁ = 9

Common Difference = (d) = 2

Now, For 16ᵗʰ term, n = 16

aₙ = a + (n - 1)d

a₁₆ = 7 + (16 - 1) × 2

a₁₆ = 7 + 15 × 5

a₁₆ = 7 + 75

a₁₆ = 82

Thus, The 16ᵗʰ term of this sequence is 82

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A music fan at a swimming pool is listening to a radio on a diving platform. The radio is playing a constant- frequency tone when this fellow, clutching his radio, jumps off. Describe the Doppler Effect heard by (a) a person left behind on the platform and (b) a person down below floating on a rubber raft. In each case, specify (1) whether the frequency is greater or smaller than the frequency produced by the radio, (2) whether the observed frequency is constant, and (3) how the observed frequency changes during the fall, if it does change. Give your reasoning.

Answers

Answer:

The Doppler Effect is given by the following relation;

[tex]f' = \left (\dfrac{v + v_0}{v - v_s} \right) \times f[/tex]

Where;

f' = The frequency the observer hears

f = Actual frequency of the wave

v = The velocity of the sound wave

[tex]v_o[/tex] = The velocity of the observer

[tex]v_s[/tex] = The velocity of the source

Where the observer is stationary, we have;

(i) When the source is moving in the direction of the observer

[tex]f' = \left (\dfrac{v }{v - v_s} \right) \times f[/tex]

(ii) When the source is receding from the observer, we have;

[tex]f' = \left (\dfrac{v }{v + v_s} \right) \times f[/tex]

Therefore;

(a) A person left behind on the platform

For a person left behind on the platform, we have that the radio source is receding, therefore, we have;

[tex]f' = \left (\dfrac{v }{v + v_s} \right) \times f[/tex]

(1) Given that (v + [tex]v_s[/tex]) > v, therefore, v < (v + [tex]v_s[/tex]), f' < f, the frequency heard by the person left on the platform, f', is smaller (lower) than the frequency produced by the radio

(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity

(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively smaller

(b) A person down below floating on a rubber raft

For the the person down below on the rubber raft, the radio source is advancing

Therefore, the radio source is moving towards the person at rest down on the rubber raft, therefore, we have;

[tex]f' = \left (\dfrac{v }{v - v_s} \right) \times f[/tex]

(1) Given that (v - [tex]v_s[/tex]) < v, therefore, f' > f, the frequency heard by the person down below floating on the rubber raft, f', is greater (higher) than the frequency produced by the radio

(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity

(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively greater (higher)

Explanation:

what forces are being used when walking a dog and how ?

Answers

There are tons of forces that balance out on your body while you walk. Subsequent physics classes will tell you about each and how they are represented. Here are a few in order of how people usually learn them.

Gravity: The earth exerts a gravitational force on each particle in your body that has mass. Overall, this can be represented as a single force that pulls directly toward the center of the earth from the point called your center of mass.

Normal Force: The contact between your feet/shoes and the ground exerts a force normal (straight out from) the ground. If you are on flat ground, this force is directly opposite the force of gravity, and in most cases will be equal to it such that you have no vertical net force.

Friction: Friction between your shoes/feet and the ground, pointing parallel to the ground and in the direction of your walking motion creates the force necessary for you to move. The microscopic peaks and valleys of the ground and your feet/shoes create small normal forces that can sum into a direction of motion.

Air Buoyancy: Since you are in a fluid, the mass of the fluid you displace creates an upward force away from the center of the earth. Since the density of air is miniscule, this force is generally neglected except in the most precise of circumstances.

Drag and Air resistance: While you walk, as you move through a fluid, that fluid exerts friction on your body in the form of drag. It is usually small unless you’re moving very fast relative to the fluid.

Air pressure, blood pressure, body tensions: Your body has a balance of blood pressure, muscle tensions, which oppose outside air pressures which equalize out to form the shape your body is in.

Internal forces: Many forces act within you such as air pressure, other muscle tensions, and internal stresses which balance out. Usually in physics these are lumped under internal forces.

The distance between the two nearest points on a wave where the particles are in phase is 2 m. What is the wavelength of the wave?

A. 1/2 m

B. 1 m

C. 2 m

D. 2 seconds

E. none of these

Answers

Answer:

Suppose that the wave equation is:

f(x) = A*cos(k*x)

The wave is in phase for two points x₁ and x₂ if:

f(x₁) = f(x₂)

And if these points are consecutive (for example, two consecutive peaks) then the wavelength of the wave is:

wavelength = x₂ - x₁

In this case, we know that the wave is in phase for two points that are 2 m apart.

Then we can use the points:

x₁ and x₂ such that:

x₂ = x₁ + 2m

We also know that these are the nearest points such that this happens, then we can assume that the points are consecutive.

Then the wavelength will be:

wavelength = x₂ - x₁ = (x₁ + 2m) - (x₁) = 2m

Then the wavelength is 2m.

The correct option is C.

answer right away!!—A plucked guitar string emits a dominant
frequency of 320 Hz. What is the
frequency of the 3rd harmonic?

Answers

Answer:

20000000000000hz only for this

Help plz for 25 points !! I only have an hour left !

Answers

See the pic for the work!

Which law best describes contact force

A.
second law
B.
third law
C.
law of gravity
D.
first law

Answers

Answer:

b is the answer the third law

Explanation:

B because Newton's second law, which states that the force F acting on a body is equal to the mass m of the body multiplied by the acceleration a of its centre of mass, F = ma, is the basic equation of motion in classical mechanics.

An 80 kg runner has 3,000 J of kinetic energy. What is her velocity in m/s?

Answers

Answer: 8.6m/s

Explanation:From KE=1/2mv^2

In order to make v the subject of the formula we divide both sides by 1/2m. Thus V^2 will be left alone on the RHS. But we are looking for v and not v^2. Thus we find the square root of KE1/2m

Meaning V= sqrt[3000÷1/2 of 80]

=sqrt[3000÷40]

=sqrt(75)

=8.6m/s

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