The diagram shows the four primary steps in the production of work in a four-stroke heat engine.

What is the correct order in which these steps occur?
A. Y, W, X, z
B. X, Z, W. Y
C. W, X, Y, Z
D. Z, X, Y, W

Answer:

When elements bond together or when bonds of compounds are broken and form a new substance

Explanation:

Answer:

D

Explanation:

Answer:

A.) acceleration= 55.6m/s^2

B.) acceleration of table= 5.0m/s^2

C.) More acceleration

Explanation:

A.) 100N/1.8kg= -55.6

B.) 100N÷20kg= 5

C.) Because since the table would have less mass, it would have had to accelerate more

Answer:

C

Explanation:

Diagram C is the correct answer, because the ball is at the point with the highest height relative to the ground, in this way all the kinetic energy has been transformed into potential energy.

We must remember that potential energy is defined as the product of mass by gravity by height

Ep = m*g*h

where:

m = mass [kg]

g = gravity acceleration [m/s²]

h = elevation [m]

So when we have a great value for h in the above equation, we will have a big value for potential energy.

Answer:

True.

Explanation:

Exercises and yoga are important for the individual's health. The exercise makes the individual, fit, healthy and also reduces the chances of the deadly disease in human beings.

Different types of exercise can be performed by the individual. The aerobic exercises increase the amount of oxygen in the body. With the aerobic exercise, the exercise that can increase the strength, flexibility and total fitness must also be included.

Answer:

Explanation:

distance = 1.25 mile

time traveled = 5 min.

find velocity in miles / hour

solution:

use the formula: velocity = distance / time

velocity =     1.25 mile     x 60 min  

                     5 min            1 hour

velocity = 15 miles / hour

Answer:

length of brass=24cm and length of steel rod=36cm

Answer:

The answer is below

Explanation:

The speed of the boat in still water is perpendicular to the speed of the water flow. Therefore the speed relative to the ground (V), the speed of flow and the speed of the boat in still water form a right angled triangle. Hence the speed relative to the ground is given as:

V² = 56² + 126²

V² = 19012

V = 137.9 m/s

Answer:

7.67m/s²

Explanation:

The net force on the block is;

  Net force = Force of pull  - Frictional force

mass of block = 4.5kg

force of pull  = 42N

Frictional force  = 7.5N

  Net force  = 42  - 7.5

    Force  = mass x acceleration

    ma  = 34.5

     4.5 x a = 34.5

             a = [tex]\frac{34.5}{4.5}[/tex]   = 7.67m/s²

Answer:

Q = 50.25 [J]

Explanation:

To solve this problem we must use the following equation that relates the temperature change with the mass and with the specific heat.

Q = m*Cp*(DT)

where:

Q = energy in form of heat [J]

m = mass = 5 [g] = 0.005 [kg]

Cp = specific heat = 1005 [J/kg*°C]

DT = temperature change = 10 [°C]

Now replacing:

Q = 0.005*1005*10

Q = 50.25 [J]

Answer:

When ice of polar caps of earth melts, mass concentrated near the axis of rotation spreads out. Therefore, the moment of inertia I increases. With increase of I,T will increase i.e length of the day will increase.

Answer:

nothing moves if anything other doesn't move it.

natural position of things is the resting

Explanation:

yeah that's it

Answer:

The book does not move because all the forces acting on the book are in equilibrium, creating a net force of zero magnitude on the book. Since the net force on the book is zero, this means that the book will remain in its present state of motion (which is that the book is motionless).

Explanation:

Newton's first law states that all body will remain in  their present state of motion unless acted upon by an external force. In order word, a moving body should continue moving forever, and a body at rest should remain like that forever, unless they are acted upon by a force to either cause them to stop stop or to start moving respectively.

Answer:

The mass of the object is 133.33 kg

Explanation:

From Newton's second law of motion

F = ma

Where F is the force

m is the mass

and a is the acceleration

From the question,

A stationary object is pushed with a force of 400N, that is F = 400N. To determine the mass of the object,

First, we will determine the acceleration.

From one of the equations of kinematics for linear motion,

v = u + at

Where v is the final velocity

u is the initial velocity

a is the acceleration

and t is time

We  can write that

v - u = at

Then, a = (v - u) / t

From the question,

t = 8s

v = 24m/s

u = 0 m/s (Since the object was stationary, that is, it was pushed from rest)

∴ a = (24m/s - 0m/s) / 8s

a = 24 / 8 = 3 m/s²

Therefore, acceleration is 3 m/s²

Now,

From F = ma

m = F / a

From the question

F = 400N

∴ m = 400N / 3m/s²

m = 133.33 kg

Hence, the mass of the object is 133.33 kg.  

Answer:

3°C

Explanation:

Given parameters:

Heat capacity  = 300cal

Specific heat capacity  = 0.5cal/g°C

Mass of the object  = 200g

Initial temperature  = 0°C

Unknown:

Final temperature  = ?

Solution:

The heat capacity is the amount of heat required to raise the temperature of a substance by 1°C;

 Mathematically ;

        H  = m c x  (t₂ - t₁)

H is the heat capacity

m is the mass

c is the specific heat capacity

t is the temperature

  Insert the parameters and solve;

         300  = 200 x 0.5 x (t₂- 0 )

         100 t₂ = 300

              t₂ = 3°C

Answer:

Definition: Pressure:- Force per unit area surface is called pressure. P = F/ A Pressure = Force /Area Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed. Gauge pressure is the pressure relative to the ambient pressure. 

Answer:

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. When the interaction ceases, the two objects no longer experience the force.

Pressure is defined to be the amount of force exerted per area.

Formula of pressure = P = F÷A

Where, P = Pressure,

            F = Force applied and,

            A = Unit area.

Examples of Pressure is Air pressure.

Answer:

0.35

Explanation:

Answer:

A. 1.8x10⁵

Explanation:

For this question we have

72km/h = speed

Total mass = 2250kg

Stopped at t = 0.2250s

To get average force acting on this car on collision:

72km/3.6 = 20m|s

Impulse = ∆p

This implies:

F∆t = m∆v

F = m∆v/∆t

= 2250x20/0.250

= 180000

= 1.8x10⁵

Therefore option A is correct.

Answer:

weathering

Explanation:

Answer:

F = 2.69 10⁻³ m   [ N]

Explanation:

This exercise asks to calculate the gravitational field of the Earth on the lunar surface, let's use the universal gravitation law

          F = G m M / r²

where m is the mass of the body, M the mass of the Earth and r the distance between the Earth and the Moon

         F = (G M / r²) m

         F = (6.67 10⁻¹¹ 5.98 10²⁴ / (3.85 10⁸)² ) m

         F = 2.69 10⁻³ m   [ N]

This force is directed from the Moon towards the Earth, therefore it reduces the weight of the body

Answer:

voltage= 17.88volts

current= 0.04 amps

Explanation:

Step one:

given data

resistance R=400 ohms

Power P= 0.8W

a.  What is the maximum voltage that can be applied across this resistor without damaging it?

the expression relating power and voltage is

P=V^2/R

substituting we have

0.8=V^2/400

V^2=0.8*400

V^2=320

V=√320

V=17.88 volts

the maximum voltage is 17.88volts

b.What is the maximum current it can draw?

we know that from Ohm' law

V=IR

17.88=I*400

I=17.88/400

I=0.04amps

Answer:

The radius of the circular loop is 0.233 m

Explanation:

Given;

current on the circular loop, I = 63 A

magnitude of the magnetic field, B = 1.7 x 10⁻⁴ T

The magnetic field at the center of a circular loop is given by;

[tex]B = \frac{\mu I}{2R} \\\\[/tex]

Where;

R is the radius of the circular loop

μ is the permeability of free space = 4π x 10⁻⁷ T.m/A

Substitute the givens;

[tex]B = \frac{\mu I}{2R}\\\\R = \frac{\mu I}{2B}\\\\R = \frac{(4\pi*10^{-7})(63) }{2(1.7*10^{-4})}\\\\R = 0.233 \ m[/tex]

Therefore, the radius of the circular loop is 0.233 m

It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The radius of the circular loop is 0.233 m.

It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.

The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.

As we know that current is directly propotional to the induced magnetic field greater the current I, the greater the magnetic field B.

The given data in the problem is;

I is the value of current = 63 A

B is the megnetic field = 1.70 10⁻⁴ T

r is the radius of loop=?

μ is the permeability of free space = 4π x 10⁻⁷ T.m/A

The value of the megnetic field at the center is given by;

[tex]\rm B= \frac{\mu I}{2r} \\\\ \rm r= \frac{\mu I}{2B} \\\\ \rm r= \frac{4\pi \times 63}{2\times 1.7\times 10^{-4}} \\\\ \ \rm r=0.233 m[/tex]

Hence the radius of the circular loop is 0.233 m.

To learn more about the magnetic field refer to the link;

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Answer:

C firework

Explanation:

from Quizlet

Answer:

(a) A = 0.0800 m, λ = 20.9 m, f = 11.9 Hz

(b) 250 m/s

(c) 1250 N

(d) Positive x-direction

(e) 6.00 m/s

(f) 0.0365 m

Explanation:

(a) The standard form of the wave is:

y = A cos ((2πf) t ± (2π/λ) x)

where A is the amplitude, f is the frequency, and λ is the wavelength.

If the x term has a positive coefficient, the wave moves to the left.

If the x term has a negative coefficient, the wave moves to the right.

Therefore:

A = 0.0800 m

2π/λ = 0.300 m⁻¹

λ = 20.9 m

2πf = 75.0 rad/s

f = 11.9 Hz

(b) Velocity is wavelength times frequency.

v = λf

v = (20.9 m) (11.9 Hz)

v = 250 m/s

(c) The tension is:

T = v²ρ

where ρ is the mass per unit length.

T = (250 m/s)² (0.0200 kg/m)

T = 1250 N

(d) The x term has a negative coefficient, so the wave moves to the right (positive x-direction).

(e) The maximum transverse speed is Aω.

(0.0800 m) (75.0 rad/s)

6.00 m/s

(f) Plug in the values and find y.

y = (0.0800 m) cos((75.0 rad/s) (2.00 s) − (0.300 m⁻¹) (1.00 m))

y = 0.0365 m

Answer:

[tex]F=3.61\times 10^{-47}\ N[/tex]

Explanation:

Mass of a proton, [tex]m_p=1.67\times 10^{-27}\ kg[/tex]

Mass of an electron, [tex]m_e=9.11\times 10^{-31}\ kg[/tex]

The distance between the electron and the proton is, [tex]r=5.3\times 10^{-11}\ m[/tex]

We need to find the mutual attractive gravitational force between the electron and proton. The gravitational force is given by :

[tex]F=G\dfrac{m_em_p}{r^2}[/tex]

Where G is the universal Gravitational constant

[tex]F=6.67\times 10^{-11}\times \dfrac{9.11\times 10^{-31}\times 1.67\times 10^{-27}}{(5.3\times 10^{-11})^2}\\\\F=3.61\times 10^{-47}\ N[/tex]

So, the force between the electron and proton is [tex]3.61\times 10^{-47}\ N[/tex].

precisely which regions?

Answer:

Romans have ruled for 450 years

Explanation:

Answer:

Explanation:

Sum all the forces that are acting on the object and what ever the sum is, is what the net force is.

For example if there is a piece of wood sitting on a table the net force would be the sum of the forces that are acting on it, so the force of gravity (which is negative) + the normal force which would equal zero because they are the same value.

I would say food but like they take weight too

Answer:

(a) 0.993 s

(b) 14.0 N/m

(c) -3.02 m/s

(d) -6.01 m/s²

Explanation:

(a) The block's position can be modeled as a cosine wave:

x(t) = A cos(ωt)

where A is the amplitude (in this case, 50 cm) and ω is the angular frequency.

At t = 0.200 s, x(t) = 15.0 cm.

15.0 cm = 50.0 cm cos((0.200 s) ω)

0.3 = cos((0.2 s) ω)

1.266 rad = (0.2 s) ω

ω = 6.33 rad/s

The period is:

T = (2π rad) (1 s / 6.33 rad)

T = 0.993

(b) For a spring-mass system, ω = √(k/m).  The mass of the block is 0.350 kg, so:

ω = √(k/m)

6.33 rad/s = √(k / 0.350 kg)

6.33 rad/s = √(k / 0.350 kg)

40.1 rad/s² = k / 0.350 kg

k = 14.0 N/m

(c) Energy is conserved:

EE₀ = EE + KE

½ kx₀² = ½ kx² + ½ mv²

kx₀² = kx² + mv²

(14.0 N/m) (0.50 m)² = (14.0 N/m) (0.15 m)² + (0.35 kg) v²

v = -3.02 m/s

Alternatively, we can take the derivative of our position equation:

v(t) = -Aω sin(ωt)

v = -(0.50 m) (6.33 rad/s) sin((6.33 rad/s) (0.2 s))

v = -3.02 m/s

(d) Sum of forces on the block:

∑F = ma

-kx = ma

a = -kx / m

a = -(14.0 N/m) (0.15 m) / (0.350 kg)

a = -6.01 m/s²

Alternatively, we can take the derivative of our velocity equation:

a(t) = -Aω² cos(ωt)

a = -(0.50 m) (6.33 rad/s)² cos((6.33 rad/s) (0.2 s))

a = -6.01 m/s²

Answer:

The electrostatic force will remain the same

Explanation:

From the question we are told that  

     The charge on the each conducting sphere is [tex]q = 2 \ C[/tex]

      The radius each sphere is [tex]r_1 = r_2 = r = 0. 1\ m[/tex]

Generally electrostatic force between the sphere is mathematically represented as

             [tex]F = \frac{k * q_1 q_2 }{d^2}[/tex]

Here  k is the coulomb constant ,

         d  is the distance between the two sphere which is measured from one center of the sphere to the other center of the sphere  

Now from the question we are told that the radius of the spheres is doubled (i.e  from 0.10 m  to 0.2 m ) , this will not affect the distance between the sphere because their center are still in the same position

and given there is no change in the distance between the spheres , the electrostatic force will remain the same

Answer:

The minimum speed = [tex]\sqrt{\frac{2GM}{R} }[/tex]

Explanation:

The minimum speed that the rocket must have for it to escape into space is called its escape velocity. If the speed is not attained, the gravitational pull of the planet would pull down the rocket back to its surface. Thus the launch would not be successful.

The minimum speed can be determined by;

                      Escape velocity = [tex]\sqrt{\frac{2GM}{R} }[/tex]

where: G is the universal gravitational constant, M is the mass of the planet X, and R is its radius.

If the appropriate values of the variables are substituted into the expression, the value of the minimum speed required can be determined.

The minimum speed that the rocket must have for it to escape into space is  [tex]\sqrt{\frac{2GM}{R} }[/tex].

Escape velocity is the minimum speed that the rocket must have for it to escape into space.

The minimum speed (escape velocity) that the rocket must have for it to escape into space is given as;

[tex]V = \sqrt{\frac{2GM}{R} }[/tex]

where;

Thus, the minimum speed that the rocket must have for it to escape into space is  [tex]\sqrt{\frac{2GM}{R} }[/tex].

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