The ΔH°vap of water at the critical point is approximately 0.04614 kJ/mol.
To calculate the ΔH°vap (enthalpy of vaporization) of water at the critical point, we can use the Clausius-Clapeyron equation;
ln(P₂/P₁) = ΔH°vap/R [1/T₁ - 1/T₂]
where P₁ and T₁ are the pressure and temperature at which the enthalpy of vaporization is known (usually at standard conditions of 1 atm and 100 °C), P₂ and T₂ are the pressure and temperature at the critical point, ΔH°vap is the enthalpy of vaporization, and R is the gas constant (8.314 J/mol∙K).
Using the given values, we can plug them into the equation and solve for ΔH°vap;
ln(3.2 atm / 1 atm) = ΔH°vap / R [1/373 K - 1/275 K]
Simplifying;
ln(3.2) = ΔH°vap / R [0.0026819]
ΔH°vap / R = ln(3.2) / 0.0026819
ΔH°vap / R = 5.552
Multiplying both sides by R:
ΔH°vap = 5.552 x R
ΔH°vap = 5.552 x 8.314 J/mol∙K
ΔH°vap = 46.14 J/mol
Converting to kJ/mol;
ΔH°vap = 0.04614 kJ/mol
Therefore, the ΔH°vap of water is 0.04614 kJ/mol.
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Anyone know how to solve this?
The ratio of the concentrations at equilibrium is as follows:
3.7 0.85 0.04 21.3 42.6 12212.92 0.81 0.11 7.4 14.8 6012.2 0.63 0.43 1.5 3 274What are reactions in equilibrium?Chemical equilibrium is the point in a chemical reaction where both the forward and backward processes are occurring at the same rate.
The concentrations of the reactants and products are constant at equilibrium because the forward and reverse speeds are equal.
Considering the given statements based on the reaction equilibrium concentrations, the correct options are:
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Need help matching pairs of structures to diastereomers, enantiomers, constitutional isomers, not isomers, diff representations of the same?
A pair of molecules which exist in two forms that are mirror images of each other but cannot be superimposed one upon the other are called the enantiomers. They are present in pairs and have similar molecular shape.
The compounds with the same molecular formula but are non-superimposable non-mirror images are called diastereomers. They have distinct physical properties and molecular shape.
The constitutional isomers have the same molecular formula but have different bonding atomic organization and bonding patterns.
So here:
1st structure is constitutional isomers (c), 2nd structures are enantiomers (b) and the 3rd are completely different not isomers (d).
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Balloons for a New Years Eve party in Fargo, ND, are filled to a volume of 1.90 L at a temperature of 22.0 c and then hung outside. what is the volume of the balloon once they have cooled to the outside temperature of -34.0 c?
The volume of the balloon once they have cooled to the outside temperature of -34.0 c is 1.53 L.
Charles' law predicts the relationship between the volumes and the temperatures of a sample of an ideal gas at different conditions. For this equation to hold true, the number of molecules and the pressure must remain constant despite changes in the environment.
Determine the volume of the balloon outside, V2. We do this by applying Charles' law, such that we relate the volume, V, and the temperature, T, of a sample of gas as
V₁ /T₁ = V₂/ T₂
at two conditions. We are given the following values for the variables:
• V₁ = 1.90 L
T₁ = 22.0+ 273.15 = 295.15 K
T₂= 34.0+273.15= 239.15 K
We proceed with the solution.
V₁/T₁ = V₂/T₂
V₁ /T₁ × T₂ = V₂
1.90 L/295.15 K x 239.15 K = V₂
1.53 L =V₂
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The complete question is
Balloons for a New Year's Eve party in Fargo, ND, are filled to a volume of 1.90 L at a temperature of 22.0 degrees Celsius and then hung outside where the temperature is -34.0 degrees Celsius. What is the volume of the balloons after they have cooled to the outside temperature? Assume that atmospheric pressure inside and outside the house is the same.
The enthalpy combustion of ethanol is -1430 kJ/mol. Determine heat given off from the combustion of 1 dm³ of ethanol. Given density of ethanol is 0.79 gcm³. (molar mass ethanol = 46 g/mol)
Answer:
The enthalpy of combustion of ethanol is -1430 kJ/mol, which means that for every mole of ethanol that is burned, 1430 kJ of heat is released.
To determine the amount of heat given off from the combustion of 1 dm³ of ethanol, we need to first calculate the number of moles of ethanol in 1 dm³.
1 dm³ is equivalent to 1000 cm³. Since the density of ethanol is 0.79 g/cm³, the mass of 1 dm³ of ethanol can be calculated as:
mass = density x volume
mass = 0.79 g/cm³ x 1000 cm³
mass = 790 g
To convert this mass to moles, we need to divide by the molar mass of ethanol:
moles = mass / molar mass
moles = 790 g / 46 g/mol
moles = 17.17 mol
Therefore, 1 dm³ of ethanol contains 17.17 moles of ethanol.
To calculate the heat given off from the combustion of 1 dm³ of ethanol, we can use the following equation:
heat = enthalpy of combustion x moles of ethanol
heat = -1430 kJ/mol x 17.17 mol
heat = -24,551 kJ
Therefore, the heat given off from the combustion of 1 dm³ of ethanol is -24,551 kJ, or approximately 24,551 kJ of heat is released.
Write the cations and anions present in CrO2
The chemical molecule CrO2 is also known as chromium(IV) oxide or chromic acid. It has the molecular formula CrO2 and is an inorganic substance.
In the solid state, CrO2 exists as a solid with a layered structure, and it is considered a cationic compound. The cation present in CrO2 is chromium(IV) ion, denoted as Cr4+.
On the other hand, the anion present in CrO2 is oxide ion, denoted as O2-. The oxidation state of oxygen in this compound is -2.
So, the cations present in CrO2 are Cr 4+ ions, and the anions present are O2 -2 ions.
In CrO2, the cation present is Chromium (Cr) with a charge of +4, and the anion present is Oxygen (O) with a charge of -2.
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A sample of air occupies 0.75 L at standard conditions. What is the pressure in atm if the volume is 100.0 mL at 25oC?
P1 = 760 mmHg P2 = ?
V1 = 0.750 L V2 = 100.0 mL
T1 = 273 K T2 = 25oC
According to the ideal gas law, a gas's pressure is inversely related to its volume and directly proportionate to its temperature. So, if a gas sample's volume is reduced, the gas sample's pressure must also increase.
As a result, in order to determine the pressure of the gas sample under the specified circumstances, we must first determine the ratio of the two volumes before multiplying the starting pressure of the sample by that ratio.
We may get the ratio of the two volumes using the ideal gas law as follows: V2/V1 = (100.0 mL/0.75 L) x (273 K/25oC) = 8.02 As a result, the gas sample's pressure at 25 oC with a volume of 100.0 mL is 8.02 times higher than the sample's original pressure.
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What is the difference between practical work inside a laboratory and outside a laboratory
Answer:
The main difference between practical work inside and outside a laboratory is that the practical work inside the lab includes good equipment and chemicals which are very advanced and the practical outside a laboratory is more about the safety of life.
Explanation:
Practicals are set up at stations with lab equipment and chemicals, where students can learn, and researchers can experiment and find different new things.
Thus, the practical work inside the lab includes lab equipment and chemicals, and the practical outside a laboratory is more about conserving nature.
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If the amount of solute present in a solution at a given temperature is less than the maximum amount that can be dissolved at that tempature the solution is said to be
Answer:
Unsaturated
Explanation:
A solution is unsaturated when it contains less than the maximum amount of solute that is capable of being dissolved.
Silver chloride, AgCl, is a sparingly soluble solid. Answer the following questions about a saturated solution prepared by placing solid silver chloride in a 2.45 10-5 M NaCl(aq) solution. At some temperature, the silver ion concentration, [Ag+], was found to be 5.36 10-6 M.
(a) What is the concentration of chloride ions, [Cl − ], in the resulting solution?
The solubility of silver chloride (AgCl) can be represented by the following equilibrium equation:
AgCl(s) ⇌ Ag+(aq) + Cl-(aq)
In a saturated solution of AgCl, the concentration of Ag+ ions is equal to the solubility product constant (Ksp) for AgCl at that temperature. Since the concentration of Ag+ ions in the solution is given as 5.36 x 10^-6 M, we can write:
[Ag+] = 5.36 x 10^-6 M
According to the stoichiometry of the equilibrium equation, the concentration of chloride ions ([Cl-]) is also equal to the concentration of Ag+ ions, as one mole of AgCl dissociates to yield one mole of Ag+ ions and one mole of Cl- ions. Therefore:
[Cl-] = 5.36 x 10^-6 M
So, the concentration of chloride ions in the resulting solution is 5.36 x 10^-6 M.
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A student is tasked with writing the net ionic equation for the following
reaction:
4
Al(s) + 3 AgNO3(aq) → Al(NO3)3(aq) + 3 Ag(s)
What is the net ionic equation?
The net ionic equation of the reaction is as follows:
4 Al3+(aq) + 12 NO3-(aq) + 3 Ag(s) = 4 Al(s) + 12 Ag+(aq) + 12 NO3-(aq)
Ions which remain in their ground state and do not take part in the reaction are called spectator ions. The net ionic equation cancels out these ions, which are present on both the reactant and product sides of the equation.
Spectator ions, which can be found on both the reactant and product sides, but are not included in the finished reaction from the net ionic equation. The [tex]NO^3^-[/tex] ions are spectator ions in this example, thus taking them out of the equation. The net ionic equation makes up the rest of the species.
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Which of the following statements confirms the law of conservation of energy?
Statement that shows that the total energy of a system remains constant and is conserved would confirm the law of conservation of energy.
What is law of conservation?
The law of conservation of energy states that energy cannot be created or destroyed, only transformed from one form to another. Therefore, any statement that shows that the total energy of a system remains constant and is conserved would confirm the law of conservation of energy.
Here are some examples of statements that confirm the law of conservation of energy:
The total energy of a closed system, such as a roller coaster, remains constant as the coaster moves from one point to another. Even though the potential energy of the coaster decreases as it goes downhill and the kinetic energy increases, the total energy of the coaster (potential plus kinetic) remains constant.When a pendulum swings back and forth, the potential energy is converted into kinetic energy and back again, but the total energy of the pendulum remains constant.In a chemical reaction, the total energy of the reactants is equal to the total energy of the products. Although energy can be released or absorbed during the reaction, the total energy of the system is conserved.When a ball is thrown into the air, it gains potential energy as it rises and loses potential energy as it falls back down. However, the total energy of the ball (potential plus kinetic) remains constant, neglecting air resistance.All of these statements confirm the law of conservation of energy by showing that the total energy of a system is conserved over time.
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Complete question is: "The total energy of a system remains constant and is conserved" statement would confirm the law of conservation of energy.
N2(g)+3H2(g)->2NH3(g), ΔH=-92.40kJ 1. How many grams of H2 are needed to involve 150.9kJ of heat? 2. How many moles of NH3 were produced in the process?
1. To solve for the grams of H2 needed, we need to use the given ΔH value to calculate the amount of moles of N2 that reacted. From the balanced chemical equation, we know that for every 3 moles of H2 that reacts, 1 mole of N2 reacts. Therefore, we can use the mole ratio to convert the moles of N2 to moles of H2 and then use the molar mass of H2 to convert to grams.
First, we need to calculate the moles of N2 that reacted to produce 150.9kJ of heat:
ΔH = -92.40 kJ/mol N2
150.9 kJ = (1 mol N2 / -92.40 kJ) x (-150.9 kJ)
mol N2 = 1.63 mol
Using the mole ratio from the balanced chemical equation:
1 mol N2 : 3 mol H2
We can calculate the moles of H2 needed:3 mol H2 = 1 mol N2
3 mol H2 = 1.63 mol N2
mol H2 = 0.543 mol
Finally, we can convert moles of H2 to grams:
mol H2 = 0.543 mol
molar mass of H2 = 2.02 g/mol
grams of H2 = (0.543 mol) x (2.02 g/mol)
grams of H2 = 1.10 g
Therefore, 1.10 grams of H2 are needed to involve 150.9kJ of heat.
2. To solve for the moles of NH3 produced, we can use the same mole ratio from the balanced chemical equation:
1 mol N2 : 2 mol NH3
From the moles of N2 that reacted calculated in part 1, we can calculate the moles of NH3 produced:
1 mol N2 = 2 mol NH3
1 mol N2 = 1.63 mol N2
mol NH3 = (2 mol NH3 / 1 mol N2) x (1.63 mol N2)
mol NH3 = 3.26 mol
Therefore, 3.26 moles of NH3 were produced in the process.
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Strychnine, a deadly poison, has a molecular mass of 334 g/mol and a percentage composition of 75.45% carbon, 6.59% hydrogen, 8.38% nitrogen, and the balance oxygen. What is the molecular formula of strychnine?
The molecular formula of the strychnine, given that it is composed of 75.45% carbon, 6.59% hydrogen, 8.38% nitrogen, and the balance oxygen is C₂₁H₂₂N₂O₂
How do i determine the molecular formula?First, we shall obtain the empirical formula of compound. Details below:
Carbon (C) = 75.45%Hydrogen (H) = 6.59%Nitrogen (N) = 8.38%Oxygen (O) = 100 - (75.45 + 6.59 + 8.38) = 9.58%Empirical formula =?Divide by their molar mass
C = 75.45 / 12 = 6.2875
H = 6.59 / 1 = 6.59
N = 8.38 / 14 = 0.5986
O = 9.58 / 16 = 0.59875
Divide by the smallest
C = 6.2875 / 0.5986 = 10.5
H = 6.59 / 0.5986 = 11
N = 0.5986 / 0.5986 = 1
O = 0.59875 / 0.5986 = 1
Multiply through by 2 to express in whole number
C = 10.5 × 2 = 21
H = 11 × 2 = 22
N = 1 × 2 = 2
O = 1 × 2 = 2
Thus, we can conclude that the empirical formula is C₂₁H₂₂N₂O₂
Now, we shall determine the molecular formula of strychnine. Details below
Empirical formula = C₂₁H₂₂N₂O₂Molar mass of compound = 334 g/molMolecular formula =?Molecular formula = empirical × n = mass number
[C₂₁H₂₂N₂O₂]n = 140.22
[(12×21) + (1×22) + (14×2) + (16×2)]n = 334
334n = 334
Divide both sides by 334
n = 334 / 334
n = 1
Molecular formula = [C₂₁H₂₂N₂O₂]n
Molecular formula = [C₂₁H₂₂N₂O₂]1
Molecular formula = C₂₁H₂₂N₂O₂
Thus, we can conclude that the molecular formula of strychnine is C₂₁H₂₂N₂O₂
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please provide explanation!! thank you in advance!!
The molarity of the product is 0.00368 M. Option B
What is the reaction equilibrium?When the rates of the forward and reverse reactions in a chemical reaction are equal and the concentrations of reactants and products are stable over time, this condition is referred to as reaction equilibrium.
The equilibrium constant is a measure of the relative concentrations of reactants and products at equilibrium.
[tex]Keq = [H_{2} O] [CO]/[H_{2}] [CO_{2} ]\\0.106 = x^2/(0.0113)^2\\x = \sqrt{} 0.106 (0.0113)^2\\x = 0.00368 M[/tex]
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You want to make a 50 mL SATURATED solution of potassium chloride at 40 degrees Celsius. How many grams of potassium chloride do you need?
We need 21 grams of potassium chloride to make a 50 mL saturated solution at 40 degrees Celsius. It's important to note that if the temperature or volume of the solution were to change, the amount of solute needed to make a saturated solution would also change, as solubility is dependent on both temperature and volume.
According to the solubility table, the solubility of potassium chloride at 40 degrees Celsius is 42 grams per 100 mL of water. This means that we can dissolve 42 grams of potassium chloride in 100 mL of water at 40 degrees Celsius to make a saturated solution.
To make a 50 mL saturated solution, we can use the following formula:
mass of solute = (volume of solution x solubility)/100
mass of solute = (50 x 42)/100
mass of solute = 21 grams
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Based on the solubility rules, which one of these phosphate compounds is insoluble in water?
A) Li2CO3
B) Na3PO4
C) Ba(OH)2
D) (NH4)3PO4
(NH4)3PO4 is insoluble in water. The correct option is D
What is solubility rules ?According to their chemical formula and ionic charges, ionic compounds generally follow a set of solubility laws that define their solubility patterns in water. These guidelines aid in determining whether an ionic compound will dissolve in water or not as well as if it will precipitate when combined with other ionic compounds.
Therefore, (NH4)3PO4 is the compound that is expected to be insoluble in water based on the solubility rules.
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How many grams of magnesium oxide would be formed if 28.2 grams of magnesium was burned?
Mg + O2 --> MgO
When 28.2 grams of Mg is burned, 46.7 grams of MgO will be formed.
How to determine the amount of MgO formed when 28.2 grams of Mg is burnedThe balanced chemical equation for the combustion of magnesium is:
2 Mg + O2 --> 2 MgO
This equation shows that 2 moles of Mg react with 1 mole of O2 to produce 2 moles of MgO.
To determine the amount of MgO formed when 28.2 grams of Mg is burned, we first need to convert the given mass of Mg to moles:
molar mass of Mg = 24.31 g/mol
moles of Mg = mass of Mg / molar mass of Mg
moles of Mg = 28.2 g / 24.31 g/mol
moles of Mg = 1.16 mol
According to the balanced chemical equation, 2 moles of Mg produce 2 moles of MgO. Therefore, we can use the mole ratio to calculate the moles of MgO formed:
moles of MgO = moles of Mg x (2 moles of MgO / 2 moles of Mg)
moles of MgO = 1.16 mol x 1
moles of MgO = 1.16 mol
Finally, we can convert the moles of MgO to grams using its molar mass:
molar mass of MgO = 40.31 g/mol
mass of MgO = moles of MgO x molar mass of MgO
mass of MgO = 1.16 mol x 40.31 g/mol
mass of MgO = 46.7 g
Therefore, when 28.2 grams of Mg is burned, 46.7 grams of MgO will be formed.
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5. A sample of unknown metal has a mass of 135 grams. As the sample cools from 100.5 °C to 35.5 °C, it releases 7500 joules of energy. What is the specific heat of the sample?
please show work
The sample of the unknown metal has the mass of the 135 grams. The sample cools from the 100.5 °C to the 35.5 °C, and it releases the 7500 joules of the energy. The specific heat of the sample is 0.854 J/g °C.
Th mass of the metal = 135 g
The initial temperature = 100.5 °C
The final temperature = 35.5 °C
The heat energy releases = - 7500 J
The heat energy is expressed as :
Q = mc ΔT
Where,
The m is mass of the metal = 135 g
The c is the specific heat capacity = ?
The Q is heat energy releases = - 7500 J
The ΔT is the change in the temperature = final temperature - initial temperature.
The ΔT is the change in the temperature = 35.5 - 100.5
The ΔT is the change in the temperature = - 65 °C
The specific heat capacity, c = Q / m ΔT
The specific heat capacity, c = - 7500 / 135 × - 65
The specific heat capacity, c = 0.854 J/g °C
The specific heat capacity of metal is 0.854 J/g °C.
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What mass (grams) of oxygen will be released when 268.9 grams of Potassium Chlorate is thermally decomposed?
KClO3 --> KCl + O2
The centripetal acceleration experienced by the object can be calculated using the formula a = v^2/r, where v is the speed of the object and r is the radius of the circle. Substituting the given values, we get:
a = (50 cm/s)^2 / (250 cm)
a = 10 cm/s^2
Therefore, the centripetal acceleration experienced by the object is 10 cm/s^2.
To calculate the centripetal acceleration experienced by the object, you can use the formula:
Centripetal acceleration (a_c) = (velocity^2) / radius
Here, the velocity (v) is 50 cm/s and the radius (r) is 250 cm. Plugging in these values, we get:
a_c = (50^2) / 250 = 2500 / 250 = 10 cm/s²
So, the centripetal acceleration experienced by the object is 10 cm/s².
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d. Given this law, 4 of 4.
Select Choice
of hydrogen (H2) is produced in the following reaction.
Zn + 2HCl → ZnCl2 + H2
65 g 72 g 135 g ?
The mass of hydrogen produced in the reaction is 2g.
What is Mole?The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.
A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.
Given,
Mass of Zn = 65g
Mass of HCl = 72g
Moles of Zn = mass / molar mass
= 65 / 65 = 1 mole
Moles of HCl = 72 / 36.5
= 1.97 moles
Since moles of Zn is lesser, therefore it is the limiting reagent.
From the reaction, 1 mole of Zn gives 1 mole of hydrogen
Moles of hydrogen = 1 mole
mass of hydrogen = moles × molar mass
= 1 × 2 = 2g
Therefore, the mass of hydrogen produced in the reaction is 2g.
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Why does the air feel "sticky" on warm summer days? What is in the air that caausses this
Hellpppp with this question!!! THE ANSWER IS NOT 0.3 or 0.5
the answer is 2.5 according to me
What is the equilibrium constant, K? 3 A(g) + 3 B(g) <-> 5 C(g) + 2 D(g)
The equilibrium constant is written as;
Keq = [tex][D]^2 [C]^5/[A] [B]^3[/tex]
What is the equilibrium constant?The equilibrium constant's value is influenced by the reaction's chemical make-up and temperature.
The product of the product concentrations, each raised to the power of their stoichiometric coefficient, divided by the product of the reactant concentrations, each raised to the power of their stoichiometric coefficient, is known as the equilibrium constant.
The equilibrium constant is Keq = [tex][D]^2 [C]^5/[A] [B]^3.[/tex]
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help with questions 1-5 pls??
In comparison to towns located inland, cities close to water features like lakes or oceans typically experience cooler summer temperatures.
Why is a city not so hot in summer when the city is close to water?Since water has a higher specific heat capacity than land, this is the case. The quantity of energy needed to raise a substance's temperature by a specific amount is known as its specific heat capacity. Compared to land, raising the temperature of water requires more energy because water has a higher specific heat capacity.
The summer sun warms both land and water, but due to land's lower specific heat capacity, land warms up more quickly than water. As a result, communities farther from water bodies tend to be hotter than cities closer to water.
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8. The compound C2H4 has van der Waals constants a = 4.612 atm•L2/mol2 and b = 0.0582 L/mol. Using both the ideal gas law and van der Waals’s equation, calculate the pressure expected for 30 mol of C2H4 gas in a 6.00-L container at 20 °C.
Using the Ideal Gas Law, the pressure expected for 30 mol of [tex]C_2H_4[/tex] gas in a 6.00-L container at 20 °C is 1210.07 atm, and using the van der Waals equation, the pressure is 1179.71 atm.
To calculate the pressure expected for 30 mol of [tex]C_2H_4[/tex] gas in a 6.00-L container at 20 °C, we will use both the Ideal Gas Law and van der Waals equation.
Ideal Gas Law: PV = nRT
P = pressure
V = volume (6.00 L)
n = moles (30 mol)
R = ideal gas constant (0.0821 L•atm/mol•K)
T = temperature (20 °C + 273.15 = 293.15 K)
Solve for P (pressure):
P = nRT / V
P = (30 mol)(0.0821 L•atm/mol•K)(293.15 K) / 6.00 L
P = 1210.07 atm
Van der Waals equation:
(P + a(n/V)²)(V - nb) = nRT
a = 4.612 atm•L²/mol²
b = 0.0582 L/mol
Solve for P (pressure):
(P + (4.612)(30/6)²) (6 - 0.0582 * 30) = (30)(0.0821)(293.15)
P = 1179.71 atm
Using the Ideal Gas Law, the pressure is 1210.07 atm, and using the van der Waals equation, the pressure is 1179.71 atm.
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what element has 68 degrees Celsius
PLEASE HELP!!
351.6g of Chromium-63 is allowed to decay for 128.8 years, how much Chromium-63
is left? (The half life of 63 Cr is 32.2 days.) Please, enter your answer as a one decimal
place number with no units.
A crucial trace mineral is chromium. Trivalent chromium, which is safe for people, and hexavalent chromium, which is toxic, are the two types.
Thus, Foods and dietary supplements both contain trivalent chromium. It might assist maintain normal blood sugar levels by enhancing the body's utilization of mineral.
Chromium is used by people to treat deficiencies. Additionally, it is used to treat bipolar disorder, diabetes, high cholesterol, and a variety of other conditions, but the majority of these uses are not well-supported by science.
Chromium by mouth doesn't help control blood sugar levels in people with prediabetes. Schizophrenia. Taking chromium by mouth doesn't affect weight or mental health in people with schizophrenia.
Thus, A crucial trace mineral is chromium. Trivalent chromium, which is safe for people, and hexavalent chromium, which is toxic, are the two types.
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Perform the conversions between energy units.
6.61 x 10^6 J = ___kcal. My initial answer was 6610 but it was wrong can someone show me how to get the correct answer
After considering the given data and performing the evaluation regarding the convertion of energy units the answer derived is 6.61 x 10⁶ J = 1577.16 kcal.
In order to alter joules (J) to kilocalories (kcal), the below conversion can be applied.
1 kcal = 4.184 kJ.
We start by, converting J to kJ by dividing by 1000:
6.61 x 10⁶ J = 6.61 x 10³ kJ
Next step we convert kJ to kcal by dividing by 4.184:
= 6.61 x 10³ kJ ÷ 4.184
= 1577.16 kcal (rounded to five significant figures)
1 joule (J) is the amount of energy needed to apply a force of 1 newton (N) over a distance of 1 meter (m).
1 kilocalorie (kcal), on the other hand, is described as the amount of energy required to increase the temperature of 1 kilogram (kg) of water by 1 degree Celsius (°C), which is equal to 4184 joules (J).
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please help me pair pka values with displayed molecules
If we label the compounds ABCD from left to right;
A - 12.10
B - 15.90
C - 12.66
D - 12.35
What is the pKa?A molecule or compound's acidity is quantified by the pKa, which is the negative logarithm (base 10) of the acid dissociation constant (Ka). The lower the pKa value, the stronger the acid; it reflects a compound's propensity to give a proton (H+) in a solution.
The compound that has the highest number of attachment of the most electronegative elements would have the greatest pKa.
The justification of the answer above is that, seeing that the compound labelled B has three highly electronegative atoms hence it would have the most or the highest pKa of about 15.90 among the other compounds. The other compounds A, C and D have fewer electronegative atoms attached and thus a lower pKa as shown
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Isoprenol (C₅H₁₀O) can be produced from isobutene (C₄H₈) and formaldehyde (CH₂O) via the following reaction scheme. What is the change in enthalpy in kJ associated with the production of 155.3 g C₅H₁₀O (isoprenol)?
C₄H₈(g) + CH₂O(g) → C₅H₁₀O(l) ∆H = -191.3 kJ
To determine the change in enthalpy associated with the generation of 155.3 g of [tex]C_5H_1_0O[/tex] we must first calculate the moles of [tex]C_5H_1_0O[/tex] produced using its molar mass.
The molar mass of C₅H₁₀O is:
5(12.01 g/mol) + 10(1.01 g/mol) + 16.00 g/mol = 88.15 g/mol
Moles of C₅H₁₀O produced:
155.3 g / 88.15 g/mol = 1.763 mol C₅H₁₀O
The balanced chemical equation states that the formation of 1 mol of C₅H₁₀O results in an enthalpy change of -191.3 kJ.
As a result, the enthalpy change during the formation of 1.763 mol of C₅H₁₀O is: -191.3 kJ/mol x 1.763 mol = -337.8 kJ
The enthalpy change for the production of 155.3 g of C5H10O is -337.8 kJ.
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