The concentration of NO3- ions in 0. 25 M Ti(NO3)4(aq) is???

Here, 47.29 mg of chlorine is needed to react with 0.175g of gold.

To calculate the mass of chlorine needed to react with 0.175g of gold, we will use the equation and the relative atomic masses provided.

1. First, find the moles of gold:

Moles of gold = mass / relative atomic mass

Moles of gold = 0.175g / 197g/mol

                       = 0.0008883 mol

2. According to the balanced equation, 2 moles of gold react with 3 moles of chlorine. So, we need to find the moles of chlorine required:

Moles of chlorine = (3/2) * moles of gold

Moles of chlorine = (3/2) * 0.0008883 mol

                             = 0.001332 mol

3. Now, find the mass of chlorine needed:

Mass of chlorine = moles of chlorine * relative atomic mass

Mass of chlorine = 0.001332 mol * 35.5g/mol

                            = 0.04729g

4. Finally, convert the mass from grams to milligrams:

Mass of chlorine in mg = 0.04729g * 1000mg/g

                                      = 47.29mg

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Weather forecasting has substantially improved thanks to technical and data analytic advancements, but there are still a lot of intricate and dynamic aspects that can influence weather patterns, such as changes in air pressure, temperature, and humidity.

It is challenging to forecast a storm's precise trajectory and strength due to the possibility of unforeseen events and anomalies. The effects of catastrophic weather occurrences can be mitigated and forecasting accuracy can be increased with the help of ongoing technical and scientific developments.

In addition to forecasting technologies, infrastructure should be resilient to the effects of powerful storms and early warning systems that can alert people to approaching danger from severe weather should be available.

Not all countries have the financial means to support the development and application of these technologies. It is morally right for developed countries to help less developed ones obtain this technology.

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The subscript numbers in covalent compounds can be determined by the prefixes used in the written name of the compound.

Covalent compounds are formed by the sharing of electrons between atoms, and their names are derived from the prefixes used to indicate the number of each type of atom in the compound.

The prefix indicates the number of atoms of each element, and the second element is given an "-ide" ending. For example, carbon dioxide has one carbon atom and two oxygen atoms, and is written as CO₂. The prefix "di" indicates two atoms of oxygen, and the subscript "2" indicates that there are two oxygen atoms.

Similarly, dinitrogen trioxide has two nitrogen atoms and three oxygen atoms, and is written as N₂O₃. The prefix "di" indicates two nitrogen atoms, and the prefix "tri" indicates three oxygen atoms, thus leading to the correct subscript numbers.

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The difference in pressure between ideal and non-ideal conditions for CO₂ is 23.42 atm.

To find the difference in pressure between ideal and non-ideal conditions for CO₂, we need to use the van der Waals equation:

(P + a(n/V)²)(V - nb) = nRT

where P is the pressure, n is the number of moles, V is the volume, T is the temperature, R is the gas constant, a is a constant related to the attractive forces between molecules, and b is a constant related to the volume of the molecules.

First, we need to calculate the volume of the CO₂ molecules using the given values of n and V:

V/n = V/2.0 mol = 7.30 L/2.0 mol = 3.65 L/mol

Next, we can plug in the given values of a, b, n, V, and T into the van der Waals equation:

(P + a(n/V)²)(V - nb) = nRT

(4.50 atm + 3.59 L²･atm/mol²(2.0 mol/3.65 L)²)(7.30 L - 0.0427 L/mol × 2.0 mol) = 2.0 mol × 0.0821 L･atm/mol･K × 200.0 K

Simplifying the equation, we get:

(4.50 + 3.59(2.0/3.65)²)(7.30 - 0.0427 × 2.0) = 32.19

Therefore, the non-ideal pressure is:

Pnon-ideal = 32.19 atm

To find the ideal pressure, we can use the ideal gas law:

PV = nRT

Pideal = nRT/V = 2.0 mol × 0.0821 L･atm/mol･K × 200.0 K/7.30 L

Pideal = 8.77 atm

Finally, we can calculate the difference in pressure between ideal and non-ideal conditions:

ΔP = Pnon-ideal - Pideal = 32.19 atm - 8.77 atm = 23.42 atm

Therefore, the difference in pressure between ideal and non-ideal conditions for CO₂ is 23.42 atm.

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The phrase "the molarity of a solution" refers to the concentration of a solution and is defined as the number of moles of solute dissolved in one liter of solution. It is denoted by the symbol "M" and has units of moles per liter (mol/L).

Molarity is a commonly used unit of concentration in chemistry and is particularly useful in stoichiometry calculations, as it allows for the conversion of the volume of a solution to the number of moles of solute present.

For example, a solution with a molarity of 0.1 M contains 0.1 moles of solute per liter of solution. If the volume of the solution is known, it is possible to calculate the number of moles of solute present and use this information to determine other important parameters, such as the mass of the solute or the volume of another solution required for a reaction.

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Nitrogen gas ([tex]N_2[/tex]) has a molar mass of 28.02 g/mol, while hydrogen gas ([tex]H_2[/tex]) has a molar mass of 2.02 g/mol. Ammonia ([tex]NH_3[/tex]) has a molar mass of 17.03 g/mol.

We must calculate the moles of each reactant in order to identify the limiting reactant. We may determine that there are 5.0 moles of [tex]N_2[/tex] and 1.0 moles of [tex]H_2[/tex] based on the stated masses. The reaction is described by the balanced chemical equation [tex]N_2 + 3H_2 2NH_3[/tex], which indicates that 1 mole of [tex]N_2[/tex] reacts with 3 moles of [tex]H_2[/tex]. As a result, [tex]H_2[/tex] is the limiting reactant and there will be an excess reactant of 2.0 - (1.0/3) = 1.67 grams of [tex]H_2[/tex].

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--The complete Question is, What is the molar mass of nitrogen gas, hydrogen gas, and ammonia in the Haber Process? Given that 11.0 grams of nitrogen gas and 2.0 grams of hydrogen gas are available, which reactant is the limiting reactant? What is the amount of excess reactant left over after the reaction?--

The pH of the solution is 1.30

To determine the pH of a solution, the formula:

pH = -log[H3O+]

Given a concentration of H3O+ in the solution as 0.050 M, substituting this value into the formula yields:

pH = -log(0.050)

By evaluating this expression using a calculator, the pH is found to be 1.30. This pH value indicates that the solution is acidic since it is less than 7. The pH scale is logarithmic, meaning that each unit change in pH corresponds to a tenfold change in the acidity or basicity of the solution. Consequently, a solution with a pH of 1 is ten times more acidic than a solution with a pH of 2, and a hundred times more acidic than a solution with a pH of 3, and so forth.

Therefore, a pH of 1.30 denotes a moderately acidic solution.

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Ten different pollinators plants or trees or flowers are Bee balm, Black-eyed Susan, Butterfly weed, Coneflower, Lavender, Milkweed, Redbud tree, Sunflower, Wild rose, and Zinnia.

Pollinator plants are known as plants that attract and support pollinators, such as bees, butterflies, birds, and other insects or animals. The pollinators they attract help transfer pollen from one flower to another.

When pollinators tranfer pollens, they facilitate the fertilization and reproduction of flowering plants.

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Red tape is used to repair a broken red taillight of a car as it is transparent to red light, reflects and absorbs other colors of light.

When white light (which is made up of different colors of light) hits the red tape, it absorbs all colors except for red, which is transmitted through the tape.

This is due to the selective absorption property of the tape, which means that it absorbs certain colors of light while allowing others to pass through. Additionally, the tape also reflects red light, which allows it to mimic the original color of the taillight and appear red when viewed from behind.

This property of selective absorption and reflection makes red tape a suitable material for repairing a broken red taillight of a car.

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In the reaction of the oxidation of chromium, 4 chromium atoms each lose 3 electrons to become positively charged ions, and 3 oxygen molecules each gain 4 electrons to become negatively charged ions. This means that a total of 12 electrons are transferred in the oxidation of chromium.

The oxidation of chromium can be broken down into two half-reactions:

1) The oxidation of chromium:
4Cr(s) --> 4Cr³⁺(aq) + 12e-

In this half-reaction, each

chromium atom loses 3 electrons to become a positively charged ion (Cr³⁺), and a total of 12 electrons are

transferred

.

2) The reduction of oxygen:
3O₂(g) + 12e- --> 6O²⁻(aq)

In this half-reaction, each oxygen molecule gains 4 electrons to become a negatively charged ion (O²⁻), and a total of 12 electrons are transferred.

Therefore, the total number of electrons transferred during the reaction of the oxidation of chromium is 12. It is important to note that this reaction involves the transfer of O₂ electrons, not O₄ electrons.

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The reaction Zn + 2HCl → ZnCl2 + H2 involves the oxidation of zinc (Zn) to zinc chloride (ZnCl2) and the reduction of hydrogen ions (H+) to hydrogen gas (H2). In this reaction, zinc loses electrons, which is known as oxidation, while hydrogen ions gain electrons, which is known as reduction.

The balanced half-reactions describing these processes are:

Oxidation half-reaction: Zn → Zn2+ + 2e-

Reduction half-reaction: 2H+ + 2e- → H2

In the oxidation half-reaction, zinc atoms lose two electrons each and are oxidized to Zn2+ ions. These electrons are then transferred to the hydrogen ions in the reduction half-reaction, where they are used to reduce H+ ions to form H2 gas. Overall, the two half-reactions combine to form the balanced equation:

Zn + 2HCl → ZnCl2 + H2

It is important to note that oxidation and reduction always occur together in a redox reaction, and the transfer of electrons is what drives the reaction. In the case of ZnCl2 formation, the reaction is driven by the transfer of electrons from the zinc atoms to the hydrogen ions.

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The order of the reaction in ligand is zeroth order, as changing the ligand concentration from 1.0 mM to 200 mM does not affect the reaction rate. The rate equation is: rate = k[substrate], where k is the rate constant.

The order of the reaction in substrate is first order, as doubling the substrate concentration (from 5 mM to 10 mM) leads to a doubling of the reaction rate so the or.

To find the MSDS for decahydronaphthalene, one can search for it on the website of the manufacturer or supplier. Alternatively, one can search for it on the website of the National Institute for Occupational Safety and Health (NIOSH), which provides a database of MSDSs for various chemicals.

It is important to consult the MSDS before handling or using the chemical, as it contains information on its physical and chemical properties, hazards, and precautions for safe use and disposal.

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a) The ionization reaction of nitric acid (HNO₃) with water can be written in two different ways:

HNO₃ + H₂O → H₃O⁺ + NO₃⁻

or

HNO₃ + H₂O ⇌ H⁺ + NO₃⁻ + H₂O

Both equations are balanced.

b) The two expressions for the acid dissociation constant (Ka) can be derived from the two equations above:

Ka = [H₃O⁺][NO₃⁻] / [HNO₃]

or

Ka = [H⁺][NO₃⁻] / [HNO₃]

c) Nitric acid is a strong acid, meaning that it fully dissociates in water. As a result, the concentration of HNO3 in the equation is very low, making the Ka value very large. In fact, the Ka value for nitric acid is around 24, which is significantly higher than the Ka values for weak acids. This indicates that nitric acid is a very strong acid.

Let us learn more about this.

a) Ionization reaction - The ionization reaction refers to the process in which a molecule or compound dissociates into ions when it comes into contact with a solvent such as water. In the case of nitric acid (HNO₃), when it is added to water, it ionizes to produce hydronium ions (H₃O⁺) and nitrate ions (NO₃⁻), which is represented by the following balanced equation: HNO₃ + H₂O -> H₃O⁺ + NO₃⁻

b) Ka - To define Ka, we need to first understand that it is the equilibrium constant for the ionization reaction, which indicates the strength of an acid. Specifically, Ka measures the extent to which an acid dissociates in water, which can be expressed as the following two equations: Ka = [H₃O⁺][NO₃⁻]/[HNO₃] Ka = [H⁺][NO₃⁻]/[HNO₃] where [H₃O⁺] and [H⁺] represent the concentration of hydronium ions, and [NO₃⁻] and [HNO₃] represent the concentration of nitrate ions and nitric acid, respectively.

c) As nitric acid is a strong acid, it dissociates completely in water, meaning that the concentration of H₃O⁺ and NO₃⁻ ions will be high compared to the concentration of undissociated HNO₃. Therefore, the value of Ka for this reaction will be very large, indicating that nitric acid is a strong acid with a high degree of ionization.

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At equilibrium, the concentrations of [tex]H_{3} O+, C_{6} H_{5}COO[/tex]-, and [tex]C_{6} H_{5}COO[/tex] in the solution will be 0.038 M, 0.038 M, and 0.012 M, respectively.

First, we can write the chemical equation for the dissociation of benzoic acid in water as follows:  [tex]C_{6}H5COOH + H_{2}O[/tex] ⇌[tex]C_{6}H_{5}COO- + H_{3}O[/tex]

The acid dissociation constant, Ka, is given as 6.3 × 10^-5.

[tex]Ka = [C_{6}H_{5}COO-][H_{3}O+] / [C_{6}H_{5}COOH][/tex]

We can assume that the initial concentration of [tex]C_{6}H_{5}COOH[/tex] is equal to its concentration at equilibrium, x. Thus, at equilibrium:

[tex][C_{6}H_{5}COOH] = x M \\[/tex]

[tex][C_{6}H_{5}COO-] = y M \\[/tex]

[tex][H_{3}O+] = y M\\[/tex]

Using the equilibrium expression and the given value of Ka, we can solve for the values of x and y:

[tex]Ka = [C_{6}H_{5}COO-][H_{3}O+] / [C_{6}H_{5}COOH]\\6.3 * 10^-5 = y^2 / x[/tex]

Since we know that the initial concentration of benzoic acid is 0.050 M, we can write: [tex]x + y = 0.050 M[/tex]

Now we have two equations and two unknowns. Solving for x and y:

[tex]x = 0.012 M\\y = 0.038 M[/tex]

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the molar solubility of Ni(OH)2 when buffered at pH 8.0, 10.3, and 11.9 is approximately 3.9×10^-6 M in all cases.

The solubility of Ni(OH)2 depends on the pH of the solution because it can undergo acid-base reactions according to the following equilibrium:

Ni(OH)2(s) + 2 H2O(l) ⇌ Ni(OH)2(aq) + 2 OH^-(aq)

1. At pH 8.0, the solution is slightly basic, so we can assume that the hydroxide ion concentration is 10^-6 M.

The solubility product expression for Ni(OH)2 is:

Ksp = [Ni2+][OH^-]^2

Since the solution is buffered at pH 8.0, we can assume that the concentration of Ni2+ is negligible compared to the concentration of OH^-.

Therefore, [OH^-]^2 = Ksp = 6.0×10^-16 M^3

[OH^-] = sqrt(Ksp) = 7.7×10^-6 M

The molar solubility of Ni(OH)2 is half the hydroxide ion concentration, or 3.9×10^-6 M.

2. At pH 10.3, the hydroxide ion concentration is 10^-4.7 M.

[OH^-]^2 = Ksp = 6.0×10^-16 M^3

[OH^-] = sqrt(Ksp) = 7.7×10^-6 M

The excess hydroxide ion concentration is:

[OH^-] - 10^-4.7 M = -7.6×10^-6 M

Since the excess hydroxide ion concentration is small compared to the total concentration of OH^-, we can assume that the concentration of Ni2+ is negligible compared to the concentration of OH^-.

The molar solubility of Ni(OH)2 is half the hydroxide ion concentration, or 3.9×10^-6 M.

3. At pH 11.9, the hydroxide ion concentration is 10^-3.1 M.

[OH^-]^2 = Ksp = 6.0×10^-16 M^3

[OH^-] = sqrt(Ksp) = 7.7×10^-6 M

The excess hydroxide ion concentration is:

[OH^-] - 10^-3.1 M = -9.9×10^-6 M

Since the excess hydroxide ion concentration is small compared to the total concentration of OH
^-, we can assume that the concentration of Ni2+ is negligible compared to the concentration of OH^-.

The molar solubility of Ni(OH)2 is half the hydroxide ion concentration, or 3.9×10^-6 M.

Therefore, the molar solubility of Ni(OH)2 when buffered at pH 8.0, 10.3, and 11.9 is approximately 3.9×10^-6 M in all cases.
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The blanks are filled by the following;

A balanced reaction equation is a chemical equation that shows the reactants and products of a chemical reaction, and the relative amounts of each involved in the reaction.

In a balanced reaction equation, the number of atoms of each element must be the same on both sides of the equation. This is achieved by adjusting the coefficients (the numbers in front of the chemical formulas) of the reactants and products until the number of atoms of each element is equal on both sides.

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The molarity of the diluted ammonium chloride solution is 0.09475 M.

The molarity of the diluted ammonium chloride solution, we can use the equation:

[tex]M_1V_1 = M_2V_2[/tex]

here [tex]M_1[/tex] is the initial molarity

[tex]V_1[/tex] is the initial volume,

[tex]M_2[/tex] is the final molarity, and

[tex]V_2[/tex] is the final volume.

[tex]M_1[/tex] = 3.79 M (from the initial solution)

,[tex]V_1[/tex]  = 50.0 mL = 0.050 L (from the initial solution)

[tex]V_2[/tex] = 2.0 L (the final volume after dilution)

For  [tex]M_2[/tex] , we get:

[tex]M_2[/tex]  = ( [tex]M_1[/tex] × ,[tex]V_1[/tex] ) /  [tex]V_2[/tex]

[tex]M_2[/tex]  = (3.79 M × 0.050 L) / 2.0 L

[tex]M_2[/tex]  = 0.09475 M

Therefore, the molarity of the diluted ammonium chloride solution is 0.09475 M.

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If we add 45.0 g of sodium chloride to 500.0 g of water,  the melting point is -  5.7 °C and the boiling point of the solution is 101.5 °C.

The mass of the NaCl = 45 g

The mass of the water = 500 g

The moles of the NaCl = mass / molar mass

                                      = 45 / 58.44

                                      = 0.770 mol

The molality is expressed as :

b = moles of solute / mass of solvent in kg

b = 0.770 / 0.5

b = 1.54 m

The boiling-point elevation  :

ΔTb = 2 × 0.512 × 1.54

       = 1.5 ° C

The boiling point, Tb = 100°C + 1.5 °C

                                   = 101.5 °C

The expression is as :

ΔTf = 2 × 1.86 × 1.54

     = 5.7 °C

The melting point = 0 - 5.7

                              = - 5.7 °C

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Compared to the average population around the world, North America has a (a) 24% greater percentage of people with access to safely managed drinking water facilities as of 2020.

According to the information provided, the percentage of the population with access to drinking water facilities in North America is higher than the average for the world.

The exact percentage varies depending on the option selected in the question, but the difference ranges from 16% to 98%. This difference may be attributed to several factors, including a more developed infrastructure and better regulation of water quality in North America.

However, it is important to note that access to drinking water is still a significant issue in some areas of North America, particularly among marginalized communities. Efforts to improve water access and quality must continue to ensure that everyone has access to this essential resource.

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Answer is D)1.10 grams

From the balanced equation, we know that for every 1 mole of carbonic acid (H2CO3) that is heated, 1 mole of carbon dioxide ([tex]CO_2[/tex]) is produced. The molar mass of [tex]H_2CO_3[/tex] is 62.03 g/mol, while the molar mass of [tex]CO_2[/tex] is 44.01 g/mol.

To find out how much carbon dioxide is formed from 1.55 g of carbonic acid, we first need to convert the mass of  [tex]H_2CO_3[/tex] to moles:

1.55 g  [tex]H_2CO_3[/tex] / 62.03 g/mol  [tex]H_2CO_3[/tex] = 0.025 mol  [tex]H_2CO_3[/tex]

Since the mole ratio of [tex]H_2CO_3[/tex] to [tex]CO_2[/tex] is 1:1, we know that 0.025 moles of [tex]CO_2[/tex] will be produced.

To convert this to grams:

0.025 mol [tex]CO_2[/tex] x 44.01 g/mol [tex]CO_2[/tex] = 1.10 g CO2

Therefore, 1.55 g of carbonic acid will produce 1.10 g of carbon dioxide upon heating.

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This procedure of filtering barium sulfate out of water doesn't remove all of the barium ions from the water.

The balanced equation is

BaCl₂(aq) + K₂SO₄(aq) → BaSO₄(s) + 2KCl(aq)

The reaction consumes 1 mole of barium chloride. The reaction produces 1 mole of barium sulfate and 2 moles of potassium chloride. This type of reaction is an example of a double displacement reaction where mutual exchange of cation and anion takes place.

Since, the aqueous ions are too small to filter they are carried away with the filtrate solution, leaving behind the precipitate. So, Barium ions will still be present in the solution of water.

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The molarity of the hydrochloric acid solution is 1.93 M.

In this titration, a solution of hydrochloric acid of unknown concentration is titrated with a standard solution of magnesium hydroxide. The balanced chemical equation for the reaction is:

[tex]Mg(OH)2 + 2HCl[/tex] →[tex]MgCl2 + 2H2O[/tex]

moles HCl = moles Mg(OH)2 * (2/1)

From the problem, we know that 14.3 mL of 1.35 M Mg(OH)2 is required to titrate 20.0 mL of HCl of unknown concentration.

moles Mg(OH)2 = (1.35 mol/L) * (0.0143 L) = 0.019305 mol

Finally, we can calculate the molarity of the hydrochloric acid solution:

Molarity of HCl = moles HCl / volume of HCl solution in liters

Molarity of HCl = 0.03861 mol / 0.0200 L = 1.93 M

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16.128 grams of hydrogen gas would need to react in order to produce 972 kJ of heat energy.

So, first, we can calculate the amount of heat energy released per mole of [tex]H_2[/tex] reacted:

243 kJ of heat / 2 moles of [tex]H_2[/tex] = 121.5 kJ/mol of [tex]H_2[/tex]

We can use the following equation to calculate the amount of hydrogen gas required:

Amount of [tex]H_2[/tex]  = Energy released / Heat of reaction per mole of [tex]H_2[/tex]

Amount of [tex]H_2[/tex] = 972 kJ / 121.5 kJ/mol = 8 moles of [tex]H_2[/tex]

Finally, we can calculate the mass of [tex]H_2[/tex] required using its molar mass:

Mass of [tex]H_2[/tex] = Number of moles of[tex]H_2[/tex]x Molar mass of [tex]H_2[/tex]

Mass of [tex]H_2[/tex] = 8 moles x 2.016 g/mol = 16.128 g of [tex]H_2[/tex]

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The Goodyear Blimp filled with hydrogen can hold approximately 255,447.62 moles of hydrogen.

To find the number of moles of hydrogen that would fit into the blimp, we first need to calculate the mass of hydrogen that the blimp can hold.

The molar mass of hydrogen is 2.016 g/mol.

To calculate the mass of hydrogen that the blimp can hold, we multiply the volume of the blimp (5.74 x 10^6 L) by the density of hydrogen at standard temperature and pressure (STP), which is 0.0899 g/L:

Mass of hydrogen = volume of blimp x density of hydrogen at STP
Mass of hydrogen = 5.74 x 10^6 L x 0.0899 g/L
Mass of hydrogen = 515,026 g

Now, we can calculate the number of moles of hydrogen by dividing the mass of hydrogen by its molar mass:

Number of moles of hydrogen = mass of hydrogen / molar mass of hydrogen
Number of moles of hydrogen = 515,026 g / 2.016 g/mol
Number of moles of hydrogen = 255,447.62 mol

So, approximately 255,447.62 moles of hydrogen would fit into the Goodyear Blimp under standard temperature and pressure conditions.

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The explanations aq and g are the ones that accurately explain the chemical equation. The appropriate choices are thus C. (so), solid

D. (l), liters

Symbols serve the following four purposes: Motivating others to take action via emotion; socially uniting groups by fostering a sense of common identity and values Clarification and revelation - show insight and clarity into the divine. Communication - conveying emotional components of an event.

The product and reactant symbols have been used to represent the chemical equation. The moles of an element that underwent a reaction are contained in the chemical equation. Prior to the compound, the moles were written as the coefficient.

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The amount of work done on the system is 34 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.

Thermodynamic work is called the transfer of energy between the system and the environment by methods that do not depend on the difference in temperatures between the two. When a system is compressed or expanded, a thermodynamic work is produced which is called pressure-volume work (p - v).

The pressure-volume work done by a system that compresses or expands at constant pressure is given by the expression:

W system= -p∆V

W system: Work exchanged by the system with the environment. Its unit of measure in the International System is the joule (J)

p: Pressure. Its unit of measurement in the International System is the pascal (Pa)

∆V: Volume variation (∆V = Vf - Vi). Its unit of measurement in the International System is cubic meter (m³)

In this case:

p= 0.400 atm

ΔV=(185-100)ml = 85 ml

W system=  0.400 atm× 85 ml =34 J

The amount of work done on the system is 34 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.

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The concentration of KBr in the solution prepared by mixing 0.200 L of 0.053 M KBr with 0.550 L of 0.078 M KBr is 0.0713 M.

The concentration of KBr in the solution can be calculated using the formula:

Concentration = (moles of solute) / (volume of solution in liters)

First, we need to find the moles of KBr in each solution by multiplying the volume of the solution by its molarity:

0.200 L x 0.053 M = 0.0106 moles KBr
0.550 L x 0.078 M = 0.0429 moles KBr

Next, we need to add the moles of KBr from each solution to find the total moles of KBr in the final solution:

0.0106 moles KBr + 0.0429 moles KBr = 0.0535 moles KBr

Finally, we can use the total moles of KBr and the total volume of the solution (which is the sum of the two volumes used) to calculate the concentration:

Concentration = 0.0535 moles / (0.200 L + 0.550 L)
Concentration = 0.0535 moles / 0.750 L
Concentration = 0.0713 M

Therefore, the concentration of KBr in the solution prepared by mixing 0.200 L of 0.053 M KBr with 0.550 L of 0.078 M KBr is 0.0713 M.

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According to the question 19.2 liters of NH3 at 32.6°C and 4.25 kPa is required to react completely with 30.0L of NO at STP.

STP (Standard Temperature and Pressure) is an important concept in the physical sciences. It is the reference state for temperature and pressure in which most measurements are made. In chemistry, STP is used as a reference state for calculating the physical properties of various substances. It is also used in thermodynamics to calculate the physical state of a system. STP is defined as 0 °C (273.15 K) and a pressure of 1 atmosphere (101.325 kPa).

According to the balanced equation, for every 6 moles of NO, 5 moles of NH3 is required. Therefore, we need to calculate the number of moles of NO first.

1 mole of gas at STP occupies 22. 4 liters, so 30.0 liters of NO at STP is equal to 30.0/22.4 = 1.34 moles of NO.

Since we need 5 moles of NH3 for every 6 moles of NO, we need 5/6 x 1.34 = 1.12 moles of NH3.

At 32.6°C and 4.25 kPa, 1 mole of NH3 occupies 17.1 liters, so 1.12 moles of NH3 is equal to 1.12 x 17.1 = 19.2 liters of NH3.

Therefore, 19.2 liters of NH3 at 32.6°C and 4.25 kPa is required to react completely with 30.0L of NO at STP.

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