The CERN particle accelerator is circular with a circumference of 7.0 km.

Required:
a. What is the acceleration of the protons (m=1.67×10^−27kg) that move around the accelerator at of the speed of light? (The speed of light is v=3.00×10^8m/s.)
b. What is the force on the protons?

We are given:

Mass of the rocket = 10 kg

Weight of the Rocket = 100 N

Upward thrust applied by the rocket = 400 N

Net upward force on the rocket:

We are given that gravity pulls the rocket with a force of 100 N

Also, the rocket applied a force of 400N against gravity

Net upward force = Upward thrust - Force applied by gravity

Net upward force = 400 - 100

Net upward force = 300 N

Upward Acceleration of the Rocket:

From newton's second law:

F = ma

replacing the variables

300 = 10 * a

a = 30 m/s²

Answer:

Kinetic energy is converted to internal energy

Explanation:

We are required to explain what happens to this decreased kinetic energy in this question.

Here is what a diffuser does, this device increases the pressure of a fluid and in so doing it slows it down. The lost kinetic energy would then be converted to internal energy. This is the correct answer to the question.

Thank you

Answer:

I like to memorize excerpt from articles to solve and answer questions like these. I hope this can help, it's from study.com: "The relationship between voltage, current, and resistance is described by Ohm's law. This equation, i = v/r, tells us that the current, i, flowing through a circuit is directly proportional to the voltage, v, and inversely proportional to the resistance, r."

Answer: 30 N (in the direction of the 45 N force)

Explanation:

You have to choose a positive and negative direction since the question says the forces are in opposite directions.

Lets assume:

- <----------> +

<------ 15 N

45 ------->

45-15=30

Explanation:

1) the diagonal force times the sine of the angle it makes will give you the vertical component or y component . use this to get the vertical components of all the diagonal forces . add all the vertical components as well as the vertical forces together

2) the diagonal force times the cosine of the angle it makes gives the horizontal component or x component. do this to get the x component of all the diagonal forces.

add all the x components as well as the horizontal forces together to get the final x component

3)using the triangle of vectors, the resultant force is calculated

sum of y component = 3.2N

sum of x component= 5.7N

resultant force = 6.5N

Answer:

[tex]\mathbf{F_{thrust} \simeq 2.3 \times 10^4 \ N}[/tex]

Explanation:

For a lunar lander acceleration in an upward direction, the net force that acts on it can be expressed as:

[tex]F_{net} = F_{thrust} - F_{g(moon)}[/tex]

The equation for the net force that acts on the lunar lander is:

[tex]F_{net} = m_La[/tex]

For the lander touch down to be zero acceleration, it implies that the acceleration of the moving rocket is zero(a free body fall)

i.e. a = 0

We can now regard the Apollo 12 lunar as a freely falling body

However; the force of gravity as a result of the moon acting on the lunar rocket is:

[tex]F_{g(moon)} = m_Lg_m[/tex]

Then; the equation for the thrust force of the lunar rocket is:

[tex]F_{net} = F_{thrust} - F_{g(moon)}[/tex]

[tex]m_La = F_{thrust}-m_Lg_m[/tex]

[tex]m_L(0)= F_{thrust}-m_Lg_m[/tex]

[tex]0= F_{thrust}-m_Lg_m[/tex]

[tex]-F_{thrust}= -m_Lg_m[/tex]

[tex]F_{thrust}= m_Lg_m[/tex]

Finally; the thrust force of the lunar rocket can be determined as:

[tex]F_{thrust}= m_Lg_m[/tex]

Acceleration due to gravity ot the surface of the moon = 1.625 m/s²

[tex]F_{thrust}=(1.4 \times 10^{4} \ kg) (1.625 \ m/s^2)[/tex]

[tex]F_{thrust}=2.275 \times 10^4 \ N[/tex]

[tex]\mathbf{F_{thrust} \simeq 2.3 \times 10^4 \ N}[/tex]

A thrust force of 22680N will be necessary to  to have the lander touch down with zero acceleration.

Given the data in the question;

Mass of Apollo 12 lunar lander; [tex]m_L = 1.4 * 10^4 kg[/tex]

Using the expression for the net-force that acts on the lander when it is accelerated in the upward direction:

[tex]F_{net} = F_{thrust} - F_{g(moon)}[/tex] ------- Let this be equation 1

Also, the net-force that acts on the lunar lander can be expressed as:

[tex]F_{net} = m_L*a[/tex] ------- Let this be equation 2

Where [tex]m_L[/tex] is the mass of the lunar lander and a is the acceleration ( 0 ),

( the acceleration of the moving rocket is zero and its freely falling )

Also, Force of gravity due to moon that acts on the lunar lander is expressed as:

[tex]F_{g(moon)} = m_L * g_m[/tex]  ------- Let this be equation 3

Where [tex]m_L[/tex] is the mass of the lunar lander and [tex]g_m[/tex] is the moon's gravity ( [tex]1.62m/s^2[/tex] )

Lets substitute equation 2 and 3 into 1

[tex]m_L * a = F_{thrust} - (m_L * g_m)\\\\m_L * 0= F_{thrust} - (m_L * g_m)\\\\0=F_{thrust} - (m_L * g_m)\\\\ F_{thrust} = m_L * g_m[/tex]

We substitute our values into the equation

[tex]F_{thrust} = (1.4*10^4kg) * 1.62m/s^2\\\\F_{thrust} = 22680 kg.m/s^2\\\\F_{thrust} = 22680N[/tex]

Therefore, a thrust force of 22680N will be necessary to  to have the lander touch down with zero acceleration.

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Answer:

1 hour

Explanation:

t = 6/6

6/6 = 1

You just said that his speed enables him to cover 6 miles in each hour. From this information, I calculated that it will take him one hour to travel 6 miles.

We are given:

The tuning fork vibrates at 15660 oscillations per minute

Period of one back-and forth movement:

the given data can be rewritten as:

1 minute / 15660 oscillations

60 seconds / 15660 oscillations          (1 minute  = 60 seconds)

dividing the values

0.0038 seconds / Oscillation

Therefore, one back and forth vibration takes 0.0038 seconds

Answer:

yes

Explanation:

the brain perform two separate tasks at the same time

Answer:

[tex]3.24\times 10^{-7}\ \text{m}[/tex]

Explanation:

m = Mass of bullet = 4.8 g

v = Velocity of bullet = 170 m/s

B = Magnetic field of Earth = [tex]5\times 10^{-5}\ \text{T}[/tex]

q = Charge of bullet = [tex]1.06\times 10^{-8}\ \text{C}[/tex]

a = Acceleration

Time the bullet will be in the air for is [tex]t=\dfrac{1000}{170}=5.88\ \text{s}[/tex]

Force is given by

[tex]F=ma[/tex]

Magnetic force is given by

[tex]F=qvB[/tex]

So

[tex]ma=qvB\\\Rightarrow a=\dfrac{qvB}{m}\\\Rightarrow a=\dfrac{1.06\times 10^{-8}\times 170\times 5\times 10^{-5}}{4.8\times 10^{-3}}\ \text{m/s}^2[/tex]

From the linear equations of motion we have

[tex]s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0+\dfrac{1}{2}\times \dfrac{1.06\times 10^{-8}\times 170\times 5\times 10^{-5}}{4.8\times 10^{-3}}\times 5.88^2\\\Rightarrow s=3.24\times 10^{-7}\ \text{m}[/tex]

The defelection of the bullet is [tex]3.24\times 10^{-7}\ \text{m}[/tex]

Answer:

Equilibrium is when the rate of the forward reaction equals the rate of the reverse reaction. All reactant and product concentrations are constant at equilibrium.

Explanation:

Answer:

J

Explanation:

The daughter moves with greater acceleration backwards because of her weight.

Both mother and daughter move backward, but the daughter moves with greater acceleration. Therefore, option (J) is correct.

This law states that the acceleration of a body depends on two factors. The first one is the mass of the body and the net force acting on the body. The acceleration is inversely proportional to the mass and is directly proportional to the net force acting on the body and

Newton’s second law can be written in an expression as follows:

F = ma

or,   a = F/m

According to Newton's third law of motion, there is an equal and opposite reaction for every action. So when the two skaters push each other. They both will move in a backward direction.

But the mass of the daughter is 50 Kg while the mass of the mother is 100 Kg. As the mass of the daughter is less. Therefore daughter moves in a backward direction with greater acceleration.

Therefore, both move backward but the daughter moves with greater acceleration in comparison to the mother.

Learn more about Newton's second law of motion, here:

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#SPJ2

Given :

A weight lifter lifts a 280-N set of weights from ground level to a position over his head, a vertical distance of 1.60 m.

To Find :

How much work does the weight lifter do, assuming he moves the weights at constant speed.

Solution :

We know, work done is given by :

[tex]W= Fdcos\ \theta[/tex]

Here, F = 280 N and d = 1.60 m

Since, weight lifer is applying and upward force and displacement is also in upward direction.

[tex]\theta = 0^{\circ}\\cos\ 0^{\circ} = 1[/tex]

Putting all these in above equation, we get :

[tex]W = 280\times 1.6\times 1\\\\W = 448\ J[/tex]

Therefore, work done by weight lifter 448 J.

Hence, this is the required solution.

Answer:

D

Explanation:

Answer:

I'm going to guess 15 N

Explanation:

Answer:

261.84 N.

Explanation:

From the question given above, the following data were obtained:

Energy (E) = work (W) = 741 J

Distance (d) = 2.83 m

Force (F) =?

Work is simply defined as the product of force and the distance moved in the direction of the the force. Mathematically, it is expressed as:

Work (W) = Force (F) × distance (d)

W = F × d

Thus, we obtained the weight of the object using the above formula.

Work (W) = 741 J

Distance (d) = 2.83 m

Force (F) =?

W = F × d

741 = F × 2.83

Divide both side by 2.83

F = 741 / 2.83

F = 261.84 N

Since force and weight has the same unit of measurement i.e Newton (N), the weight of the object is 261.84 N

Answer:

ok

Explanation:

ok ok I will thanks for free

Answer:

The minimum downward force on the box that will keep it from slipping is 63.14 N

Explanation:

Given;

mass of the object, m = 30 kg

applied force, f = 125 N

coefficient of static friction, μ = 0.35

Normal reaction (R) is acting upwards, weight of the box (mg) is acting downwards and the minimum downward force (F) on the box that will keep it from slipping is also acting downwards.

The net vertical forces on the box is given by;

R - mg - F = 0

F = R - mg

Now, determine normal reaction, R

f = μR

R = f / μ

R = 125 / 0.35

R = 357.14 N

Finally, determine the minimum downward force on the box that will keep it from slipping;

F = R - mg

F = 357.14 - (30 x 9.8)

F = 357.14 - 294

F = 63.14 N

Therefore, the minimum downward force on the box that will keep it from slipping is 63.14 N

At angular speed of 3 rev/s, the object moves a distance equal to 3 times the circumference of the circle each second, or a distance of 3 • 2π (1.20 cm) ≈ 22.6 cm.

So, with a linear speed of 22.6 cm/s = 0.226 m/s, the object has a centripetal acceleration a of

a = (0.226 m/s)² / (0.012 m) ≈ 18.8 m/s²

directed toward the center of the circle.

Answer:

False

Explanation:

Answer:

False

Explanation:

Hope this helped, Have a Wonderful Day/Night!!

Answer:

The volume would become 2.34 L if the temperature dropped to 11.0 °C

Explanation:

From the question, A balloon was filled to a volume of 2.50 L when the temperature was 30.0 °C.

To determine what the volume will become if the temperature dropped to 11.0 °C, we will use one of the Gas laws that relates Volume and Temperature. The Gas law that relates Volume and Temperature is the Charlse' law which states that, "the Volume of a fixed mass of gas is directly proportional to its Temperature ( in Kelvin) provided that the Pressure remains constant"

That is

V ∝ T ( at constant pressure)

Where V is the Volume

and T is the Temperature in Kelvin

Then, we can write that

V = kT

Where k is the constant of proportionality

Then,

[tex]\frac{V}{T} = k[/tex]

Hence, we can write that

[tex]\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} } = \frac{V_{3} }{T_{3} } ...[/tex]

∴ [tex]\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }[/tex]

Where [tex]{V_{1} }[/tex] is the initial volume

[tex]{T_{1} }[/tex] is the initial temperature

[tex]{V_{2} }[/tex] is the final volume

and [tex]{T_{2} }[/tex] is the final temperature

From the question,

[tex]{V_{1} }[/tex] = 2.50 L

[tex]{T_{1} }[/tex] = 30.0 °C = 30.0 + 273.15 K = 303.15 K

[tex]{V_{2} }[/tex] = ??

[tex]{T_{2} }[/tex] = 11.0 °C = 11.0 + 273.15 K = 284.15 K

Putting the values into the equation, we get

[tex]\frac{2.50}{303.15} = \frac{V_{2} }{284.15}[/tex]

∴ [tex]V_{2} = \frac{2.50 \times 284.15}{303.15}[/tex]

[tex]V_{2} = 2.34 L[/tex]

Hence, the volume would become 2.34 L if the temperature dropped to 11.0 °C.

The final volume of the balloon is equal to 0.92 Liter.

Given the following data:

To determine the final volume of the balloon, we would apply Charles's law:

Mathematically, Charles law is given by the formula;

[tex]\frac{V}{T} =k\\\\\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]

Where;

Substituting the given parameters into the formula, we have;

[tex]\frac{2.5}{30} = \frac{V_2}{11} \\\\2.5 \times 11 = 30V_2\\\\27.5 = 30V_2\\\\V_2 = \frac{27.5}{30}[/tex]

Final volume = 0.92 Liter.

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Answer:

I believe none

Explanation:

Answer:

NEWTON

Explanation:

ISSAC NEWTON

HOPE IT HELP U

Answer:

hans bethe

Explanation:

Hans Bethe

In 1939, in a paper entitled "Energy Production in Stars", Hans Bethe analyzed the different possibilities for reactions by which hydrogen is fused into helium. He defined two processes that he believed to be the sources of energy in stars.

i looked it up and thats what it said

Answer:

d = 7.5 [cm]

Explanation:

To be able to solve this problem we must understand well the concept of a simple lever of First Class, which consists of a support point (fulcrum) and a beam where a force is applied at one end, while at the other end the force exerted is multiplied.

In the attached image we can see an image that will help us better understand the concept of this first-class lever.

The moment created by the effort and the distance is equal to:

M = 100*30 = 3000 [N*cm]

Now the balance is created because we have the same moment exerted by the effort and the one created by the load.

3000 = 400*d

d = 7.5 [cm]

Answer:

9,800 watts

Explanation:

The first step is to calculate the force

F= mg

= 500 × 9.8

= 4,900 N

The next step is to calculate the work done

= 4,900 × 100

= 490,000 joules

Therefore the power can be calculated as follows

Power= work done /time

= 490,000/50

= 9,800 watts

Answer:

can I see like the actual activity on a computer or book?

Answer:

d

Explanation: