. Suppose you randomly choose 10 dentists and ask whether they recommend Colgate toothpaste. What is the probability that exactly 8 dentists in your sample recommend Colgate toothpaste

Answers

Answer 1

Answer:

Step-by-step explanation:

The probability that a dentist recommend Colgate is;

P = 1/2 = 0.5

The probability that a dentist doesn't recommend Colgate is;

P' = 1 - P = 1 -0.5 = 0.5

Of 10 sample dentists, the probability that exactly 8 dentists recommend Colgate toothpaste is;

8 will recommend and two will not recommend it.

P(X) = P^8 × P'^2

P(X) = (0.5)^8 × (0.5)^2

P(X) = 0.0039 x 0.25

P(X) = 0.00098 = 0.098%


Related Questions

A foundry has been commissioned to make souvenir coins. The coins are to be made from an alloy that is 40% silver. The foundry has on hand two alloys, one with 50% silver content and one with a 25% silver content. How many kilograms of each alloy should be used to make 10 kilograms of the 40% silver alloy?

Answers

Answer:

the amount of 50% silver alloy is 6 kilograms and the amount of 25% silver alloy is (10-6)= 4 kilograms.

Step-by-step explanation:

Suppose, the weight of the alloy with 50% silver content is x  kilograms.

As, the weight of the mixed alloy should be 10 kilograms, so the weight of the alloy with 25% silver content will be:  kilograms

The percentage of silver content in the mixed alloy is 40%. So the equation will be calculated as

[tex]0.5x+0.25(10-x)=0.4\times10\\0.5x+2.5-0.25x=4\\0.25x=1.5\\\Rightarrow x=\frac{1.5}{0.25} = 6[/tex]

So, the amount of 50% silver alloy is 6 kilograms and the amount of 25% silver alloy is (10-6)= 4 kilograms.

What’s the correct answer for this question?

Answers

Answer:

A.

Step-by-step explanation:

Density = Mass / Volume

D = 3/0.2

D = 15 kg/m³

Answer:

density=mass/volume

d=3kg/0.2m3

=15kgm-3

you will get alot of points if you answer this explain your answer

Answers

Answer:

The surface area of stand is 46 feet.

First

taking the upper rectangular prism only.

so we get

l=3

w=1

h=3

surface area of rectangular prism = 2lw+2lh+2hw

= 2×3×1+2×3×3+2×3×1

= 30

taking the lower rectangular prism only.

surface area of rectangular prism = 2lw+2lh+2hw

=2×7×2+2×1×7+2×2×1

=46

add both the rectangular prism.

we get,

30+46

76

Yes, $15 is enough

Taking out the square of all the rectangle the total would be 52m²

52/25×6.79 ( as 6.79 dollars for 25 m²)

$14.1232

Answer:

freecoins

Step-by-step explanation:

Karissa begins to solve the equation StartFraction one-half EndFraction left-parenthesis x minus 14 right-parenthesis plus 11 equals StartFraction one-half EndFraction x minus left-parenthesis x minus 4 right-parenthesis.. Her work is correct and is shown below. Three lines of math. The first line, StartFraction one-half EndFraction left-parenthesis x minus 14 right-parenthesis plus 11 equals StartFraction one-half EndFraction x minus left-parenthesis x minus 4 right-parenthesis. The second line, StartFraction one-half EndFraction x minus 7 plus 11 equals StartFraction one-half EndFraction x minus x plus 4. The third line StartFraction one-half EndFraction x plus 4 equals negative StartFraction one-half EndFraction x plus 4. StartFraction one-half EndFraction x minus 7 plus 11 equals StartFraction one-half Endfraction x minus x plus 4. StartFraction one-half EndFraction x plus 4 equals negative StartFraction one-half Endfraction x plus 4. When she subtracts 4 from both sides, Startfraction one-half EndFraction x equals negative StartFraction one-half EndFraction x. results. What is the value of ? –1 –negative StartFraction one-half EndFraction 0 StartFraction one-half EndFraction.

Answers

Answer:

  x = 0

Step-by-step explanation:

Given

Karissa begins to solve the equation ...

  [tex]\dfrac{1}{2}(x-14)+11=\dfrac{1}{2}x-(x-4)[/tex]

Her work is correct and is shown below. Three lines of math.

  [tex]\dfrac{1}{2}(x-14)+11=\dfrac{1}{2}x-(x-4)\qquad\text{given}\\\\\dfrac{1}{2}x-7+11=\dfrac{1}{2}x-x+4\qquad\text{eliminate parentheses}\\\\\dfrac{1}{2}x+4=-\dfrac{1}{2}x+4\qquad\text{collect terms}[/tex]

When she subtracts 4 from both sides, the result is ...

  [tex]\dfrac{1}{2}x=-\dfrac{1}{2}x[/tex]

Find

What is the value of x?

Solution

Karissa can determine the value of x by adding 1/2x to both sides:

  [tex]x=0[/tex]

Answer:

Option C (0)

Step-by-step explanation:

A random sample of 18 graduates of a certain secretarial school typed an average of 80.6 words per minute with a standard deviation of 7.2 words per minute. Assuming a normal distribution for the number of words typed per​ minute, compute the 95​% prediction interval for the next observed number of words per minute typed by a graduate of the secretarial school.

Answers

Answer: ( 77.27 , 83.93)

Therefore at 95% confidence/prediction interval is

= ( 77.27 , 83.93)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 80.6 words per minute

Standard deviation r = 7.2

Number of samples n = 18

Confidence interval = 95%

z(at 95% confidence) = 1.96

Substituting the values we have;

80.6+/-1.96(7.2/√18)

80.6+/-1.96(1.697056274847)

80.6 +/- 3.33

= ( 77.27 , 83.93)

Therefore at 95% confidence/prediction interval is

= ( 77.27 , 83.93)

Age (years) Population Under 15 2600 15 - 64 16000 Over 64 4000 Calculate the child dependency ratio from the chart above. Round to 3 decimals places.

Answers

Answer:

16.25%

=0.163 (correct to 3 decimal places)

Step-by-step explanation:

The child dependency ratio of a population is defined as the number of children (Under 15 years) divided by the working-age population (15–64 years old).

[tex]\mathrm{ Child}\;\mathrm{ dependency}\;\mathrm{ ratio}=\dfrac{{\mathrm{ Population}\,\left( \text{Under 15} \right)}}{{\mathrm{ Population}\,\left( {15-64} \right)}}\times 100[/tex]

From the given table:

Population Under 15 years = 2600

Population of the working class (between 15-64) = 16000

Therefore:

[tex]\mathrm{ Child}\;\mathrm{ dependency}\;\mathrm{ ratio}=\dfrac{2600}{16000}\times 100\\\\=16.25\%[/tex]

=0.163 (correct to 3 decimal places)

what is X:
|4x−1|=3

|x|=−4

Answers

Answer:

1

Step-by-step explanation:

the answer is x=1 hope this helped

Which graph represents the function f(x) = |x| – 4? On a coordinate plane, an absolute value graph has a vertex at (0, 4). On a coordinate plane, an absolute value graph has a vertex at (negative 4, 0). On a coordinate plane, an absolute value graph has a vertex at (0, negative 4). On a coordinate plane, an absolute value graph has a vertex at (4, 0).

Answers

Answer:

(0, -4)

Step-by-step explanation:

The graph that represents the function is (c) on a coordinate plane, an absolute value graph has a vertex at (0, -4)

The equation of the function is given as:

[tex]f(x) = |x| - 4[/tex]

The above function is an absolute value function shifted down by 4 units

Hence, the graph that represents the function is a graph that has its vertex at (0,-4)

Read more about absolute value graphs at:

https://brainly.com/question/2166748

Which of the following functions is graphed below

Answers

Answer:

B

Step-by-step explanation:

For all the people that have to do algebra and dont want to do it yourself there is a website or you can download it on your phone its called*** MATH PAPA*** ****IT SHOWS YOU STEP BY STEP AND GIVES YOU THE ANSWER*** Just input the equation

Answers

is it good? or worth to download

Find the values of x in the figure below. Express your answer in simplest radical form.

Answers

Answer:

Step-by-step explanation:I don't say u must have to mark my ans as brainliest but if it has really helped u plz don't forget to thank me...

A county real estate appraiser wants to develop a statistical model to predict the appraised value of houses in a section of the county called East Meadow. One of the many variables thought to be an important predictor of appraised value is the total number of rooms in the house. Consequently the appraiser decided to fit the simple linear regression model, ^y=β0+β1x , where y= the appraised value of the house (in thousands of dollars) and x= the number of rooms. Using data collected for a sample of n = 74 houses in East Meadow, the following results were obtained:

Answers

Answer:

Step-by-step explanation:

Hello!

The statistical model predicts the appraised value of houses in a section of the county East Meadow (Y) in relationship with the number of rooms of the house (X)

For a sample of n=64 houses the simple linear regression was estimated:

^Y= 74.80 + 24.93X

Range of X: 5 - 11

Range of Y: 160 - 300 ($ thousands of dollars)

Interpretation of the estimates of the y-intercept and the slope

y-intercept:

74.80 thousand dollars is the estimated average value of a house in a section of the county East Meadow when the house has zero rooms.

Slope:

24.93 [tex]\frac{thousand dollars}{rooms}[/tex] is the modification of the estimated average value of a house in a section of the county East Meadow when the number of rooms increases on one.

I hope this helps!

what is the solution set for the equation (x-2)(x-8)=0

Answers

Answer:

x=2           x =8

Step-by-step explanation:

(x-2)(x-8)=0

Using the zero product property

x-2 = 0    x-8 = 0

x=2           x =8

Answer:x = 2 and x = 8

Step-by-step explanation:

( 2 - 2)( 8 - 8)

(0)(0)

=0

Marcus states that angle ORP and angle LRP are a linear pair. Which best describes his statement?

Answers

Answer:

He is incorrect. Ray RO and ray RL are not opposite rays.

Step-by-step explanation:

Two angles are linear pair if they are supplementary and share a leg. 

∠ORP and ∠LRP are not supplementary, because ray RO and ray RL are not opposite rays.

Therefore, ∠ORP and ∠LRP are not linear pair.

correct me if this is wrong

if the base of a right angled triangle is 4cm and its area is 20cm^2, find its height

Answers

answer will be 10cm² as i calculate it

An HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you that the printing speed is actually a Normal random variable with a mean of 17.48 ppm and a standard deviation of 3.25 ppm. Suppose that you draw a random sample of 10 printers.
Using the information about the distribution of the printing speeds given by the manufacturer, find the probability that the mean printing speed of the sample is greater than 18.06 ppm. (Please carry answers to at least six decimal places in intermediate steps. Give your final answer to the nearest three decimal places). Probability (as a proportion)

Answers

Answer:

0.288

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

[tex]\mu = 17.48, \sigma = 3.25, n = 10, s = \frac{3.25}{\sqrt{10}} = 1.027740[/tex]

Find the probability that the mean printing speed of the sample is greater than 18.06 ppm.

This is 1 subtracted by the pvalue of Z when X = 18.06. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{18.06 - 17.48}{1.027740}[/tex]

[tex]Z = 0.56[/tex]

[tex]Z = 0.56[/tex] has a pvalue of 0.712

1 - 0.712 = 0.288

The answer is 0.288

Two competing gyms each offer childcare while parents work out Gym A charges $9.00 per hour of childcare. Gym B
charges $0.75 per 5 minutes of childcare. Which comparison of the childcare costs is accurate?

Answers

Answer:

They charge an equal amount of money each hour.

Answer:

Gym B and Gym A charge the same hourly rate for childcare.

Step-by-step explanation:

answer on edge

A large software company gives job applicants a test of programming ability and the mean for that test has been 160 in the past. Twenty-five job applicants are randomly selected from a large university and they produce a mean score of 183 with a standard deviation of 12. Use a 0.05 level of significance to test whether the mean score for students from this university is greater than 160. use the P-value method of testing hypotheses.

Answers

Answer:

[tex]t=\frac{183-160}{\frac{12}{\sqrt{25}}}=9.58[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=25-1=24[/tex]  

And the p value would be:

[tex]p_v =P(t_{(24)}>9.58)\approx 0[/tex]  

Since the p value is very low at any significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 160

Step-by-step explanation:

Information provided

[tex]\bar X=183[/tex] represent the sample mean

[tex]s=12[/tex] represent the sample standard deviation

[tex]n=25[/tex] sample size  

[tex]\mu_o =160[/tex] represent the value to test

[tex]\alpha=0.05[/tex] represent the significance level

t would represent the statistic

[tex]p_v[/tex] represent the p value

Hypothesis to test

We want to verify if the true mean is greater than 160, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \leq 160[/tex]  

Alternative hypothesis:[tex]\mu > 160[/tex]  

The statistic is given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex]  (1)  

Replacing the info we got:

[tex]t=\frac{183-160}{\frac{12}{\sqrt{25}}}=9.58[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=25-1=24[/tex]  

And the p value would be:

[tex]p_v =P(t_{(24)}>9.58)\approx 0[/tex]  

Since the p value is very low at any significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 160

g(-4)
Please help!!

Answers

Answer:

1

Step-by-step explanation:

g(-4) means what is the y value when x is -4.

Find x=-4, and when x=-4. y=1

Answer:

1

Step-by-step explanation:

Find the area of a circle with radius, r = 19cm.
Give your answer rounded to 3 SF.

Answers

pi * 19^2 = 11134.11
1134.11 to 3 sf = 1130

Answer:

1130

Step-by-step explanation:

since radius of the circle was given and the formula of the area is pie r square

Solve the system of equations by using substitution

Y=2x+3
Y=x+2

Answers

Y = 2x + 3Y = x + 2

Since our first equation reads y = 2x + 3, we can substitute a 2x + 3

in for y in our second equation and then solve from there.

So we have 2x + 3 = x + 2.

Now subtract x from both sides to get x + 3 = 2.

Now subtract 3 from both sides to get x = -1.

To find y, plug -1 back into either equation.

I have chosen to plug it into the second.

So we have y = (-1) + 2 which simplifies to 1.

So our solution to this system is (-1, 1).

I really need help :( anybody ??

Answers

_______________________________

Hey!!

Answer:{2,4,5}

Explanation:

Range

Let R be relation from A to B.The set of second components or the set of elements of B are called range.

Hope it helps..

_______________________________

Identify the domain of a radical function with an odd index.

Answers

Answer:When n is an odd number, [tex]\sqrt[n]{a}[/tex] is a real number for all values of a. Then, the domain is the real domain.

A box plot is shown below:



What is the median and Q1 of the data set represented on the plot?


Median = 31; Q1 = 26

Median = 30; Q1 = 26

Median = 31; Q1 = 20

Median = 30; Q1 = 20

Answers

Answer:

Step-by-step explanation:

Hello!

I didn't find the exact box plot for this exercise but I've found one that'll help you identify the required values

When constructing a box plot the box lower and upper limits are defined by the first and third quartiles and the line separating it in two represents the median.

In this case, the box is lying on the side, the first quartile is represented by the left side of the box. If you see the graphic this one corresponds to 25.

The median, as said, is represented by the line drawn inside the box, it is not necessarily in its middle but it will always be inside it.

Watching the example, the median is 33

I hope this helps!

Answer: D

Step-by-step explanation:


please help me on this work please !

Answers

The second one I beileve is the answer to your question

Among fatal plane crashes that occurred during the past 55 ​years, 415 were due to pilot​ error, 96 were due to other human​ error, 169 were due to​ weather, 622 were due to mechanical​ problems, and 68 were due to sabotage. Construct the relative frequency distribution. What is the most serious threat to aviation​ safety, and can anything be done about​ it?

Answers

Answer:

Relative frequency:

[tex]\text{Pilot error}=415/1370=0.30\\\\\text{Other human error}=96/1370=0.07\\\\\text{Weather}=169/1370=0.12\\\\\text{Mechanical problems}=622/1370=0.45\\\\\text{Sabotage}=68/1370=0.05\\\\[/tex]

The most serious threat to aviation safety is, according to this data, "mechanical failures". It can be improved by more rigorous inspection and better maintenance policies and execution.

Step-by-step explanation:

We have the data for fatal plane crashes. The sum of plane crashes is

We can calculate the relative frequency as:

[tex]\text{Pilot error}=415/1370=0.30\\\\\text{Other human error}=96/1370=0.07\\\\\text{Weather}=169/1370=0.12\\\\\text{Mechanical problems}=622/1370=0.45\\\\\text{Sabotage}=68/1370=0.05\\\\[/tex]

We can see that the most frequent cause is "mechanical problems", with a relative frequency of 0.45.

someone answer this

Answers

Answer:

16

Step-by-step explanation:

The right triangle shown is a 30:60:90 triangle.

30:60:90 right triangles have a 1:sqrt(3):2 ratio between their sides.

Since the side opposite from the 30 degree is 8, and x is opposite from the 90 degree angle, 8 and x have a 1:2 ratio, or 8:16.

A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 4 students' scores on the exam after completing the course: 12,7,13,11 Using these data, construct a 80% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal. Step 3 of 4 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.

Answers

Answer:

The 80% confidence interval for the average net change is (8.596, 12.904).

Critical value t=1.638.

Step-by-step explanation:

First, we calculate the mean and standard deviation of the sample:

[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{4}(12+7+13+11)\\\\\\M=\dfrac{43}{4}\\\\\\M=10.75\\\\\\s=\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2\\\\\\s=\dfrac{1}{3}((12-10.75)^2+(7-10.75)^2+(13-10.75)^2+(11-10.75)^2)\\\\\\s=\dfrac{20.75}{3}\\\\\\s=6.92\\\\\\[/tex]

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=10.75.

The sample size is N=4.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.63}{\sqrt{4}}=\dfrac{2.63}{2}=1.315[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=4-1=3[/tex]

The t-value for a 80% confidence interval and 3 degrees of freedom is t=1.638.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_M=1.638 \cdot 1.315=2.154[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M-t \cdot s_M = 10.75-2.154=8.596\\\\UL=M+t \cdot s_M = 10.75+2.154=12.904[/tex]

The 80% confidence interval for the average net change is (8.596, 12.904).

Solve for the value of x

Answers

Answer:

  x = 8

Step-by-step explanation:

The angle with the expression in it is complementary to the 30° angle, so is 60°. Then we have ...

  4 +7x = 60

  7x = 56 . . . . . . subtact 4

  x = 8 . . . . . . . . .divide by 7

M5-3/2x less than or equal to 1/3

Answers

Answer: choice A

Step-by-step explanation:

by rearranging the initial inequality you’ll get

[tex]\frac{3}{2} x\leq 5-\frac{1}{3}[/tex]

which equals

[tex]\frac{3}{2} x\leq\frac{14}{3}[/tex]

then multiply both sides by 2/3

[tex]x\leq \frac{28}{9}[/tex]

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