Answer:
Expectation is equal to 4.75
Variance is equal to 3.02
Step-by-step explanation:
Consider the attached image.
Let [tex]x_i[/tex] denotes each of the outcome.
Expectation [tex]=E(X)[/tex] = ∑[tex]x_if(x_i)[/tex]
[tex]=1(\frac{1}{12}) +2(\frac{1}{12}) +3(\frac{1}{12}) +4(\frac{1}{12}) +5(\frac{1}{12}) +6(\frac{7}{12})[/tex]
[tex]=\frac{1}{12}+\frac{2}{12}+\frac{3}{12}+\frac{4}{12}+\frac{5}{12}+\frac{42}{12}\\\\=\frac{57}{12}\\\\=4.75[/tex]
[tex]E(X^2)=[/tex] ∑ [tex]x_i^2f(x_i)[/tex]
[tex]=1^2(\frac{1}{12}) +2^2(\frac{1}{12}) +3^2(\frac{1}{12}) +4^2(\frac{1}{12}) +5^2(\frac{1}{12}) +6^2(\frac{7}{12})[/tex]
[tex]=(\frac{1}{12}) +4(\frac{1}{12}) +9(\frac{1}{12}) +16(\frac{1}{12}) +25(\frac{1}{12}) +36(\frac{7}{12})\\\\=\frac{307}{12}[/tex]
Variance [tex]=E(X^2)-[E(X)]^2[/tex]
[tex]=(\frac{307}{12})-(\frac{57}{12})^2\\\\ =\frac{307}{12}-\frac{3249}{144}\\\\ =\frac{3684-3249}{144}\\\\ =\frac{435}{144}\\\\ =3.02[/tex]
Suppose the number of insect fragments in a chocolate bar follows a Poisson process with the expected number of fragments in a 200-gram chocolate bar being 10.2. 15. What is the expected number of insect fragments in 1/4 of a 200-gram chocolate bar? 16. What is the probability that you have to eat more than 10 grams of chocolate bar before nding your rst fragment? 17. What is the expected number of grams to be eaten before encountering the rst fragment?
Answer:
a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b)0.6004
c)19.607
Step-by-step explanation:
Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2
X ~ Poisson(A) where [tex]\lambda = \frac{10.2}{200} = 0.051[/tex]
a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar
[tex]\frac{1}{4} \times 200 = 50[/tex]
50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55
So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment
Let X denotes the number of grams to be eaten before another fragment is detected.
[tex]P(X>10)= e^{-\lambda \times x}= e^{-0.051 \times 10}= e^{-0.51}=0.6004[/tex]
c)The expected number of grams to be eaten before encountering the first fragments :
[tex]E(X)=\frac{1}{\lambda}=\frac{1}{0.051}=19.607 gram[/tex]s
Which expression is equivalent to -4(w-1)
4w-4
4w
-4w+4
-5w
None of the above
Answer:
-4w+4
Step-by-step explanation:
Answer:
-4w+4 Is te correct answer
The access code to a house’s security system consists of eight digits. How many different codes are available if each digit can be repeated? Please show work!
Answer:
Consider one of eight positions separately from all others. There are 10 possible ways to choose
a digit to place on this position since there are ten digits from 0 to 9, and this choice is
independent of all other positions since each digit can be repeated and there is no restriction on
how to choose digits.
So, we have 8 positions and each one is filled by a digit in 10 ways independently from each other,
therefore the total number of possible codes equals to ways it can be done for each independent
position multiplied altogether. This is 10 × 10 × … × 10 = 108
(100 million).
Answer: 108 different codes.
Step-by-step explanation:
Find the measure of the missing angle
Multiply.
8.12⋅30.3
no answers are telling me and I'm stuck
Answer:
8,640
Step-by-step explanation:
Answer:
8X12X30X3 well we have to follow the order of operations. first 8X12=96
98X30=2880 2880x3=8640
Step-by-step explanation:
The school athletic director had a budget of $703.55 to purchase 55 items for the volleyball team. He purchased uniforms for $18.50 each, volleyballs for $12.99 each, and knee pads for $9.75 per pair. He purchased six more balls than uniforms. Define the variables and write a system of equations to represent the situation.
Answer:
Variables are x, y, z
System of equations are;
2x + z = 49
31.49x + 9.75z = 625.61
Step-by-step explanation:
Let x represent uniforms, y represent volleyball, z represent a pair of knee pads.
We are told he bought 6 more balls than uniforms. Thus; y = x + 6
Since he is buying 55 items, thus equation that represents total number of items bought is;
x + y + z = 55
Since y = x + 6, then;
x + x + 6 + z = 55
2x + z = 49
We are told he purchased uniforms for $18.5 each, volleyball for $12.99 dollar each, knee pads for $9.75 dollar for each pair
Since he has a budget of $703.55.
Thus, equation that represents budget and amount for each item is;
18.5x + 12.99(x + 6) + 9.75z = 703.55
18.5x + 12.99x + 77.94 + 9.75z = 703.55
31.49x + 9.75z = 703.55 - 77.94
31.49x + 9.75z = 625.61
(30 POINTS NEED HELP FAST)
A line has a slope of 2 and goes through the point (4,−3). What is the equation of this line in Standard Form?
−2x+y=−5
2x+y=−5
−2x+y=5
−2x+y=−11
Answer: −2x+y=−11
(4,-3) = −2x+y=−11.
Answer: −2x+y=−11.
Can someone answer this and explain how to solve the 3 with the exponent of -4?
Answer:
3⁷
Step-by-step explanation:
When you multiplying or dividing numbers with exponents, you keep the base the same and specifically with dividing, you subtract the exponents themselves. So, you would be doing 3-(-4), which is 7.
[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the Concept of the Exponents and power,
Since we know the concept that, any power in denominator of a fraction is shows as negative power when it comes to the Numerator of the fraction,like eg:-
[tex]1 \div ( {5}^{8} ) = {5}^{ - 8} [/tex]
so we apply here same,
also
[tex]1 \div ({5}^{ - 8} ) = {5}^{8} [/tex]
so we get as,
[tex] {3}^{3} \div {3}^{ - 4} = {3}^{3} \times {3}^{4} [/tex]
this is the answer.
what is eighteen and three fourths divided by two and a half?
Answer:
the answer is 7.5
Which of the following expressions is equal to -3x2 - 12?
Answer:
C. (-3x+6)(x+2)
Step-by-step explanation:
that should help you
Which equation represents a line perpendicular to the line shown on the graph?
On a coordinate plane, a line goes through (negative 2, 0) and (0, 4).
y = one-half x minus 2
y = negative one-half x + 3
y = 2 x + 1
y = negative 2 x + 4
Answer:
A
Step-by-step explanation:
The equation of the perpendicular line is y = -1/2x + 3. The correct option is (B).
What is a Linear equation?A linear equation is a equation that has degree as one.
To find the solution of n unknown quantities n number of equations with n number of variables are required.
The coordinates of the given points are (-2, 0) and (0, 4).
The equation of the line for the given points can be written as follows,
(y - 4)/(x - 0) = (4 - 0)/(0 - (-2))
=> y - 4 = 2x
=> y = 2x + 4
Comparing the above equation with the general equation y = mx + c the slope is given as,
m = 2
Now, the product of the slopes of two perpendicular lines is -1.
Thus, the slope of the perpendicular line is,
m' = -1/2.
In order to find the the correct answer compare all the options with general equation y = mx + c and check if the slope is -1/2 as below,
(a) y = 1/2x - 2
m = 1/2
(b) y = -1/2x + 3
m = -1/2
(c) y = 2x + 1
m = 2
(d) y = -2x + 4
m = -2
Hence, the equation for the line perpendicular to the given line is y = -1/2x + 3.
To know more about linear equation click on,
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andre has x dollars. He buys lunch using 1/6 of his money and earns 8$ by doing chores after school
Isopropyl alcohol has a density of 0.786 grams per cubic centimeter (g/cm 3). An object has a mass of 13 grams (g) and a volume of 21 cubic centimeters (cm 3). What will happen when the object is placed into isopropyl alcohol?
Answer:
B, it will float bc it is less dence. give me brainliest ;)
Step-by-step explanation:
find the missing terms in the arithmetic sequences
a). -45, _ , _ , _, -39
b) -34,_,_,77
The distribution of bladder volume in men is approximately Normal with mean 550 ml and standard deviation 100 ml.
Required:
a. What percent of men have a bladder volume smaller than 450 ml?
b. Between what volumes do the middle 95% of men’s bladders fall?
c. What proportion of male bladders are between 500 and 600 ml?
d. What volumes do the middle 90% of men’s bladder fall?
Answer:
a) 15.866%
b) Middle 95% = 350 ml to 750 ml
c) 0.3829
d) Middle 90% of men’s bladder fall = 385.5ml to 714.5 ml
Step-by-step explanation:
We solve using z score formula
z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
The distribution of bladder volume in men is approximately Normal with mean 550 ml and standard deviation 100 ml.
Required:
a. What percent of men have a bladder volume smaller than 450 ml?
z = 450 - 550/100
= -1
P-value from Z-Table:
P(x<450) = 0.15866
Convert to percentage
0.15866 × 100
= 15.866%
b. Between what volumes do the middle 95% of men’s bladders fall?
Middle 95% falls between 2 standard deviation of the mean
μ ± 2σ
μ - 2σ
550 - 2(100)
= 550 - 200
= 350 ml
μ + 2σ
= 550 + 2(100)
= 550 + 200
= 750 ml
Middle 95% = 350 ml to 750 ml
c. What proportion of male bladders are between 500 and 600 ml?
For 500ml
z = 500 - 550/100
= -0.5
Probability value from Z-Table:
P(x = 500) = 0.30854
For 600ml
z = 600 - 550/100
= 0.5
Probabilty value from Z-Table:
P(x = 600) = 0.69146
Proportion of male bladders are between 500 and 600 ml
P(x = 600) - P(x = 500)
0.69146 - 0.30854
= 0.38292
≈ 0.3829
d. What volumes do the middle 90% of men’s bladder fall?
The z score for middle 90% + / – 1.645
Hence,
1.645 = x - 550/100
1.645 × 100 = x - 550
164.5 + 550 = x
x = 714.5 ml
-1.645 = x - 550/100
-1.645 × 100 = x - 550
- 164.5 + 550 = x
x = 385.5ml
Middle 90% of men’s bladder fall = 385.5ml to 714.5 ml
3(4x-2)=12x
A. The equation has one solution
B. The equation has no solution
C. The equation has a few solution
D. The equation has many solution
Is the product of 0.4 * 1.8 greater then or less then 0.4
Answer:
Greater
Step-by-step explanation:
.4*1.8 is .72
.72 is greater than .4
Select the correct answer from each drop-down menu.
Points A, B, and C form a triangle. Complete the statements to prove that the sum of the interior angles of ΔABC is 180°.
Statement Reason
Points A, B, and C form a triangle. given
Let be a line passing through B and parallel to . definition of parallel lines
∠3 ≅ ∠5 and ∠1 ≅ ∠4
m∠1 = m∠4 and m∠3 = m∠5
m∠4 + m∠2 + m∠5 = 180° angle addition and definition of a straight line
m∠1 + m∠2 + m∠3 = 180° substitution
Answer:
Alternate interior angle theorem
Step-by-step explanation:
Answer:
For the second drop down menu I put third option.
Step-by-step explanation:
Point M is the midpoint of segment AC. Point M is located at (25.5, 60.1) and point C is located at (18.3, 72.5). What is the location of Point A ?
Answer:
[tex]A = (32.7,47.7)[/tex]
Step-by-step explanation:
Given
[tex]M = (25.5,60.1)[/tex]
[tex]C = (18.3,72.5)[/tex]
Required
Determine the coordinates of A
Midpoint is calculated as thus:
[tex]M(x,y) = (\frac{A_x + C_x}{2}, \frac{A_y + C_y}{2})[/tex]
Substitute the given values
[tex](25.5,60.1) = (\frac{A_x + 18.3}{2}, \frac{A_y + 72.5}{2})[/tex]
Multiply through by 2
[tex]2 * (25.5,60.1) = (\frac{A_x + 18.3}{2}, \frac{A_y + 72.5}{2}) * 2[/tex]
[tex]2 * (25.5,60.1) = (A_x + 18.3, A_y + 72.5)[/tex]
[tex](51,120.2) = (A_x + 18.3, A_y + 72.5)[/tex]
By comparison:
[tex]A_x + 18.3 = 51[/tex]
[tex]A_y + 72.5 = 120.2[/tex]
[tex]A_x + 18.3 = 51[/tex]
[tex]A_x = 51 - 18.3[/tex]
[tex]A_x = 32.7[/tex]
[tex]A_y + 72.5 = 120.2[/tex]
[tex]A_y = 120.2 - 72.5[/tex]
[tex]A_y = 47.7[/tex]
Hence:
[tex]A = (32.7,47.7)[/tex]
Xochitl has saved $201.60. Yamka has saved 1.5 times the amount Xochitl saved. Zack has saved 2/3 the amount Yamka saved. How much have they saved all together?
Answer:$758.53Step-by-step explanation:Xochintl has $201.60 and Yamka has 1.5 times of that which is $302.40 which equals 504.00 total and Zack has 2/3 times as Yamka which is $254.93:all together is 758.93 hope this helps
PLEASE SOLVE NOW!! I’m in desperate need
Answer:
sqr of 161
Step-by-step explanation:
8^2 + x^2 = 225
64+x^2 = 225
161=x^2
sqr of 161 = x
hope i helped!!!
Step-by-step explanation:
[tex] {15}^{2} - {8}^{2} = (15 + 8)(15 - 8) \\ = 23 \times 7 = 161[/tex]^-2
Katie ran 4 miles. She ran at a rate that was 1.1 minutes per mile slower than Jasmine. For how many minutes did Katie run? Explain how you determined your answer.
Answer:
it is 7.1
Step-by-step explanation:
how i got my answer is because jasmine ran 8.2 minute per mile
and Katie was 1.1 slower than jasmine so we will have to subtract like this
8.2
- 1.1
7.1 so katie ran 7.1 minutes per mile
If Katie ran at a rate that was 1.1 minutes per mile slower than Jasmine's.She takes 29.2 minutes to run.
What is the rate of change?It is defined as the change in values of a dependent variable with respect to the independent variables. the rate of change of distance with respect to time denotes the speed i.e. m/sec.
It is given that, Katie ran 4 miles. She ran at a rate that was 1.1 minutes per mile slower than Jasmine.
Time is taken by Katie for the given rate,
T = 5 miles × 8.4 mins / mile
T = 42 minute
The rate for Jasmine,
r = 8.4 - 1.1
r=7.3
The time for which Katie run,
t = 4 × 7.3
t = 29.2 minute
Thus, if Katie ran at a rate that was 1.1 minutes per mile slower than Jasmine's. She takes 29.2 minutes to run.
The question is incomplete.
The complete question is"Katie ran 4 miles at a rate of 1.1 miles slower than jasmine how many minutes did Katie run if jasmine ran 5 miles at 8.4 minutes per mile"
Learn more about the rate of change here:
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What is the coefficient in the expression 10x+8
Answer:
In the given expression, 10x + 8, the numerical coefficient is 10 and the literal coefficient is x. The number 8 is not considered as a coefficient since the value is a constant.
Answer: 10 + 8
Step-by-step explanation: If you want to find a coefficient you need to only remove the variable from the expression. For example what is the coefficient of 4x its 4. Please mark as the brainliest!
The volume of a cylinder with height and radius can be found using the formula
Suppose the volume of a cylinder is 1952 1 read the height is twice the radius what is the radius
of the cylinder. Determine the radius, rounded to the nearest whole foot
The radius is
feet
Answer:
7 feet
Step-by-step explanation:
Volume of a cyclinder = πr^2h
Volume of a cyclinder = 1952
π = 3.14
r = ?
h = 2r
Volume of a cyclinder = πr^2h
1952 = 3.14 * r^2 * 2r
1952 = 3.14 * 2r^3
1952 = 6.28r^3
Divide both sides by 6.28
r^3 = 1952 / 6.28
= 310.83
r^3 = 310.83
Find the cube root of both sides
r = 6.77 feet
Approximately 7 feet
Which expression is the coefficient of the n term -1
Answer:
C. -2n² - n + 5
Step-by-step explanation:
In expression C, the coefficient of the n term is -1;
The expression in choice C is given as:
-2n² - n + 5
The coefficient is the number before a variable;
For n², the coefficient is -2
for n, the coefficient is -1
A hockey player needs to shoot a puck 55 m from his current location to his opponents goal to score a goal after the shot the puck is 120 cm from his opponents goal if there are 100 cm in 1 m how many meters did the puck travel
Answer:
Step-by-step explanation:
hockey canada
Answer:
The puck changes direction at
✔ (25, 0) .
The puck goes into the opponent’s score zone located at
✔ (50, 20)
, because the graph is
✔ symmetric .
Step-by-step explanation:
2/3 of all your books are fiction. 1/6 of those are historical what fraction of all your books are historical fiction?
Answer with step-by-step explanation:
Since you're calculating 1/6 of 2/3, you'd need to do 1/6 × 2/3, which would get you 1/9
Hope this helped!
12. An object is fired from the top of a 200 ft. tower with an initial velocity of 80 ft/sec. and is
modeled by the equation h(t) = -16t^2+80t + 200.
a) How long after firing does it reach its maximum height?
b) What is the maximum height?
Answer:
a) The object reaches its maximum height at t=2.5 seconds
b) The maximum height is 300 m
Step-by-step explanation:
Maximum Value of a Function
First derivative criteria:
If f(t) is a real continuous function of t and the first derivative of f called f'(t) exists, then solving the equation:
f'(t)=0
Gives the critical points of f, some of which could be maximum or minimum.
Second derivative criteria:
If t=t1 is a critical point of f(t) and the second derivative of f:
f''(t1) is positive, then t1 is a minimum of f
f''(t1) is negative, then t1 is a maximum of f.
f''(t1)=0, no conclusion can be drawn.
The height of the object is modeled by the function:
[tex]h(t) = -16t^2+80t + 200[/tex]
a)
To find the maximum height, we use the above criteria.
Find the first derivative:
h'(t) = -32t+80
Equate h'(t)=0
-32t+80=0
Solve:
[tex]-32t=-80[/tex]
[tex]t=80/32=2.5[/tex]
t=2.5 seconds
Find the second derivative:
h''(t)=-32
Since the second derivative is negative, the critical point is a maximum.
The object reaches its maximum height at t=2.5 seconds
b) Evaluate h(2.5)
[tex]h(2.5) = -16\cdot 2.5^2+80\cdot 2.5 + 200[/tex]
[tex]h(2.5) = -100+200 + 200[/tex]
h(2.5)=300 m
The maximum height is 300 m
how many times can 130 go into 22? DIVIDE
130 cannot go into 22.
22 can go into 130 5 times
130 can not go into 22 idk if u meant 22 into 130
Explain your answer!
