If we suppose that there is a big drop in the interest rates in Mexico and a small drop in the interest rates in the U.S.A, with everything else equal, the value of MXN will decrease.
The foreign exchange market works according to the principles of firms, households, and investors:
These three constituent factors of the foreign exchange market determine the demand and supply patterns in the market. Demand for a foreign currency might increase in the foreign exchange market is linked to the expectation of an increase in the value of a foreign currency. Supply of a foreign currency in the foreign exchange market is linked to an inverse principle, where the expectation of a decrease in the value of foreign currency pushes supply upwards. If we are to suppose that there is a big drop in the interest rates in Mexico and a small drop in the interest rates in the U.S.A., then the value of the MXN will decrease, with everything being equal. A higher interest rate leads to the appreciation of a foreign currency relative to other currencies in the foreign exchange market. A lower interest rate leads to the depreciation of a foreign currency relative to other currencies in the foreign exchange market.Therefore, if we suppose that there is a big drop in the interest rates in Mexico and a small drop in the interest rates in the U.S.A, with everything else equal, the value of MXN will decrease.
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Calculate this logarithmic expression
The solution of the logarithmic expression [tex]\log_2(17 -\sqrt{19}) + \log_2(17 +\sqrt{19})[/tex] is [tex]\log_2[270][/tex]
How to solve the logarithmic expression?The expression is given as:
[tex]\log_2(17 -\sqrt{19}) + \log_2(17 +\sqrt{19})[/tex]
Apply the product law of logarithm
[tex]\log_2[(17 -\sqrt{19}) *(17 +\sqrt{19})]\\[/tex]
Apply the difference of two squares
[tex]\log_2[(17^2 -(\sqrt{19})^2][/tex]
Evaluate the squares
[tex]\log_2[(289 -19][/tex]
Evaluate the difference
[tex]\log_2[270][/tex]
Hence, the solution of the logarithmic expression [tex]\log_2(17 -\sqrt{19}) + \log_2(17 +\sqrt{19})[/tex] is [tex]\log_2[270][/tex]
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Fill in the blanks below.
Find the slope of the line passing through the points (8,5) and (8,-4).
Step-by-step explanation:
please mark me as brainlest
Please help whilst I try to solve as well.
Answer:
Step-by-step explanation:
Answer:
420 cm³Step-by-step explanation:
we find the volume as if it were a parallelepiped and we remove the volume of the missing part.
8 * 6 * 10 = 480 cm³
480 - 2 * 3 * 10 = 420cm³
the funtions f(x) and g(x) are shown on the graph f(x)=x^2
what is g(x)?
Answer:
C
Step-by-step explanation:
A reflection of a graph on the x axis simply adds the opposite sign to the x^2, in this case, since f(x) = x^2 is positive, a reflection would mean that g(x) would be -x^2. As g(x) is also vertically translated down 2 units, the equation would then become g(x) = -x^2 - 2 and the correct answer would be C.
Evaluate the integral
-7x³
x³ +1
Note: Use an upper-case "C" for the constant of integration.
I
dx
The value of the integration is
[tex]\int {\frac{-7x^{3} }{x^{3}+1} } \, dx =7x - \frac{7}{3} \ln(x+1) + \frac{7}{6} ln (x^{2} -x+1)-\frac{7\sqrt{3} }{3} tan^{-1} (\frac{2x-1}{\sqrt{3} })+C[/tex], where C is an integrating constant.
We know that finding the area of the curve's undersurface is the process of integration. To do this, cover the area with as many tiny rectangles as possible, then add up their areas. The sum gets closer to a limit that corresponds to the area under a function's curve. Finding an antiderivative of a function is the process of integration. If a function can be integrated and its integral over the domain is finite with the given bounds, then the integration is definite.
Here, we have to determine the value of the given integral
[tex]\int {\frac{-7x^{3} }{x^{3}+1} } \, dx[/tex].
So,
[tex]\int {\frac{-7x^{3} }{x^{3}+1} } \, dx = 7 \int {\frac{1-x^{3}-1 }{x^{3}+1} } \, dx[/tex][tex]= 7 \int [{1-\frac{1 }{x^{3}+1} } ]\, dx =7\int \, dx - 7 \int {\frac{1 }{x^{3}+1} } \, dx[/tex] ...(1)
Now,
[tex]\frac{1}{x^{3} +1} = \frac{1}{(x+1)(x^{2} -x+1)}[/tex]
We can write
[tex]\frac{1}{(x+1)(x^{2} -x+1)}=\frac{A}{(x+1)} + \frac{Bx+C}{(x^{2} -x+1)}[/tex]
i.e. [tex]1 = A(x^{2} -x+1)+(Bx+C)(x+1)[/tex]
i.e. [tex]1 = Ax^{2} -Ax + A+Bx^{2} +Bx+Cx+C[/tex]
i.e. [tex]1=(A+B)x^{2} +(-A+B+C)x +(A+C)[/tex]
Comparing both sides, we get
[tex]A+B=0 \implies B = -A[/tex] ...(2)
[tex]-A+B+C = 0 \implies -A+(-A)+C=0 \implies -2A+C=0[/tex] ...(3)
[tex]A+C=1[/tex] ...(4)
Subtracting (3) from (4),
[tex]A+C+2A-C=1-0 \implies 3A=1 \implies A=\frac{1}{3}[/tex]
From (4), [tex]C= 1-\frac{1}{3} =\frac{3-1}{3} =\frac{2}{3}[/tex]
From (2), [tex]B =-\frac{1}{3}[/tex]
We get
[tex]\frac{1}{x^{3}+1 } =\frac{1}{3} \frac{1}{(x+1)} - \frac{1}{3} \frac{x-2}{x^{2} -x+1}[/tex]
[tex]=\frac{1}{3} \frac{1}{(x+1)} - \frac{1}{6} \frac{2x-4}{x^{2} -x+1}[/tex]
[tex]=\frac{1}{3} \frac{1}{(x+1)} - \frac{1}{6} \frac{2x-1-3}{x^{2} -x+1}[/tex]
[tex]=\frac{1}{3} \frac{1}{(x+1)} - \frac{1}{6} \frac{2x-1}{x^{2} -x+1}+\frac{3}{6} \frac{1}{x^{2} -x+1}[/tex]
[tex]=\frac{1}{3} \frac{1}{(x+1)} - \frac{1}{6} \frac{2x-1}{x^{2} -x+1}+\frac{1}{2} \frac{1}{x^{2} -x+1}[/tex]
Integrate both sides,
[tex]\int \frac{1}{x^{3}+1 }\, dx =\frac{1}{3} \int \frac{1}{(x+1)} \, dx - \frac{1}{6} \int \frac{2x-1}{x^{2} -x+1}\, dx+\frac{1}{2} \int \frac{1}{x^{2} -x+1}\, dx[/tex]
i.e. [tex]\int \frac{1}{x^{3}+1 }\, dx =\frac{1}{3} \ln(x+1) - \frac{1}{6} ln (x^{2} -x+1)+\frac{\sqrt{3} }{3} tan^{-1} (\frac{2x-1}{\sqrt{3} })[/tex]
From (1),
[tex]\int {\frac{-7x^{3} }{x^{3}+1} } \, dx =7x - \frac{7}{3} \ln(x+1) + \frac{7}{6} ln (x^{2} -x+1)-\frac{7\sqrt{3} }{3} tan^{-1} (\frac{2x-1}{\sqrt{3} })+C[/tex]
Therefore, the value of the integration is
[tex]\int {\frac{-7x^{3} }{x^{3}+1} } \, dx =7x - \frac{7}{3} \ln(x+1) + \frac{7}{6} ln (x^{2} -x+1)-\frac{7\sqrt{3} }{3} tan^{-1} (\frac{2x-1}{\sqrt{3} })+C[/tex], where C is an integrating constant.
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Karl, Serene and Pauline have 1281 stickers altogether. 08
Pauline had 3 times as many stickers as Serene.
Karl had 175 stickers fewer than Pauline.
How many stickers did Pauline have?
Pauline has 371 stickers. Karl, Serene, and Pauline have 1281 stickers altogether.
What is the equation?A mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.
Let Karl, Serene and Pauline have x, y, and z stickers.
Given condition;
Karl, Serene, and Pauline have 1281 stickers altogether;
x+y+z = 1281
Pauline had 3 times as many stickers as Serene.
z = 3 y
y=z/3
Karl had 175 stickers fewer than Pauline.
x=z -175
Substitute all the values in the terms of z;
x+y+z = 1281
z -175 + z/3 + z = 1281
8z/3 = 1281 +175
z=546
Pauline have;
x = z -175
x =546 -175
x = 371
Hence Pauline has 371 stickers.
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Evaluate and reduce:
The ratio of (1/5 of 245ml) to (0.2 of 0.84l)
The ratio is given by 98:0.34.
The ratio of (1/5 of 245ml) to (0.2 of 0.84ml).
What is the Ratio?The ratio can be defined as the comparison of the fraction of one quantity towards others. e.g.- water in milk.
we have (1/5 of 245ml) to (0.2 of 0.84ml).
⇒ [tex]\frac{1}{5} 245 :0.2*0.84[/tex]
⇒[tex]98:0.34[/tex]
Thus, the required ratio is 98:0.34.
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URGENT WILL GIVE BRANLIEST IF CORRECT!!! A car is moving at 22.5 m/s, when it begins to accelerate at 1.45 m/s². How much time does it take to travel 60.2 m?
(Unit = s)
Answer:
2.48 seconds
Step-by-step explanation:
See attached
One third of all guitars that are sold in the shop is a Stratocaster, one fourth of them are Telecasters, and one fifth of them is a Les Paul. If Jamie goes and buys a guitar, what are the chances she gets a telecaster or a Les Paul?
A. 58%
B. 53%
C. 45%
D. 43%
The probability that Jamie buys a telecaster or a Less Paul is 45% or forty-five percent.
How to find out the probability?1. Find the individual probabilities:
Probabilities to buy a telecaster:
1/ 4 = 0.25Probabilities to buy a Les Paul:
1/ 5 = 0.22. Add the probabilities:
0.25 + 0.2 = 0.453. Multiply by 100:
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Help please!! I’m stuck with these questions. :)
Answer:
61
Step-by-step explanation:
the question is asking to find the number of element of set b that are not in set a
to find this one must know the common elements
the question has given the common elements to be 5
now subtract the number of elements in set b with the common elements
i.e. 66-5
=61
6/64 reduce to lowest terms
Answer:
[tex]\frac{3}{32}[/tex]
Step-by-step explanation:
-> Simplify
[tex]\frac{6}{64} =\frac{6/2}{64/2} =\frac{3}{32}[/tex]
6/64 simplified.
please help! I need this quickly
write an equation in standard form of the line passing through the points (12,6) and (-3,11)
Answer:
x + 3y = 30
Step-by-step explanation:
We are given that a line contains the points (12,6) and (-3,11).
We want to write the equation of this line in standard form.
Standard form is written as ax+by=c, where a, b, and c are free integer coefficients, however a and b cannot be 0, and a cannot be negative.
Regardless, before we write an equation in slope-intercept form, we must first write the equation in a different form, such as slope-intercept form.
Slope-intercept form is given as y=mx+b, where m is the slope and b is the value of y at the y-intercept.
So first, let's find the slope of the line.
The slope (m) can be found using the formula [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are points.
Even though we already have 2 points, let's label their values to avoid any confusion and mistakes when calculating.
[tex]x_1=12\\y_1=6\\x_2=-3\\y_2=11[/tex]
Now substitute these values into the formula.
m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
m=[tex]\frac{11-6}{-3-12}[/tex]
Subtract
m=[tex]\frac{5}{-15}[/tex]
Simplify
m=[tex]-\frac{1}{3}[/tex]
The slope is -1/3
Here is the equation of the line so far in slope-intercept form:
[tex]y=-\frac{1}{3} x + b[/tex]
We need to solve for b.
As the equation passes through (12,6) and (-3,11), we can use either one to help solve for b.
Taking (12, 6) for example:
[tex]6=-\frac{1}{3}(12) + b[/tex]
Multiply
[tex]6=-\frac{12}{3} + b[/tex]
Divide
6 = -4 + b
Add 4 to both sides.
10 = b
Substitute 10 as b in the equation.
[tex]y = -\frac{1}{3} x + 10[/tex]
Here is the equation in slope-intercept form, but remember, we want it in standard form.
In standard form, the values of both x and y are on the same side, so let's add -1/3x to both sides.
[tex]\frac{1}{3} x + y = 10[/tex]
Remember that a (the coefficient in front of x) has to be an integer, 1/3 is not an integer.
So, let's multiply both sides by 3 to clear the fraction.
[tex]3(\frac{1}{3} x + y) = 3(10)[/tex]
Multiply.
x + 3y = 30
Topic: finding the equation of the line (standard form)
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In the equation y/6 = 156, what is the next step in the equation solving sequence
Answer:
Linear Equations In One Variable =
Next step :
in the equation y/6 = 156, it would be equivalent to y = 156 × 6.
so that :
y = 156 × 6
y = 936
this equation solved. (Answer : 936)
A piecewise function is shown here:
f(x) = {-3x +5 if x <2
{1/2x - 4 if 2 < or = to x < or = to 8
{2 if x > 8
Use the piecewise function to find each value given below.
f(0) =
f(-4) =
f(6) =
f(9)=
f(2) =
f(0) = -3(0) + 5 = 5
f(-4) = -3(-4) + 5 = 17
f(6) = ½(6) - 4 = -1
f(9) = 2
f(2) = ½(2) - 4 = -3
Using the restraints, find which equation the f(x) function validates and plug it in.
As a nurse, part of your daily duties is to mix medications in the proper proportions for your patients. For one of your regular patients, you always mix Medication A with Medication B in the same proportion. Last week, your patient's doctor indicated that you should mix 90 milligrams of Medication A with 72 milligrams of Medication B. However this week, the doctor said to only use 8 milligrams of Medication B. How many milligrams of Medication A should be mixed this week?
The Medication A mixed this week should be 10 milligrams.
We have,
Medications to be mixed in the proper proportions.
Last week's proportions as the doctor indicated ;
Medication A = 90 milligrams
Medication B = 72 milligrams
This week's proportions as doctor indicated;
Medication B = 8 milligrams
Let, Medication A = x milligrams
As we are instructed to mix the Medication in the proper proportions,
So,
According to the question,
90/72 = x/8
10/8 = x/8
⇒ x = 10 milligrams
Here, the Medication A mixed is 10 milligrams.
Therefore, the Medication A mixed this week should be 10 milligrams.
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A swimming pool is to be constructed in a 1,408-ft2 backyard. There is to be a fence that will surround a 12-by-24-foot pool. The pool builder wants to build a concrete paver deck of a uniform width, x, surrounding the pool and filling the entire area of the backyard. What is the width of the pool deck?
The width of the pool is 10 feet.
What is area of rectangle?The area of rectangle is product of length and breadth.
Let the width be x.
length = 24 + 2x. and breadth = 12 + 2x
We know, area= 1408 ft².
(12 + 2x)(24 + 2x) = 1408
12*24 + 12*2x + 24*2x + (2x)² = 1408
288 + 72x + 4x² = 1408
4x² + 72x + 288 - 1408 = 0
4x² + 72x - 1120 = 0
x² + 18x - 280 = 0
x² - 10x + 28x - 280 = 0
x(x - 10) + 28(x - 10) = 0
(x - 10)(x + 28) = 0
So, x=10, -28.
Hence, the width be 10 feet.
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If a line has a slope of 4 and goes through the point open parentheses short dash 1 comma 1 close parentheses, then the equation for the line in slope-intercept form is ______________.
a.)
y equals short dash 4 x minus 3
b.)
y equals 4 x plus 3
c.)
y equals 4 x plus 5
d.)
y equals short dash 4 x minus 5
A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of the line will be y =4x+5. Thus, the correct option is C.
What is the equation of a line?A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,
y =mx + c
where,
x is the coordinate of the x-axis,
y is the coordinate of the y-axis,
m is the slope of the line, and
c is the y-intercept.
Given the slope of the line is 4 and it goes through (-1,1), therefore, the equation of the line will be,
y = mx + c
y = 4x + c
Substitute the value of points,
1 = 4(-1) + c
1 = -4 + c
5 = c
Hence, the equation of the line will be y =4x+5. Thus, the correct option is C.
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The fox population in a certain region has a continuous growth rate of 7 percent per year. It is estimated that the population in the year 2000 was 15000.
(a) Find a function that models the population
t
years after 2000 (
t
=
0
for 2000).
Your answer is
P
(
t
)
=
(b) Use the function from part (a) to estimate the fox population in the year 2008.
Your answer is (the answer must be an integer)
There are 25773 foxes in the region in the year 2008
How to determine the function?The given parameters are:
Initial value, a = 15000Rate, r = 7% or 0.07Let the number of years after 2000 be x.
So, the function is
f(x) = a * (1 + r)^x
This gives
f(x) = 15000 * (1 + 0.07)^x
In 2008, we have:
x = 8
So, the equation becomes
f(8) = 15000 * (1 + 0.07)^8
Evaluate
f(8) = 25773
Hence, there are 25773 foxes in the region in the year 2008
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Please helpppp I really need please
Step-by-step explanation:
please mark me as brainlest
Find sin
A. 12/13
B. 1
C. 13/12
D. 13/5
Answer: A. [tex]\frac{12}{13}[/tex]
Step-by-step explanation:
The best way to remember this is SOH-CAH-TOA. For sin, it would be the opposite angle over the hypotenuse. The opposite angle of ∠C is 24 and the hypotenuse is 26. But that isn't in the answer choices, so you'll simplify the fraction.
[tex]\frac{24}{26} =\frac{12}{13}[/tex], therefore, the answer is A.
I hope this helps! Pls mark brainliest!! :)
Find the zeros of the quadratic polynomial f(x) = 6x²-3, and verify the relationship between the zeros and its coefficients.
Step-by-step explanation:
1) zeros of the given function:
6x²-3=0; ⇔ 6(x²-0.5)=0; ⇔ x²=0.5; ⇔
[tex]\left[\begin{array}{ccc}x=-\sqrt{0.5} \\x=\sqrt{0.5} \end{array}[/tex]
2) relationship:
if to see the equation x²-0.5=0 (ax²+bx+c=0 is standart form!), then the sum of the zeros is '0' (it is 'b' of the standart form), the product of equation roots is '-0.5' (it is 'c' of the standart form).
[tex]{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}[/tex]
★ The polynomial
f(x) = 6x² - 3
[tex]{\large{\textsf{\textbf{\underline{\underline{To \: find :}}}}}}[/tex]
★ Zeroes of the polynomial f(x) = 6x² - 3
[tex]{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}[/tex]
We have,
[tex]f(x) = \tt 6 {x}^{2} - 3[/tex]
Which can also be written as
[tex] \implies f(x) = \tt {(\sqrt{6} x)}^{2} - { (\sqrt{3}) }^{2} [/tex]
Using a² - b² = (a - b) (a + b)
[tex] \implies f(x) = \tt ( \sqrt{6} x - \sqrt{3} )( \sqrt{6} x + \sqrt{3} )[/tex]
To find the zeroes, solve f(x) = 0
[tex] \longrightarrow \tt ( \sqrt{6} x - \sqrt{3} )( \sqrt{6} x + \sqrt{3} ) = 0[/tex]
either [tex] \tt \sqrt{6} x - \sqrt{3} = 0 \: or \: \sqrt{6} x + \sqrt{3} = 0[/tex]
[tex] \implies \tt \sqrt{6} x = \sqrt{3 \: } \: or \: \: \sqrt{6} x = - \sqrt{3}[/tex]
[tex] \implies \tt x = \dfrac{ \sqrt{3} }{ \sqrt{6} } \: or \: x = - \dfrac{ \sqrt{3} }{ \sqrt{6} }[/tex]
[tex] \implies \tt x = \dfrac{ \sqrt{3} }{ \sqrt{2 \times 3} } \: or \: x = - \dfrac{ \sqrt{3} }{ \sqrt{2 \times 3} }[/tex]
[tex]\implies \tt x = \dfrac{ \cancel{ \sqrt{3} }}{ \sqrt{2} \: \cancel{\sqrt{3}} } \: or \: x = - \dfrac{ \cancel{ \sqrt{3} }}{ \sqrt{2} \: \cancel{\sqrt{3}} }[/tex]
[tex]\implies \tt x = \dfrac{1}{ \sqrt{2} } \: \: or \: \: - \dfrac{1}{ \sqrt{2} }[/tex]
Hence, the zeroes of f(x) = 6x² - 3 are:
[tex] \tt \alpha =\sf \boxed {{ \red{ \dfrac{1}{ \sqrt{2} } } }}\: \: and \: \: \beta =\sf \boxed {{ \red{ - \dfrac{1}{ \sqrt{2} } } }}[/tex]
• Verification
Sum of zeroes = [tex] ( \alpha + \beta )[/tex]
[tex] = \tt \dfrac{1}{ \sqrt{2} } + \bigg(- \dfrac{1}{ \sqrt{2} } \bigg)[/tex]
[tex] = \tt \dfrac{1}{ \sqrt{2} } + - \dfrac{1}{ \sqrt{2} } [/tex]
[tex]= \tt 0[/tex]
and, [tex]\tt - \dfrac{Coefficient \: of \: x}{Coefficient \: of \: {x}^{2} }[/tex]
[tex] \tt = - \dfrac{0}{6} [/tex]
[tex] \tt = 0[/tex]
[tex] \therefore \tt \: Sum \: of \: zeroes = {\boxed{ \red{\dfrac{ \tt Coefficient \: of \: x}{ \tt Coefficient \: of \: {x}^{2}}}}}[/tex]
Also,
Product of zeroes = [tex] \alpha \beta [/tex]
[tex] = \dfrac{1}{ \sqrt{2} } \times - \dfrac{1}{ \sqrt{2} } [/tex]
[tex] = - \dfrac{1}{ 2 } [/tex]
and, [tex]\tt - \dfrac{Constant \: term}{Coefficient \: of \: {x}^{2} }[/tex]
[tex] \tt = \dfrac{ - 3}{6} [/tex]
[tex] \tt = \dfrac{ - 1}{2} [/tex]
[tex] \therefore \tt \: Product \: of \: zeroes = {\boxed{ \red{\dfrac{ \tt Constant \: term}{ \tt Coefficient \: of \: {x}^{2}}}}}[/tex]
[tex]\rule{280pt}{2pt}[/tex]
in a study of birth orders and intelligence, IQ test were given to 18 and 19 years old men to estimate the size of difference, if any, between the main IQs of firstborn sons and second born sons. The following data for 10 firstborn sons and 10 second born sons are consistent with the means and standard deviation's reported in the article. It is reasonable to assume that the samples come from populations that are approximately normal. First born numbers are 107, 113, 84, 126, 99, 95, 98, 109, 91, 90. Second born numbers are 112, 92, 102, 86, 97, 106, 105, 116, 109, 95. construct a 95% confidence interval for the difference in mean IQ between first born and second born sons. Let them one denote the main IQ of firstborn sons.
In a study of birth orders and intelligence, IQ tests were given to 18 and 19 years old men to estimate the size of the difference, we have that [tex]|t|=0.618\leq t_c =2.101[/tex] and for this reason, we cannot reject the null hypothesis.
What are the Test Statistics?Null and Alternative Hypotheses
[tex]H_o: \mu_{1} = \mu_{2}\\\\Ha: \mu_1 \neq \mu_2 .[/tex]
Since the population standard deviations are unknown, we will apply a t-test on the means of the two populations, using two independent samples.
The degrees of freedom are df = 18, and the significance threshold is set at alpha = 0.05, based on the data presented. If we assume that the population variances are the same, we can calculate the degrees of freedom in this way:
The rejection region for this two-tailed test is R = \{t : |f| > 2.101}
Therefore the Test Statistics is
[tex]t= \frac{X 1 -X 2 }{\frac{\sqrt{ (n_1 -1)s_1 ^ 2 +(n_2 -1)s_2 ^2}} {n_1 +n_2 -2} (( 1/n_1 + 1 n_2 )}}[/tex]
[tex]t= \frac{X 1 -X 2 }{\frac{\sqrt{ (n_1 -1)s_1 ^ 2 +(n_2 -1)s_2 ^2}} {n_1 +n_2 -2} (( 1/n_1 + 1 n_2 )}}[/tex]
t=0.618
In conclusion. we have that [tex]|t|=0.618\leq t_c =2.101[/tex]
For this reason, we cannot reject the null hypothesis.
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O
11
O
12 13
←
14
15
Which number line represents the solutions to -2|x| = -6?
←
16
17
18
←
+ +
-8-7-6-5-4-3 -2 -1 0 1 2 3
+
-8-7-6-5-4-3 -2 -1 0 1
19
+
-8-7-6-5-4-3 -2 -1 0 1 2
2 3
++
20
++ ++
4
567
4 5 6 7
3 4
5 6 7
8
8
+
8
H
-8-7-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8
T
Answer:
thats not even understandable
The solution set is {3, -3} and is represented by the number line shown below.
What is number line?It is the representation of numbers in real order.
The difference between the consecutive numbers in a number line is always positive.
We have,
To solve the equation -2|x| = -6,
We can begin by dividing both sides by -2:
|x| = 3
This means that the absolute value of x is equal to 3.
The solutions to this equation are x = 3 and x = -3.
The number line that represents these solutions is:
<--(+)===================(+)--->
-3 3
The open circles indicate that the solutions are not included in the solution set since the absolute value of x cannot be negative.
Therefore,
The solution set is {3, -3} and is represented by the number line shown above.
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After 8 points are added to each score in a sample.
the mean is found to be M = 40. What was the
value for the original mean?
Skyler, Robert, and Kaitlyn all solve the same exponential problem but have different approaches. Skyler Robert Kaitlyn 729=9 729=9 729=9 (36)=9 (93)=91 (36)=32 6x = 9 3x = 1 6x = 2 x = 96 x = 13 x = 26 x = 32 x = 13 Explain Sklyer's processes. Is Skyler correct? If not, where did she go wrong? Explain Robert's processes. Is Robert correct? If not, where did he go wrong? Explain Kaitlyn's processes. Is Kaitlyn correct? If not, where did she go wrong?
The justification for whether Skyler, Robert, or Kaitlyn was right or wrong stems from how they went about their processes:
Skyler erred by failing to equalize the bases of both sides before equating the exponents.Robert is right since he equalized the exponents before comparing the bases of the two sides.Since Kaitlyn made the bases of both sides equal before equating the exponents, she is accurate.1) SKYLER'S PROCESS:
Skyler wants to resolve the following issue;
Reduce 729 to the lowest base possible as a first step; [3^(6)]^x = 9
729^(x) = 9
The next thing she did was convert 6x to 9.
Since both sides must have the same base when dealing with exponent equality, she may have transformed 9 to have the same base of 3 as the left hand side before equating the exponents.
So Skyler is wrong.
2) ROBERT'S PROCESS:
Skyler failed to capture both bases equally, as we witnessed, but Robert has now made the right decision by;
9^(3x) = 9¹
After which he equated the exponents to get;
3x = 1
x = 1/3
Thus; Robert is correct
3) KAITLYN'S PROCESS:
Kaitlyn is also accurate since she adhered to the same method, which calls for comparing bases before comparing exponents.
Learn more about laws of exponents here:
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Warm Shelters.org received a donation of $32,000 to buy beds and dressers for its new dormitories. Each bed will cost $320.00 and each dresser will be $75.00 each. A total of 132 pieces of beds and dressers are needed. What is the percentage of dressers with respect to the number of beds?
Please HELP
Answer:
you can buy 98 beds and buy dresses by rest of the money
HELP ASAP
8. The tubes on the frame of this road bike form a triangle. The owner's manual
identifies some of the angle measures formed by the bike frame. Based on the
information in the diagram below, determine which tube is the longest.
top tube
seat tube
top tube
30%
7
55
C
down tube
Part I: Classify the triangle formed by the three bike frame tubes as equilateral,
isosceles, or scalene. Find the measure of ZB and explain your classification. (3
points; 1 point for classification, 1 point for the angle measure, and 1 point for
explanation)
seat tube
down tube
Answer:
See below
Step-by-step explanation:
Longest is the down tube.....it is opposite the largest angle (95°) angle in the triangle . This is a SCALENE triangle ( all sides of different length)
The longest tube that we have here is the down tube. The triangle that is formed id the scalene triangle
What is the scalene triangle
A scalene triangle is a type of triangle where all three sides have different lengths. In other words, no two sides of a scalene triangle are equal in length. Additionally, the angles of a scalene triangle are also different from each other.
The term "scalene" comes from the Greek word "skalenos," which means "uneven" or "unequal." This name reflects the defining characteristic of the scalene triangle, which is the absence of any equal sides or angles.
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9 is subtracted from 3 times the sum of 4 and 2.
Answer:
9
Step-by-step explanation:
This problem is represented below.
=3(4+2)-9
=3(6)-9
=18-9
=9
What is the range of the function in the graph?
. 1≤x≤6
B. 20≤y≤60
C. 20≤x≤60
D. 1≤y≤60
Answer:
B
Step-by-step explanation:
Range is all the possible values of 'y'. As seen in the graph, the smallest value of 'y' is 20, where the point is (6, 20), and the largest value of 'y' is 60, where the point is (1, 60). Therefore, the range is B. 20≤y≤60
